if rechargeable cell is being charged from a source of EMF the EMF of cell during charging is
A. always equal to its terminal potential difference
B. always greater than its terminal potential difference
C. always less than its terminal potential difference​
D. either equal or less than its terminal potential difference

Answers

Answer 1

Answer:

a

Explanation:

I think bec. I am in small school


Related Questions

Calculate the acceleration in meters per second-squared, of a car moving at 10 m/s that accelerates to 24 m/s over a time of 7 second--

Answers

Explanation:

v = u + at

24 = 10 + a * 7

24 = 10 * 7 a

a = 24 - 10/7

a = 14/7

a = 2m/sec^2

hope it helps you

Answer:

First calculate change in velocity:

final velocity = 20 m/s.

initial velocity = 30 m/s.

change in velocity = (20 - 30) = -10 m/s.

acceleration = -10 ÷ 25.

acceleration = -0.4 m/s 2

The acceleration value is negative here because the car is slowing down or decelerating.

Explanation:

1. Label the parts of the chicken wing in the black wing diagram below

Answers

Where is the diagram ?

PLEASE HELP! NO FAKE ANSWERS
1. Imagine a person flying straight up from Earth's surface. She would experience different conditions as she goes through the layers of the atmosphere. Some layers are cooler, some are hotter, some have oxygen, and some have almost no molecules. Answer the questions below to describe the conditions in each layer. (10 points)
A. What are the conditions in the troposphere? (2 points)
B. What sort of temperatures would she experience in the stratosphere? What other layer is found within the stratosphere? (3 points)
C. What sort of temperatures would she experience in the mesosphere? (2 points)
D. What sort of temperatures would she experience in the thermosphere? What other layer is found within the thermosphere? (3 points)

Answers

Troposphere, stratosphere, mesosphere, thermosphere and exosphere.

What are five layers of earth?

Earth's atmosphere has five major layers.

From lowest to highest, layers are the troposphere, stratosphere, mesosphere, thermosphere and exosphere.

a) What are the conditions in the troposphere?

The atmospheric temperature descends upward with a slope of ~10 K km−1 for dry air and ~7 K km−1 for wet air in troposphere.

The temperature of troposphere decreases with an increase in height.

B) What sort of temperatures would she experience in the stratosphere? What other layer is found within the stratosphere?

The temperature in the stratosphere ranges from- 60° F at the troposphere boundary to -5°F at the top.

The temperature increase is due to the ozone layer that absorbs ultraviolet light from solar radiation.

C)What sort of temperatures would she experience in the mesosphere?

The temperature in the mesosphere ranges from -2.5°C to -90°C

The temperature decreases because of a decrease in the absorption of penetrating solar radiation.

The atmosphere gets cooler with an increase in altitude because an increase in distance from the Earth's surface.

D)What sort of temperatures would she experience in the thermosphere? What other layer is found within the thermosphere?

4,500°F is the temperature of thermosphere.

Temperatures climb sharply in the lower thermosphere , then level off and hold fairly steady with increasing altitude above that height.

Temperatures in the upper thermosphere can range from about 500° C (932° F) to 2,000° C (3,632° F) or higher.

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multiple choice
15) A coiled spring used to help a door close has ________ ________energy when the door is open.

16) After braking, a bicycle's tires increase in temperature as friction causes some of the
mechanical energy to transfer to ________ energy.

Answers

A coiled spring which is used to close a door ,aquires elastic potential energy when the door is open.After braking , the mechanical energy gets converted into thermal energy resulting in increased temperature of the tires.What is the Law of conservation of energy?

According to conservation of energy, the energy of interacting bodies in a closed system remains constant. The total energy of an isolated system remains constant; it is said to be conserved over a period of time.

Elastic energy is the mechanical implicit energy stored in the configuration of a material or physical system as it's subjected to elastic distortion by work performed upon it. Elastic energy occurs when objects are impermanently compressed, stretched or generally misshaped in any manner.

The mechanical energy is never lost forever , rather it gets converted to thermal energy because of the friction .

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Using the Kohler curves estimate the following: (a) the radius of the droplet that will form on a sodium chloride particle of mass 10^-18 kg in air that is 0. 1% supersaturated; (b) the relative humidity of the air adjacent to a droplet of radius 0. 4 microns that contains 10^-19 kg of dissolved ammonium sulfate; (c) the critical supersaturation required for an ammonium sulfate particle of mass 10^-19 kg to grow beyond the haze state

Answers

By using the Kohler curves is 4×\(10^{-5} cm\). If Rh is not shown in the graph therefore the sensitivity is near 1.00 S Rh is 88%. That is 0.0055 means 0.55%.

