Does oil or water expand more? Will give brainliest!
Answer:
Heat, which is the exchange of energy between a system and its surroundings, occurs in three major ways: conduction, convection and radiation.
Which has higher heat capacity oil or water?
For both the hot plate and the microwave, olive oil will heat up faster than water because the heat capacity of oil is lower than the heat capacity of water. Water requires more energy per gram of liquid to change its temperature.
when I search I found this answer I hope it can help you answer your question.
at divergent plate boundaries, iron-rich minerals will align themselves with the existing magnetic field when they cool from a magma. t/f
Answer:
True
Explanation:
True or false—If a rock is thrown into the air, the increase in the height would increase the rock’s kinetic energy, and then the increase in the velocity as it falls to the ground would increase its potential energy.
If a rock is thrown into the air, the increase in the height would increase the rock’s kinetic energy, and then the increase in the velocity as it falls to the ground would increase its potential energy. _ This is false statement.
What is projectile motion?When a particle is hurled obliquely near the surface of the earth, it travels along a curved path while accelerating continuously in the direction of the planet's center (we assume the particle stays close to the surface of the globe). Such a particle's motion is known as projectile motion, and its route is referred to as a projectile.
In projectile motion total energy is conserved. Hence, when a rock is thrown into the air, the increase in the height would increase the rock’s potential energy, and then the increase in the velocity as it falls to the ground would increase its kinetic energy.
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A bar magnet has
a. one magnetic pole.
b. two magnetic poles.
c. three magnetic poles.
d. four magnetic poles.
Answer:
b
Explanation:
Bar magnets have two magnetic poles
HELP ME the mean free path λ and the mean collision time τ of the molecules of a diatomic gas of molecular mass 6.00 × 10⁻²⁵ kg and radius r = 1.0 x 10⁻¹⁰ m are measured. From these microscopic data can we obtain macroscopic properties such as temperature T and pressure P? If so, consider λ = 4.32 x 10⁻⁸ m and τ = 3.00 x 10⁻¹⁰ s and calculate T and P.
The temperature of the diatomic gas is 300.5 K and the pressure is 5.33 atm.
The given parameters;
Mass of the gas molecules, m = 6 x 10⁻²⁵ kgRadius of the gas, r = 1 x 10⁻¹⁰ mMean free path, \(\lambda_{rms}\) = 4.32 x 10⁻⁸ mMean collision time, \(\tau = 3 \times 10^{-10} \ s\)The mean velocity of the gas molecules is calculated as follows;
\(\tau = \frac{\lambda _{rms}}{V_{rms}} \\\\V_{rms} = \frac{\lambda _{rms}}{\tau} \\\\V_{rms} = \frac{4.32 \times 10^{-8} }{3 \times 10^{-10}} \\\\V_{rms} = 144 \ m/s\)
The temperature of the gas molecules is calculated as follows;
\(V_{rms} = \sqrt{\frac{3kT}{M} } \\\\V_{rms}^2 = \frac{3kT}{M} \\\\T = \frac{V_{rms} ^2 M}{3k}\)
where;
k is Boltzmann constant\(T = \frac{V_{rms} ^2 M}{3k} \\\\T = \frac{(144)^2 \times (6.0 \times 10^{-25})}{3 \times 1.38 \times 10^{-23}} \\\\T = 300.5 \ K\)
The number of gas molecules per unit volume is calculated as follows;
\(\lambda = \frac{1}{4\pi \sqrt{2} \ r^2 n} \\\\n = \frac{1}{\lambda 4\pi \sqrt{2} \ r^2} \\\\n = \frac{1}{(4.32 \times 10^{-8}) \times 4 \pi \times \sqrt{2} \ \times (1\times 10^{-10})^2} \\\\n = 1.303 \times 10^{26} \ molcules/m^3\)
The pressure of the gas molecule is calculated as follows;
\(n = \frac{P}{kT} \\\\P = nkT\\\\P = (1.303 \times 10^{26} ) \times (1.38 \times 10^{-23}) \times (300.5)\\\\P = 540,341.07 \ Pa\\\\P = 5.33 \ atm\)
Thus, the temperature of the diatomic gas is 300.5 K and the pressure is 5.33 atm.
