Jose conducted an experiment to measure the rate of minerals dissolving in water and changed the temperature of the water for each trial.
What is the independent variable in this experiment?
A: number of trials being tested
B: temperature of the water
C: type of minerals used for each trial
D: rate the minerals dissolved
Answers
Answer: B. Temperature of water
Explanation:
An independent variable is "the variable that is changed or controlled in a scientific experiment or a mathematical or statistical model" and "It is the variable that the researcher chooses and that may affect the dependent variable"
The Temperature of the water is only affected by Jose thus it is a independent variable
Related Questions
A battery management systems primary purpose is to ___.
Answers
A battery management systems primary purpose is to protect the cells from being operated in unsafe conditions.
The BMS's main objective is to safeguard the cells from hazardous operating situations. The BMS can also be used to monitor any battery irregularities and report status (such as battery life) to the user and/or powered (host) device. A battery pack, which is an assembly of battery cells electrically organized in a row by column matrix configuration, is under the control of a battery management system (BMS).
BMS is a piece of technology designed to deliver a targeted range of voltage and current for a period of time against anticipated load scenarios. With the maximum energy density, lithium-ion rechargeable cells are the appropriate option for battery packs in a wide range of consumer goods, from laptops to electric automobiles.
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a photo taken by an american spy plane pilot at 60,000 feet was just released. what does it show?
Answers
Historically, photographs taken by American spy planes at high altitudes have been used for various purposes such as reconnaissance and intelligence gathering.
Depending on the specific photograph in question, it could potentially show a wide range of information such as military installations, troop movements, or other sensitive information. The altitudes at which a photo is taken can affect the level of detail that can be seen in the image. However, it is important to note that the use of such technology can also raise privacy and security concerns, particularly if it is used to gather information on individuals or groups without their consent or knowledge.
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In a heat engine, 2.00 mol of a monoatomic gas are carried through the cycle ABCDA. The segment AB represents an isothermal expansion, the segment BC is an adiabatic expansion, the segment CD is an isobaric compression, and DA is a constant volume process. The pressure and temperature at A are 5.00 atm and 600 K. The volume at B is twice the volume at A. The pressure at D is 1.00 atm.
a) What is the pressure at B?
b) What is the temperature at C?
c) Find the total work done by the gas in one cycle.
Answers
(a)The pressure at B is 0.1248 atm.
(b)The temperature at C is 727.1 K.
(c)The total work done by the gas in one cycle is -1979J
General calculation:
We can use the First Law of Thermodynamics to analyze the heat engine cycle:
ΔU = Q - W
where ΔU is the change in internal energy, Q is the heat added to the system, and W is the work done by the system. For a complete cycle, ΔU = 0, so:
Q = W
We can also use the ideal gas law to relate the pressure, volume, and temperature of the gas:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the absolute temperature.
(a)How to find the pressure at B segment?
To find the pressure at B, we can use the fact that the segment AB is an isothermal expansion. This means that the temperature remains constant, so:
PV = nRT
PB = (nRT)/(2V) = (2.00 mol)(0.0821 L·atm/mol·K)(600 K)/(2V) = (0.0821 L·atm/mol)(600 K)/V
Since the pressure at A is 5.00 atm, we can use the fact that the temperature is constant to find the volume at A:
PV = nRT
VA = (nRT)/P = (2.00 mol)(0.0821 L·atm/mol·K)(600 K)/5.00 atm = 197.76 L
Since the volume at B is twice the volume at A, we have:
VB = 2VA = 395.52 L
Substituting into the expression for PB, we get:
PB = (0.0821 L·atm/mol)(600 K)/395.52 L = 0.1248 atm
Therefore, the pressure at B is 0.1248 atm.
(b) How to find the temperature at segment C?To find the temperature at C, we can use the fact that the segment BC is an adiabatic expansion. This means that no heat is added or removed from the system, so:
\(PV^\gamma\)= constant
where γ is the ratio of specific heats (for a monoatomic gas, γ = 5/3). We can use the fact that the volume at C is equal to the volume at A to find the pressure at C:
\(PAV^\gamma = PCV^\gamma\)
PC = \(PA(V/A)^\gamma\) = 5.00 atm\((1/2)^(^5^/^3^)\) = 1.556 atm
Since the segment BC is adiabatic, the temperature changes but no heat is added or removed from the system. Using the ideal gas law, we can relate the pressure, volume, and temperature:
PV = nRT
TC = (PCVC)/(nR) = (1.556 atm)(197.76 L)/(2.00 mol)(0.0821 L·atm/mol·K) = 727.1 K
Therefore, the temperature at C is 727.1 K.
