i need help. ill mark brain to the first to answer.

Based on the information provided regarding same as cash loans, Chelsea won't be charged interest for the first 6 months of the loan, nor will she have to make payments for the first 6 months. (Option D)

A Same-As-Cash Loan refers to a short-term lending solution in which no interest or monthly payment are required to be paid during a set “Same-As-Cash” period. At the end of a predetermined period, the loan is paid off. Hence, the customer owes no interest or monthly payments during a set promotional period and pays the same amount on the loan as they would have paid up front with cash. These are interest deferred loans in which the loans interest still accrues during that promotional period, however if the customer pays off the entire principal balance before the period ends, they are not required to pay that interest. The advantage of these loans is that customers may spend the same amount they would have if they had paid with cash up front. Hence, if Chelsea opts for loan that offered 6 months, same as cash, there would be no requirement of payment or interest charged for the 6 months.

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Based on the above, the segments that are perpendicular to EF are LM and NP.

Note that when two lines are perpendicular, we can say that;

M1 * M2 = -1 As M1 and M2 are known to be the slopes of the lines.

Therefore, when the the slope of EF is said to be −5/2, then  one can say that the slope of  the segment that is said to be  perpendicular to EF will have to be equal to m1*m2=-1, m2=-1/m1, m2=-1/(-5/2) or m2=2/5.

Scenario one:

JK , if J is at (3, −2) and K is at (5, −7)

To find the slope JK, then

m=(y2-y1)/x2-x1)

m=(-7+2)/(5-3)

m=-5/2

-5/2 is not equal to 2/5

Therefore,  JK is not perpendicular to EF

Scenario 2

Find GH , when G is at (6, 7) and H is at (4, 12)

To find the slope GH

m=(y2-y1)/x2-x1)

m=(12-7)/(4-6)

m=5/-2

m=-5/2

Since -5/2 is not equal to 2/5 then GH is not perpendicular to EF

Scenario 3:

Find LM , If L is at (1, 9) and M is at (6, 11)

To find the slope LM, then

m=(y2-y1)/x2-x1)

m=(11-9)/(6-1)

m=2/5

Since 2/5 is equal to 2/5

Then LM is perpendicular to EF

Scenario 4:

Find NP , if N is at (−3, 4) and P is at (−8, 2)

To find the slope NP, then

m=(y2-y1)/x2-x1)

m=(2-4)/(-8+3)

m=-2/-5

m=2/5

Since 2/5 is equal to 2/5.

Therefore,  NP is perpendicular to EF

Based on the above calculations, the segments that are perpendicular to EF are LM and NP.

See correct format of question written below

The slope of EF is −5/2 .

Which segments are perpendicular to EF?

Select all the right answers please

1. JK , where J is at (3, −2) and K is at (5, −7)

2. GH , where G is at (6, 7) and H is at (4, 12)

3. LM , where L is at (1, 9) and M is at (6, 11)

4. NP , where N is at (−3, 4) and P is at (−8, 2)

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The line best illustrates the growth of a facultative anaerobe incubated aerobically is (b) on the graph.

Cells are the basic unit of life, and they carry out a variety of functions within an organism.

When a catalase-negative cell is exposed to hydrogen peroxide, the hydrogen peroxide will not be broken down into water and oxygen as quickly as it would be in a catalase-positive cell (i.e., a cell that does produce catalase).

This can have important implications for the survival of the cell, particularly under aerobic (i.e., oxygen-rich) conditions.

The figure may contain several lines or curves, each of which represents the change in concentration of hydrogen peroxide over time for a different type of cell.

One of these lines will correspond to the catalase-negative cell. Since this cell does not produce catalase, the rate at which hydrogen peroxide is broken down will be slower than in a catalase-positive cell.

Therefore, the line corresponding to the catalase-negative cell should show a slower decrease in hydrogen peroxide concentration over time than the line corresponding to a catalase-positive cell.

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Answer:

2.99924 in

Step-by-step explanation:

Volume of a cone

V = pi x r^2 x h/3

So to solve this problem you plug in the number we already have which is the volume and the height

103.62 = pi x r^2 x 11/3

28.26 = pi x r^2

28.26/pi = r^2

\(\sqrt{\frac{28.26}{\pi } }\) = r ≈ 2.99924

A statement which correctly compares the two functions on the given interval [-1, 2] is: C. Both functions are increasing, but function g increases at a faster average rate.

First of all, we would determine the values of function g(x) on the given interval [-1, 2] as follows:

g(x) = -18(⅓)^x + 2

At x = -1, we have:

g(-1) = -18(⅓)^(-1) + 2

g(-1) = -52.

At x = 0, we have:

g(0) = -18(⅓)^(0) + 2

g(0) = -16.

At x = 1, we have:

g(1) = -18(⅓)^(1) + 2

g(1) = -4.

At x = 2, we have:

g(2) = -18(⅓)^(0) + 2

g(2) = 0.

By critically observing the values of each functions, we can logically deduce that both functions are increasing but function g(x) increases at a faster average rate because it started with a lower value and ended with a higher value.

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Answer:

= 1.21577e19

Step-by-step explanation:

I used a calculator that should tell you. :))

A rectangle with a given base and height, its area is given by A = base x height. For a rectangle with a given perimeter, the maximum area is obtained when it is a square, i.e., all sides are equal.

The area of the rectangle is given by A = base x height. If one of the dimensions is fixed, the area is maximized when the other is maximized. In this case, the base is fixed and the area is to be maximized by finding the height that maximizes the area. For that, let the base of the rectangle be 'b', and its height be 'h'. Then the perimeter of the rectangle is given by 2b + 2h. As the base is fixed, we can write the perimeter in terms of height as 2b + 2h = P. Solving for h, we get h = (P - 2b)/2. Substituting the value of h in the area equation, we get A = b(P - 2b)/2. This is a quadratic equation in b, which can be solved by completing the square or differentiating. By differentiating the area equation with respect to b, and equating it to zero, we get b = P/4. Therefore, the largest area of the rectangle is obtained when it is a square, i.e., all sides are equal.

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Answer:

2

Step-by-step explanation:

2

Answer:

735.13268 units^2

Step-by-step explanation:

A=2πrh+2πr2=2·π·9·4+2·π·92≈735.13268

a. One possible curve C1 is a line segment from (0,0) to (π/2,0), given by r(t) = <t, 0>, 0 ≤ t ≤ π/2. One possible curve C2 is the line segment from (0,0) to (0,-14π), given by r(t) = <0, -14πt>, 0 ≤ t ≤ 1.

a) We have F = ∇f = <∂f/∂x, ∂f/∂y>.

So, F(x, y) = <cos(x-7y), -7cos(x-7y)>.

To find a curve C1 such that F · dr = 0, we need to solve the line integral:

∫C1 F · dr = 0

Using Green's Theorem, we have:

∫C1 F · dr = ∬R (∂Q/∂x - ∂P/∂y) dA

where P = cos(x-7y) and Q = -7cos(x-7y).

Taking partial derivatives:

∂Q/∂x = -7sin(x-7y) and ∂P/∂y = 7sin(x-7y)

So,

∫C1 F · dr = ∬R (-7sin(x-7y) - 7sin(x-7y)) dA = 0

This means that the curve C1 can be any curve that starts and ends at the same point, since the integral of F · dr over a closed curve is always zero.

One possible curve C1 is a line segment from (0,0) to (π/2,0), given by:

r(t) = <t, 0>, 0 ≤ t ≤ π/2.

b) To find a curve C2 such that F · dr = 1, we need to solve the line integral:

∫C2 F · dr = 1

Using Green's Theorem as before, we have:

∫C2 F · dr = ∬R (-7sin(x-7y) - 7sin(x-7y)) dA = -14π

So,

∫C2 F · dr = -14π

This means that the curve C2 must have a line integral of -14π. One possible curve C2 is the line segment from (0,0) to (0,-14π), given by:

r(t) = <0, -14πt>, 0 ≤ t ≤ 1.

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Margo is right; Jules made a 45 degree angle.

To determine who is right about the angle made by Jules while taking the first piece of pizza, we need to compare their estimates of 20 degrees and 45 degrees.

Since angles are measured using a protractor or other measuring tools, we rely on accurate measurement techniques to determine their values. If both Jules and Margo used appropriate measuring tools and techniques, we would expect their measurements to be close.

However, a 20-degree angle is significantly smaller than a 45-degree angle. Therefore, based on the provided information, Margo's estimate of a 45-degree angle seems more reasonable and likely to be correct.

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Answer:

1,678

Step-by-step explanation:

1030(1.05)^10 = 1677.76

Answer:

y=mx+b

Step-by-step explanation:

a. Rn = (6 / n) * [4(1 - 1/n)² + 4(1 + 1/n)² + ... + 4(5 - 3/n)²]

b. The exact area under the graph is 168.

A relation between a collection of inputs and outputs is known as a function. A function is, to put it simply, a relationship between inputs in which each input is connected to precisely one output.

A) To find a formula for Rn, we can use the midpoint rule. The midpoint rule approximates the area under a curve by dividing the interval into n equal subintervals and taking the height of the rectangle as the value of the function at the midpoint of each subinterval.

Let's calculate Rn for the function f(x) = (2x)² on the interval [−1, 5] using n subintervals.

The width of each subinterval is given by:

Δx = (b - a) / n = (5 - (-1)) / n = 6 / n

The midpoint of each subinterval is given by:

xi = a + (i - 1/2)Δx

Using these values, we can calculate Rn:

Rn = Δx * [f(x1) + f(x2) + ... + f(xn)]

   = (6 / n) * [(2(-1 + 1/2 * (6/n))²) + (2(-1 + 3/2 * (6/n))²) + ... + (2(5 - 1/2 * (6/n))²)]

Simplifying further:

Rn = (6 / n) * [4(1 - 1/n)² + 4(1 + 1/n)² + ... + 4(5 - 3/n)²]

B) To compute the area under the graph as a limit, we take the limit of Rn as n approaches infinity. This is equivalent to integrating the function over the interval [−1, 5].

To find the exact area under the graph of f(x) = (2x)² on [−1, 5], we integrate the function:

∫[−1, 5] (2x)² dx

Evaluating the integral:

∫[−1, 5] (2x)² dx = ∫[−1, 5] 4x² dx = [4/3 * x] from -1 to 5

                                  = (4/3 * 5³) - (4/3 * (-1)^3)

                                  = (4/3 * 125) - (4/3 * (-1))

                                  = (500/3) + (4/3)

                                  = 504/3

                                  = 168

Therefore, the exact area under the graph is 168.

As n approaches infinity, the value of Rn will approach the exact area of 168.

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The probability of finding 0 contaminated pieces in  225 g of chocolate is 5.57 X 10⁻⁷.

Here the number of contaminated fragments follows a Poisson process. Hence, let the distribution for the same be X.

Hence we get X ~ Poi(λt)

where λ is the mean no. of contaminated pieces and t is the no. of bars consumed.

For P(X = x) we get [(λt)ˣ  e^(-λt)]/x!

Here λ = 14.4 and t = 1 Hence we will get

P(X = x) = [(14.4)ˣ e⁻¹⁴°⁴]/x!

Here we need to find the probability of the no. of contaminated pieces = 0

Therefore

P(X = 0) = [(14.4)⁰ e⁻¹⁴°⁴]/0!

Hence the probability of finding 0 contaminated pieces in a bar of chocolate is

P(X = 0) =  e⁻¹⁴°⁴

= 5.57 X 10⁻⁷

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If W = 60,

60 / 6 + 4 = 14

14 is not equal to 5

so 60 is not a solution

The optimal values of these parameters are:

a. β₁ = 0

b. β₂ = 0

The linear regression y = β1 + β2x + e, assuming that the sum of squared errors (SSE) takes the following form:

SSE = 382 + 681 + 382 + 18β1β2

Derive the partial derivatives of SSE with respect to β1 and β2 and solve the optimal values of these parameters.

Given that SSE = 382 + 681 + 382 + 18β1β2 ∂SSE/∂β1 = 0 ∂SSE/∂β2 = 0

Now, we need to find the partial derivative of SSE with respect to β1.

∂SSE/∂β1 = 0 + 0 + 0 + 18β2 ⇒ 18β2 = 0 ⇒ β2 = 0

Therefore, we obtain the optimal value of β2 as 0.

Now, we need to find the partial derivative of SSE with respect to β2. ∂SSE/∂β2 = 0 + 0 + 0 + 18β1 ⇒ 18β1 = 0 ⇒ β1 = 0

Therefore, we obtain the optimal value of β1 as 0. Hence, the partial derivative of SSE with respect to β1 is 18β2 and the partial derivative of SSE with respect to β2 is 18β1.

Thus, the optimal values of β1 and β2 are 0 and 0, respectively.

Therefore, the answers are: a. β₁ = 0 b. β₂ = 0

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Answer:

105% of 400 is 420, the percent is 42000%

Step-by-step explanation:

Answer:

The last one

Step-by-step explanation:

The more weight something has the faster it will fall

If there are 5 finalists at a singing competition, in 120 ways they can be ordered, if they each take turns singing by applying basic counting principles.

There are 5 finalists at a singing competition and each of them takes turns singing.

We can calculate the number of ways the 5 finalists can take up turn by applying basic counting principles.

Therefore, they can be ordered in n factorial ways, that is n !, where n is the number of finalists who take turns to sing.

Thus, number of ways the finalists can be ordered is = 5!

= 5*4*3*2*1 ( ways )

= 120 ways

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The following are the zeros for the function h (x) = x2 + 3x - 8: - x= -4 and x=2.

Given a collection of inputs X (domain) and a set of potential outputs Y (codomain), a function is more technically defined as a set of ordered pairings (x,y) where xX and yY with the caveat that there can only be one ordered pair with the same value of x. The function notation f:XY can be used to express that f is a function from X to Y.

