The required values are:
Maximum value is 7, occurring at (0, 0, -5) and (0, 0, 5).
Minimum value is -17, occurring at (-4, 3, 0) and (2, -3, 0).
The function
f(x, y, z) = x + 2y
can be subject to the constraints
y² + z² = 25
and
x + y + z = −2.
The maximum and minimum values of the function are asked to be found.
We can solve this by using the method of Lagrange multipliers.
Step 1: Setting up the equations
Let the constraints be
g₁(y, z) = y² + z² - 25
and
g₂(x, y, z) = x + y + z + 2,
and let λ be the Lagrange multiplier.
Then we get the following equations:
f(x, y, z) = x + 2y
g₁(y, z) = y² + z² - 25
g₂(x, y, z) = x + y + z + 2
Step 2: Finding the partial derivatives
We can find the partial derivatives of f, g₁, and g₂ as follows:
fₓ = 1,
fₓ = 2,
fₓ = 0
g₁ᵧ = 2y,
g₁_z = 2z
g₂ₓ = 1,
g₂ᵧ = 1,
g₂_z = 1
Step 3: Setting up the system of equations
We can now set up the system of equations by equating the partial derivatives:
fₓ = λg₂ₓ
fᵧ = λg₂ᵧ
f_z = λg₂_
zg₁(y, z) = 0g₂(x, y, z) = 0
We get the following system of equations:
1 = λ2y
= λ1 = λx + y + z + 2
= 0y² + z² - 25 = 0
Step 4: Solving the system of equations
From the first equation, we get λ = 1.
From the second and third equations, we get:
y + z = -1x
= -y - z - 2
Substituting the value of x in the equation
y² + z² - 25 = 0,
we get:
(-y - z - 2)² + y² + z² - 25 = 0
Expanding and simplifying, we get:
3y² + 3z² + 2yz - 4y - 4z - 21 = 0
We can now use this equation to solve for y and z. Since we are asked to find the maximum and minimum values, we can find the critical points of the function by finding the stationary points of the function.
These are the points where the partial derivatives of the function are zero.
We can differentiate the function
f(x, y, z) = x + 2y
with respect to x, y, and z to get:
fₓ = 1fᵧ
= 2f_z
= 0
We can now substitute the values of y and z in the function to get
:f(x, y, z) = -3 - 2z
We can see that the value of f(x, y, z) depends only on the value of z. Hence, we can find the maximum and minimum values of
f(x, y, z)
by finding the maximum and minimum values of z, subject to the constraint
y² + z² = 25
and
x = -y - z - 2.
Step 5: Finding the maximum and minimum values
To find the maximum and minimum values of z, we can use the method of substitution. From the equation
y² + z² = 25,
we get
y = ±sqrt(25 - z²).
Substituting this in the equation
x = -y - z - 2, we get:
x = -sqrt(25 - z²) - z - 2
or
x = sqrt(25 - z²) - z - 2
We can now substitute these values of x and y in the function
f(x, y, z) = -3 - 2z
to get:
f(z) = -3 - 2z
or
f(z) = -1 + 2z
We can now find the maximum and minimum values of f(z) by finding the maximum and minimum values of z, subject to the constraint
y² + z² = 25.
Since y can take on two values, we can find two sets of maximum and minimum values of f(z). We can tabulate the values as follows:
z y f(z)
Maximum/Minimum
-5 0 7 Maximum
5 0 -17 Minimum
0 -5 -3 Maximum
0 5 -1 Minimum
Hence, we can see that the maximum value of f(x, y, z) is 7, occurring at (0, 0, -5) and (0, 0, 5).
The minimum value of f(x, y, z) is -17, occurring at (-4, 3, 0) and (2, -3, 0).
Therefore, the required values are:
Maximum value is 7, occurring at (0, 0, -5) and (0, 0, 5).
Minimum value is -17, occurring at (-4, 3, 0) and (2, -3, 0).
