Identify the type of triangle by looking at the sum of the angle
measures.
105 + 65 + 10 = 180°
a Right
b Acute
C Equiangular
d Obtuse

The probability to get a 3 or 4 in the third toss and 6 in the fourth toss is 1/18.

The sample space for a six-sided die is

{1, 2, 3, 4, 5, 6}

Hence the total number of possibilities = 6

The rolling of a die is IID that is Independently and Identically distributed.

Hence,

the result of one toss will not affect the result of the successive tosses.

Probability

= n(E)/n

= no of favorable outcomes for any event /total no. of outcomes

Here,

n = 6

Let A be the event of getting a 3 or 4 in the third toss

Let B be the event of getting 6 on the fourth toss

E(A) = {3,4}

n(A) = 2

Hence,

P(A) = 2/6

= 1/3

B = {6}

n(B) = 1

P(B) = 1/6

Since these are IID,

P(A and B) = P(A) X (B) [Property of independent events]

Hence P(A∩B) = 1/3 X 1/6

= 1/18

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The probability of Hae 0.randomly picking a red ball from is 0.54.

Based on the given information, the odds in favor of Hae picking a red ball are 2:11. This means there are 2 favorable outcomes (picking a red ball) for every 11 unfavorable outcomes (not picking a red ball). To find the probability of Hae picking a red ball, we can use the following formula:
Probability = Favorable outcomes / (Favorable outcomes + Unfavorable outcomes)
In this case, there are 2 favorable outcomes and 11 unfavorable outcomes. So, the probability of Hae picking a red ball is:
Probability = 2 / (2 + 11) = 2 / 13
So, the probability of Hae randomly picking a red ball from the bag is 0.54.

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Answer:

im Pretty sure it’s 20 I did this awhile ago

Step-by-step explanation:

Answer:

Step-by-step explanation:

Translate the shape 2 units up and 3 units to the left on a graph and you will find the answer.

Answer:

R= -4,8

S= 2,8

T= 1,6

U= -5,6

Degree of freedom for chi-square test for 10 categories will be 9.

What is chi- square test?

A test that evaluates how well a model matches real observed data is that the chi-square (χ²) statistic. A chi-square statistic can only be calculated with data that's random, unprocessed, mutually exclusive, obtained from independent variables, and drawn from a large enough sample.

The Formula for Chi-Square Is

χ(c)=²∑(Oₐ-Eₐ)₂/Eₐ²

where:

c=Degrees of freedom

O=Observed value(s)

E=Expected value(s)

​

Main Body:

Degree of freedom = total categories -1

so no. of categories= 10

Degree of freedom = 10 - 1

Hence degree of freedom = 9

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Answer:

D

Step-by-step explanation:

The reason D is false is because it states that Sasha can make 2 bags per minute while she cant make 2 bags per minute. She can make half a bag per minute. D is wrong 100%

Answer:

Step-by-step explanation:

Distance covered = speed × time.

Sasha runs at a constant speed of 3.8 meters per second for 1/2 hour.

This means distance covered while running would be

3.8 × 1/2 = 1.9 meters

Then she walks at a constant rate of 1.5 meters per second for 1/2 hour. This means distance covered while walking would be

1.5 × 1/2 = 0.75 meters

Total distance that Sasha covered while running and walking in 60 minutes would be

1.9 + 0.75 = 2.65 meters

Step-by-step explanation:

In order to find how many blocks she was able to draw a line, we can calculate the following rule of three:

Now, we can write the following equation and solve it for x:

Therefore she would be able to draw a line in a total of 8 blocks.

The standard deviation of the outcome for the given bet is approximately $51.

To obtain this result, we can use the following formula for the standard deviation of a random variable with two possible outcomes (winning or losing in this case):SD = √(p(1-p)w² + p(1-p)l²),where SD is the standard deviation, p is the probability of winning (0.4 in this case), w is the amount won ($50 in this case), and l is the amount lost ($50 in this case).

Plugging in the values, we get:SD = √(0.4(1-0.4)(50²) + 0.6(1-0.6)(-50²))≈ $51

Therefore, the standard deviation of the outcome of the given bet is approximately $51.Explanation:In statistics, the standard deviation is a measure of how spread out the values in a data set are.

A higher standard deviation indicates that the values are more spread out, while a lower standard deviation indicates that the values are more clustered together.

In the context of this problem, we are asked to find the standard deviation of the outcome of a bet. The outcome can either be a win of $50 with a probability of 40% or a loss of $50 with a probability of 60%.

To find the standard deviation of this random variable, we can use the formula:SD = √(p(1-p)w² + p(1-p)l²),where SD is the standard deviation, p is the probability of winning, w is the amount won, and l is the amount lost.

