If an = 3n - 4, what is a5?

Answer:

63/2

Step-by-step explanation:

Answer:63/2

Step-by-step explanation:

Answer:

D!

Step-by-step explanation:

We need to obviously subtract, only C and D do thatt. But, you don't multiple t or 28 by 4. You need to multiply the difference, so you need parentheses!

Answer:

38.1 cm²

Step-by-step explanation:

area of full circle = π6² = 113.04 cm²

area of 150° segment = (150/360)(113.04) = 47.1 cm²

triangle base = sin 75° x 6 x 2 = 11.59

triangle height = cos 75° x 6 = 1.553

area of triangle = 1/2(11.59)(1.553) = 9 cm²

150° segment - triangle = 47.1 - 9 = 38.1 cm²

Answer:

11+12+13+14=50

Step-by-step explanation:

Just estimate. We know that 15 times 4 = 60, so it has to be less than that. We know that 10 times 4 is 40, so it has to be in that range. Just do trial and error to find the exact answer. I'm editing this now and I realized that I didn't answer the question. I don't know how to write the equation using N but the first integer is 11.      

The volume of the cylindrical solid generated by revolving the region in the first quadrant bounded by the coordinate axes, the curve y = e^x and the line x = ln 9 about the line x = ln 9 is approximately 19.251 cubic units.

To find the volume of the solid generated by revolving, we can use the method of cylindrical shells.

Consider a vertical strip of thickness dx at a distance x from the line x = ln 9. Revolving this strip about the line x = ln 9 will generate a cylindrical shell of radius (ln 9 - x) and height e^x. The volume of this cylindrical shell is given by:

dV = 2π (ln 9 - x) e^x dx

To find the total volume of the solid, we need to integrate dV over the range of x that defines the region of interest. Since the region is bounded by the coordinate axes, we can integrate from x = 0 to x = ln 9. Thus, the total volume of the solid is:

V = ∫0^ln9 2π (ln 9 - x) e^x dx

Using integration by parts, we can evaluate this integral as:

V = 2π [x e^x - e^x] from x = 0 to x = ln 9

V = 2π [(ln 9)(9/e) - (1/e)]

Therefore, the volume of the solid generated by revolving the region in the first quadrant bounded by the coordinate axes, the curve y = e^x and the line x = ln 9 about the line x = ln 9 is approximately 19.251 cubic units.

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Answer:

Step-by-step explanation:

\( \csc(a) = \frac{1}{ \sin(a) } \\ \sin(a) = \frac{15}{25} \\ \\ \csc(a) = \frac{1}{ \frac{15}{25} } \\ \\ \csc(a) = \frac{25}{15} \)

So no one of the above

Answer:

15 feet

Step-by-step explanation:

\(a^{2} +b^{2} =c^{2} \\a^{2} +(20)^{2} =(25)^{2} \\a^{2} +400=625\\a^{2} =225\\a=15\)

Answer:

15 feet

Step-by-step explanation:

We can imagine the structure as a right triangle: the right angle is formed where the ground meets the wall.

Based on the question:

We can solve using the Pythagorean theorem: a² + b² = c²

Solve:

The distance from the base of the ladder to the wall is 15 feet.

-Chetan K

If 40% of the students on the museum trip love the museum, then the remaining 60% don't love the museum. To find out how many students love the museum, we can multiply the total number of students by the percentage who love the museum:

Number of students who love the museum = 40% of 240 students

= 0.4 x 240

= 96 students

Therefore, 96 students on the field trip love the museum.

The range of |f(x)| is [0, 9].

We are given that the range of the function f is [−2, 9]. We are required to find the range of |f(x)|.

Range of a function is defined as the set of all output values (y-values) that a function can produce. It is also called the codomain of the function.

The absolute value of a number is always positive or zero. Therefore, if the function has any negative values in the range, the absolute value of those negative values will be positive and their range will be the same as the positive range.

Therefore, the range of |f(x)| will be [0, 9]. This means that the range of |f(x)| is [0, 9] and is expressed in the interval notation as follows: [0,9].

Therefore, the range of |f(x)| is [0, 9].

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The sample size is 58

a. Normal distribution should be used to compute the confidence interval for the population mean μ.

Because the sample size is greater than 30 and the population standard deviation is known.

b. The critical value for a 96% confidence interval for μ is obtained from the Z-table and it is 1.75.

c. The margin of error (E) is given by the formula:

E = zσ/√n,

where,

z = critical value,

σ = population standard deviation,

n = sample size, and

E = maximum error allowed

E = (1.75)(7.5)/√45E = 1.90 ml/kg d.

To find the confidence interval, we use the formula:

CI = xˉ ± ECI = 37.5 ± 1.90CI = (35.6, 39.4) ml/kg e.

The sample size necessary for a 96% confidence level with the maximum margin of error E=2.30 for the mean plasma volume in male students of the college is given by the formula:

n = (zσ/E)^2n = [(1.75)(7.5)/2.30]^2n = 57.22 ≈ 58

Hence, the required sample size is 58.

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Answer:11.4

Step-by-step explanation:

The solution is in the attached file

The System Effectiveness is approximately 0.763.

To calculate the System Effectiveness, we need to multiply the values of Operational Readiness, Design Adequacy, Availability, Maintainability, and Mission Reliability.

System Effectiveness = Operational Readiness * Design Adequacy * Availability * Maintainability * Mission Reliability

Plugging in the given values:

System Effectiveness = 0.89 * 0.95 * 0.98 * 0.93 * 0.99

System Effectiveness ≈ 0.763

Therefore, the System Effectiveness is approximately 0.763.

The correct answer is a. 0.763.

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Answer:

Amount of plastic need to cover paper role = 565.2 inches

Step-by-step explanation:

Given:

Diameter of paper role = 10 inch

Height of paper role = 13 inch

Find:

Amount of plastic need to cover paper role

Computation:

Radius of paper role = Diameter of paper role / 2

Radius of paper role = 10 / 2

Radius of paper role = 5 inch

Amount of plastic need to cover paper role = Total surface area of cylinder

Amount of plastic need to cover paper role = 2πr(h+r)

Amount of plastic need to cover paper role = 2(3.14)(5)(13+5)

Amount of plastic need to cover paper role = (3.14)(10)(18)

Amount of plastic need to cover paper role = 565.2 inches

For this case we have the following kinematic equation that models the problem:

h (t) = (1/2) * (- 9.8) * t ^ 2 + 12 * t + 2

Rewriting we have:

h (t) = -4.9 * t ^ 2 + 12 * t + 2

When the ball hits the ground we have:

-4.9 * t ^ 2 + 12 * t + 2 = 0

Solving the polynomial we have:

t1 = -0.16

t2 = 2.61

We ignore the negative root because it is time.

Answer: It will take the ball to hit the ground about:

t = 2.61 sec

The congruences that are true by CPCTC are option (B) ∠A ≅ ∠D (D) BC ≅ EF (F) AC ≅ DF.

Two triangles are similar if they have the same ratio of corresponding sides and equal pair of corresponding angles. Similar triangles are the triangles that are the same in shape, but may not be equal in size.

For the given situation,

The triangles ΔABC ≅ ΔDEF.

The CPCTC theorem states that when two triangles are congruent, then every corresponding part of one triangle is congruent to the other.

This means, when two or more triangles are congruent then their corresponding sides and angles are also congruent or equal in measurements.

\(AB = DE, BC = EF, AC = DF\) and

\(\angle A = \angle D, \angle B = \angle E, \angle C = \angle F\)

Hence we can conclude that the congruences that are true by CPCTC are option (B) ∠A ≅ ∠D (D) BC ≅ EF (F) AC ≅ DF.

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The function f(x) is vertically compressed to form g(x)

The functions are given as

f(x) =x^2

g(x) =3x^2

Substitute f(x) =x^2 in g(x) =3x^2

g(x) =3f(x)

This means that the function f(x) is vertically compressed to form g(x)

See attachment for the function g(x)

Also, both functions have the same domain and range

The complete table is:

x      -2    -1    0   1    2

g(x)  12    3    0    3   12

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Answer:

x=4

Step-by-step explanation:

21x+6=90(alternate angles)

21x=90-6

x=94/21

Therefore, x=4

Answer:

x=4

Step-by-step explanation:

21x+6=90

-6. -6

21x=84

/21. /21

x=4

Answer:    T= -4

Step-by-step explanation: Well i guess it would be that ? If it's not sorry but it should be that

The state that is valid is

"Every diameter of a circle is also a chord because a chord of a circle is any line segment joining two points on the circumference of the circle."

A diameter is a line that divides a circle into two halves, a diameter is also a chord

A chord is a line that connects points on a circle, a chord is not a diameter because it does not divide a circle into two equal halves

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Answer: 360% - 7 x 180 rotation

Step-by-step explanation: your welcome

Answer:

Step-by-step explanation:

f(-3) = 2 * (-3)^2           h(6) = -4 * 6          g(-2) = 3*-2 -1            f(-4)= 2*(-4)^2

       =  2* 9                           = - 24                     = -6 -1                       = 2* 16

      = 18                                                              = -7                            = 32

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Answer:

It's probably B

Step-by-step explanation:

True. In a linear regression equation, when X is equal to the mean of X (MX), the predicted value of Y will be equal to the mean of Y (MY). This is because the regression equation aims to model the relationship between X and Y by finding the line that best fits the data points.