(c) How to find the total work done by the gas in one cycle?The total work done by the gas in one cycle is the sum of the work done in each segment of the cycle:
W = WAB + WBC + WCD + WDA
For segment AB, the work done is:
WAB = -QAB = -∫PdV = -nRT∫(1/V)dV = -nRT ln(VB/VA) = -(2.00 mol)(0.0821 L·atm/mol·K)(600 K) ln(2) = -602 J
For segment BC, the work done is:
WBC = -QBC = -∫PdV = -nγRT∫(1/V)dV = -nγRT
We know that VB = 2VA and VC = 2VD, so we can express the ratio VB/VC in terms of VA/VD:
VB/VC = (2VA)/(2VD) = VA/VD
Substituting into the expression for WBC, we get:
WBC = -nγRT ln(VA/VD)
For segment CD, the work done is:
WCD = -QCD + PCDΔV = -nCpΔT + PCDΔV
where Cp is the specific heat at constant pressure, ΔT is the change in temperature, and ΔV is the change in volume. We know that the segment CD is isobaric, so ΔV = VB - VA = (2VA) - VA = VA. We can also use the ideal gas law to relate the pressure, volume, and temperature:
PV = nRTPC = (nRT)/VDSubstituting into the expression for WCD, we get:
WCD = -nCpΔT + (nRT/VD)VA = -nCp(TC - TD) + (nRT/VD)VA
For segment DA, the work done is:
WDA = -QDA + ΔU = -nCvΔT
where Cv is the specific heat at constant volume. We know that the segment DA is isovolumetric, so ΔV = 0. Using the First Law of Thermodynamics, we know that ΔU = 0 for a complete cycle, so:
QDA = -WDA = nCvΔT
Substituting into the expression for WDA, we get:
WDA = -nCvΔT
Adding up the work done in each segment, we get:
W = WAB + WBC + WCD + WDA
= -(2.00 mol)(0.0821 L·atm/mol·K)(600 K) ln(2)- (2.00 mol)(5/3)(0.0821 L·atm/mol·K)(727.1 K) ln(VA/VD)- (2.00 mol)(Cp)(TC - TD) + (2.00 mol)(0.0821 L·atm/mol·K)(600 K) ln(2)- (2.00 mol)(Cv)(TC - TA)
We know that Cp and Cv for a monoatomic gas are related by Cp = Cv + R, so we can express Cp in terms of Cv:
Cp = Cv + R = (3/2)R + R = (5/2)R
Substituting and simplifying, we get:
W = (2.00 mol)(0.0821 L·atm/mol·K)(600 K) ln(2)- (2.00 mol)(5/3)(0.0821 L·atm/mol·K)(727.1 K) ln(VA/VD)- (2.00 mol)(5/2)(0.0821 L·atm/mol·K)(727.1 K)+ (2.00 mol)(5/2)(0.0821 L·atm/mol·K)(600 K)
W = -966.2 J - 4957 J - 7476 J + 5154 J
= -1979 J
Therefore, the total work done by the gas in one cycle is -1979 J
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An old version of stellar evolution, popular at the beginning of the twentieth century, maintained that stars begin their lives as large, cool spheres of gas, like the giant stars on the H-R diagram. They then contract and heat up under the pull of their own gravity to become hot, bright blue O stars. For the remainder of their lives they lose energy, becoming dimmer and redder with age. As they slowly move down the main sequence, they eventually end up as cool, dim red M stars. Explain how observations of stellar clusters, plotted on the H-R diagram, contradict this idea.
Answers
Every star goes through distinct evolutionary stages that are determined by its internal structure and method of energy production depending on its initial mass. The temperature and luminosity of the star change with each of these stages, and as the star develops, it can be seen moving to various locations on the HR diagram.
One of the most crucial tools for studying stellar evolution is the HR diagram, also known as the Hertzsprung-Russell diagram (HR diagram). It was independently created by Ejnar Hertzsprung and Henry Norris Russell in the early 1900s and plots either the colour of stars (or spectral type) against their absolute magnitude or the temperature of stars against their luminosity.
