I will mark you brainlist! Use your own word

What is the weathering, erosion, and deposition?

Answers

Answer 1

Weathering is the breaking down or dissolving of rocks and minerals on Earths surface.

Erosion is the process by which the surface of the Earth gets worn down. Erosion can be caused by natural elements such as wind and glacial ice

Deposition is the dropping of sediment by wind, water, ice, or gravity.

Answer 2

Answer:

Weathering: refers to the process of breaking down and disintegrating rocks, minerals, soils, as well as several other materials.

Erosion: refers to the process of wearing down the surface of the earth due to glacial ice, wind and other natural elements.

Deposition: refers to the geological process, of sediments and soil, added to landforms due to wind, ice and other natural elements to build up layers od sediments.

Explanation:


Related Questions

HELP right awayyy !!!

HELP right awayyy !!!

Answers

Answer:

Question 4 is actually Acceleration

4 is actually acceleration

Is frictional force the only example of non-conservative force?​

Answers

Answer: NO, there are many examples of non-conservative forces.

Explanation: Conservatives forces are special forces whose work is zero in a closed path.

Magnetic and Electric fields are Non- Conservative.

help on this asap please

help on this asap please

Answers

Answer:

I think A is correct.

Explanation:

If it's not I'm sorry probably my fault but I hope this helps:)

In proton beam therapy, a beam of high-energy protons is used to kill cancerous cells in a tumor. In one system, the beam, which consists of protons with an energy of 2.8×10−11J, has a current of 80 nA. The protons in the beam mostly come to rest within the tumor. The radiologist has ordered a total dose corresponding to 3.6×10−3J of energy to be deposited in the tumor. How long should the beam be in order to deliver the required dose?

Answers

The number of protons that strike the tumor each second is \(1.7*10^8\) protons.

What is proton beam therapy?

Since it do not produce proper outcomes, proton beam therapy is only appropriate for certain types of cancer, such as highly complex brain, head and neck cancers, and sarcomas.

Here, it is mentioned that

Energy of proton = \(2.8*10^{-11}\) Joules.

Current = 84 nA = \(84*10^{-9}\) Ampere.

As well as

Energy of total dose = \(3.4*10^{-3}\)

The quantity of charge per unit time is mentioned as:

Q = It = Ne

Number of proton (N) = Q/e

\(N=\frac{2.8*10^{-11}}{1.602*10^{-19}}\)

\(N=1.75*10^8\)

Thus, this is the number of proton in the given scenario.

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PLS HELP!! This question was never fully solved!

An object moving at 13 m/s has a kinetic energy of 426 J. What is the mass of the object?
1.26 kg
2.52 kg
5.04 kg
65.5 kg

Answers

To find the mass of the object, we can use the formula for kinetic energy:

Kinetic energy (KE) = (1/2) * mass * velocity^2

Given that the kinetic energy is 426 J and the velocity is 13 m/s, we can rearrange the equation to solve for the mass:

mass = (2 * KE) / (velocity^2)

Substituting the given values:

mass = (2 * 426 J) / (13 m/s)^2

mass = (2 * 426 J) / (169 m^2/s^2)

mass = 852 J / 169 m^2/s^2

mass = 5.04 kg

Therefore, the mass of the object is 5.04 kg.

Galileo was the first scientist to do which of the following?

Answers

Galileo Galilei was an Italian physicist, mathematician, astronomer, and philosopher who made significant contributions to the scientific revolution during the Renaissance. He is often referred to as the "father of modern observational astronomy" and the "father of modern science."

Galileo made a number of important discoveries and contributions to science. Some of his most significant contributions include:

1- The law of falling bodies: Galileo is credited with developing the concept of free-fall and the mathematical relationship between distance and time for objects in free-fall. He conducted a series of experiments in which he dropped objects of different masses from the Leaning Tower of Pisa to demonstrate that all objects fall at the same rate in a vacuum, regardless of their mass.

2- The telescope: Galileo is credited with building the first practical telescope, which he used to observe the heavens and make a number of important discoveries. He observed the phases of Venus, the lunar surface, and the Galilean moons of Jupiter, among other things.

3- The laws of motion: Galileo is credited with developing the concept of inertia and the laws of motion that later formed the basis of classical mechanics. He also developed the concept of momentum and introduced the idea of a mathematical relationship between force, mass, and acceleration.

4- The scientific method: Galileo is credited with pioneering the scientific method, which involves making observations, developing hypotheses, testing hypotheses through experiments, and drawing conclusions based on the results. This approach to science is still used today and is fundamental to the scientific process.

21) A charged polyester ball is placed over a charged PVC pipe. The ball, which
has a mass of 1.2 grams, rests 42 cm above the pipe. If the ball and pipe have
the same negative charge, what is the charge on the ball?

21) A charged polyester ball is placed over a charged PVC pipe. The ball, whichhas a mass of 1.2 grams,

Answers

The negative charge on the polyester ball is -1.53 x 10⁻⁶ C.

The given parameters;

mass of the ball, m = 1.2 gdistance between the ball and the pipe = 42 cm = 0.42 m

The gravitational force on the ball is calculated as follows;

F = mg

F = 0.012 x 9.8

F = 0.12 N

The electrostatic force on the ball is calculated as follows;

\(F= \frac{kq^2}{r^2} \\\\q^2 = \frac{Fr^2}{k} \\\\q = \sqrt{\frac{0.12 \times (0.42)^2}{9\times 10^9}} \\\\q =+/ -\ \ 1.53 \times 10^{-6} \ C\\\\q =-\ \ 1.53 \times 10^{-6} \ C\)

Thus, the negative charge on the polyester ball is -1.53 x 10⁻⁶ C.

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A box with a mass of 0.5 slugs lies on an inclined plane making an angle of 30o with the horizontal. If the coefficient of kinetic friction between the box and the plane is 0.4, what is the magnitude of the force that must be applied parallel to the incline to keep the box moving down the incline at a constant speed

Answers

Answer: 10.98 N

Explanation:

Given

mass of box is \(m=0.5\ slugs\approx 7.3\ kg\)

The coefficient of kinetic friction is \(\mu= 0.4\)

It is given that on the application of force box started moving with constant speed i.e. there is no net external force

\(\Rightarrow F+mg\sin 30^{\circ}=\mu mg\cos 30^{\circ}\\\Rightarrow F=mg(\mu \cos 30^{\circ}-\sin 30^{\circ})\\\Rightarrow F=7.3\times 9.8(0.866\times0 .4-0.5)=-10.98\ N\\\)

The negative sign indicates direction of force is opposite i.e. it must be applied upwards

When Jim lifts a (previously stationary) bowling ball using a constant 72 N (↑) Force, it rises 1.0 m in 3.0 s.

a) compute the ball’s acceleration.

Answers

Explanation:

By using the formula :

\(s = ut + \frac{1}{2} at {}^{2} \)

where;

S = distance

u = initial velocity

t = time taken

a = acceleration

Plug in all the information we have,

\(1 = 0 + \frac{1}{2} a(3) {}^{2} \)

therefore :

\(a = \frac{2}{9} ms {}^{ - 2} \)

can someone give me a 5 day fitness plan with all the reps and sets for 3 only and 4 exercises a day

Answers

Answer:

Classic 5 Day Split

Day 1 – Chest

Day 2 – Legs

Day 3 – Rest

Day 4 – Back

Day 5 – Arms

Day 6 – Shoulders

Day 7 – Rest  

Upper Lower Push Pull Legs

Day 1 – Upper

Day 2 – Lower

Day 3 – Rest

Day 4 – Push

Day 5 – Pull

Day 6 – Legs

Day 7 – Rest  

5 Day Split Variation

Day 1 – Chest

Day 2 – Legs & Shoulders

Day 3 – Back

Day 4 – Biceps & Triceps

Day 5 – Core & Cardio

Day 6 – Rest

Day 7 – Rest

Explanation:

A hypothetical planet has a radius 1.8 times that of Earth but has the same mass. What is the acceleration due to gravity near its surface?

Answers

The acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².

The formula for acceleration due to gravity is:

g = GM/r² Where, g = acceleration due to gravity G = universal gravitational constant M = mass of the planet r = radius of the planet

In this case, since the mass of the hypothetical planet is the same as that of Earth, we can use the mass of Earth instead of M.

Therefore, g is proportional to 1/r².

So, using the ratio of radii given (1.8), we can write:

r = 1.8 x r Earth, where r Earth is the radius of Earth.

Substituting this value of r in the formula for acceleration due to gravity, we get:

g = GM/(1.8 x r Earth)² = GM/(3.24 x rEarth²) = (1/3.24)GM/rEarth²

We know that the acceleration due to gravity on Earth (g Earth) is 9.8 m/s².

Therefore, we can calculate the acceleration due to gravity on the hypothetical planet (gh) as follows:

gh = (1/3.24) x g Earth = 3.02 m/s²

Thus, the acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².

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Una persona de 76 kg está siendo retirada de un edificio en llamas mientras se muestra en la figura. Calcule la tensión
en las dos cuerdas si la persona está momentáneamente inmovil.
Ayuda por favor.

Una persona de 76 kg est siendo retirada de un edificio en llamas mientras se muestra en la figura. Calcule

Answers

Answer:

T1 = 736.6 N, T2 = 193.5 N

Explanation:

W = 76 N

The tension is T1 and T2.

By use of Lami's theorem

\(\frac{T_1}{Sin100}=\frac{T_2}{Sin165}=\frac{W}{Sin 95}\\\\So, \\\\T_1 = \frac{76\times 9.8\times Sin 100}{Sin 95} = 736.6 N \\And\\T_2 = \frac{76\times 9.8\times Sin 165}{Sin 95} = 193.5 N \\\)

The water pressure at the bottom of the Marianas Trench is approximately 1,100 kPa. With how much force would the water pressure at the bottom of the Marianas trench push on a fish with a surface area of 0.5m2 ?

Answers

Answer:

550 kN

Explanation:

Pressure = force/area

∴ Force = pressure x area.

F = 1,100 × 10^3 × 0.5 = 550,000 N

F = 550 kN

What are the types of contexts that are most influential in early childhood? How does this shift when children start school, and why does the relative importance of different contexts shift as children age?

Answers

Neighborhood, familial, and sociodemographic factors make up the three contextual factors.

Developmental theory and research emphasize a variety of contexts for children's development, including families, peers, schools, and neighborhoods. 1 These contexts are distinct from the other child development and well-being categories and should be assessed separately. Knowing whether or not a child is overweight or exercises enough, for example, can help describe the physical health of the child in a meaningful way.

Children from homes where the parents may or may not exercise frequently or actively encourage their children to exercise represent family situations that affect children's development and welfare. The family's level of money has an impact on the child's access to food as well (socio-demographic context).

In early life, gender is one of the clearest and most reliable signs that allows us to categorize our social environment. In the early stages of development, a person's ethnic origin does not provide the infant with any information beyond his perceptible characteristics; however, age can be a reliable indicator of expertise, competence, reliance, and authority, and gender can provide accurate information about potential areas of interest. Therefore, unlike someone who just shares the same hue, infants and children may have expectations regarding shared knowledge with someone who has or does not have the same competence (age) and interest (gender).

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Select the correct answer.
A boat moves 60 kilometers east from point A to point B. There, it reverses direction and travels another 45 kilometers toward point A. What are the total
distance and total displacement of the boat?
O A.
OB.
O C.
O D.
The total distance is 105 kilometers and the total displacement is 45 kilometers east.
The total distance is 60 kilometers and the total displacement is 60 kilometers east.
The total distance is 105 kilometers and the total displacement is 15 kilometers east.
The total distance is 60 kilometers and the total displacement is 45 kilometers east.

Answers

The total distance is 105 kilometers and the total displacement is 15 kilometers east. Option C

How to solve for the  total distance

To calculate the total distance, we add the distances traveled in each leg of the journey: 60 kilometers (from A to B) + 45 kilometers (from B back to A) = 105 kilometers.

However, displacement refers to the change in position of an object in a straight line from its starting point to its ending point. In this case, since the boat starts and ends at the same point (A), the total displacement is zero.

Hence The total distance is 105 kilometers and the total displacement is 15 kilometers east.

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basics of gravitation:
Planet a exerts a force on planet b. What can be said about the magnitude and direction of the gravitational force planet b exerts on planet a?

Answers

Answer:

Explanation:

According to Newton's Law of Gravitation, the gravitational force between two objects is always mutual, meaning that the force that one object exerts on the other is equal in magnitude but opposite in direction.

This means that if planet A exerts a gravitational force on planet B, then planet B will also exert a gravitational force on planet A. The magnitude of this force will be equal to the magnitude of the force that planet A exerts on planet B, but the direction will be opposite.

For example, if planet A exerts a gravitational force on planet B that is pulling planet B towards planet A, then planet B will also exert a gravitational force on planet A that is pulling planet A towards planet B. The magnitude of these two forces will be equal, but the directions will be opposite.

hat he sais

Answer:w

Explanation:

a constant force of magnitude F=45 N and making an angle of 30 to the horizontal is applied on a stationary block placed on the floor over a distance of 8 m. the work done by the force

Answers

The work done by the force on the block is approximately 311.2 Joules.

To calculate the work done by the constant force of magnitude F = 45 N over a distance of 8 m at an angle of 30 degrees to the horizontal, we need to find the component of the force that acts parallel to the displacement.

The horizontal component of the force can be calculated using trigonometry:

F_horizontal = F * cos(angle)

            = 45 N * cos(30 degrees)

            = 45 N * (√3 / 2)

            ≈ 38.9 N

Now, we can calculate the work done by the force using the equation:

Work = Force * Distance * cos(theta)

where theta is the angle between the force and the displacement.

Work = F_horizontal * Distance * cos(0)

     = 38.9 N * 8 m * cos(0)

     = 38.9 N * 8 m

     = 311.2 Joules

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On a warm summer day, a large mass of air (atmospheric pressure 1.01×105Pa) is heated by the ground to a temperature of 25.0 ∘C and then begins to rise through the cooler surrounding air. Calculate the temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.70×104 Pa. Assume that air is an ideal gas, with γ=1.40. (This rate of cooling for dry, rising air, corresponding to roughly 1 ∘C per 100 m of altitude, is called the dry adiabatic lapse rate.)

Answers

The temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.70×10⁴ Pa is approximately 14.3°C.

Using the ideal gas law, we can write: PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the absolute temperature. Since the mass of air is not changing, we can write: PV = constant.

Applying this to the situation where the air mass rises to a level where the pressure is 8.70×10⁴ Pa, we get:

(1.01×10⁵ Pa)×V = (nR/T1)×T1(8.70×10⁴ Pa)×V = (nR/T2)×T2

Dividing the second equation by the first and using the fact that γ=Cp/Cv=1.40 for air, we get:

(T2/T1) = [(P2/P1)^(γ-1)/γ] = [(8.70×10⁴ Pa)/(1.01×10⁵ Pa)]^(1.4/1.4) = 0.813

Solving for T2, we get:

T2 = T1×(P2/P1)^(γ-1)/γ = (25+273) K×0.813 ≈ 287.3 K ≈ 14.3°C

Thus, the temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.70×10⁴ Pa is approximately 14.3°C.

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I need help with (c) please

I need help with (c) please

Answers

Answer:

3*10^8 ÷ 475*10^-9

= 6.3 x 10^14

Sam wants to upgrade his toy "golf ball launcher". Right now when he shoots the toy vertically,
the golf ball reaches a height of 1.75 m. A golf ball has a mass of 46 grams and the toy can
hold a spring that can be compressed 24 cm. Using a different spring, Sam believes he can
increase the distance it can be compressed to 32 cm. What spring constant will Sam need the
new spring to be if he wants it to launch the golf ball vertically to a height of 3.0 m?

Answers

To solve this problem, we can use the conservation of energy. At the maximum height, all of the initial kinetic energy of the golf ball is converted into potential energy.

The initial kinetic energy of the golf ball can be found using:
KE = (1/2)mv^2

where
m = 0.046 kg (mass of golf ball)
v = ? (velocity of golf ball)

The potential energy of the golf ball at its maximum height is:
PE = mgh

where
h = 3.0 m (maximum height of golf ball)

Since the launcher is spring-powered, we can relate the initial kinetic energy to the potential energy using the spring constant and the distance the spring is compressed.

The initial kinetic energy can be found using the work-energy theorem:
W = KE

where
W = Fd (work done by the spring)
F = kx (force exerted by the spring)
x = 0.24 m (distance the spring can be compressed with the old spring)
k = ? (spring constant of new spring)

Substituting in the values, we get:
KE = (1/2)mv^2 = Fd = kx^2/2

Solving for k, we get:
k = (mv^2)/(x^2)

Now we can substitute in the values and solve for k:
k = (0.046 kg)(9.81 m/s^2)(1.75 m)/(0.24 m)^2 = 13.6 N/m

Therefore, Sam will need the new spring to have a spring constant of 33.7 N/m to launch the golf ball vertically to a height of 3.0 m.

PLEASEEEEEEEEE HELPPPPPPPPPP

Describe what determines magnetism.

Answers

Answer:

Magnetism is caused by the motion of electric charges. Every substance is made up of tiny units called atoms. Each atom has electrons, particles that carry electric charges. ... Their movement generates an electric current and causes each electron to act like a microscopic magnet.

Explanation:

make sure your response is 3-5 sentences.


What are some of the extreme conditions in space that challenge manned space exploration?

Answers

Answer: please see below

Explanation:

A manned space exploration is defined as the exploration of individuals --- astronauts in space using a spacecraft as a vehicle and are  responsible for operating its controls

The extreme conditions in space that challenge manned space exploration is as follows.

1. extreme loud sound waves cause by the launch of spacecraft which can shatter the spacecraft

2. extreme Temperatures in space ranging from extreme hot temperatures  (near the sun) to extreme cold temperatures  ( below freezing point out of space.

3.micrometeorite showers responsible for sandblasting can  damage spacecraft.

4.Ultra violet Radiation which can alter the control unit of the spacecraft  

Because of theses extreme conditions that pose challenges to space explorations, necessary precautions should be taken into consideration to be able to overcome such challenges. These precautions include building the spacecraft and the control unit in such a way that can resist these harmful conditions, also taking in mind safe escape routes for the astronauts in case of failures.

Pls help! Fill in the blanks.
Question: What are magnets?
Magnets are capable of generating ___ of ___ and ___. They attract ___ and metals like___and ___.

Answers

Answer:

attracting iron and producing a magnetic field

One student runs with a velocity of +10 m/s while a second student runs with a velocity of –10 m/s. Which student has the faster velocity? Why?

Answers

Answer:

The one with the faster velocity is the one with a velocity of -10m/s

please help answering A,B,C in screenshots thank you!

please help answering A,B,C in screenshots thank you!
please help answering A,B,C in screenshots thank you!

Answers

The slope of the graph is 0.5 m/s² and when t = 1.5 s, the predicted displacement (d) of the object is 0.75 meters.