Kohler curves, also known as Kohler plots, are a graphical representation of the magnetoresistance of a material as a function of the magnetic field strength. They were first introduced by Walter Kohler in 1934 to describe the behavior of ferromagnetic materials. Kohler curves are useful in the study of magnetic materials and have applications in the development of magnetic sensors and memory devices.

Kohler curves plot the ratio of the resistance of a material at a given magnetic field strength to its resistance in the absence of a magnetic field, versus the square of the magnetization of the material. The resulting curve can be used to determine the degree of spin polarization in the material, which is a measure of the alignment of electron spins in the material with the magnetic field.

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Complete Question:

Using the Kohler curves estimate the following: (a) the radius of the droplet that will form on a sodium chloride particle of mass 10^-18 kg in air that is 0. 1% supersaturated; (b) the relative humidity of the air adjacent to a droplet of radius 0. 4 microns that contains 10^-19 kg of dissolved ammonium sulfate; (c) the critical supersaturation required for an ammonium sulfate particle of mass 10^-19 kg to grow beyond the haze state

Using the Kohler curves estimate the following: (a) the radius of the droplet that will form on a sodium

The development of the atomic model shows how scientists improve____ and______. They use all the information that’s available to them at the time.

Answers

The development of the atomic model shows how scientists improve their understanding and knowledge. They use all the information that's available to them at the time.

If a star has a mass of 80 times greater than the Sun and is orange or red in color, it is likely be classified as...
A.) white dwarf
B.) main sequence star
C.) giant or supergiant
D.) variable star

Answers

Answer:

the answer is main sequence star

A high-voltage power line carries a current of 110 A at a location where the Earth's magnetic field has a magnitude of 0.39 G and points to the north, 72° below the horizontal. Find the direction and magnitude of the magnetic force exerted on a 210-m length of wire if the current in the wire flows in the following directions. (If the elevation is 0°, choose "on the horizontal".)
(a) horizontally toward the east magnitude ______________ N
direction ________________at ___________°
(b) horizontally toward the south magnitude _____________N
direction ________________at____________°

Answers

(a) When the current flows horizontally toward the east, the magnitude of the magnetic force is approximately 9078 N, and the direction is upward at 90° from the horizontal. (b) When the current flows horizontally toward the south, the magnitude of the magnetic force is 0 N, and there is no specific direction associated with it.

To find the direction and magnitude of the magnetic force exerted on the wire, we can use the equation:

F = |B| * I * L * sin(θ)

where:

F is the magnetic force,

|B| is the magnitude of the magnetic field,

I is the current,

L is the length of the wire, and

θ is the angle between the current and the magnetic field.

Given:

Current, I = 110 A

Magnitude of the magnetic field, |B| = 0.39 G

Length of the wire, L = 210 m

(a) When the current flows horizontally toward the east:

θ = 90° (since the wire is perpendicular to the magnetic field)

Plugging in the values:

F = (0.39 G) * (110 A) * (210 m) * sin(90°)

F = (0.39 G) * (110 A) * (210 m) * 1

F ≈ 9078 N

The magnitude of the magnetic force is approximately 9078 N.

The direction of the magnetic force is perpendicular to both the current and the magnetic field. Since the wire is horizontal and the magnetic field points north (downward at 72° below horizontal), the magnetic force acts vertically upward.

Therefore, the direction of the magnetic force is upward, and the angle is 90°.

(b) When the current flows horizontally toward the south:

θ = 180° (since the current and the magnetic field are parallel and in opposite directions)

Plugging in the values:

F = (0.39 G) * (110 A) * (210 m) * sin(180°)

F = (0.39 G) * (110 A) * (210 m) * 0

F = 0

The magnitude of the magnetic force is 0 N.

Since the magnetic force is zero, there is no direction associated with it.

Therefore, the magnitude of the magnetic force when the current flows horizontally toward the south is 0 N, and there is no specific direction.

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Two point charges of 9μC and 4μC are placed a distance of 4 m apart.

1) Calculate the magnitude of the force, in Newtons, on a positive 5μC charge at the midpoint between the two charges.
2) Find the point, measured in meters from the 9μC charge, between the two charges where the force on the 5μC charge is 0?

