If a material conducts heat easily, it is a good__________________. The answer has to be 18 letters long please type in the right answer please and tank you
Please answer if you know it I need this today this question is only for people who have done it or they know the answer. Please answer this I need to know the answer please and thank you have a good day! It would be amazing if I got an A+ on my final test! PLEASE HELP AND PLEASE ANSWER IF YOU KNOW THE ANSWER PLEASE HELP!!!!!!!!!!

AND DO NOT PUT IT ON NO FILE OR NOTHING PLEASE AND I MEAN IT PLEASE DON'T I CAN'T OPEN IT PLEASE DON'T PUT ANSWER ON FLIE PLEASE!!!!!!!!!!!!!!!

The volume of \(H_2S\)collected at 32°C when the atmospheric pressure was 749 torr is approximately 0.0231 liters.

To calculate the volume of \(H_2S\)collected, we need to use the ideal gas law equation:

PV = nRT

Where:

P = total pressure (in torr)

V = volume of gas (in liters)

n = number of moles of gas

R = ideal gas constant (0.0821 L·atm/(mol·K))

T = temperature (in Kelvin)

First, let's calculate the number of moles of \(H_2S\)produced. From the balanced chemical equation, we see that 1 mole of CuS reacts to produce 1 mole of \(H_2S\). Given the molar mass of CuS (63.5 g/mol) and the mass of CuS (4.22 g), we can calculate the number of moles:

moles of CuS = mass of CuS / molar mass of CuS

moles of CuS = 4.22 g / 63.5 g/mol

moles of CuS ≈ 0.0664 mol

Since the reaction produces 1 mole of \(H_2S\)for every mole of CuS, the number of moles of \(H_2S\)is also 0.0664 mol.

Next, let's convert the temperature from Celsius to Kelvin:

T(K) = T(°C) + 273.15

T(K) = 32°C + 273.15

T(K) ≈ 305.15 K

Now, we can calculate the partial pressure of \(H_2S\)using Dalton's law of partial pressures:

Partial pressure of \(H_2S\)= Total pressure - Vapor pressure of water

Partial pressure of \(H_2S\)= 749 torr - 36 torr

Partial pressure of \(H_2S\)≈ 713 torr

Finally, we can rearrange the ideal gas law equation to solve for the volume:

V = (nRT) / P

V = (0.0664 mol * 0.0821 L·atm/(mol·K) * 305.15 K) / 713 torr

V ≈ 0.0231 L

for more such question on atmospheric pressure

https://brainly.com/question/19587559

#SPJ8

Answer:

Calcium hydroxide is a white precipitate, too, and it won't dissolve if more sodium hydroxide is added to the solution. No significant precipitate will be formed between calcium ions and ammonia.

The rate of a chymotrypsin-catalyzed reaction will increase by using more

enzyme in the reaction mixture.

The rate of a chemical reaction and the enzyme concentration have a direct

relationship. As concentration increases, the rate of a chemical reaction  

also increases and vice versa.

In this scenario, we were told more enzyme was used in the reaction mixture

which signifies an increase in the concentration and a corresponding

increase in the rate of reaction.

Read more on https://brainly.com/question/12330608

The correct option is 2.

A 88

B 94

C 100

To solve this problem, we need to use our knowledge of how streams flow and how velocity changes in different parts of the stream.

Typically, streams flow fastest in the center of the channel and slowest along the edges, due to friction with the banks and bottom of the stream.

Given that it lies in the middle of the stream's two extreme velocities, option 2, which equals 94, is probably the right response. The velocity near the channel's middle is probably closer to 100 because the stream runs there the quickest.

On the other hand, it is likely that the velocity near the edges is closer to 88 since the stream runs more slowly along the edges due to friction with the banks and streambed. Consequently, a velocity of 94 is the most logical choice because it is within the range that is  predicted by the velocity distribution of a stream.

Learn more about streams at:

https://brainly.com/question/14012546

#SPJ1

The pH of an aqueous solution is defined as the negative of the logarithm of the concentration of H ion in the solution is 0.7 .

What is meant by logarithm ?

To learn more about logarithm refer to

https://brainly.com/question/25710806

#SPJ4

The amount, in kJ, of heat needed to completely vaporize 50.0g of water at 100°C is 118.8 kJ.

The heat needed to completely vaporize 50.0g of water at 100°C can be calculated using the following formula:

q = m x Hv

where:

First, we need to convert 50.0g to moles by dividing by the molar mass of water which is approximately 18.015 g/mol3:

moles of water = 50.0 g / 18.015 g/mol moles of water = 2.776 mol

Thus:

q = (2.776 mol) x (40.65 kJ/mol) q = 112.8 kJ

In other words, 112.8 kJ of heat is needed to completely vaporize 50.0g of water at 100°C.

More on heat of vaporization can be found here: https://brainly.com/question/12625048

#SPJ1

Answer:

1.) 17.76 moles H₂O

2.) 323.1 g HCN

Explanation:

1.) An equation is balanced when there is an equal amount of each element on both sides of the reaction. The quantities can be modified by adding coefficients in front of the molecules.

The unbalanced equation:

Al₄C₃(s) + H₂O -----> Al(OH)₃(s) + CH₄(g)

Reactants: 4 aluminum, 3 carbon, 2 hydrogen, 1 oxygen

Products: 1 aluminum, 1 carbon, 7 hydrogen, 3 oxygen

The balanced equation:

Al₄C₃(s) + 12 H₂O -----> 4 Al(OH)₃(s) + 3 CH₄(g)

Reactants: 4 aluminum, 3 carbon, 24 hydrogen, 12 oxygen

Products: 4 aluminum, 3 carbon, 24 hydrogen, 12 oxygen

Now that the equation is balanced, you can use the relevant coefficients to construct a mole-to-mole ratio. This will allow you to convert between moles Al₄C₃ to moles H₂O.

 1.48 moles Al₄C₃           12 moles H₂O
----------------------------  x  ------------------------  =  17.76 moles H₂O
                                         1 mole Al₄C₃

2.) To find the mass of HCN, you need to (1) convert grams NH₃ to moles NH₃ (via molar mass), then (2) convert moles NH₃ to moles HCN (via mole-to-mole from equation coefficients), and then (3) convert moles HCN to grams HCN (via molar mass). It is important to arrange the coefficients in a way that allows for the cancellation of units.

Molar Mass (NH₃): 14.009 g/mol + 3(1.008 g/mol)

Molar Mass (NH₃): 17.033 g/mol

Molar Mass (HCN): 1.008 g/mol + 12.011 g/mol + 14.009 g/mol

Molar Mass (HCN): 27.028 g/mol

2 CH₄(g) + 3 O₂(g) + 2 NH₃(g)  ------> 2 HCN(g) + 6 H₂O(g)

203.6 g NH₃            1 mole            2 moles HCN           27.028 g
---------------------  x  ----------------  x  ------------------------  x  -----------------  =
                                17.033 g           2 moles NH₃             1 mole

=  323.1 g HCN

Explanation:

The molar mass of octane (C8H18) is approximately 114 g/mol.

To find the energy required to increase 1 mole of substance by 10°C, we can use the formula:

ΔE = n * C * ΔT

where ΔE is the energy required, n is the number of moles, C is the specific heat, and ΔT is the change in temperature.

For water, n = 1 mol, C = 4.184 J/gK, and ΔT = 10°C.

So, the energy required to increase 1 mole of water by 10°C is:

ΔE_water = n * C_water * ΔT

= 1 mol * 4.184 J/gK * 10 K

= 41.84 J

For octane, n = 1 mol, C = 2.22 J/gK, and ΔT = 10°C.

So, the energy required to increase 1 mole of octane by 10°C is:

ΔE_octane = n * C_octane * ΔT

= 1 mol * 2.22 J/gK * 10 K

= 22.2 J

Therefore, it takes more energy to increase 1 mole of water by 10°C than 1 mole of octane.

Answer: The partial pressure of nitrogen gas if the total pressure is 111.7 atm is 88.243 atm.

