Find the angle in degrees for the third-order maximum for 590 nm wavelength yellow light falling on a diffraction grating having 1,680 lines per centimeter
Answers
The angle for the third-order maximum for 590 nm yellow light falling on a diffraction grating with 1,680 lines per centimeter is approximately 62.77 degrees.
To find the angle for the third-order maximum for 590 nm wavelength yellow light falling on a diffraction grating, we can use the formula:
d * sin(θ) = m * λ
Where:
d is the grating spacing (1,680 lines per centimeter, which can be converted to 16.8 lines per millimeter or 0.0168 mm),
θ is the angle of diffraction,
m is the order of the maximum (in this case, the third-order maximum),
and λ is the wavelength of light (590 nm).
Rearranging the formula, we have:
sin(θ) = (m * λ) / d
Plugging in the values:
sin(θ) = (3 * 590 nm) / 0.0168 mm
To find the angle θ, we can take the inverse sine (sin⁻¹) of both sides:
θ = sin⁻¹[(3 * 590 nm) / 0.0168 mm]
Converting the angle to degrees:
θ ≈ 62.77°
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Related Questions
SWOT analysis, PESTEL analysis, Porter's Five
Forces Analysis, and Value Chain Analysis on the
company of a company (excluding netflix india, and amazon)
Answers
SWOT Analysis: Apple Inc. has a strong brand image and innovative product portfolio, but faces challenges such as high product prices and intense competition.
PESTEL Analysis: Apple Inc. is influenced by global political stability, economic conditions, changing consumer preferences, rapid technological advancements, environmental sustainability practices, and legal regulations.
Porter's Five Forces Analysis: Apple Inc. faces moderate threats of new entrants and supplier bargaining power, high buyer bargaining power and threats of substitute products, and intense competitive rivalry.
Value Chain Analysis: Apple Inc.'s value chain includes primary activities like logistics, operations, marketing, and support activities such as procurement, technology development, and human resource management.
SWOT Analysis of Apple Inc.:
Strengths: Strong brand image, innovative product portfolio, loyal customer base.Weaknesses: High product prices, dependence on a few key products, and limited customization options.Opportunities: Emerging markets, expansion into new product categories (e.g., wearables), growing demand for smart devices.Threats: Intense competition, rapidly changing technology landscape, legal and regulatory challenges.PESTEL Analysis of Apple Inc.:
Political: Global political stability, taxation policies, intellectual property rights.Economic: Global economic conditions, exchange rates, consumer spending patterns.Sociocultural: Changing consumer preferences, lifestyle trends, environmental consciousness.Technological: Rapid technological advancements, cybersecurity risks, automation.Environmental: Environmental sustainability practices, renewable energy usage.Legal: Intellectual property laws, privacy regulations, antitrust regulations.Porter's Five Forces Analysis of Apple Inc.:
The threat of new entrants: Moderate due to high barriers to entry, and strong brand loyalty.Bargaining power of suppliers: Moderate due to Apple's size and brand power.Bargaining power of buyers: High due to numerous alternative products available.The threat of substitute products: High due to intense competition in the tech industry.Competitive rivalry: Intense competition from companies like Samsung, and Microsoft.Value Chain Analysis of Apple Inc.:
Primary activities: Inbound logistics, operations, outbound logistics, marketing, sales, and after-sales service.Support activities: Procurement, technology development, human resource management, firm infrastructure.Learn more about SWOT analysis at
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the circular disk rotates about its center. for the instant represented, the magnitude of velocity of a is 8 ft/s and the magnitude of tangential acceleration of b is 9 ft/s2. what is the magnitude of the acceleration of point a?
Answers
Answer:ddddddddddddddd
Explanation:
The work-energy theorem states that Work = Change in Kinetic Energy. A 5.0 kg crate is moving at 5.0 m/s. How much work would be needed to increase the speed to 10.0 m/s?
Answers
The work-energy theorem states that 187.5 J of work would be needed to increase the speed of a 5.0 kg crate from 5.0 m/s to 10.0 m/s.
Work is a change in kinetic energy.