The HR diagram is dominated by the main sequence, which extends from the upper left (hot, luminous stars) to the bottom right (cool, faint stars). In their cores, stars spend about 90% of their lives converting hydrogen to helium.
In the area above the main sequence, red giant and supergiant stars of luminosity classes I through III can be found. The Stefan-Boltzmann law states that because of their low surface temperatures and high luminosities, they also have large radii. Once a star's core has run out of hydrogen fuel and has begun to burn helium and other heavier elements, it enters this stage of evolution.
Low-mass stars reach their final evolutionary stage as white dwarf stars (luminosity class D).
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what is the volume (in cubic inches) of 3.4 lb of titanium?
Answers
The volume of 3.4 lb of titanium is approximately 20.84 cubic inches.
To determine the volume of 3.4 lb of titanium, we need to know the density of titanium. The density of a substance is defined as its mass per unit volume.
The density of titanium varies depending on its grade and specific form, but a commonly used value is around 4.51 grams per cubic centimeter (g/cm³) or 0.163 lb per cubic inch (lb/in³).
To find the volume, we can use the equation:
Volume = Mass / Density.
Converting the mass of titanium to grams:
3.4 lb * (453.59 g / 1 lb) = 1542.1066 g.
Now, we can calculate the volume:
Volume = 1542.1066 g / 4.51 g/cm³ ≈ 341.53 cm³.
To convert the volume to cubic inches:
Volume ≈ 341.53 cm³ * (0.06102 in³ / 1 cm³) ≈ 20.84 in³.
Therefore, the volume of 3.4 lb of titanium is approximately 20.84 cubic inches.
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a roller coaster moves 85 m horizontally, then travels 45 m at an angel of 30 above the horizontal. what is its displacement from its starting point? use graphical techniques.
Answers
Explanation:
done with the meeting today so I m ready for bed k tai you
Answer:
Explanation:
Dx = 85 + 45·cos 30° = 85 + 45·(√3 / 2) ≈ 124 m
Dy = 45·sin 30° = 45·(1/2) = 22.5 m
D = √ (Dx² + Dy²) = √ (124² + 22.5²) ≈ 126 m
Name at least four factors involved in performing a good throw.
Answers
Answer:
You need to have a good stance, release, power, speed, body, movement, and aim. You should be able to throw an effective pass or throw by using your body and having the correct amount of balance and form
CALCULATE ELECTRIC POTENTIAL
URGENT PLEASE HELP ASAP
Answers
Given two charges, \(q_2 =2 \times 10^{-6} \ C\) and \(q_3 =-2 \times 10^{-6} \ C\) we are asked to calculate the the Electrical Potential at a point, "P."
The distance from point "P" to charge 2 is \(r_{p2}=0.12 \ m\)
The distance from point "P" to charge 3 is \(r_{p3}=0.05 \ m\)
What is Electric Potential?
Electric potential is a measure of an electric fields ability to alter/change the potential energy of a charge.
Electric potential can be solved in various ways, in this case we are talking about point charges. So we can calculate the electric potential at point "P" using the following equation,
\(\boxed{V=\frac{k_eq}{r}}\)
Where,
=>\(k_e=8.99 \times 10^9 \ \frac{Nm^2}{C^2}\) which is Coulomb's constant
=> q is the charge (in Coulombs)
=> r is the distance (in meters) from the charge to point you want to know the electric potential at.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
\(V_{tot}=V_2+V_3 \Longrightarrow V_{tot}=\frac{k_eq_2}{r_{p2}}+\frac{k_eq_{3}}{r_{p3}}\)
\(\Longrightarrow V_{tot}=\frac{(8.99 \times 10^9 \ \frac{Nm^2}{C^2})(2 \times 10^{-6} \ C)}{0.12 \ m}+\frac{(8.99 \times 10^9 \ \frac{Nm^2}{C^2})(-2 \times 10^{-6} \ C)}{0.05 \ m}\)
\(\Longrightarrow V_{tot}=149833 \ V-359600 \ V\)
\(\Longrightarrow \boxed{V_{tot}=-209767 \ V} \therefore Sol.\)
The electric field potential at the point P is -3.6 * 10^5 V
What is the electric field potential?Electric potential, sometimes referred to as electric potential energy per unit charge, is a scalar quantity that calculates how much effort is required to transfer a test charge from one location in an electric field to another. Volts (V) are used to quantify it, which are the same as joules per coulomb (J/C).
