Given are four statements. We need to identify which of the following statements are true or false with regard to the ionosphere.1)true. 3)true. 2)false. 4)true are the answers
4.)The ionosphere straddles the homosphere and heterosphere. The ionosphere is located in the heterosphere, which is the upper layer of the Earth's atmosphere. The homosphere, on the other hand, is the lower layer of the atmosphere. Therefore, the given statement "The ionosphere straddles the homosphere and heterosphere" is True.
1) Ions reflect certain radio transmission frequencies, such as those of AM radio.Ions can reflect radio signals back to the Earth's surface. As a result, it is possible to transmit radio signals over long distances by bouncing them off the ionosphere. The ionosphere can reflect radio frequencies up to a certain wavelength, such as those of AM radio. Therefore, the given statement "Ions reflect certain radio transmission frequencies, such as those of AM radio" is True.
3)Air molecules interact with solar radiation directed to the poles by Earth's magnetic field, producing aurora. The Earth's magnetic field directs charged particles from the sun towards the poles. When these particles collide with air molecules in the upper atmosphere, they can cause the air molecules to become ionized. These ionized particles can then produce the bright lights known as aurora borealis and aurora australis. Therefore, the given statement "Air molecules interact with solar radiation directed to the poles by Earth's magnetic field, producing aurora" is True.
2) The ionosphere is located within the stratosphere. The ionosphere is not located in the stratosphere but rather in the heterosphere, which is the upper layer of the Earth's atmosphere. Therefore, the given statement "The ionosphere is located within the stratosphere" is False.
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Explain how a helicopter lifts itself up, from a Newton's 3rd Law perspective,
A ball Of Mass. 0.5 kg initially at rest is kick directly toward offense from appoint 20 m away as shown below the velocity of the ball as it leaves the kickers foot is 16 M/S at angle 45 degrees above the horizontal the top of the fence is 4 m high the ball hits nothing Wallen flight and a resistance is negligible the acceleration due to gravity is 9.8 M/S^2 determine the time it takes for the ball to reach the plane of the fence.
Answer:
a. The horizontal component of the velocity is constant so vxt = d where vx = v0 cosθ = 16m/s t = d/v = 2s
b. The height of the ball during its flight is given by y = v0yt + ½ gt2 where v0y = v0sinθ = 12m/s and g = –9.8m/s2 which gives at t = 2s, y = 4.4m. The fence is 2.5m high so the ball passes above the fence by 4.4m – 2.5m = 1.9m
Explanation:
A plate moves 200 m in 10,000 years. What is its rat in cm/year
Answer:
2cm/year
Explanation:
20000/10000=2cm/year
In a certain region of space, the electric potential is given by V=y2+2.5xy−3.5xyz.
A)Determine the components of the electric field vector, E⃗ , in this region
The components of the electric field vector E⃗ in the given region are:
Eₓ = -2.5y - 3.5yz
Eᵧ = 2y + 2.5x - 3.5xz
E_z = 3.5xy
To determine the components of the electric field vector E⃗ in the given region, we need to take the negative gradient of the electric potential V.
The electric field is defined as the negative gradient of the electric potential:
E⃗ = -∇V
where ∇ denotes the gradient operator.
To find the components of E⃗ , we calculate the partial derivatives of V with respect to each coordinate (x, y, and z) and negate them:
Eₓ = -∂V/∂x
Eᵧ = -∂V/∂y
E_z = -∂V/∂z
Let's calculate each component of the electric field vector:
Eₓ = -∂V/∂x = -∂/∂x (y² + 2.5xy - 3.5xyz)
= -2.5y - 3.5yz
Eᵧ = -∂V/∂y = -∂/∂y (y² + 2.5xy - 3.5xyz)
= 2y + 2.5x - 3.5xz
E_z = -∂V/∂z = -∂/∂z (y² + 2.5xy - 3.5xyz)
= 3.5xy
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According to the Law of Reflection, a light ray strikes a mirror ________________________________.
moves into the mirror at a slightly different angle.
continues moving through the mirror in the same direction.
bounces off the mirror towards the direction it came from.
bounces off the mirror at the same angle it hits the solid surface.
Answer:
bounces off the mirror at the same angle it hits the solid surface.
Explanation:
According to the Law of Reflection, a light ray strikes a mirror at the point of incidence bounces off the mirror at the same angle it hits the solid surface.
The incident ray and the reflected ray lie in the same plane
The angle of incidence is equal to the angle of reflection as a ray of light reflects off a solid surface.
So,
correct answer is ''bounces off the mirror at the same angle it hits the solid surface.''
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Answer:
the answer to the first one is B and the second one is c I hope I got them right
Ten seconds after starting from rest, a freely-falling object will have a speed of about ________________________
Answer:
100 m/s
Explanation:
Speed increases at a rate of 10 m/s (actually 9.8 m/s) every second. Thus after 10 seconds, the speed is 10 x 10 = 100 m/s.
In oxidative phosphorylation, cytochrome c acts as:A. a 1-electron carrier.B. a 2-electron carrier.C. a 3-electron carrier.D. a 4-electron carrier.
In oxidative phosphorylation, cytochrome c acts as: A. a 1-electron carrier.
The oxidative phosphorylation is the one of the steps in cellular respiration. The cellular respiration involves glycolysis, Krebs cycle and final step of oxidative phosphorylation, which leads to generation of maximum amount of ATP compared to other steps.
The cytochrome c and other cytochromes, the heme containing proteins, transfer the electrons within the mitochondrial inner membrane space and matrix. Cytochrome c transfer one electron from complex III to complex IV.
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Part B Which, if any, of these scenarios produce an inverted image? Which, if any, of these scenarios produce an upright image? Sort the following scenarios into the appropriate bins. Reset Help d=5 cm f = 20 cm d d=10 cm f5 cm d d 15 cm J = 5 cm d 10 cm f = 20 cm 15 cm - 20 cm 20 cm 10 cm inverted image upright image Submit Request Answer Part Rank the images on the basis of the magnitude of their magnification Rank these from largest to smallest. To rank items as equivalent, overlap them. View Available Hint(s) Reset Help d 15 cm 10 cm 20 cm d=20 cmd =10 cm f = 10 cm If=5 cm d = 15 cm f=5 cm d = 5 cm f =20 cm 1 20 cm largest smallest Submit
based on how much they have been magnified, the images Sort them in order of greatest to smallest. Overlap things to determine their equality.
m₆>m₁>m₅>m₃=m₂>m₄
Part B:-
By using the lens equation
\(\frac{1}{f} = \frac{1}{d} +\frac{1}{i}\)
\(i=\frac{fd}{d-f}\)(1)
now the equation for magnification is
\(m=\frac{-i}{d}\)(2)
(i) d=5cm , f=20cm
put values in the (i) equation
\(i=\frac{20*5}{5-20}\)\(=-6.7cm\)
for (2) equation
\(m=\frac{-(-6.7)}{5}\)
=1.34 →image upright
(ii) d=10cm f=5cm
\(i=\frac{10*5}{10-5}\) \(= 10cm\)
m=-10/10=-1→image is inverted
(iii) d=15cm f=5cm
\(i=\frac{15*5}{15-5}\) \(= 7.5cm\)
\(m=\frac{-7.5}{15}\) \(= -0.5\)→images is inverted
(iv) d=10cm f=20cm
\(i= \frac{10*20}{10-20}\) \(=-20cm\)
\(m=\frac{-(-20)}{10}\) =2→image is upright
(v) d=15cm f=20cm
\(i= \frac{15*20}{15-20}\) = -60cm
\(m=\frac{-(-60)}{15}\) = 4→image is upright
(vi) d=20cm f=10cm
\(i=\frac{20*10}{20-10}\) \(= 20cm\)
\(m=\frac{-20}{20}\) = -1 →image is inverted
part c
\(\frac{1}{f} =\frac{1}{d} + \frac{1}{i}\)
\(i=\frac{df}{d-f}\)
The magnitude of magnification is
m=|-i/d|=|-f/(d-f)|
(i)m₁=|-20/(10-20)|=2
(ii)m₂=|-10/(20-10)|=1
(iii)m₃=|-5/(10-5)|=1
(iv)m₄=|-5/10|=0.5
(v)m₅=|-20/5-20|=1.33
(vi)m₆=|-20/-5|=4
∴m₆>m₁>m₅>m₃=m₂>m₄
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An air mass, shown in the image below, that forms over parts of Mexico, Texas, and Arizona will be a _______.
a. continental polar air mass
b. continental tropical air mass
c. maritime polar air mass
d. maritime tropical air mass
Based on the location of formation and the characteristics of the air mass, the air mass shown in the image is most likely a continental tropical air mass.
Location: The air mass forms over parts of Mexico, Texas, and Arizona, which are located in the southwestern United States and northern Mexico. This region is characterized by warm to hot temperatures and dry conditions, which are typical of continental tropical air masses.
Characteristics: Continental tropical air masses form over warm land areas in the tropics and subtropics, and are characterized by high temperatures, low humidity, and stable atmospheric conditions.
Therefore, based on the location and characteristics of the air mass, we can conclude that it is most likely a continental tropical air mass.
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what is the physical state of gold at room temperature
Answer:
solid
Explanation:
Gold is a chemical element with symbol Au and atomic number 79. Classified as a transition metal, Gold is a solid at room temperature.
There are two containers of equal volumes, each filled with a different gas. Both containers have the same number of moles of gas and are at the same temperature. The molecules of gas in container 1 are four times more massive than the molecules of gas in container 2.
State which container, 1 or 2, has the larger value of the following quantities, or, if they are equal, state that they are equal. Explain your reasoning. (Please show any formulas and calculations used.)
i) Pressure
ii) "Average" (rms) speed of gas molecules
iii) Average kinetic energy of gas molecules
iv) Thermal energy
Let's denote the following terms as given: Container 1 and 2 are equal and filled with different gas. Both containers have the same number of moles of gas and are at the same temperature. Answer: i) Pressure: Equal ii) "Average" (rms) speed of gas molecules: Container 2 iii) Average kinetic energy of gas molecules: Equal iv) Thermal energy: Equal
The molecules of gas in container 1 are four times more massive than the molecules of gas in container 2. We have to determine which container would have the larger value of Pressure, "average" (rms) speed of gas molecules, average kinetic energy of gas molecules, and thermal energy. i) Pressure: m We can determine the pressure of the gas molecules by the Ideal gas law, Pressure of the gas molecules is given by the formula: P = nRT/V where n is the number of moles of the gas molecules R is the gas constant T is the temperature of the gas molecules V is the volume of the gas molecules. From the above formula, we can see that the pressure is inversely proportional to the volume. Since both containers have the same volume, they should have the same pressure. Thus, the pressure of both the containers is equal. ii) "Average" (rms) speed of gas molecules we can determine the average speed of the gas molecules by the root mean square (rms) speed rms speed of gas molecules is given by the formula: v rms = √(3kT/m)Where k is the Boltzmann's constant T is the temperature of the gas molecules m is the mass of the gas molecules. From the above formula, we can see that the average speed is directly proportional to the square root of the temperature and inversely proportional to the square root of the mass of the gas molecule. The molecules of gas in container 1 are four times more massive than the molecules of gas in container 2. So, the gas molecules in container 1 will move slower than the gas molecules in container
2. Thus, the container with the less massive gas molecules will have a larger value of the "average" (rms) speed of gas molecules. So, container 2 has a larger value of the "average" (rms) speed of gas molecules. iii) Average kinetic energy of gas molecules Average kinetic energy of gas molecules is given by the formula: KE avg = (3/2)kT. From the above formula, we can see that the average kinetic energy of gas molecules is directly proportional to the temperature and independent of the mass of the gas molecules. Therefore, both containers will have the same average kinetic energy of gas molecules. Thus, the average kinetic energy of both the containers is equal .iv) Thermal energy: Thermal energy of gas molecules is the sum of the average kinetic energy of gas molecules and the potential energy of the gas molecules. Since both the containers have the same number of moles of gas and are at the same temperature, they should have the same thermal energy. Therefore, both containers will have the same thermal energy. Thus, the thermal energy of both the containers is equal.
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BRAINLIEST WILL BE GIVEN!!!!! After communicating the information you requested above, he pushes the sled a total distance of 50 m and exerts a horizontal force of 800 N. During the sled push he pushes the sled 25 m, turns around and pushes it 25 m back to where he started. He argues that the work done is 40000 J, but you say the total work is actually 0 J. Why are you correct and he is wrong?
