Answer:
Not gonna lie. I actually had to think about this a lot XD
Running in the rain can cause you to slip and get hurt. Which I think isn't what you would want.
Walking in the rain (although it is sad), is actually a better idea than running.
Hope this helps!
Answer:
Walk
Explanation:
Running might stop you from being outside for as long, but running on wet ground will most likely result in a not-so-graceful faceplant.
Answer these questions pls ASAP
Answer:
Balloon , vaccum,and thats about it at least all i can think of
Particles q₁ +8.0 μC, q2 +3.5 μC, and
93-2.5 μC are in a line. Particles q₁ and q2 are
separated by 0.10 m and particles q2 and q3 are
separated by 0.15 m. What is the net force on
particle q₂?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
+8.0μ.C
+91
0.10 m
+3.5 C
+92
0.15 m
-2.5μ C
93
The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.
To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.
The force between two charged particles can be calculated using Coulomb's law:
F = k * |q₁ * q₂| / r²
Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.
First, let's calculate the force exerted on q₂ by q₁:
F₁₂ = k * |q₁ * q₂| / r₁₂²
F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²
F₁₂ ≈ 252000 N
The force is positive because q₁ and q₂ have opposite charges.
Next, let's calculate the force exerted on q₂ by q₃:
F₂₃ = k * |q₂ * q₃| / r₂₃²
F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²
F₂₃ ≈ -63000 N
The force is negative because q₂ and q₃ have the same charge.
Finally, we can find the net force on q₂ by summing the individual forces:
Net force = F₁₂ + F₂₃
Net force = 252000 N + (-63000 N)
Net force ≈ 189000 N
The net force on particle q₂ is approximately 189000 N.
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A ball is projected at an angle of 53°. If the initial velocity is 48 meters/second, what is the vertical component of the velocity with which it was launched?
A.) 31 meters/second
B.) 38 meters/second
C.) 44 meters/second
D.) 55 meters/second
Answer:
The vertical component of the velocity can be found using the formula:
V₀y = V₀ * sin(θ)
where V₀ is the initial velocity, θ is the angle of projection, and V₀y is the vertical component of the velocity.
Substituting the given values, we have:
V₀y = 48 * sin(53°)
Using a calculator, we can evaluate sin(53°) to be approximately 0.799:
V₀y = 48 * 0.799
V₀y ≈ 38.352
Therefore, the vertical component of the velocity with which the ball was launched is approximately 38 meters/second, which corresponds to option B.
Answer:
B.) 38 meters/second
Explanation:
Sound energy can be produced by which of these objects below? 1:drum2:flashlight3:copper4:battery
The drum is one of the objects that produce sound energy. When the drum is stuck by the person, it transfers the energy in the form of sound.
Hence, the correct answer is drum.
In the summer time fruit flies are the worst. One morning I woke up to 5 fruit flies in my kitchen. Three hours later there were 13 fruit flies. If the growth rate is continuous, at what rate are the flies increasing? Round answers to four decimal places.
We are asked to determine the continuous growth rate. To do that we will use the following function:
\(P(t)=P_0e^{kt}\)Where "P0" is the initial population, "k" is the growth rate, and "t" is time. Replacing the initial population of 5 we get:
\(P(t)=5e^{kt}\)Now we are told that the population is 13 when the time is 3 hours. Replacing we get:
\(13=5e^{3k}\)Now we solve for "k". First, by dividing both sides by 5:
\(\frac{13}{5}=e^{3k}\)Now we take natural logarithm to both sides:
\(\ln (\frac{13}{5})=\ln (e^{3k})\)Now we use the following property of logarithms:
\(\ln x^y=y\ln x\)Applying the property:
\(\ln (\frac{13}{5})=3k\ln e\)We have that the value of ln(e) is 1, therefore:
\(\ln (\frac{13}{5})=3k\)Now we divide both sides by 3:
\(\frac{1}{3}\ln (\frac{13}{5})=k\)Solving the operation we get:
\(0.319=k\)Therefore, the growth rate is 0.319.
PLEASE HELP 15 POINTS AND BRAINIEST
Reporting fake answers
A ball has a mass of 1.99x1040 kg. The planet Neptune has a mass of 1.03x1026 kg and is 4.50x1012 m from the Sun.
Calculate the gravitational force between the Sun and Neptune.