We know that the electric field potential can be obtained as;
V = kq/r
V = 9 * 10^9 * -2 * 10^-6/0.05
V = -3.6 * 10^5 V
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if 56 j of work energy is required to lift a dumbbell to a height of 7m, what is the weight of the dumbbell?
Answers
Answer:
8 N
Explanation:
work=force*distance
force=work/distance
=56/7
=8
Can someone please explain
1) Centripetal force with example
2) Centrifugal force with example
3) Circular motion with example
Answers
Explanation:
centripetal force is a force that makes a body follow a curved path. for example, twirling,a lasso, cream seperator etc.
A force that causes an objectmoving in a circular path to move out and away from the centres of it's path is centrifugal force. for example,drifting, banked roads, washing machine etc.
Circular motion is a movement of an object along the circumference of a circle or rotation along a circular path. for example, stirring batter, stone tied to a string etc
hope its helpfull♡
What would it take to get the stone slab to move? Propose an
idea and explain how it would work in the context of Newton's
laws.
Answers
In order to get a stone slab to move, one would have to apply force to it. This can be done in a number of ways, depending on the situation. Here are a few possible laws that could be proposed for moving a stone slab:1. Newton's first law of motion: This law states that an object at rest will stay at rest unless acted upon by an external force. Therefore, to move a stone slab, one would need to apply a force to it.
This could be done by pushing it, pulling it, or applying a force from a lever or other mechanical device. Newton's second law of motion: This law states that the force required to accelerate an object is directly proportional to its mass. Therefore, to move a stone slab, a greater force would be required if it is more massive. This could be accomplished by using more people to push or pull the slab, or by using a larger lever or other mechanical device.. Friction: Friction is the force that opposes motion between two surfaces that are in contact with each other. In order to move a stone slab, one would need to overcome the friction between it and the surface it is resting on. This could be accomplished by reducing the friction (for example, by using rollers or lubricant), or by applying a greater force to overcome the friction.Work: Work is defined as the product of force and distance. Therefore, in order to move a stone slab, one would need to apply a force over a certain distance.This could be accomplished by pushing or pulling the slab over a distance, or by using a lever or other mechanical device to apply force over a greater distance.These are just a few possible laws that could be proposed for moving a stone slab. Ultimately, the best approach will depend on the specific situation and the resources available.For such more question on Newton's second law
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Silver has a mass of 10.5 grams and a volume of 19.3 cm3. What is its density?
Answers
Answer:
The answer is 0.54 g/cm³Explanation:
The density of a substance can be found by using the formula
\(density = \frac{mass}{volume} \\ \)
From the question we have
\(density = \frac{10.5}{19.3} \\ = 0.54404145...\)
We have the final answer as
0.54 g/cm³Hope this helps you
A hydraulic lift is used to lift a car that weighs 1400 kg. The foot pedal is attached to a piston that has an area of 50 cm2. This is attached to a lift with a large piston with an area of 4400 cm2.a. What force needs to be applied to the small piston in order to lift the car?b. How far will the smaller piston need to be pushed in order to raise the car by 2 meters?
Answers
The smaller piston needs to be pushed approximately 176 meters to
raise the car by 2 meters
a. To determine the force needed to lift the car using the hydraulic lift,
we can use Pascal's law, which states that the pressure in a fluid is
transmitted equally in all directions.
The formula for calculating the force exerted by the hydraulic lift is:
Force = Pressure * Area
Given:
Area of the small piston (A₁) = 50 cm²
Area of the large piston (A₂) = 4400 cm²
Weight of the car (W) = 1400 kg (weight is equivalent to mass multiplied
by acceleration due to gravity, which is approximately 9.8 m/s²)
First, we need to find the pressure exerted by the small piston:
Pressure₁ = Force₁ / Area₁
Since the pressure is transmitted equally, we can equate the pressure in
the small piston to the pressure in the large piston:
Pressure₁ = Pressure₂
Force₁ / Area₁ = Force₂ / Area₂
Substituting the given values:
Force₁ / 50 cm² = W / 4400 cm²
Solving for Force₁:
Force₁ = (W / 4400 cm²) * 50 cm²
Converting cm² to m²:
Force₁ = (W / 4400) * 0.005 m²
Substituting the weight of the car:
Force₁ = (1400 kg / 4400) * 0.005 m²
Calculating the force:
Force₁ = 2.84 kN (rounded to two decimal places)
Approximately 2.84 kilonewtons of force needs to be applied to the
small piston to lift the car.
b. To determine how far the smaller piston needs to be pushed to raise
the car by 2 meters, we can use the concept of equal pressure in the
hydraulic system.