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CAN SOMEONE HELP? ⚠️ I WILL GIVE ANY POINTS PLEASE I AM SO CONFUSED EVEN IF ITS JUST THE ANSWER I HAVE SO MUCH TO DO IF SOMEONE CAN HELP ME
HELP ME PLEASE!!! I cant do this and it is due in 10 minutes.
25% of 7th-grade classrooms are math classrooms. The 7th-grade area has three math classrooms. How many classrooms are there in the seventh-grade area?
Answer:
12 classrooms
Step-by-step explanation:
We know that there are 3 math classrooms, and three math classrooms is 25% of all of the classrooms. We need to know the total number of classrooms, which is 100% of the classrooms, so we do 25% times 4. Because we did 25 times 4, we have to do 3 classrooms times 4, and we get 12 classrooms.
Here's a ratio explanation.:
Percent of classrooms : Classrooms
25 : 3
100 : 12
how do I find the volume?
Answer:
Width x length
Step-by-step explanation:
Find the width or how wide it is
Then find the length or how long it is
multiply those
Data that are accurate, consistent, and available in a timely fashion are considered: A) Oracle-based. B) Microsoft-based. C) high-quality. D) low-quality.
Data that are accurate, consistent, and available in a timely fashion are considered C) high-quality.
High-quality data is characterized as being reliable, consistent, and timely. High-quality data offers a strong foundation for analysis and decision-making because it is accurate, error-free, and consistent.
It is a valuable asset for organizations because it promotes accurate reporting and analysis, increases operational efficiency, and allows for informed decision-making. Although database management systems like Oracle and Microsoft SQL Server can assist with managing and storing data, the quality of the data is unrelated to the particular technology or program employed.
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If a = -9 and b= -4, what is the value of a + b? -5, 5, -13, 13.
Answer:
-13
Step-by-step explanation:
simply add
Answer:
Step-by-step explanation:
a+b
-9+(-4)
-9-4
-13
332,519,000 in scientific notation
Answer:
332519000 in scientific notation is 3.32519 x 10^8
Step-by-step explanation:
Hope that helped
Answer:
The form is a * 10ᵇ where 0 < a < 10
A school wants to buy a chalkboard that measures 1 meter by 2 meters. The chalkboard costs $31.00 per square meter. How much will the chalkboard cost?
Answer:
62$
Step-by-step explanation:
Board in square meters = 2×1 = 2 m²
Cost per square meter = $31.00
Total cost = 31×2 = $62.00
Answer:
The cost of the chalkboard is $27.74
Step-by-step explanation:
right!!
what is 240 + 90 equal
Answer:
330
Step-by-step explanation:
MATHZ
11.
Martin is organising a summer fair.
He needs bread buns and burgers for the barbecue.
Bread buns are sold in packs. Each pack contains 40 bread buns.
Burgers are sold in packs. Each pack contains 24 burgers.
Martin buys exactly the same number of bread buns as burgers.
What is the least number of each pack that Martin buys?
The least number of each pack that Martin can buy is 5 packs of burger and 3 packs of bread buns.
Since the packs of bread buns contain 40 bread buns and each pack of burgers contains 24 burgers, then we'll calculate the multiples of each number. This will be:
Multiples of 24 = 24, 48, 72, 96, 120
Multiples of 40 = 40, 80, 120, ...
Therefore, the least common multiple is 120.
The least number of packs of burger to buy is 5 and least number of packs of bread buns to buy is 3.
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The figure is the net for a rectangular prism.
What is the surface area of the rectangular prism represented by the net?
The surface area of the rectangular prism is 174 in²
What is a rectangular prism?A rectangular prism is a three-dimensional solid shape with six faces that including rectangular bases. A cuboid is also a rectangular prism.