Answer:
6.75×10³⁰ N.
Explanation:
Applying Newron's Law of universal gravitation.
From the question,
F = Gm₁m₂/r²................................................................. Equation 1
Where F = Gravitational force between the sun and Neptune, m₁ = mass of Neptune, m₂ = mass of the sun, r = distance bewteen the sun and Neptune, G = gravitational constant.
Given: m₁ = 1.99×10⁴⁰ kg, m₂ = 1.03×10²⁶ kg, r = 4.50×10¹² m
Constant: G = 6.67×10⁻¹¹ Nm²kg⁻².
Substitute these values into equation 1
F = [(6.67×10⁻¹¹)( 1.99×10⁴⁰)(1.03×10²⁶)]/(4.50×10¹²)²
F = (13.67×10⁴⁰⁺²⁶⁻¹¹)/(20.25×10²⁴)
F = (13.67×10⁵⁵)/(20.25×10²⁴)
F = 0.675×10⁵⁵⁻²⁴
F = 0.675×10³¹
F = 6.75×10³⁰ N.
3. A car with a mass of 1600 kg has a kinetic energy of 125 000 J. How fast is it moving?
The car is moving at approximately 12.5 meters per second.
The kinetic energy (KE) of an object can be calculated using the formula:
KE = 1/2 * m * \(v^2\)
where
KE = kinetic energy,
m =Mass of the object, and
v = velocity.
In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .
Substituting the values , we have:
125,000 J = 1/2 * 1600 kg *\(v^2\)
Now, we can solve for v by rearranging the equation:
\(v^2\) = (2 * 125,000 J) / 1600 kg
\(v^2\) = 156.25 \(m^2/s^2\)
Taking the square root, we find:
v = √156.25\(m^2/s^2\)
v ≈ 12.5 m/s
Therefore, the car is moving at approximately 12.5 meters per second.
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Were is the computer located
Answer:
where u put it last time or retrace ur steps to where u last put it
which phase of the moon is above the horizon during the day, but the most difficult to see? group of answer choices full moon waning half new moon first quarter
We can't see the moon in the new moon since the sun is quite far from the earth.
What is the moon?We know the moon to be one of the heavenly bodies. The heavenly bodies are those bodies that we tend to see in the outer space. There are several heavenly bodies that we have out there and they can be classified based on weather or not the bodies do produce light.
The heavenly bodies that produce light as said to be luminous bodies while the heavenly bodies that do not produce light are said to be non luminous bodies.
Now we can see that the moon s a non luminous body and it depends on the sun so as to be able to give light. In this case, we know that the moon may sometimes be hidden from sight and can not be seen and this occurs in the course of the new moon because the side of the moon that gets the light lies at a far away position from the earth.
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POINTS + BRAINLIEST TO CORRECT ANSWER
In old Polaroid cameras, the image was projected on film that developed inside the camera. The developed image was then ejected from the camera as a printed photograph. The standard film size for one popular camera was 79 mm square. The film was 116 mm behind the lens.
If you wanted a picture of your 1.8-m-tall friend to fill half the frame, how far away from you did she need to stand?
100 points + Brainliest to correct answer
Answer:
5.3 m
Explanation:
Your friend is 1800 mm tall, and you want them to fill half the frame (79 mm / 2 = 39.5 mm).
The film is 116 mm behind the lens. Using similar triangles:
x / 1800 = 116 / 39.5
x = 5286
Rounded to two significant figures, your friend should stand 5.3 meters away.
In a DC generator, the generated emf is directly proportional to the
In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.
This relationship is described by the equation for the generated emf in a DC generator:
Emf = Φ * N * A * Z / 60
Where:
Emf is the generated electromotive force (in volts),
Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),
N is the number of turns in the armature winding,
A is the effective area of the armature coil (in square meters),
Z is the total number of armature conductors, and
60 is a constant representing the conversion from seconds to minutes.
From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.
The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.
The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.
Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.
By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.
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The questions are in the pictures
A ladder is leaned against a wall. The wall has friction but the floor is frictionless. It should be noted that the ladder cannot be in static equilibrium
How to explain the equilibriumIn order for the ladder to be in static equilibrium, the net force acting on it must be zero. However, in this case, there will be a horizontal force exerted by the wall on the ladder due to friction, which will create a torque about the base of the ladder.
When a ladder is leaned against a wall, it exerts a force on the wall called the normal force, which is perpendicular to the surface of the wall. In order for the ladder to be in equilibrium, the normal force must balance the weight of the ladder and any objects on it. This torque will cause the ladder to rotate and hence, it cannot be in static equilibrium.
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3. What are the charges and location of each of the parts of the atom?
There are two parts main parts of the atoms they are the nucleus and the orbits.
The atom mains consists of three particles, protons, neutrons, and electrons.
The protons are positively charged particles. The charge of a proton is 1.602×10⁻¹⁹ C. And the neutron does not possess any charge. The neutrons are neutral particles. Protons and neutrons are located at the nucleus of an atom.
The electrons are negatively charged particles. The charge of an electron is -1.602×10⁻¹⁹ C. The electrons will be orbiting the nucleus. Thus they are located around the nucleus of an atom.
How do meteorites differ from meteors and meteoroids?
Answer:
When meteoroids enter Earth's atmosphere (or that of another planet, like Mars) at high speed and burn up, the fireballs or “shooting stars” are called meteors. When a meteoroid survives a trip through the atmosphere and hits the ground, it's called a meteorite.
Explanation:
Answer: Meteoroid: Small particle from a comet or asteroid orbiting the Sun. Meteor: The light phenomena which results from a meteoroid entering the Earth's atmosphere and vaporizing; this is basically a shooting star. Meteorite: A meteoroid that survives through the Earth's atmosphere and lands on the Earth's surface.
*
If a rock falls for 3 seconds off of a bridge, how far will the rock fall?
-30 m
-45m
-60m
-75m
What is the purpose of using an ammeter to demonstrate that a moving
magnet causes an electric current to flow in a wire coil?
A. It detects any current in the wire.
B. It protects the investigators from receiving an electric shock.
C. It increases the strength of the permanent magnet.
D. It takes the place of the battery needed for an electromagnet.
Answer: A
Explanation:
Answer:
The answer is A. It detects any current in the wire.
Explanation:
I took the quiz.
1. A 15.0 kΩ resistor is hooked up to a 45.0 V battery in a circuit with a switch.
(a) Draw a circuit diagram for the circuit described. Label all parts and values.
(b) What is the current flowing through the resistor?
(c) What is the power dissipated by the resistor?
(a) The circuit diagram is in the image attached.
(b) The current flowing through the resistor is 0.003 A.
(c) The power dissipated by the resistor is 0.135 W.
What is current flowing through the resistor?(b) The current flowing through the resistor is calculated by applying Ohm's law as follows;
V = IR
I = V/R
where;
V is the voltageR is resistanceI = 45 V / 15,000Ω
I = 0.003 A
(c) The power dissipated by the resistor is calculated as follows;
P = IV
where;
I is the current V is the voltageP = 0.003 x 45 V
P = 0.135 W
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If you pull with a constant force of 400n , how much mechanical work does it take to pull pinball launcher back 0.2meters
If you pull with a constant force of 400 N for 0.2 meters, then the work done will be equal to 80 J.
What is Work?In physics, the word "work" involves the measurement of energy transfer that takes place when an item is moved over a range by an externally applied, at least a portion of which is applied within the direction of the displacement.
The length of the path is multiplied by the element of a force acting all along the path to calculate work if the force is constant. The work W is theoretically equivalent towards the force f times the length d, or W = fd, to portray this concept.
As per the given information in the question,
Force, f = 400 N
Displacement, d = 0.2 meters
\(Work done(W)=Force(f)*Displacement(d)\)
W = 400 × 0.2
W = 80 J.
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How are magnetic fields like vectors?
Answer:Magnetic fields from two sources add up as vectors at each point, so the strength of the field is not necessarily the sum of the strengths1. Magnetic fields are vectors, which means they have direction as well as size. Therefore, the sum of two magnetic fields is not simply the sum of their magnitudes2.
Explanation:
Four very long straight parallel wires, located at the corners of a square of side l, carry equal currents Io perpendicular to the page as shown in Figure. Determine the magnitude and direction of B at the center C of the square.
The magnitude and direction of B at the center C of the square is
2µNIo/πL on every corner of square.
Given that four long straight parallel wires, located at the corners of a square carry equal currents perpendicular to the page.
