If a snowboarder’s initial speed is 4 m/s and comes to rest when making it to the upper level. With a slightly greater initial speed of 5 m/s, the snowboarder is moving to the right on the upper level. His final speed in this case is 3 m/s. Suppose this situation is repeated on planet Epsilon, where gravity is less than gravity on earth.
A. Would the height of the hill on Epsilon cause a reduction in speed from 4 m/s to 0 greater than, less than, or equal to the height of the corresponding hill on earth? Explain.
B. Consider the hill on Epsilon discussed in part A. If the initial speed at the bottom of the hill is 5 m/s, will the final speed at the top of the hill be greater than, less than, or equal to 3 m/s? Explain.
Answers
(a) At a corresponding hill on Earth and a lesser gravity on planet Epslion, the height of the hill will cause a reduction in the initial speed of the snowboarder from 4 m/s to a value greater than zero (0).
(b) If the initial speed at the bottom of the hill is 5 m/s, the final speed at the top of the hill be greater than 3 m/s.
Conservation of mechanical energy
The effect of height and gravity on speed on the given planet Epislon is determined by applying the principle of conservation of mechanical energy as shown below;
ΔK.E = ΔP.E
¹/₂m(v²- u²) = mg(hi - hf)
¹/₂(v²- u²) = g(0 - hf)
v² - u² = -2ghf
v² = u² - 2ghf
where;
v is the final velocity at upper levelu is the initial velocityhf is final heightg is acceleration due to gravitywhen u² = 2gh, then v² = 0,
when gravity reduces, u² > 2gh, and v² > 0
Thus, at a corresponding hill on Earth and a lesser gravity on planet Epslion, the height of the hill will cause a reduction in the initial speed of the snowboarder from 4 m/s to a value greater than zero (0).
Final speedv² = u² - 2ghf
where;
u is the initial speed = 5 m/sg is acceleration due to gravity and its less than 9.8 m/s²v is final speedhf is equal heightSince g on Epislon is less than 9.8 m/s² of Earth;
5² - 2ghf > 3 m/s
Thus, if the initial speed at the bottom of the hill is 5 m/s, the final speed at the top of the hill be greater than 3 m/s.
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Related Questions
The figure below shows a box with a mass of m = 7.40 kg that starts from rest at point A and slides on a track with negligible friction. Point A is at a height of ha = 5.10 m. An illustration shows a wavy track, starting from a crest, moving to a trough, then again to a crest and trough, and finally to a crest that then moves downward. Three points in the track are highlighted, A, B, and C. Point A is at the top of the track where a box of mass m is placed ready to get released. It is at the height labeled ha from the ground. Point B is shown at the next crest and is at a height of 3.20 meters from the ground. Point C is shown at the following trough and is at a height of 2.00 meters from the ground. (a) What is the box's speed at point B (in m/s)? m/s What is the box's speed at point C (in m/s)? m/s (b) What is the net work (in J) done by the gravitational force on the box as it moves from point A to point C?
Answers
Work done by gravity when it moves from A to C will be 288.6 joule
How to calculate the valueApplying conservation of energy between point A and B,
7.4xgx5.9 = 1/2x7.4xv2 + 7.4xgx3.2
873.2 = 7.4v2 + 473.6
v = 7.34 m/s
It should be noted that to find velocity at C, which has come down to a height of 2 meter, it means it has travelled by 5.9-2 =3.9 m
so, v2 = 2gh = 20x3.9 =
v = 8.83 m/s
Work done by gravity when it moves from A to C = mxgx(5.9-2) = 288.6 joule
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bowling ball weighing 710 N attached to the ceiling by a rope of length 3.87 mThe ball is pulled to one side and released it then swings back and forth as a pendulum. As the rope swings through the vertical, the speed of the bowling ball is 4.51 m/s
What is the acceleration of the bowling ball, in magnitude and direction, at this instant?
What is the tension in the rope at this instant?
Answers
Answer:
a = 5.256 m / s² with the vertical direction upwards and T = 1090.8 N
Explanation:
to find the acceleration we must use Newton's second law, in the lowest part of the motion
T - W = m a
where the acceleration is centripetal
a = v² / r
let's calculate
a = 4.51² / 3.87
a = 5.256 m / s²
As the acceleration is centripetal it is directed towards the center of the circle, which in the lower part coincides with the vertical direction upwards.
