express as a trinomial (2x-9)(3x-5)

The blanks in each statement about the line segment should be completed as shown below.

Since we know U is the midpoint, we can say TU=8x + 11 substituting in our values for each we get:

8x + 11 = 12x - 1

Solve for x

We now want to solve for x.

−4x+11=−1

−4x = -12

x= 3

Solve for TU, UV, and TV

This is just the first part of our question. Now we need to find TU, UV, and TV. Lets start with TU and UV.

TU=8x+11 We know that x=3 so let’s substitute that in.

TU=8(3)+11

TU= 35

We will do the same for UV. From our knowledge of midpoint, we know that TU should equal UV, however let’s do the math just to confirm.

UV=12x−1 We know that x=3 so let’s substitute that in.

UV=12(3)−1

UV= 35

Based on the segment addition postulate, we have:

TU+UV=TV

35+35=TV

TV= 70

Find the detailed calculations below;

TU = UV

8x + 11 = 12x - 1

8x + 11 - 11 = 12x - 1 - 11

8x = 12x - 12

8x - 12x = 12x - 12 - 12x

-4x = -12

x = 3

By using the substitution method to substitute the value of x into the expression for TU, we have:

TU = 8x + 11

TU = 8(3) + 11

TU = 24 + 11

TU = 35

By applying the transitive property of equality, we have:

UV = TU and TU = 15, then UV = 35

By applying the segment addition postulate, we have:

TV = TU + UV

TV = 35 + 35

TV = 70

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Answer:

729

Step-by-step explanation:

hope it helps

Answer: 27/2 = 13 1 2\

also 729

Answer: 240¢

Step-by-step explanation:

100¢ in a dollar.

$2.40 * 100 = 240

240¢

Answer:

6, 8, 10, and 12

Step-by-step explanation:

x + (x + 2) = (x + 4) + (x + 6) = 36

4x + 12 = 36

subtract 12 rom each side of the equation:

4x = 24

divide both sides by 4:

x = 6

x + 2 = 8

x + 4 + 10

x + 6 = 12

The vertex of the transformed parabola with the equation \(y=a(x-h)^2+k\) is (h, k).

The transformation rules are:

Translation: (x, y) → (x + a, y) or (x, y) → (x - a, y) (Horizontal shift)

Translation: (x, y) → (x , y + b) or (x, y) → (x , y - b) (Vertical shift)

It is given that, the transformed parabola is \(y=a(x-h)^2+k\)

This parabola has vertex at (h, k).

Since this equation is obtained by shifting h units horizontally and k units vertically.

So, the original vertex is at (h - h, k - k) = (0, 0)

Thus, the equation of the actual parabola is \(y=ax^2\)

Therefore, the given transformed equation of parabola has vertex (h, k).

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Answer:

B] (h,k)
The next answer is Vertex (-5, -4)

☆
EDGE2022; Good luck :3!!!!

The difference between the starting and ending grades is 0.90%

The time for integer (INT) operations reduced if the total time is reduced by 20% is 0.6667

The number of full (+00) stations on the curve is 66,666.

The difference between the starting and ending grades can be calculated as follows:

Difference = Ending Grade - Starting Grade

Difference = -2.85% - (-3.75%)

Difference = -2.85% + 3.75%

Now, let's perform the calculation:

Difference = 0.90%

Next, we need to determine the number of full stations on the curve. To do this, we divide the length of the curve by the rate of change of grade per station. The rate of change of grade per station is the difference between the starting and ending grades.

Length of Curve = 600 feet

Rate of Change of Grade per Station = Difference

Now, let's calculate the number of full stations:

Number of Full Stations = Length of Curve / Rate of Change of Grade per Station

Number of Full Stations = 600 feet / 0.90% = 0.6667

To convert the rate of change of grade from a percentage to a decimal, we divide by 100:

Number of Full Stations = 600 feet / (0.90% / 100)

Number of Full Stations = 600 feet / (0.0090)

Calculating this expression gives us the number of full stations on the curve.

Number of Full Stations = 66,666.67

Therefore, we round down the number of full stations to the nearest whole number, which gives us:

Number of Full Stations = 66,666 (rounded down)

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Complete Question:

Another pitfall cited is expecting to improve the overall performance of a computer by improving only one aspect of the computer. Consider a computer running a program that requires 250 s, with 70 s spent executing FP instructions, 85 s executed L/S instructions, and 40 s spent executing branch instructions.

