If the loading and unloading curves are not straight enough then what would be the main problem: a The instrument is not properly calibrated b Sample is too soft c Operating speed is too high d Sample is not tight enough

Answer:

Explanation:

I think I will say it is because most, if not all resistors have been made to standard already.

The value for the resistor that is chosen for two fixed arms from the Wheatstone Bridge have to be quite bear each other, as much as possible. The arm that moves and the other that doesn't move, their resistance values are made to be quite close as well. This makes the resistance of the arm that moves to be set somewhere in the middle, and as a result, the measurements don't exceed beyond the resistance range of the arm that moves.

I hope you understand?

Answer:

A

Explanation:

The true power is obtained as 70.7 VA.

We define the power a the rate of doing work, we know that the power in a circuit is the product of the current and the voltage. In this case, we want to find the true power thus we have to involve the use of the phase shift in degrees.

Thus;

True power = PcosΦ

P =  100 VA

Φ = 45 degrees

True power =  100 VA * cos 45 degrees

True power = 70.7 VA

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Processes can obtain a time slice in one second for 100. (.01 * 100 = 1)

Long settings will result in a poor response to quick interactive operations. Typically, a quantum of 100 msec or less is acceptable.

The time slice expires and the process is preempted if a process is prevented from finishing inside the time slice or becomes blocked due to an I/O operation. This preempted process is moved to the tail of the run queue, where it must wait for all the other processes in the queue to complete their CPU cycle before moving forward.

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Answer:

10 flip -flops are required to build a binary counter circuit to count to from 0 to 1023 .

Explanation:

Answer:

The answer is "\(\bold{1.32 \times 10^{-3} \ cm}\)".

Explanation:

All of the atoms in a BCC crystalline structure are contained in the 8-corner unit cell.  

Each corner connects the atom to a single cell \(\frac{1}{8}\)  

Therefore, the unit cell number of atoms:  

\(= 8 \times \frac{1}{8}+ 1 \\\\= 1+1 \\\\= 2 \ atom\)

\(The mass unit cell = \frac{ \text{Number of atoms} \times \text{atomic weight}} {Avagadro number}\\\\= \frac{2 \times 50.9}{6.023 \times 10^{23}}  \\\\= 1.69 \times 10^{-22} \ g\\\\Area Of the atom= \frac{4r}{\sqrt{3}}\\\\   5.96 = \frac{1.69 \times 10^{-22}}{volume}\\\\volume= 2.835 \times 10^{25}\\\\v=d^3\\\\v= (\frac{4r}{\sqrt{3}})^3\\\\\to 2.835 \times 10^{-23} \times (\sqrt{3})^3 = 4^3 r^3\)  

\(\to \sqrt[3]{\frac{{2.835 \times 10^{-23} \times (\sqrt{3})^3}}{4^3}} =r\\\\\to r= 1.32 \times 10^{-3} \ cm\)

In order for an aircraft to spin, it must be placed in a specific flight condition known as an aggravated stall. This occurs when the angle of attack of the aircraft is too high and the airflow over the wings becomes disrupted, causing a loss of lift.

As a result, one wing may stall before the other, creating an unequal lift distribution that can cause the aircraft to enter a spin. Pilots must be trained to recognize and recover from this dangerous situation in order to prevent accidents.
In order to spin, an aircraft must be placed in a specific flight condition known as a "stall." A stall occurs when the angle of attack is too high, causing a reduction in lift and an increase in drag. To initiate a spin, the aircraft must be in a stalled condition and have a yawing motion (rotation around the vertical axis). This combination of factors causes one wing to generate more lift than the other, resulting in the spinning motion.

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In order for an aircraft to spin, it must be in a stall condition. A stall occurs when the angle of attack (AOA) is too high, causing the airflow over the wings to separate and the lift generated by the wings to decrease. When the AOA reaches the critical angle of attack, the airflow can no longer create enough lift to keep the aircraft in the air, and it begins to descend.

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Answer:

the total charge which crosses into the collector is 60 nC

Explanation:

Given the data in the question;

current flowing into the collector lead of the bipolar junction transistor (BJT); i = 1 nA = 10⁻⁹ A

no charge was transferred in or out of the collector lead prior to t = 0

the current flow time t = 1 min = 60 sec

Now we write the relation between current, charge, and time;

i = dq / dt

where i is current, q is charge and t is time. { d refers to change }

Now,

\(q=\int\limits^t_{t=0} {i(t)} \, dt\)

\(q=\int\limits^{t=60}_{t=0} { (10^{-9}) } \, dt\)

\(q = ( 10^{-9}) (t)_0^{60\)

\(q = ( 10^{-9}) ( 60 - 0 )\)

q = 60 × 10⁻⁹ C

q = 60 nC

Therefore, the total charge which crosses into the collector is 60 nC

When thrust faults occur, the region undergoing stress is subject to compression stress.

Compressive stress is a force that causes a substance to deform in order to take up less space.

When thrust faults occur, the region undergoing stress is subject to compression stress. A substance is said to be under compression when it is subjected to compressive stress.

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Dr. Brooks should invest in solar panels due to positive returns at a 20% required rate of return, resulting in an annual savings of $542.42. However, a recalculation of the NPV at a 9% discount rate is necessary to assess the investment's continued viability.

First, we calculate the expected annual savings by dividing the initial cost ($6,571) by the payback period (12.11 years), resulting in approximately $542.42 per year.

Next, using the methodology discussed in class, we compare the expected annual savings to the required rate of return of 20%. If the expected annual savings are greater than or equal to the required rate of return, the investment is considered profitable. In this case, $542.42 is less than 20%, so the investment does not meet the required rate of return.

If we change the appropriate discount rate to 9%, we repeat the same comparison. The expected annual savings of $542.42 is still less than 9%, indicating that the investment remains unprofitable even with the lower discount rate.

Based on these calculations, Dr. Brooks should not invest in solar panels under the given conditions, regardless of the discount rate.

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The amplitude of the sinusoid is 28384 *x soít cos.

Amplitude is defined as the greatest deviation from equilibrium of a point on a vibrating body or wave in terms of displacement or distance traveled. In most cases, amplitude is calculated by looking at a wave graph and determining the height of the wave from rest. The strength or intensity of the wave is gauged by its amplitude.

Sinusoid is defined as a signal with sine wave characteristics. In the liver, spleen, and bone marrow, sinusoids and irregular tubules transport blood in place of venules and capillaries. The sine or cosine functions from trigonometry form the foundation of sinusoidal signals, which are periodic functions.

Thus the amplitude of the sinusoid is 28384 *x soít cos.

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The results of the calculations are (a) P = 37.97 kN and (b) P = 35.62 kN.

The surface won't be cut if you press the flat section of the knife against the fruit. The force is dispersed over a wide area.

Using the parameters and figure provided in the problem, we have:

A = b*h = 0.14*0.24 = 0.0336 m^2

S = (b*h^2)/6 = (0.14*0.24*0.24)/6 = 0.001344 m^3

q = 5400*0.0336 = 181.44 N/m

(a) The load P at 8.5 MPa = 8.5*106 Pa (allowable bending stress)

σ = M/S

M = *S thus equals 0.001344*8.5*106 = 11424 Nm.

Aside from that

M = (P*L/4) + (q*L^2)/8

11424 = (P*1.2/4) + (181.44*1.2^2)/8

11424 = 0.3*P + 32.6592

P = (11424-32.6592)/0.3 = 37.97 kN

(b) If (allowable shear stress) = 0.8 MPa, then the value of P is equal to 0.8*106 Pa.

(2*A*τ/3) = P/2 + q*L/2

(2*0.0336*0.8*10^6)/3 = P/2 + 181.44*1.2/2

17920 = P/2 + 108.864

P = (17920 - 108.864) * 2 = 35.62 kN.

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The time required for this system to come to rest is equal to 9.87 seconds.

Given the following data:

In order to calculate the time required for this system to come to rest, we would have to determine the moment of inertia for gears A and C.

Mathematically, the moment of inertia for a gear can be calculated by using this formula:

I = mr²

Where:

For gear A, we have:

I = mr²

I = 0.675 × 0.04²

I = 0.675 × 0.0016

I = 1.08 × 10⁻³ kg·m².

For gear C, we have:

I = mr²

I = 3.6 × 0.1²

I = 3.6 × 0.01

I = 0.036 kg·m².

Next, we would convert the initial angular velocity of gear C in revolution per minutes (rpm) to radian per seconds (rad/s) as follows:

ωc₁ = 2000 × 2π/60

ωc₁ = 4000π/60

ωc₁ = 209.44 rad/s.

Also, the initial angular velocity of gears A and B is given by:

ωA₁ = ωB₁ = rc/rA × (ωc₁)

ωA₁ = ωB₁ = 0.15/0.06 × (209.44)

ωA₁ = ωB₁ = 2.5 × (209.44)

ωA₁ = ωB₁ = 523.60 rad/s.

Taking the moment about A, we have:

I_A·ωA₁ + rA∫F_{AC}dt - M(f)_A·t = 0

Substituting the given parameters into the formula, we have;

(1.08 × 10⁻³)·(523.60) + 0.06∫F_{AC}dt - 0.15t = 0

0.15t - 0.06∫F_{AC}dt = 0.56549    ......equation 1.

Similarly, the moment about B is given by:

0.15t - 0.06∫F_{BC}dt = 0.56549    ......equation 2.

Note: Let x = ∫F_{BC}dt + ∫F_{AC}dt

Adding eqn. 1 & eqn. 2, we have:

0.3t - 0.06x = (0.56549) × 2

0.3t - 0.06x = 1.13098      ......equation 3.

Taking the moment about A, we have:

Ic·ωc₁ - rC∫F_{AC}dt - rC∫F_{BC}dt - Mc(f)_A·t = 0

0.036(209.44) - 0.3t - 0.15(∫F_{BC}dt + ∫F_{AC}dt) = 0

0.3t + 0.15x = 7.5398      ......equation 4.

Solving eqn. 3 and eqn. 4 simultaneously, we have:

x = 30.5 Ns.

Time, t = 9.87 seconds.

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An nmos and gate can be implemented using 2 nmos transistors in series, or the output of 2 nmos transistors in parallel connected to the input of a single nmos transistor.

In the first implementation, the two nmos transistors are connected in series, with the input signal connected to the gate of the first transistor and the output taken from the drain of the second transistor. When the input signal is high, the first transistor is turned on, allowing current to flow to the second transistor. If the second transistor is also turned on, the output will be low, otherwise, the output will be high.

In the second implementation, the two nmos transistors are connected in parallel, with their sources and gates connected together, and the output taken from the drains. When the input signal is high, both transistors are turned on, allowing current to flow to the output. If either of the transistors is turned off, the output will be low.

Both of these implementations use two nmos transistors, but they are connected differently to achieve the desired logic function. A single nmos transistor can be used to implement a NOT gate or an inverter, but it cannot implement an AND gate

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Answer:

A video camera with onboard storage(whether is a tape or digital memory) will record sound

Answer:

C. Wants are less important to survival than needs

Explanation:

✓In economics, want can be regarded as things( goods/services) that is been desired. Human nature will always has unlimited wants even though there are limited resources.

✓Needs are things that's required for survival, they are necessary things that one needs to function. They could be physical needs such as food, shelter, water.

Wants are less important to survival than needs, For instance, food, water are needs, and one might not be be able to survive without food and water but having a car, latest private jet are wants they are not required before one can survive. When there is no resources to get what we want we can survive but needs are necessity.

Answer:

Yes, the forging can be completed

Explanation:

Given h = 100 mm, ε = ㏑(450/100) = 1.504

\(Y_f = 230 \times 1.504^{0.15} = 244.52\)

V = π·D²·L/4 = π × 50²×450/4 = 883,572.93 mm³

At h = 100 mm, A = V/h = 883,572.93 /100 = 8835.73 mm²

D = √(4·A/π) = 106.07 mm

\(K_f\) = 1 + 0.4 × 0.1 × 106.07/100 = 1.042

F = 1.042 × 244.52 × 8835.73 = 2252199.386 N =2.25 MN

Hence the required force = 2.25 MN is less than the available force = 3 MN therefore, the forging can be completed.

Answer:

knowledge of animal behavior and anatomy

Explanation:

the qualification that will make Milton successful in his research is a knowledge of animal behaviour and also their anatomy. the knowledge of whales behaviour has opened his eyes into their world so he knows to a great deal about them. it is through his knowledge of the behaviour of whales that he's able to get used to their migrating patterns to know where and when to find them. Also, through the body anatomy of whales he knows what their movement is like.

Answer:

knowledge of animal behavior and anatomy

Answer:

yea

Explanation:

okkudjeheud email and delete the electronic version of this communication

Engineering controls are devices that block or eliminate sharps hazards, such as self-coating needles and sharps containers.

Standard precautions include hand washing and use of appropriate personal protective equipment (PPE) when contact with a patient's bodily fluids is anticipated. Engineering controls are devices that isolate or eliminate the risk of blood-borne pathogens from the workplace (OSHA, 2019a). Management of environmental hazards is part of policies to reduce the potential for the spread of blood-borne pathogens and other potential infectious agents.

Engineering controls protect workers by eliminating hazardous conditions or creating barriers between workers and hazards. Examples include local exhaust ventilation to trap and remove airborne emissions and mechanical guards to protect workers.

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Here are the appropriate flowchart symbols for each of the statements:

I. Accept Variable num: Parallelogram with "Input/Output" written inside

II. Is num > 0 ?: Diamond with "Yes" and "No" written on either side

III. Display num: Parallelogram with "Input/Output" written inside

IV. Num = num + 1: Rectangle with "Process" written inside

V. Stop: Oval with "Terminator" or "End" written inside

Putting all these symbols together, the flowchart would look like this:

     +--------------+

     |              |

+---->+ Input/Output |

|     |              |

|     +------+-------+

|            |

|            v

|      +-----+-----+

|      |           |

|      |   Diamond |

|      |           |

|      +-+-----+---+

|        | Yes |

|        v     v

|      +-------+---+

|      |           |

|      | Input/Output |

|      |           |

|      +-------+---+

|              |

|              v

|      +-------+-+

|      |         |

|      |  Process |

|      |         |

|      +---------+

|              |

|              v

|      +-------+-+

|      |         |

|      |  End    |

|      |         |

|      +---------+

|              

+--------------+

On the print you would expect the pitch diameter of the gear to be 9.00 inches. Option A is right.

Gear ratio = 1/3

This is solved as number of teeth on pinion / teeth on gear

= Np/Ng

The pitch diameter = 1.5 x 2

= 3

Diametral pitch = 12

NP = 3 x 12 = 36

This is the teeth on piston

Ng = 3NP

Ng = 3 * 36

= 108

Hence pitch diameter = 108/12 = 9

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Answer:

The block will float with its axis vertical.

Explanation:

For it to float, the upward force on the cylindrical block must be equal to the weight of an equal volume of water. Also, this upward force must be greater than or equal to the weight of the cylindrical block for it to float.

So, weight of cylindrical block, W = specific weight × volume

specific weight = 7500 N/m³

volume = πd²h/4 where d = diameter of block and h = height of block

volume = π(1 m)² × 1 m/4 = π/4 m³ = 0.7854 m³

W = 7500 N/m³ × 0.7854 m³ = 5890.5 N

Since the density of water = 1000 kg/m³, its specific weight W' = 1000 kg/m³ × 9.8 m/s² = 9800 N/m³

Since the volume of the cylinder = volume of water displaced, the weight of water displaced W' = upward force = specific weight of water × volume of water displaced =  9800 N/m³ × 0.7854 m³ = 7696.92 N

Since W' = 7696.92 N > W = 5890.5 N, the block will float with its axis vertical since the upward force is greater than the weight of the cylindrical block.

Answer:

a

Explanation:

digital identity is the answer

The core domain for Accenture’s multi-party System is that of a digital identity. Ths that option A is correct.

A multiparty system is a shared data infrastructure within the individual and the organizations that drive the efficiency nf new business and lead to the formation of the revenue models. They include the blockchain and distribution database and include a variety of technology and other capabilities.

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Answer: True

Explanation:

The Advanced Encryption Standard (AES) is a widely used symmetric-key encryption algorithm that provides strong encryption and is used to protect sensitive data.

It was established by the National Institute of Standards and Technology (NIST) in 2001 and has since become the industry standard for encrypting data. AES offers a high level of security by operating on fixed block sizes of 128 bits and supporting key sizes of 128, 192, or 256 bits. AES is used in a variety of applications, including encryption of electronic data, such as credit card transactions and personal information, and in military and government applications.Advanced Encryption Standard (AES).

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Answer:

they agreed to reduce nuclear weapons

Answer:

A

Explanation:

Edu 2023