A 5.0-kg crate is moving at 5.0 m/s.
How much work would be needed to increase the speed to 10.0 m/s?
The formula for the work-energy theorem is given by:
W = ΔK where W is the work done,
is the symbol for change, and K is the symbol for kinetic energy.
For a 5.0 kg crate moving at 5.0 m/s, the initial kinetic energy will be:
K1 = 0.5 × m × v1^2
where m is the mass and v1 is the initial velocity.
Substituting values,
K1 = 0.5 × 5.0 kg × (5.0 m/s)²
= 62.5 J
Now, to increase the velocity to 10.0 m/s, the final kinetic energy is given by:
K2 = 0.5 × m × v2²
Substituting values,
K2 = 0.5 × 5.0 kg × (10.0 m/s)²
= 250 J
The change in kinetic energy,
ΔK = K2 – K1
= 250 J – 62.5 J
= 187.5 J
Thus, 187.5 J of work would be needed to increase the speed of a 5.0 kg crate from 5.0 m/s to 10.0 m/s.
Answer: 187.5 J of work would be needed to increase the speed to 10.0 m/s.
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How is distance, mass and work done related?
Answers
Answer: The force exerted on an object is the mass of an object times the acceleration of the object: F = ma, where m is the mass in kg, and F is in kg m/s2 = Newton. Work is the force exerted on an object times the distance over which the force is exerted: W = Fx, where W is the work in Nm = Joule.
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૮₍˶ •. • ⑅₎ა ♡Which one of the following statements is true: The reactive power is the power dissipated in the form of heat by the network. The reactive power is the power delivered to a load without considering the effects of the power-factor angle of the load. The apparent power is the power delivered to a load without considering the effects of the power-factor angle of the load. The real power is the power associated with reactive elements that provides a measure of the energy associated with setting up the magnetic and electric fields.
Answers
Answer:
The apparent power is the power delivered to a load without considering the effects of the power-factor angle of the load
Explanation:
If I and V are the current and voltage across the load, the apparent power, = IV
Since,
apparent power = active power + reactive power
active power = IVcosФ
reactive power = IVsinФ
So, IV = IVcosФ + IVsinФ
where I = current, V = voltage and Ф = power factor angle.
We see that the apparent power is the product of the current, I and the Voltage, V without considering the power factor angle of the load.
So, the apparent power is the power delivered to a load without considering the effects of the power-factor angle of the load.
Physics , help please
Answers
At 3s we can see the slope is 0, so that means his acceleration is zero. That means he was moving at a constant velocity
At 5s we can see that the slope is negative. And from 5s to 6s the change in velocity is -5m/s^2
At 7s we can see the slope is very positive. And from 7s to 8s the change in velocity is +15m/s^2
And again, at 9s the slope is 0 so his acceleration is also zero. He’s moving at a constant velocity
If you take the integral of a velocity vs time graph, you get position. So the area underneath a velocity vs time graph is the distance traveled. Anything below the x axis is considered negative distance. We need to take the area of a triangle and the area of two rectangles to find the distance.
So, let’s do the two rectangles first. From 8s to 9s it is a width of 1 and a length of 40. So the area would be 40 meters. Let’s do the second rectangle. From 7s to 8s it is a width of 1. Then the length goes up to 25. So the area is 25 meters.
Now the triangle, the base is 1 and the height is 15. Divide 15 in half to get 7.5 meters
25 + 40 + 7.5 = 72.5 meters
The sunlight reaches the ground through radiation
Answers
Answer:
y e s
Explanation:
How is a brown object appear brown when white light is reflected on it even though brown is not a colour component of white light?
Answers
A housekeeper is cleaning the kitchen and decides to to use a ladder to reach a top shelf. As he/she is cleaning he/she is started by a mouse and falls off the ladder to the floor. As the he/she is falling, what is true about the magnitude of the Earth's gravitational force exerted on the housekeeper compared to the magnitude of gravitational force that the housekeeper exerts on the Earth?
Answers
The amount of gravitational force between both objects will be the same.