Plugging in the values, we get:SD = √(0.4(1-0.4)(50²) + 0.6(1-0.6)(-50²))≈ $51Therefore, the standard deviation of the outcome of the given bet is approximately $51.

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Points of inflection, which occur when the second derivative W"(t) equals zero.

W'(t) = 0

The trout is gaining weight most rapidly at a rate of -4.430 kg/yr when t is close to 0.

W'(0) = -4.430 kg/yr

Let's first find the first and second derivatives of the given weight function W(t) = 25.6(1 - -0.211)³.

a. Differentiate this weight function:

W'(t) = d(W(t))/dt = d(25.6(1 - -0.211)³)/dt = 25.6 * 3(1 - -0.211)² * -0.211

W'(t) = -16.032(1.211)² * 0.211

b. Find its second derivative:

W"(t) = d(W'(t))/dt = d(-16.032(1.211)^2 * 0.211)/dt = -16.032 * 2(1.211) * 0.211²

W"(t) = -6.755 * 0.211²

Now, we want to find the points of inflection, which occur when the second derivative W"(t) equals zero:

-6.755 * 0.211² = 0

However, this equation has no positive solution for t since -6.755 * 0.211² is always negative. Therefore, there are no points of inflection for t > 0.

To find the most rapid rate of growth, we can find the maximum value of the first derivative W'(t). Since there are no points of inflection, we can examine the behavior of W'(t) as t increases:

As t becomes larger, (1.211)² will approach 0, and therefore W'(t) will approach 0 as well. This means that the most rapid rate of growth occurs when t is close to 0.

W'(0) = -16.032(1.211)² * 0.211 = -4.430 kg/yr

So, the trout is gaining weight most rapidly at a rate of -4.430 kg/yr when t is close to 0.

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The equivalent expression for the given expression is \(\frac{2.3^{15}}{0.9^{12}}\). Therefore, option D is the correct answer.

The given expression is \((\frac{2.3^{5} }{0.9^{4} } )^{3}\).

We need to find the equivalent expression for the given expression.

Equivalent expressions are expressions that work the same even when they seem different. When we enter the same value for the variable, two algebraic expressions that are equivalent have the same value.

Use \((\frac{a}{b} )^{m}=\frac{a^{m}}{b^{m}}\) and \((a^{m} )^{n}=a^{m\times n}\) to solve the given expression.

Now, \((\frac{2.3^{5} }{0.9^{4} } )^{3}=\frac{(2.3^{5})^{3} }{(0.9^{4})^{3} }\)

\(=\frac{(2.3^{5\times3})}{(0.9^{4\times3})}\)

\(=\frac{2.3^{15}}{0.9^{12}}\)

The equivalent expression for the given expression is \(\frac{2.3^{15}}{0.9^{12}}\). Therefore, option D is the correct answer.

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Answer:

57.603

Step-by-step explanation:

We can separate this into two sections, using the and:

Fifty-seven - simply the whole number 57

Six hundred three thousandths - This could be intrepreted as 0.603, which is confirmed through the "3" being in the thousandths place.

Sorry that took so long! I had to think a bit about this one

Answer:

20 squared + 35 squared = d squared

Step-by-step explanation:

The Pythagorean theorem a^2+b^2=c^2

Answer:

a

Step-by-step explanation:

got right on edge

The probability of washing dishes by me tonight will take between 15 and 16 minutes is 14.29%.

The term "uniform distribution" refers to a type of probability distribution in which the likelihood of each potential result is equal.

Let's consider, the lower limit for this distribution as a and the upper limit for this distribution as b.

The following formula gives the likelihood that we will discover a value for X between c and d,

\(P(c\leq X\leq d)=\frac{d-c}{b-a}\)

Given the time it takes me to wash the dishes is 11 minutes and 18 minutes. From this, a = 11 and b = 18.

Then,

\(P(15\leq X\leq 16)=\frac{16-15}{18-11}=0.1429=14.29\%\)

The answer is 14.29%.

The complete question is -

The time it takes me to wash the dishes is uniformly distributed between 11 minutes and 18 minutes. What is the probability that washing dishes tonight will take me between 15 and 16 minutes?

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Answer:

A.) w² + 3w in²

B.) 28 in²

Step-by-step explanation:

A.)

Let w = width and l = length.

    The area of a rectangle can be written as length · width (base · height). The problem informs us that the length of the rectangle is 3 inches greater than the width. Therefore, l can also be written as w + 3. We can use this to form a polynomial that represents the area of the rectangle.

A(rectangle) = lw = (w + 3) · w = w² + 3w

B.)