The regression equation takes the form of Y = bX + a, where b is the slope of the line and a is the y-intercept. When X is equal to its mean (MX), the term bX in the equation becomes b * MX, which simplifies to b * MX. Additionally, the y-intercept term a remains constant.

Since the mean of X (MX) is a fixed value, multiplying it by the slope (b) in the equation gives a constant term. This means that the predicted value of Y, when X is equal to its mean (MX), will be equal to a constant term plus the y-intercept (MY).

Therefore, when X = MX, the predicted value of Y in the regression equation is equal to MY, the mean of Y.

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Answer:

Step-by-step explanation:

9) 12/n=20/25

simplify 20/25=4/5

12/n=4/5

cross product

n*4=12*5

4n=60

n=60/4

n=15

The missing proportion in each of the following problems shown below:

Statement of equality between two expressions consisting of variables and/or numbers

9) 12/n=20/25

12/n=4/5

n*4=12*5

4n=60

n=60/4

n=15

10) 5/8=n/24

   8n= 5*24

   8n= 120

    n= 120/8

    n=15

11) 2/3= 16/n

   2n=48

   n=24

12) 12/14= n/21

     n=18

13) n/10 = 6/15

    n=4

14)  12/3 = 10/n

     n= 2.5

15) 5/n = 10/16

       n=8

16) 12/8 = 4/n

     n=8/3

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Answer:

aaaaaa

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

For edge

Answer: 8y-56

Step-by-step explanation: the equivalent expression is 8y-56

Answer: 8y - 56

Step-by-step explanation: Hello! Here are the steps to solve this:

8(y - 7)            Use the distributive property, distribute 8 to y and 8 to -7

8y - 56           8 x y = 8y, 8 x -7 = -56

8y - 56 is an equivalent expression to 8(y - 7) because it is simplified.   I hope this helps!

After integrating the expression  \($$I=\int_1^{\sqrt{3}} 5 \arctan \left(\frac{1}{x}\right) d x$$\) we will get the value as: \($I=\left(\frac{5 \sqrt{3}}{6}-\frac{5}{4}\right)^\pi+\frac{5}{2} \ln |2|$\)

Integration by parts, also known as partial integration, is a technique used in calculus and more widely in mathematical analysis to determine the integral of a function's product in terms of the integral of the product of the function's derivative and antiderivative.

The integration of the result of two functions is the integration by parts. Typically, the two functions are shown as f(x) and g. (x). The first function, f(x), is chosen from the two functions in such a way that its derivative formula exists, while the second function, g(x), is chosen in such a way that its integral formula exists.

∫ f(x).g(x).dx = f(x) ∫ g(x).dx - ∫(f'(x) ∫g(x).dx).dx + C

We have, \($$I=\int_1^{\sqrt{3}} 5 \arctan \left(\frac{1}{x}\right) d x$$\)

We know that

\(\frac{1}{x}=arccot(x) \\I=5 \int_1^{\sqrt{3}} arccot(x) dx\)

Integrating by parts

\($$\int f g^{\prime}=f g-\int f^{\prime} g$$\)

let  us assume that,

\($\quad f=\cot ^{-1}(x) \quad g^{\prime}=1$\)

\($I=5 \int_1^{\sqrt{3}} \cot ^{-1}(x) d x$\)

\($I=5\left[x \cot ^{-1}(x)-\int \frac{-x}{x^2+1} d x\right]$\)

\($I=5\left[x \cot ^{-1}(x)+\frac{1}{2} \ln \left|x^2+1\right|\right]_1^{\sqrt{3}}$\)

\($I=5\left[\left(\sqrt{3} \cot ^{-1}(\sqrt{3})+\frac{1}{2} \ln |4|\right)-\left(\cot ^{-1}(1)+\frac{1}{2} \ln |2|\right)\right]$\)

\($I=5\left[\frac{\sqrt{3} \pi}{6}+\ln 2-\frac{\pi}{4}-\frac{1}{2} \ln |2|\right]$\)

\($I=\left(\frac{5 \sqrt{3}}{6}-\frac{5}{4}\right)^\pi+\frac{5}{2} \ln |2|$\)

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The correct question should be:

Evaluate the integral \($$I=\int_1^{\sqrt{3}} 5 \arctan \left(\frac{1}{x}\right) d x$$\)