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a sleepy student drops a calculator out of a window. we can ignore air resistance. what is the velocity of the calculator after falling for 1.8s?
Answer: -18
Explanation:
Answer:
its -18
Explanation:
Khan Academy
Each value measured in nature has a number value, called its magnitude, and
a dimension, or
Answer here
Answer:
yassssssssssssssssssssssssssssssssssssss
Explanation:
A ball of mass m is fastened to a string. the ball swings at constant speed in a vertical circle of radius r with the other end of the string held fixed. neglecting air resistance, what is the difference between the string's tension at the bottom of the circle and at the top of the circle? (note: a vertical circle means the ball is moving up and down as it goes in a circle - this means that gravity must be considered.)
The difference between the string's tension at the bottom of the circle and at the top of the circle is 2mg.
Given the mass of the ball is m
radius of circle = r and constant speed is maintained = v
At the top of the circle, ΣF = FT + mg = mv^2/r, where F is the force acting on the string, T is tension, m is mass and g is gravitational acceleration.
Here as the ball moves in circle it carries centripetal force = mv^2/r.
Then FT = mv^2/r – mg.
At the bottom of the circle, ΣF = FT – mg = mv^2/r, So
FT = mv^2/r + mg
By comparing these two equations we get:
The difference is (mv^2/r + mg) – (mv^2/r – mg) = 2mg.
Hence the required difference is 2mg.
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There is a 2mg difference in string tension between the circle's bottom and top points.
Calculation:the mass of the ball is m
radius of circle = r and constant speed is maintained = v
At the top of the circle, ΣF = FT + mg = mv^2/r, where F is the force acting on the string, T is tension, m is mass and g is gravitational acceleration.
Here as the ball moves in circle it carries centripetal force = mv^2/r.
Then FT = mv^2/r – mg.
At the bottom of the circle, ΣF = FT – mg = mv^2/r, So
FT = mv^2/r + mg
By comparing these two equations we get:
The difference is (mv^2/r + mg) – (mv^2/r – mg) = 2mg.
Hence the required difference is 2mg.
Why does the top of a circle have zero tension?When the centripetal force and the gravitational force are exactly equal at the peak of the swing, the minimum speed will occur. The tension would then be exactly zero, and the ball would hardly be able to keep rolling in a circle.
Why is the bottom where stress is greatest?The weight of the body operates vertically downward while the centrifugal force acts vertically downward at the lowest position. As a result, the string's tension is at its highest. The weight of the body acts vertically downward and the centrifugal force acts vertically upward at the highest point.
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A ball is thrown horizontally at 30 m/s from a height of 45m. How long is it in the air?
(i) How fast is it moving horizontally when it hits the ground?
Answer:
1.25s
1) 90.9m
Explanation:
From the question, we are given the following;
Speed v = 30m/s
Maximum height H = 45m
Required;
Time
Using the equation of motion S = ut + 1/2gt²
Substitute;
45= 30t + 1/2(9.8)t²
45 = 30t + 4.9t²
4.9t² + 30t - 45 = 0
Factorize;
t = -30 ±√30²-4(-45)(4.9)/2(4.9)
t = -30 ±√900+882/9.8
t = -30 ±42.21/9.8
t = -30 + 42.21/9.8
t = 12.21/9.8
t = 1.25secs
Hence the ball spent 1.25secs in air.
i) To get the horizontal distance, we will use the formula;
R = U√2H/g
R = 30√2(45)/9.8
R = 30√90/9.8
R = 30√9.18
R = 30(3.03)
R = 90.9m
Hence the horizontal distance is 90.9m
In the graph below, why does the graph stop increasing after 30 seconds?
A. The hydrogen gas is absorbing heat to undergo a phase change.
B. A catalyst needs to be added to increase the amount of hydrogen produced.
C. No more hydrogen can be produced because all of the reactants have become products at this point.
D. It has reached the maximum amount of product it can make at this temperature. The temperature would need to increase to produce more.
Answer:
The answer is "Option C".
Explanation:
It's evident from the figure below that after thirty minutes, not no more hydrogen can be created because all of the reactants have converted into products.
hydrogen gas created in cm cubes per period x = 20 seconds, y = 45 centimeters squared, and so on.
A reaction's terminus (the graph's flat line) indicates that no further products are being created during the reaction.
Problem #2.3
A sphere of radius i rotates with an angular velocity of 2 about the axis Oz. The surface
charge density c is constant. Find the vector potential and intensity of the magnetic
field inside and outside the sphere.
The vector potential inside the sphere is μ₀cπ, and the magnetic field inside the sphere is zero. Outside the sphere, the magnetic field intensity is given by B = (μ₀cR²/r²), where R is the radius of the sphere and r is the radial distance from the center of the sphere.
To find the vector potential and intensity of the magnetic field inside and outside a rotating sphere with a constant surface charge density, we can use the Biot-Savart law and Ampere's law.
Inside the sphere:
Inside the sphere, the radial distance r is less than the radius R of the sphere. We consider a circular current loop of radius r within the sphere.
Using the Biot-Savart law, the vector potential (A) at a point inside the sphere due to the circular current loop can be expressed as:
A = (μ₀/4π) ∫(Idl × r)/r²
Since the charge density is constant, the current (I) flowing through the circular loop is proportional to the area of the loop, which can be expressed as I = c × πr².
Substituting this expression for I into the equation for A, we get:
A = (μ₀c/4) ∫(dl × r)/r²
By integrating around the loop, we find that the integral term is equal to 2π, and simplifying further, we obtain:
A = (μ₀c/2r) ∫dl
The integral term on the right-hand side is simply the circumference of the loop, which is 2πr. Substituting this back into the equation, we get:
A = (μ₀c/2r) × 2πr = μ₀cπ
The magnetic field (B) can be obtained from the vector potential using the equation B = ∇ × A. Since the vector potential A is independent of position, the curl of A is zero. Therefore, the magnetic field inside the sphere is zero.
Outside the sphere:
Outside the sphere, the radial distance r is greater than the radius R of the sphere. Using Ampere's law, we can find the magnetic field.
Around a circular loop outside the sphere, the magnetic field is given by:
B = (μ₀I/2πr)
Since the current I is proportional to the area of the loop, which is πR², we have I = cπR². Substituting this expression for I into the equation for B, we get:
B = (μ₀cR²/2πr³) × 2πr = (μ₀cR²/r²)
Therefore, the intensity of the magnetic field outside the sphere is given by B = (μ₀cR²/r²).
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kenneth ran a marathon (26.2 miles) in 5.5 hours. What was Kenneth’s average speed? (Round your answer to the nearest tenth.)
0.2 mph
4.8 mph
5.5 mph
144.1 mph
it is actually science i couldn't find the word science
Answer:
4.8mph
Explanation:
Speed= Distance/time
Speed= 26.2/5.5
= 4.76mph
( To the nearest tenth ) = 4.8mph
Answer:
38.7 mph
Explanation:
I just add all the numbers together then divided them by 4, which is the amount of numbers you gave.
I need help with (c) please
The frequency of light with a wavelength of 655 nm is 4.58 x 1014 Hz, the frequency of light with a wavelength of 515 nm is 5.83 x 1014 Hz, and the frequency of light with a wavelength of 475 nm is 6.32 x 1014 Hz. The frequency of light can be calculated using the equation c = λν, where c is the speed of light, λ is the wavelength, and ν is the frequency.
