Jack is pushing a 30.0 kg cart at a constant acceleration of 2.1 m/s^2. He is combatting a force of 24N of gravity. If Jack let go of the cart when the velocity was 1.5 m/s, how far would the cart travel before stopping?

Answers

Answer 1

Answer:

The car will travel 1,41 m before stop.

Explanation:

F = m * a

- 24 N (loss) = 30 Kg * a

a = -24/30 = -0,8 m/s^2

Using the Torricelli equation:

V^2 = Vo^2 = 2*a*S

final velocity = 0 (when the car stops)

initial velocity = 1,5 m/s (when the driver stops the acceleration)

0^2 m/s = (1,5 m/s)^2 + (2 * -0,8 m/s^2 * S)

0 = 2,25 - 1,6S

S = -2,25/-1,6

S = 1,41 m


Related Questions

24. A body A rests on a smooth horizontal table. Two bodies of mass 2 kg and 10 kg hanging freely, are attached to A by strings which pass over smooth pulleys at the edges of the table. The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 . Find the mass of A.

Answers

The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.

Let the mass of the body A be ‘m’.

The two strings are taut so they exert a tension ‘T’ on body A.

Let ‘a’ be the acceleration produced in the system.

The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)

As the two strings are taut, we can say that tension in both strings is equal.

Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.

The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)

As per the given problem, the system is released from rest.

Hence the initial velocity is zero.

Also, we are given that the system accelerates at 2 m/s2.

Therefore a = 2 m/s2 …(2)

From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5

Thus, the mass of A is 8m/5 kg.

Answer: Mass of A = 8m/5 kg.

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Which kind of precipitation is formed, in part, by wind?

A. Rain
B. Snow
C. Sleet
D. Hail

Answers

Answer:

Rain

Explanation:

the answer would be A. rain

You have a source of energy containing 21 gj of energy at 600k how much this energy can be converted to work when rejecting heat to the atmosphere at 27°C?

Answers

Answer:

Available energy = 35 x 10⁶ J

Explanation:

Given:

Amount of energy (Q) = 21 gj = 21 x 10⁹ J

Temperature T1 = 600 k

Temperature T0 = 27 + 273 = 300k

Find:

Available energy

Computation:

Available energy = Q[1/T0 - 1/T1]

Available energy = 21 x 10⁹ J[1/300 - 1/600]

Available energy = 35 x 10⁶ J

Which energy transformation occurs when a butane lighter is lit?

Which energy transformation occurs when a butane lighter is lit?

Answers

It is electrical energy into connected energy has in relation to the question

When a butane lighter is lit, chemical energy transforms into heat energy.

What is law of conservation of energy?

Energy cannot be created or destroyed, says the law of conservation of energy. However, it has the ability to change its form. The total energy of an isolated system is constant when all sources of energy are taken into account.

The chemical energy is the bonds of chemical molecules contain energy. Exothermic reactions are those in which chemical energy is released during the reaction, frequently in the form of heat.

In butane energy is stored as a chemical energy as  bonds of chemical molecules and when it is lit, the chemical energy of the butane transforms into heat energy.

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A tabletop two-slit interference experiment consists of a laser pointer shining through two narrow, closely spaced slits in an opaque barrier. The light from the slits produces a characteristic pattern of alternating bright and dark regions on a nearby wall. Listed are five ways to modify the parameters of the experiment. Match each modification according to the effect it would have on the spacing between the bright spots on the wall. In each case, assume that everything else is held constant.

a. Causes the spacing between the bright spots on the wall to increase.
b. Causes the spacing between the bright spots on the wall to decrease.
c. Has effed on the spacing between the bright spots on the wall.

1. increasing the distance d between the two slits in the barrier
2. increasing the brightness of the laser light
3. increasing the distance L from the slits to the wall
4. increasing the distance x from the laser to the slits
5. increasing the wavelength of the laser light

Answers

Answer:

a - 3, 5

b - 1

c - 2, 4

Explanation:

a). The distance between fringes on the screen

        \($y = \frac{m \lambda L}{d}$\)

where, λ is wavelength, m is order of pattern, L is distance between slit and screen, d is separation between slits.

Now we analyze that spacing between bright spots increases as increasing distance L from slits to wall and increasing the wavelength of the laser light, λ.

b). The spacing between the bright spots decreases as the distance between the two slits increases.

c). Has no effect on the spacing between the bright spots on the wall by increasing the distance from the laser to the slits as well as increasing the brightness of the laser.

what is something that is useful to us like the sun and water​

Answers

Answer:

soil

Explanation:

without soil we can't plant we can't have water because water is from underground therefore soil is also useful

Answer:

Oxygen

Explanation:

Our body needs oxygen to obtain energy to fuel all our living processes

Which of the following is not among the uses of dimensional analysis? (a) determination of the Numerical constant (b) to convert one system of unit to another (c) to change the units of derived quantities (d) to test the correctness of an equation

Answers

To convert one system of unit to another  of derived quantities is not a use of dimensional analysis.

What is dimensional analysis?

Checking for consistency in the dimensions on both sides of an equation entails looking at the dimensions of the physical quantities involved in a problem, such as length, mass, time, electric charge, and temperature.

The core tenet of dimensional analysis is that physical quantities, such as length, mass, and time, may be described in terms of their basic dimensions.

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All of the options listed are included in the uses of dimensional analysis.

What is dimensional analysis?

Dimensional analysis is a powerful tool used in physics to:

check the correctness of equations derive new equationsconvert units from one system to anotherdetermine numerical constants that relate physical quantities.

The dimensional analysis involves analyzing the dimensions of physical quantities and using them to establish relationships between them.

By using the principles of dimensional analysis, we can simplify complex physical problems and gain insights into the behavior of physical systems.

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Give examples of motion in which the directions of the velocity and acceleration vectors are (a) opposite, (b) the same, and (c) mutually perpendicular​

Answers

Answer:

a) When moving body applies brake then velocity and acceleration would be in opposite direction

b) When body starts to increase velocity then velocity and acceleration would be in same direction

c) When body is circulating then velocity and acceleration would be perpendicular to each other

Explanation:

a) When body applies brake then its velocity starts decreasing, in this case its acceleration would try to stop the moving body. So direction of velocity would be same as direction of motion of body but direction of acceleration would be in opposite direction

b) When body starts to increase velocity, its acceleration would make the body to move faster. So direction of velocity would be the direction of motion of body and acceleration would also be in same direction

c) When body moves in circular path then its acceleration would be towards centre of circle and velocity would try to snap the body out of circle to straight line which in tangent to circle.

Give examples of motion in which the directions of the velocity and acceleration vectors are (a) opposite,

a box of mass 8.0 kg rests on a horizontal rough surface. a string attached to the box passes over a smooth pulley and supports a 2.0 kg mass at its other end, when the box is released, a frictional force of 6.0 n acts on it. (a) draw free-body diagrams of the 8.0 kg box and the 2.0 kg mass. (b) determine the (i) acceleration of the system, (in) tension in the string.

a box of mass 8.0 kg rests on a horizontal rough surface. a string attached to the box passes over a

Answers

a. The free-body diagrams of the 8.0 kg box and the 2.0 kg mass is attached below.

bi) the acceleration of the system is 0.4 m/s^2

bii)  the tension in the string is 0.8 N.

How do we calculate?

Net force = ma

Net force = T - F_friction

where T is the tension force and F_friction is the frictional force.

Substituting the given values, we have:

T - F_friction = ma

T - 6.0 N = (8.0 kg + 2.0 kg) a (since the tension force acts on both masses)

T - 6.0 N = 10.0 kg a

(ii) To find the tension in the string, we can apply Newton's second law of motion to the 2.0 kg mass:

Net force = ma

where m is the mass of the mass and a is the acceleration of the system. The net force on the mass is the tension force:

Net force = T

Substituting the given values, we get:

T = ma

T = 2.0 kg x a

To solve for T, we need to find the acceleration of the system.

To find both a and T, we can use the equations we derived above and solve them simultaneously:

T - 6.0 N = 10.0 kg a (equation 1)

T = 2.0 kg x a (equation 2)

Substituting equation 2 into equation 1, we get:

2.0 kg x a - 6.0 N = 10.0 kg a

Solving for a, we get:

a = 0.4 m/s^2

Substituting a into equation 2, we get:

T = 2.0 kg x 0.4 m/s^2 = 0.8 N

Therefore, the acceleration of the system is 0.4 m/s^2 and the tension in the string is 0.8 N. of the system is 0.4 m/s^2 and the tension in the string is 0.8 N.

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A 752mL sample of water was placed in a 1.00kg aluminum pan. The initial temperature of the pan was 26°C and the final temperature of the system was 39°C. What was the initial temperature of the water? The specific heat of aluminum is 0.9025 J/g°C.

Answers

Answer:

35.24°C.

Explanation:

To solve this problem, we can use the principle of conservation of energy. The heat lost by the water will be equal to the heat gained by the aluminum pan.

The equation for heat transfer is:

Q = m * c * ΔT

Where:

Q is the heat transferred

m is the mass of the substance

c is the specific heat capacity of the substance

ΔT is the change in temperature

Let's calculate the heat lost by the water:

Q_water = m_water * c_water * ΔT_water

We know the mass of the water is 752 mL, which is equivalent to 752 grams (since the density of water is 1 g/mL).

m_water = 752 g

c_water = 4.18 J/g°C (specific heat of water)

ΔT_water = final temperature - initial temperature = 39°C - initial temperature

Similarly, let's calculate the heat gained by the aluminum pan:

Q_aluminum = m_aluminum * c_aluminum * ΔT_aluminum

The mass of the aluminum pan is given as 1.00 kg.

m_aluminum = 1,000 g

c_aluminum = 0.9025 J/g°C (specific heat of aluminum)

ΔT_aluminum = final temperature - initial temperature = 39°C - 26°C

Since the heat lost by the water is equal to the heat gained by the aluminum pan, we can set up the equation:

Q_water = Q_aluminum

m_water * c_water * ΔT_water = m_aluminum * c_aluminum * ΔT_aluminum

Plugging in the values:

752 g * 4.18 J/g°C * (39°C - initial temperature) = 1,000 g * 0.9025 J/g°C * (39°C - 26°C)

Simplifying:

3135.776 g * (39°C - initial temperature) = 903.5 g * 13°C

122,287.664 g°C - 3135.776 g * initial temperature = 11,705.5 g°C

-3135.776 g * initial temperature = 11,705.5 g°C - 122,287.664 g°C

-3135.776 g * initial temperature = -110,582.164 g°C

Dividing by -3135.776 g:

initial temperature = (-110,582.164 g°C) / (-3135.776 g)

initial temperature ≈ 35.24°C

Therefore, the initial temperature of the water was approximately 35.24°C.

Hope this helps ^^

During the 28-day lunar cycle, the positions of the Sun,
Earth, and the Moon change in relation to one another. The
diagram shows how their relative positions change.

Which statement describes the positions of the Moon, the Sun, and Earth
during a new moon?

A. Earth is closer to the Sun than to the Moon.

B. The Moon is between Earth and the Sun.

C. Earth is between the Moon and the Sun.

D. The Sun is between Earth and the Moon.

During the 28-day lunar cycle, the positions of the Sun,Earth, and the Moon change in relation to one

Answers

Answer: B

Explanation: B is the correct statement describing the positions of the Moon, the Sun, and the Earth during a new moon. The Moon is between Earth and the Sun.

During a new moon, the Moon is positioned between the Sun and the Earth, with the illuminated side of the Moon facing away from the Earth. This means that the side of the Moon that faces the Earth is not receiving any sunlight, making it invisible to us from Earth. The new moon is the first phase of the lunar cycle and occurs roughly every 29.5 days.

If California experienced heavy rainfall, which system would be responsible for it and WHY?

Answers

Answer:

California has one of the most variable climates of any U.S state, and often experiences very wet years followed by extremely dry ones . The state's reservoirs have insufficient capacity to balance the water supply between wet and dry years.

PLEASE MARK ME AS BRAINLIEST

Given the displacement vector
D = (5î − 8ĵ) m,
find the displacement vector (in m)
R
so that
D + R = −7Dĵ.
(Express your answer in vector form.)

Answers

wow this is rlly hard Idrk but good luck

Essential Questions: What does the particle theory tell us about the nature of matter? How does
each state of matter behave?

Answers

sowwie :( i need points

Explanation:

Lia lives in the mountains of Colorado. Her aunt came to visit and had a difficulty breathing for a few days until she adjusted to the higher altitude. Which explanation best describes the reason for this difficulty

Answers

There is decreased pressure on the air molecules as one moves higher and the air is thinner

What happens at high altitude?

We know that the air pressure decreases with height. This implies that the air is thinner as you move up to higher altitude. This is the idea behind the use of the phrase; "Thin air".

Now, owing to the fact that there is decreased pressure on the air molecules as one moves higher and the air is thinner, it is much harder to breath until her aunt adjusts to the higher altitude.

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Can someone please explain why the answer to this net torque question is +115 Nm

Can someone please explain why the answer to this net torque question is +115 Nm

Answers

Answer:

Net torque in positive direction:

Fz = -450 * cos 30 deg * 1.5 = -585 N-M

Fz = 200 * 3.5 = 700 N-M

Net F = 115 N-M

Torque is generally defined as L = R X F

X cross Y = Z     normal coordinate system

Note that Z will be out of the page giving the positive value for the torque.

Calculate the displacement in meters of a motorcycle that has a speed of 100 kilometers per hour if it has circulated for 50 minutes​

Answers

Hello..!

To calculate its displacement, we first apply the data to the problem.

Data:

V = 100km/hT = 50minD = ?

Now, we apply a conversion.

Conversion:

100km/h • (1000m/1km) • (1h/3600s) V = 27.7m/s50min • (60s / 1min) T = 3000s

Then, we apply the formula that is.

Formula:

D = V • T

Finally we develop the problem.

Developing:

D = (27.7m/s) • (3000s)D = 83100m

The displacement of the bike is 83100 meters.

Answer:

83,333.33 m (2 d.p.)

Explanation:

\(\boxed{\sf Speed=\dfrac{Distance}{Time}}\)

Given values:

Speed = 100 k/hTime = 50 minutes

As there are 60 minutes in one hour, convert minutes into hours by dividing by 60:

\(\implies \sf Time=\dfrac{50}{60}=\dfrac{5}{6}\;hour\)

Substitute the values into the formula and solve for distance:

\(\implies \sf 100=\dfrac{Distance}{\frac{5}{6}}\)

\(\implies \sf 100=Distance \times \dfrac{6}{5}\)

\(\implies \sf Distance=\dfrac{100 \times 5}{6}\)

\(\implies \sf Distance=\dfrac{250}{3}\;km\)

\(\implies \sf Distance=83.33333...\;km\)

At there are 1000 meters in one kilometer, convert kilometers into meters by multiplying by 1000:

\(\implies \sf Distance=83.33333...\times 1000=83333.33\;m\;(2\;d.p.)\)

20 points - Help me please with explanation of (A) and (B)​

20 points - Help me please with explanation of (A) and (B)

Answers

(a)to find voltage of battery we use the wire containg 4 ohm resistor and 3 ohm resistor

the voltage of 4ohm = Ri=4x1.5=6V

the voltage of 3 ohm = Ri=3x1.5=4.5v

since voltage is additive in series then Voltage of batteries = 4.5+6=10.5V

(b) the currrent flowing in 20 ohm resistor is the same as 8 ohm resistor so

Voltage of 8 ohm + voltage of 20 ohm= 10.5

8i+20i=10.5

28i=10.5

i=0.375 A

Important parts of stydi g physics

Answers

Answer:

put your question in proper way' i hope you understand.

Explanation:

if kinetic energy of a body is decreased by 10percent then decrease in linear momentum of that body​

Answers

Answer:

E = 1/2 M V^2 = 1/2 P V     since P = M V

E2 / E1 = P2 V2 / (P1 V1)

P2 / P1 = E2 V1 / (E1 V2) = V2^2 V1 / (V1^2 V2) = V2 / V1

E2 / E1 = V2^2 / V1^2

V2 / V1 = (E2 / E1)^1/2

V2 / V1 = (.9)1/2 = .95

The linear momentum would have to decrease by 5%


Which two substances are elements?

A. sand and air B. salt and sand
C. iron and helium
D. helium and water

Answers

C, iron and helium are elements since they consist of only one type of atoms

is the energy present when an object is in motion?​

Answers

Answer:

Kinetic energy is present in an object which is in motion.

Explanation:

muscular strength and muscular endurance are measured by the same test true or false

Answers

Answer:

False

Explanation:

The Earth orbits the Sun at a speed of 30 km/s. At that speed it completes one path around the Sun every year. Of course, as that happens we are heading toward a different place in space constantly, always accelerating toward the Sun to stay on the circular path. Suppose at a paritcular instant we are headed in the direction of a distant star and we measure the speed of the light from that star as it arrives on Earth. In the vacuum of space we would measurea. 299,792,458 m/sb. 299,792,428 m/sc. 299,792,488 m/sd. 0 m/s

Answers

Answer:

a. 299,792,458 m/s

Explanation:

Since the speed of light in a vacuum is invariant and has the value of 299,792,458 m/s, we would measure this value of 299,792,458 m/s for the speed of light from the star as it arrives on Earth.

7. Apply Concepts: suppose the dog walked at a constant speed the whole way. What
would the graph look like then? Explain.

Answers

If the dog walked at a constant speed the whole way, the graph of the dog's position versus time would be a straight line. This is because the dog's velocity (which is the derivative of position with respect to time) would be constant, and the acceleration (which is the derivative of velocity with respect to time) would be zero.

What is the speed about?

A straight line on a position-time graph indicates that the object is moving at a constant velocity. The slope of the line would be equal to the velocity of the dog.

If the graph is a horizontal line, it would indicate that the dog is at rest. If the line slopes upward, the dog is moving in the positive direction (for example, to the right in a position-time graph), and if the line slopes downward, the dog is moving in the negative direction.

In all, A constant speed means a constant velocity and the line is a straight line with a particular slope.

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7. Apply Concepts: suppose the dog walked at a constant speed the whole way. Whatwould the graph look

Brainlist!! Help!! Atom A consists of 10 protons, 12 neutrons, and 10 electrons.

Atom B consists of 10 protons, 10 neutrons, and 12 electrons.


The atoms are isotopes of each other.

The atoms are not isotopes of each other.

Answers

Atom A has 10 protons, 12 neutrons, and 10 electrons, while Atom B has 10 protons, 10 neutrons, and 12 electrons.

Atom A and Atom B are not isotopes of each other. Isotopes are atoms of the same element that differ in the number of neutrons but have the same number of protons. In this case, Atom A and Atom B have different numbers of protons, which means they are not isotopes of each other.

The number of protons determines the element, and since Atom A and Atom B have different numbers of protons, they belong to different elements.

Isotopes, on the other hand, have the same number of protons but differ in the number of neutrons.

This variation in the number of neutrons gives isotopes different atomic masses while retaining the same chemical properties.

However, Atom A and Atom B do not fulfill this criterion, so they cannot be considered isotopes of each other.

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2. A 7 kg. Mass is moved across the table at 25 m/sec. What force caused the acceleration?

Answers

A 7 kg mass moving across the table at an acceleration of 25 m\(/s^2\)requires a force of 175 N.

To determine the force required to cause the acceleration of a 7 kg mass moving across the table at 25\(m/s^2\), we can use Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration.

Given:

Mass (m) = 7 kg

Acceleration (a) = 25 \(m/s^2\)

We can substitute these values into the equation:

Force (F) = mass (m) * acceleration (a)

F = 7 kg * 25 \(m/s^2\)

F = 175 kg·\(m/s^2\)

Therefore, the force required to cause the acceleration of the 7 kg mass is 175 kg·\(m/s^2\).

To understand the calculation, we need to know that force is a measure of how much an object accelerates when a certain amount of mass is acted upon by that force. In this case, the mass of the object is 7 kg, and it is experiencing an acceleration of 25\(m/s^2\).

By multiplying the mass and acceleration together, we find that the force required is 175 kg·\(m/s^2\). This unit, also known as a Newton (N), represents the force required to accelerate a 1 kg mass at a rate of 1 \(m/s^2\)

In summary, the force required to cause the acceleration of the 7 kg mass across the table at 25 \(m/s^2\) is determined to be 175 kg·\(m/s^2\). This calculation follows Newton's second law of motion and shows the relationship between mass, acceleration, and force.

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13. What is the acceleration of a 1,000-kilogram truck with a net force of 7,000 newtons?

Answers

Answer:

7 m/s²

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{f}{m} \\ \)

f is the force

m is the mass

From the question we have

\(a = \frac{7000}{1000} = 7 \\ \)

We have the final answer as

7 m/s²

Hope this helps you

A ball has a velocity of 11 m/s and a momentum of 47 kgm/s, what is its mass? Show
your given, required, and solutions.

Answers

Explanation:

p=m x v

to find the mass:

m= p/v

=47/11

=4.27 kg

Which statement is true about the theory of plate tectonics and the theory of continental drift?

A) The theory of plate tectonics proves the theory of continental drift completely wrong.

B) The theory of plate tectonics tells exactly where the continents were before Pangaea divided.

C) The theory of plate tectonics gives the method by which continents can move as part of plates.

D) The theory of plate tectonics does not explain how continental movements could occur.

Answers

The statement that is true about the theory of plate tectonics and the theory of continental drift C. The theory of plate tectonics gives the method by which continents can move as part of plates .

What is theory of plate tectonics and the theory of continental drift ?

According to the scientific hypothesis of plate tectonics, the underground movements of the Earth create the primary landforms. By explaining a wide range of phenomena, including as mountain-building events, volcanoes, and earthquakes, the theory, which became firmly established in the 1960s, revolutionized the earth sciences.

The scientist Alfred Wegener is most closely connected with the concept of continental drift. Wegener wrote a paper outlining his notion that the continents were "drifting" across the Earth, occasionally crashing through oceans and into one another, in the early 20th century.

According to tectonic theory, the Earth's surface is dynamic and can move up to 1-2 inches every year. The numerous tectonic plates constantly move and interact. The outer layer of the Earth is altered by this motion. The result is earthquakes, volcanoes, and mountains.

Therefore, option C is correct.

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