Find the vector using parallelogram law [and Pythagoras theorem (h² = a² + o²) h being the hypothenuse, a being the adjacent side and o being the opposite side]
Answers
The Pythagorean Theorem states that the squares on the hypotenuse (the side across from the right angle) of a right triangle, or, in standard algebraic notation, a2 + b2, are equal to the squares on the legs.
What is Pythagorean Theorem called?The Pythagorean theorem, sometimes known as Pythagoras' theorem, is a fundamental relationship between a right triangle's three sides in Euclidean geometry. According to this rule, the areas of the squares on the other two sides add up to the area of the square whose side is the hypotenuse, or the side across from the right angle. The Pythagorean equation, which is typically used to express this theorem, can be expressed as an equation linking the lengths of the legs (a, b), and the hypotenuse (c):
There are several ways to generalize the theorem, including to higher-dimensional spaces, non-Euclidean spaces, objects other than right triangles, and even things that are not triangles at all but n-dimensional solids. The Pythagorean theorem has garnered interest outside of mathematics as a representation of mathematical mystique, power, or obscurity; there are numerous references to it in popular works of fiction, dramas, musicals, songs, stamps, and cartoons.
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Related Questions
a hollow sphere has mass , radius , and moment of inertia about an axis through its center of mass. it is initially rolling on a horizontal plane with center of mass velocity and angular velocity . for all of the questions on this page you should assume that there is no slipping.
Answers
A hollow sphere has a moment of inertia I = (2/3)MR^2, where M is the mass, and R is the radius.
In the given scenario, the hollow sphere is initially rolling without slipping on a horizontal plane, with center of mass velocity (v) and angular velocity (ω).
The relationship between linear velocity and angular velocity can be described as v = Rω, due to the no-slip condition. Since the moment of inertia of a hollow sphere is given by the formula I = (2/3)MR^2, we can use this information to further analyze the sphere's motion.
Summary: For a hollow sphere rolling without slipping on a horizontal plane, its moment of inertia is I = (2/3)MR^2, and its linear and angular velocities are related by the equation v = Rω.
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When ___ attacks the surface of a metal, it becomes tarnished.
Answers
Answer:corrosion (i believe)
Explanation:
Answer
Mix baking soda and salt with hot water and cover everything with it. The proportions are not crucial, but about 1 tablespoon of salt and 1 tablespoon of baking soda to 3 dl water should do the trick. Lightly tarnished objects should clean up in a few minutes, and you just rinse them of and dry them.
Explanation:
plz do all of it i will give brainlest and thanks to best answer
plz do it right
Answers
Answer:
d
Explanation:
because earth does have more water than land so it would be d
The speed of all electromagnetic waves is 3. 00 × 10^8 meters per second. What is the wavelength of an x-ray with a frequency of 1. 18 × 10^18 hz?.
Answers
The formula to find the wavelength of any electromagnetic wave is λ = c / f, where λ is the wavelength, c is the speed of light, and f is the frequency of the wave. Since x-rays are a type of electromagnetic wave, this formula can be applied to find the wavelength of an x-ray with a frequency of 1.18 × 10^18 Hz.
Substituting the given values into the formula, we get λ = (3.00 × 10^8 m/s) / (1.18 × 10^18 Hz). Simplifying this equation, we get λ = 2.54 × 10^-10 meters.
Therefore, the wavelength of an x-ray with a frequency of 1.18 × 10^18 Hz is 2.54 × 10^-10 meters. It's important to note that x-rays have a much shorter wavelength than visible light, which allows them to penetrate through dense materials and create detailed images of bones and organs in medical imaging.
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A body of mass 5kg is connected by a light inelastic string which is passed over a fixed frictionless pulley to a moveable frictionless pulley of mass 1kg over which is wrapped another light inelastic string which connects masses 3kg and 2kg. Find 1) the acceleration of the masses.