The visible spectrum of electromagnetic radiation has a range of wavelengths that varies from the longest (red) to the shortest (violet) that our eyes can detect. The frequencies of light with wavelengths of 655 nm, 515 nm, and 475 nm can be calculated using the equation c = λν, where c is the speed of light, λ is the wavelength, and ν is the frequency.(a) For light with a wavelength of 655 nm, the frequency can be calculated as: c = λν ==> ν = c/λ where c = 3.00 x 108 m/s (speed of light in a vacuum)λ = 655 nm = 6.55 x 10-7 m. Therefore, ν = (3.00 x 108 m/s) / (6.55 x 10-7 m) = 4.58 x 1014 Hz(b) For light with a wavelength of 515 nm, the frequency can be calculated as: c = λν ==> ν = c/λ where c = 3.00 x 108 m/s (speed of light in a vacuum)λ = 515 nm = 5.15 x 10-7 m. Therefore, ν = (3.00 x 108 m/s) / (5.15 x 10-7 m) = 5.83 x 1014 Hz(c) For light with a wavelength of 475 nm, the frequency can be calculated as: c = λν ==> ν = c/λ where c = 3.00 x 108 m/s (speed of light in a vacuum)λ = 475 nm = 4.75 x 10-7 m. Therefore, ν = (3.00 x 108 m/s) / (4.75 x 10-7 m) = 6.32 x 1014 Hz.For more questions on frequency
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A single loop of wire with an area of 0.0820 m2 is in a uniform magnetic field that has an initial value of 3.80 T, is perpendicular to the plane of the loop, and is decreasing at a constant rate of 0.220 T/s .
Required:
a. What emf is induced in this loop?
b. If the loop has a resistance of 0.600Ω, find the current induced in the loop.
Answer:
a) emf = 0.01804 V
b) I = 0.03 A
Explanation:
a) The emf is calculated by using the following formula:
\(|emf|=|\frac{d\Phi_B}{dt}|=|\frac{d(A\cdot B)}{dt}|\) \(=A|\frac{dB}{dt}|\)
A: area of the loop = 0.0820m^2
B: magnitude of the magnetic field
dB/dt: change of the magnetic field, in time: 0.220 T/s
Where ФB is the magnetic flux, the surface vector and magnetic vector are perpendicular between them, and the area A is constant.
You replace the values of A and dB/dt in the equation (1):
\(|emf|=(0.082m^2)(0.220T/s)=0.01804V\)
b) The current in the loop is:
\(I=\frac{emf}{R}\)
R: resistance of the loop = 0.600Ω
\(I=\frac{0.01804V}{0.600\Omega}=0.03A=30mA\)
a. The emf induced in this loop is 18.04mV.
b. The current induced in the loop is 30.06mA.
a. We know that,
\(flux(\phi)=B*A\)
Where B is magnetic field and A is the area.
\(emf=\frac{d\phi}{dt}=A*\frac{dB}{dt}\)
Given that, Area , \(A=0.0820m^{2},B=3.80T,\frac{dB}{dt}=0.220T/s\)
Substituting all values in above equation.
\(emf=0.0820*0.220=0.01804V=18.04mV\)
b. Resistance, \(R=0.600ohm\)
Current induced in the loop is,
\(I=\frac{emf}{R}=18.04/0.6=30.06mA\)
Hence, the emf induced in this loop is 18.04mV.
The current induced in the loop is 30.06mA.
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You have two identical looking spools (same mass, same shape, same size). However, one is hollow, made from iron, the other is solid, made from aluminum. A string is wound around each spool. If you pull on both strings with equal forces, which spool is going to have the larger angular acceleration
Answer:
The one made from AL will have a smaller moment of inertia and thus a greater acceleration:
α = I ω
I = M R^2 for the iron (all the mass at a distance R)
Replacing any of the Fe with Al (and putting at a smaller radius) is going to reduce the total moment of inertia,
A guitar string transmits waves at
315 m/s, and oscillates at 370 Hz.
What is the length of the string?
(Unit = m)
Answer:
The wavelength of the waves on the string is found using v = λf:
λ = v/f = 315/370 = 0.85135m
The first harmonic (fundamental) standing wave formed on the string has nodes only at the ends (see diagram in link) so:
String length = λ/2 = 0.85135/2 = 0.426m (to 3 sig. figs.)
Is frictional force the only example of non-conservative force?
Answer: NO, there are many examples of non-conservative forces.
Explanation: Conservatives forces are special forces whose work is zero in a closed path.
Magnetic and Electric fields are Non- Conservative.John drove a truck for one hour at a rate of 80 kilometers per hour (km/hr). The next hour, he drove at 100 km/hr. What was his average speed during those two hours?
km/hr
Please i have asked a.question please help.me
Explanation:
Please i have asked a question in math please help me
Show work for either one thanks
The maximum velocity of the pendulum is determined as 3.03 m/s.
Maximum velocity of the pendulum
The maximum velocity of the pendulum is calculated from the principle of conservation of energy as shown below;
K.E = P.E
¹/₂mv² = mgh
v² = 2gh
v = √2gh
where;
h is the maximum height = 0.468 mv is the maximum velocityv = √(2 x 9.8 x 0.468)
v = 3.03 m/s
Thus, the maximum velocity of the pendulum is determined as 3.03 m/s.
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Which of the following substances is a compound?
O A. hydrogen gas
B. nitrogen gas
O c. table sugar
O D. oxygen gas
Table sugar is a compound, it consists of carbon, hydrogen, and oxygen.
Hence, C is the correct answer.
What is the chemical state of matter?The chemical state of matter consists :
ElementCompound andMixturesElement-The substance which contains only one atom and cannot be broken down. Example-Hydrogen.Compound-It is defined as a substance formed when two or more chemical elements are chemically bonded together. The substance can be pure or impure.Mixture-It contains two or more elements or compounds, but they are not chemically combined. Mixtures are of two types :Homogeneous mixture and,Heterogeneous mixtureHence, table sugar is a compound because it is formed by more than 2 chemical elements, and they are chemically bonded together.
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what is the total moved without regard to direction
The entire motion of an object, regardless of direction.
In physics, motion is that the phenomenon in which an object changes its position with respect to time. Motion is mathematically described in terms of displacement, distance, velocity, acceleration, speed, and frame of regard to an observer and measuring the change in position of the body relative to that frame with change in time. The branch of physics describing the motion of objects without regard to their cause is called kinematics, while the branch studying forces and their effect on motion are named dynamics.
If an object isn't changing relative to a given frame of reference, the thing is said to be at rest, motionless, immobile, stationary, or to possess a constant or time-invariant position with reference to its surroundings. Modern physics holds that, as there's no absolute frame of reference, Newton's concept of absolute motion can't be determined
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Given f(x)= 5x-4, find x if f(x)= 26
Answer:
126
Explanation:
Find the vector whose magnitude is 5 and which is in the direction of the vector 4i -3j +k
The vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.
To solve this problemThe given vector can be normalized before being multiplied by the desired magnitude. This is how to locate the vector:
The vector that has been provided should be normalized by dividing each of its components by its magnitude. The Pythagorean theorem can be used to determine the magnitude of the vector 4i - 3j + k:
Magnitude = √(4² + (-3)² + 1²) = √(16 + 9 + 1) = √26
Normalize the vector by dividing each component by the magnitude:
Normalized vector = (4/√26)i + (-3/√26)j + (1/√26)k
Multiply the normalized vector by the desired magnitude:
To obtain a vector with a magnitude of 5, multiply each component of the normalized vector by 5:
Desired vector = 5 * ((4/√26)i + (-3/√26)j + (1/√26)k)
Simplifying the expression gives:
Desired vector ≈ (20/√26)i + (-15/√26)j + (5/√26)k
So, the vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.
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I don't know understand how to approach this problem.
The centripetal acceleration of the plane is 0.255 g.
What is centripetal acceleration?
centripetal acceleration is the rate at which a body moves through a circle. Due to the fact that velocity is a vector quantity (i.e., it has both a magnitude, the speed, and a direction), when a body travels in a circle, its direction is continually changing, which causes a change in velocity, which results in an acceleration. The circle's Centre is where the acceleration is pointed radially.
Since we are given the tension in the cable and the angle of inclination, we can use trigonometry to find the vertical and horizontal components of tension.
Tsinθ = mg
Tcosθ = mv²/r
where θ = 35°, v = 180 km/h = 50 m/s, r = 1000 m, and m = 1000 kg.