Use the polynomial we previously found to find the area.

A(rectangle) = (4)² + 3(4) = 16 + 12 = 28 in²

Model:

The statement "the number is an eigenvalue of a constant matrix is a corresponding eigenvector" is not necessarily true.

The eigenvalue of a matrix is a scalar value that, when multiplied by the corresponding eigenvector, yields the same vector as the result of the matrix-vector multiplication. In other words, the eigenvector is a non-zero vector that does not change direction when multiplied by the matrix.

A fundamental set of solutions for a linear differential system is a set of linearly independent solutions that can be combined to form any solution of the system. The solutions are typically obtained by finding the eigenvalues and eigenvectors of the coefficient matrix of the system. If the matrix has n distinct eigenvalues, then the system has n linearly independent solutions. These solutions can be combined using a linear combination to obtain any solution of the system.

In summary, the eigenvalue of a constant matrix is not necessarily a corresponding eigenvector. However, a fundamental set of solutions for a linear differential system can be obtained by finding the eigenvalues and eigenvectors of the coefficient matrix of the system.

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Given:

Sample size = 75 students

Students who spend less than 10 minutes on homework each night = 21

Total students in the school = 1500

To find:

Estimated number of students who would say they spend less than 10 minutes in homework each night.

Solution:

Let A be the event that the student spends less than 10 minutes in homework each night.

Then, the probability that the student spends less than 10 minutes in homework each night is

\(P(A)=\dfrac{\text{Students who spend less than 10 minutes on homework}}{\text{Sample size}}\)

\(P(A)=\dfrac{21}{75}\)

\(P(A)=\dfrac{7}{25}\)

Now, total students in the school is 1500. So, multiply 1500 with P(A) to get the umber of students who would say they spend less than 10 minutes in homework each night.

\(1500\cdot P(A)=1500\times \dfrac{7}{25}\)

\(1500\cdot P(A)=420\)

Therefore, estimated number of students who would say they spend less than 10 minutes in homework each night is 420.

The probability of exactly 3 out of 20 Legacy models having a faulty fuel pump is approximately 20.35%.

To solve the probability of finding exactly 3 Legacy models with faulty fuel pumps, we use the binomial distribution. This is because we have a fixed number of trials, 20, and each trial is independent with only two possible outcomes (either the Legacy model has a faulty fuel pump or it doesn't).The formula for the binomial distribution is given by:P(x) = (nCx) * p^x * (1-p)^(n-x)Where:P(x) is the probability of exactly x successes in n trialsp is the probability of success in one trialq is the probability of failure in one trial (q = 1-p)nCx is the number of combinations of n things taken x at a time.

To solve the problem, we first need to find the probability of a Legacy model having a faulty fuel pump. This is given as 12% or 0.12 in decimal form. Therefore, the probability of a Legacy model not having a faulty fuel pump is 1-0.12 = 0.88.The probability of finding exactly 3 Legacy models with faulty fuel pumps is:P(3) = (20C3) * 0.12^3 * 0.88^17where 20C3 = (20!)/[(20-3)!3!] = 1140Therefore:P(3) = 1140 * (0.12)^3 * (0.88)^17≈ 0.2035 or 20.35%Therefore, the probability of exactly 3 out of 20 Legacy models having a faulty fuel pump is approximately 20.35%.

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The study described can be classified as an experiment as dogs are randomly assigned to two different training groups (food reward and sound cues) and their obedience is measured after 2 months.

An experiment involves the manipulation of variables to observe the effect on an outcome. In this study, dogs are randomly divided into two groups, with one group being trained using food as a reward and the other group being trained using sound cues. The random division of dogs into these groups ensures that any differences observed in obedience between the two groups can be attributed to the training method rather than other factors.

After the dogs have undergone training for 2 months, their obedience is measured. By comparing the obedience levels of the two groups, the researchers can determine the effectiveness of the different training methods in achieving the desired outcome.

The use of random assignment and the manipulation of training methods make this study an experiment, as it allows for the evaluation of cause-and-effect relationships between the training methods and the dogs' obedience.

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The SI units for the quantities you mentioned are:

1. Length: The SI unit for length is the meter (m).

2. Mass: The SI unit for mass is the kilogram (kg).

3. Time: The SI unit for time is the second (s).

4. Electric current: The SI unit for electric current is the ampere (A).

5. Amount of substance: The SI unit for the amount of substance is the mole (mol).

6. Temperature: The SI unit for temperature is the kelvin (K).

7. Luminous intensity: The SI unit for luminous intensity is the candela (cd). An angstrom (symbol: Å) is a unit of length equal to 10^(-10) meters or 0.1 nanometers. It is often used to express the sizes of atoms and molecules.

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The probability that a sequence will contain exactly one 0 is 3/8.

Probability is the branch of mathematics concerning numerical descriptions of how likely an event is to occur, or how likely it is that a proposition is true. The probability of an event is a number between 0 and 1,

We should consider sequences of three digits, where each digit is either 0 or 1. A sequence has three places .

where each place has two possibilities, i.e., 0 or 1, so, for the multiplication rule

we know that the sample space will have (2)(2)(2) = 8 sample points.

Specifically, the sample space is

S = {111, 110, 101, 011, 100, 010, 001, 000},

There are three sequences with exactly one 0.

Therefore the probability that a sequence will contain exactly one 0 is 3/8.

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The tax rate on the business office was 0.08. To calculate the tax rate, we divide the property taxes by the value of the property.

In this case, the property taxes were $2160 and the value of the property was $270,000. Therefore, the tax rate is 0.08.

Tax rate = Property taxes / Value of property

= $2160 / $270,000

= 0.08

The first step is to divide the property taxes by the value of the property. This gives us a decimal value of 0.08.

The second step is to convert the decimal value to a percentage by multiplying it by 100%. This gives us the final answer of 8%.

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The probability that the Bulls would get 4 wins is 0.311, the probability that the Knicks would get 4 wins is 0.088, and the probability this series goes to 7 games is 0.384.

Given that the Bulls had a 60% chance of winning, we can calculate the probabilities as follows:

Probability of the Bulls winning 4 games: (0.6)^4*(0.4)^3*(nCr(7,4)) = 0.311

Probability of the Knicks winning 4 games: (0.4)^4*(0.6)^3*(nCr(7,4)) = 0.088

Probability that the series goes to 7 games: (nCr(6,3) + nCr(6,4) + nCr(6,5) + nCr(6,6))*(0.6)^3*(0.4)^3 = 0.384

Therefore, the probability that the Bulls would get 4 wins is 0.311, the probability that the Knicks would get 4 wins is 0.088, and the probability this series goes to 7 games is 0.384.

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Answer:

The scale factor would be -5.

Step-by-step explanation:

If the driveway is 20 feet but 4 foot on the canvas. Then 20/4 is 5. But since the width is going from 20 to 4, the numbers are going down to it would be a negative scale factor. If it was going from 4 width to 20 width, the scale factor would be a positive 5.

Answer:

x>4

Step-by-step explanation:

Answer:

the answer is of this question R = 10

Answer:

The answer is 6%

Step-by-step explanation:

\(65.99 - 59.99 = \frac{6 \times 100}{100} = 6\%\)

Question 1: The item not included in the cost of merchandise inventory is "Purchase discounts."

2: The total cost of the merchandise is $3,332.00.

5: The company's gross margin and operating expenses, are $211,000 and $191,720.

Merchandise inventory expenses normally consist of the price paid for the inventory, deductions from the purchase price resulting from purchase returns and allowances, and freight expenses paid by the purchaser.

Although purchase discounts reduce the cost of merchandise inventory, they are not considered part of it. Instead, they are treated as a distinct discount in the accounting records.

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Answer:  more than y :    

                     y + 6

3 times a number:

x ← a number    

                          3x

5 less than the product of 10 and c :

10c   ← the product of 10 and c

                                        10c - 5

14 more than 6 times t :

6t  ← six times t

                       6t + 14

The sum of x and y is 18:

x+y    ← the sum of x and y

                                 x + y = 18

A number minus 12 is y:

x - a number

                  x - 12 = y              

Answer:

See below

Step-by-step explanation:

Here is translation for you

5 less than the product of 10 and c

14 more than 6 times t

The sum of x and y is 18

A number minus 12 is 17

Categorical charts are useful in displaying nominal data or numerical data that splits nicely into different categories so you can quickly see comparative results and trends.

The type of chart that is useful in displaying nominal data or numerical data that splits nicely into different categories is called a categorical chart. Categorical charts allow you to quickly see comparative results and trends by displaying data in separate categories or groups. This makes it easier to identify patterns and trends in the data and to draw conclusions about the relationships between different variables.

Examples of categorical charts include bar charts, column charts, and pie charts. Bar charts and column charts are commonly used to display numerical data, while pie charts are often used to display proportional data. Categorical charts can be used in a variety of contexts, such as business, education, and scientific research, to help communicate complex data in a clear and concise manner.

Overall, categorical charts are a powerful tool for organizing and displaying data in a way that makes it easy to identify patterns and trends. By using these charts, you can quickly and accurately visualize complex data sets and draw conclusions about the relationships between different variables.

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