The magnitude of the Earth's gravitational force exerted on the housekeeper is calculated by applying Newton's second law of motion;
F = mg
where;
m is the mass of the housekeeper
g is acceleration due to gravity
According to Newton's third law of motion, action and reaction are equal and opposite.
The force exerted on the housekeeper by the Earth is equal in magnitude to the force exerted on the Earth by the housekeeper.
\(F_{H} = - F_{E}\)
The two forces are equal in magnitude but opposite in direction.
Thus, the correct option is " the amount of gravitational force between both objects will be the same"
The missing part of the question is below:
a. the Earth exerts the largest amount of gravitational force
b. the housekeeper exerts the largest amount of gravitational force
c. the amount of gravitational force between both objects will be the same
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Find the magnitude and direction of the net gravitational force on mass A due to masses B and
C in the figure. Each mass is 2 kg.
a. 2.8x10^-8N, to the right
b. 2.54x10^-8N, to the right
c. 3.4x10^-8N, to the left
d. 3.4x10^-8N, to the right
Answers
Answer is A 2.8 x 10^-8 N, to the right
The net gravitational force on mass A due to masses B and C is required.
The correct option is a. \(2.8\times 10^{-8}\ \text{N}\) to the right.
G = Gravitational constant = \(6.674\times 10^{-11}\ \text{Nm}^2/\text{kg}^2\)
\(r_{AB}\) = Distance between A and B = 0.4+0.1 = 0.5 m
\(r_{AC}\) = Distance between A and C = 0.1 m
\(m_A=m_B=m_c\) = Mass of each particle = 2 kg
The required force is
\(F_A=F_{AB}+F_{AC}\\ =\dfrac{Gm_Am_B}{r_{AB}^2}+\dfrac{Gm_Am_C}{r_{AC}^2}\\ =Gm^2\left(\dfrac{1}{r_{AB}^2}+\dfrac{1}{r_{AC}^2}\right)\\ =6.674\times 10^{-11}\times 2^2\left(\dfrac{1}{0.5^2}+\dfrac{1}{0.1^2}\right)\\ =2.8\times 10^{-8}\ \text{N}\)
The magnitude of force will be \(2.8\times 10^{-8}\ \text{N}\)
The direction will be towards the right since C is closer to A.
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A car traveling at 2 m/s increases its speed to 14 m/s in 4s. Its aceleration is 3.045m/s m/s2 a = (vf-vi)t
Answers
The acceleration of a car traveling at 2 m/s and increases its speed to 14 m/s in 4s is 3m/s².
How to calculate acceleration?The acceleration of a moving body is the amount by which a speed or velocity increases. It is the change in velocity with respect to time.
The acceleration of a moving body can be calculated using the following formula:
a = (v - u)/t
Where;
a = accelerationv = final velocityu = initial velocityt = timeAccording to this question, a car is traveling at 2 m/s and increases its speed to 14 m/s in 4s. The acceleration can be calculated as follows:
a = (14 - 2)/4
a = 12/4
a = 3m/s²
Therefore, the acceleration of a car traveling at 2 m/s and increases its speed to 14 m/s in 4s is 3m/s².
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A vessel containing 200 ml hydrogen gas at pressure 500torr at temperature 10 degree C.Find its volume when pressure increased to 700 torr and temperature 20degree C.
Answers
Answer:
When the pressure and the temperature are increased the volume is 285.7 ml.
Explanation:
We can find the new volume by using the Ideal Gas Law:
\( PV = nRT \)
Where:
P: is the pressure
V: is the volume
n: is the number of moles
R: is the gas constant
T: is the temperature
Initially, when V₁ = 200 ml, P₁ = 500 torr and T₁ = 10 °C, we have:
\( nR = \frac{P_{1}V_{1}}{T_{1}} \) (1)
And finally, when P₂ = 700 torr and T₂ = 20 °C, we have:
\( nR = \frac{P_{2}V_{2}}{T_{2}} \) (2)
By equating (1) with (2):
\( \frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}} \)
\(V_{2} = \frac{P_{1}V_{1}T_{2}}{T_{1}P_{2}} = \frac{500 torr*200 ml*20 ^{\circ} C}{10 ^{\circ} C*700 torr} = 285.7 ml \)
Therefore, when the pressure and the temperature are increased the volume is 285.7 ml.
I hope it helps you!
. Why are the Jovian planets formed from materials different from the terrestrial planets?
a. Terrestrial planets were protected by the asteroid belt between Mars and Jupiter.
b. The composition of elements in a planet was a random process after the big bang.
c. When the solar system first formed, the heaviest elements sank toward the center of the nebulae and the lightest elements floated out.
d. Gaseous Jovian planets, formed farther away from the heat of the Sun, are formed from light weight nebulae "dust."
e. Only the terrestrial planets formed from planetesimals.
Answers
The Jovian planets are formed from materials different from the terrestrial planets for the reason that gaseous Jovian planets, formed farther away from the heat of the Sun, are formed from light weight nebulae "dust."
A Jovian planet, also known as a gas giant, is a huge planet that has a primarily gaseous composition. The Jovian planets include Jupiter, Saturn, Uranus, and Neptune. They are primarily made up of hydrogen and helium, and they have enormous atmospheres.Jovian planets are formed farther away from the heat of the Sun, so they are formed from lighter-weight nebulae "dust." Terrestrial planets, on the other hand, are formed nearer to the Sun, so they are formed from heavier-weight nebulae "dust." The density of the materials that make up the Jovian planets is lower than that of the terrestrial planets due to this. This means that the Jovian planets have lower densities and a greater volume than the terrestrial planets.
Hence, the correct option is d. Gaseous Jovian planets, formed farther away from the heat of the Sun, are formed from light weight nebulae "dust."
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Which situation provides the best evidence that a chemical reaction is taking place?
Help please !!!!
Answers
Answer:
A new product is formed
Explanation:
Physical reactions generally result in a change of state (solid, liquid, gas). Chemical reactions generally result in the production of a new product/ substance (structure/ properties are different than the intial reactants'... example= burning wood)
What pattern would you say matches creating a negative ion?
What pattern would you say matches creating a positive ion?
Answers
The pattern that would match creating a negative ion is that they can gain one electron and become 1-.
For example Group 16 elements gain two electrons to become 2-, and Group 15 elements gain three electrons to become 3-.
The pattern that would match creating a positive ion is when they give up one electron and become +1.
In the case of Group 2 elements give up two electrons to become 2+, and Group 3 give up three electrons to become 3+
What is an ion?An ion is described as an atom or molecule with a net electrical charge.
We know that some elements can form ions with two or more different charges. Iron (Fe), for example, can form both an iron ion with 2+ (Fe²⁺) and an iron ion with 3+ (Fe³⁺).
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Which pair of elements primarily make up a nebula?
hydrogen and helium
helium and oxygen
carbon and oxygen
hydrogen and oxygen
Answers
Answer: hydrogen and helium
Explanation:
A rock is dropped from a sea cliff, and the sound of it striking the ocean is heard 2.9 s later. If the speed of sound is 340 m/s, how high is the cliff?
Answers
Answer:
h = 493 m
Explanation:
Given that,
A rock is dropped from a sea cliff, and the sound of it striking the ocean is heard 2.9 s later.
The total distance covered by the rock is 2d. We know that,
Speed = distance/time
\(v=\dfrac{2d}{t}\\\\d=\dfrac{vt}{2}\\\\d=\dfrac{340\times 2.9}{2}\\\\d=493\ m\)
So, the height of the cliff is equal to 493 m.
Which facility relies on a no renewable source of energy
Answers
Answer:
Coal
Explanation:
what is that distance traveled by an arrow going 78 m/s for 5 seconds
Answers
Explanation:
velocity=distance/time
distance= velocity×time
distance= 78×5=390m
Consider the polynomial
() = −0. 14 − 0. 153 − 0. 52 − 0. 25 + 1. 2
The true value of its derivative at x=0. 5 is ′
(0. 5) = −0. 9125. Use backward, forward, and centered
first finite differences to estimate the derivative numerically if the step size ∆ = 0. 25, and determine
the percent error between the true value and each of the estimated values (percent error is given by
= −
converted to a percentage. ) What value of ∆ would you have to use for the backward and forward
finite differences to get the same percent error as the centered finite difference (hint: it should be less
than 0. 25. )
Answers
The backward finite difference method for estimating the derivative at x=0.5 is:
(f(0.5) - f(0.25)) / (0.5 - 0.25) = (-0.14 - (-0.4025)) / (0.5 - 0.25) = 0.2625 / 0.25 = 10.5
The percent error between this estimate and the true value is:
|(10.5 - (-0.9125)) / (-0.9125)| * 100% = |11.4125 / (-0.9125)| * 100% = 12.48%
The forward finite difference method for estimating the derivative at x=0.5 is:
(f(0.75) - f(0.5)) / (0.75 - 0.5) = (-0.6275 - (-0.14)) / (0.75 - 0.5) = -0.4875 / 0.25 = -1.95
The percent error between this estimate and the true value is:
|(-1.95 - (-0.9125)) / (-0.9125)| * 100% = |-1.0375 / (-0.9125)| * 100% = 1.14%
The centred finite difference method for estimating the derivative at x=0.5 is:
(f(0.75) - f(0.25)) / (0.75 - 0.25) = (-0.6275 - (-0.4025)) / (0.75 - 0.25) = -0.225 / 0.5 = -0.45
The percent error between this estimate and the true value is:
|(-0.45 - (-0.9125)) / (-0.9125)| * 100% = |0.4625 / (-0.9125)| * 100% = 0.51%
To get the same percent error as the centred finite difference, we would have to use a step size of ∆ = 0.125.
This is because a smaller step size means a smaller difference between the estimates and the true value, and therefore a smaller percent error.
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If the temperature in the past was 2.9 C higher than today what would the corresponding change in the Fahrenheit temperature have been?
Answers
Answer:
1 deg C = 5/9 deg F (Ex. 212 F - 32) * 5/9 = 100
So deg F = 9/5 deg C = 9/5 * 2.9 = 5.2 deg F
A stationary 3-kg hard steel ball is hit head-on by a 1-kg hard steel ball moving to the right at 4 m/s. After the collision, the 3-kg ball moves to the right at 2 m/s. What is the velocity (speed and direction) of the 1-kg ball after the collision?
Answers
From conservation of momentum we have that:
\(\begin{gathered} 1(4)+3(0)=1v+3(2) \\ 4=v+6 \\ v=4-6 \\ v=-2 \end{gathered}\)Therefore the velocity of the 1 kg ball after the collision is 2 m/s to the left.
hello what is quantum physics
Answers
Answer:
It is a fundamental theory in physics that provides a description of the physical properties of nature at the scale of atoms and subatomic particles.
calculate the time taken to raise the temperature of 1.5 kg of water in a kettle from 15°C to 100°C given that specific heat capacity of water is 4200 J/kg/K and the heater is rated 250V , 2kW
Answers
Answer:
270 s or 4.5 min
Explanation:
First find the amount of heat needed:
q = mCΔT
q = (1.5 kg) (4200 J/kg/K) (100 − 15) K
q = 535,500 J
q = 535.5 kJ
Power is energy per time.
P = E / t
2 kW = 535.5 kJ / t
t = 270 s
Q1 What is the velocity of the "Right" ball after the elastic collision below? Left ball heading rightwards btw.
Before: Left Ball Velocity= 2.0 m/s Left Ball Mass 0.25 kg; Right Ball Velocity= 0 m/s Right Ball Mass= 0.25 kg
After:?
Answers
Answer:
In an elastic collision, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision. This means that we can use the conservation of momentum to determine the velocity of the right ball after the collision.
The momentum of an object is equal to its mass multiplied by its velocity, so the initial momentum of the left ball is 0.25 kg * 2.0 m/s = 0.5 kgm/s. Since the initial velocity of the right ball is 0, the total initial momentum of the two balls is 0.5 kgm/s.
