Find the rate of change from 2008 to 2016

AS ITS 700 PER MONTH FOR 2 YEARS SO

700×24

=16,800

16,800+6,000

=22,800

22,800-20000

so its 2800

Hope its right! Give brainliest :)

Vector v can be written as the sum of two vector components, \(v_x = -5i\)  and \(v_y = 6j\)

To write vector v as the sum of two vector components, we need to decompose it into two vectors along different directions.

v = -5i + 6j

w = 3i + 4j

We can decompose vector v into two components, one along the x-axis and the other along the y-axis.

Let's denote the component along the x-axis as \(v_x\) and the component along the y-axis as \(v_y.\)

The x-component, \(v_x,\) represents the projection of vector v onto the x-axis and can be found using the dot product of v and the unit vector i:

\(v_x = v . i = (-5i + 6j) . i = -5i . i + 6j . i = -5\)

Similarly, the y-component, \(v_y,\) represents the projection of vector v onto the y-axis and can be found using the dot product of v and the unit vector j:

\(v_y = v . j = (-5i + 6j) . j = -5i . j + 6j . j = 6\)

Now, we can write vector v as the sum of its components:

\(v = v_x + v_y = -5i + 6j\)

So, vector v can be written as the sum of two vector components: -5i along the x-axis and 6j along the y-axis.

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The Total length of two sides based on the information will be 7x²+2x+1

The Length of the third side will be 4 x³-10x²-7.

Total length of two sides= Side 1 + Side 2

= 8x² − 5x − 2+ 7x − x²+ 3

= 8x²-x²-5x+7x-2+3

= 7x²+2x+1

Length of the third side = Perimeter - Total length of two sides

Length of the third side=4x³ − 3x² + 2x − 6-(7x²+2x+1)

= 4x³ − 3x² + 2x − 6-7x²-2x-1

= 4 x³-10x²-7

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Answer:

i belive it is reflection across y=x

Step-by-step explanation: When you reflect a point across the line y = x, the x-coordinate and y-coordinate change places

Hello!

surface area

= 2(4 x 2) + 2(12 x 4) + 2(12 x 2)

= 160cm²

Using simple interest, it is found that:

Simple interest is used when there is a single compounding per time period.

The interest after t years in is modeled by:

\(I(t) = Prt\)

In which:

In this problem:

Then:

\(I_1 = 0.07P_1\)

\(I_2 = 0.08P_2\)

Considering \(P_1 + P_2 = 10000 \rightarrow P_2 = 10000 - P_1\):

\(I_2 = 0.08(10000 - P_1)\)

Considering \(I_1 + I_2 = 780 \rightarrow I_2 = 780 - I_1\):

\(780 - I_1 = 0.08(10000 - P_1)\)

Considering \(I_1 = 0.07P_1\):

\(780 - I_1 = 0.08(10000 - P_1)\)

\(780 - 0.07P_1 = 0.08(10000 - P_1)\)

\(0.01P_1 = 20\)

\(P_1 = \frac{20}{0.01}\)

\(P_1 = 2000\)

And:

\(P_1 + P_2 = 10000\)

\(2000 + P_2 = 10000\)

\(P_2 = 8000\)

Then:

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Answer:

x comes before y (x, y). One way to remember is 'you go along the hallway before you go up the stairs'.

Step-by-step explanation:

Answer:

yes

Step-by-step explanation:

The value of the car after 3 years is $79, 000

To determine the value, we have to use the formula;

Value = Initial value × (1 - Depreciation rate)ⁿ

Substitute the values given, we get;

Remaining value after 3 years = $100,000 × (1 - 0.10)³

Expand the bracket, we get;

Value after 3 years = $100,000 × (0.90)³

Find the cube value and substitute, we have;

Value after 3 years = $100,000 × 0.729

Multiply the values, we have;

Value after 3 years = $72,900

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Answer:

Step-by-step explanation:

I DONT UNDERSTAND

The mechanical advantage of the given machine is 40, Velocity ratio is 80 and efficiency is 0.5.

The given question is concerned with finding the mechanical advantage, velocity ratio and efficiency of a weight lifting machine.

The problem has provided the following information:

Weight of the object, W = 1 kN = 1000 NEffort applied, E = 25 NHeight through which the object is lifted, h = 100 mm = 0.1 m Distance through which the effort is applied, d = 8 m

We know that, mechanical advantage = load/effort = W/E and velocity ratio = distance moved by effort/distance moved by the load.Mechanical advantage

The mechanical advantage of the given machine is given by; Mechanical advantage = load/effort = W/E= 1000/25= 40Velocity ratioThe velocity ratio of the given machine is given by;

Velocity ratio = distance moved by effort/distance moved by the load.= d/h = 8/0.1= 80EfficiencyThe efficiency of the given machine is given by;

Efficiency = (load × distance moved by load) / (effort × distance moved by effort)Efficiency = (W × h) / (E × d)= (1000 × 0.1) / (25 × 8)= 0.5

Therefore, the mechanical advantage of the given machine is 40, velocity ratio is 80 and efficiency is 0.5.

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Answer:

True. It would need two interior angles of 90 degrees to have parallel lines. However the interior angles must add up to 180 in order for it to be a triangle therefore it is true.

Step-by-step explanation:

A triangle cannot have side that are parallel is True.

The fundamental characteristics listed below make it simple to recognise parallel lines.

No matter how long you make them, parallel lines will never cross one another.

and, A polygon with three sides and three angles is called a triangle.

So, A triangle does not include any parallel lines because of its shape.

Also, We cannot say a triangle is parallel because a side doesn't have an opposite side.

Hence, A triangle cannot have side that are parallel is True.

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Answer:

153 miles

Step-by-step explanation:

1 inch = 36 miles.

First, find the measurement of miles for 1/4 inch. Divide 36 with 4:

36/4 = 9

1/4 inch. = 9 miles.

Next, find the amount of measurement of miles per 4 inches:

4 x 36 = 144 miles.

Finally, combine the two measurements together:

144 + 9 = 153 miles.

153 miles is your answer.

~

Step-by-step explanation:

Given:-

To Find:-

Solution:-

we are given with that 1 inch here represents 36 miles on map. So, we will find the that how much miles will be cover in 4+1/4? We will find measurement of 1/4 by dividing the value 36 and 4 (approx).

\(\dashrightarrow\sf\dfrac{36}{4} \: = \: 9 \: which \: means \: \dfrac{1}{4} = 9 \: miles.\)

Now-

We will find the measurement of miles by per 4 inches.

➠ 36 × 4 = 144 miles

Similarly-

we will combine or Add the two outcomes measurement.

➠ 144 + 9 = 153 miles

.°. 4 + 1/4 will represent 153 miles on the map.

Let P and Q be two complex numbers such that

P = a+bi

Q = c+di

Where a,b,c,d are real numbers and i = sqrt(-1).

This means i^2 = -1.

-------------------

Adding P and Q means

P+Q = (a+bi)+(c+di)

P+Q = a+bi + c+di

P+Q = (a+c) + (bi+di)

P+Q = (a+c) + (b+d)i

As you can see, we just add the corresponding components together.

-------------------

Subtraction is a similar story.

P-Q = (a+bi)-(c+di)

P-Q = a+bi - c-di

P-Q = (a-c) + (bi-di)

P-Q = (a-c) + (b-d)i

We subtract the corresponding components

-------------------

Multiplication is a bit more complicated.

We'll use the FOIL rule

P*Q = (a+bi)*(c+di)

P*Q = a*c + a*di + bi*c + bi*di

P*Q = a*c + ad*i + bc*i + bd*i^2

P*Q = a*c + ad*i + bc*i + bd*(-1)

P*Q = a*c + ad*i + bc*i - bd

P*Q = (ac - bd) + (ad*i + bc*i)

P*Q = (ac - bd) + (ad + bc)i

Unfortunately multiplication isn't as simple as addition or subtraction, but we can at least make a tidy formula for it. You could also use the box method to visually organize the terms into a table to help multiply out P and Q.

Answer:

because they have different stepa

The onto functions (surjective functions) are:

c. f(m, n) = m + n + 1.

At first we have to identify onto (surjective) functions from Z x Z to Z, we need to check if each element in the codomain (Z) has at least one preimage in the domain (Z x Z).

a. f(m, n) = 2m - n

This function is not onto because for odd numbers in the codomain (Z), there is no pair of integers (m, n) in the domain that will map to them.

b. \(f(m, n) = m^2 - n^2\)

This function is not onto because for negative numbers in the codomain (Z), there is no pair of integers (m, n) in the domain that will map to them.

c. f(m, n) = m + n + 1

This function is onto. For any integer 'z' in the codomain (Z), we can find a pair of integers (m, n) in the domain such that m + n + 1 = z.

For example, if z = 0, we can choose m = 0 and n = -1, and then m + n + 1 = 0.

d. f(m, n) = |m| - |n|

This function is not onto because negative numbers in the codomain (Z) cannot be obtained from the domain (Z x Z).

For example, there is no pair of integers (m, n) in the domain that maps to -1.

Hence, The onto functions (surjective functions) are:

c. f(m, n) = m + n + 1.

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The Variables (a) Gender is Categorical , (b) Alcohol can be either Categorical or Quantitative and (c) Height is Quantitative .

We can identify the type of each variable as categorical or quantitative.

(a) Gender: This variable is categorical, as it describes a characteristic that can only take on a limited number of values (e.g., male or female).

(b) Alcohol: Without additional information , it is not clear whether this variable is categorical or quantitative.

If the data set only includes information about whether an individual drinks alcohol or not, then this variable is categorical. If the data set includes information about how much alcohol an individual consumes, then this variable would be quantitative.

(c) Height: This variable is quantitative, as it represents a numerical measurement of a continuous variable.

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The given question is incomplete , the complete question is

Identify and classify the variable(s) you will use. here is the list of variables in the data set.  

(i) identify the variable as either categorical or quantitative.

the variables are (a) Gender , (b) Alcohol , (c) Height .

(a) One ball is drawn at random from the urn and it is red, so the posterior distribution of X can be found using Bayes' theorem:

P(X = x | red) = P(red | X = x) * P(X = x) / P(red)

where P(X = x) is the prior probability of X being x, P(red | X = x) is the probability of getting a red ball given that X is x, and P(red) is the total probability of getting a red ball.

Since all possible values of X from 0 to 9 are equally likely, the prior probability of X being x is P(X = x) = 1/10 for x = 0, 1, 2, ..., 9.

The probability of getting a red ball given that X is x can be calculated using the hypergeometric distribution:

P(red | X = x) = (x choose 1) * (9-x choose 8-x) / (9 choose 1)

where (x choose k) is the number of combinations of x items taken k at a time.

The total probability of getting a red ball is:

P(red) = sum(P(red | X = x) * P(X = x)) for x = 0, 1, 2, ..., 9

Using these formulas, we can find the posterior distribution of X and the mean of X:

Posterior distribution of X:

P(X = x | red) = P(red | X = x) * P(X = x) / P(red)

Mean of X:

E(X | red) = sum(x * P(X = x | red)) for x = 0, 1, 2, ..., 9

(b) Now suppose that a second ball is drawn from the urn, without replacing the first, and it is green, so the posterior distribution of X can be found using Bayes' theorem again:

P(X = x | red, green) = P(green | X = x) * P(X = x | red) / P(green)

where P(X = x | red) is the posterior distribution of X from part (a), P(green | X = x) is the probability of getting a green ball given that X is x, and P(green) is the total probability of getting a green ball.

The probability of getting a green ball given that X is x can be calculated using the hypergeometric distribution:

P(green | X = x) = (9-x choose 1) * (x choose 8-x) / (9 choose 1)

The total probability of getting a green ball is:

P(green) = sum(P(green | X = x) * P(X = x | red)) for x = 0, 1, 2, ..., 9

Using these formulas, we can find the posterior distribution of X and the mean of X:

Posterior distribution of X:

P(X = x | red, green) = P(green | X = x) * P(X = x | red) / P(green)

Mean of X:

E(X | red, green) = sum(x * P(X = x | red, green)) for x = 0, 1, 2, ..., 9

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Answer:

Hey there!

A good estimation is one dollar.

2 pairs of shoes for 14 dollars= 28 dollars

29-28=1 dollars.

Hope this helps :)

Answer:

x > 8

Step-by-step explanation:

You can start y multiplying both sides by 4 to cancel out the division by 4:

x/4 > 2

*4      *4

x > 8

Answer:

x > 8

Step-by-step explanation:

x/4 > 2

=> x > 2 × 4

=> x > 8

Answer:

(6.4)(1.2)

= 7.68

it's just Multiplying 6.4 by 1.2 which equals 7.68

hope this helped ^u^ and always happy to help with math

The answer of the given question based on the expression is , the value of the summation when m = 3 is 137.

In mathematics, an expression is a combination of numbers, variables, and operators that represents a value or a set of values. It can be a simple combination of numbers and variables or a more complex combination involving mathematical operations like addition, subtraction, multiplication, division, exponents, and roots. Expressions can be used to represent a wide range of mathematical concepts, from simple arithmetic to complex functions and equations.

To evaluate the summation 1(1!) + 2(2!) + 3(3!) + 4(4!) + m(m!), where m = 3, we substitute m = 3 and simplify:

1(1!)+2(2!) +3(3!) +4(4!) +3(3!)

= 1(1) + 2(2) + 3(6) + 4(24) + 3(6) (since n! = n(n-1)! for all positive integers n)

= 1 + 4 + 18 + 96 + 18

= 137

Therefore, the value of the summation when m = 3 is 137.

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Answer:

the paracium never dies because it keeps on reproducing

Step-by-step explanation:

the paracium lets say it starts as 1

and then taht 1 divides inti

1/2 and 1/2 and that 1/2 turns into 1

and it keeps on dividing and multiplying

The solution is,  2.5 miles per hour was her walking rate in miles per hour.

We know that,

Speed is measured as distance moved over time.

The formula for speed is speed = distance ÷ time.

To work out what the units are for speed, you need to know the units for distance and time.

In this example, distance is in metres (m) and time is in seconds (s), so the units will be in metres per second (m/s).

Speed = Distance/ Time.

Here, given that,

Bao walked 15 miles in 6 hours.

so, we get,

in 6 hours = 15 miles

so, in 1 hour = 15 / 6 miles

                    =2.5 miles

Hence, The solution is,  2.5 miles per hour was her walking rate in miles per hour.

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The expression of "The difference of -10 and the product of p and q" in algebraic notation is pq + 10

From the question, we have the following parameters that can be used in our computation:

The difference of -10 and the product of p and q

The numbers are given as

p and q

The product of p and q means pq

So, we have the following

The difference of -10 and pq

The difference of -10 and pq means

pq + 10

Hence, the expression is pq + 10

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Answer:

I think his first error is step2

Answer:

  C.  38°

  D.  30°

Step-by-step explanation:

The relevant relation in both cases is the inscribed angle measures half the measure of the arc it intercepts.

__

C. Angle TSQ intercepts arc TQ, so the measure of arc TQ is 2(86.5°) = 173°. The measure of arc TR is the difference between the measures of arcs TQ and RQ, so is ...

  arc TR = 173° -135° = 38°

__

D. Inscribed angle PQR intercepts arc PR, so is half its measure.

  angle PQR = 60°/2 = 30°

The point in Figure 2 that corresponds to point L in Figure 1 is the midpoint of line segment NP.

When two figures are congruent, it means that they have the same shape and size. This implies that corresponding points in the two figures have the same position and distance from each other.

In Figure 1, the points I, J, L, K, N, P, and Q are labeled. To find the point in Figure 2 that corresponds to point L, we need to look for a point that has the same relative position and distance as point L in Figure 1.

From Figure 1, we can see that point L is the midpoint of the line segment JK. Therefore, to find the corresponding point in Figure 2, we need to look for a point that is the midpoint of the line segment that corresponds to JK. In Figure 2, the line segment that corresponds to JK is NP, and the midpoint of NP corresponds to the point that is equivalent to point L. Therefore, the point that corresponds to point L in Figure 2 is the midpoint of line segment NP.

It is important to note that identifying corresponding points in congruent figures is a fundamental concept in geometry and is often used to solve problems involving congruence and similarity.

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Answer:

33.33%

Step-by-step explanation:

We need to calculate the unit selling price and cost of each cosmetics.

If a person bought some cosmetics from wholesale market at the rate of Rs 360 per dozen., then for 1 cosmetics, we will say;

x = 1 cosmetic

since 360 = 12 cosmetic

cross multiply

12x = 360

x = 360/12

x = 30

Hence the unit cost price of the cosmetics will be Rs. 30

Similarly, if he sells it at Rs 80 a pair, then he sold one cosmetic at 80/2 = Rs. 40 (a pair is 2 cosmetics)

Selling price per unit = Rs. 40

Cost price per unit = Rs. 30

percent gain = SP-CP/CP * 100%

percent gain = 40-30/30 * 100

percent gain = 10/30 * 100

percent gain = 100/3

percent gain = 33.33%

Hence the percentage gain is 33.33%

Mikey Johnson shipped out 34 2/7 pounds of electrical supplies. The supplies are placed in individual packets that weigh 2 1/7 pounds each. Therefore, Mikey shipped out 16 packets of electrical supplies.

To solve the problem, we can use the following steps.Step 1: Find the weight of each packet.

We are given that the weight of each packet is 2 1/7 pounds.

To convert this mixed number into an improper fraction, we can multiply the whole number by the denominator and add the numerator.

This gives us: 2 1/7 = (2 × 7 + 1) / 7= 15 / 7 pounds.

Therefore, the weight of each packet is 15/7 pounds.

Now, divide the total weight by the weight of each packet.

We are given that the total weight of the supplies shipped out is 34 2/7 pounds.

To convert this mixed number into an improper fraction, we can multiply the whole number by the denominator and add the numerator.

This gives us: 34 2/7 = (34 × 7 + 2) / 7= 240 / 7 pounds.

Therefore, the total weight of the supplies is 240/7 pounds.

To find the number of packets that Mikey shipped out, we can divide the total weight by the weight of each packet.

This gives us: 240/7 ÷ 15/7 = 240/7 × 7/15= 16.

Therefore, Mikey shipped out 16 packets of electrical supplies.

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