Answers
Answer:
0.64 molesExplanation:
To find the number of moles in a substance given it's number of entities we use the formula
\(n = \frac{N}{L} \)
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
\(n = \frac{3.86 \times {10}^{23} }{6.02 \times {10}^{23} } = \frac{3.86}{6.02} \\ = 0.641196...\)
We have the final answer as
0.64 molesHope this helps you
Related Questions
What is the pH of a 3.5 x 10-5 M solution of HCl?
Answers
Answer:
pH = 4.45
Explanation:
We need to find the pH of \(3.5\times 10^{-5}\ M\) solution of HCl. We know that, pH of a solution is given by :
\(pH=-log[H]^+\)
Put all the values,
\(pH=-log[3.5\times 10^{-5}]\\\\pH=4.45\)
So, the pH of the solution of HCl is 4.45.
A German automobile's gas mileage is 18km/L. Convert this quantity to miles per gallon.
Answers
Answer:
42
Explanation:
miles per gallon = kilometers per liter × 2.35
What happens to a buffered solution when a small amount of base is added?
O The solution quickly becomes neutral.
O The solutions resists changes in pH.
O The solution slowly becomes acidic.
O The solution quickly becomes basic.
Answers
Answer:
solution resists changes in pH
Explanation:
the inherent property of buffers is to resist change to ph even when acids and bases are added. when the base is added, it is quickly neutralized by the conjugate acid, so the ph won't change.
Answer:
B: The solutions resists changes in pH.
Explanation:
Buffer reactions maintain stable pH of solutions.
Tim and Jose are moving furniture. Tim pushes a 150kg sofa with 300N force. As a result, Sofa’s acceleration was _____ according to Newton’s Second Law of motion. [F=ma]
Answers
Answer: 160
Explanation:
Answer:150/ms behfhefjioweufioefwebveour
What is the median reaction of second end point in HCL and NaOH titration
Answers
The median reaction at the second end point in the HCl and NaOH titration is: HCl + NaOH → NaCl + H2O
In a titration between hydrochloric acid (HCl) and sodium hydroxide (NaOH), the reaction involved is the neutralization reaction between an acid and a base. The balanced equation for this reaction is:
HCl + NaOH → NaCl + H2O
In this reaction, one mole of HCl reacts with one mole of NaOH to form one mole of NaCl (sodium chloride) and one mole of water.
During the titration process, the reaction occurs gradually as the base is added to the acid solution.
The first end point of the titration is reached when the moles of HCl and NaOH are stoichiometrically equivalent, meaning they react in a 1:1 ratio. At this point, all the HCl has been neutralized by the NaOH, and no excess of either reagent remains.
However, if the titration is continued beyond the first end point, the reaction between HCl and NaOH can still occur, albeit in a different ratio.
The second end point refers to the point where the moles of NaOH added exceed the stoichiometrically required amount to neutralize the HCl completely. As a result, any excess NaOH added after the second end point reacts with the excess HCl in a 1:1 ratio.
Therefore, the median reaction at the second end point in the HCl and NaOH titration is:
HCl + NaOH → NaCl + H2O
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how many grams of F2 are needed to react with 3.50 grams of Cl2 Equation needed for question- Cl2+3F2-->2ClF3 please explain how to get the answer.
Answers
Answer:
5.62 g of F2
Explanation:
We have to start with the chemical reaction:
\(Cl_2~+~3F_2~-->~2ClF_3\)
We have a balanced reaction, so we can continue with the mol calculation. For this, we need to know the molar mass of \(Cl_2\) (70.906 g/mol), so:
\(3.5~ g~Cl_2 \frac{1~mol~Cl_2}{70.906~g~Cl_2}=0.049~mol~Cl_2\)
Now, with the molar ratio between \(Cl_2\) and \(F_2\) we can convert from moles of \(Cl_2\) and \(F_2\) (1:3), so:
\(0.049~mol~Cl_2\frac{3~mol~F_2}{1~mol~Cl_2}=0.148~mol~F_2\)
Finally, with the molar mass of \(F_2\) we can calculate the gram of \(F_2\) (37.99 g/mol), so:
\(0.148~mol~F_2\frac{37.99~g~F_2}{1~mol~F_2}=5.62~g~F_2\)
I hope it helps!
Using the balanced equation CaC₂(ş) + 2 H₂O(1) --> C₂H₂(g) + Ca(OH)₂(aq) how many moles of Ca(OH)2 would be produced if 3.5 moles of H₂O are consumed?
Answers
Answer:
1.75 moles
Explanation:
According to CaC₂(s) + 2 H₂O(l) --> C₂H₂(g) + Ca(OH)₂(aq)
2 moles of H20 will produce 1 mole of Ca(OH)2
therefore 3.5 moles of H2O will produce 3.5 x (1/2) = 1.75 moles of Ca(OH)2
Determine whether the compounds below could be used to prepare an buffer solution. Items (6 items) (Drag and drop into the appropriate area below) acetic acid Ka-1.8x10-5 ammonia Kb= 1.8x10 carbonic acid Ka-4.3x107 chlorous acid: calcium Ka-1.1x10-2 sulfuric acid hydroxide Categories CANNOT be used Drag and drop here Drag and drop here
Answers
Answer:
Acetic acid, carbonic acid and chlorous acid with calcium hydroxide
Ammonia with sulfuric acid
Explanation:
A buffer is an aqueous mixture of a weak acid and its conjugate base or vice versa.
Weak acids reacts with strong bases to produce the conjugate base. In the right amount, you can produce a buffer. In the same way, you can produce a buffer from the mixture of weak bases with strong acids.
In the problem, you have weak acids (acetic acid, carbonic acid, chlorous acid), one weak base (ammonia), one strong base (calcium hydroxide) and one strong acid (Sulfuric acid).
Thus, the mixtures that can produce a buffer are:
Acetic acid, carbonic acid and chlorous acid with calcium hydroxide
And:
Ammonia with sulfuric acid
Isabel and Ruth scored a total of twenty-two points in their last basketball game scored two more points than Isabelle.How many points did Isabel score?
A:2x-2=22; x=12
B:x+2=22; x=20
C:2x+2=22; x=10
D:2x+2=22; x=12
Answers
isabel is represented as x
ruth is represented as x+2
so the equation would be
x+(x+2)=22
the (x+2) is ruth. so to check if its right solve it. 2x+2=22
-2 -2
2x+20
__ ___
2 2
x=10
so now you know that isabel scored 10 goals since she was x. to figure out ruth just add 2.
Write ashort note on the
first battle of
of panipat
Answers
Answer:
The First Battle of Panipat was fought between the invading forces of Babur and the Lodi Empire, which took place on 21 April 1526 in North India. It marked the beginning of the Mughal Empire. This was one of the earliest battles involving gunpowderfirearms and field artillery.
For you to write an essay on Panipat first bring into view
Introduction body conclusionThen write a brief story using this format.
How to write a short note on the first battle of Panipat?In writing this essay, you must consider the structure and content of the essay or short note
For structure kick off with
Introduction body conclusionIn conclusion, for the content of the short note you can consider this,
Panipat fought its first battle on 21 April 1526 in the North of India, This battle was fought between the invading powers of Babur and the Lodi Empire.
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In a protein molecule, the number of amino acid molecules may be as few as
5
5,000
500
50
Answers
In a protein molecule, the number of amino acid molecules may be as few as d. 50.
Proteins are large macromolecules composed of chains of amino acids. These amino acids are linked together through peptide bonds to form the primary structure of a protein. The number of amino acids present in a protein molecule can vary greatly and depends on the specific protein.
Proteins can range in size from small peptides composed of just a few amino acids to large complex proteins containing thousands of amino acids. The minimum number of amino acids required for a protein to be considered functional is typically around 50. This is because proteins need a certain length and structural complexity to carry out their specific functions.
Proteins play vital roles in living organisms and are involved in various biological processes such as enzyme catalysis, cell signaling, structural support, and immune response. The specific number and sequence of amino acids in a protein molecule determine its unique structure and function.
Therefore, while some proteins may consist of as few as 50 amino acids, larger and more complex proteins can contain thousands of amino acids, enabling them to perform intricate and diverse functions within living systems. Therefore, Option D is correct.
The question was incomplete. find the full content below:
In a protein molecule, the number of amino acid molecules may be as few as
a. 5
b. 5,000
c. 500
d. 50
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Pls help I’ll give brainly
Answers
A weather balloon contains 9.7 moles of helium at a pressure of 0.955 atm and a temperature of 25 °C at ground level. What is the volume (in L) of the balloon under these conditions?
Answers
Answer:
2.5 × 10² L
Explanation:
Step 1: Given and required data
Moles of He (n): 9.7 molPressure (P): 0.955 atmTemperature (T): 25 °CIdeal gas constant (R): 0.0821 atm.L/mol.KStep 2: Convert 25 °C to Kelvin
We will use the following expression.
K = °C + 273.15 = 25 + 273.15 = 298 K
Step 3: Calculate the volume (V) of the balloon
We will use the ideal gas equation.
P × V = n × R × T
V = n × R × T / P
V = 9.7 mol × (0.0821 atm.L/mol.K) × 298 K / 0.955 atm = 2.5 × 10² L
The formula for a compound containing sodium and oxide ions would contain... This
compound would have an overall ... charge.
Answers
Explaintion.
Answer:
Explanation:
the formula of the compound containing sodium and oxide ion is
NaOH the charge on sodium is partial positive and the charge on hydroxide ion is partial negative
another compound containing sodium and oxide ion is Na2O here the charge on sodium oxide is neutral
you have isolated a decapeptide (a 10-residue peptide) called fp, which has anticancer activity. determine the sequence of the peptide from the following information. (note that amino acids are separated by commas when their sequence is not known.) (a) one cycle of edman degradation of intact fp yields 2 mol of pth-aspartate per mole of fp. (b) treatment of a solution of fp with 2-mercaptoethanol followed by the addition of trypsin yields three peptides with the composition (ala, cys, phe), (arg, asp), and (asp, cys, gly, met, phe). the intact (ala, cys, phe) peptide yields pth-cysteine in the first cycle of edman degradation. (c) treatment of 1 mol of fp with carboxypeptidase (which cleaves the c-terminal residue from peptides) yields 2 mol of phenylalanine. (d) treatment of the intact pentapeptide (asp, cys, gly, met, phe) with cnbr yields two peptides with the composition (homoserine lactone, asp) and (cys, gly, phe). the (cys, gly,phe) peptide yields pth-glycine in the first cycle of edman degradation.
Answers
Due to its simplicity of use and high-throughput operations, liquid chromatography-mass spectrometry (LC-MS) is a widely used technique for determining peptide sequences.
What is meant by LC-MS?Liquid chromatography-mass spectrometry is an analytical chemistry method that combines the mass spectrometric mass analysis skills with the physical separation capabilities of liquid chromatography. A method used in laboratories to separate, identify, and quantify the concentration of several compounds in a liquid sample by combining two distinct processes.Liquid chromatography (LC) can be used to separate the components, and the sample eluents from LC are then carried into mass spectrometry (MS), where the detection, identification, and measurement of the masses of the components can be done while other components are present.The components within each peak are then recognised and detected using the mass spectra of those components. Using LC-MS, mixtures are separated depending on their physical and chemical features.To learn more about LC-MS, refer to:
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What mass of NaClO2, is contained in 400 grams of water whose
molality is 0.60
Answers
Answer:
Nacio, is contained in 400 grams of water whose molality ... Molality= moles of solute / mass of solvent in Kg Now molality=0.60 Mass
Explanation:
/////
What is the element of lowest atomic number whose electronic configuration has four completely filled p sub shells
Answers
The element of lowest atomic number whose electron configuration has 4 completely filled p orbitals is, Xenon, Xe with electron configuration:1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶.
According to the question, we are required to identify the element with the lowest atomic number whose electronic configuration has four completely filled p sub-shells.
Evidently, the shell with energy level one has no p orbital.
Therefore, the existence of p orbitals in electron configuration begins with shell energy level, n=2.However, we must know that the p-orbital comprises of 3 sub-orbitals namely;p(x) , p(y) and p(z) with two electrons of opposing spin in each sub orbital.
Therefore, the total number of electrons in the p orbital is 6 electrons.In essence, the element in question should have electron configuration;
1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶.The electron configuration above contains 54 electrons and has atomic number, 54.
In essence, the element of lowest atomic number whose electron configuration has 4 completely filled p orbitals is, Xenon, Xe.
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b. How many kJ of heat are needed to completely vaporize 50.0g of water at 100°C? [Ans:113. kJ]
Answers
The amount, in kJ, of heat needed to completely vaporize 50.0g of water at 100°C is 118.8 kJ.
Heat of vaporization of waterThe heat needed to completely vaporize 50.0g of water at 100°C can be calculated using the following formula:
q = m x Hv
where:
q is the heat needed in joules (J)m is the mass of water in grams (g)Hv is the heat of vaporization of water which is approximately 40.65 kJ/mol at standard temperature and pressure.First, we need to convert 50.0g to moles by dividing by the molar mass of water which is approximately 18.015 g/mol3:
moles of water = 50.0 g / 18.015 g/mol moles of water = 2.776 mol
Thus:
q = (2.776 mol) x (40.65 kJ/mol) q = 112.8 kJ
In other words, 112.8 kJ of heat is needed to completely vaporize 50.0g of water at 100°C.
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6 mol of KClO3 decomposes. How many mass of O2 will be produced? [8pts]
KClO3 → KCl + O2
Answers
6 mol of KClO3 will produce 288 grams of O2, when 6 mol of KClO3 decomposes.
How to calculate mass of O2 for this problem?
The balanced chemical equation for KClO3 decomposition is:
2 KClO3 →
2 KCl + 3 O2
According to the equation, 2 moles of KClO3 produce 3 moles of O2.
Therefore, 6 moles of KClO3 will produce (6/2) x 3 = 9 moles of O2.
To calculate the mass of O2 produced, we need to use the molar mass of O2, which is approximately 32 g/mol.
So, the mass of O2 produced will be:
mass = number of moles x (molar mass)
mass = 9 mol x 32 g/mol
mass = 288 g
Therefore, 6 mol of KClO3 will produce 288 grams of O2.
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32 g of Br2 are added to 10 g of a mixture of ethene and ethane. What is the mass percent of ethene in the mixture?
Answers
Answer:
A mixture of ethane and ethene occupies 40 litre at 1.00 atm and at 400 K.The mixture reacts completely with 130 g of O2 to produce CO2 and H2O . Assuming ...
Missing: 32 Br2
The volume of a beaker is 65.0 mL. What is the volume of
water that you need to fill up the beaker in cubic centimeters?
Answers
Answer
65cm^3
Explanation
1mL=1cm^3
so; 65.0mL=65cm^3
whats the meaning
Speed ?
and the
meaning of
of Motion?
Answers
Motion; the action or process of moving or being moved
A student mixed 25 grams of salt into 1,000 grams of water.
What is the mass of the mixture?
A. 975 grams
B. 1,000 grams
C. 1,025 grams
D. 2,500 grams
Answers
The two main postulates that was given by Antoine Lavoisier are, oxygen play an important role in combustion and the other is mass of reaction is always conserved. Therefore, the mass of the mixture is 1025g. the correct option is option C.
What is law of conservation of mass?According to Law of conservation of mass, mass can neither be created nor be destroyed. Mass can only be transformed from one form to another. The law of conservation of mass was given by Antoine Lavoisier. Every reaction in nature follow the law given by Antoine Lavoisier that is mass is always conserved.
mass of salt+ mass of water=mass of solution
mass of salt =25 grams
mass of water=1,000 grams
substituting the given values, we get
25 grams+ 1,000 grams =mass of solution
mass of solution=1025g
Therefore, the mass of the mixture is 1025g. the correct option is option C.
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Part D What evidence can be used to support the fact that oxidation, reduction, or both took place in test tube 5?
Answers
Copper atoms (Cu) were created by reducing copper ions (Cu2+). An illustration of a reduction reaction is this. (Mg2+).To create Mg2+ ions, Mg atoms lost their electrons. An example of an oxidation reaction is this.
Oxidation and reduction occurred in test tube 5. Here is the equation for the reaction that took place:MgSO4 (aq) + Cu (s) CuSO4 (aq) + MgCuSO4's blue hue was neutralised to a solid copper hue. Copper atoms (Cu) were created by reducing copper ions (Cu2+). An illustration of a reduction reaction is this. Cu atoms are created when Cu2+ gains electrons. Due to the presence of magnesium ions (Mg2+), the solution was greenish-yellow.To create Mg2+ ions, Mg atoms lost their electrons. An example of an oxidation reaction is this. Two electrons were lost by the magnesium atom, leaving two electrons behind.
As a result, test tube 5 experienced both oxidation and reduction.It is possible to prove that oxidation, reduction, or both took place through the reaction's electron transfer and colour changes. A reduction reaction was seen when copper ions transformed into copper atoms. An oxidation reaction was evident when magnesium atoms transformed into magnesium ions.
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Forensics:
roshni, a forensic scientist, has ruled out several different drugs when testing a substance found in a car. She suspects that the substance is cocsine, what should roshni do next?
1-Perform a confirmatory test
2-Put the substance in a bag, label it, and send it to a DEA office
3-Confer with a colleague about her suspicions.
4-Collect a blood sample and see if it also contains the same substance
Answers
Since she suspects that the substance is cocsine, the thing that she should do next is option 1-Perform a confirmatory test.
How the Evidence Is Collected?The way that Drug evidence is collected is that from any crime scene, evidence is obtained, photographed, packaged, documented as well as been sent for analysis and then the forensic scientist will carry out the Analysis.
Since the evidence has been sent to Roshni, all she has to do is to carry out the confirmatory test to see if the drug is what she suspected.
Therefore, Since she suspects that the substance is cocsine, the thing that she should do next is option 1-Perform a confirmatory test.
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The solution you identified in question (1) acts as a buffer due to reactions that occur within the solution when an acid or a base is added. Write the net ionic chemical equation for the reaction that occurs within this buffer solution when HCl(aq) is added. (Phase labels should be included in all net ionic chemical equations.)
Answers
Answer:
The answer is "\(\bold{CH_3COO^{-} \ (aq) + H^{+}\ (aq) \longrightarrow CH_3COOH \ (aq)}\)"
Explanation:
When \(HCI\) is added in the chemical equation it reacts with sodium acetate so, it will give the following chemical equation:
\(CH_3COONa\ (aq) + HCl\ (aq)\longrightarrow CH_3COOH\ (aq) + NaCl\ (aq)\\\\\)
In this, the \(CH_3COOH\) is a weak acid so, it not completely dissociated.
\(CH_3COONa \ (aq) \ \ and \ NaCl\) were strong electrolytes they are completely dissociated.
The \(HCl\) is a strong acid so, it is completely dissociated So, the net ionic equation is:
\(CH_3COO^{-} \ (aq) + H^{+}\ (aq) \longrightarrow CH_3COOH \ (aq)\)
can you solve these?
Answers
Answer:
yes
Explanation:
it's easy
Select the correct answer.
What are factors of production?
OA.
О в.
O c.
OD.
all the human efforts involved in the production process
all the resources used to produce any goods and services
all the physical tools and equipment used in the production process
all the naturally occurring resources found in land, air, and water
Reset
N
Answers
Answer: B. all the resources used to produce any goods and services
Explanation:
The factors of production are all the resources used to produce any goods and services. This means our answer is option B.
This includes, but is not limited to, land, labor, capital, and entrepreneurship.
7. Calculate moles of H2 needed to form 2.25 moles HCl in the reaction H2 + Cl2==>2HCl
Answers
Answer:
1.125 moles
Explanation:
2mole of HCl produced 1mole of H2
2.25moles of HCl will produce x moles
cross multiply
2x=™1×2.25
x= 2.25÷2
x=1.125mole
A chemistry student needs of acetone for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the student discovers that the density of acetone is . Calculate the volume of acetone the student should pour out. Be sure your answer has the correct number of significant digits.
Answers
Answer:
The answer is "\(7.90 \ g\)".
Explanation:
Please finds the complete question in the attached file.
\(Volume = 10.0 \ mL \\\\Density =0.79 g\ cm^3\)
\(\text{Density}=\frac{Mass}{Volume}\)
\(Mass = Density \times Volume\)
\(=(0.790 g\ cm^3) \times 10.0 \ mL\\\\=7.90 \ g\)
The mass of acetone to be weighed is \(7.90 \ g\)