Answers

Hi there!

1)

Since the charge placed in the middle is positive, we know that the particle is being repelled.

The particle experiences a greater repelling force by the 9μC charge. We can use the equation for electric force:
\(F_E = \frac{kq_1q_2}{r^2}\)

k = Coulomb's Constant

q₁, q₂: Charges (C)
r = distance between charges (m)

This is a VECTOR quantity, so we must subtract the forces since they point in opposite directions.

Force from 9μC particle:
\(F_E = \frac{k(.000005)(.000009)}{2^2} = .101\\\\\)

Force from 4μC particle:
\(F_E = \frac{k(0.000005)(0.000004)}{2^2} = 0.0450\)

Subtract:
\(.101 - 0.0450 = \boxed{0.561 N}\)

2)

We can find a position by setting the two equations equal to one another. (Both repelling forces must be EQUAL for the force = 0 N)

Let the distance between the 9μC and 5μC charge equal 'x', and the distance between the 4μC and 5μC charge equal '4 - x'.

\(\frac{k(0.000009)(0.000005)}{x^2} = \frac{k(0.000004)(0.000005)}{(4 - x)^2}\)

Cancel out 'k' and the 5μC value.

\(\frac{0.000009}{x^2} = \frac{0.000004}{(4 - x)^2}\)


Solve for 'x' using a graphing utility.

\(\boxed{x = 2.4 m}\)

A certain atom has eight protons, eight electrons, and eight neutrons. How many nucleons does this atom have? What is the atomic number of this atom? What is the mass number of this atom?

Answers

Explanation:

Number of nucleons

= no of protons + no of neutrons

= 8 + 8

= 16

Atomic number = no of protons = 8

Atomic mass = 15.999

Gamma rays are given out from the
of radioactive atoms. What one word completes the sentence??

Answers

Gamma rays are given out by the nucleus of certain radioactive materials. Radioactive material ray causes harm to the human beings and environment.

What is gamma-decay?

Gamma decay is the production of extremely high-frequency electromagnetic radiation in order to stabilize the unstable nucleus. You must be well-versed in the various energy levels found in an atom.

The Nucleus has its own amount of energy. Gamma decay is the nucleus' method of transitioning from a higher energy level to a lower energy level by emitting high energy photons.

Gamma rays are given out by the nucleus of certain radioactive materials.

Hence, nucleus is the right answer for the blank.

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A 7kg ball is dropped from 20m, if the speed just before it hits the ground is 18 m/s, what is the work done by air resistance?

Answers

-266

The kinetic energy of an object is the energy that it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains its kinetic energy unless its speed changes. The same amount of work is done by the body in decelerating from its current speed to a state of rest.

What is acceleration?

Acceleration is the rate of change of the velocity of an object with respect to time. Accelerations are vector quantities (in that they have magnitude and direction).

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Help someone :(((((((((((((((

Help someone :(((((((((((((((

Answers

The answer is B

I attached the image and explanation below.
Help someone :(((((((((((((((

What is the function of the organelle depicted in the photo?

What is the function of the organelle depicted in the photo?

Answers

Answer:

It's a golgi body

Explanation:

It controls the transport system of the cell

What goes in and out the cel

The ____ method is described as a type of posthumous extirpation.
a. electrical stimulation
b. introspection
c. scientific
d. experimental
e. clinical

Answers

The d. experimental method is described as a type of posthumous extirpation.

Posthumous extirpation refers to the removal or extraction of a specific part of an organism's body after death, often for the purpose of scientific research. The experimental method is a systematic approach used by researchers to test hypotheses and draw conclusions about a particular phenomenon. It involves the manipulation of one or more independent variables to determine their effects on dependent variables.

This method allows scientists to gather empirical data, control for confounding factors, and establish causal relationships. By applying the experimental method to posthumous extirpation, researchers can gain valuable insights into the structure and function of various biological systems. This can lead to a better understanding of human and animal anatomy, as well as contribute to advancements in medical treatments and surgical procedures. So therefore  described as a type of posthumous extirpation is d. experimental method.

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Why is it necessary to blank the spectrophotometer whenever the wavelength is changed?.

Answers

It is necessary to blank the spectrophotometer whenever the wavelength is changed to eliminate stray light interference and ensure accurate readings.

Spectrophotometers are used in biochemical laboratories to quantify the concentration of specific molecules in a sample. It works by measuring the intensity of light absorbed by the sample at a specific wavelength of light. The purpose of blanking the spectrophotometer is to eliminate any light absorption caused by impurities or other substances in the solvent or sample.

These impurities are referred to as stray light, and they can interfere with the readings of the spectrophotometer. Blank solutions are used to detect the presence of stray light and to correct the instrument to zero absorbance before taking the readings. The blank solution contains the same solvent and reagents used in the sample.

By blanking the spectrophotometer before taking the readings, it ensures that the readings are accurate, and the interference of stray light is eliminated.

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If a horse trots past the fence post located 14 m to the left of the gate post and then passed another fence post located 15 m to the right of the gate Post 14 seconds later what is the average velocity of the horse

Answers

Answer:

19 miles away from the home

The average velocity of the horse at the given displacement is 2.07 m/s.

The given parameters:

Initial position of the horse, x₁ = 14 m leftFinal position of the horse, x₂ = 15 m rightTime of motion of the horse, t = 14 s

The average velocity of the horse is determined as the ratio of the total displacement to time of motion.

\(v = \frac{\Delta x}{\Delta t} \\\\v = \frac{x_2 - x_1 }{t} \\\\v = \frac{15 - (-14)}{14} \\\\v = \frac{15 + 14}{14} \\\\v = \frac{29}{14} \\\\v = 2.07 \ m/s\)

Thus, the average velocity of the horse at the given displacement is 2.07 m/s.

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The term "constant returns to scale" describes a situation where_____

Answers

"Constant returns to scale" refers to a situation where an increase in all inputs leads to a proportional increase in output.

What is Constant?

In the context of "constant returns to scale," the term "constant" refers to the proportionality between the increase in inputs and the increase in output. If an increase in inputs results in a proportional increase in output, it is referred to as "constant returns to scale.

" This means that the relationship between inputs and outputs remains unchanged, regardless of the size of the inputs. The term "constant" in this context refers to the fact that this relationship is constant and does not change over time.

According to question:

"Constant returns to scale" describes a situation where an increase in all inputs of a production process leads to a proportional increase in output. In other words, if inputs are doubled, output will also double, maintaining the same average cost per unit of output.

This property is useful in analyzing the behavior of large-scale production processes and determining the optimal level of inputs for maximum efficiency.

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A fathometer is used to send a wave down to the sea bed, the reflected wave is released after 0.5 seconds. Calculate the depth of the sea

Answers

To calculate the depth of the sea using the given information, we need to consider the speed of the wave and the time it takes for the wave to travel down to the sea bed and back.

The time taken for the wave to travel down to the sea bed and back is twice the time it takes for the reflected wave to be received. In this case, the reflected wave is received after 0.5 seconds, so the total round trip time is 2 * 0.5 seconds = 1 second.

Now, we need to determine the speed of the wave. The speed of a wave can be calculated using the formula:

\(Speed = \frac{Distance}{Time}\)

In this case, the distance is twice the depth of the sea because the wave travels down to the sea bed and then back up to the surface. Therefore, we have:

\(Speed = \frac{2 \times Depth}{Time}\)

Rearranging the formula to solve for the depth, we get:

\(Depth = \frac{Speed \times Time}{2}\)

Since we are not given the speed of the wave, we cannot calculate the exact depth. The speed of the wave will depend on the properties of the medium through which it is traveling (such as water) and may need to be provided in the question.

Once the speed is known, we can substitute it into the formula along with the given time of 1 second to calculate the depth of the sea. Without the speed value, we cannot determine the exact depth.

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Temperature is a measure of how hot or cold
something is but need
Explanation

Answers

Answer:

Temperature is a measure of the average kinetic energy of the particles in an object.

Using the modern celcius system of temperature measurement, We. an easily determine how hot or cold it is. It was also know as Centigrade. This is because it is based on the freezing and boiling points of water with 100 degrees between those temperatures.

An object is thrown off a cliff with a horizontal speed of 10 m/sec and some unknown initial vertical velocity. After 3 seconds the object hits the ground which is 30 meters below the cliff. Find the initial vertical velocity and the total horizontal distance traveled by the object.
a. What do you know?
b. What do you need to solve for?
c. What equation(s) will you use?
d. What is the solution to this problem?

