Find the components of vtot along the x and y axes in Figure 3.25, where = 23.0° and vtot = 7.56 m/s.

vtot, x =




m/s

vtot, y =

m/s

The approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

To approximate the heat transfer through the air layer in the double-paned window, we can assume that the glass layers have a negligible impact on the heat flow. The heat transfer can be calculated using Fourier's Law of Heat Conduction, which states that the heat flow (Q) is proportional to the temperature difference (ΔT) and inversely proportional to the thickness (L) and thermal conductivity (k) of the material.

First, we need to calculate the effective thermal conductivity of the air layer due to its thickness and the thermal conductivity ratio between air and glass. Let's denote the thermal conductivity of air as k_air and the thermal conductivity of glass as k_glass. Since glass has a thermal conductivity roughly 36 times greater than air, we have k_glass = 36 * k_air.

Next, we calculate the effective thermal conductivity of the air layer as:

k_eff = (k_air * L_air) / (L_air + k_glass)

Substituting the given values, we have:

k_eff = (k_air * 0.0165 m) / (0.0165 m + 0.005 m) = 0.01309 * k_air

Now, we can calculate the heat flow per second through the air layer using the formula:

Q = (k_eff * A * ΔT) / L_air

Substituting the given values, we get:

Q = (0.01309 * k_air * 0.760 m^2 * 23.0 K) / 0.0165 m = 24.4 J/s

Therefore, the approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

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A ripcord system pulls a closing pin, which releases a spring-loaded pilot chute, and opens the container; from which the parachute comes out.

If a skydiver is unable to open her/his parachute, an automatic activation device will automatically open the parachute.

A parachute works by forcing air into the front of it and creating a structured 'wing' under which the canopy pilot can fly. Parachutes are controlled by pulling down on steering lines which change the shape of the wing, cause it to turn, or to increase or decrease its rate of descent.

Answer:

The answer is D

Explanation:

The chloroplast absorbs sunlight for energy not the cell wall

Answer:

Plasma is a phase of matter that makes up stars.

Answer: I think you have the correct answer. (I think it is false.)

Explanation: The Earth's magnetic field is mostly caused by electric currents in the liquid outer core. The Earth's core is hotter than 1043 K, the Curie point temperature above which the orientations of spins within iron become randomized. Such randomization causes the substance to lose its magnetization.

Explanation:

The orbiting period of a satellite at a height h from earth' surface is

T=2πr32gR2

where r=R+h.

Then, T=2π(R+h)R(R+hg)−−−−−−−−√

Here, R=6400km,h=1600km=R/4

T=2πR+R4−−−−−−√R(R+R4g)−−−−−−−−−⎷=2π(1.25)32Rg−−√

Putting the given values,

T=2×3.14×(6.4×106m9.8ms−2)−−−−−−−−−−−−√(1.25)32=7092s=1.97h

Now, a satellite will appear stationary in the sky over a point on the earth's equator if its period of revolution around the earthh is equal to the period of revolution of the earth up around its own axis whichh is 24h. Let us find the height h of such a satellite above the earth's suface in terms of the earth,'s radius.

Let it be nR.Then

T=2π(R+nR)R(R+nRg)−−−−−−−−−−√

=2π(Rg)−−−−−√(1+n)32

=2×3.14(6.4×106m/s9.8m/s2)−−−−−−−−−−−−−−−⎷(1+n)32

(5075s)(1+n)32=(1.41h)(1+n)32

For T=24h, we have (24h)=(1.41h)(1+n)32

or (1+n)32=241.41=17

or 1+n(17)23=6.61

or n=5.61

The height of the geostationary satellite above the earth's surface is nR=5.61×6400km=6.59×104km.

The kinetic energy of the flywheel after 1 minute of rotation, given that it has a mass of 50 and radius of 40 cm is 32.4 KJ (Option D)

We'll begin by obtaining the velocity of the flywheel. This is shown below:

v = at

v = 0.6 × 60

v = 36 m/s

Finally, we shall determine the kinetic energy of the flywheel. Details below:

KE = ½mv²

KE = ½ × 50 × 36²

KE = 25 × 1296

KE = 32400 J

Divide by 1000 to express in KJ

KE = 32400 / 1000

KE = 32.4 KJ

Thus, the kinetic energy is 32.4 KJ (Option D)

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Answer:

Green

Explanation:

This process of color subtraction can be represented by knowing that cyan light (a mixture of blue and green) shines upon the same magenta filter. Magenta absorbs its complementary color - green. Thus, green is subtracted from cyan light.

