How many concrete cylinders must be taken for a single 28-day concrete compression test?
Answers
In order to conduct a 28-day concrete compression test, a certain number of concrete cylinders must be taken. The exact number of cylinders that need to be taken depends on several factors, including the size of the concrete pour, the type of concrete being used, and the requirements of the testing agency or organization.
Typically, at least two cylinders are taken for each concrete pour, and sometimes more depending on the size and complexity of the project. These cylinders are then sent to a laboratory for testing, where they are placed under pressure to determine their compressive strength.
The number of cylinders taken also depends on the specific requirements of the testing agency. For example, some agencies may require three cylinders to be taken for each pour, while others may only require one or two.
Overall, it is important to follow the guidelines and requirements of the testing agency or organization to ensure accurate and reliable test results. Taking the appropriate number of concrete cylinders for each compression test can help ensure that the concrete meets the required standards for strength and durability.
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Related Questions
Technician A says that engine blocks are either cast iron or aluminum. Technician B says that cores are used inside a mold to form water jackets and cylinder bores. Who is right
Answers
Both technicians are correct. Engine blocks can indeed be made of either cast iron or aluminum, with each material having its own advantages and disadvantages. Cast iron is known for its strength and durability, while aluminum is lighter and can provide better fuel efficiency.
In addition, both materials can be designed to meet specific requirements for engine performance and emissions. Cores are also commonly used in the casting process to form water jackets and cylinder bores, as they help to create the necessary cavities within the block.
Overall, the use of cast iron or aluminum and the incorporation of cores are important factors in engine block design and construction.
Technician A is correct in stating that engine blocks are typically made from either cast iron or aluminum. Technician B is also right in saying that cores are used inside a mold to form water jackets and cylinder bores.
Therefore, both technicians A and B are correct in their respective statements.
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The subsequent result of the
system to the input is known
as
Select one:
A.Response
B.Command
C.Process Control
D.Process Controller
as
Answers
Answer the question on the image and a brianiest will be given to the person that provided the right answer to it.
Answers
Answer:
(a) The distance up the slope the wagon moves before coming to rest is approximately 21.74 m
(b) The distance the wagon comes to rest from the starting point is approximately 12.06 m
(c) The value of 'U' at which the wagon should be propelled if it is to come finally to rest at its starting point is approximately 3.214 m/s (the difference in value can come from calculating processes)
Explanation:
The wagon motion parameters are;
The mass of the wagon, m = 7,200 kg
The initial velocity with which the wagon is projected along the horizontal rail, v = U
The length of the horizontal portion of the rail = 100 m
The angle of inclination of the inclined portion of the rail, θ = sin⁻¹(0.01)
The exerted frictional resistance to motion of the rail, \(F_f\) = 140 N
∴ θ = sin⁻¹(0.01)
The work done by the frictional force on the horizontal portion of the rail = 140 N × 100 m = 14,000 J
(a) If U = 3 m/s, we have;
Kinetic energy = 1/2·m·v²
The initial kinetic energy of the wagon, K.E. is given with the known parameters as follows;
K.E. = 1/2 × 7,200 kg × (3 m/s)² = 32,400 J
The energy, E, required to move a distance, 'd', up the slope is given as follows;
E = \(F_f\) × d + m·g·h
Where;
\(F_f\) = The friction force = 140 N
m = The mass of the wagon = 7,200 kg
g = The acceleration due to gravity ≈ 9.81 m/s²
h = The height reached = d × sin(θ) = d × 0.01
Therefore;
E = 140 N × d₁ + 7,200 kg × 9.81 m/s² × d₁ × 0.01 = 846.32 N × d
The energy, \(E_{NET \ horizontal}\), remaining from the horizontal portion of the rail is given as follows;
\(E_{NET \ horizontal}\) = Initial kinetic energy of the wagon - Work done on frictional resistance on the horizontal portion of the rail
∴ \(E_{NET \ horizontal}\) = 32,400 J - 14,000 J = 18,400 J
\(E_{NET \ horizontal}\) = 18,400 J
Therefore, for the wagon with energy, \(E_{NET \ horizontal}\) to move up the train, we get;
\(E_{NET \ horizontal}\) = E
∴ 18,400 J = 846.32N × d
d₁ = 18,400 J/(846.36 N) ≈ 21.7401579 m
d₁ ≈ 21.74 m
The distance up the slope the wagon moves before coming to rest, d₁ ≈ 21.74 m
(b) Given that the initial velocity of the wagon, U = 3 m/s, the distance up the slope the wagon moves before coming to rest is given above as d₁ ≈ 21.74 m
The initial potential energy, PE, of the wagon while at the maximum height up the slope is given as follows;
P.E. = m·g·h = 7,200 kg × 9.81 m/s² × 21.74 × 0.01 m = 15,355.3968 J
The work done, 'W', on the frictional force on the return of the wagon is given as follows;
W = \(F_f\) × d₂
Where d₂ = the distance moved by the wagon
By conservation of energy, we have;
P.E. = W
∴ 15,355.3968 = 140 × d₂
d₂ = 15,355.4/140 = 109.681405714
Therefore;
The distance the wagon moves from the maximum height, d₂ ≈ 109.68 m
The distance the wagon comes to rest from the starting point, d₃, is given as follows;
d₃ = Horizontal distance + d₁ - d₂
d₃ = 100 m + 21.74 m - 109.68 m ≈ 12.06 m
The distance the wagon comes to rest from the starting point, d₃ ≈ 12.06 m
(c) For the wagon to come finally to rest at it starting point, we have;
The initial kinetic energy = The total work done
1/2·m·v² = 2 × \(F_f\) × d
∴ 1/2 × 7,200 × U² = 2 × 140 × d₄
d₄ = 100 + (1/2·m·U² - 140×100)
(1/2·m·U² - 140×100)/(m·g) = h = d₁ × 0.01
∴ d₁ = (1/2·m·U² - 140×100)/(m·g×0.01)
d₄ = 100 + d₁
∴ d₄ = 100 + (1/2·m·U² - 140×100)/(m·g×0.01)
∴ 1/2 × 7,200 × U² = 2 × 140 × (100 + (1/2 × 7,200 × U² - 140×100)/(7,200 × 9.81 ×0.01))
3,600·U² = 280·(100 + (3,600·U² - 14,000)/706.32)
= 28000 + 280×3,600·U²/706.32 - 280 × 14,000/706.32
= 28000 - 280 × 14,000/706.32 + 1427.11518858·U²
3,600·U² - 1427.11518858·U² = 28000 - 280 × 14,000/706.32
U²·(3,600 - 1427.11518858) = (28000 - 280 × 14,000/706.32)
U² = (28000 - 280 × 14,000/706.32)/(3,600 - 1427.11518858) = 10.3319363649
U = √(10.3319363649) = 3.21433295801
The value of 'U' at which the wagon should be propelled if it is to come finally to rest at its starting point is U ≈ 3.214 m/s
Percentage error = (3.214-3.115)/3.214 × 100 ≈ 3.1% < 5% (Acceptable)
The difference in value can come from difference in calculating methods
Which of the following was the most important group of engineers on the project described in the following scenario? The "Big Dig" in Boston, Massachusetts, redesigned the entire highway system in the city, moving roads underground in many areas. The "Big Dig* required the services of different types of engineers. computer engineers civil engineers manufacturing engineers electrical engineers
Answers
Answer:
the answer is A
Explanation:
Answer:
A
Explanation:
is the systematic application of a series of malformed inputs to test how the program responds.
Answers
Fuzzing provides random, imperceptible input and records the system's behavior in response.
What is a fuzz test?
Fuzz testing or fuzzing is a software testing technique that injects invalid or random data, called her FUZZ, into a software system to discover coding errors and security vulnerabilities.
Why Fuzz Test?
Fuzzy testing usually finds the most serious security flaws or flaws.
Fuzz testing works best when combined with black box testing, beta testing, and other debugging methods.
Fuzz testing is used to check software for vulnerabilities. This is a very cheap test technique.
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You have a Switch LED Lightbulb with the following information: It is equivalent to a 75 Watt incandescent lightbulb. It uses 20 Watts of electricity. It is estimated to last 25,000 hours. The purchase price of the lightbulb is $51.99.
The package claims an estimated energy cost of $2.41 per year, but this estimate is not based on local electricity costs. Assume that local electricity costs $0.086 per kW-hr.
Based on this information, we can now calculate the cost of ownership for this bulb. The cost of ownership is defined as the purchase price of the lightbulb plus the cost of the electricity required to run the lightbulb until failure.
Note the equation below: Purchase price + Total electricity cost = Cost of ownership Calculate the cost of ownership for this lightbulb. Then select the answer below that matches your calculation.
a.$40.14
b.$51.99
c.$94.99
d.$103.98
Answers
cost of ownership for the Switch LED Lightbulb is $94.99.
To calculate the cost of ownership for the Switch LED Lightbulb, we need to first determine the total electricity cost. We know that the bulb uses 20 watts of electricity and is estimated to last 25,000 hours. To find the total electricity cost, we need to multiply the wattage by the hours of use and the cost of electricity per kW-hr.
20 watts x 25,000 hours = 500,000 watt-hours
500,000 watt-hours ÷ 1,000 = 500 kWh
500 kWh x $0.086/kWh = $43.00
So the total electricity cost for the Switch LED Lightbulb is $43.00.
Next, we need to add the purchase price of $51.99 to the total electricity cost of $43.00:
$51.99 + $43.00 = $94.99
Therefore, the correct answer is c. $94.99.
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Which of the following are examples of guarding? Select all that apply. warning labels elevated platforms partitions locked circuit breaker panel enclosed rooms lockout/tagout Question 8 of 10
Answers
The option that is an example of Guarding are:
warning labels elevated platforms partitions locked circuit breaker.What is a locked circuit breaker?
Circuit breaker locks are used to prevent the unintentional or deliberate shutting off of certain electrical circuits. A circuit breaker lock is fitted on a Square-D circuit breaker, which is suitably colored red and marked. This breaker lock can only be opened with a key.
Guarding is situating or enclosing electric equipment to prevent individuals from unintentionally coming into touch with live parts. Effective guarding necessitates placing equipment with exposed parts that operates at 50 volts or more in a location that is only accessible to authorized individuals who are competent to deal with it.
Shielding, protective barriers, or insulating materials must be used to protect workers from electric shock, burns, or other electrical-related injuries when working on exposed low-voltage parts that may be touched or that may generate hazardous electrical heat or arcing.
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Dependence of oxidation on the temperature 10 points total The process temperature is an important parameter for the oxide growth process. To get an estimate for the temperature dependence of the Deal-Groove formula, the following considerations can be used. All processes (transport, diffusion and reaction) that are used in the Deal-Groove model are thermally activated. Thus, the dependence on the growth parameters on the temperature T can be estimated by: X(T) = Xpe Xe{A, B, B/A} (5) Here kB = 8.617 x 10-5 eV/K is the Boltzmann Constant and EX is the activation energy for the parameter. X, is the value for the corresponding parameter at T =0 K. Please note that this is not a 'physical activation energy but rather an average/fit parameter for all the physical and chemical thermally activated processes relevant for the process. In the original publication by Deal and Groove, they gave the following parameter sets for dry oxidation: Oxidation temperature in 'C A in um Bin um²/h 1000 0.165 0.0117 1200 0.040 0.045 a)EXct and X, for A, B and B/A
a) Use the given values for the parameters A and B in the table above, along with equation ?? to derive the activation energies EXd and zero temperature values X(T = 0 K) for all three parameters A, B and B/A. Then use this calculate the corresponding values of A,B, B/A for the following temperatures: 1000°C, 1200°C, 800°C and 900 °C.
b) Plot estimates for other temperatures 2 points Use the obtained values from the previous sub-task along with the full Deal-Groove model equation for Z:(t) to plot the oxide thickness over time (0-100h) using at least 20 data points each for the following temperatures: 1000°C, 1200°C, 800°C and 900 °C. Assume Zo = Om.
Answers
Answer:
mama mia
Explanation:
haha
Water is pumped from a lake to a storage tank 18 m above at a rate of 70 L/s while consuming 20.4 kW of electric power. Disregard any frictional losses in the pipes and any changes in kinetic energy, determine (a) the overall efficiency of the pump-motor unit (5-point), and (b) the pressure difference between the inlet and the exit of the pump (5-point).
Answers
Part A
For each method,a function to model the expected number of plants for each year
Part B
Use the Functions to Find the expected number of plants in 10 years for each method.
Part C
A given lithium ion battery can supply 700 mA⋅hr with a constant output voltage of 16 V. How much energy in Joules is stored in this battery? Give your answer to a precision of 3 decimal points in engineering notation and include units in your answer using a standard SI prefix and the appropriate SI unit symbol
Answers
The energy stored in the given lithium-ion battery is 4.032 × 10⁴ Joules.
To calculate the energy stored in the lithium-ion battery, we can use the formula:
Energy (Joules) = Voltage (V) × Charge (Coulombs)
First, we need to convert the capacity of the battery from milliampere-hours (mA·hr) to coulombs (C).
Since 1 Coulomb is equal to 3600 Coulombs (1 A·hr = 3600 C), we can convert 700 mA·hr to coulombs:
700 mA·hr = 700 × (1/1000) A × 1 hr × 3600 s/hr
= 2.52 × 10³ C
Now, we can calculate the energy stored in the battery:
Energy (Joules) = 16 V × 2.52 × 10³ C
= 4.032 × 10⁴ J
Therefore, the energy stored in the given lithium-ion battery is 4.032 × 10⁴ Joules in engineering notation with units using a standard SI prefix and the appropriate SI unit symbol.
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application's of kirchoff's law
Answers
-0-1"
-0
-20
-15
-10
0
-5
Answers
75743366
Explanation:
1. Declare a variable named num with an
initial value of 0. Create a while loop that
will print "Keep going" as long as the value
of num is less than 5. Use window.alert()
for displaying the output.
2. Create a function named showProd that
returns the product of n1 and n2.
3. Using the new keyword, create an array
named info with three (3) values: your first
name, your nickname, and your last name.
Answers
The code to
Declare a variable and increment with a while loop until the variable is not less than 5Create a function that returns the product of two numbersUses the new keyword to create an arraywere written in JavaScript and are found in the attached images
Declaring a variableThe first code declares a variable called num and gives it an initial value of 0. It then enters a while loop that lauches a message box (using window.alert) to print the message "Keep going" as long as num remains less than 5.
If nothing is done within the loop to increment num towards the value 5, the loop will go on endlessly notifying the user to "Keep going".
So, an increment of 1 was added to the loop body to increment the variable num. This makes sure the loop terminates.
Creating a function that returns the product of two numbersHere, a function was created that receives two arguments (n1 and n2), then returns the product (n1 * n2)
Declaring an ArrayThis last code segment creates an array using the new keyword. The new keyword is generally used in constructing objects.
In this case the object constructed is an array having three strings;
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When using the superposition theorem, each ideal voltage and current source must be replaced by an open circuit.
true
false
Answers
what device will produce an electrical current when a turbine is used to rotate an iron core wrapped with a coil of wire near a magnet?
Answers
A device that will produce an electrical current when a turbine is used to rotate an iron core wrapped with a coil of wire near a magnet is a generator.
A generator is a device that uses electromagnetic induction to convert mechanical energy into electrical energy. It operates on the basis of the Faraday Law of Electromagnetic Induction, which states that a current is induced in a conductor that is moving through a magnetic field.
The following components are found in a basic generator:
1) rotating magnetic field 2) rotating armature 3) wires 4) coils 5) commutator 6) brushes
Generators are used in a variety of applications, including power plants, wind turbines, and hydroelectric facilities. They are essential for converting mechanical energy into electricity. They have also been utilized as backup power supplies for homes and businesses.
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A current is set up in a wire loop consisting of a semicircle of radius 4.00 cm, a smaller concentric semicircle, and two radial straight lengths, all in the same plane. Figure shows the arrangement but is not drawn to scale. The magnitude of the magnetic field produced at the center of curvature is 47. 25μT.
Answers
After reversing the direction of the magnetic field which resulted in a Magnetic field produced at the centre of curvature(reversed) of 15.75μT then the radius of the small arc is 2cm. When
It is given that,
Magnetic field produced at the centre of curvature = 47. 25μT
Magnetic field produced at the centre of curvature(reversed) = 15.75μT
Let Br be a magnetic field of large radius and Br' be a magnetic field of small radius.
We know that Magnetic field produced due to arc of radius R and substanding angle ∅ is,
|B| = (µ0i∅)/4πr
According to the question Br and Br' are using ∅ = r for half circle
So, 47. 25μT = Br + Br'
47. 25μT = (µ0i∅)/4π × (1/r + 1/r') —-- (1)
and, 15.75μT = Br - Br'
15.75μT = (µ0i∅)/4π × (1/r - 1/r') —-- (2)
By dividing (1) by (2) we get
47. 25μT / 15.75μT = [(µ0i∅)/4π × (1/r + 1/r')] / [(µ0i∅)/4π × (1/r - 1/r')]
3 = (1/r + 1/r') / (1/r - 1/r')
2/r = 4/r'
r' = r/2
r' = 4/2
r' = 2 cm
Therefore the radius of the small arc is 2cm.
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—-------- Correct question format is given below —--------
(Q). A current is set up in a wire loop consisting of a semicircle of radius 4.00 cm, a smaller concentric semicircle, and two radial straight lengths, all in the same plane. Figure shows the arrangement but is not drawn to scale. The magnitude of the magnetic field produced at the center of curvature is 47.25μT.The smaller semicircle is then flipped over (rotated) until the loop is again entirely in the same plane. The magnetic field produced at the (same) center of curvature now has magnitude 15.75μT, and its direction is reversed from the initial magnetic field. What is the radius of the smaller semicircle? (fig is given below)
A particular load is rated to use 2.2 KW at 240 volts. If two of these loads are connected to the same circuit, the total circuit current is that of one load.
Answers
If two of these loads that's rated to use 2.2 KW at 240 volts are connected to the same electric circuit, the total circuit current is double that of one load.
What is an electrical circuit?An electric circuital can be defined as an interconnection of different electrical components, in order to create a pathway for the flow of electric current (electrons) due to a driving voltage.
The components of an electrical circuit.Generally, an electrical circuit comprises the following electrical components:
ResistorsCapacitorsBatteriesTransistorsSwitchesWiresLoads such as fans, light bulb, etc.In this scenario, we can infer and logically conclude that if two of these loads that's rated to use 2.2 KW at 240 volts are connected to the same electric circuit, the total circuit current is double that of one load.
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Please I want (Medical and/or industrial examples ) for Ceramics in science and engineering (please put the reference)
Answers
Examples of dental implants and high temperature furnace lining have beneficial applications of ceramics in both medical and industrial settings, demonstrating their unique properties and contributions to science and engineering.
Ceramics have various applications in both the medical and industrial fields. Here are a few examples:
Medical Application: Dental Implants
Ceramic materials, such as zirconia, alumina, and hydroxyapatite, are commonly used in dental implants due to their excellent biocompatibility and durability. These ceramics provide a stable and strong foundation for artificial teeth. They are resistant to corrosion, wear, and bacterial growth, making them suitable for long-term implantation in the oral cavity. [Reference: Piconi, C., & Maccauro, G. (1999). Zirconia as a ceramic biomaterial. Biomaterials, 20(1), 1-25.]
Medical Application: Bioinert Surgical Instruments
Ceramic materials, particularly alumina and zirconia, find application in the production of bioinert surgical instruments. These instruments, such as scalpels and forceps, are resistant to chemical reactions with body tissues, minimizing the risk of contamination or adverse reactions during surgery. Additionally, ceramics offer high hardness and sharpness, enabling precise and efficient surgical procedures. [Reference: Rau, J. V., & Boerman, O. C. (2009). Bioinert ceramics in surgery. Acta Biomaterialia, 5(3), 817-831.]
Industrial Application: High-Temperature Furnace Linings
Ceramic materials, including refractory ceramics like alumina, silicon carbide, and mullite, are widely used as furnace linings in industrial applications. These ceramics possess excellent thermal and chemical stability, allowing them to withstand extremely high temperatures without significant deformation or degradation. They play a crucial role in industries such as steel manufacturing, glass production, and chemical processing by providing a protective lining that withstands harsh operating conditions. [Reference: Trindade, B. Z., et al. (2020). Review of refractory ceramics for high‐temperature applications. International Journal of Applied Ceramic Technology, 17(6), 1942-1957.]
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1:
Determine the dynamic pressure of water received at the site described below.
Water Tower holds water at an elevation of 265 feet
Site is at an elevation of 145 feet
The water supply system uses cast iron pipes.
The water travels through 3.2 miles of pipes before reaching the site
The pipe has a diameter of 8 inches
The water travels through 9 90-degree bends, 4 Branch tees, and 1 Swing Check Valve
The water has a flow rate of 105 gpm
Round to the hundredths place (2 places after the decimal)
2:
What is the static head of a water supply system if the water tower holds water at and elevation of 462 feet and the site that uses the water is at an elevation of 294 feet?
Answer value
Answers
Answer:
20.87 Pa
Explanation:
The formula for dynamic pressure is given as;
q= 1/2*ρ*v²
where ;
q=dynamic pressure
ρ = density of fluid
v = velocity of fluid
First find v by applying the formula for flow rate as;
Q = v*A where ;
Q= fluid flow rate
v = flow velocity
A= cross-sectional area.
A= cross-sectional vector area of the pipe given by the formula;
A= πr² = 3.14 * 4² = 50.27 in² where r=radius of pipe obtained from the diameter given divided by 2.
Q = fluid flow rate = 105 gpm----change to m³/s as
1 gpm = 0.00006309
105 gpm = 105 * 0.00006309 = 0.006624 m³/s
A= cross-sectional vector area = 50.27 in² -------change to m² as:
1 in² = 0.0006452 m²
50.27 in² = 50.27 * 0.0006452 = 0.03243 m²
Now calculate flow velocity as;
Q =v * A
Q/A = v
0.006624 m³/s / 0.03243 m² =v
0.2043 m/s = v
Now find the dynamic pressure q given as;
q= 1/2 * ρ*v²
q= 1/2 * 1000 * 0.2043² = 20.87 Pa
3. gravity-induced stress in a soft layer (30 pts 15 bonus pts for the last question) a soft incompressible rubber layer is attached to a rigid wall and under the action of its own gravitational force. the thickness of the rubber layer is much smaller than its lateral size. neglecting the edge effects and assuming the stress/strain in the layer is homogenous, please calculate the stress state in the rubber layer. incompressible neo-hooken model can be used to describe the mechanical behavior of the rubber. in a recent experiment, it has been observed that when the layer is soft enough, the free surface on the bottom of the layer is will not be flat anymore. instead, the bottom surface becomes undulated. can you explain the phenomenon qualitatively based on energy minimization?
Answers
Undulations in the bottom surface of a soft rubber layer under its own gravitational force can be explained qualitatively based on energy minimization, where the undulations reduce the gravitational potential energy of the layer.
When a soft rubber layer is under its own gravitational force, it deforms and experiences stress due to the weight of the material. According to the neo-Hookean model, the stress state in the rubber layer can be calculated based on the strain energy density function. The undulation on the bottom surface of the rubber layer can be explained based on energy minimization. The deformation of the rubber layer under gravity induces a curvature on the surface of the layer, which increases the strain energy of the material. The undulation phenomenon occurs due to the elastic instability of the material, where the elastic energy of the material is reduced by forming a pattern of wrinkles on the surface. This phenomenon is a result of the balance between the elastic energy and gravitational potential energy in the rubber layer.
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The chart describes four people’s credit histories.
Creditworthy Criteria
Name
Description of Credit History
Ellie
Has more debt than earnings
Collin
Pays only some of his bills every month
Jacob
Has made three late payments in the past year
Eesha
Pays more than the minimum payment each month
Which person is creditworthy?
Answers
Answer:
D). Eesha pays more than the minimum payment each month.
Explanation:
Eesha would be considered most creditworthy among the given persons as she not only pays on time but also repays more than the minimum amount assigned to pay each month. In order to test the creditworthiness of an individual, his ontime debt paying capability is tested at first followed by the past credit repayment history and the credit score. Except Eesha, all the given candidates have failed to make timely repayment of their debts and hence, they cannot be considered creditworthy.
explain the distinction between a real address and a virtual address?
Answers
Virtual addresses refer to the virtual store viewed by the process.
might be different, in which case virtual addresses must be mapped into physical addresses.
Consider a machine of mass 70 kg mounted to ground through an isolation system of total stiffness 30,000 N/m, with a measured damping ratio of 0.2. The machine produces a harmonic force of 450 N at 13 rad/s during steady-state operating conditions. Determine
Answers
Complete Question
Consider a machine of mass 70 kg mounted to ground through an isolation system of total stiffness 30,000 N/m, with a measured damping ratio of 0.2. The machine produces a harmonic force of 450 N at 13 rad/s during steady-state operating conditions. Determine
(a) the amplitude of motion of the machine,
(b) the phase angle of the motion,
(c) the transmissibility ratio,
(d) the maximum dynamic force transmitted to the floor, and
(e) the maximum velocity of the machine.
Answer:
a) \(X=0.0272m\)
b) \(\phi=22.5 \textdegree\)
c) \(T_r=1.57\)
d) \(F=706.5N\)
e) \(V_{max}=0.35m/s\)
Explanation:
From the question we are told that:
Mass \(M=70kg\)
Total Stiffness \(\mu=30000\)
Damping Ratio \(r=0.2\)
Force \(F=450N\)
Angular velocity \(\omega =13rad/s\)
Generally the equation for vibration in an isolated system is mathematically given by
\(\omega_n=\sqrt{\frac{k}{m}}\)
\(\omega_n=\sqrt{\frac{30000}{70}}\)
\(\omega_n=20.7rad/s\)
a)
Generally the equation for Machine Amplitude is mathematically given by
\(X=\frac{F_O/m}{(\omega_n^2-\omega^2)^2-(2*r*\omega)*\omega_n*\omega^2)^{1/2}}\)
\(X=\frac{450}{70}}{(20.7^2-(137^2)^2-(2*0,2*(20.7(13)))^2)^{1/2}\)
\(X=0.0272m\)
b)
Generally the equation for Phase Angle is mathematically given by
\(\phi=tan^{-1}\frac{2*r*\omega_n*\omega}{\omega_n^2*\omega^2}\)
\(\phi=tan^{-1}\frac{2*0.2*20.7*13}{\20.7^2*13^2}\)
\(\phi=22.5 \textdegree\)
c)
Generally the equation for transmissibility ratio is mathematically given by
\(T_r=\sqrt{\frac{1+(2r\beta)^2}{(1-r^2)^2+(2*\beta*r)^2}}\)
Where
\(\beta=Ratio\ of\ angular\ velocity\)
\(\beta=\frac{13}{20.7}\\\beta=0.638\)
Therefore
\(T_r=\sqrt{\frac{1+(2*(0.2)(0.638))^2}{(1-(0.2)^2)^2+(2*0.2*0.638)^2}}\)
\(T_r=1.57\)
d)
Generally the equation for Maximum dynamic force transmitted to the floor is mathematically given by
\(F=(T_r)*F_o\)
\(F=(1.57)*450\)
\(F=706.5N\)
e)
Generally the equation for Maximum Velocity of Machine is mathematically given by
\(V_{max}=\omega*x\)
\(V_{max}=13*0.0272\)
\(V_{max}=0.35m/s\)
how does a less-than-truckload (ltl) motor operation differ primarily from a truckload (tl) operation? group of answer choices ltl carriers only provide short-distance service. ltl carriers do not use full-size trailers like truckload operations. ltl carriers usually provide service without re-handling the freight. ltl operations require several terminal locations for extensive coverage.
Answers
A less-than-truckload (LTL) motor operation primarily differs from a truckload (TL) operation because LTL operations require several terminal locations for extensive coverage.
A less-than-truckload (LTL) motor operation differs primarily from a truckload (TL) operation in several ways. Firstly, LTL carriers usually provide service without re-handling the freight, whereas TL carriers typically only handle the freight once, at the beginning of the journey. Additionally, LTL carriers do not use full-size trailers like truckload operations. Instead, they combine smaller shipments from multiple customers into a single truckload. This allows LTL carriers to provide more flexible service, as they can accommodate smaller shipments and provide more frequent pick-up and delivery times. Finally, LTL operations require several terminal locations for extensive coverage, while TL operations can often be handled from a single location. Overall, LTL operations are geared towards smaller, more frequent shipments, while TL operations are better suited for larger, less frequent shipments.
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which best describes machine language? select one. question 1 options: machine language is the most used language today. machine language instructions comprise only 1s and 0s of binary code. machine language is considered the easiest language to write. machine language relies heavily on go to statements question 2 (1 point) saved listen readspeaker webreader: listen which is a type of high level programming? select one.
Answers
Machine language, also known as machine code or object code, is a set of binary digits or bits that the computer reads and decodes. The only language that a computer can comprehend is machine language.
The fundamental language of computers is machine code, which is also referred to as machine language. It is made of digital binary integers, is read by the central processing unit (CPU) of the computer, and appears to be a very lengthy string of zeros and ones.
Machine language is a type of low-level programming language that can only be understood by machines and is composed of binary integers or bits. The CPU immediately executes the instructions, often known as machine code or object code.
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In the AC resistor circuit of Figure Q2.1, the voltage of the AC power source is
U = 100 sin(120pi x t) V .
what are
(a) the peak voltage of the AC power source
(b) the frequency of the alternating current in the circuit
(c) the instantaneous voltage of the power source at t = 20 ms
(d) the peak voltage across each resistor
(e) the instantaneous resistor voltages at t = 20 ms,
(f) to sketch the waveform of voltage in the first two periods
Answers
Answer:
(a) 100 V
(b) 60 Hz
(c) 95.106 V
(d) 25 V, 75 V
(e) 23.776 V, 71.329 V
(f) see attached
Explanation:
(a)The peak value of the sine function is 1, so the peak value of U is ...
100·1 = 100 V.
__
(b)The argument of the sine function is 2πft, so f = 120πt/(2πt) = 60 Hz.
__
(c)When t=0.020, the voltage is ...
U = 100sin(120π·0.020) = 100 sin(2.4π) ≈ 95.106 V
__
(d)The resistors are in the ratio of 1 : 3, so divide the source voltage in that ratio.
The peak voltage across the 5Ω resistor is 1/4 of 100 V, or 25 V.
The peak voltage across the 15Ω resistor is 3/4 of 100 V, or 75 V.
__
(e)The same fractions as in (d) apply to the instantaneous voltage.
The voltage on the 5Ω resistor is 1/4·95.106 V ≈ 23.776 V
The voltage on the 15Ω resistor is 3/4·95.106 V ≈ 71.329 V
__
(f)See attached.
In which situation is a are food service workers not required to wash their hands?
Answers
Answer:
when wearing gloves?
Explanation:
?
or when off duty
Answer:
When off duty
Explanation:
a rectangular gasoline tank can hold 50kg of gasoline when full what is the depth of the tank if it is 0.5m wide by 0.9m long ?relative density of gasoline is 0.75 live the answer in centimeters [p(water)=1000kgm -3meter cube
Answers
Given :
Mass of gasoline , m = 50 kg .
Length of tank , l = 0.9 m.
Breadth of tank , b = 0.5 m .
Relative density of gasoline , R.D = 0.75 .
Density of water , \(\rho_{water}=1000\ kg/m^3\) .
To Find :
The depth of tank .
Solution :
We know ,
\(R.D=\dfrac{\rho_{gasoline}}{\rho_{water}}\\\\\rho_{gasoline}=0.75\times 1000 \ kg/m^3\\\\\rho_{gasoline}=750\ kg/m^3\)
Now , volume of gasoline is :
\(V=\dfrac{m}{\rho_{gasoline}}\\\\V=\dfrac{50}{750}\ m^3\\\\V=\dfrac{1}{15}\ m^3\)
Since , the tank is rectangular , volume is given by :
\(V=l\times b\times h\\\\h=\dfrac{V}{l \times b}\\\\h=\dfrac{1}{15\times 0.9\times 0.5}\ m\\\\h=0.148\ m=14.8\ cm\)
Therefore , the answer in centimetres is 14.8 cm .
Hence , this is the required solution .
1lb-mass of water fills a 2.4264-ft3 weighted piston-cylinder device at a temperature of 600of. the piston-cylinder device is now cooled until its temperature is 200of. determine the final pressure of water, in psia, and the volume, in ft3.
Answers
The final pressure of water is 397.15 psia, and the final volume is \(4.1403 ft^3\)
To solve this problem, we can use the ideal gas law, which relates the pressure, volume, and temperature of a gas.
However, water is not an ideal gas, so we need to use the appropriate equation of state for water, such as the steam tables.
Given data:
Mass of water = 1 lb
Initial volume = 2.4264 ft^3
Initial temperature = 600 °F
Final temperature = 200 °F
We need to determine:
Final pressure of water in psia
Final volume of water in ft^3
To solve this problem, we can use the steam tables to find the specific volume of water at the given initial and final temperatures.
At 600 °F, the specific volume of water is 0.0105 ft^3/lb, and at 200 °F, the specific volume is 0.0179 ft^3/lb.
Using the principle of mass balance, we can write:
Initial mass = Final mass
Density × Initial volume = Density × Final volume
We know the initial mass of water is 1 lb, and we can use the initial specific volume to find the initial density:
Initial density = 1 lb / 0.0105 ft^3/lb = 95.2381 lb/ft^3
Now we can solve for the final volume:
Final volume = (Initial volume × Initial density) / Final density
Final density = \(1 lb / 0.0179 ft^3/lb = 55.8659 lb/ft^3\)
Final volume = \((2.4264 ft^3) * (95.2381 lb/ft^3) / (55.8659 lb/ft^3) = 4.1403 ft^3\)
Finally, we can use the ideal gas law to find the final pressure of water:
P1 × V1 / T1 = P2 × V2 / T2
where P1, V1, and T1 are the initial pressure, volume, and temperature, and P2, V2, and T2 are the final pressure, volume, and temperature.
We can assume that the system is quasi-static and adiabatic, so the process is reversible and no heat transfer occurs. Therefore, the entropy change is zero, and we can use the isentropic relation:
\(P2 / P1 = (V1 / V2)^{(k)}\)
where k is the specific heat ratio of water, which varies with temperature. At the given temperatures, we can use an average value of k = 1.31.
Substituting the values and solving for P2, we get:
\(P2 = P1 * (V1 / V2)^{(k)} = 397.15 psia\)
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A noisy transmission channel has a per-digit error probability p = 0.01.
(a) Calculate the probability of more than one error in 10 received digits?
Answers
Answer:
The appropriate answer is "0.0043".
Explanation:
The given values is:
Error probability,
p = 0.01
Received digits,
n = 10
and,
\(x\sim Binomial\)
As we know,
⇒ \(P(x)=\binom{n}{x}p^xq^{n-x}\)
Now,
⇒ \(P(x >1) =1- \left \{ P(x=0)+P(x=1) \right \}\)
⇒ \(=1-\left \{\binom{10}{0}(0.01)^0(0.99)^{10-0}+\binom{10}{0}(0.01)^1(0.99)^{10-1} \right \}\)
⇒ \(=1-0.9957\)
⇒ \(=0.0043\)