The ratio of the distances moved by the small piston (d₁) and the large
piston (d₂) is equal to the ratio of their respective areas:
d₁ / d₂ = A₂ / A₁
Substituting the given values:
d₁ / d₂ = 4400 cm² / 50 cm²
Simplifying:
d₁ / d₂ = 88
We know that d₂ is 2 meters. We can substitute this value and solve for d₁:
d₁ / 2 m = 88
d₁ = 88 * 2 m
d₁ = 176 m
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which statements accurately describe mechanical waves
Answers
Answer:
Explanation:
so a mechanical wave transfers energy through a medium but unlike other waves that move through very long distances
the distance of the mechanical wave is different
What is the frequency of a wave if the wavelength is 567 m and the velocity is 23,000 m/s?
Answers
Answer:
40.56Hertz
Explanation:
v=f×lamda( I don't have the symbol)
from the question,
v=23,000
f=?
lamda i.e wavelength=567m
therefore, 23000=f×567
divide by 567
23000/567=567f/567
40.56 Hz=f
so, f=40.56Hz
What method is used to find the number of neutrons in an atom?
a
rounded atomic mass - atomic number = number of neutrons
b
atomic number - rounded atomic mass = number of neutrons
c
atomic number - electron number = number of neutrons
d
electron number - atomic number = number of neutrons
Answers
Answer:
B
Explanation:
a projectile is launched diagonally into the air and has a hang time of 24.5 seconds. approximately how much time is required for the projectile to reach its apex?
Answers
The time required for the projectile to reach its apex is 3.13 seconds (to two decimal places). When a projectile is launched diagonally into the air and has a hang time of 24.5 seconds, the time required for the projectile to reach its apex is a function of its vertical velocity (or initial vertical velocity, to be precise) at launch.
The projectile motion equation is h = vit + ½at², where: h is the maximum height of the projectile vit is the initial vertical velocity at launch a is the acceleration due to gravity, and t is the time of hang time.
At the apex of the projectile, the vertical velocity becomes 0 m/s, then the maximum height is given by:
h = vit + ½at²
= 0 + ½at²
= ½ gt²,
where g = 9.8 m/s² is the acceleration due to gravity in free fall.
Substituting given values, 24.5 seconds, we have:
24.5 = ½ gt²t²
= 24.5(2)/g
= 49/9.8t
= √(49/9.8)
= 3.13 s
Therefore, the time required for the projectile to reach its apex is 3.13 seconds (to two decimal places).
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An arch carries the thrust of weight to its _____(1)______. With a _____(2)______, the horizontal part of the structure supports all the weight above it. A. (1) center; (2) post-and-bearing b. (1) base; (2) springing line c. (1) keystone; (2) groin vault d. (1) sides; (2) post-and-lintel Please select the best answer from the choices provided A B C D.
Answers
Option D is correct. An arch carries the thrust of weight to its sides with a post-and-lintel.
What is an arch?
An arch is indeed a vertical curving construction that covers an elevated space that may or may not sustain the load above it or the pressure gradient against it
In the case of a horizontally arched, such as an embankment dam. While arches and vaults are often confused, A vault is defined as an ongoing arch forming a roof.
Option D satisfies the fill-in blanks option.
Hence option D is correct. An arch carries the thrust of weight to its sides with a post-and-lintel.
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the local convection heat transfer coefficient for uniform flow perpendicular to a heated ciruclar disk can is determined
Answers
The local convection heat transfer coefficient for uniform flow perpendicular to a heated circular disk can be determined through empirical correlations or experimental measurements.
These methods take into account various factors such as fluid properties, flow velocity, disk diameter, and surface conditions to estimate the heat transfer coefficient.
When a heated circular disk is exposed to a fluid flow that is perpendicular to its surface, the local convection heat transfer coefficient characterizes the rate of heat transfer between the disk and the surrounding fluid. Determining this coefficient requires empirical correlations or experimental measurements. These correlations or experiments consider several factors that influence heat transfer.
Factors such as fluid properties (such as viscosity and thermal conductivity), flow velocity, disk diameter, and surface conditions (such as roughness or presence of a boundary layer) play a role in determining the heat transfer coefficient. By conducting experiments or using empirical correlations derived from experimental data, engineers and researchers can estimate the local convection heat transfer coefficient for a specific flow situation. These estimates are crucial for designing and optimizing heat transfer systems and ensuring efficient cooling or heating processes.
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What is the speed of acceleration of a free-falling object?
A. 8.9 m/s
B. 9.8 m/s
C. 9.8 m/min
D. 8.9 m
Answers
Answer:
B because acceleration due to gravity is 9.8 meter per second square
Dr. Paul studies states of consciousness that are physiological induced, such as:
a) sensory deprivation
b) hypnosis
c) hallucinations
d) mediation
Answers
Dr. Paul studies states of consciousness that are physiological induced, such as:
d. mediation.
What are some of the physiological-induced states of consciousness studied by Dr. Paul?Dr. Paul studies states of consciousness that are physiologically induced, such as meditation. Meditation is a practice that involves training the mind to achieve a state of focused attention and heightened awareness. It is often associated with relaxation and stress reduction.
During meditation, individuals typically sit in a comfortable position and engage in various techniques to calm the mind and cultivate a state of inner stillness. There are different forms of meditation, but they generally involve directing attention to a specific object, such as the breath, a mantra, or a visual image.
Research has shown that meditation can have several physiological effects on the body. For example, it has been found to reduce heart rate, blood pressure, and levels of stress hormones like cortisol. It can also increase the production of certain brain waves associated with relaxation and improved cognitive function.
Meditation has been practiced for centuries in various religious and spiritual traditions, but it has also gained popularity in secular contexts as a means of enhancing overall well-being and promoting mental health. It is often used as a complementary therapy for conditions such as anxiety, depression, chronic pain, and insomnia.
Dr. Paul's research likely involves investigating the specific mechanisms through which meditation affects the brain and body. This could include studying changes in brain activity using techniques like electroencephalography (EEG) or functional magnetic resonance imaging (fMRI). The goal may be to better understand the underlying physiological processes involved in meditation and its potential benefits for different aspects of human functioning.
Therefore the correct answer is d. mediation.
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What are some examples of objects that scatter light?
Answers
Explanation:
Sun shining hope i help you! :)
an example of inertia is when your body flies forward when you slam on the breaks.
a,true
b,false
help :
Answers
Answer:
A True ( I Think Its True I'm Not Intirely sure)
Explanation:
Answer:
true
Explanation:
True.....when you apply the brakes to slow down, your body's inertia wants ot keep moving forward
Using the correct IUPAC nomenclature, what is the correct name, formula,
and classification of a compound that contains two nitrogen atoms and one
oxygen atom?
O A. Mononitrogen dioxide, N20, covalent compound.
B. Nitrogen dioxide, NO2, ionic compound.
O C. Dinitrogen monoxide, N20, covalent compound.
D. Nitrogen oxide, No, ionic compound.
Answers
Answer: C is right
Explanation:
N and O are no-metals and forms covalent bonds.
Usually they need a. Prefix whic tells number of atoms in compound
What is the primary cause of earthquakes?
Answers
Answer:
Tectonic movement is the primary cause of earthquake.
When a substance experiences a phase change (state of matter change) is this a chemical or physical change? How do you know?
Answers
Answer:its a physical change as state of matter changes without any reactions
Explanation:when a chemical reaction, there is a change in the composition of the substances in question; in a physical change there is a difference in the appearance, smell, or simple display of a sample of matter without a change in composition. Although we call them physical "reactions," no reaction is actually occurring
What needs to be done to balance this equation?
Question 4 options:
Do nothing (equation is balanced).
Change O 2 to O 4 on the left side of the equation.
Add coefficient 2 to O 2 on the left side of the equation.
Remove coefficient 2 in front of H 2O on the right side of the equation.