Explanation:

Given: Mole fraction of oxygen = 0.21

Total pressure = 111.7 atm

It is known that the sum of moles fractions is always equal to 1. So, mole fraction of nitrogen is calculated as follows.

Mole fraction of nitrogen + mole fraction of oxygen = 1

Mole fraction of nitrogen = 1 - mole fraction of oxygen

Mole fraction of nitrogen = 1 - 0.21

Mole fraction of nitrogen = 0.79

Now, formula used to calculate the partial pressure of nitrogen is as follows.

\(P_{N} = X_{N} \times P_{total}\)

where,

\(P_{N}\) = partial pressure of nitrogen

\(X_{N}\) = mole fraction of nitrogen

\(P_{total}\) = total pressure

Substitute the values into above formula as follows.

\(P_{N} = X_{N} \times P_{total}\\= 0.79 \times 111.7 atm\\= 88.243 atm\)

Thus, we can conclude that the partial pressure of nitrogen gas if the total pressure is 111.7 atm is 88.243 atm.

To determine the temperature of the air inside the tire when the pressure increases to 87.3 kPa, we can use the ideal gas law equation:

PV = nRT

Where:

P = pressure

V = volume

n = number of moles

R = gas constant

T = temperature

Assuming the volume of the tire remains constant, we can rearrange the equation as follows:

P₁/T₁ = P₂/T₂

Where:

P₁ = initial pressure (82.0 kPa)

T₁ = initial temperature (26.0 °C + 273.15 K) [converting Celsius to Kelvin]

P₂ = final pressure (87.3 kPa)

T₂ = final temperature (unknown)

Substituting the values into the equation:

82.0 kPa / (26.0 °C + 273.15 K) = 87.3 kPa / T₂

Now, let's solve for T₂:

T₂ = (87.3 kPa * (26.0 °C + 273.15 K)) / 82.0 kPa

Calculating the expression:

T₂ ≈ 299.19 K

To convert this temperature back to Celsius:

T₂ ≈ 299.19 K - 273.15 ≈ 26.04 °C

Therefore, the temperature of the air inside the tire, when the pressure increases to 87.3 kPa, is approximately 26.04 °C.

To know more about pressure:

https://brainly.com/question/30673967

#SPJ1

Answer:

0.364

Explanation:

Let's do an equilibrium chart for the reaction of combustion of ammonia:

2NH₃(g) + (3/2)O₂(g) ⇄ N₂(g) + 3H₂O(g)

4.8atm 1.9atm 0 0 Initial

-2x -(3/2)x +x +3x Reacts (stoichiometry is 2:3/2:1:3)

4.8-2x 1.9-(3/2)x x 3x Equilibrium

At equilibrium the velocity of formation of the products is equal to the velocity of the formation of the reactants, thus the partial pressures remain constant.

If pN₂ = 0.63 atm, x = 0.63 atm, thus, at equilibrium

pNH₃ = 4.8 - 2*0.63 = 3.54 atm

pO₂ = 1.9 -(3/2)*0.63 = 0.955 atm

pH₂O = 3*0.63 = 1.89 atm

The pressure equilibrium constant (Kp) is calculated with the partial pressure of the gases substances:

Kp = [(pN₂)*(pH₂O)³]/[(pNH₃)²*]

Kp = [0.63*(1.89)³]/[(3.54)²*]

Kp = 4.2533/11.6953

Kp = 0.364

Answer:

Option 4, \(O^{2-}\)

Explanation:

Step 1:  Determine which option is correct

We know that Ne has 10 electrons therefore we need to find a different ion that has the same amount.  

Option 1 → Ca has 20 electrons and with 2+ we would remove 2 of those which would leave us with 18.

Option 2 → Cl has 17 electrons and with a - we would add 1 of those which would leave us with 18.

Option 3 → Li has 3 electrons and with a + we would remove 1 of those which would leave us with 2.

Option 4 → O has 8 electrons and with a 2- we would add 2 of those which would leave us with 10.  

Since the only one that matches up in the number of electrons is \(O^{2-}\) we can conclude that option 4 is correct.

Answer:  Option 4, \(O^{2-}\)

An example of heterogeneous equilibrium is:

Heterogeneous equilibrium refers to an equilibrium state in a chemical reaction where the reactants and products exist in different physical states or phases. It occurs when substances in different phases, such as solids, liquids, and gases, are involved in a chemical reaction.

Considering the given equations:

The equation I: FeO(s) + CO(g) ⇌ Fe(s) + CO₂(g) represents a heterogeneous equilibrium.

This is because the reactants and products involve different phases (solid and gas). FeO is a solid (s), CO is a gas (g), Fe is a solid (s), and CO₂ is a gas (g). The reaction involves the conversion of a solid and a gas to another solid and a gas, and the equilibrium is established between these different phases.

Learn more about heterogenous equilibrium at: https://brainly.com/question/25257772

#SPJ1

Answer:

The disadvantages of each of the given model of electron configuration have been mentioned below:

1). Dot Structures - They take up excess space as they do not display the electron distribution in orbitals.

2). Arrow and line diagrams make the counting of electrons and take up too much space.

3). Written Configurations do not display the electron distribution in orbitals and help in lose counting of electrons easily.

Advantages:

-Dot structures make it easy to count electrons and they show the number of electrons in each electron shell.

-Arrow and line diagrams show the spin of electrons and show every orbital.

-Written configurations require minimal space and show the distribution of electrons between subshells.

When two iron bars at different temperatures are placed in thermal contact, the rate of heat exchange can vary depending on whether the system is isolated or open.

If the iron bars were placed in thermal contact in an open system instead of an isolated system, the results would be different due to the exchange of energy with the surroundings. In an open system, energy can be transferred between the system and the surroundings, typically in the form of heat.

When the iron bars are in thermal contact, heat will flow from the hotter bar to the cooler bar until they reach thermal equilibrium. In an open system, the heat transferred from the hotter bar will not be retained within the system but will instead be dissipated into the surroundings. Similarly, the cooler bar will absorb heat from the surroundings. This continuous exchange of heat with the surroundings will affect the rate of temperature change in the bars.

In the given scenario, where the room temperature is 25°C, when the iron bars are in contact, the hotter bar at 200°C will lose heat to the surroundings, and the cooler bar at 120°C will absorb heat from the surroundings. This heat exchange with the surroundings will slow down the rate at which the bars reach thermal equilibrium.

Therefore, in an open system, after 30 minutes of thermal contact, the iron bars may not reach the exact temperature of 160°C as they did in the isolated system. The final temperature of the bars would depend on the rate of heat exchange with the surroundings and the difference in temperature between the bars and the surroundings.

Know more about   temperatures    here:

https://brainly.com/question/4735135

#SPJ8

The balanced equation is: 4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

The given chemical equation is unbalanced. To balance it, we need to adjust the coefficients in front of each chemical species until the number of atoms on both sides of the equation is equal.

The unbalanced equation is:

2 \(H_2S\)+ 3 \(O_2\)→ \(SO_2\)

Let's start by balancing the sulfur (S) atoms. We have two sulfur atoms on the left side and one sulfur atom on the right side. To balance the sulfur, we can place a coefficient of 2 in front of the \(SO_2\):

2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)

Now, let's balance the hydrogen (H) atoms. We have four hydrogen atoms on the left side (2 from each \(H_2S\)) and none on the right side. To balance the hydrogen, we can place a coefficient of 4 in front of the water (H2O) on the right side:

2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)

Finally, let's balance the oxygen (O) atoms. We have six oxygen atoms on the right side (3 from \(O_2\) and 3 from 2 \(SO_2\)) and three on the left side (2 from \(H_2S\)). To balance the oxygen, we can place a coefficient of 3/2 in front of the O2:

2 \(H_2S\)+ (3/2) \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)

To remove the fractional coefficient, we can multiply all coefficients by 2:

4 \(H_2S\) + 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

Now the equation is balanced, with an equal number of atoms on both sides. The balanced equation is:

4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

For more such questions on  balanced equation visit:

https://brainly.com/question/23877810

#SPJ8

The heat of reaction when a sodium chloride solution is formed using a 10.0 g sample of NaCl(s) and 50.0 ml of water in a coffee cup calorimeter. The equation is :

E. q = ((60.0 g)(4.18 J/g K)(T f - T i))/(10.0 g/(58.44 g/mol))

Given that :

The mass of the NaCl = 10 g

The volume of sample = 50 mL

The molar heat of the reaction for NaCl ( sodium chloride ) = + 3.9 kJ/mol

The equation for the heat is given as :

q = m c ΔT

Where,

q = heat energy

m = mass

c = specific heat capacity

ΔT = change in temperature

Therefore the equation is given as :

q = m c ΔT

q = ( 50 g + 10 g) (4.184 J/g °C) (T f - T i)

q / mol = q water / mol NaCl

q = ((60.0 g)(4.18 J/g K)(T f - T i)) / (10.0 g/(58.44 g/mol))

The given question is incomplete, the complete question is :

You want to determine the molar heat of solution of sodium chloride using a 10.0 g sample of NaCl(aq) and 50.0 mL of water in a coffee cup calorimeter. Which of the following equations would you use? Assume the specific heat of the solution is the same as the specific heat of water.

A. q = (50.0 g)(4.18 J/g K)(T i - T f)

B. q = ((10.0 g)(4.18 J/g K)(T f - T i))/(10.0 g/(58.44 g/mol))

C. q = (60.0 g)(4.18 J/g K)(T f - T i)

D. q = (60.0 g)(4.18 J/g K)(T i - T f)

E. q = ((60.0 g)(4.18 J/g K)(T f - T i))/(10.0 g/(58.44 g/mol))

To learn more about heat here

https://brainly.com/question/16267186

#SPJ4

Answer:

\(m_{Al}=3.38gAl\)

\(Y=83.1\%\)

Explanation:

Hello.

In this case, for the given balanced reaction:

\(Fe_2O_3(s) + 2Al(s)\rightarrow 2Fe(s) + Al_2O_3(s)\)

For 10.0 g of iron (III) oxide (molar mass = 160 g/mol), based on the 1:2 mole ratio with Al (atomic mass = 27 g/mol), the required mass is then:

\(m_{Al}=10.0gFe_2O_3*\frac{1molFe_2O_3}{160gFe_2O_3} *\frac{2molAl}{1molFe_2O_3} *\frac{27gAl}{1molAl} \\\\m_{Al}=3.38gAl\)

Moreover, as 5.3 g of aluminum oxide are actually yielded, from the 10.0 g of iron (III) oxide, we can compute the theoretical mass of aluminum oxide (molar mass = 102 g/mol) via their 1:1 mole ratio:

\(m_{Al_2O_3}=10.0gFe_2O_3*\frac{1molFe_2O_3}{160gFe_2O_3} *\frac{1molAl_2O_3}{1molFe_2O_3} *\frac{102gAl_2O_3}{1molAl_2O_3} \\\\m_{Al_2O_3}=6.38gAl_2O_3\)

Thus, the percent yield (actual/theoretical*100%) turns out:

\(Y=\frac{5.3 g}{6.38 g}* 100\%\\\\Y=83.1\%\)

Best regards.

Air escape from a tire when tire valve is opened because the pressure from the weight of the car is forcing the already pressurized air out .

When air is filled in tires, it get into more compact area than the outer atmosphere, therefore particles in tire are close to each other and exert pressure continuously on tire walls to get out of it. Thus, material of the tire need to be pressure resistant as much possible.

After opening the tire valve, air starts leaving with huge sound as strain outside the tire is weaker than that inside the tire. Molecules strike with the same force on larger area and pressure starts diminishing.

To know more about tire valve, refer

https://brainly.com/question/3720473

#SPJ1

Note: The question given on the portal is incomplete. Here is the complete question.

