gh¯¯¯¯¯¯ has endpoints g(−3, 2) and h(3, −2). find the coordinates of the midpoint of gh¯¯¯¯¯¯ . a. (−3, 0) b. (0, 2) c. (0, 0) d. (0, −2)

Answer:

All of them except for the 3rd one

Step-by-step explanation:

2) 15 - 3x = 5(x + 4) - 8x

15 - 3x = 5x + 20 - 8x

15 - 3x ≠ -3x + 20

4) 2(x - 7) = 2x - 10

2x - 14 ≠ 2x - 10

1) 24x - 22 = -4(1 - 6x)

24x - 22 ≠ -4 + 24x

3) 12 - 2x = 6(2x + 2)

12 - 2x = 12x + 12

0 = 14x

0 = x, only one that has a solution

The data do not support the claim that the mean cost of a daily newspaper is $1.00. Because we fail to reject the null hypothesis that the mean cost of a daily newspaper is $1.00 at the 1% level of significance

To test the claim that the mean cost of a daily newspaper is $1.00, we can use a one-sample t-test.

The null hypothesis H0 is that the population mean μ equals $1.00, and the alternative hypothesis Ha is that μ is not equal to $1.00.

The test statistic is calculated as

t = (X - μ) / (s / sqrt(n))

where X is the sample mean, μ is the hypothesized population mean, s is the sample standard deviation, and n is the sample size.

Substituting the given values, we get

t = (0.93 - 1) / (0.18 / sqrt(13)) = -1.90

The degrees of freedom for this test are n - 1 = 12.

Using a t-table (or a calculator), the critical values for a two-tailed test with 12 degrees of freedom at the 1% level of significance are ±2.718.

Since our calculated t-value (-1.90) is within the range of the critical values, we fail to reject the null hypothesis. This means that the data do not provide enough evidence to support the claim that the mean cost of a daily newspaper is $1.00 at the 1% level of significance.

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The expected number of rolls until all faces have appeared in some order in six consecutive rolls is 1 / [1 - (5/6)^6].

To find the probability that all faces have appeared in some order in six consecutive rolls of a 6-sided die, we can use the principle of inclusion-exclusion.

Let's calculate the probability of the complement event first, which is the probability that at least one face is missing from the sequence in six consecutive rolls.

In the first roll, there are 6 possibilities for the face that appears. In the second roll, there are 5 possibilities remaining, and so on. Therefore, the probability of missing a face in one roll is (5/6).

Since we want to find the probability of missing a face in six consecutive rolls, we multiply the probabilities together: (5/6)^6.

Now, to find the probability of all faces appearing in some order in six consecutive rolls, we can subtract the probability of the complement event from 1.

Probability = 1 - (5/6)^6.

For the expected number of rolls until such a sequence appears, we can use the concept of geometric distribution. The expected number of rolls for a geometric distribution is equal to 1 divided by the probability of success.

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Step-by-step explanation:

To find the percent change in price of the four new tires, we can use the formula:

percent change = (new value - old value) / old value * 100%

Here, the old value is $638 and the new value is $523.

percent change = ($523 - $638) / $638 * 100%

percent change = -$115 / $638 * 100%

percent change = -0.18 * 100%

percent change = -18%

The result is a decrease of 18%, so the answer is A. 18% decrease.

Okay, let's solve this step-by-step:

Original price of 4 tires: $638

New price of 4 tires: $523

To calculate the percent change, we use the formula:

Percent Change = (New Price - Original Price) / Original Price

So in this case:

Percent Change = ($523 - $638) / $638 = -$115 / $638 = -0.18 = 18%

Since the new price is less than the original price, this is a decrease.

Therefore, the answer is A: 18% decrease

So the answer is A: 18% decrease

Supplementary angles = The angles add up to 180 degrees / form a straight line.

Angle KLO and angle KLJ form a straight line -> they are supplementary angles.

The expected number of mutual friends Alice and Bob have is 2.5.

In the scenario described, Alice and Bob each have 50 friends out of 1000 people in their town. They believe that the probability of having a mutual friend is low since each of them is only friends with 5% of the population. To calculate the expected number of mutual friends, we can consider it as a matching problem.

Alice's 50 friends can be thought of as a set of 50 randomly selected people out of the 1000, and similarly for Bob's friends. The probability of any given person being a mutual friend of Alice and Bob is the probability that the person is in both Alice's and Bob's set of friends.

Since the selection of friends for Alice and Bob is independent, the probability of a person being a mutual friend is the product of the probability that the person is in Alice's set (5%) and the probability that the person is in Bob's set (5%). Therefore, the expected number of mutual friends is \(0.05 * 0.05 * 1000 = 2.5\).

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Answer:

C = -2t + 30

Step-by-step explanation:

There are 528 possible ways to form a debate team of 4 with both of the twin brothers.

To frame a discussion group of 4 with both of the twin siblings, we initially select the twin siblings and afterward select 2 additional understudies from the leftover 33 understudies. Since the request in which we pick the understudies doesn't make any difference, we utilize the mix equation to compute the quantity of ways of picking 2 understudies from a gathering of 33.

The recipe for mix is:

C(n, r) = n! /(r! * (n-r)!)

where n is the complete number of things, r is the quantity of things to be chosen.

Utilizing this recipe, we have:

C(33, 2) = 33! /(2! * (33-2)!) = (33 * 32)/2 = 528

In this way, there are 528 potential ways of framing a discussion group of 4 with both of the twin siblings. This is acquired by duplicating the quantity of ways of choosing 2 understudies from 33 by 2, since there are two twin siblings who should be chosen as a component of the group.

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In triangle △QUW, point T is the centroid and VT is given as 5. We need to find the lengths QT and VQ.In a triangle, the centroid is the point where the three medians intersect.

The centroid divides each median into two segments in a 2:1 ratio, where the segment connecting the centroid to a vertex is twice as long as the segment connecting the centroid to the midpoint of the opposite side.

Given that VT is 5, we can use the 2:1 ratio to find the lengths of QT and VQ.

Finding QT:

Since VT is twice the length of TQ, we can divide VT by 2 to find QT:

QT = VT / 2 = 5 / 2 = 2.5

Finding VQ:

Using the 2:1 ratio, we know that VQ is one-third the length of VT. We can calculate VQ as follows:

VQ = VT / 3 = 5 / 3 ≈ 1.67

Therefore, QT is approximately 2.5 units and VQ is approximately 1.67 units.

In summary, based on the properties of a centroid in a triangle, we can determine the lengths of QT and VQ. Given that VT is 5, QT is found by dividing VT by 2, resulting in a length of approximately 2.5 units. VQ is calculated by dividing VT by 3, giving us a length of approximately 1.67 units. The centroid and its corresponding ratios provide a systematic approach to finding the lengths of segments within a triangle.

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\( \: \)

The F-distribution is used to test the significance of the population coefficient of determination (option D).

The coefficient of determination, denoted as R², measures the proportion of the variance in the dependent variable that is explained by the independent variables in a regression model. It ranges from 0 to 1, where 0 indicates no relationship and 1 indicates a perfect relationship.

To determine the significance of R², the F-distribution is used. The F-test compares the variation explained by the regression model (numerator) to the unexplained or residual variation (denominator). It calculates the F-statistic, which is the ratio of the two variances.

The F-distribution provides critical values that allow us to determine whether the observed F-statistic is statistically significant or not. By comparing the calculated F-value with the critical value from the F-distribution, we can assess whether the coefficient of determination is significantly different from zero, indicating the presence of a meaningful relationship between the variables. The correct option is d.

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Answer:

3

Step-by-step explanation:

The range of the test scores in Mr. Miller's math class is 42.

Mathematically, the range refers to the difference between the highest value and the lowest value in a data set.

The range is computed by subtraction of the lowest value from the highest value.

Mr. Miller can use the range to measure the spread or dispersion of the test scores.

Test Scores:

52, 61, 69, 76, 82, 84, 85, 90, 94

Highest score = 94

Lowest score = 52

Range = 42 (94 - 52)

Thus, we can conclude that for the math students in Mr. Miller's class, the range of their test scores is 42.

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Answer:

yes, because 6 is less than 11

Step-by-step explanation:

Hope this helps!!
Mark me brianliest and good luck!!

By using given figure, x=9/4 and the length of GH = 21.75.

What is the length ?

Here, in given figure,

BG≈GF and CH≈HE

now by using these similarities, we can write as,

BG≈GF therfore, \(\frac{GF}{BG}\) = 1:1

\(\frac{GF}{BF}\)=\(\frac{4x+8}{34}\)

1/2=\(\frac{4x+8}{34}\)

8x+16=34

8x= 18

x=9/4

if x=9/4 then,

GH= 7x+6 = 7(9/4)+6 =63/4+6 =\(\frac{63+24}{4}\) = 21.75

What is similarity of sides?

similarity of sides refers to the property of two geometric shapes or figures having the same shape but not necessarily the same size. More specifically, two shapes are said to be similar if their corresponding angles are congruent and their corresponding sides are proportional in length.

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Answer:

C

Step-by-step explanation:

A. 81 + 144 = 225. Is Pythagorean triple.

B. 25 + 144 = 169. Is Pythagorean triple.

C. 16 + 36 = 52, but 7² is 49. Is not Pythagorean triple.

D. 36 + 64 = 100. Is Pythagorean triple.

Answer:

The relationship between altitude and atmospheric pressure is exponential, as shown by the function f(x) in this problem.

Step-by-step explanation:

a. To find the pressure at sea level, we need to evaluate f(x) at x=0:
f(0) = 1038(1.000134)^0 = 1038 millibars.

Therefore, the pressure at sea level is approximately 1038 millibars.

b. To find the atmospheric pressure at an altitude of 2000 meters, we need to evaluate f(x) at x=2000:
f(2000) = 1038(1.000134)^(-2000) ≈ 808.5 millibars.

Therefore, the approximate atmospheric pressure at the McDonald Observatory in Texas is 808.5 millibars.

c. As altitude increases, atmospheric pressure decreases. This is because the atmosphere becomes less dense at higher altitudes, so there are fewer air molecules exerting pressure.

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Answer:

(-1,-3) (0,-5)

Step-by-step explanation:

Move dot at the origin to (-1,-3) down three and one to the left

Select other dot and move it to (0,-7)

Answer:

1/3

Step-by-step explanation:

2/8 ÷ 3/4

Copy dot flip

2/8 * 4/3

Simplify

2*4  / (8*3)

8/24

1/3

Answer:

0.333333333333 should be the answer, hope this helps!

3x - 8 = 4

or, 3x = 4 + 8

or, 3x = 12

or, x = 12/3

or, x = 4

So, x is 4.

Answer:

\(3x - 8 = 4 \\ 3x = 8 + 4 \\ 3x = 12 \\ x = \frac{12}{3} \\ \boxed{x = 4}\)

Yeah I feel like lately I've been overdoing it a bit. I've been playing video games way longer then I used too, then again I have nothing better to do, but it's time I start taking a little more care of my body. Thanks for the nice words!  2+2 = 4.

Answer:

4

Step-by-step explanation:

well if you count 1,2, then that's two. Now count 2 more after that and you get 4!!!

Hope this helped! :)

lol

Lakisha's total job benefits per year are (D) $58,196.

To find  Lakisha's total job benefits:

If Lakisha's employer pays $2,150 in health insurance and $86 in life insurance per year, and she also gets $3,520 in paid time off per year, then Lakisha's total job benefits per year are equal to:

Total Benefits = Health Insurance + Life Insurance + Paid Time Off + Annual Gross Pay

Therefore,  Lakisha's total job benefits per year are (D) $58,196.

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Answer The answer is D

Step-by-step explanation:

I got it correct on edg

The value of the fractions will be:

1. 4/10 + 2/10 = 6/10

2. 9 /12 + 3/12 = 1

3. 6/10 + 4/10 = 1

4. 2/8 + 3/8 = 5/8

5. 2/7 + 6/7 = 1 1/7

6. 11/9 + 8/9 = 2 1/9

7. 5/13 + 10/13 = 1 2/13

8. 3/5 + 7/10 = 1 3/10

9. 7/8 + 13/16 = 1 11/16

10. 9/30 + 3/5 = 9/10

A fraction simply means a piece of a whole. In this situation, the number is represented as a quotient such that the numerator and denominator are split. In this situation, in a simple fraction, the numerator as well as the denominator are both integers.

It should be noted that in order to add the numbers it's essential to have a common denominator. For example, 7/8 + 13/16 will be:

= 7/8 + 13/16

= 14/16 + 13/16

= 27/16

= 1 11/16

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Slope: -1

y-intercept: (0,1)

Given:

A population of rabbits is growing at the rate of 23% per annum.

Required:

To find the number of years that the population would double.

Explanation:

If growth rate remain constant, total number of years it will take to double the population “n" will be:

(where r is annual growth rate)

Hence, for your question it would be

Final Answer:

3 years.

y(x) = y_c(x) + y_p(x)

To find the general solution of the given differential equations using the variation of parameters method:

(i) y" - 4y' + 3y = e^x

The complementary solution of the homogeneous equation is found by solving the characteristic equation:

r^2 - 4r + 3 = 0

(r - 1)(r - 3) = 0

The roots are r = 1 and r = 3, so the complementary solution is:

y_c(x) = C1e^x + C2e^(3x)

Now, we need to find the particular solution using the variation of parameters method. Assume the particular solution has the form:

y_p(x) = u1(x)e^x + u2(x)e^(3x)

where u1(x) and u2(x) are functions to be determined.

Differentiating y_p(x), we have:

y_p'(x) = u1'(x)e^x + u1(x)e^x + u2'(x)e^(3x) + 3u2(x)e^(3x)

y_p''(x) = u1''(x)e^x + 2u1'(x)e^x + u1(x)e^x + u2''(x)e^(3x) + 6u2'(x)e^(3x) + 9u2(x)e^(3x)

Substituting y_p(x), y_p'(x), and y_p''(x) back into the original equation, we get:

(u1''(x)e^x + 2u1'(x)e^x + u1(x)e^x + u2''(x)e^(3x) + 6u2'(x)e^(3x) + 9u2(x)e^(3x))

4(u1'(x)e^x + u1(x)e^x + u2'(x)e^(3x) + 3u2(x)e^(3x))

3(u1(x)e^x + u2(x)e^(3x)) = e^x

Now, we equate the coefficients of like terms on both sides of the equation:

e^x terms:

u1''(x) - 2u1'(x) + u1(x) = 1

e^(3x) terms:

u2''(x) + 6u2'(x) + 9u2(x) = 0

Solve these two differential equations to find u1(x) and u2(x). Once you have u1(x) and u2(x), substitute them back into the particular solution:

y_p(x) = u1(x)e^x + u2(x)e^(3x)

Finally, the general solution is given by:

y(x) = y_c(x) + y_p(x)

(ii) y" - 2y' + y = e^x / (x^2 + 1)

The process is similar to the first equation, but with a slight difference in the particular solution. Assume the particular solution has the form:

y_p(x) = u1(x)e^x + u2(x)e^xln(x^2 + 1)

Differentiate y_p(x) and substitute it back into the original equation to find u1(x) and u2(x). Then the general solution is given by:

y(x) = y_c(x) + y_p(x)

Note: Solving the differential equations for u1(x) and u2(x) in both cases can be quite involved, and the exact form of the particular solution may vary depending on the specific calculations.

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The equation that is not a power equation is p = v²×i

From the question, we are to determine which of the given equations is not a power equation

Where the Voltage, V, and the Current, I, are given, the power, P is given by

P = IV

When the Voltage and the Resistance, R, are given

P =  V²/R

When the Current and the Resistance are given,

P = I²R

∴ P =  V²/R, P = IV, and P = I²R are power equations.

Hence, the equation that is not a power equation is p = v²×i

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