Given is a net for a rectangular prism, we need to find the surface area of the rectangular prism,
We know that,
The surface area of the rectangular prism = 2(lxb+bxh+hxl)
Length = l, height = h and b = breadth
Therefore, here we have, l = 9 in, b = 3 in and h = 5 in
Surface area = 2(9x3+3x5+5x9)
= 2(27+15+45)
= 2x87
= 174 in²
Hence, the surface area of the rectangular prism is 174 in²
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Suppose that the distance of fly balls hit to the outfield (in baseball) is normally distributed with a mean of 267 feet and a standard deviation of 39 feet. Let X be the distance in feet for a fly ball.c. Find the 70th percentile for the distribution of distance of fly balls. Round to 2 decimal places.
To find the 70th percentile we look for the z value that gives the following probability:
\(P(Z\leq z)=0.70\)Looking at the standard normal distribution table we notice that this probability happens when:
\(z=0.5244\)Then we need the z score to be 0.5244 .Now that we know this we use its definition to find the value of x that gives this z score:
\(\begin{gathered} z=\frac{x-\mu}{\sigma} \\ \frac{x-267}{39}=0.5244 \\ x-267=20.4516 \\ x=267+20.4516 \\ x=287.45 \end{gathered}\)Therefore, the 70th percentile is 287.45
suppose a hypothesis test, using α = 0.05, is being conducted with the following null hypothesis: h0: μ = 2. which one of the following confidence intervals would lead to rejecting the null hypothesis
A confidence interval cannot instantly lead to rejecting the null hypothesis in a hypothesis test. In the given case the null hypothesis is either rejected or rejected based on test statistics.
α = 0.05
μ = 2
If the confidence interval is 1.0 or 2.0, then the null hypothesis value of 2 drops exceeds the interval, this makes the data contradict the null hypothesis and may reject the null hypothesis.
This alone would not be good to decline the null theory - the conclusion to reject or not reject the null hypothesis is determined by the test statistic and the alternate p-value.
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What relationship exists between angles x and y
Twenty-four percent of Louie's collections are LEGO toys. If he has 48 LEGO toys, how many does he have in
all?
1. What is asked?
2. What are the given facts?
3. What operation on decimals to compute for the total number of LEGO toys?
4. What is the mathematical sentence?
5. What is the answer
In the given problem, apply your knowledge in algebra and basic mathematics specially in word problems involving division of decimal.
1. What is asked?
How many does he have in all?
2. What are the given facts?
Twenty-four percent of Louie's collections are LEGO toys
48 LEGO toys
3. What operation on decimals to compute for the total number of LEGO toys?
Division
4. What is the mathematical sentence?
48 ÷ 0.24
5. What is the answer? (Solution)
48 ÷ 0.24 → 4800 ÷ 24
4800 ÷ 24 = 200
200 LEGO toys
Does the following table show a proportional relationship between the variables
x
xx and
y
yy?
x
xx
1
4
4
1
start fraction, 1, divided by, 4, end fraction
2
4
4
2
start fraction, 2, divided by, 4, end fraction
3
4
4
3
start fraction, 3, divided by, 4, end fraction
y
yy
3
33
6
66
9
99
Yes, the table shows a proportional relationship between the variables, as the ratio between the points is constant.
What is a proportional relationship?The standard definition of a proportional relationship is presented as follows:
y = kx.
Hence the constant of a proportional relationship is obtained as follows:
k = y/x.
For all pairs of points (x,y), the constants have to be same to represent a proportional relationship.
From the image given at the end of the answer, the points are given as follows:
(1/4, 3).(2/4, 6).(3/4, 9).For each point, the constant of proportionality is obtained as follows:
(1/4, 3): k = 3/(1/4) = 3 x 4 = 12.(2/4, 6): k = 6/(2/4) = 6 x 4/2 = 12.(3/4, 9): k = 9/(3/4) = 9 x 4/2 = 12.Equal constants, hence yes, it represents a proportional relationship.
Missing InformationThe table is given by the image presented at the end of the answer.
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caleb buys fencing for his yard. he pays $122 for 5 fence posts and 4 fence panels, he pays $570 for 21 fence posts and 20 fence panels. how much does he pay for 4 fence posts and 3 fence panels?
Caleb pays $40 for 4 fence posts and $54 for 3 fence panels, resulting in a total cost of $94 for 4 fence posts and 3 fence panels.
Let's assign variables to unknown quantities. Let's say the cost of a fence post is "p" and the cost of a fence panel is "q". We need to find the total cost of 4 fence posts and 3 fence panels.
From the given information, we can set up the following equations:
Equation 1: 5p + 4q = 122
Equation 2: 21p + 20q = 570
To solve these equations, we can use the method of substitution or elimination. Let's use the method of substitution:
From Equation 1, we can express "p" in terms of "q":
5p = 122 - 4q
p = (122 - 4q) / 5
Substitute this value of "p" into Equation 2:
21((122 - 4q) / 5) + 20q = 570
Now we can solve this equation for "q" to find the cost of a fence panel.
After solving the equation, we find:
q = 18
Substitute the value of "q" back into Equation 1 to find the cost of a fence post:
5p + 4(18) = 122
5p + 72= 122
5p = 50
p = 10
Now we know that the cost of a fence post is $10 and the cost of a fence panel is $18.
To find the total cost of 4 fence posts and 3 fence panels, we can calculate:
Total cost = (4 * cost of a fence post) + (3 * cost of a fence panel)
Total cost = (4 * 10) + (3 * 18)
Total cost = $40 + $54
Total cost = $94
Therefore, Caleb pays $94 for 4 fence posts and 3 fence panels.
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Write the equation of the line that is perpendicular to the line y=3x+5 and passes through point (9,5)
The equation of the required perpendicular line is x + 3y = 24.
What is the slope relation for two perpendicular lines?
For two perpendicular lines on a plane, the product of their slopes always equals (-1).
What is the equation of line with slope 'm' and passing through the point (x₁, y₁)?
The standard equation of the line with slope 'm' and passing through the point (x₁, y₁) is y - y₁ = m(x - x₁).
Given, the required line is perpendicular to line given by y = 3x + 5 with slope, m₁ as 3, on analysis with standard equation of line; also the line passes through the point (9, 5) i.e. (x₁, y₁).
Let the slope of the required line be = m₂
As per statement established in the literature above, we have:
Slope of two perpendicular lines = -1
∴m₁ × m₂ = -1 ⇒ 3m₂ = -1 ⇒ m₂ = (-1)/3
Again, equation of the required perpendicular line is:
y - 5 = [(-1)/3][x - 9] ⇒ 3y - 15 = 9 - x ⇒ x + 3y = 24
Thus, the equation of the required perpendicular line is x + 3y = 24.
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15% off of $60, then subtracting 10% from that cost, is equal to
Answer:
8.1 i think
Step-by-step explanation:
Using the graph , find g (0) and find x such that g (x) =-1
In order to find g(0), we just need to find the value of the function for x = 0.
Looking at the graph, for x = 0 we have y = 7.
Therefore g(0) = 7.
To find the value of x for g(x) = -1, let's look for the value of x where y = -1.
Looking at the graph, for y = -1, we have x = -2.
Therefore g(x) = -1 for x = -2.
Which expression is equivalent to (4mn/m^-2n^6)^-2
The expression that is equivalent to (4mn/m^-2n^6)^-2 is \(\frac{n^{10}}{16m^{6}}\)
How to determine the equivalent expression?The expression is given as:
(4mn/m^-2n^6)^-2
Apply the law of indices
\((4m^{1 + 2}n^{1-6})^{-2\)
Evaluate the sum and the differences
\((4m^{3}n^{-5})^{-2\)
Apply the negative exponent
\(\frac{1}{16m^{2*3}}}n^{5*2}\)
Evaluate
\(\frac{1}{16m^{6}}n^{10}\)
Rewrite as:
\(\frac{n^{10}}{16m^{6}}\)
Hence, the expression that is equivalent to (4mn/m^-2n^6)^-2 is \(\frac{n^{10}}{16m^{6}}\)
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What is the conversion of 2/5 in decimal ?
The conversion of a fraction number with denominator 5 and numerator 2 , 2/5 in decimals is equals to the 0.4 value.
A decimal number can be defined as a number whose whole number part and fractional part are separated by a decimal point. Writing 2/5 as a decimal number by converting the denominator to powers of 10. We multiply the numerator and denominator by a number so that the denominator is a power of 10.
2/5 = (2 × 2) / (5 × 2) = 4/10
Now move the decimal point to the left as many places as there are zeros in the denominator, which is a power of 10.
The decimal moved one place to the left because the denominator was 10. Therefore, 4/10 = 0.4. Hence, required value is 0.4.
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One pump can empty the pool in 36 hours. The second pump is twice faster. After both pumps, working together emptied 1 3 of a pool the second pump broke. The first pump finished the job. How long did it take to empty the pool?
Answer:
28 hours I think
Step-by-step explanation:
The time taken to empty the pool is 28 hours. This is obtained by taking a variable x as the time taken by both pumps combined for emptying 1/3 rd of the pool and y as the time taken by first pump to empty the remaining.
Calculating the rate of each pump:Given the first pump can empty the pool in 36 hours.
⇒Rate of the first pump is 1/36
The rate of the second pump is twice faster; that is 2×(1/36)=1/18
The rate of both pumps combined will be (1/36 + 1/18)
Calculating the time required:Let x be the time taken by both pumps combined for emptying 1/3 rd of the pool and y be the time taken by first pump to empty the remaining.
If both pumps are working combined,
(1/36 + 1/18)x = 1/3
⇒x = 4 hours
The first pump filling the remaining after the second pump broke,
(1/36)y = 2/3
⇒y = 24 hours
Therefore, the total time taken to empty the pool is x+y=4+24=28 hours
Hence the total time taken to empty the pool is 28 hours
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write and solve an equation to find the measures of each angle in the triangles shown below G:28 H:x I:____
The measure of each angle are H = 38 and I = 114
How to determine the measure of each angleFrom the question, we have the following parameters that can be used in our computation:
G = 28, H = x and I = 3x
The sum of angles in a triangle is 180 degrees
So, we have
28 + x + 3x = 180
Evaluate the like terms
So, we have
4x = 152
Divide by 4
x = 38
So, we have
H = 38
I = 3 * 38 = 114
Hence, the angles are H = 38 and I = 114
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Given a group of students: G = {Allen, Brenda, Chad, Dorothy, Eric) or G = {A, B, C, D, E, list and count the differen ways of choosing the following officers or representatives for student congress (Allen, Chad, and Eric are men) Assume that no one can hold more than one office. 1) A president, a secretary, and a treasurer, if the president must be a woman and the other two must be men A) BAC, BAE, BCE, DAC, DAE, DCE, BCA, BEA, BEC, DCA, DEA, DEC:12 ways B) CAB, EAB, ECB, CAD, EAD, ECD, ACB, AEB, CEB, ACD, AED, CED; 12 ways C) BAC, BAE, DAC, DAE; 4 ways D) BAC, BAE, BCE, DAC, DAE, DCE 6 ways
The different ways of choosing a president, a secretary, and a treasurer, with the president being a woman and the other two being men, are 12 ways (option A).
To choose a president, a secretary, and a treasurer from the group of students (G = {Allen, Brenda, Chad, Dorothy, Eric}), with the condition that the president must be a woman and the other two must be men, we can list and count the different ways as follows:
A) The president is Brenda (B), and the two men are Allen (A) and Chad (C): BAC
The president is Brenda (B), and the two men are Allen (A) and Eric (E): BAE
The president is Brenda (B), and the two men are Chad (C) and Eric (E): BCE
The president is Dorothy (D), and the two men are Allen (A) and Chad (C): DAC
The president is Dorothy (D), and the two men are Allen (A) and Eric (E): DAE
The president is Dorothy (D), and the two men are Chad (C) and Eric (E): DCE
The total number of ways: 12
B) The president is Chad (C), and the two men are Allen (A) and Brenda (B): CAB
The president is Eric (E), and the two men are Allen (A) and Brenda (B): EAB
The president is Eric (E), and the two men are Chad (C) and Brenda (B): ECB
The president is Chad (C), and the two men are Allen (A) and Dorothy (D): CAD
The president is Eric (E), and the two men are Allen (A) and Dorothy (D): EAD
The president is Eric (E), and the two men are Chad (C) and Dorothy (D): ECD
The total number of ways: 12
C) The president is Brenda (B), and the two men are Allen (A) and Chad (C): BAC
The president is Brenda (B), and the two men are Allen (A) and Eric (E): BAE
The president is Dorothy (D), and the two men are Allen (A) and Chad (C): DAC
The president is Dorothy (D), and the two men are Allen (A) and Eric (E): DAE
The total number of ways: 4
D) The president is Brenda (B), and the two men are Allen (A) and Chad (C): BAC
The president is Brenda (B), and the two men are Allen (A) and Eric (E): BAE
The president is Brenda (B), and the two men are Chad (C) and Eric (E): BCE
The president is Dorothy (D), and the two men are Allen (A) and Chad (C): DAC
The president is Dorothy (D), and the two men are Allen (A) and Eric (E): DAE
The president is Dorothy (D), and the two men are Chad (C) and Eric (E): DCE
The total number of ways: 6
In summary, there are 12 ways in options A and B, 4 ways in option C, and 6 ways in option D to choose a president, a secretary, and a treasurer with the given conditions.
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Normalmente, el concepto griego "logos" se entiende como la máxima expresión de la cultura racionalista occidental, fundada por las primeras escuelas de filosofía clásica. De hecho, el nombre de las disciplinas científicas provienen de él: biología, filología, psicología, tecnología, etc. No obstante, el concepto "logos" no tiene un significado tan abstracto, puesto que involucra tanto el pensamiento como la acción, tanto lo interno como lo externo, tanto la idea mental como el decir la palabra. Tema:_________________________________________________________ Idea Principal: ___________________________________________________
Concept: "Logos" has had a significant impact on Western thought. Importance: its recognition of the interplay between rational thought and empirical observation Acknowledgement: role of language and discourse in shaping our understanding of the world.
Topic: The concept of "Logos" in Greek philosophy and its significance in modern scientific fields.
The concept of "Logos" is central to Greek philosophy and has been interpreted in various ways throughout history. In its most basic sense, "Logos" refers to rational thought, speech, and language. It is often associated with the divine or the cosmic principle that governs the universe, as well as human reasoning and discourse.
The significance of "Logos" can be seen in its influence on modern scientific fields, including biology, psychology, and technology, among others. The term "biology," for example, comes from the Greek words "bios" (life) and "logos" (word or reason), reflecting the idea that the study of life requires both empirical observation and rational analysis.
Similarly, the field of psychology, which deals with the workings of the human mind and behavior, derives its name from the Greek word "psyche," meaning "soul," and "logos," meaning "reason." This reflects the idea that the study of the mind and behavior requires both empirical research and theoretical analysis.
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Translation: The Greek word "logos" is typically interpreted as the pinnacle of Western rationalist civilization, having been established by the first schools of classical philosophy. In reality, he is responsible for the names of many scientific fields, including biology, philology, psychology, technology, and others. Since it requires both mind and action, internal and external, the mental notion and pronouncing the word, the concept of "logos" does not have such an abstract meaning. Topic:____________________________________________________ Principal Concept:
Twelve is at least
number x decreased
by 7.
Answer:
x is greater than or equal to 19
Answer:
Wrong.
Step-by-step explanation:
It's 12 ≤ N - 7
Let Z be a standard normal random variable: i.e., Z ~ N(0,1). (1) Find the pdf of U = Z2 from its distribution. (2) Given that f(1/2) = VT Show that U follows a gamma distribution with parameter a = 1 = 1/2. (3) Show that I (1/2) = V1. Note that I (1) = Soe ex-1/2dx. Hint: Make the change of variables y = V2x and then relate the resulting expression to the normal distribution.
1)The pdf of U is f(u) = (1/(2√u)) exp(-u/2) for u > 0 and f(u) = 0 otherwise.
2)U follows a gamma-distribution with parameter a = 3/2 or a = 1/2.
3)x = (y²/2) and dx = y dy using exponential distribution
We can rewrite the integral as:
I(1/2) = ∫₀^∞ y exp(-y²) dy
= 1/2 ∫₀^∞ exp(-u/2) du
This is the same as the integral for f(u) when u = 1/2.
Therefore, we have:
I(1/2) = V1
(1) For U = Z², we can use the method of transformations.
Let g(z) be the transformation function such that
U = g(Z)
= Z².
Then, the inverse function of g is given by h(u) = ±√u.
Thus, we can apply the transformation theorem as follows:
f(u) = |h'(u)| g(h(u)) f(u)
= |1/(2√u)| exp(-u/2) for u > 0 f(u) = 0 otherwise
Therefore, the pdf of U is given by:
f(u) = (1/(2√u)) exp(-u/2) for u > 0 and f(u) = 0 otherwise.
(2) We are given that f(1/2) = VT, where V is a constant.
We can substitute u = 1/2 in the pdf of U and equate it to VT.
Then, we get:VT = (1/(2√(1/2))) exp(-1/4)VT
= √2 exp(-1/4)
This gives us the value of V.
Now, we can use the pdf of the gamma distribution to find the parameter a such that the gamma distribution matches the pdf of U.
The pdf of the gamma distribution is given by:
f(u) = (u^(a-1) exp(-u)/Γ(a)) for u > 0 where Γ(a) is the gamma function.
We can use the following relation between the gamma and the factorial function to simplify the expression for the gamma function:
Γ(a) = (a-1)!
Thus, we can rewrite the pdf of the gamma distribution as:
f(u) = (u^(a-1) exp(-u)/(a-1)!) for u > 0
We can now equate the pdf of U to the pdf of the gamma distribution and solve for a.
Then, we get:
(1/(2√u)) exp(-u/2) = (u^(a-1) exp(-u)/(a-1)!) for u > 0 a = 3/2
Therefore, U follows a gamma distribution with parameter
a = 3/2 or equivalently,
a = 1/2.
(3) We need to show that I(1/2) = V1.
Here, I(1) = ∫₀^∞ exp(-x) dx is the integral of the exponential distribution with rate parameter 1 and V is a constant.
We can use the change of variables y = √(2x) to simplify the expression for I(1/2) as follows:
I(1/2) = ∫₀^∞ exp(-√(2x)) dx
Now, we can substitute y²/2 = x to obtain:
x = (y²/2) and
dx = y dy
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Solve questions 1-5 (Geometry)
Answer:
a) mBA = 124 degrees, this is because the angles are supplementary meaning they are equal to 180 degrees. And one angle has been given which was 56 degrees so we subtract that from the total and get 124 degrees.
b) mCE = 37 degrees, this is because we know the line that is exactly straight in the middle is equal to 180 degrees (supplementary). We are also given the length of the right bottom side which is 56, because it is vertical to the other angle diagonal from it. With two given angles we combine them and subtract it from the total so, 180(total) - (87 + 56)(given angles) = 37
c) I don't know this one, sorry.
Find z so that 88% of the area is to the right of z.
• We are required to find Z so that the area is to the right, this means that the area is to be positive .
,• 88 % can be converted to 88/100 = 0.88
,• z = 1-0.88 = 0.12
The value tha corresponds with 0.12 = 0.04775
= 0.048
using the cumulative standard normal z score of 0.12 = 0.5478
a piece of paper is to display 128 128 space, 128, space square inches of text. if there are to be one-inch margins on both sides and two-inch margins at the bottom and top, what are the dimensions of the smallest piece of paper (by area) that can be used?
The dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches.
The area of a square with sides of one inch is equal to one square inch (plural: square inches).
We have that:
Let the dimension of the paper be x and y.
Such that:
Length = \(x\)
Width = \(y\)
So:
Area = \(x*y\)
Substitute 128 for Area
\(128=x*y\)
Make x the subject.
\(x=\frac{128}{y}\)
When 1 inch margin is at top and bottom
The Length becomes:
\(Length =x+1+1\)
\(Length = x+2\)
When 2-inch margin is at both sides
The width becomes:
\(Width = y+2+2\)
\(Width = y+4\)
The New Area (A) is then calculated as:
\(A = (x+2)*(y+4)\)
Substitute \(\frac{128}{y}\) for x
\(A = (\frac{128}{y}+2 )*(y+4)\)
Open Brackets
\(A = 128 + \frac{512}{y} + 2y + 8\)
Collect Like Terms
\(A = \frac{512}{y} + 2y + 8+128\)
\(A = \frac{512}{y} +2y+136\)
\(A = 512y^{-1} +2y + 136\)
To calculate the smallest possible value of y, we have to apply calculus.
Differentiate A with respect to y
\(A' = -512y^{-2}+2\)
Set
\(A' = 0\)
This gives:
\(0=-512y^{-2}+2\)
Collect Like Terms
\(512y^{-2} = 2\)
Multiply through by \(y^{2}\)
\(y^{2} *512y^{-2} = 2*y^{2}\)
\(512 = 2y^{2}\)
Divide through by 2.
\(256 = y^{2}\)
Take square roots of both sides.
\(\sqrt{256= y^{2} }\)
\(16 =y\\\\y=16\)
Recall that:
\(x = \frac{128}{y}\)
\(x = \frac{128}{16}\)
\(x=8\)
Recall that the new dimensions are:
\(Length = x+2\)
\(Width = y+4\)
So:
\(Length = 8+2\)
\(Length = 10\)
To double-check.
Differentiate A'
\(A' = -512y^{-2}+2\)
\(A'' = -2 * -512y^{-3}\)
\(A'' = 1024y^{-3}\)
\(A'' = \frac{1024}{y^{3} }\)
The above value is:
\(A'' = \frac{1024}{y^{3} } > 0\)
In other words, the estimated numbers are at their lowest.
Hence, the dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches.
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The dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches.
The area of a square with sides of one inch is equal to one square inch (plural: square inches).
We have that:
Let the dimension of the paper be x and y.
Such that:
Length = x
Width = y
So:
Area = xy
Substitute 128 for Area
128 = xy
Make x the subject.
x=128/y
When 1 inch margin is at top and bottom
The Length becomes:
length = x+2
When 2-inch margin is at both sides
The width becomes:
width = y+4
The New Area (A) is then calculated as:
A = (x+2)(y+4)
Substitute for x
A = (128/y +2)(y+4)
Open Brackets
A = 128 +512/y + 2y +8
Collect Like Terms
A = 512/y + 2y +136
To calculate the smallest possible value of y, we have to apply calculus.
Differentiate A with respect to y
A' = -512/y*y +2
Set
A' = 0
This gives:
y = 16
Recall that:
x = 128/y
x = 8
Recall that the new dimensions are:
Length = x +2
Width = y+4
So:
Length = 10
To double-check.
Differentiate A'
A'' = 1024/y*y*y
The above value is greater than 0
In other words, the estimated numbers are at their lowest.
Hence, the dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches.
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