Question: Air leaves a tire when the tire valve is opened because

A. the pressure outside the tire is lower than the pressure inside the tire.

B. the pressure outside the tire is greater than the pressure inside the tire.

C. the temperature is higher outside the tire than inside the tire.

D. there are more gas particles outside the tire than inside the tire.

The balanced equation for the reaction is as follows:

3 AI2O3 (s) + 3C (s) + 2CI2 (g) → 3AICI3 (s) + 3CO (g)

Combination reactions happen when two or more reactants come together to create a single product. In this instance, the reactants are chlorine gas, carbon, and aluminium oxide (AI2O3) (CI2). Aluminum chloride (AICI3) and carbon monoxide make up the final product (CO). Exothermic means that energy is released when the reactants come together in this reaction. Both heat and light are manifestations of this energy. The bonds between the atoms in the reactants are broken and new bonds between the atoms in the product are formed when the reactants combine. The reaction is exothermic because of the energy released during this process.

learn more about exothermic Refer:brainly.com/question/4345448

#SPJ1

Answer:

Cr(OH)2(s), Na+(aq), and NO3−(aq)

Explanation:

Let is consider the molecular equation;

2NaOH(aq) + Cr(NO3)2(aq) -----> 2NaNO3(aq) + Cr(OH)2(s)

This is a double displacement or double replacement reaction. The reacting species exchange their partners. We can see here that both the sodium ion and chromium II ion both exchanged partners and picked up each others partners in the product.

Sodium ions and nitrate ions now remain in the solution while chromium II hydroxide which is insoluble is precipitated out of the solution as a solid hence the answer.

These are reactions that transfer energy to the surroundings (ie the energy exits from the reaction, hence the name exothermic). The energy is usually transferred as heat energy, causing the reaction mixture and its surroundings to become hotter. A thermometer is used to detect the temperature increase.

Examples:

Combustion

Neutralisation between acids and alkali

These are reactions that take in energy from the surroundings (ie energy enters the reaction, which will help you to remember the name endothermic). The energy is usually transferred as heat energy, causing the reaction mixture and its surroundings to become colder. A thermometer is used to detect the temperature decrease.

Example:

Electrolysis

Answer:

More common near convergent boundaries

Explosive Eruptions

Low Viscosity Magma

Explanation:

Hot spots like hawaii are better known for shield volcanoes. The magma is high viscosity which causes them to build pressure before erupting, leading to explosive eruptions.

Answer:80.8g

Explanation:

 = . / ()

The name of the aromatic hydrocarbon shown in the photo is 1,4-dimethylbenzene.

Xylene, xylol or dimethylbenzene is a derivative of benzene. It is made up of carbon and hydrogen. It is a colorless, flammable liquid with a toluene-like odor. This aromatic hydrocarbon is a good solvent, we find it in many fuel formulations.

This aromatic hydrocarbon is found in different substances such as some oils, in coke gases (combustible gases that have a luminous flame when burned) and in gases obtained from the distillation of wood.

Xylenes are substances that can affect the functions of living beings, their vapors can give different symptoms such as nausea, headache and discomfort.

Therefore, we can confirm that the name of the aromatic hydrocarbon shown in the photo is 1,4-dimethylbenzene.

To learn more about xylenes visit: https://brainly.com/question/27860606?referrer=searchResults

#SPJ1

The pOH of the 0.001 M NaOH solution is approximately 3.

To determine the pOH of a solution, we need to know the concentration of hydroxide ions (OH-) in the solution.

In the case of a 0.001 M NaOH solution, we can assume that all of the NaOH dissociates completely in water to form Na+ and OH- ions. Therefore, the concentration of hydroxide ions in the solution is also 0.001 M.

The pOH is calculated using the equation:

pOH = -log[OH-]

Substituting the concentration of hydroxide ions, we have:

pOH = -log(0.001)

Using a calculator, we can evaluate the logarithm:

pOH ≈ 3

Therefore, the pOH of the 0.001 M NaOH solution is approximately 3.

Know more about  hydroxide ions   here:

https://brainly.com/question/28464162

#SPJ8

Answer:

no of moles=mass in gm÷molar mass so let x be the mass in gm

4.5=x÷35.5×2

x=4.5×35.5×2 grams

x=319.5 gm

Explanation:

formula