2) the tensions in the strings in terms of g, the acceleration dey to gravity
Answers
(a) The acceleration of the masses is determined as 1.1 m/s² in the direction of the 5 kg mass.
(b) The tension in the string in terms of gravity is T = g.
What is the acceleration of the masses?(a) The acceleration of the masses is calculated by applying Newton's second law of motion.
F(net) = ma
where;
m is the massesa is the acceleration of the masses(5 kg x 9.8 m/s² ) - (1 kg + 3 kg )9.8 m/s² = ma
9.8 N = (5kg + 1 kg + 3 kg )a
9.8 = 9a
a = 9.8 / 9
a = 1.1 m/s² in the direction of the 5 kg mass.
(b) The tension in the string in terms of gravity is calculated as follows;
T = ( 5kg)g - (1 kg + 3 kg ) g
T = 5g - 4g
T = g
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If an electron vibrates back and forth in an clean wire with a frequency of 60.0 Hz, how many cycles make in 1.0 h?
a. 8.1 x 10^5
b. 6.0 x 10^2
c. 3.7 x 10^3
d.2.2 x 10^5
e. 4.6 x 10^4
Plz Help
Answers
If an electron vibrates back and forth in an clean wire with a frequency of 60.0 Hz, then it will make 2.2×10⁵ cycles. in 1.0 h. Hence option D is correct.
What is electric charge ?Electric charge is the physical property of matter that experiences force when it is placed in electric field. F = qE where q is amount of charge, E = electric field and F = is force experienced by the charge. there are two types of charges, positive charge and negative charge which are generally carried by proton and electron resp. like charges repel each other and unlike charges attract each other. the flow charges is called as current. Elementary charge is amount of charge a electron is having, whose value is 1.602 x 10⁻¹⁹ C
Amplitude is a measure of loudness of a sound wave. More amplitude means more loud is the sound wave.
Wavelength is the distance between two points on the wave which are in same phase. Phase is the position of a wave at a point at time t on a waveform. There are two types of the wave longitudinal wave and transverse wave.
Frequency is nothing but the number of oscillation in a unit time.
Given,
frequency f = 60.0 Hz.
time t = 1.0 h = 60*60 = 3600s
F = number of cycles/time
number of cycles = F×time
The number of cycles in 1 Hr is
60*3600 = 2.2×10⁵ cycles.
Hence option D is correct.
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How high will the ball go? I would really appreciate a step by step answer!
Answers
Answer:
y = 3.26 [m]
Explanation:
In order to solve this problem, we must use the following equation of kinematics.
\(v_{f}^{2}= v_{o}^{2}-2*g*y\)
where:
Vf = final velocity = 0
Vo = initial velocity = 8 [m/s]
g = gravity acceleration = 9.81 [m/s²]
y = elevation [m]
Note: The negative sign in the equation above represents that the movement is againts the direction of the gravity acceleration.
Now replacing:
\(0=8^{2} -2*9.81*y\\19.62*y=64\\y=3.26 [m]\)
A cannon with a muzzle velocity of 500. meters per second fires a cannonball at an angle of 30.° above the horizontal. What is the vertical component of the cannonball's velocity as it leaves the cannon?
0.0 m/s
250. m/s
433 m/s
500. m/s
Answers
Complete question
A cannon with a muzzle velocity of 500. meters per second fires a cannonball at an angle of 30.° above the horizontal. What is the vertical component of the cannonball's velocity as it leaves the cannon?
A 0.0 m/s
B 250. m/s
C 433 m/s
D 500. m/s
Answer:
The correct option is C
Explanation:
From the question we are told that
The velocity is \(v = 500 \ m/s\)
The angle is \(\theta = 30^o\)
Generally the vertical component of the canon ball is mathematically represented as
\(v_y = v * cos (30 )\)
=> \(v_y = 500 * cos (30 )\)
=> \(v_y = 433 \ m/s\)
Answer:
250. m/s
Explanation:
It is vertical component so you do: 500mSin(30°) = 250m/s
2
Which statement about the relationship between an organism's traits and its genes is true?
A.
An organism's genes are a direct result of its inherited traits.
B. Traits code for the proteins that determine an organism's genes.
C.
Genes code for proteins that determine an organism's traits.
D. Genes code for the DNA that determines an organism's traits.
Answers
TO be completely Honest with this, Based of reading the questions and answers it may be D. just off sheer legibility of logic alone, Hope this is not wrong.
A child drops a bouncy ball. Each time it bounces, it reaches a lower height until it eventually
stops. Describe the energy transfers and explain why the ball lowered in height
Answers
Answer:
the ball's was lowered because of the gravitational force and because of the friction force's
If the acceleration is 600m/s/s and the mass is 300kg, calculate the for the force
Answers
Answer:
180000N
Explanation:
Given parameters:
Acceleration = 600m/s²
Mass = 300kg
Unknown:
Force = ?
Solution:
From Newton's second law of motion;
Force = mass x acceleration
Force = 300 x 600 = 180000N
A student fires a cannonball diagonally
from the ground as shown. Neglect drag
and the initial height of the cannonball.
After the ball lands on the ground enter
zero for all speeds and heights if necessary.
Answers
Answer:The cannons total flight time is 2.23seconds
Explanation:
A ball fired diagonally is fired at an angle of 45° to the horizontal. The motion of the fired ball is a projectile motion. A projectile is a motion in which an object fired into space with an initial velocity U is allowed to fall freely under the influence of gravitational force.
To total time of flight T of the cannon ball can be expressed as;
T = 2Usin(theta)/g where;
U is the initial velocity or speed of the ball = 31m/s
theta is the angle that the ball make with the horizontal = 45°
g is the acceleration due to gravity = 9.81m/s²
Substituting the given datas into the formula we have;
T = 31sin45°/9.81
T = 31×0.7071/9.81
T = 21.92/9.81
T = 2.23seconds
5.how many ml of 0.10 m naoh should the student add to 20 ml 0.10 mhfor if she wished to prepare a buffer with a ph of 3.4, the same as in problem 4.
Answers
To prepare a buffer with a pH of 3.4, the student will need to add a specific amount of NaOH to the solution. The equation to find the amount of NaOH needed is:
pH = pKa + log ([A-]/[HA])
In problem 4, the pKa was given as 3.4, so we can plug that into the equation and solve for [A-]/[HA]:
3.4 = 3.4 + log ([A-]/[HA])
0 = log ([A-]/[HA])
[A-]/[HA] = 1
This means that the ratio of the concentration of the conjugate base to the weak acid in the buffer must be 1. So, if the initial solution had a concentration of 0.10 M for both the weak acid and its conjugate base, then the concentration of the weak acid in the buffer should still be 0.10 M.
To achieve this, we can use the Henderson-Hasselbalch equation:
pH = pKa + log ([A-]/[HA])
3.4 = 3.4 + log ([A-]/0.10)
log ([A-]/0.10) = 0
[A-] = 0.10 M
Now, we know that we need the concentration of the conjugate base to be 0.10 M in the buffer. Since the initial solution had a concentration of 0.10 M for both the weak acid and its conjugate base, this means that we need to add NaOH to convert some of the weak acids into its conjugate base.
The balanced chemical equation for the reaction between NaOH and the weak acid is:
HA + NaOH → A- + H2O
The mole ratio between HA and NaOH is 1:1, so we can use the equation:
Moles of NaOH = Molarity of NaOH x Volume of NaOH
To find the volume of NaOH needed, we can rearrange the equation:
The volume of NaOH = Moles of NaOH / Molarity of NaOH
Since we know that the initial solution had a volume of 20 mL and a concentration of 0.10 M, we can find the moles of the weak acid present:
Moles of HA = Concentration of HA x Volume of HA
Moles of HA = 0.10 x 20 mL
Moles of HA = 0.002 mol
Since we need the concentration of the conjugate base to be 0.10 M, we know that the moles of the conjugate base must be the same as the moles of the weak acid. So:
Moles of A- = Moles of HA = 0.002 mol
To convert all of the weak acids into its conjugate base, we need to add enough NaOH to neutralize 0.002 mol of the weak acid. The balanced chemical equation shows that 1 mole of NaOH reacts with 1 mole of HA, so we need to add 0.002 moles of NaOH. To find the volume of NaOH needed, we can use the equation:
The volume of NaOH = Moles of NaOH / Molarity of NaOH
The volume of NaOH = 0.002 mol / 0.10 M
Volume of NaOH = 0.020 L
Volume of NaOH = 20 mL
Therefore, the student should add 20 mL of 0.10 M NaOH to 20 mL of 0.10 M HA to prepare a buffer with a pH of 3.4.
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Describe some tests that could be done to determine what an unknown substance is.
Answers
Answer:
by finding melting and boiling points
Explanation:
Answer:
Simple chemical tests can be used to identify the presence of various elements or classes of molecules (Tollen's test). ... Electron spin resonance (ESR): Also referred to as electron paramagnetic resonance (EPR), this method uses the spins of unpaired electrons in molecules to determine structure
How does the us constitution protect democratic ideals?
Answers
Answer: These ideas, that all men are created equal and that government is based on the consent of the governed, became the foundation for the US political ideal of popular sovereignty: that the government exists to serve the people, who elect representatives to express their will.
Explanation: Hope this helped! <3
You pull horizontally on a 50 kg crate with a force of 400N and the friction force on the crate in 150N. What is the acceleration of the crate?
Answers
If you pull horizontally on a 50 kg crate with a force of 400 N and the friction force on the crate of 150 N, then the acceleration of the crate would be 5 m / s² .
What is Newton's second law?Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.
As given in the problem if you pull horizontally on a 50 kg crate with a force of 400 N and the friction force on the crate in 150 N.
The net force acting on the crate = 400 N - 150 N
= 250 N
The acceleration of the crate = 250 / 50
= 5 m / s²
Thus, the acceleration of the crate would be 5 m / s² .
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A bar, 22 mm times 30 mm in cross-section, is loaded axially in tension with F_min = -4 kN and F_max = 12 kN. A 10 mm hole passes through the center of the 30 mm side. The steel has S_Ut = 500 MPa and S_y = 350 MPa. What are the notch sensitivity and fatigue stress concentration factors for this bar? What are the mean and alternating stresses? Find the fatigue strength for 100 cycles 10,000 cycles 100,000 cycles 1,000,000 cycles Infinite life
Answers
The notch sensitivity and fatigue stress concentration factors for the bar are calculated to determine the mean and alternating stresses and find the fatigue strength for different cycles.
What are the factors influencing the fatigue strength and stress concentration in the given bar?To calculate the notch sensitivity and fatigue stress concentration factors, we need to consider the presence of the 10 mm hole in the center of the 30 mm side of the bar. The notch sensitivity factor quantifies the effect of the hole on the stress concentration, while the fatigue stress concentration factor determines the increase in stress due to cyclic loading.
The mean stress (σm) is the average of the minimum (F_min) and maximum (F_max) axial loads applied to the bar. The alternating stress (σa) is half the difference between F_max and F_min.
The fatigue strength for a certain number of cycles is determined by applying the appropriate factors to the ultimate tensile strength (S_Ut) or yield strength (S_y) of the material. The fatigue strength is typically given for a specified number of cycles, such as 100, 10,000, 100,000, or 1,000,000 cycles. The fatigue strength for infinite life refers to the stress level below which the material can withstand an unlimited number of cycles without failure.
To provide accurate values for the notch sensitivity, fatigue stress concentration factors, mean and alternating stresses, and fatigue strength for the specified number of cycles, further calculations and data specific to the material properties and geometry of the bar are required.
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What has more energy a 2 kg mass at 10 m/s or a 2 kg mass 5 m above the ground
Answers
Answer:
Both have same energy
Explanation:
Given:
Sample 1
Mass m = 2 kg
Velocity v = 10 m/s
Sample 2
Mass m = 2 kg
Height h = 5 m
Assume g = 10 m/s²
Find:
What has more energy
Computation:
In sample 1
Ke = 1/2(m)(v)²
Ke = 1/2(2)(10)²
Ke = 100 joule
In sample 2
Pe = mgh
Pe = (2)(10)(5)
Pe = 100 joules
Both have same energy
5. A mass of 25 g moves with simple harmonic motion. It has "springiness" of 1.5 N/m and frictioncauses it to slow down with a damping constant of 250 g/s. Is the system overdamped orunderdamped? What would the damping constant need to be for the system to be critically damped?
Answers
For the system to be critically damped, the damping constant should be equal to the critical damping constant, which is approximately 0.346 kg/s.
To determine if the system is overdamped or underdamped, we need to compare the damping constant with the critical damping constant. The critical damping constant can be calculated using the formula:
Critical damping constant = 2 * sqrt(mass * springiness)
where mass is in kg and springiness is in N/m.
First, convert the mass from grams to kilograms: 25 g = 0.025 kg.
Now, calculate the critical damping constant:
Critical damping constant = 2 * sqrt(0.025 kg * 1.5 N/m) ≈ 0.346 kg/s
The given damping constant is 250 g/s, which is equivalent to 0.25 kg/s. Since the damping constant (0.25 kg/s) is less than the critical damping constant (0.346 kg/s), the system is underdamped.
For the system to be critically damped, the damping constant should be equal to the critical damping constant, which is approximately 0.346 kg/s.
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Find the derivative of the function y=sin x² with respect to x at x=√π.
Answers
Answer: y'=-0.3924695585
Explanation: Find the first derivative of the function y then plug in x.
y'=2(sinx)(cosx)
y'=2(sin(√π))(cos(√π))
y'=2(.9797359)(-0.2002935)
y'=-0.3924695585
What is the average acceleration during the time interval 0 seconds to 10 seconds?
A. 0.5 meters/second?
B. 1 meter/second
C. 2 meters/second?
D. 3 meters/second?
Answers
Answer:
yea its D .
Explanation:
Which of the following is the independent variable in this experiment? (Velocity)
A. The distance the ball travels
B. The mass of the ball C.The time it takes the ball to travel
D.The average velocity of the ball
Answers
Answer:
B. The mass of the ball
What physical quantity describing motion does the driver neglect when he/she practices tailgating? [Choices: distance, displacement, speed, velocity or acceleration]
Answers
The physical quantity that is neglected when practicing tailgating is :
Distance TailgatingTailgating is the act of driving or following a vehicle very closely and this can be very dangerous as well, during this act the distance between the vehicles is been neglected by the driver.
Distance is the difference in position of an object with time in respect to another object. ( i.e It is a scalar quantity ).
Hence we can conclude that the physical quantity that is neglected when practicing tailgating is Distance.
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as light passes from water into air it has a refracted angle of 35 degrees. calculate the incident angle of the light.
Answers
What is the speed of an object at rest?
0 m/s
O 1 m/s
O 10 m/s
Answers
Answer:
1 m/s so number 2 is the right one
Explanation:
so when it is at rest it still has some of the left over energy so it would be at 1 m/s
what is the mass and volume of 1000kg/m3 of water?
Answers
Answer: The mass would be 1000m3 and the volume would be 1000kg
Explanation:
a car of mass 1850 kg is traveling at 22.5 m/s in a straight line. a truck of mass 3170 kg has the same momentum as the car. the speed of the truck is
Answers
A car of mass 1850 kg is traveling at 22.5 m/s in a straight line. A truck of mass 3170 kg has the same momentum as a car. The speed of the truck is 13.43 m/s.
How to solve momentum and speed-related problems?Momentum and speed-related problems can be solved by using the formula, p= mv. The momentum of an object is defined as the product of its mass and velocity.
The formula for the speed of an object is given by,
speed = distance/time.
To solve this problem, we will equate the momentum of the car with the momentum of the truck.
the momentum of car = momentum of truck
m₁v₁ = m₂v₂
where m₁ = 1850 kg, v₁ = 22.5 m/s, m₂ = 3170 kg and v₂ = speed of truck
Substituting the given values in the above equation, we get
1850 × 22.5 = 3170 × v₂
v₂ = 41250/3170
v₂ = 13.43 m/s
Therefore, the speed of the truck is 13.43 m/s.
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Mechanical and chemical weathering depend on _______________________________________ and temperature.
A.) acid
B.)air
C.)water
Answers
Answer:
C.)water
Explanation:
Weathering is the physical disintegration and chemical decomposition of rocks to form sediments and soils.
Mechanical weathering is the breaking down of rocks by physical means.
Chemical weathering is the decay of rocks by chemical means.
Both chemical and mechanical requires water for the processes to occur. Water is usually the medium for chemical actions to take place in a rock. For mechanical processes, water in different phases plays a very important role too.how does the internal energy of the ice and water mixture change if the temperature does not rise while the ice is melting?
a. It decreases, because you need to use energy to make freezer run; but ice melts spontaneously
b. no enough information to determine
c. it increases, because it takes more energy for water molecules to be disordered than to be ordered
d. it remains the same because both are at the same temperature
Answers
Option-d). it remains the same because both are at the same temperature. If the temperature does not increase while the ice melts, the internal energy of the ice and water mixture changes.
A temperature is a unit of hotness or coldness that can be described in terms of a variety of arbitrary scales. It also indicates the direction in which heat energy will naturally flow, i.e., from a hotter body to a colder body (one at a lower temperature). Temperature is not the same as the energy of a thermodynamic system; for instance, an iceberg has a considerably higher temperature than a burning match, but it has a far larger total heat energy than a match. As opposed to extensive qualities like mass or volume, which are reliant on the amount of stuff being studied, the temperature is an intensive attribute, just like pressure or density.
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The height of a ball t seconds after it is thrown upward from a height of 6 feet and with an initial velocity of 48 feet per second is f (t)
Answers
The height of the ball at time t seconds can be determined using the equation f(t) = -16t^2 + 48t + 6. The ball reaches its maximum height after 1.5 seconds, and the height can be found by substituting the value of t into the equation.
The height of a ball thrown upward can be represented by a quadratic function \(f(t) = -16t^2 + v0t + s0\), where v0 is the initial velocity and s0 is the initial height.
In this case, the ball is thrown upward from a height of 6 feet and with an initial velocity of 48 feet per second. Therefore, the equation becomes f(t) = -16t^2 + 48t + 6.
To find the height of the ball at a specific time t, substitute the value of t into the equation f(t). For example, to find the height of the ball after 2 seconds, substitute t = 2 into the equation:
f(2) = -16(2)^2 + 48(2) + 6
= -64 + 96 + 6 = 38 feet.
It's important to note that the height of the ball will be negative when it is below its initial height (below 6 feet in this case). The ball reaches its maximum height when its velocity becomes zero, which can be determined by finding the time when f'(t) = 0. In this case, f'(t) = -32t + 48 = 0. Solving this equation gives t = 1.5 seconds.
In summary, the height of the ball at time t seconds can be determined using the equation f(t) = -16t^2 + 48t + 6.
The ball reaches its maximum height after 1.5 seconds, and the height can be found by substituting the value of t into the equation.
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