Kin made a Picture frame for a square picture with sides that are 5f-4 inches long. Framing the picture adds 2 inches to the length of each side. Use the distributive property to write two expressions for the perimeter of the frame picture.
SHOW YOUR WORK

Pls help Tysm!

Conjugations and real structures are important tools used to study complex vector spaces.

A vector is a mathematical object with magnitude and direction. A complex vector space is a vector space where the vectors have complex numbers as components.

Conjugation is a mathematical operation that involves changing the sign of the imaginary part of a complex number.

Real structures refer to certain mathematical objects or operations that preserve the real part of a complex number.

The relationship between the concepts of conjugate complex vector space and conjugations/real structures is that they are both used to study complex vector spaces.

A conjugate complex vector space is a complex vector space equipped with a conjugation, which is an antilinear and involatile map.

The conjugation on a complex vector space allows us to distinguish between real and imaginary parts of a vector.

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We have to find the value of  `(sinθ+cosθ−tanθ)/(secθ+cscθ−cotθ)`

Let's find all trigonometric ratios:

We can say that:

\($$\tan \theta= \frac{opp}{adj}= \frac{-4}{3}$$$$\text\)

{Using the Pythagorean Theorem we can find the hypotenuse }

\($$$$\text{Hypotenuse = } \sqrt{(-4)^2+(3)^2}\)

\(= \sqrt{16+9}\)

= \(\sqrt{25}\)

=\(5$$$$\)

Substituting the values of sinθ, cosθ and tanθ in `

\(= \frac{\frac{3}{5} + \frac{-4}{5} - \frac{-4}{3}}{\frac{-4}{5} + \frac{5}{3} - \frac{-3}{4}}$$$$\)

\(=\frac{\frac{9}{15} + \frac{-12}{15} + \frac{20}{15}}{\frac{-16}{20} + \frac{25}{12} + \frac{3}{4}}$$$$\)

\(=\frac{\frac{17}{15}}{\frac{-14}{15}}$$$$\)

\(=-\frac{17}{14}$$\)

Therefore, \(`(sinθ+cosθ−tanθ)/(secθ+cscθ−cotθ)\)` is equal to

`-17/14` when `tanθ=−43` (Quadrant II).

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The mass of salt in the tank at time t.

dS/dt = 10 - S/400

S(0) = 100 grams

The solution is S(t) = 4000 - 3900\(e^{\frac{-t}{400}}\)

A tank holds water V(0) = 4000 liters in which salt S(0) = 100 grams.

So dS/dt = S(in) - S(out)

S(in) = 1 × 10 = 10 gram/liters

S(out) = S/V × 10 = 10S/V gram/liters

V = V(0) + q(in) - q(out)

V = 4000 + 10t - 10t

V = 4000 liters

dS/dt = 10 - 10S/V

dS/dt = 10 - 10S/4000

dS/dt = 10 - S/400

Now given; S(0) = 100.

Here, p(t) = 1/400, q(t) = 10

\(\int p(t)dt = \int\frac{1}{400}dt\)\(\int p(t)dt = \frac{1}{400}t\)

\(\mu=e^{\int p(t)dt}\)

\(\mu=e^{\frac{t}{400}}\)

So, S(t) = \(\frac{\int\mu q(t)dt+C}{\mu}\)

S(t) = \(\frac{\int e^{\frac{t}{400}} \cdot10dt+C}{e^{\frac{t}{400}}}\)

S(t) = \(e^{\frac{-t}{400}} \left({\int e^{\frac{t}{400}} \cdot10dt+C}\right)\)

S(t) = \(e^{\frac{-t}{400}} \left({10\times\frac{e^{\frac{t}{400}}}{1/400} +C}\right)\)

S(t) = \(e^{\frac{-t}{400}} \left({4000\times{e^{\frac{t}{400}} +C}\right)\)

Now solving the bracket

S(t) = 4000 + \(e^{\frac{-t}{400}}\)C.....(1)

At S(0) = 100

100 = 4000 + \(e^{\frac{-0}{400}}\) C

100 = 4000 + \(e^{0}\) C

100 = 4000 + C

Subtract 4000 on both side, we get

C = -3900

Now S(t) = 4000 - 3900\(e^{\frac{-t}{400}}\)

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The complete question is:

A tank holds 4000 liters of water in which 100 grams of salt have been dissolved. Saltwater with a concentration of 1 grams/liter is pumped in at 10 liters/minute and the well mixed saltwater solution is pumped out at the same rate. Write initial the value problem for:

The mass of salt in the tank at time t.

dS/dt =

S(0) =

The solution is S(t) =

Answer:

C and D

Step-by-step explanation:

–4x = –3   and   3 = 4x     is the answer.

(I did the quiz)

The total amount due on November 15th would be $1667.81

Let's first calculate the trade discount amount:

Suggested list price: $1400

Trade discount rate: 40/10 = 4%

Trade discount amount: $1400 x 4% = $56

After deducting the trade discount, the price becomes:

$1400 - $56 = $1344

Next, let's calculate the cash discount:

Amount after trade discount: $1344

Cash discount rate: 8/10 = 8%

Cash discount amount: $1344 x 8% = $107.52

After deducting the cash discount, the price becomes:

$1344 - $107.52 = $1236.48

Finally, let's calculate the total amount due:

Amount after cash discount: $1236.48

Markup rate: 35%

Markup amount: $1236.48 x 35% = $431.33

Total amount due: $1236.48 + $431.33 = $1667.81

So, the total amount due on November 15th would be $1667.81.

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Answer:

I wouldn't say this is entirely correct, but I think it's 45%.

Step-by-step explanation:

If you started with $90 and it was reduced 20%, than 25% MORE, the final percentage that was lowered would be the 20% and 25% added together.

The answer is 45%.

(Please do tell me if I got this wrong!!)

The original price reduced to 60%.

A percentage is a ratio or number that can be expressed as a fraction of 100. Additionally, it is denoted by the symbol "%."

On September 1, a dress was priced at $90. On October 1, the price was reduced by 20%.

That means,

the price is now = $90 - (90 x 20 /100) = $72

On November 1, the price was further reduced by 25% of the October 1 price.

The price is now = $72 - ( 72 x 25 / 100) = $54

To find the percentage of original price;

The percentage of original price

= 5400 / 90

= 60%

Therefore, the final price is 60% of the original price.

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Answer:

3b/2 + 3

Step-by-step explanation:

The formula to calculate perimeter of rectangle is 2l + 2w

The length is half the width so length is 1/2 (b/2 +1), which when simplified is b/4 + 1/2

Using the formula to calculate perimeter you can substitute and calculate

p= 2l + 2w

p= 2(b/4 + 1/2) + 2(b/2 + 1)

p= 2b/4 +2/2 + 2b/2 +2

p= 1/2b + 1 + b + 2

p= 3/2b + 3

Simplified it's 3b/2 +3

Answer:

5x • 8

Step-by-step explanation:

First you'd switch the numbers around so they can work together.

(3x+2x)(5+3)

Then you add them together.

5x • 8

This would be the equation simplified.

Answer:

2a+50=5a-4

5a-2a=50+4

3a=54

a=18

Answer:

\(a=18\)

Step-by-step explanation:

\(2a+50=5a-4\\\mathrm{Subtract\:}50\mathrm{\:from\:both\:sides}\\2a+50-50=5a-4-50\\Simplify\\2a=5a-54\\\mathrm{Subtract\:}5a\mathrm{\:from\:both\:sides}\\2a-5a=5a-54-5a\\\mathrm{Simplify}\\-3a=-54\\\mathrm{Divide\:both\:sides\:by\:}-3\\\frac{-3a}{-3}=\frac{-54}{-3}\\Simplify\\\frac{-3a}{-3}=\frac{-54}{-3}\\\mathrm{Simplify\:}\frac{-3a}{-3}:\quad a\\\frac{-3a}{-3}\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{-b}=\frac{a}{b}\\=\frac{3a}{3}\\\mathrm{Divide\:the\:numbers:}\:\frac{3}{3}=1\)

\(=a\\\mathrm{Simplify\:}\frac{-54}{-3}:\quad 18\\\frac{-54}{-3}\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{-b}=\frac{a}{b}\\=\frac{54}{3}\\\mathrm{Divide\:the\:numbers:}\:\frac{54}{3}=18\\=18\\a=18\)

Answer: 400 cm²

Step-by-step explanation:

the area of a trapezoid is: A = (b1+b2)/2 x h

using this formula:

A = (30+10)/2 x 20

A = 40/2 x 20

A = 20 x 20

.: A = 400cm²

Hope this helped :)

Answer:

A.) $10,400

Contribution every payday = $60

Pay periods in a year = 26

Step-by-step explanation:

Assume her salary, that is total cost = y

Percentage deduction 15% of total cost

biweekly paychecks = $60

Therefore, 15% of y = $60

(15/100)y = 60

15y = 6000

y = 400

Total value of contribution:

$400 × number of biweeks in a year

If number of weeks in a year = 52

No of bi-weeks = 52/2 = 26

$400 × 26 = $10400

Answer:

the correct answer is $9,750.00

got it right

Step-by-step explanation:

Answer: y=2x-1

Step-by-step explanation:

In slope intercept form y=Mx+b

Mx=slope and b=intercept

Y=2x-1

The equation of line with slope m = 2 and y-intercept is -1 is given by

y = 2x - 1

The equation of a line is expressed as y = mx + b where m is the slope and b is the y-intercept

And y - y₁ = m ( x - x₁ )

y = y-coordinate of second point

y₁ = y-coordinate of point one

m = slope

x = x-coordinate of second point

x₁ = x-coordinate of point one

The slope m = ( y₂ - y₁ ) / ( x₂ - x₁ )

Given data ,

Let the equation of line be represented as A

Now , the value of A is

Let the slope of the line m = 2

Let the y intercept of the line b = -1

Now , equation of a line is expressed as y = mx + b where m is the slope and b is the y-intercept

Substituting the values in the equation , we get

y = 2x - 1   be equation (1)

Therefore , the value of A is y = 2x - 1

Hence , the equation of line is y = 2x - 1

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Answer:

label the coners of heagon 1 abcdef and draw a smaller or biger hexagon and label its coners ghijkl then just compare the labed coners

Answer:

See below

Step-by-step explanation:

Odds AGAINST are 3 to5        then odds FOR are  2 to 5

    2/5   = .4 = 40%   chance of winning

Therefore , the solution of the given problem of surface area comes out to be Concave hexagonal area equals 24.

Its surface area serves as a proxy for how much overall space it occupies. The whole environment of a three-dimensional shape is taken into account when calculating its surface area. The overall size of something is its surface area. The volume of water in a cuboid can be determined by summing the faces on all of its six rectangular sides. To determine the box's measurements, apply the following formula: For 2lh, 2lw, but also 2hw, the surface is the identical (SA). The region is represented by the surface area of the muti form.

Here,

Given :

The Pythagorean theorem can be used to calculate the distance between it circle centers and the difference in the radii of two circles (4-2=2) to determine the lengths of the rectangle's sides. 

We can calculate the area of rectangular as well as the two triangles using that. The regions of the these three forms are added to create the hexagon's surface area.

Let d be the distance between both the circle centers in the scenario described.

d² = (4+2)^2

d = √((4+2)^2) = √(36) = 6

Rectangle area = 26 divided by 12

Each triangle's area is equal to (1/2)(2d)/(1/2)(2*6), or 6

Hexagonal area equals 12 + 2 * 6 = 24.

Concave hexagonal area equals 24.

Therefore , the solution of the given problem of surface area comes out to be Concave hexagonal area equals 24.

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The money invested into the first portion is $78000 while the second is $7000.

Simple interest is a way to figure out how much interest will be charged on a sum of money at a specific rate and for a specific duration of time.

Unlike compound interest, which adds the interest from the principal of prior years to determine the interest of the following year.

Suppose the money invested in the first portion is x while in the second is y.

Total amount  = x + y

x + y = 85000

Now, x is earning 5.5% of interest and y is earning 2.75% of interest.

Total interest = 0.055x + 0.0275y

0.055x + 0.0275y = 4482.50

By substitution,

0.055x + 0.0275(85000 - x) = 4482.50

x = $78000

y = $7000

Hence "The initial investment was $78000, and the subsequent investment was $7000".

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Answer:21.b



Step-by-step explanation: I found the mass

Answer:

the size of the bacterial population after 100 minutes is 20,158.7 bacteria

the size of the bacterial population after  10 hours is 2097152000 bacteria

Step-by-step explanation:

Given that

The bacteria contains 2000

It would be double at every half hour

We need to find out the size of the bacteria after 100 minutes & 10 hours

So,

The size of the bacteria after 100 minutes is

= 2000 × 2^(100 ÷ 30)

= 2000 × 10.079

= 20,158.7 bacteria

Now the size of the bacteria after 10 hours is

10 hours = 10 × 60 minutes = 600 minutes

= 2000 × 2^(600 ÷ 30)

= 2097152000 bacteria

Answer:

40 meters

Step-by-step explanation:

Radius = Diameter / 2

= 80/2

= 40 meters

The reference angle is an acute angle formed between the terminal side of an angle in standard position and the x-axis. the reference angle associated with the angle \(\theta = \frac{7\pi}{8}\) is \(\theta' = \frac{9\pi}{8}\).

In this case, the angle \(\theta = \frac{7\pi}{8}\) is already in radians and lies in the third quadrant of the unit circle. To find the reference angle, we need to determine the angle formed by the terminal side of \(\theta\) and the negative x-axis.

Since the unit circle has a total circumference of \(2\pi\), we can subtract the angle \(\frac{7\pi}{8}\) from \(2\pi\) to find the reference angle:

\(\theta' = 2\pi - \frac{7\pi}{8}\)

Simplifying this expression, we have:

\(\theta' = \frac{16\pi - 7\pi}{8} = \frac{9\pi}{8}\)

Therefore, the reference angle associated with the angle \(\theta = \frac{7\pi}{8}\) is \(\theta' = \frac{9\pi}{8}\).

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The probability that fewer than 3 of the selected consumers believe that cash will be obsolete in the next 20 years is ;

Pr(C & fewer than 3) = 0.1985

What is probability?

Simply put, probability measures how probable something is to occur. We can discuss the probabilities of various outcomes, or how likely they are, whenever we are unsure of how an event will turn out. Statistics is the study of events subject to probability.

Here, we are required to find the probability that fewer than 3 of the selected consumers believe that cash will be obsolete in the next 20 years.

Let Pr(C) be the number of consumers who believe that cash will be obsolete in the next 20 years.

Therefore, since 39.7% believe so,

Pr(C) = 39.7/100 = 0.397

If 6 consumers are selected randomly, the probability that fewer than 3 of the selected consumers believe that cash will be obsolete in the next 20 years will be;

Probability of 2 out 6 to believe so or Probability of 1 out of 6 to believe so.

Pr(2/6) + Pr (1/6)

Therefore the probability that fewer than 3 of the selected consumers believe that cash will be obsolete in the next 20 years is;

Pr (fewer than 3) = (2/6) + (1/6)

Pr (fewer than 3) = 3/6

Therefore, the probability that fewer than 3 of the selected consumers believe that cash will be obsolete in the next 20 years is ;

Pr(C) × Pr (fewer than 3)

i.e 0.397 × (3/6) = 0.1985

Therefore, the probability that fewer than 3 of the selected consumers believe that cash will be obsolete in the next 20 years is ;

Pr(C & fewer than 3) = 0.1985

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Answer:

-25

Hope this helps you out :)

Answer:

the answer should be -25

Answer:

4²+b² = 5²

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem to find the length of the missing side.

The Pythagorean theorem states that the sum of the squares of the legs of a right triangle is equal to the square of the hypotenuse.  Algebraically, this is represented as

a²+b² = c²

We have the measure of one leg, 4 in.  We also have the measure of the hypotenuse, 5 in.  This gives us

4²+b² = 5²

I hope this helps <3

We are given the following Initial value problem:

y''-4y'+8y=78e^{5t} , y(0)=6, y'(0)=32

To solve the given IVP using the Laplace Transform method, we will follow these steps:

Step 1: Take the Laplace Transform of the entire differential equation.

Step 2: Use the initial conditions to form the Laplace Transform of y.

Step 3: Solve for Y in the Laplace domain.

Step 4: Take the inverse Laplace Transform to obtain the solution in the time domain.