Answer:
W=F*D
40,000=800*50
With this you are wrong and he is right because work is not like displacement where if you go 10 ft to the right then 10 ft to the left you have traveled gone 0 ft from original spot. because your distance was 50 m and you exerted 800 N you multiply that together and come out with 40,000 so HE IS RIGHT YOU ARE WRONG.
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A train moves at 300 km/h. How far will it go in 5 hours?
Answer:
1,500 km
Explanation:
300 km/h
300 kilometers PER HOUR
So you want to see how far it will go in 5 hours, all you need to do is multiply the kilometers by 5. Since we know that per hour it's 300 km.
300 * 5 = 1,500
The train moves at 1,500 km in 5 hours.
Hope this helped!
Have a supercalifragilisticexpialidocious day!
11. What is the wavelength of an earthquake wave if it has a speed of 5000 m/s and a frequency of 10 HZ
step#1
step#2
step#3
Answer:
500 m
Explanation:
The applicable relation is ...
wavelength = speed/frequency
wavelength = (5000 m/s)/(10 cycles/s) = 500 m/cycle
The wavelength is 500 meters.
An 8kg mass has a KE of 144j, what is its velocity
Answer:
6m/s
Explanation:
KE=m*v^2/2
=>v=(2*KE/M)^(1/2)
*SECOND ONE* Complete this equation that represents the process of nuclear fusion.
Superscript 226 Subscript 88 Baseline R a yields Superscript A Subscript B Baseline R n + Superscript 4 Subscript 2 Baseline H e
A:
B:
ANSWER:
222
86
The completed equation for the process of nuclear fusion is \(^{226}{88}Ra\) → \(^{222}{86}Rn\) + \(^{4}_{2}He\).
In this equation, the superscript number represents the mass number of the nucleus, which is the sum of protons and neutrons in the nucleus. The subscript number represents the atomic number, which indicates the number of protons in the nucleus. In the given equation, the initial nucleus is \(^{226}{88}Ra\), which stands for radium-226.
Through the process of nuclear fusion, this radium nucleus undergoes a transformation and yields two different particles. The first product is \(^{222}{86}Rn\), which represents radon-222, and the second product is \(^{4}_{2}He\), which represents helium-4.
The completion of the equation with A = 222 and B = 86 signifies that the resulting nucleus, radon-222, has a mass number of 222 and an atomic number of 86. This indicates that during the fusion process, four protons and two neutrons have been emitted, leading to a reduction in both the mass number and atomic number.
Nuclear fusion is a process in which atomic nuclei combine to form a heavier nucleus, releasing a significant amount of energy. It is a fundamental process that powers stars, including our Sun. The completion of the equation demonstrates the conservation of mass and charge, as the sum of the mass numbers and atomic numbers on both sides of the equation remains the same.
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When the mass of the cylinder increased by a factor of 3, from 1. 0 kg to 3. 0 kg, what happened to the cylindera's gravitational potential energy? It decreased by a factor of 3. It decreased by a factor of 2. It increased by a factor of 2. It increased by a factor of 3.
The mass of the cylinder increased by a factor of 3, the gravitational potential energy increases by a factor of 3.
The given parameters:
Initial mass of the cylinder, m₁ = 1.0 kgFinal mass of the cylinder, m₂ = 3.0 kgThe gravitational potential energy of an object is calculated as follows;
P.E = mgh
where;
m is the mass
g is acceleration due to gravity
h is the height of the cylinder
when the mass = 1 kg
P.E = 1 x g x h
P.E = gh
when the mass = 3 kg
P.E = 3 x gh
P.E = 3gh
Thus, when the mass of the cylinder increased by a factor of 3, the gravitational potential energy increases by a factor of 3.
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Darcel runs the simulation for the large version of each object. What can he say in general about the energies of the objects in the simulation as they roll down the incline? (Select all that apply.)"The total energy of the system remains constant and is equal to the gravitational potential energy of the object at the top of the incline.""The total kinetic energy of a rolling object is the sum of the rotational kinetic energy about the center of mass and the translational kinetic energy of the center of mass.""The translational kinetic energy is always greater than the rotational kinetic energy.""The potential energy of the system remains constant, and is equal to the total energy."