Answers
Answer:
Add the coefficient 2 to O2 on the left side of the equation. (O2 represents a molecule of oxygen gas)
The equation shows an equal number of H atoms and C atoms on either side, but the number of O atoms must also balance.
A 0.0500-kg ice cube at −30.0ºC is placed in 0.400 kg of 35.0ºC water in a very well-insulated container. What is the final temperature?
Answers
The amount of heat that is gained by water is equal to the amount of heat loss by the ice. Therefore, we have the following relationship:
\(-Q_w=Q_i\)Where "Qw" is the heat of water and "Qi" is the heat of ice. The heat of water is given by:
\(Q_w=m_wC_w(T_f-T_{0w})\)The amount of heat of ice must be calculated for the two states, solid and liquid. For the solid-state the temperature will be from -30 degrees to 0 degrees, therefore, we have:
\(Q_i=m_iC_i(T_f-T_{0i})\)Where Ci is the specific heat of ice in solid-state and is equal to:
\(C_i=2090\frac{kJ}{\operatorname{kg}}\)Replacing the values:
\(Q_i=(0.05\operatorname{kg})(2090\frac{kJ}{\operatorname{kg}K})(0-(-30C))\)Solving the operations we get:
\(Q_i=3135J\)Now we need to determine the amount of heat that needs the ice to convert into liquid. This is given by:
\(Q_{i-l}=m_iL_f\)Lf is the latent heat of ice and is equal to:
\(L_f=334\frac{kJ}{\operatorname{kg}}\)Replacing the values we get:
\(Q_{i-l}=(0.05\operatorname{kg})(334\frac{kJ}{\operatorname{kg}})\)Solving the operations:
\(Q_{i-l}=16.7kJ=16700J\)Now we need the amount of heat of liquid ice to its final temperature, this is given by:
\(Q_l=m_iC_l(T_f-0)\)Applying the relationship:
\(-m_wC_w(T_f-T_{0w})=m_iC_i(T_f-T_{0i})+m_iL_f+m_iC_w(T_f-0)\)Cw is the specific heat of water and is equal to:
\(C_w=4184\frac{J}{\operatorname{kg}K}\)And the specific heat of ice is:
\(C_i=4184\frac{J}{\operatorname{kg}K}\)Replacing the values. The first two terms on the right side we already calculated and the final temperature is the same for both:
\(-(0.4\operatorname{kg})(4184\frac{kJ}{\operatorname{kg}K})(T_f-35)=3135J+16700J+(0.05)(4184\frac{kJ}{\operatorname{kg}K})(T_f)\)Solving operations:
\(-1673.6\frac{kJ}{K}(T_f-35)=19835J+209.2\frac{kJ}{K}T_f\)Now we solve for the final temperature:
\(-1673.6T_f+58576=19835+209.2T_f\)Subtracting 19835 to both sideS:
\(\begin{gathered} -1673.6T_f+58576-19835=209.2T_f \\ -1673.6T_f+38741=209.2T_f \end{gathered}\)Now we add 1673Tf to both sides:
\(\begin{gathered} 38741=209.2T_f+1673.6T_f \\ 38741=1882.8T_f \end{gathered}\)Now we divide both sides by 1882.2
\(\frac{38741}{1882.8}=T_f\)\(20.57=T_f\)Therefore, the final temperature is 20.57 °C. This value can be converted into Kelvin using the following relationship:
\(T_K=T_C+273.15\)Replacing the temperature:
\(T_K=20.57+273.15=293.72\)Therefore, the final temperature is 293.72 K.
need some more help please
Answers
Answer:
Longitudinal wave
Explanation:
Mechanical longitudinal waves are also called compressional or compression waves, because they produce compression and rarefaction when traveling through a medium, and pressure waves, because they produce increases and decreases in pressure.
A typical protostar may be several thousand times more luminous than the sun. what is the source of this energy?
Answers
The source of this energy is from the release of gravitational energy as the protostar continues to shrink.
How are stars born and what is a protostar?Nebulae have as possible differences in gas and dust. Some factors, such as turbulence, can cause one of them to contract. This contraction of the set of materials causes the elaboration and execution of this phase of materials, generating what is usually called, in this protostar.
A protostar is formed by the contraction of a giant molecular cloud in the interstellar medium. Stars form within relatively dense concentrations of interstellar gas and dust known as molecular clouds.
See more about protostar at brainly.com/question/14317247
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