Let's find the tension of the rope with the first equation
T = W + m a
W = m g
let's calculate
T = 710 + 710 5.256 / 9.8
T = 1090.8 N
Which component of an atom contains the MAJORITY
of its mass?
Answers
Answer:
proton and neutrons
Explanation:
electron has negligible mass
1. an object given an initial velocity,which can move under gravity and is affected by air resistance is an example of projectile motion
A.True. B.False
2.the horizontal component is always equal to the vertical component of the velocity
A.True B.False
3.The formula Vx=Vø tan Ø is used to determine the magnitude of the horizontal component of the velocity
A.True B.False
4.The velocity is directed vertically upward
A.True. B.False
5.when no air acts on a projectile,it's horizontal acceleration is upward gravity
A.True B.False
6.A stone thrown into the air is an example of projectile motion
A.True. B.False
7.The time to reach the top will be 1.5625s if. projectile is thrown at angle 30° above the ground with a velocity of 100ft/s
A.True B.False
Answers
2. B. False
3. A. True
4. B. False
5. B. False
6. A. True
7. B. False
Explanation:
1. The statement is true. Projectiles are objects that are launched into the air and then follow a curved path under the influence of gravity and air resistance.
2. The statement is false. The horizontal component of the velocity is independent of the vertical component of the velocity, and they can have different values.
3. The statement is true. The formula Vx=Vø tan Ø is the formula for the horizontal component of the initial velocity of a projectile.
4. The statement is false. The velocity of a projectile is directed at an angle to the horizontal, with both horizontal and vertical components.
5. The statement is false. When no air acts on a projectile, its horizontal acceleration is zero, because there is no force acting in the horizontal direction. The vertical acceleration is still due to gravity.
6. The statement is true. A stone thrown into the air follows a curved path under the influence of gravity, making it an example of projectile motion.
7. The statement is false. The time to reach the top of the projectile's path depends on the initial velocity and angle of launch, as well as the acceleration due to gravity. The time to reach the top can be calculated using the formula t = Vy/g, where Vy is the vertical component of the initialvelocity, g is the acceleration due to gravity, and t is the time. Using this formula, the time to reach the top of the projectile's path can be calculated as:
t = Vy/g = Vø sin Ø/g = (100 ft/s)(0.5)/(32.2 ft/s²) = 1.55 s (approx.)
Therefore, the statement is false.
Please answer all the questions.
Answers
in the life cycle of a star, the masses that begins as the nebula is huge globule of gas and dust.
What is the life cycle about?The masses that ends as black hole is stars with its final masses in the range from 2 to 3 solar masses.
The fuel for all stars is nuclear fusion of hydrogen to form heliumIn the first stage of the cycle, the Stars are said to be born in a region that is called high density Nebula.A star is said to be born as atoms of light elements are said to be folded under a lot of pressure for their nuclei to be able to undergo fusion.Nuclear fusion is known to be the reaction via which two or more light nuclei meet together to create a heavier nucleus.Note that if often condenses into a huge globule of gas and dust and it is said to widens under its own gravity.
Therefore, Stars starts in the nebula as gravity pulls dust and gas together with a lot of mass to create a protostar.
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A special spring is constructed in which the restoring force is in the opposite direction to the displacement but is proportional to the cube of the displacement; i.e., F= -kx^3
this spring is placed on a horizontal frictionless surface. One end of the spring is fixed, and the other end is fastened to a mass M. The mass is moved so that the spring is stretched a distance A and then released. Determine each of the following in terms of k, A, and M
a) The potential energy in the spring at the instant the mass is released
b) the maximum speed of the mass
c) The displacement of the mass at the point where the potential energy of the spring and the kinetic energy of the mass are equal
Answers
Answer:
Explanation:
a ) Restoring force in special spring F = k x³
let it is stretched by length l and it is further stretched by dl .
work done on spring in stretching by dl
= F dl
= k l³ dl
work done in stretching by A
= ∫k l³ dl between limit 0 to A
= k [ l⁴ / 4 ] between limit 0 to A
= k A⁴ / 4 ;
b )
Let v be the maximum speed attained ,
kinetic energy of mass = potential energy of spring
1/2 M v² = k A⁴ / 4
v² = kA⁴ / 2
v = A² √( k/2 )
c ) Let the required displacement be d .
potential energy = k d⁴ / 4
at displacement d , potential energy and kinetic energy are equal so potential energy = 1 /2 of total potential energy = 1/2 x k A⁴ / 4
= k A⁴ / 8
So
k A⁴ / 8 = k d⁴ / 4
\(d = A\times ( \frac{1}{2} )^\frac{1}{4}\)
A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. How much nonconservative work (in kJ) was done on the boy?
Answers
A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. The nonconservative work done on the boy is approximately -42.7 kilojoules.
To find the nonconservative work done on the boy, we need to consider the change in the boy's mechanical energy during the process. Mechanical energy is the sum of the boy's kinetic energy (KE) and gravitational potential energy (PE).
The initial mechanical energy of the boy is given by the sum of his kinetic energy and potential energy when he catches the wave:
E_initial = KE_initial + PE_initial
The final mechanical energy of the boy is given by the sum of his kinetic energy and potential energy after he drops through the height:
E_final = KE_final + PE_final
The nonconservative work done on the boy is equal to the change in mechanical energy:
Work_nonconservative = E_final - E_initial
Let's calculate each term:
KE_initial = (1/2) * m * v_initial^2
= (1/2) * 66.1 kg * (1.60 m/s)^2
PE_initial = m * g * h_initial
= 66.1 kg * 9.8 m/s^2 * 1.59 m
KE_final = (1/2) * m * v_final^2
= (1/2) * 66.1 kg * (8.51 m/s)^2
PE_final = m * g * h_final
= 66.1 kg * 9.8 m/s^2 * 0
Since the boy ends at ground level, the final potential energy is zero.
Substituting the values into the equation for nonconservative work:
Work_nonconservative = (KE_final + PE_final) - (KE_initial + PE_initial)
Simplifying:
Work_nonconservative = KE_final - KE_initial - PE_initial
Calculating the values:
KE_initial = (1/2) * 66.1 kg * (1.60 m/s)^2
PE_initial = 66.1 kg * 9.8 m/s^2 * 1.59 m
KE_final = (1/2) * 66.1 kg * (8.51 m/s)^2
Substituting the values:
Work_nonconservative = [(1/2) * 66.1 kg * (8.51 m/s)^2] - [(1/2) * 66.1 kg * (1.60 m/s)^2 - 66.1 kg * 9.8 m/s^2 * 1.59 m]
Calculating the result:
Work_nonconservative ≈ -42.7 kJ
Therefore, the nonconservative work done on the boy is approximately -42.7 kilojoules. The negative sign indicates that work is done on the boy, meaning that energy is transferred away from the boy during the process.
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A ball is thrown up into the air. When it gets to the very top,
what kind of energy does it have?
Answers
At the highest attitude, the velocity of the ball is 0 m/s, so the kinetic energy is 0 as well.
Hence the answer is potential energy because it doesn't depend on velocity .
What is one of the causes of mechanical weathering?
acid rain
oxidation
animal actions
carbon dioxide
Answers
The cause of mechanical weathering among the given options is animal actions. The correct answer is option C
WEATHERINGThis is the breaking down of rocks and minerals into particles of matters
There are three types of weathering. They are:
Physical weatheringchemical weatheringbiological weatheringThe one which is the cause of mechanical weathering among the given options is animal actions.
Therefore, the correct answer is option C
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Answer:
the answer is C animal actions
Explanation:
EDG 2022
A 2 m long wire carrying 2 A of current pointing to the right is placed in a magnetic field of 4 T directed away from you. Which direction does the force on the wire point?
A. Down
B. Up
C. Left
D. Right
Answers
Explanation:
To determine the direction of the force on the wire, we can use the right-hand rule for the cross product of two vectors. The force on the wire is given by:F = I * L x Bwhere I is the current, L is the length of the wire, and B is the magnetic field.
If we point our right-hand thumb in the direction of the current (to the right), and our fingers in the direction of the magnetic field (away from us), then our palm will point in the direction of the force.
So, using the right-hand rule, we can see that the force on the wire will be directed downward. Therefore, the correct answer is A. Down.I need help with (c) please
Answers
Answer:
3*10^8 ÷ 475*10^-9
= 6.3 x 10^14
How much POWER is used in 30 seconds when you complete 150 Joules of work?
Answers
Answer:
Power of 5 watts is used
Explanation:
Mechanical Work and Power
Mechanical work is the amount of energy transferred by a force.
Being F the force vector and s the displacement vector, the work is calculated as:
\(W=\vec F\cdot \vec s\)
If both the force and displacement are parallel, then we can use the equivalent scalar formula:
W=F.s
Power is the amount of energy converted per unit of time. The SI unit of power is the watt, equal to one joule per second.
The power can be calculated as:
\(\displaystyle P=\frac {W}{t}\)
Where W is the work and t is the time.
It's required to calculate the power used in t=30 seconds when W=150 Joules of work are completed. Substitute in the formula:
\(\displaystyle P=\frac {150}{30}\)
P = 5 Watt
Power of 5 watts is used
một chất điểm chuyển động tròn với vận tốc góc w=at^2 +b trong đó a= 0.01 rad/s^2 b=0.05rad/s. Sau khoảng thời gian t=2 kể từ lúc bắt đầu chuyển động, tìm góc hợp bởi vecto gia tốc toàn phần và vecto vận tốc.
Answers
Answer:
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By flowing back across the membrane, protons (H+) seek to
find electrons they can combine with
become antiprotons (H-)
equalize their concentration of both sides of the membrane
transfer their energy to other protons
Answers
By flowing back across the membrane, protons (H+) seek to equalize their concentration of both sides of the membrane.
The third option is correct.
What is the process called?The process by which Protons (H+) flowing back across a membrane seek to equalize their concentration on both sides of the membrane is known as proton gradient equilibration or proton motive force equilibration.
During cellular respiration, protons are pumped across a membrane to create a gradient. This gradient is then used to generate ATP, the energy currency of the cell. Protons flow back across the membrane through a channel called ATP synthase, which generates ATP as the protons flow through it.
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A ball thrown horizontally from a point 24 m above the ground, strikes the ground after traveling horizontally a distance of 18 m. With what speed was it thrown, assuming negligible air resistance
Answers
s
=
1
2
g
t
2
t
=
√
2
s
g
t
=
√
2
×
24
9.8
t
=
2.21
s
The horizontal component of velocity is constant so:
v
=
s
t
=
18
2.21
=
8.14
m/s
The velocity in the horizontal direction will not change. Then the horizontal speed will be 8.133 meters per second.
What is the projectile motion?An item or particle that is propelled in a gravitational influence, such as from the crust of the Ground, and moves along a curved route while solely being affected by gravity is said to be in projectile motion.
A ball thrown horizontally from a point 24 m above the ground, strikes the ground after traveling horizontally a distance of 18 m.
The initial velocity is zero. Then the time taken to reach the ground is given as,
h = ut + 1/2at²
- 24 = 0×t + 1/2 (-9.8)t²
24 = 4.9t²
t² = 4.8979
t = 2.213 seconds
Then the horizontal speed is given as,
v = 18 / 2.213
v = 8.133 meters per second
The velocity in the horizontal direction will not change. Then the horizontal speed will be 8.133 meters per second.
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Ritalin and the pain medication Demerol have a high risk of dependence but may be used for medicinal purposes under a doctor's supervision. These substances are _____ of the CSA list.
Answers
Ritalin and Demerol are both controlled substances that have a high risk of abuse and dependence.
What is the list?Schedule II drugs are believed to have a high abuse potential that could lead to severe psychological or physical dependence. They do, however, occasionally have other known medical applications and can be prescribed by a licensed healthcare provider.
Ritalin is an example of a stimulant, whereas Demerol is an example of an opioid. Thus the drugs that have been mentioned here are drugs that are strictly controlled.
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PE (J)
A 0.155 kg arrow is shot from
ground level, upward at 31.4 m/s.
What is its potential energy (PE)
when it is 30.0 m above the
ground?
Answers
Answer:
45.6 J
Explanation:
PE=mgh
m=0.155 kg
g=9.81 m/s^2
h=30.0 m
0.155(9.81)(30)=45.6
A train accelerates at a constant rate of 1 m/s2. It passes through a 24.5 m wide level crossing in a time of 2 s. After the train leaves the crossing, how much time is required until its speed reaches 31 m/s?.
Answers
A train accelerates at a constant rate of 1 m/s², then the velocity of the train after time t₁ will be equal to 15.25 m/s.
What is Velocity?Velocity is really the direction speed of an item in motion as a measure of the rate at which its location is changing as seen through a particular point of view and as determined by a specific unit of time. A key idea in kinematics, the area of classical physics that studies how bodies move, is velocity.
Acceleration, a = 1 m/s²
Distance, d = 24.5 m
Time, t = 2 s
Velocity, v₂ = 31 m/s
By the equation of motion,
v = u + at
v = v₁
t = t₁
v = v₁ - 4.2 (1)
24.5 = u(2) + 1/2(1)(2²)
u = 11.25 m/s
v₁ = u + 4
v₁ = 11.25 + 4
v₁ = 15.25 m/s.
Therefore, the velocity of the train after time t₁ is 15.25 m/s.
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A small plane starts from rest and accelerates uniformly to the east to a takeoff velocity of 70 m/s in 5 seconds. What is the plane’s acceleration?
Please help!
Answers
The acceleration of the plane after 5 seconds will be 14 m/s².
What is acceleration?The rate of change of velocity with respect to time is called acceleration. Mathematically -
a = Δv/Δt
Given is a small plane that starts from rest and accelerates uniformly to the east to a takeoff velocity of 70 m/s in 5 seconds.
The acceleration of the body can be calculated as follows -
a = Δv/Δt
a = (70 - 0)/(5 - 0)
a = 70/5
a = 14 m/s²
Therefore, the acceleration of the plane after 5 seconds will be 14 m/s².
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The acceleration of gravity on the
Moon is 1.62 m/s2. The mass of the
Moon is 7.35 x 1022 kg. From this
information, what is the radius of the
Moon?
Answers
Answer:
1.74 x 10^6
Explanation:
Brainliest :)
The approximate radius of the Moon is \(1.736 * 10^7\) meters, or 17,360 kilometers.
To find the radius of the Moon, we can use Newton's law of universal gravitation, which relates the acceleration due to gravity (g) to the mass of the celestial body (M) and the distance (radius, r) between the center of the body and the object experiencing the gravitational force.
The formula for the acceleration due to gravity on the surface of a celestial body is:
\(g = G * (M / r^2),\)
where:
g = acceleration due to gravity on the Moon's surface (\(1.62 m/s^2\)),
G = universal gravitational constant (approximately\(6.67430 * 10^{-11\) m^3/kg/s^2),
M = mass of the Moon (\(7.35 * 10^{22\) kg), and
r = radius of the Moon (what we want to find).
Let's rearrange the formula to solve for the radius (r):
\(r^2\) = G * (M / g).
Now, we can plug in the known values:
\(r^2 = (6.67430 * 10^{-11} m^3/kg/s^2) * (7.35 * 10^{22} kg / 1.62 m/s^2)\).
Calculate the value of \(r^2\):
\(r^2\) ≈ \(3.018 * 10^{14} m^2.\)
Finally, take the square root of both sides to find the radius (r):
r ≈ \(\sqrt{(3.018 * 10^{14} m^2)\)≈ \(1.736 * 10^7\) meters.
So, the approximate radius of the Moon is\(1.736 * 10^7\) meters, or 17,360 kilometers.
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How far apart are two conducting plates that have an electric field strength of 8.53 x 103 V/m between them, if their potential difference is 23.0 kV
Answers
Answer:
\(d=2.7m\)
Explanation:
From the question we are told that:
Electric Field strength \(E=8.53 * 10^3 V/m\)
Potential difference is \(V= 23.0 kV\)
Generally the equation for distance is mathematically given by
\(d=\frac{V}{E}\)
\(d=\frac{23.0*10^3}{8.53 * 10^3 V/m}\)
\(d=2.7m\)
Why did the model spacecraft go so much faster than expected on Wednesday?
Write your final explanation to the Universal Space Agency. It may be helpful to review the USA Evidence Cards on the next screen or refer to your Modeling Tool: Spacecraft Launches student sheet as you write. write a essays
Amplify magnetic field lesson 3.3 activity 5
Answers
Because of the larger magnetic field close to the magnet, the Wednesday launch was able to store more potential energy and propel the spacecraft at the a faster rate.
Which type of energy is most crucial for our planet*?The sun is a significant energy source. The main source of energy is the solar, from which every energy the earth is derived. Sunlight not only provides us with solar thermal energy but also allows sun (photo - voltaic) cells to generate electricity.
What is the primary energy source utilised to run equipment in deep space?Since 1961, Radiopharmaceutical Thermoelectric Devices (RTGs) have provided the majority of the electricity for American space operations. Plutonium-238 can be used as an energy source in the RTGs for spacecraft, satellites, and navigation beacons due to its high decay heat (0.56 W/g).
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Imagine observing a white light through two peices of glass, one red and the other blue directly behind it.
What color would the light appear to be?
Answers
Why do diving seabirds need to account for the bending of light?
Answers
People's perceptions of what is important in life are known as:
Answers
Given two pieces of aluminum foil, make one into a ball and one into a box, distinguish the physical properties
Answers
The difference physical properties of aluminum ball and aluminum box is: ball is sphere and box is cubic in shape.
What are the differences between cube and sphere?A cube is shaped squarely, whereas a spherical is shaped roundly.A sphere is not a regular hexahedron because it is a solid object but lacks any faces, edges, or vertices. A cube is a regular hexahedron because it contains six square faces, twelve edges, and eight vertices.A sphere is a point with a radius that extends from its centre to its outermost point. Additionally, a cube has sides that link its vertices to one another.Learn more about sphere here:
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very important!!!
A drilling rig performs 5.15∗105 J of work at an average power output of 3940 W. How long does it take the drill to perform this work?
540 s
916 s
244 s
131 s
Answers
Answer:131s
Explanation:
time = 5.15*10^5 J / 3940
A ski jumper travels down a slope and leaves
the ski track moving in the horizontal direction with a speed of 28 m/s as in the figure.
The landing incline below her falls off with a
slope of θ = 45◦
.The acceleration of gravity is 9.8 m/s^2
Calculate the distance d she travels along
the incline before landing.
Answer in units of m.
Determine how long the ski jumper is airborne.
Answer in units of s.
What is the magnitude of the relative angle φ
with which the ski jumper hits the slope?
Answer in units of ◦
Answers
Answer:
Explanation:
Nothing happens unless we know the position relationship between launch ramp and landing slope. That missing figure would sure be helpful.
ASSUMING the landing slope starts its 45° slope at the position where the skier leaves the launch track. Also assuming no air resistance or lift due to airfoil action on body and skis. (projectile trajectory)
With the launch point as origin and original velocity in the positive direction, horizontal position can be described as
x = 28t
With the launch point as origin and DOWN being positive direction, vertical position can be described as
y = ½(9.8)t²
y = 4.9t²
On a 45° downward slope, y will increase at the same rate as x. time t is common to both equations. When our y equals our x, landing occurs.
4.9t² = 28t
4.9t = 28
t = 5.714285...s
t = 5.71 s
The horizontal and vertical distances at landing are
x = 28(5.714285) = 160 m
so along the slope, the distance is
d = √(2(160²)) = 226.2741699...
d = 226 m
velocities will give us the angle of flight, subtract the slope.
φ = arctan(gt/vx) - 45 = arctan(9.8(5.714285) / 28) - 45 = 18.434948...
φ = 18°
An oil film (n = 1.42) floating on water is 264 nm thick. What is the second longest (m = 2) wavelength IN NANOMETERS that reflects brightlyfrom the film?(Hint: If you leave the wavelength in nm, the answer will be in nm. No conversion necessary.)(Unit = nm)
Answers
ANSWER
\(500\text{ nm}\)EXPLANATION
To find the second longest wavelength that reflects brightly from the film, apply the expression for constructive interference:
\(2nt+\frac{\lambda}{2}=m\lambda\)where m = 2
n = refractive index
λ = wavelength
Make λ the subject of the formula:
\(\begin{gathered} 2nt=mλ-\frac{λ}{2} \\ \\ 2nt=(2m-1)\frac{λ}{2} \\ \\ \frac{λ}{2}=\frac{2nt}{2m-1} \\ \\ λ=\frac{4nt}{2m-1} \end{gathered}\)Now, calculate the wavelength by substituting the given values into the equation:
\(\begin{gathered} λ=\frac{4*1.42*264}{2(2)-1} \\ \\ λ=\frac{1499.52}{4-1}=\frac{1499.52}{3} \\ \\ λ=499.84\text{ nm}\approx500\text{ nm} \end{gathered}\)That is the answer.
how many key reasons are there for time getting away from you?
Answers
Answer:
4
Explanation: the problem with this one is 75 the problem the problem with