12 mvCM2 is the translational kinetic energy. Rotational kinetic energy is equal to 12 I2. The combined translational and rotational kinetic energies of an object in motion determine its total kinetic energy.
A rolling object's combined linear and rotational kinetic energies make up its total kinetic energy: The second equation clearly shows that a rolling item has kinetic energy that is greater than its kinetic energy during translation. Yes, the kinetic energies of rotation and translation are same. The coordinated (non-random) movement of mass with respect to a certain reference frame involves both of them as the energy of motion. 12 mvCM2 is the translational kinetic energy. Rotational kinetic energy is equal to 12 I2.
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An eccentric inventor attempts to levitate a cork ball by wrapping it with foil and placing a large negative charge on the ball and then putting a large positive charge on the ceiling of his workshop. Instead, while attempting to place a large negative charge on the ball, the foil flies off. Explain.
Answer:
because of the idea that like charges get repulsion as a force.
Explanation:
because you wrap the ball with foil, the negative charges will leave the foil and go into the ball by induction. This leaves the foil as a positively charged particle since its electrons left it for the ball, making the ball a negatively charged particle. but if you bring the negative charge near the foil, the electrons will transfer from that and go into the foil, making it negatively charged. Now, because the ball and the foil have the same charge, they repel. the foil flies off.
A 30 kg child is sitting on a swing. Their weight is exerting a downward force on the swing. The ropes are exerting an upward force on the swing. The swing is not moving. What is the net force on the swing?
A.294 N down
B.294 N up
C.0 N
D.30 kg
during volleyball practice a volleyball is tossed over a net, starting from a height of 1.5 meters above the ground. after reaching the top of its trajectory it returns to its original height as it falls. how does the motion of the ball at the top of its trajectory compare to its motion as it passes its original height?
When a volleyball is tossed over a net, starting from a height of 1.5 meters above the ground, where after reaching the top of its trajectory it returns to its original height as it falls, the ball's speed is the same as when it was tossed, but its velocity is different.
As ball 1 gets to the top of its trajectory, its velocity becomes zero.
since not stated otherwise, we assume that both balls have the same properties
If ball 2 is released at this instance, then they both will travel down at the same time interval and have initial velocity as zero.
since vertical travel is downwards, then acceleration due to gravity g is positive for both balls.
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What does potential energy between two magnets become kinetic energy?
Answer:
HI!
Here is ur answer
100% correct Potential energy between two magnetsMagnetic PE depends on both distance and orientation in the magnetic field. ... The magnetic fields are aligned. This makes an attractive force between the two magnets. The farther apart they are, the higher their potential energy.
PLEASE MARK ME AS BRAINLISTwhy are cepheid variables so important for measuring distances in astronomy?
Cepheid variables are crucial for measuring distances in astronomy.
Cepheid variables are a type of pulsating star that undergoes regular changes in brightness over time. The period of their brightness variations is directly related to their intrinsic luminosity, meaning that brighter Cepheids have longer periods.
This relationship, known as the period-luminosity relationship, allows astronomers to use Cepheids as "standard candles" for distance measurements. By measuring the period of a Cepheid and comparing it to its observed brightness, astronomers can determine its intrinsic luminosity and then calculate its distance using the inverse square law.
Since Cepheids are observable in distant galaxies, they serve as reliable distance indicators and have played a vital role in determining the scale of the universe and studying cosmic expansion.
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Cepheid variables are important in astronomy due to their unique period-luminosity relationship allowing astronomers to measure stellar distances. This relation has helped in the discovery of the universe's expansion and breaking the distance confines of parallax, aiding exploration into more distant parts of our Galaxy and others.
Explanation:Cepheid variables are important for measuring distances in astronomy due to their unique period-luminosity relationship. The
period-luminosity relation
states that the longer the period (the time it takes for the star to vary), the greater the luminosity (brightness) of the Cepheid variable star is. This relationship is essential as it allows astronomers to measure the distance of these stars once the period has been determined.
To initially define this relationship with actual numbers, astronomers had to measure distances to a few nearby Cepheids in a different way, typically by finding Cepheids in clusters with stars whose distances could be estimated using spectral analysis. Once this period-luminosity relation was calibrated, it could be used to estimate the distance of any Cepheid, regardless of its location.
Cepheids have become crucial markers in space, acting as cosmic signposts. For instance, in the 1920s, Edwin Hubble used Cepheid variables to discover the expansion of the universe. They have been instrumental in breaking the distance confines of parallax, allowing astronomers to explore more distant parts of our Galaxy and others.
Today, the search continues with modern instruments including the Hubble Space Telescope, identifying and measuring individual Cepheids in galaxies farther and farther away. Some Cepheids are known to be about 60 million light-years away.
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What is the momentum of a 8kg ball rolling at 25 m/s?
Answer:
200
Explanation:
P = M x V
P = 8 x 25
P = 200
If one oscillation has 5.8 times the energy of a second one of equal frequency and mass, what is the ratio of their amplitudes?
If one oscillation has 5.8 times the energy of the second one of equal frequency and mass, 2.4:1 is the ratio of their amplitudes.
Oscillation is defined as the process of repeating fluctuations of a quantity or measure around its time equilibrium value. Oscillation can also be defined as the periodic fluctuation of matter between two values or about their average.
The definition of happiness is someone or something that makes you feel great joy or pleasure. An example of good luck is someone who wins the lottery. An example of happiness is a laughing baby. Besides making you feel better, positive emotions are good for your brain and body. It lowers stress hormones, relieves anxiety and depression, and strengthens the immune system. Feeling positive emotions every day has a huge impact on our well-being and health.
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Two metal disks are welded together and are mounted on a frictionless axis through their common centers. One disk has a radius R1 = 2.60 cm and mass M1 = 0.810 kg and the other disk has a radius R2 = 5.00 cm and mass M2 = 1.58 kg . (Figure 1) A string of negligible mass is wrapped around the smaller disk, and a 1.50-kg block, is suspended from the free end of the string. The block is released from rest a distance of 2.10 m above the ground. What is the block's speed just before it hits the ground?
The Inertia is 22. 488 kg. m² and the speed just before it hits the ground is 6. 4 m/s
How to determine the inertia
Using the formula:
I = 1/2 M₁R₁² + 1/2 M₂R₂²
Where I = Inertia
I = 1/2 * 0.810* (2. 60)² + 1/2 * 1. 58 * (5)²
I = 1/2 * 5. 476 + 1/2 * 39. 5
I = 2. 738 + 19. 75
I = 22. 488 kg. m²
To determine the block's speed, use the formula
v = \(\sqrt{2gh}\)
v = \(\sqrt{2* 10 * 2. 10}\)
v = \(\sqrt{42}\)
v = 6. 4 m/s
Therefore, the Inertia is 22. 488 kg. m² and the speed just before it hits the ground is 6. 4 m/s
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Two pieces of clay collide and stick together moving in one dimension. Clay 1 has a mass of 2,100 grams, and a clay 2 has a mass of 2,500 grams. Clay 1 has an initial velocity of 20 m/s immediately before they have a perfectly inelastic collision.
What is the final velocity of the two pieces of clay immediately after the collision?
a. 3.7 m/s
b. -3.7 m/s
c. 15 m/s
d.-15 m/s
The common velocity of clay 1 and clay 2 is 15 m/s. Option C
What is an inelastic collision?We know that a collision can be said to be inelastic when the momentum and the kinetic energy are not conserved. This implies that rather than having the objects move out in different directions, the objects would rather stick together and just move in the same direction.
In this case we would also need the law of the conservation of linear momentum. Recall that according to this law, the momentum before collision would just be the same as the momentum after Collison.
Thus;
Momentum before collision = momentum after Collison
(2100 * 20) + (2500 * 0) = (2100 + 2500)v
Where v is the common velocity
v = 42000/4600
v = 15 m/s
Thus they would have the common velocity of 15 m/s
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What is the net force of 25 kg of mass and it’s acceleration
Answer:
The net force is 9.8ms2, but were you given the acceleration?
A rock is dropped from a bridge and hits the water 1.5 seconds later. How high is the bridge?