The function's zero is a value of x that makes it equal to zero. In other words, the equation f(x) = 0 leads to a zero.

By putting h(x) equal to zero and figuring out x, we may determine the zeroes for the function h(x) = x2 + 3x - 8.

h(x) = x² + 3x - 8 = 0

We may factor the left side of the equation to find x:

x² + 3x - 8 = (x-2)(x+4) = 0

We set each factor to zero and solve for x to discover the zeroes:

x-2 = 0 or x+4 = 0

x = 2 or x = -4

Consequently, the function's zeros are x = 2 and x = -4.

So, A is the right response. x = -4 and x = 2

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The complete question is

What are the zeros of the function h (x) = x² + 3x - 8?

A. x = -4 and x = -2

B. x= -8 and x = 2

C. x = -2 and x = 8

D. x = 2 and x = 8

answer:

$9.50 = 125% * (last years hourly wage)

$9.50 = 1.25*X

9.50/1.25 = X

$7.60 = X

she earned $7.60 per hour last year!

The value of m for the given equation is 18. The solution has been obtained by solving the linear equation.

What is a linear equation?

A linear equation is the one with the highest degree of one. This demonstrates that there are no variables in a linear equation with an exponent bigger than one. On the graph, such an equation yields a straight line.

We are given an equation as 2 = m/2 - 7

On solving the equation for m, we get

⇒2 = m/2 - 7

⇒2 = (m - 14)/2

⇒2*2 = (m - 14)

⇒4 = m - 14

⇒m = 18

Hence, the value of m for the given equation is 18.

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Answer: Add 5 to x and y for each point.

Step-by-step explanation:

Add 5 to x and y for each point.

(-4,-1) becomes (1, 4), (-1,-4) becomes (4,1) . . . etc.

The sum of the measures of the interior angles of a convex dodecagon is 1800 degrees.

We have,

A convex dodecagon has 12 sides.

To find the sum of the measures of its interior angles, we can use the formula:

Sum of interior angles = (n - 2) x 180 degrees

where n is the number of sides.

For a convex dodecagon (n = 12), the sum of the interior angles is:

Sum = (12 - 2) x 180 = 10 x 180 = 1800 degrees

Therefore,

The sum of the measures of the interior angles of a convex dodecagon is 1800 degrees.

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Answer:

-25.00% decrease, quite a deal

Answer:

Step-by-step explanation:

$28 = 100%

$7 = 25%

$21 = 75%

so, therefore

% change = 100% - 75%

= 25%

Answer:

-17/12

Step-by-step explanation:

It’s simple math man

True, the Greek letter used to represent the probability of a Type I error is alpha (α).

In hypothesis testing, a Type I error occurs when the null hypothesis is rejected even though it is true. The alpha level, also known as the significance level, is a pre-determined threshold that indicates the probability of making such an error. By setting an appropriate alpha level, researchers can control the risk of incorrectly rejecting the null hypothesis.

Typical alpha levels used in research are 0.05 or 0.01, indicating a 5% or 1% chance of making a Type I error, respectively. It is crucial to consider the consequences of Type I errors when choosing an alpha level, as it affects the overall reliability and validity of the study.

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Answer:

126 blue marbles, 24 white marbles

Step-by-step explanation:

The ratio of blue marbles to white marbles is 21 to 4. From this, we have this equation:

\(21x + 4x = 150\)

\(25x = 150\)

\(x = 6\)

So we have 21 × 6 = 126 blue marbles and 4 × 6 = 24 blue marbles.

126/24 = 21/4

T3(x) = x - x^2/2 + x^3/6.

The Taylor polynomial of degree 3 for the function f(x) = x + e^-x centered at a = 0 is given by:

T3(x) = f(0) + f'(0)x + (f''(0)/2!)x^2 + (f'''(0)/3!)x^3

= 1 + (-1 + 1)x + (e^-0 - (-1)(-1)e^-0)x^2/2! + (0 + (-1)(-1)(-1)e^-0)x^3/3!

= x - x^2/2 + x^3/6

So T3(x) = x - x^2/2 + x^3/6.

An infinite sum of words that are expressed in terms of a function's derivatives at a single point is known as the Taylor series or Taylor expansion of a function in mathematics.

The nth Taylor polynomial of the function is a polynomial of degree n that is created by the partial sum of the first n + 1 terms of a Taylor series. Approximations of a function made by Taylor polynomials get generally better as n rises. Quantitative estimates of the mistake brought about by the use of such approximations are provided by Taylor's theorem. If a function's Taylor series is converging, its total is the upper bound of the Taylor polynomials' infinite sequence. A function's Taylor series sum may not match.

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