Answer:

No. The torque required after attaching the rope is the same as it was before attaching the rope.

L = r X F

The torque was not increased by attaching the rope.

Answer:

4

2

1

3

Explanation:

Be safe, lovelies <3

Answer:

protons: 6

electrons: 6

neutrons: 8

Explanation:

atomic number -> number of protons -> 6

mass number -> number of protons + number of neutrons

    so 14-6 = 8. 8 neutrons

this atom is neutral (net charge is 0), so the number of electrons is the same as the number of protons, which is 6

According to Doerbecker and Ernst (1996) and Francart et al. (2011), interaural time difference (ITD) and interaural level difference (ILD) are the two primary auditory cues used by binaural hearing. The delay between each ear is known as ITD.

What technique best localizes sound between the two ears?

Rayleigh's view of horizontal sound localization has come to be known as the “duplex” theory: that sound localization at low frequencies relies on differences in phase at the two ears, or ITDs, and that high-frequency localization relies on interaural differences in sound level (ILDs).

What two variables affect sound localization?

The variation in the loudness of the sound in each ear and the time it took for the sound to reach each ear are two elements that affect how the sound is localized.

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θ = 39.7º is the angle in degrees that the string makes with respect to the vertical using Newtons law.

In each exercise, we construct the equations at the equilibrium point using Newton's second law for the sphere. We'll assume that plate 1 is on the left for this exercise.

Y Axis

    Y= -W = 0 = W

X axis

       X= - F_{e2} + Tₓ = 0

Let's utilize trigonometry to determine the tension's component parts. We gauge the angle in relation to the vertical

        sin θ = Tₓ / T

        cos θ = T_{y} / t

        Tₓ = T sin θ

        T_{y} = T cos θ

Gauss's law can be used to determine the electric field of each leaf. Since a cylinder forms a Gaussian surface, the component of the field perpendicular to the cylinder's base is the one containing electric flow.

 F = ∫ E. dA

The flow is towards both sides of the plate in this instance, and the scalar product is reduced to the algebraic product.

F = 2E A = q_{int} / ε₀

let's use the concept of surface charge density

       σ = q_{int} / A

we substitute

       2E A = σ A /ε₀

         E = σ / 2ε₀

    T cos θ = mg

         - q σ₁ / 2ε₀  - q σ₂ /2ε₀  + T sinθ = 0

we introduce t in the second equations

         - q /2 ε₀  (σ₁ + σ₂) + (mg / cos θ) sin θ = 0

         mg tan θ = q /2ε₀   (σ₁ + σ₂)

         θ = tan -1 (q / 2ε₀ mg (σ₁ + σ₂)

data indicates the mass of 0.26 g = 0.26 10⁻³ kg

give the charge density on plate 2, suppose ab = 10 10⁻⁶ C / m²

let's calculate

        θ = tan⁻¹ (9.0 10⁻¹⁰ (30 + 10) 10⁻⁶ / (2  (6.25 10⁻¹² *0.26 10⁻³ 9.8))

        θ = tan⁻¹ 8.3 10⁻¹)

        θ = 39.7º

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Answer:

31.84

Explanation:

To find the magnitude of the sum of the three vectors, first, we need to add the vectors component-wise. Then, we can find the magnitude of the resulting vector.

Add the vectors component-wise:

Vector A + Vector B + Vector C = [13+13+0, 8+0+1, 0+8+8] = [26, 9, 16]

Find the magnitude of the resulting vector:

The magnitude of a vector [x, y, z] is given by the formula:

magnitude = sqrt(x^2 + y^2 + z^2)

Plugging in the values from the resulting vector:

magnitude = sqrt(26^2 + 9^2 + 16^2)

magnitude = sqrt(676 + 81 + 256)

magnitude = sqrt(1013)

magnitude ≈ 31.84

The magnitude of the sum of the three vectors is approximately 31.84.

Hope this helps!

The hypothesis will be:

H₀ = The amount of salt added to ice will not affect the rate at which the ice will melt.

H₁ =  The amount of salt added to ice will affect the rate at which the ice will melt.

The independent variable which is can be changed by increasing the rate of salt added to the equation.

The dependent variable which is ice will change or melt in response as it will decrease if the rate of the salt added increases.

Salt does not really lower the temperature of an ice cubes, it is known to just lowers their freezing point, that is lowers their melting point.

Note that if salt is around, ice cubes are known to be colder to be solid, and they tend to melt at a temperature that is said to be lower than the freezing point of pure water.

If  the ionic compound salt is known to be added, it tends to lowers the freezing point of the water, which implies that the ice on the ground is not able to freeze that layer of water at all.

Therefore, The hypothesis will be:

H₀ = The amount of salt added to ice will not affect the rate at which the ice will melt.

H₁ =  The amount of salt added to ice will affect the rate at which the ice will melt.

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The potential energy changes indicated by C and B involve energy lost by the surroundings. Therefore, option B is correct.

Potential energy is the energy possessed by an object due to its position or condition. It is often associated with the potential for the object to do work or undergo a change. The concept of potential energy arises from the interactions between objects or within a system.

Potential energy is converted into other forms of energy, such as kinetic energy (energy of motion) when the object or system undergoes a change or is acted upon by external forces.

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Your question is incomplete, most probably the correct answer is this:

Based on the diagram, which statement explains how energy is conserved during this chemical reaction? (A) is also gained by the surroundings. B. The potential energy changes indicated by C and B involve energy lost by the surroundings. C. The potential energy lost by the reaction system (C) is also lost by the surroundings. D. The potential energy lost by the reaction system (B) is gained by the surrounding​

Answer:

The medium increases in temperature while remaining in the same phase

Explanation:

The speed of a sound wave is increased when the medium increases in temperature while remaining in the same phase.

The temperature coefficient of a sound wave is defined as the measure of increase in the velocity of the sound wave per unit rise in its the temperature.

Here,

The speed of a sound wave is affected by various factors in the medium through which it propagates. Among them, speed of the wave is mostly influenced by the temperature of the medium.

The speed of a sound wave in a medium is directly proportional to the square root of its absolute temperature. So,

       v \(\alpha\) √T

where v is thee speed of the sound wave and T is the absolute temperature.

Therefore,

As the temperature of the medium increases, the kinetic energy of the wave particles increases. Thus the speed of the sound wave is increased. As a result, the sound waves will move faster.

Hence,

The speed of a sound wave is increased when the medium increases in temperature while remaining in the same phase.

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It is important for the measurements that the track is level for rolling motion in physics because the rolling objects only move on the tract that is leveled correctly.

The rolling motion is a fusion of translational motion and rotational motion. For a body, the motion of the center of mass is the adaptation motion of the body. During the rolling motion of a body, the exterior contact gets disfigured a little temporarily. A combination of translational and rotational motions happens during the rolling motion of an object. To define rolling motion, we must recognize the forces like angular momentum and torque. It is a merger of two types of motion i.e. translational and rotational motion. The translational motion of a body is the movement of the whole body from one place to another.

So we can conclude that Rolling motion is that usual combination of encircling and translational motion that we see everywhere and every day.

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Answer:

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Explanation:

Hey, wanna pair our account on Brainly so we can share the perks? https://brainly.com/invite/a88a52bd8e2ff3030b43b9056dfb032b?utm_source=invite&utm_medium=link&utm_campaign=bfp_parental_feed&utm_term=parent

Answer:

Explanation:

The vector in unit vector notation is:

B = (-1.33m)i + (2.81m)j

To find the direction relative to the x-axis. Do inverse tangent of opposite/adjacent

\(tan^-^1=|\frac{2.81}{1.33}| = 2.11\\180-2.11=177.89\)

This is relative to the positive x-axis

2.11 would be the correct answer if relative to the negative x axis

Answer: Height of object = 29.13475

Hope this helps!

Answer: 29.12 Meters.

Explanation:

When reading the simile "Bolt runs as fast as lightning," the most appropriate visual interpretation would be that "Bolt runs very fast."

This simile compares Bolt's speed to that of lightning, which is known for its incredible swiftness. The intention is to emphasize Bolt's exceptional speed by equating it to the rapid movement of lightning.

While the simile highlights Bolt's remarkable speed, it does not specify the manner in which he runs or the impact of each step. Therefore, the options suggesting Bolt runs in a straight line, in a wavy manner, or that each step produces thunder are not directly implied by the simile itself. These additional details go beyond the comparison of speed and introduce elements that are not explicitly mentioned.

Hence, the most accurate interpretation based solely on the simile is that Bolt runs very fast, comparable to the speed of lightning.

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It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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Answer:

Hey I go to GOC send me your number

Explanation:

Answer:

Please see below as the answer is self- explanatory.

Explanation:

Answer:

Charged

Explanation:

When an atoms loses or gains electrons they become charged(ion)

When an atom loses electrons it becomes positively charged and it is called a Cation

When an atom gains electrons it becomes negatively charged and it is called an Anion

Answer:

F' = 16 F

Hence, the electric force between charges becomes sixteen times its initial value.

Explanation:

The electric force between the two charges is given by the Colomb's Law:

\(F = \frac{KQ_1Q_2}{R^2}\) ------------------- eq(1)

where

F = electric force

K = Colomb's Constant

Q₁ = magnitude of the first charge

Q₂ = magnitude of the second charge

R = Distance between charges

Now the magnitudes of the charges are doubled and the distance between them is halved. Therefore:

\(F' = \frac{K(2Q_!)(2Q_2)}{(\frac{R}{2})^2}\\\\F' = 16 \frac{KQ_1Q_2}{R^2}\)

using equation (1):

F' = 16 F

Hence, the electric force between charges becomes sixteen times of its initial value.

Social structure impacts individuals like Jeff through opportunities and constraints. Mary's treatment can affect Jeff's sense of belonging at the community center, while positive treatment from Linda can foster personal growth and well-being.

1) Social Structure and Clients like Jeff:

The opportunities, resources, and limitations people like Jeff's face are shaped by social structure, which has a tremendous impact on their life.

For instance, the social structure of the economy may restrict Jeff's access to prospects for quality education and employment if he comes from a low socioeconomic background, which would have an effect on his general well-being and chances in life. His background, morals, and aspirations may also be greatly influenced by family dynamics, which themselves are shaped by social norms and values.

Government policies and social welfare programs can also affect Jeff's access to essential services like healthcare, housing, and social support. Thus, understanding social structures is crucial for identifying the factors that might influence Jeff's life choices, opportunities, and outcomes.

2) Mary's Treatment of Jeff at the Community Center:

Mary's treatment of Jeff at the community center can have a significant impact on his overall experience there. If Mary is welcoming, supportive, and inclusive, Jeff is more likely to feel valued and accepted. This positive treatment may lead to Jeff forming positive social connections with others at the center and feeling a sense of belonging.

On the other hand, if Mary is dismissive, unfriendly, or shows favoritism towards certain individuals, it could lead to Jeff feeling isolated or excluded. Negative treatment may discourage him from actively participating in center activities or engaging with others, leading to a less fulfilling experience.

Mary's behavior as a staff member can shape the overall social environment at the community center and influence how other members interact with Jeff. Positive treatment from staff can foster a sense of community and trust among participants, while negative treatment can undermine the center's inclusive atmosphere.

3) Potential Positive Outcome from Linda's Treatment of Jeff:

If Linda treats Jeff with respect, empathy, and understanding, it can create a positive and supportive relationship between them. Linda's compassionate approach can build trust with Jeff and encourage him to share his thoughts, feelings, and concerns openly.

By maintaining an open line of communication and actively listening to Jeff, Linda may gain insight into his needs and preferences, allowing her to tailor her interactions and support accordingly. This positive dynamic can lead to a stronger therapeutic relationship between Linda and Jeff, facilitating personal growth, self-awareness, and positive changes in Jeff's life.

Linda's positive treatment of Jeff can contribute to a safe and nurturing environment, where he feels comfortable exploring personal challenges and working towards his goals. This outcome can be beneficial for Jeff's emotional well-being and overall development.

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