Laplace Transform of the differential equation is:

\(\mathcal{L} \{ y'' \}-4\mathcal{L} \{ y' \}+8\mathcal{L} \{ y \}=78 \mathcal{L} \{ e^{5t} \}\)

Now, using the Laplace Transform property \(\mathcal{L} \{ f'(t) \}=s\mathcal{L} \{ f(t) \}-f(0)\)and using the initial conditions provided in the question, we can obtain the Laplace transform of y as:

\begin{aligned}\mathcal{L} \{ y'' \}-4\mathcal{L} \{ y' \}+8\mathcal{L} \{ y \}&

=78 \mathcal{L} \{ e^{5t} \}\\\mathcal{L} \{ y'' \}&

=s^2\mathcal{L} \{ y(t) \}-s(6)-32\\\mathcal{L} \{ y' \}&

=s\mathcal{L} \{ y(t) \}-y(0)\\&

=s\mathcal{L} \{ y(t) \}-6\end{aligned}

Using these transforms in the given equation, we get:

\begin{aligned}s^2Y(s)-s(6)-32-4[sY(s)-6]+8Y(s)&

=\frac{78}{s-5}\\\Rightarrow s^2Y(s)-4sY(s)+8Y(s)&

=\frac{78}{s-5}+s(6)+32\\\Rightarrow Y(s)[s^2-4s+8]&

=\frac{78}{s-5}+s(6)+32\\\Rightarrow Y(s)&

=\frac{78}{(s-5)(s^2-4s+8)}+\frac{s(6)+32}{s^2-4s+8}\end{aligned}

Next, we will use partial fraction decomposition to simplify this expression.

Y(s)=\(\frac{5}{(s-5)}-\frac{s-2}{s^2-4s+8}+\frac{6s}{s^2-4s+8}+4\)

Now, we will use the table of Laplace transforms to obtain the inverse Laplace transform of the above expression.

y(t)=5e^{5t}-[sine(2t)+cos(2t)]e^{2t}+3e^{2t}+4

Thus, the solution of the given IVP is:

y(t)=5e^{5t}-[sine(2t)+cos(2t)]e^{2t}+3e^{2t}+4

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We can use partial fraction decomposition and the properties of Laplace transforms.

To solve the given initial value problem using Laplace transforms, we'll follow these steps:

Step 1: Take the Laplace transform of both sides of the given differential equation.

Step 2: Apply the initial conditions to obtain the transformed equation.

Step 3: Solve the transformed equation for the Laplace transform of y(t).

Step 4: Use the inverse Laplace transform to find the solution y(t).

Let's go through each step in detail.

Step 1: Taking the Laplace transform of the differential equation

We'll denote the Laplace transform of y(t) as Y(s), y'(t) as Y'(s), and y''(t) as Y''(s). Using the table of Laplace transforms, we have:

L{y''(t)} = s^2Y(s) - sy(0) - y'(0)

L{y'(t)} = sY(s) - y(0)

L{y(t)} = Y(s)

Applying the Laplace transform to the given differential equation, we get:

s^2Y(s) - sy(0) - y'(0) - 4(sY(s) - y(0)) + 8Y(s) = 78 / (s - 5)

Simplifying the equation, we have:

s^2Y(s) - s(6) - (32) - 4sY(s) + 4(6) + 8Y(s) = 78 / (s - 5)

s^2Y(s) - 6s - 32 - 4sY(s) + 24 + 8Y(s) = 78 / (s - 5)

(s^2 - 4s + 8)Y(s) - 6s + 8Y(s) = 78 / (s - 5) + 8

Step 2: Applying the initial conditions

Using the initial conditions y(0) = 6 and y'(0) = 32, we substitute them into the transformed equation:

(s^2 - 4s + 8)Y(s) - 6s + 8Y(s) = 78 / (s - 5) + 8

simplify this we get

(s^2 + 4s + 8)Y(s) - 6s = 78 / (s - 5) + 8

Step 3: Solving the transformed equation for Y(s)

Rearranging the equation to solve for Y(s), we have:

(Y(s) * (s^2 + 4s + 8) + 8Y(s)) = 78 / (s - 5) + 6s

Factoring out Y(s), we get:

Y(s) * (s^2 + 4s + 8 + 8) = 78 / (s - 5) + 6s

Y(s) * (s^2 + 4s + 16) = 78 / (s - 5) + 6s

Y(s) * (s + 2)^2 = 78 / (s - 5) + 6s

Dividing both sides by (s + 2)^2, we obtain:

Y(s) = [78 / (s - 5) + 6s] / (s + 2)^2

Step 4: Inverse Laplace transform to find y(t)

To find the inverse Laplace transform of Y(s), we can use partial fraction decomposition and the properties of Laplace transforms.

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The cross sectional area of the cargo trailer floor, which is a composite figure consisting of a square and an isosceles triangle, indicates that the volume of the inside of the trailer is about 3,952 ft³.

A composite figure is a figure comprising of two or more regular figures.

The possible cross section of the trailer, obtained from a similar question on the internet, includes a composite figure, which includes a rectangle and an isosceles triangle.

Please find attached the cross section of the Cargo Trailer Floor created with MS Word.

The dimensions of the rectangle are; Width = 6 ft, length = 10 ft

The dimensions of the triangle are; Base length 6 ft, leg length = 4 ft

Height of the triangular cross section = √(4² - (6/2)²) = √(7)

The cross sectional area of the trailer, A = 6 × 10 + (1/2) × 6 × √(7)

A = 60 + 3·√7

Volume of the trailer, V = Cross sectional area × Height

V = (60 + 3·√7) × 6.5 = 3900 + 19.5·√7

Volume of the trailer = (3,900 + 19.5·√(7)) ft³ ≈ 3952 ft³

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Answer: 123

Step-by-step explanation:

Foe us to solve this, we have to find the lowest common multiple of 16, 20 and 24 first and then add 3 to the LCM. This goes thus:

Multiples of 16 = 16, 32, 48, 64, 80, 96, 112, 128, 144, 160

Multiples of 20 = 20, 40, 60, 80, 10, 120, 140, 160

Multiples of 24 = 24, 48, 72, 96, 120

Therefore, the Lowe's common multiple is 120.

We then add the remainder of 3 and this will give:

= 120 + 3

= 123

To find the selling price that will yield the maximum profit, we need to find the vertex of the quadratic function given by the profit equation y = -5x² + 286x - 2275.The x-coordinate of the vertex can be found using the formula:

x = -b/2a

where a = -5 and b = 286.

x = -b/2a

x = -286/(2(-5))

x = 28.6

So, the selling price that will yield the maximum profit is $28.60 (rounded to the nearest cent).

Therefore, the widgets should be sold for $28.60 to maximize the company's profit.

Hope I helped ya...

Answer:

29 cents

Step-by-step explanation:

The amount of profit, y, made by the company selling widgets, is related to the selling price of each widget, x, by the given equation:

\(y=-5x^2+286x-2275\)

The maximum profit is the y-value of the vertex of the given quadratic equation. Therefore, to find the price of the widgets that maximises profit, we need to find the x-value of the vertex.

The formula to find the x-value of the vertex of a quadratic equation in the form y = ax² + bx + c is:

\(\boxed{x_{\sf vertex}=\dfrac{-b}{2a}}\)

For the given equation, a = -5 and b = 286.

Substitute these into the formula:

\(\implies x_{\sf vertex}=\dfrac{-286}{2(-5)}\)

\(\implies x_{\sf vertex}=\dfrac{-286}{-10}\)

\(\implies x_{\sf vertex}=\dfrac{286}{10}\)

\(\implies x_{\sf vertex}=28.6\)

Assuming the value of x is in cents, the widget should be sold for 29 cents (to the nearest cent) to maximise profit.

Note: The question does not stipulate if the value of x is in cents or dollars. If the value of x is in dollars, the price of the widget should be $28.60 to the nearest cent.

In these options, 0ption D that is, Multicollinearity, is not an assumption of the regression model.

The regression model is a statistical technique used to model the relationship between a dependent variable and one or more independent variables. There are several assumptions associated with the regression model, which should be satisfied for accurate and reliable results.

Option A, Linearity, assumes that there is a linear relationship between the independent variables and the dependent variable. It implies that the relationship can be represented by a straight line.

Option B, Independence, assumes that the observations or data points used in the regression model are independent of each other. This means that the value of one observation does not depend on or influence the value of another observation.

Option C, Homoscedasticity, assumes that the variance of the errors or residuals in the regression model is constant across all levels of the independent variables. It implies that the spread or dispersion of the residuals is consistent.

Option D, Multicollinearity, is not an assumption of the regression model. Multicollinearity refers to a high correlation between independent variables in the regression model, which can cause issues in estimating the individual effects of the independent variables.

Therefore, the correct answer is D) Multicollinearity, as it is not an assumption of the regression model.

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