For the sluice gate problem of Example 3.10, list all the boundary conditions needed to solve this flow exactly by, say, computational fluid dynamics. EXAMPLE 3.10 The sluice gate in Fig. E3.10a controls flow in open channels. At sections 1 and 2, the flow is uniform and the pressure is hydrostatic. Neglecting bottom friction and atmospheric pressure, derive a formula for the horizontal force F required to hold the gate. Express your final formula in terms of the inlet velocity Vi, eliminating V2.

Answer:

-x, +x, -y, +y, -z, +z

Explanation:

These are the 6 axes

Answer:

a) the tubular resistance of the blood vessel is 6.88 Gpa.s/m³.

b) the flow rate is 5.8 ml/min

Explanation:

Given the data in the question;

Length of blood vessel L = 1 m

radius r = 1 mm = 0.001 m

blood viscosity μ = 2.7 × 10⁻³ pa.s = 2.7 × 10⁻³ × 10⁻⁹ Gpa.s = 2.7 × 10⁻¹² Gpa.s

Now, we know that Resistance = 8μL / πr⁴

so we substitute

Resistance = [8 × (2.7 × 10⁻¹²) × 1] / [π(0.001)⁴]

Resistance = [2.16 × 10⁻¹¹] / [3.14159 × 10⁻¹²]

Resistance = 6.8755 ≈ 6.88 Gpa.s/m³

Therefore, the tubular resistance of the blood vessel is 6.88 Gpa.s/m³.

b)

blood pressure at the inlet of the vessel = 43 mm Hg

blood pressure at the outlet of the vessel = 38 mm Hg

flow rate = ?

we know that;

flow rate Q = ΔP / R

where ΔP is change in pressure and R is resistance.

ΔP = Inlet pressure - Outlet pressure = 43 - 38 = 5 mm Hg =  665 pa

R = 6.8755 Gpa.s/m³ = { 6.8755 × 10⁹ / 60 × 10⁶ } = 114.5916 pa.min.ml⁻¹

so we substitute

Q =  665 pa / 114.5916 pa.m.ml⁻¹

Q = 5.8 ml/min

Therefore, the flow rate is 5.8 ml/min

Based on the image attached, the reading of micrometer is= 15.20.

You will see a line of numbers running down the barrel of your micrometer, starting with the barrel scale. On the barrel scale, each number corresponds to 0.100. Looking at the barrel, 1 equals 0.100, 2 equals 0.200, 3 equals 300, and so on. The distance between each tick mark and the larger numbers on the barrel is 0.025, or 25 thousandths. 

Note that micrometer is one that is also referred to as a micrometer screw gauge—is a tool with a calibrated screw that is frequently used for precise measurement of components in mechanical engineering, and others.

Looking at the image, you will see the stop ends at 15 and  and 20 so adding them together will be option A. 15.20.

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Answer:

C. Signal-to-quantization-noise ratio

Explanation:

The incremental drain-source resistance for a MOS transistor biased in the triode region is the ratio of the small change in drain current to the small change in gate voltage and is also dependent on the transistor's channel length, channel width, and oxide thickness.

For a MOS transistor biased in the triode region, the incremental drain-source resistance (also known as the "transconductance") can be defined as the ratio of the small change in drain current to the small change in gate voltage, ΔID/ΔVG. In other words, the transconductance is the change in drain current divided by the change in gate voltage.

The transconductance is also dependent on the transistor's channel length, channel width, and oxide thickness. For a given channel length and width, a longer oxide thickness will result in a lower transconductance, and vice versa. This is because a longer oxide thickness reduces the channel current, which in turn reduces the drain current.

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In the given case, Technician B is right, as according to Technician B, an automobile computer may scan its input and output circuits for an improper resistance problem.

A technician is a worker in a technological sector who is skilled in the appropriate skill and technique and has a practical comprehension of the theoretical concepts.

We also require professionals that have been adequately trained to work on, repair, and maintain the equipment. Machines that receive proper care will work more smoothly, increasing productivity on the job site while also helping to keep personnel safe.

A technician is a professional worker who install, fixes, replaces, and serves many sorts of equipment and systems. A technician spends his or her day doing various duties, depending on the situation, such as assessing issues, executing tests, and fixing equipment.

Therefore, option B is correct.

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The ways to increase air traffic control revenues in air transportation are given below in explanation part.

Several ways might be taken into consideration to raise air traffic control revenues:

Infrastructure Modernization and Expansion: By improving capacity and efficiency, air traffic control systems and infrastructure can handle more passengers and provide better services.

Implement performance-based navigation (PBN): PBN is a navigational concept that enables aeroplanes to use satellite-based systems to fly more direct routes.

Offer Value-Added Services: In addition to standard control and surveillance duties, air traffic control authority can provide value-added services.

Thus, it is vital to remember that efficient air traffic management, safety, and security should constantly be balanced with revenue generating.

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Answer:

\(\mathbf{\Delta_{max}=0.78 \ mm}\)

Explanation:

From the given information;

A simply supported beam (E = 12 GPa)

load q = 125 N/m

point load P = 200 N

the rectangular cross section

b = 75 mm

h = 200 mm

length = 3.6 m

The objective is to  calculate the maximum deflection of the beam;

Using the formula;

\(I = \dfrac{1}{E}*bh^3\)    about the z-axis that goes through the central

\(I = \dfrac{1}{12}*(75 \ mm)*(200 \ mm)^3\)

\(I = 5*10^7 \ mm^4\)

The length L = 3.6 m = 3600 mm

The maximum deflection of the beam can be calculated by using the formula:

\(\Delta _{max} = \dfrac{5}{384}* \dfrac{qL^4}{EI}+\dfrac{PL^3}{48EI}\)

\(\Delta _{max} = \dfrac{1}{12*10^3 \frac{N}{mm^2}*5*10^7 \ mm^4 }[ \dfrac{5*\frac{125 \ N}{100 \ mm}*3600 \ mm^4}{384}+\dfrac{200*(3600 \ mm )^3}{48}]\)

Thus; the maximum deflection of the beam is \(\mathbf{\Delta_{max}=0.78 \ mm}\)

Answer:

The correct answer is "99.9%".

Explanation:

According to the information given in the question,

\(P(1 \ fail) = 0.1\)

The probability of all fail will be:

\(P(all \ fail) = (0.1)^3\)

                  \(=0.001\)

hence,

\(P(not \ all \ fail)= 1-P(all \ fail)\)

                        \(=0.999\)

                        \(=99.9\) (%)

Thus the above is the right answer.

Answer:

Many techniques have been developed for the measurement of pressure and vacuum. Instruments used to measure and display pressure in an integral unit are called pressure meters or pressure gauges or vacuum gauges.

C) No, because a central assumption of the chart would be inaccurate.

The accuracy of a chart that specifies only the outdoor ambient temperature relies on the assumption that the indoor relative humidity is around 50 percent. If the indoor relative humidity deviates significantly from 50 percent, the chart's accuracy would be compromised. The relationship between temperature, relative humidity, and other factors affects the performance and comfort levels of a space, so a deviation from the assumed conditions would render the chart inaccurate.

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2.4 8 cubic yards of concrete do you need to order to pour 32 transformer pads that are 35 inches wide by 28 inches long by 3% inches high.

What is transformer?
A transformer is an electrical device used for changing the amount of voltage in an alternating current (AC) circuit. It works by converting electrical energy from one voltage level to another, without changing the frequency. Transformers are used in a variety of applications, from powering electrical equipment to stepping up or down voltage in a power distribution system. Transformers come in many shapes and sizes and can be designed to meet specific needs. The basic components of a transformer are the core, primary and secondary windings, and the insulation system. The core provides a magnetic path for the electricity to travel through, while the windings carry the electrical current. The insulation system prevents any electrical leakage.

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The correct answer is The work required by the turbine to turn the compressor is approximately 15,395,006.08 J/s ,if the compressor in a jet engine running an ideal Brayton Cycle
compresses 16 kg/s of air starting at 312 K with a pressure ratio
of 30.

The work required by the turbine to turn the compressor can be calculated using the ideal Brayton Cycle equations.

In the Brayton Cycle, the work done by the compressor is given by:

Wc = m * Cp * (T2 - T1)

Where:
Wc = work done by the compressor
m = mass flow rate of air (16 kg/s)
Cp = specific heat capacity of air at constant pressure
T1 = initial temperature of air (312 K)
T2 = final temperature of air after compression

To find T2, we can use the pressure ratio (PR) and the ideal gas law:

PR = (P2 / P1) = (T2 / T1)^(k / (k-1))

Where:
P1 = initial pressure of air
P2 = final pressure of air after compression
k = specific heat ratio of air (usually around 1.4 for air)

Given the pressure ratio of 30, we can calculate P2:

30 = (P2 / P1) = (T2 / 312)^(1.4 / 0.4)

Solving this equation for T2, we find:

T2 = 312 * (30^(0.4)) = 312 * 4.057 = 1270.784 K

Substituting the values into the work equation, we get:

Wc = 16 * Cp * (1270.784 - 312)

To find the specific heat capacity of air at constant pressure, we can assume it is approximately constant at room temperature, which is around 25 degrees Celsius or 298 K. Cp for air at 298 K is approximately 1005 J/(kg·K).

Wc = 16 * 1005 * (1270.784 - 312)

Calculating the above expression, we find:

Wc ≈ 16 * 1005 * 958.784 = 15,395,006.08 J/s

Therefore, the work required by the turbine to turn the compressor is approximately 15,395,006.08 J/s.

In conclusion, the turbine needs to perform approximately 15,395,006.08 J/s of work to turn the compressor in a jet engine operating on an ideal

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Answer:

a. 1.6 Kbytes/min

b. 10.417 Mbytes/min

Explanation:

a. The DSL modem operates at 768 Kbits/sec.

But,

    8 bits = 1 byte and 1 Kbit = 1 000 bits, so that:

       = \(\frac{768 000}{8}\)

      = 96 000 bytes

Therefore, the modem operates at 96 Kbytes/sec.

The byte to be received in 1 minute can be calculated thus;

Since 60 seconds = 1 minute, then:

 = \(\frac{96000}{60}\)

  = 1600

 = 1.6 Kbytes/min

The modem receives 1.6 Kbytes/min

b. The USB sends 5 Gbits/sec.

But, 8 bits = 1 byte and 1 Gbit = 1000000000 bits so that:

= \(\frac{5000000000}{8}\)

= 625000000

= 0.625 Gbytes

The USB sends 0.625 Gbyte/sec.

Since 60 seconds = 1 minute, then:

=  \(\frac{625000000}{60}\)

= 10416666.67

= 10.417 Mbytes/min

Answer:

the reduction in the heat gain is 2.8358 kW

Given that;

Shaft outpower of a motor  = 75 hp = ( 75 × 746 ) = 55950 W

Efficiency of motor  = 91.0% = 0.91

High Efficiency of the motor  = 95.4% = 0.954

now, we know that, efficiency of motor is defined as;  =  /

where   is the electric input given to the motor

so

=  /

we substitute

= 55950 W / 0.91

= 61483.5 W

= 61.4835 kW

now, the electric input given to the motor due to increased efficiency will be;

=  /

we substitute

= 55950 W / 0.954

= 58647.79 W

= 58.6477 kW

so the reduction of the heat gain of the room due to higher efficiency will be;

Q =  -

we substitute

Q = 61.4835 kW - 58.6477 kW

Q = 2.8358 kW

Therefore, the reduction in the heat gain is 2.8358 kW

Explanation:  i hope this answer your question if this is wrong or correct please let me know.also no trying to be rude but can you sent me like a thanks?

The dimensions of the rapid mixing tank for the given production rate of water are 5.8 feet for the width and 7.25 feet for the depth.

Production rate of water = 500,000 gallons/day

Hydraulic residence time = 30 seconds

Number of tanks = 2

Depth of the tank = 1.25 times of width. We are supposed to determine the dimensions of the rapid mixing tanks.For the purpose of the rapid sand filtration plant, the dimension of the rapid mixing tank should be at least equal to the minimum hydraulic residence time which is 30 seconds.So, the volume of water that is required to be treated per second can be calculated as follows:

V = Production rate of water / 24 × 3600 seconds = 500,000 / 24 × 3600 = 5.787 gallons/second. Let, x be the width of the tank, then the depth of the tank should be 1.25x.So, the volume of the tank can be expressed as follows:

V = x^2 × 1.25x = 1.25x^3

The minimum hydraulic residence time is given as 30 seconds.Therefore, the volume of the rapid mixing tank should beV = Q × T = 5.787 × 30 = 173.61 gallons. Therefore,1.25x^3 = 173.61x^3 = 138.89 feet. Cube root of 138.89 is approximately 5.8.Therefore, the width of the tank is approximately 5.8 feet. The depth of the tank is 1.25 times the width.Therefore, the depth of the tank is 7.25 feet.Finally, the dimensions of the tank are Width = 5.8 feet. Depth = 7.25 feet. Hence, the dimensions of the tank for the given production rate of water are 5.8 feet for the width and 7.25 feet for the depth.

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Explanation:

1. Verify the scope of work: Make sure you understand the scope of work and requirements for the customer's club instance. Confirm with the customer if any specific settings or customizations are required.

2. Schedule the PIC: Coordinate with the customer to schedule a suitable time and date for the PIC. Ensure that all necessary stakeholders are available and informed.

3. Review the customer's club instance: Review the customer's club instance to identify any potential issues or conflicts that need to be addressed during the PIC. Check the instance for any configuration, integration, or data issues.

4. Prepare for the PIC: Prepare a checklist and any necessary tools or documentation for the PIC. Make sure you have access to the customer's club instance, including any necessary login credentials or permissions.

5. Initiate the PIC: Once you have completed the above steps, initiate the PIC by going through the checklist and verifying that the customer's club instance is set up correctly and meets their requirements. Identify any issues or gaps that need to be addressed and work with the customer to resolve them.

6. Follow up: Once the PIC is complete, provide the customer with a report or summary of the findings. Follow up with any necessary actions or next steps, and confirm that the customer is satisfied with the results

Answer:

laptop printer scanner data

At 1.2mpa pressure and 50c

What is pressure?
By pressing a knife against some fruit, one can see a straightforward illustration of pressure. The surface won't be cut if you press the flat part of the knife against the fruit. The force is dispersed over a wide area (low pressure).

a)Mass flow rate of the refrigerant
Therefore h1= condenser inlet enthalpy =278.28KJ/Kg
saturation temperature at 1.2mpa is 46.29C
Therefore the temperature of the condenser

T2 = 46.29C - 5
T2 = 41.29C

Now,
d)power consumed by compressor W = 3.3KW
Q4 = QL + w = Q4
QL = mR(h1-h2)-W
= 0.0498 x (278.26 - 110.19)-3.3
=5.074KW
Hence refrigerator load is 5.74Kg

(COP)r = 238/53
(Cop) = 4.490

Therefore the above values are the (a) mass flow rate of the refrigerant, b) the refrigerant load, c) the cop, and d) the minimum power input to the compressor for the same refrigeration load.

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Answer:

Shallow foundations, often called footings, are usually embedded about a metre or so into soil. ... Another common type of shallow foundation is the slab-on-grade foundation where the weight of the structure is transferred to the soil through a concrete slab placed at the surface.

Explanation:

Because I said so.

Answer:

24cm sureeeereereeeeee

Answer:

On wht!?!?!?!

Explanation: