Answer: By double checking your work and by using quality equipment it minimizes the error while measuring the length of the body
Explanation:
Hopefully this helps
How fast much an 816kg Volkswagen travel to have the same momentum as (a) a 2650kg Cadillac going 16.0 km/h? (b) a 9080-kg truck also going 16.0 km/hr?
Answer:
Explanation:
From the given information:
the car's momentum = momentum of the truck
∴
(a) 816 kg × v = 2650 kg × 16.0 km/h
v = (2650 kg × 16.0 km/h) / 816 kg
v = 51.96 km/hr
(b) 816 kg × v = 9080 kg × 16.0 km/h
v = (9080 kg × 16.0 km/h) / 816 kg
v = 178.04 km/hr
The highness or lowness of a sound is perceived as
a.
compression.
c.
ultrasound.
b.
wavelength.
d.
pitch.
Answer:
i think its D
Explanation:
Answer:
The highness or lowness of a sound is perceived as pitch. Pitch is a perceptual property of sound that allows us to distinguish between sounds that have the same loudness and duration, but differ in their frequency content. The pitch of a sound is determined by the frequency of the sound wave, with higher frequencies producing higher pitches and lower frequencies producing lower pitches. The pitch is what makes a sound distinguishable and is important in music, language, and communication.
How are isobars and isotherms similar? How are they different?
Answer: Brainliest?
Explanation:
Isobars and isotherms are both types of contour lines used to represent data on weather maps, specifically for atmospheric pressure and temperature, respectively.
The similarities between isobars and isotherms are:
Both are contour lines that connect points of equal value on a map.
Both are used to depict weather patterns and conditions.
Both help to identify areas of high and low values.
The differences between isobars and isotherms are:
Isobars connect points of equal atmospheric pressure, whereas isotherms connect points of equal temperature.
Isobars are measured in units of pressure such as millibars, while isotherms are measured in units of temperature such as degrees Celsius or Fahrenheit.
Isobars are typically used to show pressure patterns associated with wind, while isotherms are used to show temperature patterns.
Isobars are often used to forecast weather conditions, including the movement and intensity of storm systems. Isotherms are used to identify areas of warm and cold air masses, which can affect local weather patterns.
In summary, both isobars and isotherms are useful tools for understanding weather patterns, but they represent different types of data and are used for different purposes.
Isobars and isotherms are both concepts used in meteorology and climatology to represent important variables that help to describe atmospheric conditions. While they share some similarities, they also have several key differences.
Isobars refer to lines of equal pressure, meaning they connect points on a map or graph where the atmospheric pressure is the same. Isobars are drawn on weather maps to indicate areas of high and low pressure, and to show the general movement of air masses. When isobars are closely spaced, it indicates a steep pressure gradient, which can result in strong winds.
On the other hand, isotherms refer to lines of equal temperature, meaning they connect points on a map or graph where the temperature is the same. Isotherms are often drawn on weather maps to show the boundaries between warmer and cooler air masses, and to indicate areas where temperature changes rapidly.
One similarity between isobars and isotherms is that they are both used to describe atmospheric conditions in terms of spatial variation. They are also both used to infer information about the movement of air masses and the development of weather patterns.
However, there are also some key differences between isobars and isotherms. The most obvious difference is that isobars represent pressure while isotherms represent temperature. Additionally, while isobars are generally oriented parallel to each other and indicate the direction of winds, isotherms are typically oriented perpendicular to isobars and indicate the location of temperature gradients. Finally, while isobars are more commonly used to describe weather conditions associated with areas of high and low pressure, isotherms are often used to identify the location of fronts and other weather boundaries.
In summary, isobars and isotherms are similar in that they both describe atmospheric conditions in terms of spatial variation, and can be used to infer information about the movement of air masses and the development of weather patterns. However, isobars represent pressure and are oriented parallel to each other, while isotherms represent temperature and are oriented perpendicular to isobars.
A bike accelerates from 0 m/s to 15 m/s over the span of 5 seconds. How fast is the bike
traveling after 2.5 seconds?
The bike is travelling at 22.5 m/s after 2.5 s
What is acceleration?This is defined as the rate of change of velocity which time. It is expressed as
a = (v – u) / t
Where
a is the acceleration v is the final velocity u is the initial velocity t is the time How to determine the acceleration Initial velocity (u) = 0 m/sFinal velocity (v) = 15 m/sTime (t) = 5 sAcceleration (a) =?a = (v – u) / t
a = (15 – 0) / 5
a = 3 m/s²
How to determine the final velocity in the first 2.5 s Initial velocity (u) = 15 m/sAcceleration (a) = 3 m/s²Time (t) = 2.5 s Final velocity (v) = ?a = (v – u) / t
3 = (v – 15) / 2.5
Cross multiply
v – 15 = 3 × 2.5
v – 15 = 7.5
Collect like terms
v = 7.5 + 15
v = 22.5 m/s
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pplzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz helppppp
Answer:
D. The airplane will turn towards the east
Explanation:
If the airplane is thrown straight towards the north, the window which is moving from left (west) to right (east) the wind will knock the plane towards the right (east) since thats the way it is blowing.
6. Show that the weight of an object on the moon is 1/6 its weight on earth.
Taking ratio of W & w. ≈ 6 . w = 1/6 W. Therefore , Weight of an object on the moon is 1/6 of its weight on the earth.
A fly enters through an open window and zooms around the room. In a Cartesian coordinate system with three axes along three edges of the room, the fly changes its position from point b (2.5 m, 2.0 m, 4.0 m) to point e (4.5 m, 3.0 m, 3.5 m). Find the scalar components of the flies displacement vector (in m).
Answer:
Explanation:
Displacement vector along x axes = 4.5 - 2.5 = 2 m
Displacement vector along y axes = 3 - 2 = 1 m
Displacement vector along z axis = 3.5- 4 = - 0.5 m
Displacement vector = 2 i + j - 0.5 k m
Two objects are held close together. When they are released, they move toward one another. Which conclusion is supported by this evidence? O The objects are both positively charged. O The objects are both negatively charged. O The objects have no charge. O The objects have opposite charges. Mark this and return Save and Exit 02:48:18 Next Submit
Two objects are held close together. When they are released, they move toward one another. The conclusion is supported by this evidence is the objects have opposite charges.
An electric charge is a physical property that causes matter to experience a force when in close proximity to other electrically charged matter. There are two types of electric charges: positive and negative. Protons, which are positively charged, and electrons, which are negatively charged, are subatomic particles that make up matter.
In general, the protons and neutrons in the nucleus of an atom have a net positive charge, while electrons, which orbit the nucleus, have a net negative charge. The charges of these subatomic particles are indicated by the symbols "p" for proton, "n" for neutron, and "e" for electron.
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A golfer hits the ball across a 40 meter golf course, the ball reaches the other side in 0.30 seconds. What is the average speed that the golfer hit the ball at?
a. 0.0075 m/sec
b. 40 m/sec
c. 0.30 m/sec
d. 133.33 m/sec
Which form of energy increases when a spring is compressed?
Answer:
When the spring compresses, elastic potential energy increases.
Answer:
the answer is b
Explanation:
elastic potential energy
Please please help!!!
The half-life of uranium-238 is about 4.5 billion years. How does this isotope's long half-life make it useful for finding the
age of rocks on Earth and in space?
Answer:
Because the half-life is as long as Earth has existed, virtually all rocks on Earth still have most of their uranium-238. So, measurements can easily be obtained.
Explanation:
exact answer from pluto/ edmentum
The significant part of the chemical composition of rocks is uranium. The half -life of uranium is close to the age of earth. Hence, by measuring the uranium content in rocks we can predict its age.
What is uranium?Uranium is 92nd element in periodic table. It is an actinide element. All the actinides are radioactive in which the most common is uranium. They all undergo radioactive decay process. Radioactive decay is a first order reaction. The rate constant K can be written as:
k = 1/t ln (W0/Wt)
where t is the tome of decay, W0 be the initial amount and Wt is the amount after time t.
here k = 0.693/t1/2
By this relation we can find t the age of a substance, if know the amounts and half life t1/2. Uranium is present in rocks and minerals. Uranium undergo nuclear decay and will forms its isotopes or new products.
Thus, by measuring the current amount of uranium in rocks by knowing the half life of uranium we can predict the age of rocks.
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Which of the following has kinetic energy? (1 point)
Ans:
C
Explanation:
because it is moving down the stairs
A spring travelling down a flight of stairs has kinetic energy.
What is Kinetic energy?
Since it is moving, it would be a spring moving down a set of steps. A stretched spring, a compressed spring, and a spring at the top of a set of steps are all in motion.
Kinetic energy is a type of power that a moving object or particle possesses.
An item accumulates kinetic energy when work, which involves the transfer of energy, is done on it by exerting a net force. A moving object or particle has kinetic energy, which depends on both its mass and its rate of motion.
Therefore, A spring travelling down a flight of stairs has kinetic energy.
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A toy gun mounted horizontally shoots a dart at a target. It hits the target 3 m away. The dart hit 0.82 m below the target.
What is the muzzle velocity of the dart gun? Please express your answer to three significant figures.
The muzzle horizontal velocity of the dart gun that shoots the dart to a target that is 3 m away is 7.34 m/s.
We can calculate the horizontal velocity of the dart gun with the following kinematic equation:
\( x = v_{0_{x}}t + \frac{1}{2}at^{2} \) (1)
Where:
x: is the total distance = 3 m
\( v_{0_{x}}\): is the horizontal component of the initial velocity =?
t: is the time
a: is the acceleration = 0 (there is no acceleration in the horizontal motion of the dart gun)
Since we also know the height, we can use this other equation:
\( y_{f} = \frac{1}{2}gt^{2} \) (2)
Where:
g: is the acceleration due to gravity = 9.81 m/s²
By solving equation (1) for t, and entering into (2) we have:
\( y = \frac{1}{2}gt^{2} = \frac{1}{2}g(\frac{x}{v_{0_{x}}})^{2} \)
By solving for \(v_{0_{x}}\):
\( v_{0_{x}} = \sqrt{\frac{gx^{2}}{2y}} = \sqrt{\frac{9.81 m/s^{2}*(3 m)^{2}}{2*0.82 m}} = 7.34 m/s \)
Therefore, the muzzle velocity of the dart gun is 7.34 m/s.
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Most scientific experiments are what type experiment, mostly because it is simpler and easier to test single variables? a) Natural experiment. b) Controlled experiment. c) Forced experiment. d) Redundant experiment.
Answer:
The correct answer is : option B. controlled experiments.
Explanation:
A scientific experiment which deals with a single variable at a time and compared the independent variable to a controlled variable after measuring the change in dependent variable.
It is a very simple and easy test for single variable. In these experiments subjects are divided in two groups one one, with independent variable and other variable.
Thus, the correct answer is : option B. controlled experiments.
An average person is 175 cm tall. How
many people could you stack one on top of
another to reach the top of the CN Tower
(553 m)?
The number of people you will stack to reach the top of the CN Tower (553 m) is 316 people
Hor to convert 175 centimeters to metersWe'll begin by converting 175 cm to m. This can be obtained as illustrated below:
100 cm = 1 m
Therefore,
175 cm = (175 cm × 1 m) / 100 cm
175 cm = 1.75 m
Thus, 175 cm is equivalent to 1.75 m
How to determine the number of people neededThe number of people needed to be stacked to get to the top of the CN tower can be o btained asfollow:
Height of tower = 553 mHeight of a person = 1.75 mNumber of people needed =?Number of people needed = Height of tower / height of a person
Number of people needed = 553 / 1.75
Number of people needed = 316 people
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the 20 kg block is being pushed with 50 N of force find the frictional force find the weight of the block
The frictional force acting on a 20 kg block that is being pushed with 50 N of force and the weight of the block are calculated as follows:Frictional force:The frictional force is a force that opposes motion between two surfaces that are in contact. It's typically symbolized by the letter f.
The frictional force formula is:Ff = μNwhere Ff is the frictional force, μ is the coefficient of friction, and N is the normal force.The coefficient of friction between two surfaces is a constant that depends on the materials of the surfaces in contact and the presence of any lubricants. The coefficient of friction ranges from 0 to 1, with 0 indicating no friction and 1 indicating maximum friction.The normal force is equal to the weight of the object, which is the force that gravity exerts on the object. The formula for the weight of an object is:w = mgwhere w is the weight of the object, m is the mass of the object, and g is the acceleration due to gravity (9.8 m/s2).Therefore, the frictional force acting on the 20 kg block is:Ff = μN = μ(w)And the weight of the block is:w = mgwhere m = 20 kg and g = 9.8 m/s2So, we can calculate both the frictional force and the weight of the block using the given values and formulas.For such more question on coefficient
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In the graph below, why does the graph stop increasing after 30 seconds?
A. The hydrogen gas is absorbing heat to undergo a phase change.
B. A catalyst needs to be added to increase the amount of hydrogen produced.
C. No more hydrogen can be produced because all of the reactants have become products at this point.
D. It has reached the maximum amount of product it can make at this temperature. The temperature would need to increase to produce more.
Answer:
The answer is "Option C".
Explanation:
It's evident from the figure below that after thirty minutes, not no more hydrogen can be created because all of the reactants have converted into products.
hydrogen gas created in cm cubes per period x = 20 seconds, y = 45 centimeters squared, and so on.
A reaction's terminus (the graph's flat line) indicates that no further products are being created during the reaction.
what is projectiles
A football player kicks a ball with a mass of 0.5 kg. The average acceleration of the football was 15 m/s/s. How much force did the kicker apply to the football?
A. 15.5 N
B. 7.5 N
C. 14.5 N
D. 30 N
Answer:
Explanation:
F = m*a = (0.5)*15 = 7.5 N
One swimmer in a relay race has a 0.50 s lead and is swimming at a constant speed of 5.00 m/s. The swimmer has 41.0 m to swim before reaching the end of the pool. A second swimmer moves in the same direction as the leader. What constant speed must the second swimmer have in order to catch up to the leader at the end of the pool?
5.32m/s must be the constant speed of the second swimmer in order to catch up to the leader at the end of the pool.
The equation for distance for a constant velocity is given by:
x = v * t, x = distance, v = velocity, t = time
1. The time for the first swimmer to reach the end of the pool:
t₁ = x/v₁
= 41m / 5.0m/s
=8.2s
2. The second swimmer will be at the same location at a time t₂, from where she has 0.50s less to reach the end of the pool than the first swimmer. The velocity for the other swimmer will be:
v₂ = x/t₂
= 41 / (t₁ - 0.50s) = 41m / 7.7s
=5.32m/s
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you made $100,000 this year. you have $0 in adjustments, $11,500 in deductions and $7,300 in exemptions. What is your taxable increase?
The tax rate you will pay is displayed in tax brackets for each category of taxable income.
Thus, For instance, in 2022, the first $10,275 of your taxable income is subject to the lowest tax rate of 10% if you are single.
Up until the maximum amount of your taxable income, the following portion of your income is taxed at a rate of 12%.
As taxable income rises, the tax rate rises under the progressive tax system. Overall, this has the result that taxpayers with higher incomes often pay a greater rate of income tax than taxpayers with lower incomes.
Thus, The tax rate you will pay is displayed in tax brackets for each category of taxable income.
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1. Two equally charged particles are held apart when they are released from rest, the initial acceleration of 1st particle is 7.22 m/s^2 and 2nd is 9.16 m/s^2. The mass of the 1st particle is 6.31×10^(-7) kg. Find the mass of 2nd particle and common charge.
The mass of 2nd particle be 4.97×10⁻⁷ kg.
The common charge can not be determined.
What is force?An object's push or pull is seen as exerting a force. The interaction of the objects produces push and pull. You can also use words like stretch and squeeze to describe force.
The definition of force in physics is: The push or pull on a mass-containing item changes its velocity.
Given that: two equally charged particles are held apart when they are released from rest. So force acting on them is same.
For 1st particle:
Mass: m₁ = 6.31×10⁻⁷ kg.
Acceleration: a₁ = 7.22 m/s².
For 2nd particle:
Acceleration: a₂ = 9.16 m/s².
Mass: m₂ = ?
As force acting on both particle is same.
m₁a₁ = m₂a₂
⇒ m₂ = m₁a₁/a₂ = ( 6.31×10⁻⁷ kg)×( 7.22 m/s²)/( 9.16 m/s²) = 4.97×10⁻⁷ kg.
So, the mass of 2nd particle be 4.97×10⁻⁷ kg.
As there has no mention of distance between them and which type of particle it is, common charge can not be determined.
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200. Un automóvil se desplaza
hacia la izquierda con
velocidad constante v,
en el momento en que se
deja caer un saco de lastre
desde un globo en reposo.
El vector que representa
la velocidad del saco vista
desde el automóvil en ese
instante en que se suelta es
A 500 kg train car (Car 1) is traveling at 25 m/s when it hits and attaches to another 750 kg train car (Car 2) that is at rest. Find (1) the resulting velocity of both train cars after they hit and (2) the momentum of the train cars before and after they attach.
(1) The resulting velocity of both train cars after they hit is 10 m/s.
(2) The momentum of the first train before and after collision is 12,500 kgm/s and 5,000 kgm/s respectively.
The momentum of the second train before and after collision is 0 kgm/s and 7,500 kgm/s respectively.The given parameters;
mass of the first train, m₁ = 500 kginitial velocity of the train, u₁ = 25 m/smass of the second the train, m₂ = 750 kginitial velocity of the second train, u₂ = 0(1)
The final velocity of the both trains after the collision is obtained by applying the principle of conservation of linear momentum for inelastic collision.
m₁u₁ + m₂u₂ = v(m₁ + m₂)
where;
v is the final velocity of the two trains after collision.
The resulting velocity of both train cars after they hit is calculated as
(500 x 25) + (750 x 0) = v(500 + 750)
12500 = 1250v
\(v = \frac{12500}{1250} \\\\v = 10 \ m/s\)
(2)
The momentum of the first train before collision;
\(P_1 = m_1 u_1\\\\P_1 = 500 \times 25\\\\P_1 = 12500 \ kg.m/s\)
The momentum of the first train after collision;
\(P_1_f = m_1 v\\\\P_1_f = 500 \times 10\\\\P_1_f = 5,000 \ kg.m/s\)
The momentum of the second train before collision;
\(P_2 = m_2 u_2\\\\P_2 = 750 \times 0\\\\P_2 = 0 \ kg.m/s\)
The momentum of the second train after collision;
\(P_2_f = m_2 v\\\\P_2_f = 750 \times 10\\\\P_2_f = 7,500 \ kg.m/s\)
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How is the work energy theorem represented as an equation?
Answer:
Trabajo = Δ E
Explanation:
Podemos escribir esta declaración como una ecuación que hace que sea muy fácil ver la relación: Trabajo = Δ E, donde E es energía, y la letra griega Delta significa ‘cambio en’. Entonces leemos esto como: trabajo = cambio de energía. Esto nos ayuda a comprender por qué no se realiza ningún trabajo en una pared que no se mueve.
The work- energy theorem states that the work done by the sum of forces acting on an object is equal to the change in the kinetic energy of the object.
What is work energy theorem ?According to work -energy theorem, the force resulting in a work done which is equal to the change in kinetic energy of the object. When a force applied on a body results in a displacement of the body, it is said to be work done on the body.
Kinetic energy of an object is the energy generated by virtue of its motion. It related to the mass and velocity as written below:
Ke = 1/2 mv²
Let, Vi be the initial velocity and Vf be the final velocity, then the change in kinetic energy is written as:
ΔKe = 1/2 mVf² - 1/2 mVi²
According to wok energy theorem, the work done is equal to the this kinetic energy change.
Hence, W = ΔKe.
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A hypothetical planet has a radius 1.8 times that of Earth but has the same mass. What is the acceleration due to gravity near its surface?
The acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².
The formula for acceleration due to gravity is:
g = GM/r² Where, g = acceleration due to gravity G = universal gravitational constant M = mass of the planet r = radius of the planet
In this case, since the mass of the hypothetical planet is the same as that of Earth, we can use the mass of Earth instead of M.
Therefore, g is proportional to 1/r².
So, using the ratio of radii given (1.8), we can write:
r = 1.8 x r Earth, where r Earth is the radius of Earth.
Substituting this value of r in the formula for acceleration due to gravity, we get:
g = GM/(1.8 x r Earth)² = GM/(3.24 x rEarth²) = (1/3.24)GM/rEarth²
We know that the acceleration due to gravity on Earth (g Earth) is 9.8 m/s².
Therefore, we can calculate the acceleration due to gravity on the hypothetical planet (gh) as follows:
gh = (1/3.24) x g Earth = 3.02 m/s²
Thus, the acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².
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The cone and the cylinder below have equal surface area.
2r
OA. True
B. False
B. False, the surface area of the cone and the cylinder is not the same.
What is the Surface area?The area or region that an object’s surface occupies is known as its surface area. Volume, on the other hand, refers to how much room an object has. Geometry has numerous shapes and dimensions, including spheres, cubes, cuboids, cones, cylinders, etc. Each form has its own volume and surface area.
If the slant height of the cone is 2r, then we can use the Pythagorean theorem to find the radius of the cone:
l² = (2r)² - r²
l² = 3r²
l = r√3
Using this value for the radius of the cone, the formula for its surface area becomes:
A(cone) = πrl + πr²
A(cone) = π(r)(r√3) + πr²
A(cone) = πr²(1 + √3)
For the cylinder, we can use the given height and radius to find its surface area:
A(cylinder) = 2πrl + 2πr²
A(cylinder) = 2π(r)(r) + 2π(r²)
A(cylinder) = 2πr²(1 + r)
Comparing the two surface area formulas, we can see that they are not equal in general, since each figure's coefficient in front of the second term (πr²) is different.
Therefore, we cannot conclude that the two figures have the same surface area based on the information.
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A
A penny is dropped from the top of a 200 m building and is in free fall. How long will it take
the penny to hit the ground?
Answer:
The penny will hit the ground at 6.39 seconds
Explanation:
Free Fall
The penny is dropped from a height of y=200 m. The equation of the height on a free-fall motion is given by:
\(\displaystyle y=\frac{gt^2}{2}\)
Where \(g=9.8\ m/s^2\), and t is the time.
Solving for t:
\(\displaystyle t=\sqrt{\frac{2y}{g}}\)
Using the value y=200:
\(\displaystyle t=\sqrt{\frac{2*200}{9.8}}\)
t=6.39 sec
The penny will hit the ground at 6.39 seconds
Compare sound and earthquake waves
When materials vibrate, waves are created that travel through the substance, and this energy is what we hear as sound. Earthquakes are earth vibrations that cause the (potential) energy held within rocks to be released (as a result of their pressure-generating relative positions). Seismic waves are produced by earthquakes.
How do sound waves and earthquakes compare?
The waves lose energy as they move through the air with sound or through the ground with shaking during an earthquake. Therefore, a band can be heard louder close to the stage than farther away, and an earthquake can be felt more strongly close to the fault than farther away.
In actuality, sound in the air cannot match how quickly earthquake waves move. In rock, the compressional or "P" wave of an earthquake moves at the In actuality, sound in the air cannot match how quickly earthquake waves move. The speed of a P wave is typically 10,000 mph. The speed of sound through air is roughly 750 mph.
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What is the mass of 4.00 cm3 of sodium; density = 0.97 g/cm?
Answer:
m= 3.88 g
Explanation:
p=m/v
p is density
so know we want mass, isolate for m
m=pxv
m= 0.97 g/cm x 4.00 cm^3
m= 3.88 g
The mass of 4.00 cm³ of sodium with a density of 0.97 g/cm³ is 3.88 grams. The mass is calculated in grams.
When you have 4.00 cm³ of sodium with a density of 0.97 g/cm³, the resulting mass is found to be 3.88 grams through the mass-volume relationship. This calculation helps determine the substance's weight based on its given properties.
Given:
Volume = 4.00 cm³
Density = 0.97 g/cm³
The mass is given by:
Mass = Volume × Density
Mass = 4.00 × 0.97
Mass = 3.88 g
Therefore, The mass of 4.00 cm³ of sodium with a density of 0.97 g/cm³ is 3.88 grams.
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