how many coulombs of charge are needed to reduce 127g of chromium(iii) chloride, crcl3, to chromium metal by electrolysis?

Answer:

Explanation:

4

Answer: The by-product of photosynthesis is oxygen.

Explanation: The photosynthesis process is the process by which photoautotrophs convert light energy into chemical energy which can later be used to fuel the activities of organisms. The three important elements required for the photosynthesis process are Water, carbon dioxide and light. The product formed from this process, stored in the form of sugars, which are created from water and carbon dioxide. The by-product of the photosynthesis process is oxygen.

6CO2 + 6H2O → C6H12O6 + 6O2

Answer:

Oxygen

Explanation:

Plants don't have any use for oxygen and we get oxygen from plants

The molarity of a solution that contains 14.1 g of caffeine dissolved in 942 ml of solution is 0.0770 mol/l.

The formula for molarity is,

M = n / V

where, M = molarity of solution

V = volume of solution in litres

where, n = given mass / molar mass

n = 14.1 /194.19

n = 0.0726

So, molarity is

M = 0.0726 / 0.942

M = 0.0770 mol/l

Therefore, molarity of a solution that contains 14.1 g of caffeine dissolved in 942 ml of solution is 0.0770 mol/l.

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Answer:

brain HSHSHSHSHHSSHSHS

0.310 moles of \(Cl_{2}\) are present in the container, according to the reaction. This is the answer to the given question.

Carbon tetrachloride is a manufactured chemical that does not occur naturally. It is a clear liquid with a sweet smell that can be detected at low levels. It is also called carbon chloride, methane tetrachloride, perchloromethane, tetrachloroethane, or benziform. Carbon tetrachloride molecules have tetrahedral molecular geometries in which the central carbon atom is bonded to four chlorine atoms.

The liver and kidneys are harmed by acute exposure to high quantities of carbon tetrachloride in drinking water. Headache, lightheadedness, fatigue, sluggishness, and impaired vision are further signs. Extremely high doses can also result in death, vomiting, or stomach pain.

(0.4) (25) = (0.0821) (n) (120+273)

Moles of \(Cl_{2}\),n = 0.310 mol

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Answer:

I think is B and C

Explanation:

There are two direct factors that affect solubility: temperature and pressure.Temperature affects the solubility of both solids and gases, but pressure only affects the solubility of gases.

Answer:

Explanation:

It is c and d promise took test.

87680 grams

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Answer:

87.68 times 1000 so that equals 87680 grams.

Explanation:

Answer:

E = 26.4 × 10⁻²⁷ j

Explanation:

Given data:

Frequency of photon = 4×10⁷ Hz

Energy of photon = ?

Planck's constant = 6.6 × 10⁻³⁴ js

Solution:

Formula:

E = h × v

v =  frequency

Now we will put the values in formula.

E = 6.6 × 10⁻³⁴ js × 4×10⁷ Hz

Hz = s⁻¹

E = 26.4 × 10⁻²⁷ j

The energy of photon is 26.4 × 10⁻²⁷ j.

Answer: I think it’s 3 x 10 ^-27 J, I’m sorry if it wrong

Explanation:

The family of elements that is relatively unreactive is the noble gases, also known as Group 18 or the inert gases.

This group includes helium, neon, argon, krypton, xenon, and radon. Noble gases are unreactive because their outermost electron shells are completely filled with electrons, making them stable and resistant to gaining or losing electrons to form chemical bonds with other atoms. This electronic configuration makes noble gases extremely stable and non-reactive under normal conditions. This also means that noble gases have very low electronegativity and ionization energy, making it difficult for them to form chemical bonds with other elements.

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Answer: XCl2(aq) + 2 AgNO3(aq) ---> X(NO3)2(aq) + 2 AgCl(s)

Explanation:

Hehe I remembered how...

In this instance, the equilibrium concentration of Cu⁺ with 0.10 M Br⁻ is similarly 0.10 M.

To determine the concentration of Cu⁺ in equilibrium with CuBr(s) and 0.10 M Br⁻, we need to consider the solubility equilibrium of CuBr.

The solubility equilibrium for CuBr can be represented as follows:

CuBr(s) ⇌ Cu⁺(aq) + Br⁻(aq)

The solubility product constant (Ksp) expression for this equilibrium is:

Ksp = [Cu⁺][Br⁻]

Since the stoichiometry of the reaction is 1:1 between Cu⁺ and Br⁻, the concentration of Cu⁺ in equilibrium will be equal to the concentration of Br⁻.

Therefore, in this case, the concentration of Cu⁺ in equilibrium with 0.10 M Br⁻ is also 0.10 M.

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The concentration of Cu+ in equilibrium with solid CuBr and 0.10M Br- is 7.9 x 10-5 M. This happens due to the common ion effect, which is the presence of extra Br- ions in solution that suppress the dissolution of CuBr.

You are asked to find the concentration of Cu+ in equilibrium with solid CuBr and 0.10M Br-. The solubility product constant (Ksp) defines the equilibrium between a solid and its constituent ions in a solution. The balanced equation for this dissolution process is:

CuBr(s) <==> Cu+ (aq) + Br- (aq)

For CuBr, the Ksp value is 7.9 x 10-5 M. This represents product of concentrations of its ions in the solution. However, we already have 0.10M Br-, which is much higher than that provided by the dissolution of CuBr. Therefore, the Cu+ concentration in equilibrium is essentially equal to the Ksp, i.e. 7.9 x 10-5 M.

Here, the concept of the common ion effect comes into play. The presence of extra Br- ions from the solution suppresses the dissolution of CuBr, thereby controlling the Cu+ concentration in the solution.

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To calculate the grams of NaCl in a 100 g solution with water, when the solution is 19% NaCl by weight, we can use the formula:

Grams of NaCl = Total weight of solution (in grams) × Percentage of NaCl / 100

In this case, the total weight of the solution is 100 g and the percentage of NaCl is 19%. Plugging in these values:

Grams of NaCl = 100 g × 19 / 100 = 19 grams

Therefore, there are 19 grams of NaCl in the 100 g solution.

Regarding the chemical reaction equation, to balance it, we can use the coefficients to adjust the number of atoms on each side.

The equation is: ___SO2 + ___O2 -> ___SO3

The correct balanced equation is: 2SO2 + O2 -> 2SO3

The coefficients in this balanced equation indicate that we need 2 molecules of SO2, 1 molecule of O2, and 2 molecules of SO3 to balance the reaction.

B. To calculate the density of a substance, we use the formula:

Density = Mass / Volume

In this case, the mass of the gasoline is given as 20.2 kg and the volume is given as 23.7 liters.

Density = 20.2 kg / 23.7 L

Calculating this:

Density = 0.851 Kg/L

Rounding this value to the correct significant figures gives:

Density = 0.85 Kg/L

Therefore, the density of gasoline is approximately 0.85 kg/L.

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The moles of gas that I have If I have an unknown quantity of gas at a pressure of 1.2 atm, a volume of 31 liters, and a temperature of 87 0 C is 1.26 moles.

To determine the mol of gas, we can use Mendeleev-equation Clapeyron's:

pV = nRT

Where:

n is the number of moles = ?

p is pressure = 1.2 atm

V is volume = 31 liters

T is temperature = 87°C ⇒ (273+87) = 360 K

R is the constant of all gases = 0.082 L.atm/mol.K

So, we can define the n number as:

n = pV/(RT)

n = (1.2) (31) / (0.082) (360) =

1.26 moles

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250 kJ of energy are removed from a 4.00 x 102 g sample of water at 60˚C. Will the sample of water completely freeze: Yes, because there is enough energy.

250 kJ of energy are removed from a 4.00 x 102 g sample of water at 60˚C. Will the sample of water completely freeze: Yes, because there is enough energy.

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Answer:

The answer is C) fluorine (F)

Answer:

pOH = 7.89

Explanation:

As HCl is a strong acid, [H⁺] is equal to the original acid concentration. In other words:

Knowing [H⁺], we calculate the pH of the solution:

With the pH, we can calculate the pOH of the solution, using the following formula:

Maps assist in identifying patterns in data by visually displaying spatial relationships, trends, and anomalies, making it easier to analyze and interpret the information.

Maps are an essential tool for identifying patterns in data because they present information in a spatial context. This enables users to see relationships, trends, and anomalies that might not be apparent in other formats. By representing data on a map, it becomes easier to observe geographic distributions, identify clusters or hotspots, and analyze spatial relationships between different variables.

Furthermore, maps can be layered with various data sets, allowing for a more comprehensive understanding of the connections between different factors. Ultimately, maps serve as an effective means of visualizing and interpreting complex data, making it simpler to draw conclusions and make informed decisions based on the identified patterns.

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Answer:

11.5 okkkkkkkkkkkkkkkkkkkkkkkkkkkk chutita

TiCl₄+2H₂O⇔TiO₂+4HCl

The coefficient for titanium tetrachloride = 1

Equalization of chemical reactions can be done using variables. Steps in equalizing the reaction equation:

1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c, etc.

2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index (subscript) between reactant and product

3. Select the coefficient of the substance with the most complex chemical formula equal to 1

Reaction

TiCl₄+H₂O⇔TiO₂+HCl

give coefficient

TiCl₄+aH₂O⇔bTiO₂+cHCl

Ti, left=1, right=b⇒b=1

Cl, left=4, right=c⇒c=4

H, left=2a, right=c⇒2a=c⇒2a=4⇒a=2

O, left=a, right=2b⇒a=2b⇒2=2.1⇒match

Balanced equation :

TiCl₄+2H₂O⇔TiO₂+4HCl

Answer:

the coefficient of TiCl4 would be 1

119 grams of solid magnesium chloride are required to make 250ml of 0.50M solution.

First, we know that a 1 M solution contains

moles of solute per 1.0 L of solution.

This means that a 5.0 M magnesium chloride solution contains 5.0 moles of magnesium chloride (solute) per 1.0 L of solution.

Now all we need to calculate is that the moles of magnesium chloride in solution of 250ml . Hence, the moles of magnesium chloride in 250 ml = 0.250 L of solution is equivalent to 0.50 mol in 1.0 L of solution i.e.,

mol of MgCl₂ / 0.25L = 0.50mol/ 1.0 L

using cross multiplication we get,

moles of MgCl₂ in 250ml solution is 1.24

Now, we can use the number of moles formula to find out the mass of magnesium chloride in solution.

To convert this to grams, number of moles of magnesium chloride = ratio of mass of magnesium chloride to the molar mass of magnesium chloride.

molar mass of magnesium chloride= 95.2 g then mass of magnesium chloride in 250ml solution

= 1.25 × 95.2 = 119g

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Based on the problem being investigated and the data collected, the type of investigation the students conducted is the composition of the Martian soil sample and the evidence of past life on it.

The evidence of past life on Mars is tiny seed-like fossils that appear to be pieces of fossilized shells.

Mars is the second-smallest planet in the Solar System, only slightly larger than Mercury, and is the fourth planet from the Sun.

Research has sought to find evidence for life on Mars.

Based on the study, tiny seed-like fossils serve as evidence for life on Mars.

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Answer:

A) synthesis

I hope this helps!

Answer:

Dermal tissue of the stems and leaves is covered by a waxy cuticle that prevents evaporative water loss. Stomata are specialized pores that allow gas exchange through holes in the cuticle. Unlike the stem and leaves, the root epidermis is not covered by a waxy cuticle which would prevent absorption of water.

Explanation:

Explanation:

The molecules of solids are shrinked in there normal state . but as a heat energy is produced , the molecules starts curating fast and fast as temperature goes up . since they vibrate , they hit and collide each other breaking the bondings this increases the surface of area of the solid , and molecules consumes that space and they expand .

Answer:

Both

Explanation:

The combined gas law is also known as the general gas law.

From the ideal gas law we assume that n = 1;

So;

              PV  = nRT

 and then;

                  \(\frac{P_{1}V_{1} }{T_{1} }\)  = \(\frac{P_{2}V_{2} }{T_{2} }\)

   If we cross multiply;

                P₁V₁T₂   = P₂V₂T₁

  So;

         T₁ = \(T_{2} \frac{P_{1}V_{1} }{P_{2} V_{2} }\)

Also;

         V₂  = \(V_{1} \frac{P_{1} T_{2} }{P_{2} T_{1} }\)

So from the choices both are correct

Hydration is a specific example of the phenomenon known generally as a. solvation

The act of hydrating involves combining or dissolving an object in water. It is a particular instance of the more general phenomena known as solvation, which is the process by which solvent molecules surround and scatter a solute to create a homogeneous solution. However, hydration explicitly refers to solvation with water as the solvent.

Solvation may also happen with solvents other than water. Solvation is the process through which a solute and solvent interact to stabilise a solute species. Due to its impact on the solubility, reactivity, and behaviour of compounds in solution, solvation is a crucial mechanism in many chemical and biological processes.

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The degradation of odd-chain fatty acids can boost the activity of the citric acid cycle is increase in the concentration of the cycle intermediates will causes the increase in the activity in the citric acid cycle.

The building blocks of the fats in the body and the food we consumed are called the fatty acids. The molecule  that is the  triglyceride is created when the three fatty acid molecules will linked together.

The Succinyl-CoA is the citric acid cycle intermediate. The Acetyl-CoA is the substrate in the citric acid cycle. This result, in the activity of the cycle that can be boosted by increasing the concentration of the cycle intermediates, in the case, succinyl-CoA and the acetyl-CoA.

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The theoretical yield of the reaction is 65.7 grams.

Mass C₆H₆ = 45.6 g

actual yield = 63.7 g

Balanced chemical formula:

C6H6 (l) + Cl2 (g) → C6H5Cl (s) + HCl (g)

Calculate the molar masses of C6H6 and C6H5Cl.

For C₆H₆

Molar mass of C₆H₆ = (12.01 g/mol × 6) + (1.008 g/mol × 6)

Molar mass of C₆H₆ = 78.108 g/mol

For C₆H₅Cl

Molar mass of C₆H₅Cl = (12.01 g/mol × 6) + (1.008 g/mol × 5) + (35.45 g/mol × 1)

Molar mass of C₆H₅Cl = 112.55 g/mol

Since 1 mole of C6H6 = 1 mole of C6H5Cl, the theoretical yield of the reaction is

65.7 grams

Yield calculation = 96.9%

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