Solving for Tsinθ and Tcosθ, we get:
Tsinθ = mg = (1000 kg)(9.81 m/s²) = 9810 N
Tcosθ = mv²/r = (1000 kg)(50 m/s)²/(1000 m) = 2500 N
Now we can use the horizontal and vertical components of tension to find the centripetal acceleration:
Tcosθ = ma
a = Tcosθ/m = (2500 N)/(1000 kg) = 2.5 m/s²
To express this acceleration in terms of g, we divide by the acceleration due to gravity:
a/g = 2.5 m/s² / 9.81 m/s² = 0.255
Therefore, the centripetal acceleration of the plane is 0.255 g.
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2. A crane can lift a 500 kg mass to height of 30 m in 2 minutes. The power at which the crane is operating is
A. 125 Watts
B. 1225 Watts
C.) 7500 Watts
D. 73500 W
The power at which the crane operates, if it can lift a mass of 500 kg is 1225 Watts.
What is power?Power is the rate at which work is done.
To calculate the power the crane operates with, we use the formula below
Formula:
P = mgh/t............................... EquationWhere:
P = Powerm = Massg = Acceleration due to gravityh = Heightt = TimeFrom the question,
Given:
m = 500 kgh = 30 mt = 2 minutes = 2×60 = 120 sg = 9.8 m/s²Substitute these values into equation 1
P = (500×30×9.8)/120P = 1225 WHence, the right option is B. 1225 Watts.
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What does volume measure name two different units that might be used to measure volume
Answer:
Volume measures liquid
Explanation:
Volume can be measured in meters and centimeters
What are supernovae?
A. stars that have reached the end of their lifetimes because their nuclear fuel is exhausted
B. stars that suddenly brighten by 100 to 10,000 times in a day
с. stars that have just been born
D. galaxles that have binary systems
Answer:
A
Explanation:
AAAaaaaaaaaaaaaaaaaaaaaaaaaa
Answer:
A. Stars that have reached the end of their lifetimes because their nuclear fuel
Explanation:
plato
An example of a Natural electric field is
Answer:
Lightning
Explanation
A 3.5 kilogram is loaded with a 0.52 kilogram ball. The cannon and ball are initially rolling forward with a speed of 1.27 m/s. The cannon is fired and launches the ball forward with a total speed of 75 m/s. Determine the post-explosion velocity of the cannon.
The cannon and ball are initially moving at a speed of 1.27 m/s. The cannon is fired, propelling the ball forward at a speed of 75 m/s. The post-explosion velocity of the gun is 6.18 m/s.
Total momentum prior = Total momentum subsequent
(3.5 kg + 0.52 kg) × 1.27 m/s = 3.5 kg × \(v_{cannon}\) + 0.52 kg × 75 m/s
where \(v_{cannon}\)is the velocity of the gun following the explosion.
When we simplify and solve for \(v_{cannon}\), we get:
\(v_{cannon}\) = (0.52 kg × 75 m/s - (3.5 kg + 0.52 kg) × 1.27 m/s) / 3.5 kg
\(v_{cannon}\) = 6.18 m/s.
Velocity is a measure of how quickly an object changes its position in a particular direction. It is commonly represented as a vector quantity with both magnitude and direction. The magnitude of velocity is the speed at which an object is moving, while the direction is the path it is following.
In physics, velocity is a fundamental concept used to describe motion in various contexts, including mechanics, kinematics, and dynamics. It is calculated as the rate of change of displacement with respect to time, expressed in meters per second (m/s) or other units.
Velocity is a critical parameter in understanding the behavior of objects and systems, such as vehicles, projectiles, fluids, and celestial bodies. It affects their acceleration, force, energy, and other characteristics that determine their motion and interactions. Engineers, scientists, and other professionals use velocity to design, analyze, and optimize a wide range of applications, from transportation to manufacturing to space exploration.
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How do I solve for the maximum height of someone who jumps straight up leaving the ground at 6.0 m/s.
Answer: 3.0 m/s
Explanation: