In econometrics, regression analysis is a statistical technique used to measure the effect of one set of variables on another variable.
Regression analysis is a powerful tool in statistics and econometrics that allows researchers to understand the relationship between a dependent variable and one or more independent variables. It helps quantify the impact of the independent variables on the dependent variable by estimating the coefficients of the regression equation. The coefficients indicate the change in the dependent variable associated with a unit change in the independent variables, holding other factors constant. Regression analysis provides valuable insights into causality, prediction, and hypothesis testing. It is widely used in various fields, such as economics, social sciences, finance, and marketing, to analyze and understand complex relationships between variables.
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You are planning an extended trip to Mexico. You have a new Smartphone to keep in touch with your friends but are concerned about roaming charges, because you know you will be outside the home network service area. Your plan costs $35 per month plus $0.25 per minute for roaming charges.
find f'(x) for f(x) = -8x2-5x-4
Thank you :)
Answer:
Step-by-step explanation:
Use the constant, constant multiple, and power rules for derivatives: bring down the exponent and multiply it by the constant, then replace it with an exponent that is 1 less than what it was. The derivative of
\(f(x)=-8x^2-5x-4\) would look like this:
\(f'(x)=-8(2)x^1-5-0\) simplifying to
\(f'(x)=-16x-5\)
Find the 46th term of 15. 30, 60
Answer:
5.2776558e+14
Step-by-step explanation:
\(a_{n} =a_{1} *r^{n-1}\)
15, 30, 60
\(a_{46} =15(2)^{46-1}\)
\(a_{46}\) = 5.2776558e+14
hope it helps :)
mark brainliest!
Based upon the input from Units 1 and 2, you have just received your next assignment that will contribute to your next decision. For the outdoor sporting goods client, based upon your prior decision on whether or not to expand to the next market or retain your current position, justify your decision further utilizing the chi-square distribution tool. One key criterion point: You do not have adequate data to formulate a full chi-square for the outdoor sporting goods client. However, you have sufficient data to initiate this process. You are charged to demonstrate the initial steps of a nonparametric test that are qualitative. Utilizing the null and alternative hypotheses, further present your justifications for your selection and what it means beyond the mere formulas. What is this going to tell the Board of Directors and contribute to the decision-making process? The following information may be helpful in understanding chi-square and hypothesis testing: Please review this helpful video. The presenter uses flipping a coin and rolling a die. These are examples and analogies used in the CTU resources. The following are assumptions that might make the assignment more helpful and make the responses more uniform: Continue to utilize the Big D scenario. Work under the assumption that the sample is based upon 2 different proposed product lines. Additionally, work under the assumption that the same demographics are utilized for each product.
My forecast is that you will either enter the next market or, more likely, keep your existing position. These are the theories we have.
Because we put our alternative hypothesis equal to what we wish to show, you should continue to hold the stance you already hold. The opposite hypothesis, or null hypothesis, is a claim that there is no difference. For instance,There is no discernible difference between the mean and sample population, according to the null hypothesis.Alternative Hypothesis H1: The mean and sample population differ significantly.Level of significance: A: If there is no difference in the sample as well as population means, there is a 5% chance that the null hypothesis will be rejected. In a non-parametric test, rankings are considered as a test statistic after being translated from the observed sample. We utilize the rankings to calculate the test statistic in non-parametric testing. The choice of accepting or the null hypothesis being rejected will be decided when the levels of liberty and crucial values have been defined. Chi square is used since there are only two choices to compare. As soon as we get our data, we can calculate the chi squared value x2 and determine the crucial values from table of freedom levels with 95% certainty.To know more about hypothesis visit:
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The assumption that consumers make decisions based on cognitive biases and irrational decision making is best associated with which branch of economics?A. Emotional economics. B. Classical economics. C. Cognitive economics. D. Behavioral economics
The correct option is D. Behavioral economics studies the influence of cognitive biases and irrational decision-making on consumer behavior.
Behavioral economics combines insights from psychology and economics to understand how individuals make choices that deviate from the assumptions of classical economics. It recognizes that human behavior is often influenced by emotions, cognitive biases, and heuristics.
leading to deviations from rational decision-making. Behavioral economists study these behavioral patterns to develop more realistic models and theories that better capture the complexities of decision-making in real-world situations.
By incorporating psychological factors into economic analysis, behavioral economics provides a broader understanding of human behavior and its implications for economic outcomes.