1. By how much is the total time reduced if the time for FP operations is reduced by 20%?

2. By how much is the time for INT operations reduced if the total time is reduced by 20%?

3. Can the total time can be reduced by 20% by reducing only the time for branch instructions?

Answer:

Just multiply over here

1/2 *20

1/2 * 20/1

20/2

10

answer is 10

Answer:

10

Step-by-step explanation:

multiply (1/2) by 20

10

The yearly insurance fee is paid for a house valued at 4,500 naira if the fee is 1/8 of it's value is 562.5.

The term "percentage" comes from the Latin phrase "per centum," meaning means "by the hundred." Percentages is fractions with a denominator of 100.

In other terms, it is the relationship between portion and whole in which the value of the whole is always assumed to be 100.

Calculating a percentage implies determining a portion of a whole in term of 100. A percentage can be calculated in two ways:

Now, according to the question;

The initial value of the house is 4,500.

The insurance fee is 1/8 of 4,500.

1/8 in percentage is;

= (1/8)×100

= 12.5

Now, calculate the 12.5 of 4,500.

= (12.5×4,500)/100

= 562.5

Therefore, the insurance fee paid for the house is 562.5.

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The evaluated integral ∫(x - yz - 2) ds is equal to √(2) * [t²/2 - 3t] + C, where C is the constant of integration.

Let's denote the parametric equations for the line segment as follows: x = x(t) y = y(t) z = z(t)

Since we are given the points (0, 1, 1) and (1, 0, 1) as the endpoints of the line segment, we can determine the equations for x(t), y(t), and z(t) by interpolating between these two points.

For the x-coordinate, we observe that it varies linearly from 0 to 1 as t ranges from 0 to 1. Therefore, we can set: x(t) = t

For the y-coordinate, it decreases linearly from 1 to 0 as t increases from 0 to 1. Hence, we have: y(t) = 1 - t

The z-coordinate remains constant at 1 throughout the line segment, so we can set: z(t) = 1

The arc length ds can be calculated using the formula:

ds = √(dx/dt² + dy/dt² + dz/dt²) dt

To find dx/dt, dy/dt, and dz/dt, we differentiate the parametric equations x(t), y(t), and z(t) with respect to t, respectively.

dx/dt = 1 dy/dt = -1 dz/dt = 0

Now we substitute these derivatives into the arc length formula to get: ds = √(1² + (-1)² + 0²) dt ds = √(2) dt

Finally, we can rewrite the integral in terms of t and substitute the expression for ds: ∫(x - yz - 2) ds = ∫(t - (1 - t) * 1 - 2) √(2) dt = ∫(t - 1 + t - 2) √(2) dt = ∫(2t - 3) √(2) dt

To evaluate this integral, we can integrate term by term:

= √(2) * [t²/2 - 3t] + C

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Ricardo has the greatest amount of personal control over his savings. So, correct option is A.

Savings refer to the money he has already set aside or accumulated for college. He has complete control over how much he saves and how he spends it.

Scholarships, grants, and work-study programs are external sources of funding that Ricardo can apply for and receive, but he may not have complete control over the amount of money he receives.

Scholarships and grants are typically awarded based on academic achievement, financial need, or other criteria that are beyond his control. Work-study programs may limit the number of hours he can work or the type of work he can do, and the amount of money he can earn may also be limited.

In contrast, Ricardo can decide how much money he wants to save for college and how he wants to allocate that money towards his expenses. He can also choose to invest his savings in a way that can earn interest or returns, which can help him maximize his savings. Therefore, his personal control over his savings gives him the most flexibility and independence in paying for his college expenses.

So, correct option is A.

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According to Weber's law, two items must differ in weight by "5 percent"of weight in order to detect a difference.

We are given that Weber's law

For weight discrimination, Weber’s law states that the JND is proportional to the weight of the stimulus.

The JND is defined as the smallest difference between two weights that can be detected by an observer.

The proportionality constant is known as Weber’s fraction and varies depending on the type of stimulus and the sensory modality involved.

For weight discrimination, Weber’s fraction is typically around 2-3%.

This means that two items must differ in weight by approximately 2-3% of their weight in order to detect a difference.

The difference of weight in percent is 5%, the correct option is A.

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The solution is, the remainder is 9.

Division is the process of splitting a number or an amount into equal parts.

Division is one of the four basic operations of arithmetic, the ways that numbers are combined to make new numbers. The other operations are addition, subtraction, and multiplication.

here, we have,

find the remainder in the synthetic division

1         4       6        -1

Take down the first number 4 as it is. then multiply it with divisor 1 and put it below 6. then add it and do the same till we get remainder

1         4       6        -1

        0        4        10

       --------------------------------

        4        10       9 -> Remainder

So the remainder is 9.

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Answer:

look at the pic below!

Step-by-step explanation:

Answer:

-x^6/125-y^3/64

Step-by-step explanation:

that's what it Got

The null and alternative hypothesis for this test would be:

Symbolically,

H0: p ≥ 0.9

Ha: p < 0.9

where p represents the true population proportion of people who own cats.

To test this hypothesis, we would need to collect a random sample of people and determine the proportion in the sample who own cats. We would then use a one-tailed z-test to determine if the sample proportion is significantly different from the hypothesized proportion of 0.9 at the 0.1 significance level.

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Kevin's rate is 6 miles per hour and the rate of the current is 4 miles per hour.

What is rate?

Let's call Kevin's rate (or speed) "k" and the rate of the current "c".

When Kevin is traveling downstream, his effective speed is the sum of his own speed and the speed of the current, so his effective speed can be written as:

k + c

We know that he travels 30 miles downstream in 3 hours, so we can write an equation:

30 = 3(k + c)

When Kevin is traveling upstream (against the current), his effective speed is the difference between his own speed and the speed of the current, so his effective speed can be written as:

k - c

We know that the return trip took 15 hours, so we can write another equation:

30 = 15(k - c)

Now we have two equations with two unknowns, which we can solve as a system of linear equations.

First, we can simplify the second equation by dividing both sides by 15:

2 = k - c

Now we have a system of two equations:

30 = 3(k + c)

2 = k - c

We can solve this system using substitution or elimination. Let's use substitution:

From the second equation, we can solve for k:

k = 2 + c

Substitute this expression for k into the first equation:

30 = 3(2 + c + c)

Simplify:

30 = 6 + 6c

Subtract 6 from both sides:

24 = 6c

Divide by 6:

c = 4

Now we can substitute this value of c into either equation to solve for k. Let's use the second equation:

2 = k - c

Substitute c = 4:

2 = k - 4

Add 4 to both sides:

k = 6

So Kevin's rate is 6 miles per hour and the rate of the current is 4 miles per hour.

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Based on the drawing obtained from the description, the location of

Manu's farm is located relatively south to Dogbe's farm.

Reasons:

The bearing of the cottage to Dogbe's farm = 200°

The distance Dogbe walks from the cottage to his farm = 5 km

The bearing of the cottage from Manu's farm = 110°

The distance Manu walks from the cottage to his farm = 3 km

Required:

The distance and between the two farms.

Solution:

Please find attached a drawing showing the position of the cottage

By cosine rule, we have;

Where;

b = The distance Dogbe walks from the cottage to his farm = 5 km

c = The distance Manu walks to his farm from the cottage = 3 km

a = The distance between the two farms = d

A = The angle between the paths to the cottage from the farms = 50°

By plugging in the values, we have;

d² = 5² + 3² - 2 × 5 × 3 × cos(50°)

d = √(5² + 3² - 2 × 5 × 3 × cos(50°)) ≈ 3.8

Required:

The bearing of Manu's farm from Dogbe's

Solution:

By sine rule, we have;

Which gives;

\(\displaystyle sin(C) = \mathbf{\frac{3 \times sin(50^{\circ})}{\sqrt{5^2 + 3^2 - 2 \times 5 \times 3 \times cos(50^{\circ})} }}\)

\(\displaystyle \angle C = arcsine \left(\frac{3 \times sin(50^{\circ})}{\sqrt{5^2 + 3^2 - 2 \times 5 \times 3 \times cos(50^{\circ})} } \right) \approx 38 ^{\circ}\)

The bearing of Manu's farm from Dogbe's = 200° + ∠C

Therefore;

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Answer:

30 angels

Step-by-step explanation:

The amount you could save per month would be 25% of your discretionary money.

Discretionary income is the money you have left over after paying taxes and necessary cost-of-living expenses.

The formula for discretionary money is: Discretionary money = Realized income - Fixed expenses. Inputting data, we have: Discretionary money = $3,543.22 - Fixed expenses

Amount to be saved = 25% of discretionary money

Amount to be saved = 0.25 * (Realized income - Fixed expenses)

Therefore, the amount savable is calculated as 0.25 times the difference between your realized income and fixed expenses.

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To calculate the air temperature at the compressor exit, the back work, and the thermal efficiency for the simple ideal Brayton cycle used by the dairy factory, we can follow these steps:

a) Air temperature at the compressor exit:
1. Assume the air at the compressor exit has a temperature of T2.
2. Since the Brayton cycle uses air as the working fluid and variable specific heats with temperature, we can use the relation Cp = Cp(T) to represent the specific heat capacity of air at any temperature.
3. Use the energy balance equation for the compressor:
  - Q = Wc + ΔH, where Q is the heat added, Wc is the work done by the compressor, and ΔH is the change in enthalpy.
  - Since the Brayton cycle is ideal and reversible, there is no heat transfer (Q = 0) and no change in enthalpy (ΔH = 0).
  - Therefore, the energy balance equation simplifies to: 0 = Wc.
  - This means that the work done by the compressor is equal to zero.
4. Since no work is done by the compressor, the air temperature at the compressor exit (T2) is the same as the air temperature at the compressor inlet, which is 200 K.

b) Back work:
1. The back work (Wb) is the work done by the turbine to drive the compressor.
2. Use the energy balance equation for the turbine:
  - Q = Wt + ΔH, where Q is the heat added, Wt is the work done by the turbine, and ΔH is the change in enthalpy.
  - Since the Brayton cycle is ideal and reversible, there is no heat transfer (Q = 0) and no change in enthalpy (ΔH = 0).
  - Therefore, the energy balance equation simplifies to: 0 = Wt.
  - This means that the work done by the turbine is equal to zero.
3. Hence, the back (Wb) is also zero.

c) Thermal efficiency:
1. The thermal efficiency (η) of the Brayton cycle is given by the ratio of the net work done (W_net) to the heat added (Q):
  - η = W_net / Q.
2. Since there is no net work done (W_net = 0) and no heat added (Q = 0) in the ideal and reversible Brayton cycle, the thermal efficiency is also zero.


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Step-by-step explanation:

180(n-2)/n=90 ( this is the solution for the 90)

cross multiplying

180n-360=90n

180n-90n=360

90n=360

90n/90=360/90

n=4, the number of sides for the polygon with 90° is 4 sides

Solution for 100°

180(n-2)/n=100

180n-360=100n

180n-100n=360

80n=360

80n/80=360/80

n=4.5

Same applies to the rest 110°,125° ,150°,175°

There are 28 numbers in total that are odd numbers greater than 500 with no digit being repeated.

First, there are 18 odd numbers with four digits, and all of them are greater than 500. To see that, starting from the end of the number, there are 3 options for the last digit, 3 for the second last, 2 for the second digit, and 1 for the first digit. Multiplying one gets 3*3*2*1=18.

Second, for numbers with 3 digits, in order to be greater than 500, it must start either with 5 or with 6. If it starts with 5, there are 2 options for the last digit and 2 options for the second digit.

Thus, there are 4 different numbers in this case. Finally, if it starts with 6, then there are 3 options for the last digit and 2 options for the second digit. Thus, there are 6 different numbers in this case.

Complete question: How many different odd numbers greater than 500 can be made using some or all of the digits 1,3,5 and 6 with no digit being repeated?

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As per the permutations, there as 36 three digit numbers that are greater than 500 and which are odd one also.

The term permutation in math is defined as the way of arranging objects or numbers in order.

Here we have given that we have to identify the 3 digit numbers greater than 500 are odd

Let us make three digit numbers 1st

Here we know that if we want odd number at end then one number from three numbers can come there so

=> 3P1

Then the rest of the two numbers don't matter so

Then it can be written as

=> 3P2

Then the overall combination is written as

=> 3P1 * 3P2=18

Here now let us make four digit numbers

Then the digit odd again and it can be written as

=> 3P1

Here also the rest of the order Doesn't matter so

then it can be written as

=> 3P3 =6

Then the four digit value is

=> 3p1 * 3p3= 18

Therefore, the overall count is written as

=> Overall = 18+18= 36

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The approximate area of the green visible portion of the bottom section is around 33.51 square inches.

Let x be the width of the green visible portion of the bottom section in inches. Then, the width of the yellow top of the bottom section is x + 2, and the width of the yellow top of the upper section is (x + 2) + 2 = x + 4.

Since the area of a circle is given by A = πr^2, and the yellow top of the upper section has an area of 12.56 square inches, we can set up the equation:

12.56 = π((x+4)/2)^2

Simplifying and solving for x, we get:

x ≈ 4.02

Therefore, the width of the green visible portion of the bottom section is approximately 4.02 inches, and its area is:

A ≈ (π/4)(x+2)^2 - 12.56 ≈ 33.51 square inches.

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Answer:

your answer is $2.55

Since the line is linear, the sum of the angles should be 180 degrees

x + 28 + 73 = 180

x = 180 - 28 - 73

x = 79 degrees

Hope this helped :)

To find the slope of the line tangent to the polar curve r = 9 + 7 cos(theta) at the point (16, 0), we can use the formula:

dy/dx = (dy/dtheta) / (dx/dtheta) = (r' sin(theta) + r cos(theta)) / (r' cos(theta) - r sin(theta))

where r' = dr/dtheta.

First, we need to find r' by taking the derivative of r with respect to theta:

r' = dr/dtheta = -7 sin(theta)

Then, we can plug in the given values to find the slope at (16, 0):

dy/dx = [(r' sin(theta) + r cos(theta)] / [r' cos(theta) - r sin(theta)]

= [(-7 sin(0) sin(0) + (9 + 7 cos(0)) cos(0))] / [(-7 sin(0) cos(0)) - (9 + 7 cos(0)) sin(0))]

= (9 + 7) / (-9) = -2

Therefore, the slope of the line tangent to the polar curve r = 9 + 7 cos(theta) at the point (16, 0) is -2.

To find the slope of the line tangent to the polar curve r = 9 + 7 cos(theta) at the point (2, pi), we can use the same formula as above:

dy/dx = (r' sin(theta) + r cos(theta)) / (r' cos(theta) - r sin(theta))

First, we need to find r' by taking the derivative of r with respect to theta:

r' = dr/dtheta = -7 sin(theta)

Then, we can plug in the given values to find the slope at (2, pi):

dy/dx = [(r' sin(theta) + r cos(theta)] / [r' cos(theta) - r sin(theta)]

= [(-7 sin(pi) sin(2) + (9 + 7 cos(pi)) cos(2))] / [(-7 sin(pi) cos(2)) - (9 + 7 cos(pi)) sin(2))]

= (-2) / (7)

Therefore, the slope of the line tangent to the polar curve r = 9 + 7 cos(theta) at the point (2, pi) is -2/7.

The polar curve r = 9 + 7 cos(theta) intersects the origin when r = 0, which occurs when cos(theta) = -9/7, which is not possible since the range of cosine function is [-1, 1]. Therefore, the curve does not intersect the origin.

Since the curve does not intersect the origin, the answer is "The curve does not intersect the origin" for the equation of the tangent line in polar coordinates.

The value of x that makes the equation 3(x − 6) − 8x = − 2 + 5(2x+1) true is - 7 / 5.

An equation is an expression with an 'equal to' symbol between two expressions that have equal values.

Therefore, let's find the variable x in the equation to know what make the value of x that makes the equation true.

A variable is a number represented with letters in an equation.

3(x − 6) − 8x = − 2 + 5(2x+1)

3x - 18 - 8x  = -2 + 10x + 5

3x - 8x - 18 = 3 + 10x

-5x - 18 = 3 + 10x

-5x - 10x = 3 + 18

-15x = 21

x = 21 / -15

Therefore,

x = -  7 / 5

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Answer:

11; 2

Step-by-step explanation:

It's a formula:

a(b+c)＝ab+ac

so

x(11y+2)

＝11y×x＋2×x

＝11xy+2x

The statement "the width of the 95% confidence interval for the mean reading achievement score for a population of third graders is 10" is false.

The width of a confidence interval is calculated by subtracting the lower limit from the upper limit. In this case, the given confidence interval is (44.2, 54.2). To find the width, we subtract the lower limit (44.2) from the upper limit (54.2):

Width = Upper limit - Lower limit

Width = 54.2 - 44.2

Width = 10

From this calculation, we can see that the width of the confidence interval is indeed 10. Therefore, the statement is true. However, in the question, it states that the confidence interval is 95% confidence interval. A 95% confidence interval implies that there is a 95% probability that the true population mean falls within the interval. The width of the interval alone does not determine the confidence level. The confidence level is determined by the sample size and the variability of the data.

In conclusion, the statement is false because the width of the confidence interval is correctly calculated as 10, but it does not provide enough information to determine the confidence level of the interval.

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Answer:

-39

Step-by-step explanation:

Please give me brainliest.

Answer:

-39

Step-by-step explanation:

6-45

A buyer owes a seller $45 and has gone to pay $6. The remaining dollars which the buyer must give the seller is $39.