After the collision, the total momentum of the two balls must still be 0.5 kg*m/s. Since the mass of the two balls is the same, this means that the velocity of the right ball after the collision must be 2.0 m/s, which is the same as the initial velocity of the left ball.
Therefore, the velocity of the right ball after the elastic collision is 2.0 m/s.
Sean's bike begins to rust in the winter. what tells Sean that a chemical change is happening?
Answers
Answer:
The metal is beginning to rust
Explanation:
Because when it is out side a small layer of condensation begins to form which the turns to rust as it is outside colliding with the cold air
Help!!
I'm not sure my answer is correct.
The problem is attached!
Answers
Answer:
where's ur answer?
Explanation:
hihi
a small but rigid u shaped wire carrying a 5.0 a current is placed inside a solenoid the solenoid is 17 cm long and has 800 loops of wire and the current in each loop is
Answers
The current in each loop of the solenoid is 6.25 A. current is placed inside the solenoid, we can assume that the current passing through each loop is the same.
The solenoid is 17 cm long and has 800 loops of wire. Since the wire carrying the 5.0 A current is placed inside the solenoid, we can assume that the current passing through each loop is the same.
To find the current in each loop, we can use the formula:
I_solenoid = N * I_wire
Where:
I_solenoid is the current in the solenoid,
N is the number of loops,
I_wire is the current in the wire.
Plugging in the values, we have:
I_solenoid = 800 * I_wire
5.0 A = 800 * I_wire
Solving for I_wire, we get:
I_wire = 5.0 A / 800 = 0.00625 A
Therefore, the current in each loop of the solenoid is 6.25 A.
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In an experiment, a ringing bell is placed in a vacuum jar that does not have any air in it. What best describes why the bell is seen vibrating but not heard?
Answers
Answer:
C. Light does not need a medium to travel through, but since sound waves must have a medium to vibrate, sound is not created where no air is present.
Explanation:
The reason the bell is seen to vibrate but not heard is that unlike light, which does not require a medium to pass through, sound waves require an air-filled space in order to vibrate. Option C is correct.
What is a sound wave?A sound wave is produced when a medium begins to vibrate. When an entity vibrates, a pressure wave is formed, which causes sound.
Light does not need a medium to travel through, but since sound waves must have a medium to vibrate, the sound is not created where no air is present best describes why the bell is seen vibrating but not heard.
The complete question is attached.
Hence option C is correct.
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Two parallel conducting plates are separated by 12.0 cm, and one of them is taken to be at zero volts. (a) What is the electric field strength between them, if the potential 5.7 cm from the zero volt plate is 450 V
Answers
The electric field strength between two parallel conducting plates separated by 12 cm and with one of them taken to be at zero volts is 337.5 N/C. Here's how to calculate it.Step-by-step explanation:We know that,Electric field (E) = potential difference (V) / distance (d)In this case, the distance between the two plates is d = 12 cm = 0.12 m
Let's first find the potential difference between the two plates. We are given that the potential at a distance of 5.7 cm (0.057 m) from the zero volt plate is 450 V. Since the plates are parallel, the potential difference between them will be proportional to the distance from the zero volt plate. Thus, at a distance of 0.12 m, the potential difference will be:V = (0.12 / 0.057) x 450 V ≈ 942.11 VNow we can find the electric field strength between the plates:E = V / d = 942.11 V / 0.12 m ≈ 7850.83 N/CHowever, this electric field is not uniform between the plates.
To find the electric field strength at a distance of 5.7 cm from the zero volt plate, we need to use the following formula:V = Edwhere d is the distance from the zero volt plate. Rearranging, we get:E = V / d = 450 V / 0.057 m = 7894.74 N/CThis is the electric field strength at a distance of 5.7 cm from the zero volt plate. The main answer is 7894.74 N/C, but the question asks for the electric field strength between the plates. Since this electric field is not uniform, we cannot use this value. Instead, we use the value we calculated earlier, which is 7850.83 N/C (rounded to three significant figures).
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