Answer:
What is the car's rate in kilometers per minute?
\(0.9\frac{km}{min}\)
How many kilometers will the car travel in 5 minutes?
\(4.5\ km\)
Step-by-step explanation:
If we know:
\(\frac{54\ km}{1\ hour}\)
And there are 60 minutes in an hour:
\(\frac{1\ hour}{60\ minutes}\)
We can do:
\(\frac{54\ km}{1\ hour} * \frac{1\ hour}{60\ minutes} = \frac{54\ km}{60\ minutes} = 0.9 \frac{km}{min}\)
From here, we figure out the distance from minutes:
\(0.9\frac{km}{min} * 5 = 4.5\ km\)
5. The scale on the map of a park is 5 in.: 3 mi. The distance from the entrance of the park to the playground is 9 miles. How many inches long is the distance on the map?
Answer:
15 inches
Step-by-step explanation:
Here, we have a scale of 5 inches to 3 miles
We have 9 miles here, we now want to get the amount of corresponding inches
Let the corresponding inches be x
5 inches to 3 miles
x inches to 9 miles
That means ;
x * 3 = 5.* 9
x = 45/3
x = 15 inches
Find the values of x and y.
Answer: y=37.5degrees and x=110degrees
Step-by-step explanation: sum of angle in a quadrilateral =360 and opposite angles=180. 115+2y=180,2y=180-115=75. 2y/2=75/2. therefore y=37.5. while x=70+x=180,x=180-70=110. x=110
Find the scalar and vector projections of b onto a.
a=⟨−5, 12⟩, b=⟨4, 6⟩
The scalar projection is 42/13, and the vector projection is 42/169⟨-5,12⟩.
The scalar projection of b onto a can be calculated using the formula \(\frac{a.b}{|a|}\), and the vector projection of b onto a can be calculated using the formula \(\frac{a.b}{|a|^{2} } .a\). The formula for finding the magnitude of a is |a| = √c²+d² if a = ⟨c,d⟩.
a = ⟨−5, 12⟩, b = ⟨4, 6⟩
a⋅b = ⟨−5, 12⟩⟨4, 6⟩
= -20 + 72
= 42
|a| = √[(-5)² + (12)²]
= √25 + 144
= √169
= 13
The scalar projection is
\(\frac{a.b}{|a|}\) = [⟨−5, 12⟩⟨4, 6⟩]/√[(-5)² + (12)²]
= [-20 + 72]/√25 + 144
= 42/√169
= 42/13
The vector projection is
\(\frac{a.b}{|a|^{2} } .a\) = [42/(13)²] ⟨−5, 12⟩
= 42/169⟨−5, 12⟩
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I keep getting this wrong. Which property is not used to simplify the following expression?
Answer:
Commutative Property of Addition
Step-by-step explanation:
if you have a o(log n) algorithm running, what happens when you double the size of your problem?
When you double the size of the problem, the runtime of the algorithm increases by a constant factor. Specifically, it increases by a factor of log(2) = 1. Since the algorithm's time complexity is logarithmic, it means that the runtime increases slowly as the problem size grows.
To understand this, let's consider an example. Suppose you have an algorithm that can find an element in a sorted list of n elements in O(log n) time. If the list contains 100 elements, the algorithm will take at most log(100) = 2 steps to find the element. If you double the size of the list to 200 elements, the algorithm will take at most log(200) = 2.3 steps to find the element. This is only a small increase in runtime, and the algorithm is still very efficient. This property of logarithmic time complexity makes algorithms that use it very valuable in many fields, especially in large-scale data processing and search applications, where the data size can be very large. Because of their efficiency, these algorithms can handle very large datasets in a reasonable amount of time, making them highly sought after in many industries. Since the algorithm's time complexity is logarithmic, it means that the runtime increases slowly as the problem size grows.
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a firm's total revenue is calculated as times quantity produced
Total revenue is calculated by multiplying the price per unit by the quantity produced and sold. This calculation provides valuable insights into a firm's sales performance and helps in assessing the financial health of the business.
A firm's total revenue is calculated by multiplying the quantity produced by the price at which each unit is sold. To calculate the total revenue, you can use the following equation:
Total Revenue = Price × Quantity Produced
where Price represents the price per unit and Quantity Produced represents the total number of units produced and sold.
For example, let's say a company sells a product at a price of $10 per unit and produces 100 units. The total revenue can be calculated as:
Total Revenue = $10 × 100 units
Total Revenue = $1,000
So, the firm's total revenue in this case would be $1,000.
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Total revenue is an important metric for businesses as it indicates the overall sales generated from the production and sale of goods or services. By calculating the total revenue, companies can evaluate the effectiveness of their pricing strategies and determine the impact of changes in quantity produced or price per unit on their overall revenue.
It is essential for businesses to monitor and analyze their total revenue to make informed decisions about production levels, pricing, and sales strategies.
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the questionnaire is a carefully constructed measurement instrument. group of answer choices true false
Yes, its true that the questionnaire is very carefully constructed by an individual to provide the measurement instrument.
A questionnaire is a studies device which includes a sequence of questions for the motive of amassing facts from respondents. Questionnaires may be concept of as a form of written interview. A questionnaire is a listing of questions or gadgets used to collect facts from respondents approximately their attitudes, experiences, or opinions.
Questionnaires may be used to acquire quantitative and/or qualitative facts. Questionnaires are generally utilized in marketplace studies in addition to withinside the social and fitness sciences. Questionnaires are typically taken into consideration to be excessive in reliability. This is due to the fact it's miles feasible to invite a uniform set of questions. Any troubles withinside the layout of the survey may be ironed out after a pilot study. The greater closed questions used, the greater dependable the studies.
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Find the volume of a cone with a height of 12m and a base diameter of 10m. Use the value 3.14 for π, and do not do any rounding. Be sure to include the correct unit in your answer.
314
Yes Yes Pog Pog Pog Pog Pog Pog
2. Suppose A is a n x n matrix. Write a matlab code to find: (a) sum of diagonal elements (b) product of diagonal elements (c) Execute the sum and product when A= ones (5)
it displays the computed sum and product of the diagonal elements.
Here's a MATLAB code to find the sum and product of the diagonal elements of a given matrix `A`, as well as an example execution for `A = ones(5)`:
```matlab
% Define the matrix A
A = ones(5);
% Get the size of the matrix
[n, ~] = size(A);
% Initialize variables for sum and product
diagonal_sum = 0;
diagonal_product = 1;
% Calculate the sum and product of diagonal elements
for i = 1:n
diagonal_sum = diagonal_sum + A(i, i);
diagonal_product = diagonal_product * A(i, i);
end
% Display the results
disp("Sum of diagonal elements: " + diagonal_sum);
disp("Product of diagonal elements: " + diagonal_product);
```
Example execution for `A = ones(5)`:
```
Sum of diagonal elements: 5
Product of diagonal elements: 1
```
In this example, `A = ones(5)` creates a 5x5 matrix filled with ones. The code then iterates over the diagonal elements (i.e., elements where the row index equals the column index) and accumulates the sum and product. Finally, it displays the computed sum and product of the diagonal elements.
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WILL MARK BRAINIEST!!! 25 POINTS!!! The following box plot shows points awarded to dance teams that competed at a recent competition: Which dot plot best represents the box plot data?
Answer:
The correct option is the second option.
How to make a Box-and-whisker plot:
organize your data points from least to greatest.find the median (middle number), as this will also be our second quartile (we have four in total.)find the first and third quartiles by finding the median of both the lower and upper halves made from the numbers left over from your previous median.draw a plot line and mark your quartiles with vertical lines and box them in.mark your outliers, the smallest and largest numbers with dots and connect them to your box.Solution explanation:
if you apply the rules of the boxplot above with both choices, the second lines up perfectly.
Please answer now correct answer fast
Answer:
\( Area = 112.1 m^2 \)
Step-by-step Explanation:
Given:
∆WXY
m < X = 130°
WY = x = 31 mm
m < Y = 26°
Required:
Area of ∆WXY
Solution:
Find the length of XY using Law of Sines
\( \frac{w}{sin(W)} = \frac{x}{sin(X)} \)
X = 130°
x = WY = 31 mm
W = 180 - (130 + 26) = 24°
w = XY = ?
\( \frac{w}{sin(24)} = \frac{31}{sin(130)} \)
Multiply both sides by sin(24) to solve for x
\( \frac{w}{sin(24)}*sin(24) = \frac{31}{sin(130)}*sin(24) \)
\( w = \frac{31*sin(24)}{sin(130)} \)
\( w = 16.5 mm \) (approximated)
\( XY = w = 16.5 mm \)
Find the area of ∆WXY
\( area = \frac{1}{2}*w*x*sin(Y) \)
\( = \frac{1}{2}*16.5*31*sin(26) \)
\( = \frac{16.5*31*sin(26)}{2} \)
\( Area = 112.1 m^2 \) (to nearest tenth).
A babysitting service charges $10 for the first hour and $12 for each additional hour. The babysitting service charged $58 for a recent babysitting job. Create an equation to represent this situation and define the variable used. Solve your equation, showing all steps used. Show that the solution is correct. Explain what the solution to your equation represents in the context of the given situation.
Answer: 10+12x=58
Step-by-step explanation:
The equation would be 10+12x=58, where x is the amount of additional hours babysitting besides the first hour.
To solve: move terms to one side (subtract 10) so you'd get 12x=48
The answer to this equation would be x=4 (you divide by 12)
To check if correct: plug in 4, to get 10+12(4)=58 which is 10+48=58 which gets 58=58
So the time worked was a total of 5 hours since you have to add on the first hour, but the solution to your equation represents just the amount of additional hours worked besides the first hour.
11. How many combinations of four can you make from the set?
25 baseball cards
Put your answer in the form [XXXXX]. Please do not insert a comma.
Water flows downhill through a 2.28-in.-diameter steel pipe. The slope of the hill is such that for each mile (5280 ft) of horizontal distance, the change in elevation is Δz. Determine the maximum value of Δz if the flow is to remain laminar and the pressure all along the pipe is constant.
Please solve for delta z. And please show each step. I keep getting wrong answers. Please do not copy current examples on chegg as well. Those examples are incorrect.
The maximum value of Δz for the flow to remain laminar and the pressure to remain constant, we can use the Hagen-Poiseuille equation and the pressure gradient equation for a vertical pipe.
Given:
Diameter of the pipe (D) = 2.28 in.
Horizontal distance (L) = 1 mile
= 5280 ft
We need to find the maximum value of Δz.
The Hagen-Poiseuille equation for laminar flow through a circular pipe is:
Q = (π * D^4 * ΔP) / (128 * μ * L),
where Q is the volumetric flow rate, ΔP is the pressure drop along the pipe, μ is the dynamic viscosity of the fluid, and L is the length of the pipe.
Since the pressure is constant along the pipe, ΔP = 0, and the equation simplifies to:
Q = (π * D^4 * 0) / (128 * μ * L),
Q = 0.
For laminar flow, the flow rate (Q) must be non-zero, so we can conclude that the flow must stop.
In other words, for the flow to remain laminar and the pressure to remain constant, the change in elevation (Δz) should not exceed the point where the flow stops. Therefore, there is no maximum value of Δz that satisfies the given conditions.
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If you spun the spinner 1 time, what is the probability
it would land on a gray piece?
Answer:
3/8
Step-by-step explanation:
There are 4 black sections, 3 gray sections, and 1 white section.
This means that there are 8 in total.
3/8 of the squares are gray so that would be the answer.
express the following linear equation in the form of ax+by+c=0 and indicate the value of a,b and c. 2x+3y=-5
Answer:
2x+3y+5=0
a = 2 b = 3 c=5
Step-by-step explanation:
We are asked to express 2x+3y=-5 in the form ax+by+c=0
Add 5 to both sides
2x+3y+5=0
We can now find the values of a, b and c now that the equation is in standard form.
Five movie tickets cost 40 bucks how much is eight movie tickets
Answer:
64
Step-by-step explanation:
40/8 = 8
8*8
Answer:
$64
Step-by-step explanation:
form a ratio:
5:40
simplify:
1:8
so now desimplify
8:64
Convert the equation
2y + 4x = 10 to y = mx + b form
Show your steps.
I’ll mark as brainiest
Answer:
y=-2x+5
Step-by-step explanation:
Answer:
y=-2x+5
Step-by-step explanation:
First, subtract 4x from both sides. You will get 2y=-4x+10. Then divide both sides by 2 to isolate the y. You will get y=-2x+5.
Pls help me with these two..:)
Answer:
Five: 40
Six 8000 - (-50)
Step-by-step explanation:
Five
22 - (-18)
22 + 18
40
Six
She has to look down below sea level. Getting to sea level is 8000 feet. That usually is taken to be the positive direction.
It's the 50 feet that's the problem. The whale isn't floating above her. It is 50 feet below sea level. Worse yet, it is a negative number. Though it goes entirely, against your intuition, it has to be written as
8000 - (-50)
8000 + 50
8050
please help me .......
Answer:
A
Step-by-step explanation:
GH
is dilated by a scale factor of 44 to form \overline{G'H'}
G
′
H
′
. \,\overline{G'H'}
G
′
H
′
measures 5656. What is the measure of \overline{GH}
GH
?
The measure of the pre-image, line segment GH according to the task content is; 14.
What is the measure of the line segment GH?According to the task content as described;
It follows that the pre-image in discuss is segment GH and the image is line segment; G'H'.
On this note, since it follows that the image is as a result of the dilation of the pre-image by a scale factor of 4, we can conclude that the image is 4 times greater than the pre-image.
Hence, the measure of line segment; GH according to the task content is; 56/4 = 14.
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We have a data set with 80 observations. If we use this data set to perform a 10-fold cross validation, how many observations are used for training at each iteration? A. 64 B. 72 C. 8 D. 16
At each iteration of a 10-fold cross-validation with a data set of 80 observations, 72 observations are used for training.
In a k-fold cross-validation, the data set is divided into k subsets or folds. Each fold is used as a validation set, and the remaining folds are used for training. The process is repeated k times, with each fold serving as the validation set once.
Given:
Number of observations in the data set = 80
Number of folds in cross-validation (k) = 10
To determine the number of observations used for training at each iteration, we need to calculate the size of each fold.
Number of observations in each fold = Total number of observations / Number of folds
Number of observations in each fold = 80 / 10
Number of observations in each fold = 8
Therefore, at each iteration of the 10-fold cross-validation, 8 observations are used for training.
However, we want to know the total number of observations used for training, so we need to multiply the number of observations in each fold by the number of folds minus one.
Total number of observations used for training = Number of observations in each fold * (Number of folds - 1)
Total number of observations used for training = 8 * (10 - 1)
Total number of observations used for training = 8 * 9
Total number of observations used for training = 72
In a 10-fold cross-validation with a data set of 80 observations, 72 observations are used for training at each iteration.
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Algebra 2, please help...brianliest given
Answer:
C
Step-by-step explanation:
Got it right
true or false: the quantity represented by θ is a function of time (i.e., is not constant).
Answer: the answer to this is true
Please answer :) much appreciated
There are 1,000 balls in a container. All of the balls are the same size and shape. In the container, there are • 400 red balls; • 250 orange balls; • 100 green balls; and • 250 yellow balls. A student will pick one ball at random from the container. What are the probabilities that the student will pick a ball that is either red, orange, or green? Write the three different ways to represent this probability.
Answer:
I'm guessing you mean fraction decimal and percentage
The final answer is:
3/4
0.75
75%
Step-by-step explanation:
You have to add 400 + 250 + 100 and then you will get 750. Then you make 750 into a fraction, decimal, and percentage
Can I have brainliest? It would help me out, if not thanks anyways! Hope this helped and have a nice day!
The probability that the student will pick a ball that is either red, orange, or green is 0.75
What is Probability?The probability that an event will occur is measured by the ratio of favorable examples to the total number of situations possible
Probability = number of desirable outcomes / total number of possible outcomes
The value of probability lies between 0 and 1
Given data ,
Let the probability that the student will pick a ball that is either red, orange, or green be P
Now , the total number of balls in the container = 1000 balls
And , probability that the student will pick a ball that is either red, orange, or green can be calculated as the sum of the probabilities of picking a red ball, an orange ball, or a green ball. That is,
P(Red or Orange or Green) = P(Red) + P(Orange) + P(Green)
The probability of picking a red ball is 400/1000 = 0.4
The probability of picking an orange ball is 250/1000 = 0.25
And the probability of picking a green ball is 100/1000 = 0.1.
Therefore , P (Red or Orange or Green) = 0.4 + 0.25 + 0.1 = 0.75
Hence , the probability is 0.75
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Based on historical data, your manager believes that 44% of the company's orders come from first-time customers. A random sample of 137 orders will be used to estimate the proportion of first-time-customers. What is the probability that the sample proportion is between 0.25 and 0.4? (Enter your answer as a number accurate to 4 decimal places.)
The probability of the sample proportion being between 0.25 and 0.4 is approximately 0.2496
To calculate the probability that the sample proportion is between 0.25 and 0.4, we can use the sampling distribution of the sample proportion. Given that the manager believes 44% of orders come from first-time customers, we can assume this to be the true population proportion.
The sampling distribution of the sample proportion follows a normal distribution when the sample size is large enough. We can use the formula for the standard deviation of the sample proportion, which is sqrt((p*(1-p))/n), where p is the population proportion and n is the sample size.
In this case, p = 0.44 (proportion of first-time customers according to the manager) and n = 137 (sample size).
Using the standard deviation formula, we get sqrt((0.44*(1-0.44))/137) ≈ 0.0455.
Next, we can standardize the values 0.25 and 0.4 using the formula z = (x - p) / sqrt((p*(1-p))/n), where x is the sample proportion.
For 0.25:
z1 = (0.25 - 0.44) / 0.0455 ≈ -4.1758
For 0.4:
z2 = (0.4 - 0.44) / 0.0455 ≈ -0.8791
Now, we can find the probability that the sample proportion is between 0.25 and 0.4 by calculating the area under the normal curve between the corresponding z-scores.
Using a standard normal distribution table or a calculator, we can find the probabilities associated with the z-scores. The probability of the sample proportion being between 0.25 and 0.4 is approximately 0.2496.
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which explains how to find the radius of a circle whose equation is in the gorm x^2+y^2=z
if you could show us the picture then maybe i can help you
the probability that a student prefers lifting weights to doing aerobic exercise is .21. what is the probability that of two students randomly chosen, at least one prefers weights?
Answer: The probability that of two students randomly chosen, at least one prefers lifting weights is 0.3949.
Explanation :Let A be the event that the first student prefers lifting weights and B be the event that the second student prefers lifting weights. We need to find P(A ∪ B).P(A) = probability that the first student prefers lifting weights = 0.21P(B) = probability that the second student prefers lifting weights = 0.21P(A ∩ B) = probability that both students prefer lifting weights P(A ∪ B) = P(A) + P(B) - P(A ∩ B)We have :P(A ∩ B) = P(A) × P(B) = 0.21 × 0.21 = 0.0441P(A ∪ B) = 0.21 + 0.21 - 0.0441 = 0.3659The probability that neither student prefers lifting weights is 1 - P(A ∪ B) = 1 - 0.3659 = 0.6341So, the probability that of two students randomly chosen, at least one prefers lifting weights is 0.3949.
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The following scenario applies to questions 3-5: The weights of all of the Utah County Fair pigs have an unknown mean and known standard deviation of g = 18. A simple random sample of 100 pigs found to have a sample mean weight of x = 195. Question 3 3. Calculate a 95% confidence interval for the mean weight of all Utah County Fair pigs. (195, 200) (193, 204) (191, 199) (177, 213) Question 4 4. Suppose a sample of 200 was taken instead of 100. How will the margin of error change? the margin of error will increase in size the margin of error will decrease in size the margin of error will not change in size Question 5 5. If the researcher wanted to have 90% confidence in the results with a margin of error of 6.8, how many pigs must be sampled? 38 19 10 5
Answer:
5
Step-by-step explanation:
To calculate a 95% confidence interval for the mean weight of all Utah County Fair pigs, we use the formula:
Confidence Interval = Sample Mean ± Margin of Error
Given:
Sample Mean (x) = 195
Standard Deviation (σ) = 18
Sample Size (n) = 100
The margin of error can be calculated using the formula:
Margin of Error = (Z * σ) / √n
For a 95% confidence level, the Z-value for a two-tailed test is approximately 1.96.
Margin of Error = (1.96 * 18) / √100
= 3.528
Therefore, the confidence interval is:
(195 - 3.528, 195 + 3.528)
(191.472, 198.528)
The correct answer is (191, 199).
Question 4: If the sample size is increased from 100 to 200, the margin of error will decrease in size. The margin of error is inversely proportional to the square root of the sample size. As the sample size increases, the margin of error becomes smaller, resulting in a more precise estimate.
Question 5: To find out how many pigs must be sampled to have 90% confidence in the results with a margin of error of 6.8, we can use the formula:
Sample Size (n) = (Z^2 * σ^2) / E^2
Given:
Confidence Level (1 - α) = 90% (or 0.9)
Margin of Error (E) = 6.8
Standard Deviation (σ) = 18
For a 90% confidence level, the Z-value for a two-tailed test is approximately 1.645.
Sample Size (n) = (1.645^2 * 18^2) / 6.8^2
= 3.379
Therefore, the minimum number of pigs that must be sampled is approximately 4 (rounded up to the nearest whole number).
The correct answer is 5.