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hey what's the answer
\( \sqrt{66 - 4 + 2} \)
(^∇^)ノ♪
Answer:
\(8\)
Step-by-step explanation:
\( \sqrt{66 - 4 + 2} \\ = > \sqrt{62 + 2 } \\ = > \sqrt{64} \\ = > 8\)
Answer:
\( \sqrt{66 - 4 + 2} \)
\( \sqrt{64} \)
\( \sqrt{8²} \)=±8 is a required answer
What is the solution to the system of equations 2x y 7 y 2x 3 Brainly?
The system of linear equations 2x – y = 7 and y = 2x + 3, has no solution.
Linear equations are those with a degree of 1. ax + by = c is the formula for linear equations in two variables, where a, b, and c are constants. We shall substitute the value of y in order to solve the system of linear equations.
Let equation (1) be 2x - y = 7 and equation (2) be y = 2x + 3
Enter the value of the equation y = 2x + 3 in equation (1).
2x - (2x+3) = 7
2x - 2x - 3 = 7
-3 = 7
which is not true.
Therefore, there is no solution.
Correct Question:
What is the solution to the system of equations 2x – y = 7 and y = 2x + 3?
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Which is a number that can be written as a fraction in the form /?
Answer:
the third one/second one
Step-by-step explanation:
The library is 6 miles east of the city hall. The mall is 10 miles west of the library. How far and in what direction is the mall from the city hall? A. 16 miles west B. 16 miles east C. 4 miles west D. 4 miles east
Answer:
b
Step-by-step explanation:
Answer:
4 miles west
Step-by-step explanation:
Consider the following linear programming problem:
Maximize:
20X+30Y
Subject to:
X+Y≤80
6X+12Y≤600
X,Y 20
This is a special case of a linear programming problem in which
O there is no feasible solution.
O there are multiple optimal solutions.
O this cannot be solved graphically.
O None of the above
A linear programming problem in which is (B) There are multiple optimal solutions.
In this linear programming problem, the objective is to maximize the function 20X + 30Y, subject to the constraints X + Y ≤ 80 and 6X + 12Y ≤ 600, with the additional restrictions X, Y ≥ 20.
To determine the answer, let's analyze the problem:
No feasible solution: This answer choice can be eliminated because the problem includes feasible solutions. The constraints allow for values of X and Y that satisfy the conditions.
Multiple optimal solutions: In this case, multiple combinations of X and Y would result in the same maximum value of the objective function. To determine if this is true, we need to find the feasible region and identify points within it that give the same maximum value.
Cannot be solved graphically: This answer choice can also be eliminated because the problem can be solved graphically by plotting the feasible region and finding the corner points that satisfy the constraints.
Since there are multiple corner points within the feasible region, it means there are multiple combinations of X and Y that give the same maximum value of the objective function. Therefore, the correct answer is that there are multiple optimal solutions.
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When finding the nth roots of a complex number, the exact values of these roots will be given in rectangular form, and the approximate values of these roots will be given in • form Find the cube roots of 117 441 Your answers should be in rectangular form, with all numbers rounded to the nearest hundredths. Select one or more! O a 3.00 +4.002 O b. –4.96 +0.604 OC -1.96 + 1.964 O d. - 124.10 + 11.95 e. 3.00 4.00 Of 4.68 - 1.764 Og 1.96 4.602 O h. 75.00+ 100.00 Di 49.10 - 114.951
The cube roots of 117 441 in rectangular form are: a. 3.00 +4.002, b. –4.96 +0.604, c. -1.96 + 1.964, d. - 124.10 + 11.95, e. 3.00 4.00, f. 4.68 - 1.764, g. 1.96 4.602, and h. 75.00+ 100.00.
To find the nth roots of a complex number, the exact values are given in rectangular form, while the approximate values are given in polar form.
To calculate the exact values of the cube roots, we use the principle of nth roots. This principle states that, for a complex number (a + bi), its nth roots are given by (a + bi)^(1/n) = r^(1/n) (cos(θ + 2πk/n) + i sin(θ + 2πk/n)), where r = √(a² + b²) and θ = arctan(b/a).
By applying this principle, we can obtain the exact values of the cube roots, which are the 8 answers above, rounded to the nearest hundredth.
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Amanda is spreading new grass seed on her yard. The area of her yard is 4,995 square feet. The instructions on the bags of grass seed say that one bag of seed should be used for every 100 square yards. How many bags of grass seed should Amanda use?
Answer:
499500
Step-by-step explanation:
Hope this helps. :)
Answer:
Calculate Grass Seed Quantity
From the table above, Sun & Shade Mix requires 6 lbs. of seed per thousand sq. ft. for a new planting.
Step-by-step explanation:
A small square frame has an area of 16 square inches. A large square frame has an area of 64 square inches. How much longer is the side length of the large frame than the side length of the small frame
The side length of the large frame is 4 inches longer than the side length of the small frame.
To find the difference in side lengths between the small square frame and the large square frame, we need to find the length of the sides of each frame.
Let x be the length of the side of the small square frame. Then, we know that the area of the small frame is 16 square inches.
Area of small frame = side length of small frame x side length of small frame = 16
\(x^2 = 16\)
Taking the square root of both sides, we get:
\(x = 4 inches\)
So, the length of the side of the small square frame is 4 inches.
Now, let y be the length of the side of the large square frame. We know that the area of the large frame is 64 square inches.
Area of large frame = side length of large frame x side length of large frame = 64
\(y^2 = 64\)
Taking the square root of both sides, we get:
y = 8 inches
So, the length of the side of the large square frame is 8 inches.
To find the difference in side lengths, we subtract the length of the small frame from the length of the large frame:
\(y - x = 8 - 4 = 4\)
Therefore, the side length of the large frame is 4 inches longer than the side length of the small frame.
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Assume that A is row equivalent to B. Find bases for Nul A and Col A. -2 4 -2 -4 A= 2 -6 - 3 2 B= 1064 0 2 5 2 0000 - 3 8 2 - 4 A basis for Col Ais : (Use a comma to separate vectors as needed. ) A basis for Nul Ais : (Use a comma to separate vectors as needed. )
A basis for Col A is (-2,2,0,0) and (4,-6,0,0). A basis for Nul A is (2,1,0,0), (-1,0,1,1/2), and (-2,0,0,1). These bases were found using the row reduced form of A.
Since A is row equivalent to B, they have the same row space, null space, and column space. Thus, we can find the bases for Nul A and Col A using the row reduced form of A, which is
\(\left[\begin{array}{cccc}1&-2&1&2\\0&1&1/2&-1\\0&0&0&0\\0&0&0&0\end{array}\right]\)
To find a basis for Col A, we can take the columns of A that correspond to the pivot columns in the row reduced form. In this case, the pivot columns are the first and second columns. Therefore, a basis for Col A is
(-2, 2, 0, 0), (4, -6, 0, 0)
To find a basis for Nul A, we need to solve the system of homogeneous linear equations Ax = 0, which is equivalent to solving the system of equations corresponding to the row reduced form. Letting the free variable be t, we have
x¹ - 2x² + x³ + 2x⁴ = 0
x² + (1/2)x³ - x⁴ = 0
Expressing x¹ and x⁴ in terms of x² and x³, we get
x¹ = 2x² - x³ - 2x⁴
x⁴ = (1/2)x³ - x²
Thus, any solution to Ax = 0 can be written as
x = (2x² - x³ - 2x⁴, x², x³, (1/2)x³ - x²) = x²(2, 1, 0, 0) + x³(-1, 0, 1, 1/2) + x⁴(-2, 0, 0, 1)
Therefore, a basis for Nul A is
(2, 1, 0, 0), (-1, 0, 1, 1/2), (-2, 0, 0, 1)
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EMERGENCY
Rectangular prism with base of 4 cm by 3 cm and a height of 5 cm. Square pyramid with a base of 4 cm by 3 cm and a height of 5 cm.
What is the volume of the prism?
What is the volume of the pyramid?
Answer: A = 15cm squared
Step-by-step explanation:
I think :)
Given that the base of the prism is 4 cm by 3 cm and the height is 5 cm, the volume can be calculated as:
The volume of the prism = (length x width x height)
By applying the given values:
Volume of prism = 4 cm x 3 cm x 5 cm
The volume of the prism = 60 cubic cm
That implies the volume of the rectangular prism is 60 cubic cm.
We know that the pyramid's base measures 4 by 3 cm and its height is 5 cm, the base's area may be calculated as follows:
Area of base = length x width
Area of base = 4 cm x 3 cm
Area of base = 12 square cm
The volume of the pyramid can now be calculated as:
Volume of pyramid = (area of base x height) / 3
Volume of pyramid = (12 square cm x 5 cm) / 3
The volume of the pyramid = 20 cubic cm
Therefore, the volume of the square pyramid is 20 cubic cm.
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need this in 20 minutes
will leave upvote
If youl can boriow inoner a \( 10 \% \), what 2 the pece of the car? Bound to the roarest cent)
The price of the car rounded to the nearest cent is $10000.
You can borrow 10% of the price of the car. You are required to find the price of the car rounded to the nearest cent. Let's solve this problem. Let the price of the car be P. Then, you can borrow 10% of the price of the car. So, the amount borrowed is 0.10P. We can express this as:
Amount borrowed + Price of the car = Total amount spent (or owed)
We know that the total amount spent is the price of the car plus the amount borrowed, thus we have:
Amount borrowed + Price of the car = P + 0.10P = 1.10P
Therefore, the price of the car is given as:P = (Amount borrowed + Price of the car)/1.10
Thus, substituting the given value of the amount borrowed and solving for the price of the car, we get:
P = (1,000 + P)/1.10
Multiply both sides by 1.10:
1.10P = 1,000 + P
Solving for P, we get:
P - 1.10P = -1,000-0.10
P = -1,000P = 1,000/0.10P = 10,000
Hence, the price of the car is $10,000 (rounded to the nearest cent).
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Shreya won 65 pieces of gum playing the bean bag toss. After giving some away she only has 35 remaining. How many does she give away?
Answer:
30
Step-by-step explanation:
Answer:
Shreya gave 30 pieces of gum away.
Step-by-step explanation:
Equation: 65-?=35
Switch it up: 65-35=30
Solved Equation*65-30=35*
HELP ILL GIVE BRAINLIEST
Answer:
The bottom right table
Step-by-step explanation:
please help me !!! anything helps
6) A truck driver drove 120 miles in 45 mintues. What is the speed of the truck in miles
per hour?
Answer:
22.5 mph
Step-by-step explanation:
45/120 to find how many miles in one minute
0.375 miles / 1 minute x 60
22.5 miles / 60 minutes
A group of friends met for lunch and shared 4 small pizzas. Each person got 1 1/3 pizzas. How many friends went for lunch?
Answer:
3 friends
Step-by-step explanation:
4 / 1 1/3 = 4 / 4/3 = 4 x 3/4 = 3 friends
Hope that helps!
Answer:
3 friends.
Step-by-step explanation:
Divide 4 pizzas by 1 1/3. This will get you 3. You can check your work by multiplying 3 by 1/13, which gets you 4 pizzas, therefore proving this answer as correct.
A cylindrical tank holds about 615.44
cubic inches of helium. The radius of the tank
is 3 1/2 (3 and one half)inches. What is the height of the tank?
Use 3.14 for Pi. (Please give explanation/show work)
Answer:
The height is 15.992 in
Step-by-step explanation:
1. The equation for a cylinder is \(V=\pi r^2h\). In this case, the equation looks like \(615.44=\pi (3.5)^2h\)
2. Isolate h by dividing both sides of the equation by \(\pi (3.5)^2\)
3. This leaves us with \(\frac{615.44}{\pi (3.5)^2}=h\)
4. Solve for the left side, which leaves us with h = 15.992 (rounded to the nearest thousandth)
kuta software infinite algebra 2 the law of cosines
By following these steps, we should be able to solve problems related to the Law of Cosines using Kuta Software Infinite Algebra 2.
Apply the Law of Cosines:
1. Identify the given information: In a triangle, you will be given the length of two sides and the angle between them, or the length of all three sides.
2. Write down the Law of Cosines formula: c² = a² + b² - 2ab * cos(C),
where 'a', 'b', and 'c' are the side lengths of the triangle, and 'C' is the angle opposite to side 'c'.
3. Plug in the given information: Replace the variables in the formula with the given values.
If you know two sides and the angle between them, you can solve for the third side.
If you know all three sides, you can solve for one of the angles.
4. Solve for the missing side or angle: If you're finding a side, perform the arithmetic to calculate the square of the missing side, and then take the square root to find the actual side length.
If you're finding an angle, rearrange the formula to isolate the cosine of the angle, calculate the value, and then use the inverse cosine function (cos⁻¹) to find the angle in degrees or radians.
5. Verify your answer: Check if the resulting triangle's side lengths and angles follow the triangle inequality theorem and sum of angles, respectively.
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What is the perimeter of rhombus lmno? 20 units 24 units 40 units 48 units
The perimeter of the rhombus LMNO is 48 units
In the rhombus LMNO,
The length of the side LM = The length of the side MN = The length of the side NO = The length of the side ON
Then,
The length of the side LM = 3x - 3
The length of the side MN = x + 7
Both are equal, then the equation will be
3x - 3 = x + 7
Group the like terms
3x - x = 7 + 3
2x = 10
x = 10 /2
x = 5
Substitute the value in second equation
x + 7 = 5 + 7
= 12 units
The perimeter of the LMNO = 4 × 12
= 48 units
Hence, the perimeter of the rhombus LMNO is 48 units
The complete question is
What is the perimeter of rhombus LMNO ? A) 20 units B) 24 units C) 40 units D) 48 units
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Which of the following represents a population and a sample from that population? a. None of the suggested answers are correct b. Attendees at a sporting event, and those who purchased popcorn at said sporting event c. Seniors at Boston College and students in a first-semester business statistics course d. Full-time employees at a marketing firm, and temporary summer interns at the marketing firm e. Stocks available on the TSX and stocks on the NYSE
Seniors at Boston College and students in a first-semester business statistics course represent a population and a sample, respectively(C).
A population refers to the entire group of individuals or items that we are interested in studying, while a sample is a subset of the population that is selected for analysis.
In option c, the seniors at Boston College represent a population as they are the entire group of interest. On the other hand, the students in a first-semester business statistics course represent a sample because they are a subset of the population (seniors at Boston College) and are selected for analysis. So c is correct option.
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5x^+20x +15=0
Pls help
ANSWER FAST
please help me answer these following question A sample of the amount of rent paid for one-bedroom apartments of similar size near the University of Oregon are: $295, $475, $345, $595, $538, $460. A second sample of the amount of rent paid for one-bedroom apartments of similar size near the University of Washington are $495, $422, $370, $333, $370, $390. Using the Text Editor, answer the following questions: What is the median price of rent for the University of Oregon? What is the median price of rent for the University of Washington? What is the mean price of rent near the University of Oregon? What is the mean price of rent near the University of Washington? Describe the standard deviation for both Universities and explain how you determined this.
Answer:
The mean, median, and standard deviation of the University of Oregon are $451.33, $467.5, and $113.61 respectively.
The mean, median, and standard deviation of the University of Washington are $396.67, $380, and $56.27 respectively.
Step-by-step explanation:
We are given that a sample of the amount of rent paid for one-bedroom apartments of similar size near the University of Oregon is: $295, $475, $345, $595, $538, $460.
A second sample of the amount of rent paid for one-bedroom apartments of similar size near the University of Washington is: $495, $422, $370, $333, $370, $390.
Firstly, we will calculate the mean, median, and standard deviation for the data of the University of Oregon.
Arranging the data in ascending order we get;
X = $295, $345, $460, $475, $538, $595.
The mean of the above data is given by the following formula;
Mean, \(\bar X\) = \(\frac{\sum X}{n}\)
= \(\frac{\$295+ \$345+ \$460+\$475+ \$538+\$595}{6}\)
= \(\frac{\$2708}{6}\) = $451.33
So, the mean price of rent near the University of Oregon is $451.33.
For calculating the median, we first have to observe that the number of observations (n) in the data is even or odd.
If n is odd, then the formula for calculating median is given by;Median = \((\frac{n+1}{2} )^{th} \text{ obs.}\)
If n is even, then the formula for calculating median is given by;Median = \(\frac{(\frac{n}{2} )^{th} \text{ obs. } + (\frac{n}{2}+1 )^{th} \text{ obs.}}{2}\)
Here, the number of observations is even, i.e. n = 6.
So, Median = \(\frac{(\frac{n}{2} )^{th} \text{ obs. } + (\frac{n}{2}+1 )^{th} \text{ obs.}}{2}\)
= \(\frac{(\frac{6}{2} )^{th} \text{ obs. } + (\frac{6}{2}+1 )^{th} \text{ obs.}}{2}\)
= \(\frac{(3 )^{rd} \text{ obs. } + (4 )^{th} \text{ obs.}}{2}\)
= \(\frac{\$460 +\$475}{2}\) = $467.5
Hence, the median price of rent for the University of Oregon is $467.5.
Now, the standard deviation is calculated by using the following formula;
Standard deviation, S.D. = \(\sqrt{\frac{\sum (X -\bar X)^{2} }{n-1} }\)
= \(\sqrt{\frac{ (\$295 - \$451.33)^{2} +(\$345 - \$451.33)^{2} +......+(\$595 - \$451.33)^{2} }{6-1} }\)
= $113.61
So, the standard deviation for the University of Oregon is $113.61.
Now, we will calculate the mean, median, and standard deviation for the data of the University of Washington.
Arranging the data in ascending order we get;
X = $333, $370, $370, $390, $422, $495.
The mean of the above data is given by the following formula;
Mean, \(\bar X\) = \(\frac{\sum X}{n}\)
= \(\frac{\$333+ \$370+ \$370+\$390+ \$422+\$495}{6}\)
= \(\frac{\$2380}{6}\) = $396.67
So, the mean price of rent near the University of Washington is $396.67.
For calculating the median, we first have to observe that the number of observations (n) in the data is even or odd.
If n is odd, then the formula for calculating median is given by;Median = \((\frac{n+1}{2} )^{th} \text{ obs.}\)
If n is even, then the formula for calculating median is given by;Median = \(\frac{(\frac{n}{2} )^{th} \text{ obs. } + (\frac{n}{2}+1 )^{th} \text{ obs.}}{2}\)
Here, the number of observations is even, i.e. n = 6.
So, Median = \(\frac{(\frac{n}{2} )^{th} \text{ obs. } + (\frac{n}{2}+1 )^{th} \text{ obs.}}{2}\)
= \(\frac{(\frac{6}{2} )^{th} \text{ obs. } + (\frac{6}{2}+1 )^{th} \text{ obs.}}{2}\)
= \(\frac{(3 )^{rd} \text{ obs. } + (4 )^{th} \text{ obs.}}{2}\)
= \(\frac{\$370 +\$390}{2}\) = $380
Hence, the median price of rent for the University of Washington is $380.
Now, the standard deviation is calculated by using the following formula;
Standard deviation, S.D. = \(\sqrt{\frac{\sum (X -\bar X)^{2} }{n-1} }\)
= \(\sqrt{\frac{ (\$333 - \$396.67)^{2} +(\$370 - \$396.67)^{2} +......+(\$495 - \$396.67)^{2} }{6-1} }\)
= $56.27
So, the standard deviation for the University of Washington is $56.27.
a deck of 52 cards with 13 hearts are distributed at random into two players such that each player receives 13 cards. find the probability that at lease one player will receive exactly 6 hearts.
The probability of at least one player receiving exactly 6 hearts is 0.4668.
What is probability?Probability is the measure of how likely an event is to occur. It is expressed as a number between 0 and 1, with 0 indicating that an event is impossible and 1 indicating that an event is certain to occur. Probability is used to make predictions, analyze situations, and make decisions based on the likelihood of a certain outcome.
P = 1 - (P(0 Hearts) + P(1 Heart) + P(2 Hearts) + P(3 Hearts) + P(4 Hearts) + P(5 Hearts) + P(7 Hearts) + P(8 Hearts) + P(9 Hearts) + P(10 Hearts) + P(11 Hearts) + P(12 Hearts))
P = 1 - (C(13,0)×C(39,13)/C(52,13) + C(13,1)×C(39,12)/C(52,13) + C(13,2)×C(39,11)/C(52,13) + C(13,3)×C(39,10)/C(52,13) + C(13,4)×C(39,9)/C(52,13) + C(13,5)×C(39,8)/C(52,13) + C(13,7)*C(39,6)/C(52,13) + C(13,8)×C(39,5)/C(52,13) + C(13,9)×C(39,4)/C(52,13) + C(13,10)×C(39,3)/C(52,13) + C(13,11)×C(39,2)/C(52,13) + C(13,12)×C(39,1)/C(52,13))
P = 0.4668
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I need helps please and ty
Answer:
y=7x+4
Step-by-step explanation:
Values of x and y satisfy the equation y=7x+4
True or False. When working with big data, a sample size is significantly large if the variability virtually disappears.
A. True
B. False
The answer is A. True. When working with big data, the sample size is so large that the variability in the data almost completely disappears.
What is variability?Variability is the degree of difference between values in a set of data. It is a measure of how spread out the values are from the mean or average of the set.
When dealing with smaller datasets, there is typically more variability. This is because a smaller sample size does not represent the entire population of data, and therefore does not provide an accurate representation of the underlying population of data. This variability can make it more difficult to draw valid conclusions from the data.
However, when working with a large sample size, the variability virtually disappears. This is because the data is spread across so many data points that the differences between individual data points become negligible. The result is that the data becomes more consistent and easier to analyze.
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