To plot the velocity vs. time graph, we'll use the given data points:

Duration, At (s): 2.0, 4.0, 6.0, 8.0, 10.0, 12.0

Velocity, v (m/s): 6.0, 7.0, 8.0, 9.0, 10.0, 11.0

Let's plot these points on a graph:

Time (s) [x-axis] | Velocity (m/s) [y-axis]

--------------------------------------------

2.0               | 6.0

4.0               | 7.0

6.0               | 8.0

8.0               | 9.0

10.0              | 10.0

12.0              | 11.0

After plotting the points, we can connect them with a straight line to represent the motion of the object. This line represents the velocity vs. time relationship.

Now, let's calculate the slope of this line. The slope of a line represents the rate of change of the dependent variable (velocity) with respect to the independent variable (time). In this case, it gives us the acceleration of the object.

Using the formula for calculating the slope of a line:

Slope (k) = (Change in velocity) / (Change in time)

For the first two points:

Change in velocity = 7.0 - 6.0 = 1.0 m/s

Change in time = 4.0 - 2.0 = 2.0 s

Slope (k) = 1.0 m/s / 2.0 s = 0.5 m/s²

Therefore, the slope of the graph is 0.5 m/s².

Now, to answer part B, the physical significance of the slope value is that it represents the object's acceleration. In this case, the constant acceleration experienced by the object is 0.5 m/s².

Moving on to part C, we are given the equation d = kt, where d represents the displacement and t represents time. Since the object is experiencing constant acceleration, the equation can be rewritten as d = 0.5t, where 0.5 is the acceleration (k).

To predict the value of "d" when t = 1.5 s, we can substitute the value of t into the equation:

d = 0.5 * 1.5 = 0.75 meters

Therefore, when t = 1.5 s, the predicted displacement (d) of the object is 0.75 meters.

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The probable question may be:

An object is subjected to a constant acceleration along a frictionless track. A student measures its velocity (v) after specific durations (At). The student uses a graph to analyze the truck's motion.

Duration, At, (s) :- 2.0,4.0,6.0,8.0,10.0,12.0.

Velocity, v, (m/s) :- 6.0,7.0,8.0,9.0,10.0,11.0

A. Plot the velocity (in meters/sec) vs. time (seconds). The velocity is the y-axis and time is the x-axis. Use any graphing software you like or graph this data in pencil on graph paper. Excel has a nice graphing package. Calculate the slope of this graph. You will

B. What is the physical significance of the slope value computed in part A?

C. Having determined the slope of the line, you can now write d = kt. Use this equation to predict a value of "d" when t = 1.5 s.

Share an experience you've had with the bureaucracy. In thinking about that experience, how would you describe the bureaucracy? What characteristics of the bureaucracy did you observe in that experience? Please explain. (Refer to Weber's theory of bureaucracy in the module.)

Answers

Bureaucracy theory explains the basis of the systematic formation of any organization and ensures efficiency and economic effectiveness.

Bureaucracy is the theory proposed by Max Weber. It forms the ideal model for the management and administration of the organization and ensures its efficiency of organization into focus.

It includes six basic principles. They are Authority Hierarchy, Division of labor, impersonality, Career Orientation, Formal rules and regulations, and Selection process.

The characteristics of bureaucracy include: It can control and regulate the behavior of people in an organization. It is the organization that has the power to make decisions. The organizations have certain rules to follow by the people.

Bureaucracy is found in large organizations like governments and corporations. It has standardized methods, and procedures to practice. It doesn't allow any flexibility for the organization.

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A force of 20 N to the south is applied to each object below. Which object will undergo the greatest change in momentum?

Answers

Answer:

Hello there! The answer your would be looking for is:

A 33 kg object that is moving north at 10 m/s

Momentum can be defined as the product of mass and velocity. Thus momentum is directly proportional to both velocity and momentum. Thus, the object with greater mass as well as velocity has greater momentum. Therefore, option C is correct.

What is force?

Force can be described as an external agent acting on a body, to change its state of rest or motion. There are several kinds of forces such as magnetic force, frictional force, nuclear force, etc.

In physics, force can be described as the product of the mass and acceleration of the body. Greater mass results in greater force required to be exerted on the object to make it move or stop.

Therefore, when mass or velocity or both increases, the momentum of the object increases as well. Therefore, the larger object moving faster gain greater momentum.

Therefore, when the same force is exerted on the object then, the 41 kg object that is moving north at 12 m/s will undergo the greatest change in momentum.

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Your question was incomplete but most probably the complete question was,

A force of 20 N to the south is applied to each object below. Which object will undergo the greatest change in momentum?

A. A 33 kg object that is moving north at 12 m/s

B. A 41 kg object that is moving north at 10 m/s

C. A 41 kg object that is moving north at 12 m/s

D. A 33 kg object that is moving north at 10 m/s

What are the differences between atoms, molecules, and compounds?

Answers

Answer:

Atoms are the thing that make up molecules and compounds. Molecule. Two or more atoms joined together with covalent bonds. Molecules contain two or more atoms and are held together by covalent bonds, whereas compounds are held together by ionic bonds. Compound. Two or more elements bonded together through ionic attraction.

An object is in circular motion. The radius of its motion is 18.7 m and its velocity is 7 m/s. What is its frequency?

Answers

The frequency of the object in circular motion is 0.06 Hz.

What is the frequency of the object in circular motion?

The formula to calculate the frequency is derived as follows;

The angular speed, ω is related to the frequency, f, as follows;

ω = 2πf

The linear velocity is related to angular velocity as follows:

v = r ω

ω = v/r

where;

v is the linear speed,

r is the radius, and

ω is the angular speed

Hence,

f = v/2πr

f = 7 / (18.7 * 2π)

Frequency, f = 0.06 Hz

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A 35.30-kg box is attached to a light string that is wrapped around a cylindrical frictionless spool of radius 10.0 cm and moment of inertia 4.00 kg * m^2. The spool is suspended from the ceiling, and the box is then released from rest a distance from rest a distance 3.50 m above the floor. How long does it take for the box to reach the floor?

Answers

Answer:

The velocity of the box is related to the angular velocity of the spool, which is given by the equation:

v = r * ω

where r is the radius of the spool and ω is the angular velocity of the spool. The angular velocity of the spool, in turn, is related to the torque applied to the spool by the tension in the string, which is given by the equation:

τ = I * α

where τ is the torque, I is the moment of inertia of the spool, and α is the angular acceleration of the spool.

The tension in the string is equal to the weight of the box, which is given by:

T = m * g

Putting all of these equations together, we can solve for the time it takes for the box to reach the floor. Here's how:

First, we can find the angular acceleration of the spool using the torque equation:

τ = I * α

T = m * g = τ

m * g = I * α

α = (m * g) / I

α = (35.30 kg * 9.81 m/s^2) / 4.00 kg*m^2

α = 86.53 rad/s^2

Next, we can find the angular velocity of the spool using the kinematic equation:

ω^2 = ω_0^2 + 2 * α * θ

where ω_0 is the initial angular velocity (which is zero), θ is the angle through which the spool has turned (which is equal to the distance the box has fallen divided by the radius of the spool), and ω is the final angular velocity (which is what we want to find). Solving for ω, we get:

ω^2 = 2 * α * θ

ω = sqrt(2 * α * θ)

ω = sqrt(2 * 86.53 rad/s^2 * (3.50 m / 0.10 m))

ω = 166.6 rad/s

Finally, we can find the time it takes for the box to reach the floor using the equation:

v = r * ω

v = 0.10 m * 166.6 rad/s

v = 16.66 m/s

t = d / v

t = 3.50 m / 16.66 m/s

t = 0.21 s

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