Answers

The answers to the questions of the object thrown off a cliff with a horizontal speed of 10 m/s and that reach the ground which is 30 m below after 3 seconds, are:

a. We know:

The height of the cliff = 30 mThe time for the object to reach the ground = 3 sThe initial horizontal velocity = 10 m/s

b. We need to find the initial vertical velocity and the total horizontal distance traveled.

c. To calculate the initial vertical velocity and the total horizontal distance traveled by the object, we need to use the following equations:

\( y_{f} = y_{i} + v_{i_{y}}t - \frac{1}{2}gt^{2} \)   (1)

\( v_{i_{x}} = \frac{x}{t} \)  (2)

d. The initial vertical velocity and the horizontal distance traveled by the object are 4.72 m/s and 30 m, respectively.

a. From the statement, we know:

The initial horizontal velocity (\(v_{i_{x}} \)) = 10 m/sThe time for the object to reach the ground = 3 sThe height of the cliff = 30 m

b. We need to find the initial vertical velocity and the total horizontal distance traveled.

c. To calculate the initial vertical velocity we can use the following equation:

\( y_{f} = y_{i} + v_{i_{y}}t - \frac{1}{2}gt^{2} \)   (1)

Where:

\( y_{f}\): is the final height = 0 m  

\( y_{i}\): is the initial height = 30 m  

\( v_{i_{y}}\): is the initial vertical velocity =?  

g: is the acceleration due to gravity = 9.81 m/s²

t: is the time = 3 s  

And, to find the horizontal distance traveled by the object we need to use the equation:

\( v_{i_{x}} = \frac{x}{t} \)   (2)

Where:

\(v_{i_{x}} \): is the initial horizontal velocity = 10 m/s

x: is the horizontal distance =?

d. The solution to this problem is the following.

Calculation of the initial vertical velocity (eq 1)

\( y_{f} = y_{i} + v_{i_{y}}t - \frac{1}{2}gt^{2} \)  

\( 0 = 30 m + v_{i_{y}}*3 s - \frac{1}{2}*9.81 m/s^{2}*(3 s)^{2} \)

Solving for \(v_{i_{y}}\)

\( v_{i_{y}} = \frac{\frac{1}{2}*9.81 m/s^{2}*(3 s)^{2} - 30 m}{3 s} = 4.72 m/s \)

Hence, the initial vertical velocity is 4.72 m/s.  

Calculation of the horizontal distance (eq 2)

\( v_{i_{x}} = \frac{x}{t} \)

\( 10 m/s = \frac{x}{3 s} \)

\( x = 10 m/s*3 s = 30 m \)

Therefore, the horizontal distance traveled by the object is 30 m.

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true or false: if a hard magnetic material is heated above its curie temperature and then cooled back to room temperature it will regain its original permanent magnetization.

Answers

The claim that a hard magnetic material will restore its initial permanent magnetization if heated above its curie temperature and subsequently cooled to room temperature is untrue.

When a magnetic substance reaches its Curie temperature, what happens?

The alignment of a material's magnetic moments is compelled into a disordered state when it reaches its Curie temperature. On the basis of the same concept, a material's magnetic strength gradually decreases when it is subjected to progressively greater temperatures.

If a magnet is heated to a high temperature, what will happen?

If heated over its melting point or for an extended period of time, a magnet will permanently lose its magnetic force at a temperature of about 80 °C.

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A student holds an ice cube in her hand. Which of the following best describes the movement of heat that will happen?

Answers

Answer:

The ice will melt and her hand will get cold

Explanation:

a proton is placed at a point where the electric field (due to other charges) is where is a constant with si units of n/c. what is the electric force on the proton? (e is the elementary charge: e

Answers

Answer: Electric force is = KQ1×Q2/r^2

What is Electric Field?

-- Electric field, an electric property associated with each point in space when charge is present in any form.

--The magnitude and direction of the electric field are expressed by the value of E, called electric field strength or electric field intensity or simply the electric field..

What is electric force ?

-- The repulsive or attractive interaction between any two charged bodies is called as electric force.

--  Similar to any force, its impact and effects on the given body are described by Newton's laws of motion.

-- The electric force is one of the various forces that act on objects.

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Water
Glass
A ray of light enters glass at 45° to the horizontal from water. If
the index of refraction of water is 1.3, and index of refraction of
glass is 1.5, then what is the angle of the refracted ray?

Answers

Answer: 22

Explanation:

. A family leaves for an evening walk around the neighborhood. They leave at 5 pm and return at 6 pm. They traveled a total of 2.5 miles. What is their average speed?
6. It takes you 20 minutes to walk 1.5 miles to school. How far can you walk in one hour?
I need an explanation on how you got the answer.

Answers

The average speed of the family is 2.5 mph.

At the same speed used to walk to school, the distance traveled in one hour is 4.5 miles.

What is average speed?

The average speed of an object is the total distance traveled by the object to the total time of motion of the object.

v = total distance / total time motion

total distance = 2.5 miles

total time = 6 pm - 5 pm = 1 hour

v = (2.5 miles) / (1 hour)

v = 2.5 mph

When it takes 20 minutes to walk 1.5 miles, the speed of the motion is calculated as follows;

time = 20 mins / 60 mins/hr =  0.333 hr

v = 1.5 miles / 0.333 hr = 4.5 mph

At this speed, the distance traveled in one hour is calculated as follows;

d = 4.5 mph x 1 hr

d = 4.5 miles

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A student drops a rock from a bridge to the
water 14.4 m below.
With what speed does the rock strike
the water? The acceleration of gravity is
9.8 m/s².
Answer in units of m/s.

Answers

Answer:  

Explanation:

at first the rock is at rest so initial velocity is zero
after accelerating it reaches a final velocity
we are supposed to find that final velocity


\(v^{2} = u^{2} +2ax\)
v= final velocity
u= initial velocity
x= distance
a= acceleration

\(v^{2} = 0^{2} + 2(9.8)(14.4)\)
\(v^{2} = 282.24\)
\(v= \sqrt{282.24}\)
\(v= 16.8 m/s\)





quit my nose so you have a bad guy really good guy​

Answers

Answer:

hmmmmmmmmmmmmmmm

yes.

light plane must reach a speed of 34 m/sm/s for takeoff. part a how long a runway is needed if the (constant) acceleration is 3.0 m/s2m/s2 ? express your answer using two significant figures.

Answers

The length of the runway where the light plane reaches the speed of 34m/s is 385.22 meters

The speed of the light plane is 34 m/s

The acceleration of the light plane is 3 m/s²

The length of the runway can be found by solving both acceleration and velocity, we will obtain the time taken and length of the runway.

             Acceleration, a = v / t

where v is the velocity

           t is the time taken

Let us substitute the known values, we get

                             3 = 34 / t

                             t = 34 / 3

                                = 11.33 s

Thus, the time taken to cross the runway is 11.33 seconds

              Then, the velocity, v = L/t

 where L is the length of the runway

             t is the time taken.

Let us substitute the known values, we get

                             34 = L / 11.33

                               L = 34 x 11.33

                                   = 385.22 meters

Therefore, the length of the runway is 385.22 meters

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A projectile is horizontally launched and lands 18 meters away. It takes 2.1 seconds to land.

a. How tall was the place where it was launched?

b. What was the horizontal velocity of the projectile?

c. What was the vertical velocity of the projectile?

Answers

The place where the projectile was launched was 20.88 m above the ground.

The horizontal velocity of the projectile was 8.57 m/s.

The vertical velocity of the projectile was -20.58 m/s just before landing.

How to find the height

a. To find the height of the place where the projectile was launched, we need to use the following kinematic equation for vertical motion:

h = vi * t + 0.5 * a * t^2

where:

h = height of the place where the projectile was launched

vi = initial vertical velocity (assumed to be 0 m/s)

t = time to land (2.1 s)

a = acceleration due to gravity (-9.8 m/s^2)

plugging in the values

h = 0 * 2.1 + 0.5 * (-9.8) * (2.1)^2

h = -20.88 m

b. To find the horizontal velocity of the projectile, we can use the following equation:

d = vi * t + 0.5 * a * t^2

where:

d = horizontal distance traveled (18 m)

vi = initial horizontal velocity

t = time to land (2.1 s)

a = acceleration in the horizontal direction (assumed to be 0 m/s^2)

Since the acceleration is 0, the equation simplifies to:

d = vi * t

Solving for vi, we get:

vi = d / t

vi = 18 / 2.1

vi = 8.57 m/s

c. To find the vertical velocity of the projectile, we can use the following kinematic equation for vertical motion:

vf = vi + a * t

where:

vf = final vertical velocity

vi = initial vertical velocity (assumed to be 0 m/s)

a = acceleration due to gravity (-9.8 m/s^2)

t = time to land (2.1 s)

Substituting, we get:

vf = 0 + (-9.8) * 2.1

vf = -20.58 m/s

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