Area of 4circles=4(4π}+16π in^2
Hence the area if square= 4^3=64
Remaining area
\(\\ \sf\longmapsto (64-16\pi)in^2\)
3. Your teacher is putting together 6 boxes of erasers for the table groups of students. If there are 50 erasers, are there enough for your teacher to put 9 erasers in each box? Use pictures to help you solve the problem.
No, 9 erasers in each box are not possible.
What is an expression?An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.
Example: 2 + 3x + 4y = 7 is an expression.
We have,
Number of erasers = 50
Number of box = 6
Number of erases in each box.
= 50/6
= 8.33
= 8
So,
9 erasers in each box are not possible.
Thus,
9 erasers in each box are not possible.
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Write the digit in the ten thousands place. 913,256
Answer: 913,256
6-ones place
5-tens place
2-hundreds place
3- thousands place
1-ten thousands place
9-hundred thousands place
Soooo ur answer is 1, 1 is in the ten thousands place.
Answer: the ten-thousands place is the 5th digit from the left. This digit is 1
Step-by-step explanation:
In the number 6855 is the 800 1/10 of 6000
Answer:
No
Step-by-step explanation:
A recipe requires 1 cup of milk for every 4 cups of flour. Choose a linear equation that describes the relationship.
A. y=4x
B. y=4x+1/4
C. y=1/4x+4
D. y=1/4x
Answer:
i think it is a but i am not shore. Hope this helps
Step-by-step explanation:
Which value is a solution to the inequality x 4
Answer:
0
Step-by-step explanation:
x < 4 means all numbers less than 4, excluding 4 itself.
4.5 > 4.
5 > 4.
so 0 is the solution
Answer:
4
Step-by-step explanation:
interval notation ( negative infinity, 4)
Roberto said, "I'm thinking of a fraction that is equivalent to 3 9 . The denominator is 2 more than the numerator." What fraction is Roberto thinking of?
The fraction that Roberto is thinking of is \(\mathbf{\dfrac{x}{2+x} = \dfrac{3}{9}}\) and the value of x = 1
What is a fraction?
A fraction is that part of a whole number that is used to express figures into two parts which are the numerator(upper part) and the denominator(lower part) and these two parts are separated by a division line.
From the given information, we have:
\(\mathbf{\dfrac{x}{2+x} = \dfrac{3}{9}}\)
Cross multiply
9x = 3(2+x)
9x = 6 + 3x
9x - 3x = 6
6x = 6
x = 6/6
x = 1
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A pallet of toggle bolts weighs 516 kilogram. If a warehouse has 82 pallets what is their total weight
Answer:
no se
perdon
Step-by-step explanation:
Identify the kind of graph shown?
Arithmetic
Geometric
Neither
Answer:
Arithmetic Sequence
Step-by-step explanation:
how would someone use the cross product property on an equation with 3 different values instead of two? I provided an example image
Using the cross product for the proff of Pythagoras theorem, the correct step is
By the cross product property, AB² = BC multiplied by BD
What is cross product propertyThe cross product property is typically used to solve equations with two values, where the product of the extremes (the outer terms) is equal to the product of the means (the inner terms).
For the similar triangles, the ratio is as follows
BD / BA = BA / BC
BA² = BD * BC
and AB = BA, hence
BA² = BD * BC
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if it is given that "x" is 23.5 - proof that it is a point of intersection at y= 1/2(x) - 25 if y is equal to 11. been trying but not working out.
When substituting y = 11 into the equation y = 1/2(x) - 25, we find that x = 72, confirming that (23.5, 11) is a valid point of intersection.
Given that x is 23.5, it is required to prove that it is an intersection point for the equation y = 1/2(x) - 25 when y is equal to 11.
The equation is given as y = 1/2(x) - 25
When y = 11, we can substitute the value of y in the equation to obtain 11 = 1/2(x) - 25
This can be simplified as 11 + 25 = 1/2(x)36 = 1/2(x)
On solving, x = 72Thus, when y is equal to 11 and x is equal to 72, the given point of intersection is valid.
Therefore, it can be concluded that x = 23.5 is a point of intersection for the equation y = 1/2(x) - 25 when y is equal to 11.
In summary, when given an equation with two variables, we can find the point of intersection by setting one of the variables to a given value and solving for the other variable. In this case, when y is equal to 11, we can solve for x and obtain the point of intersection as (72,11).
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The function G(m) = 49.5m + 89.75 represents the cost of joining the gym in addition to the one time membership fee. The cost, G, is measured in dollars for m months. 1. Find the value of G(6).
Answer:
386.75
Step-by-step explanation:
added in the picture
The cost of joining the gym for 6 months is 386.75.
Given,
The function G(m) = 49.5m + 89.75 represents the cost of joining the gym in addition to the one-time membership fee.
The cost, G, is measured in dollars for m months.
We need to find the value of G(6).
Here,
The one-time membership = 89.75.
Now,
Putting m = 6 months in:
G(m) = 49.5m + 89.75
G(6) = 49.5 x 6 + 89.75
= 297 + 89.75
= 386.75
Thus the cost of joining the gym for 6 months is G(6) = 386.75.
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Find the measurements (the length L and the width W) of an inscribed rectangle under the line with the 1st quadrant of the x & y coordinate system such that the area is maximum. Also, find that maximum area. To get full credit, you must draw the picture of the problem and label the length and the width in terms of x and y.
The question is incomplete. Here is the complete question.
Find the measurements (the lenght L and the width W) of an inscribed rectangle under the line y = -\(\frac{3}{4}\)x + 3 with the 1st quadrant of the x & y coordinate system such that the area is maximum. Also, find that maximum area. To get full credit, you must draw the picture of the problem and label the length and the width in terms of x and y.
Answer: L = 1; W = 9/4; A = 2.25;
Step-by-step explanation: The rectangle is under a straight line. Area of a rectangle is given by A = L*W. To determine the maximum area:
A = x.y
A = x(-\(\frac{3}{4}.x + 3\))
A = -\(\frac{3}{4}.x^{2} + 3x\)
To maximize, we have to differentiate the equation:
\(\frac{dA}{dx}\) = \(\frac{d}{dx}\)(-\(\frac{3}{4}.x^{2} + 3x\))
\(\frac{dA}{dx}\) = -3x + 3
The critical point is:
\(\frac{dA}{dx}\) = 0
-3x + 3 = 0
x = 1
Substituing:
y = -\(\frac{3}{4}\)x + 3
y = -\(\frac{3}{4}\).1 + 3
y = 9/4
So, the measurements are x = L = 1 and y = W = 9/4
The maximum area is:
A = 1 . 9/4
A = 9/4
A = 2.25
Given the figure below .find X and Y to three significant digits.Write your answer in the answer box provided below
Check the picture below.
Make sure your calculator is in Degree mode.
\(\cos(25^o )=\cfrac{\stackrel{adjacent}{x}}{\underset{hypotenuse}{12}}\implies 12\cos(25^o)=x\implies \boxed{10.876\approx x} \\\\[-0.35em] ~\dotfill\\\\ \sin(25^o )=\cfrac{\stackrel{opposite}{z}}{\underset{hypotenuse}{12}}\implies 12\sin(25^o)=z \\\\[-0.35em] ~\dotfill\\\\ \sin(50^o )=\cfrac{\stackrel{opposite}{z}}{\underset{hypotenuse}{y}}\implies y=\cfrac{z}{\sin(50^o)}\implies y=\cfrac{12\sin(25^o)}{\sin(50^o)}\implies \boxed{y\approx 6.62}\)
Which statements are correct? A) (-7.3)(10)=-73
B) (12.3)(5.1)(-10)=62.73
C) -(0.5)(0.75)=0.375
D) The product of two negative is negative
E) The product of negative and a positive is negative.
Answer:
A and C and E
Step-by-step explanation:
Answer:
A) B)F)Step-by-step explanation:
to understand thisyou need to know about:integertips and formulas:product of two negative is positiveproduct of negative and positive is negativelet's solve:A)correct
(-7.3)(10)-73B)incorrect
(12.3)(5.1)(-10)(62.73)(-10)-627.3C)incorrect
-(0.5)(0.75)-(0.375)-0.375D)incorrect
The product of two negative is negativeF)correct
The product of negative and a positive is negative.10. In a grocery shop, there was 2510 kg 350 g of wheat in the morning.
During the day, 890 kg 600 g of wheat was sold out. How much of wheat was
left in the shop in the evening?
Answer :
1619kg 750g
Explanation :
mass of wheat in the morning : 2510kg 350g
mass of sold out wheat during: 890kg 600g
the day
mass of wheat left in the shop: 1619kg 750g
in the evening
Dylan is conducting an experiment and wants to choose the ball with the lowest density.
Ball A = diameter 7cm, mass 1.742kg
Ball B = diameter 6cm, mass 1.040kg
4
Volume of sphere =
3 773
Density
= mass = volume
TT = 3.142
Which ball should he choose?
Dylan should choose Ball B which having lowest density.
What is volume of spere?
The volume of a sphere is calculated using the formula volume = 4/3πr³ where r is the sphere's radius.
Given that:
Ball A = diameter 7cm, mass 1.742kg
Ball B = diameter 6cm, mass 1.040kg
As we know that,
volume of a sphere =4/3πr³
1) For Ball A,
volume of a Ball A = 4/3π(3.5)³
volume of a Ball A = 179.6 cm³
given mass for Ball A is 1.742 kg = 1742 g.
So, Density = \(\frac{mass}{volume}\)
Density of Ball A will be 9.7 g/cm³.
2) For Ball B,
volume of a Ball B = 4/3π(3)³
volume of a Ball B = 113.11 cm³
given mass for Ball B is 1.040 kg = 1O40 g.
So, Density = \(\frac{mass}{volume}\)
Density of Ball B will be 9.19 g/cm³.
By comparing density of both balls,
Density of Ball A > Density of Ball B
Hence, Dylan should choose Ball B which having lowest density.
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When f(x)=4, what is the value of x?
This mapping shows a functional relationship.
Domain
Range
оо
O 2
2
4
3
-3
0
4
-1
→-1
→ 3
Check the picture below.
The value of f(x) at x=4 is 2.
What is Function?A function is an expression, rule, or law in mathematics that describes a relationship between one variable (the independent variable) and another variable (the dependent variable). Functions are common in mathematics and are required for the formulation of physical relationships in the sciences.
We have to find the value of function for x=4.
This means that from the figure we have to find the value of y when x= 4.
Now, looking into the figure we have
f(4)= 2
f(0)= -2
f(-1)= -1
f(3)= 4
So, the required value is 2.
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Find the values of k and m in the parallelogram?
Answer:
In order to find the values of k and m in a parallelogram, you would need to have additional information such as the coordinates of the points that make up the parallelogram and the formulas or equations that relate k and m to these points.
Here is one way to find the values of k and m in a parallelogram:
Label the four vertices of the parallelogram as A, B, C, and D with the opposite sides parallel to each other.
Find the slope of the line segment AB by using the formula (y2-y1)/(x2-x1), where (x1, y1) and (x2, y2) are the coordinates of the two points.
Let the slope of AB be represented by k.
Find the slope of the line segment AD by using the same formula and let it be represented by m.
The values of k and m are now found.
Please note that, this method is only applicable if the Parallelogram is not degenerate i.e, it is not a rectangle or a line.
It is also important to keep in mind that different formulas or equations may be used depending on the specific context of the problem. It is also important to check that the slopes of opposite sides are equal.
Step-by-step explanation:
Evaluate the integral ∫2−1|x−1|dx
I think you might be referring to the definite integral,
\(\displaystyle \int_{-1}^2|x-1|\,\mathrm dx\)
Recall the definition of absolute value:
\(|x| = \begin{cases}x&\text{if }x\ge0\\-x&\text{if }x<0\end{cases}\)
Then \(|x-1|=x-1\) if \(x\ge1\), and \(|x-1|=1-x\) is \(x<1\). So spliting up the integral at x = 1, we have
\(\displaystyle \int_{-1}^2|x-1|\,\mathrm dx = \int_{-1}^1(1-x)\,\mathrm dx + \int_1^2(x-1)\,\mathrm dx\)
The rest is simple:
\(\displaystyle \int_{-1}^2|x-1|\,\mathrm dx = \left(x-\dfrac{x^2}2\right)\bigg|_{-1}^1 + \left(\dfrac{x^2}2-x\right)\bigg|_1^2 \\\\ = \left(\left(1-\frac12\right)-\left(-1-\frac12\right)\right) + \left(\left(2-2\right)-\left(\frac12-1\right)\right) \\\\ = \boxed{\frac52}\)
The parabola X= √y-9 opens: right left down up?
The parabola x = √(y - 9) opens upwards.The given parabolic equation is x = √(y - 9). Let's identify the direction of opening of this parabola.The general form of the equation of a parabola is y = a(x - h)² + k.
Comparing this to the given equation, we can see that h = 0 and k = 9. The vertex is therefore (h, k) = (0, 9). Now, let's determine whether the parabola opens upwards or downwards.
If the coefficient of (x - h)² is positive, the parabola opens upwards, and if it's negative, the parabola opens downwards. In this case, since the coefficient of (x - h)² is 1, which is positive, the parabola opens upwards.
Therefore, the parabola x = √(y - 9) opens upwards.
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PLEASE HELP I AM TRYING TO STUDY FOR A CALCULUS EXAM!! WORTH A TOTAL OF 100 POINTS!!!!!!!!!
Find the mass of a sphere of radius 7 if δ= kρ, k a constant.
Presumably, both δ and ρ represent density of some object. Considering the context, ρ is likely a function of 3 variables, ρ = ρ(x, y, z). Then the mass of the sphere with the prescribed density δ(x, y, z) = k ρ(x, y, z) is
\(\displaystyle \iiint_B k \rho(x,y,z) \, dx\, dy\, dz\)
where B is the set
\(B = \left\{(x,y,z) ~ : ~ x^2+y^2+z^2 \le 7^2\right\}\)
If you have all the details at hand, you can compute the integral by converting to spherical coordinates, substituting
\(\begin{cases}x = u \cos(v) \sin(w) \\ y = u \sin(v) \sin(w) \\ z = u \cos(w)\end{cases} \text{ and } dx\,dy\,dz = u^2 \sin(w) \, du \, dv \, dw\)
The integral then transforms to
\(\displaystyle k \int_0^{2\pi} \int_0^\pi \int_0^7 \rho(u\cos(v)\sin(w),u\sin(v)\sin(w),u\cos(w)) \, u^2 \sin(w) \, du \, dw \, dv\)
Without any additional information, there's not much more to say...
please I need help on question 7
Answer:
x = 90
y = 30°
∠ABC = 75°
Step-by-step explanation:
Finding the angles of isosceles triangle:ΔDAB is an isosceles triangle.
⇒ ∠ADB ≅ ∠ABD = y
In ΔABD ,
120 + y + y = 180 {Angle sum property of triangle}
120 + 2y = 180
2y = 180 - 120
2y = 60
y = 60 ÷ 2
\(\sf \boxed{y = 30^\circ}\)
ΔDCB is an isosceles triangle.
∠CDB ≅ ∠CBD = 45
x + 45 + 45 = 180
x + 90 = 180
x = 180 - 90
\(\sf \boxed{x = 90^\circ}\)
∠ABC = ∠ABD + ∠DBC
= 30 + 45
= 75°
Use the histogram to answer the following questions.
Frequency
The frequency of the class 90-93 is
The frequency of the class 94-97 is
This means that a total of
5.5
5
4.5
Your answers should be exact numerical values.
The frequency of the class 86-89 is
86
94
90
Duration of Dormancy (minutes)
dormancy periods were recorded.
The parameters that are needed to calculate a probability are listed as follows:
Number of desired outcomes in the context of a problem or experiment.Number of total outcomes in the context of a problem or experiment.Then the probability is calculated as the division of the number of desired outcomes by the number of total outcomes, hence it is the same as a relative frequency.
The total number of periods is given as follows:
5 + 6 + 4 = 15.
The frequency of each class is given as follows:
86 - 89: 5/15 = 1/3.90 - 93: 6/15 = 2/5.94 - 97: 4/15.Learn more about the concept of probability at https://brainly.com/question/24756209
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Please help urgent thank you
If he wants an average of 84, he needs to get at least 93 points.
What score does he need to get in the next test?Remember that the average value between 3 values A, B, and C is:
(A + B + C)/3
Here we know that the first two scores are 76 and 83 points, let's say that the third score is x, if we want to have an average of 84 or more, then we need to solve:
(76 + 83 + x)/3 = 84
159 + x = 252
x = 252 - 159
x = 93
So he needs to get at least 93 points in the next exam.
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y > x - 3 a. Change the inequality into slope- intercept form, and then change it into an equation.
The slope of the inequality y > x - 3 is 1
What is the slope of an inequality?
The slope of a line is the ratio of the amount that y increases as x increases some amount
To change the inequality y > x - 3 into slope,
substract x from both sides of the inequality
y- x > x - 3-x
= y-x>-3
= y<-3+x
From the inequality y<-3+x the co-efficient of x is 1
Hence, The slope of the inequality is 1
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A vacant lot is being converted into a community garden. The garden and a walkway around its perimeter have an area of 648 square feet. Find the width of the walkway if the garden measures 12 feet wide by 15 feet long.
The width cannot be negative, the width of the walkway is 6 feet. The total area of the garden and the walkway is given as 648 square feet. We know the area of the garden is length multiplied by width, which in this case is 12 feet by 15 feet, so the garden area is\(12 \times 15 = 180\) square feet.
To find the area of the walkway, we subtract the garden area from the total area. Therefore, the area of the walkway is 648 - 180 = 468 square feet.
The walkway surrounds the garden on all sides, so its length and width will be greater than the corresponding dimensions of the garden.
To calculate the width of the walkway, we can use the formula for the area of a rectangle, which is length multiplied by width. In this case, the length is 12 + 2x (twice the width of the walkway) and the width is 15 + 2x.
So, we have the equation\((12 + 2x) \times (15 + 2x) = 468\).
Expanding and rearranging the equation, we get\(4x^2 + 54x - 228 = 0.\)
Solving this quadratic equation using factoring, completing the square, or the quadratic formula, we find that x = 6 or x = -9/2.
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Bookwork code: N84
This is a new version of the question Make sure you start now workings
Calculate the range, in centimetres (cm), of the following
lengths:
15 cm, 0.5 cm, 10.3 cm, 16.7 cm, 21 cm,
8.6 cm
The range, in centimetres (cm), of the following lengths is 20.5 cm
What is the range?
The difference between the lowest and highest numbers is referred to as the range. For instance, the range will be 10 - 2 = 8 if the given data set is 2, 5, 8, 10, and 3.
As a result, the range may alternatively be thought of as the distance between the highest and lowest observation. The range of observation is the name given to the outcome. Statistics' range reflects the variety of observations.
Given, 15 cm, 0.5 cm, 10.3 cm, 16.7 cm, 21 cm, 8.6 cm
So, the highest value of length = 21 cm
the lowest value of length = 0.5 cm
Then, range = the highest value - the lowest value
= 21 - 0.5 = 20.5 cm
Hence, the range, in centimetres (cm), of the following lengths is 20.5 cm
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A survey of 800 women shoppers found that 17% of them shop on impulse. What is the 98% confidence interval for the true proportion of women shoppers who shop on impulse
Answer:
The 98% confidence interval for the true proportion of women shoppers who shop on impulse is
\(0.1391 < p < 0.2009\)
Step-by-step explanation:
From the question we are told that
The sample size is n = 800
The sample proportion is \(\r p = 0.17\)
Given that the confidence level is 98%
The level of significance is evaluated as
\(\alpha = 100 -98\)
\(\alpha = 2\)%
\(\alpha = 0.02\)
given that this is a two tailed test
\(\frac{\alpha }{2} = \frac{0.02}{2} = 0.01\)
The critical values obtained from the normal distribution table is
\(z_{\frac{\alpha }{2} } = 2.33\)
Now the the margin of error is mathematically evaluated as
\(MOE = 2.33 * \sqrt{\frac{0.17 (1-0.17)}{800} }\)
\(MOE = 0.0309\)
the 98% confidence interval for the true proportion of women shoppers who shop on impulse is mathematically evaluated as
\(0.17 - 0.0309 < p < 0.17 + 0.0309\)
\(0.1391 < p < 0.2009\)
The 98% confidence interval for the true proportion of women shoppers will be:
"0.1391 < p < 0.2009".
Critical value and Margin of errorAccording to the question,
Sample size, n = 800
Sample proportion, \(\hat p\) = 0.17
Confidence level = 98%
Now,
The level of significance will be;
→ α = 100 - 98
= 2% or,
= 0.02
Two-tailed be:
→ \(\frac{\alpha}{2}\) = \(\frac{0.02}{2}\)
= 0.01
The critical value be:
\(z_{\frac{\alpha}{2} }\) = 2.33
then, The margin of error be:
= 2.33 × \(\sqrt{\frac{0.17(1-0.17)}{800} }\)
= 2.33 × \(\sqrt{\frac{0.17\times 0.83}{800} }\)
= 2.33 × \(\sqrt{\frac{0.1411}{800} }\)
= 0.0309
hence,
The 98% confidence level be:
= 0.17 - 0.0309 < p < 0.17 < 0.0309
= 0.1391 < p < 0.2009
Thus the above approach is correct.
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what is tbe percentage
Answer:
5/33
Step-by-step explanation:
Probability=10/66
P=5/33
Answer:
5/33
Step-by-step explanation:
Evaluate the expression (7+6i)−(−9−8i) and write the result in the form a+bi.
Remove the parentheses and combine the like terms:
7 - -9 = 7+ 9 = 16
6i - -8i = 6i +8i = 14i
The answer is 16 + 14i