Side of a square = L
current in square wire = Io
Here C is located at the center then distance from any corner point to center C be r. Here r acts as the hypotenuse such that r = L/√2
We know that electric field (B) = NI/2πr and is same at every point on square. Ba = Bb = Bc = Bd
B = µNIo/2π(L/√2)
B = √2µNIo/2πL
Bnet = 4 x Bcos45 = 4 x √2µNIo/2πL x 1/√2
Bnet = 2µNIo/πL
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How much work is done when pushing a desk with a force of 28N across the distance of 1.7 meters?
The work done when pushing a desk is (W)= 47.6 Joules
What is work?When an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement that explains that the work done on a object.
How can we calculate the values of the work?To calculate the values of the work done we are using the formula,
W = F×d
Here, we are given,
F = Exerted Force =28N
d = Covered Distance in the desk =1.7m
We have to calculate,
W = Work done, unit in Nm or joules
Now we put the known values in the above equation, we get,
W = F×d
Or, W = (28N)×(1.7m)
Or, W = 47.6 Nm
Or, W = 47.6 Joules
Now we can say that,
The work done when pushing a desk is (W)= 47.6 Joules
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Which two options are forms of potential energy
Answer:
Energy is the ability to do work or cause change. There are two kinds of energy – kinetic energy when something is moving, and potential energy, which is energy that is stored and ready to be used. All objects have potential energy or stored energy if they are placed in a certain position.
Answer:
chemical energy and nuclear energy - Apex
If a body travelled a distance 's' in 't'.
What is the distance travelled in 't'
Answer: Distance traveled in time t is s
Explanation: Self Explanatory
Which phrase best defines momentum?
A. the change in velocity of an object over time
B. the amount of matter in an object
C. the distance traveled by and object over time
D. the motion of an object
Answer: the motion of an object
Explanation:
I just took the test
Answer:the motion of an object
Explanation:
I finished the sample work
Galaxies that are 400 million light years away have a red shift of 0.03 approximately. A radio wave coming from one of these galaxies has an observed wavelength of 125 meters. What is the emitted wavelength in meters and the observed frequency in Megahertz
Answer:
The correct answer is "121.36 meters and 2.40 MHz".
Explanation:
Given:
Red shift,
\(\frac{v}{c}=\frac{\lambda - \lambda_0}{\lambda_0} = 0.03\)
Wavelength,
\(\lambda = 125 \ meters\)
The observed frequency will be:
⇒ \(f = \frac{c}{\lambda}\)
\(=\frac{3\times 10^8}{125}\)
\(=24\times 10^5\)
\(= 2.40\times 10^6\)
\(=2.40 \ MHz\)
hence,
The Emitted wavelength will be:
⇒ \(\frac{125-\lambda_0}{\lambda_0} =0.03\)
\(\frac{125}{\lambda_0}-1 =0.03\)
\(125=1.03 \ \lambda_0\)
\(\lambda_0=\frac{125}{1.03}\)
\(=121.36 \ m\)
An environmentally conscious physics student 250 N
mows her lawn with a push mower, exerting
a force of 250 N along the handle as shown. 40°
How much force is actually being used to push
the mower along the grou
The force actually being used to push the mower along the ground is 191 N.
When the physics student exerts a force of 250 N along the handle of the push mower, it's important to consider the components of this force that contribute to the actual force used to push the mower along the ground.
To determine the force used to push the mower along the ground, we need to find the horizontal component of the applied force. The angle of 40° indicates that the applied force can be broken down into two components: the horizontal component and the vertical component. The vertical component of the force is perpendicular to the direction of motion and does not contribute to pushing the mower forward.
To find the horizontal component, we can use trigonometry. The horizontal component is given by the formula:
Horizontal component = Applied force * cos(angle)
Plugging in the values, we get:
Horizontal component = 250 N * cos(40°)
Calculating this value, we find that the horizontal component of the applied force is approximately 191 N.
Therefore, the force actually being used to push the mower along the ground is 191 N. This is the component of the applied force that contributes to the forward motion of the mower, while the remaining vertical component is directed perpendicular to the ground and does not assist in pushing the mower forward.
By exerting a force of 250 N along the handle at a 40° angle, the student effectively applies 191 N of force to push the mower along the ground, ensuring efficient use of their effort while considering the environmental impact.
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Engineers are working on a design for a cylindrical space habitation with a diameter of 7.50 km and length of 29.0 km. The habitation will simulate gravity by rotating along its axis. With what speed (in rad/s) should the habitation rotate so that the acceleration on its inner curved walls equals 8 times Earth's gravity
Answer:
The speed will be "0.144 rad/s".
Explanation:
Given that,
Diameter,
d = 7.50 km
Radius,
R = \(\frac{7.5}{2} \ Km\)
Acceleration on inner curve,
= 8 times
Now,
As we know,
⇒ \(\omega^2R=8g\)
or,
⇒ \(\omega=\sqrt{\frac{8g}{R} }\)
On substituting the values, we get
⇒ \(=\sqrt{\frac{8\times 9.8}{\frac{7.5}{2}\times 10^3 } }\)
⇒ \(=\sqrt{\frac{78.4}{3750} }\)
⇒ \(=\sqrt{0.0209}\)
⇒ \(=0.144 \ rad/s\)
A dielectric block such as shown in Fig. P5.1 is uniformly polarized. The polarization is P. Find the polarization charge density , on the faces 1, 2, and 3. (Find both magnitude and sign of the charge.) P Fig. P5.1
The vector field that expresses the density of induced or permanent electric dipole moments in a dielectric medium is known as polarization density (also known as electric polarization or just polarization).
Thus, A dielectric is considered to be polarized when its molecules acquire an electric dipole moment when exposed to an external electric field.
Electric polarization of the dielectric is the term used to describe the electric dipole moment induced per unit volume of the dielectric material.
The forces that emerge from these interactions can be calculated using the polarization density, which also defines how a material reacts to an applied electric field and how it modifies the electric field. It is comparable to magnetization, which measures a material's equivalent response.
Thus, The vector field that expresses the density of induced or permanent electric dipole moments in a dielectric medium is known as polarization density (also known as electric polarization or just polarization).
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The mass of Jupiter is 1.9 x 10 kg and that of the sun is 2 x 10 kg. If the distance between them is 78 x 10 km, find the gravitational force between them.
Using the formula F = G * (m1 * m2) / r^2, where G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them, we can calculate the gravitational force between Jupiter and the sun.
Plugging in the values, we get:
F = (6.674 x 10^-11 N * (m^2 / kg^2)) * ((1.9 x 10^27 kg) * (2 x 10^30 kg)) / (78 x 10^6 m)^2
Simplifying this, we get:
F = 1.98 x 10^27 N
Therefore, the gravitational force between Jupiter and the sun is approximately 1.98 x 10^27 Newtons.
The gravitational force between Jupiter and the sun, calculated using Newton's law of gravitation with their masses and distance, is \(1.95 * 10^{22} N.\)
The gravitational force between Jupiter and the sun is determined using Newton's law of gravitation, which states that two masses attract each other with a force that is directly proportional to the product of their masses and inversely proportional to the square of their distance apart. Given that the mass of Jupiter is \(1.9 * 10^{27} kg\) and that of the sun is \(2 * 10^{30} kg\), and the distance between them is \(78 * 10^6 km (which is 78 * 10^9 m)\), we can use the formula: Gravitational force = G(m1m2)/r^2where G is the universal gravitational constant, m1, and m2 are the masses of the two bodies, and r is the distance between them. Substituting the values gives Gravitational force \(= (6.67 * 10^{-11} Nm^2/kg^2) * (1.9 * 10^{27} kg) * (2 x 10^{30} kg) / (78 * 10^9 m)^2= 1.95 * 10^{22} N\)Thus, the gravitational force between Jupiter and the sun is \(1.95 * 10^{22} N.\)Summary: The gravitational force between Jupiter and the sun is found using Newton's law of gravitation, which is directly proportional to the product of their masses and inversely proportional to the square of their distance apart. Given the mass of Jupiter, the mass of the sun, and the distance between them, we can calculate the gravitational force using the formula. The gravitational force between Jupiter and the sun is \(1.95 * 10^{22} N.\)For more questions on gravitational force
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A 109 kg softball player slides across the ground and comes to a stop. Her average acceleration while she stops is -0.737. Calculate the magnitude of the stop force.
Answer:96.1
Explanation: