manhattan distance is the distance traveled as if traveled along rectangular city blocks. the manhattan distance for the standardized observations of (–1.85, 0.65) and (0.55, –0.75) is _____.

If the astronomers are detecting electromagnetic waves with a wavelength of 10⁻⁵ then they are detecting the ultraviolet radiation.

Electromagnetic spectrum each and every light has a specific frequency and wavelength.

According to the Electromagnetic spectrum, the given wavelength of light corresponds to the ultraviolet radiation.

It is obvious that the radiation observed by the astronomers will be coming directly from the sun so it is very much possible that the electromagnetic waves that they are detecting is ultraviolet. This radiation has a wavelength that is slightly less than that of the visible light wavelength.

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The vertical height of the building is determined as 44.1 m.

The height of the building is calculated by applying the following kinematic equation as shown below.

h = vyt + ¹/₂gt²

where;

h = (v sinθ)t + ¹/₂gt²

where

The given parameters include the following;

h = (0 x sin25)(3)  +  ¹/₂(9.8)(3²)

h = 44.1 m

Thus, the height of the building is equal to the vertical distance travelled by the brick thrown at the given initial velocity.

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The bullet will hit 1.87 meters below the target.

Equations of motion are equations that describe the behavior of a physical system in terms of its motion as a function of time.

The first motion equation is v = u + at.

Second equation of motion: s = ut + 12 at2

Third equation of motion: v2 = u2 + 2as

Now for the given question,

Horizontal distance between the bullet and the target is 170 m.

The bullet's horizontal speed (u) is 275 m/s.

Time required to travel the horizontal distance  = \(Distance/velocity\)

Time taken (t) = \(170/275\)

t = 0.618 s

Now, in the vertical direction:

Initial velocity (u) = 0 m/s

Let the depth covered be h.

Time taken (T) = 0.618 s

Acceleration due to gravity (g) = 9.8 m/s^2

Now, using the seconds equation of motion:

\(h=ut+1/2 at^2\\h= 0+1/2 (9.8)(0.618)^2\\h=1.87 meters\)

Hence, the bullet will hit 1.87 meters below the target.

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(a) The inductive reactance in the circuit is 65.94 Ω.

(b) The capacitive reactance in the circuit is 539.51 Ω.

(c) The impedance of the circuit is in kiloohms.

(d) The resistance in the circuit is 2.23 kiloohms.

(e) The phase angle between the current and the source voltage is 21.2°.

(a) The inductive reactance (XL) can be calculated using the formula XL = 2πfL, where f is the frequency (50.0 Hz) and L is the inductance (210 mH = 0.210 H). Substituting the values, we find XL = 65.94 Ω.

(b) The capacitive reactance (XC) can be calculated using the formula XC = 1/(2πfC), where C is the capacitance (5.90 pF = 5.90 x 10^(-12) F). Substituting the values, we find XC = 539.51 Ω.

(c) The impedance (Z) of the circuit is the total opposition to the flow of current and is given by the formula Z = √(R^2 + (XL - XC)^2), where R is the resistance. Since the impedance is in kiloohms, we need to convert the resistance to kiloohms (110 mA = 0.110 A). Substituting the values, we find the impedance of the circuit.

(d) The resistance in the circuit is given as the maximum current (110 mA = 0.110 A) divided by the maximum voltage (AVmax = 240 V), resulting in a resistance of 2.23 kiloohms.

(e) The phase angle (θ) between the current and the source voltage can be calculated using the formula θ = arctan((XL - XC)/R). Substituting the values, we find the phase angle to be 21.2°.

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Answer:

This happens in two ways. If an object is at rest and an unbalanced force pushes or pulls the object, it will move. Unbalanced forces can also change the speed or direction of an object that is already in motion.

Explanation:

Answer:

165 kPa

Explanation:

Absolute pressure is:

P = Patm + ρgh

where Patm is the atmospheric pressure,

ρ is the density,

g is acceleration due to gravity,

and h is the depth.

P = 101,300 Pa + (1000 kg/m³) (9.8 m/s²) (6.50 m)

P = 165,000 Pa

P = 165 kPa

Avoidant or anxious-ambivalent attachment is more common in children with insecure attachment.

Insecure attachment can be caused by a number of factors including inconsistent care, neglect, or trauma. Children who experience insecure attachment may have difficulty forming and maintaining close relationships later in life. Avoidant attachment is characterized by a child who avoids seeking comfort or support from their caregiver, while anxious-ambivalent attachment is characterized by a child who is both clingy and resistant to their caregiver's attempts to comfort them. Both of these attachment styles can be seen in children with insecure attachment, and can lead to difficulties in forming healthy relationships as an adult. It is important to note that attachment styles are not set in stone and can be changed with positive experiences and therapeutic interventions.

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Answer:

New Moon - Crescent Moom ---- Full Moon ---- Waning Quarter

Explanation:

The Moon revolves around the Earth in a 28 day period, which is approximately one Earth month, therefore S the student has been recording the movement of the Moon for 4 Earth weeks this is a period of complete revolution of the Moon .

Consequently you must register the following phases

New Moon - Crescent Moom ---- Full Moon ---- Waning Quarter

in the period where it begins, it must go through the cycle in an orderly way to the right.

Answer:

* if the spring force is greater than the maximum of the static friction force,  

               Fe = m (a + μ_k g)

* If the elastic force is less than or equal to the static friction force, the result is with static friction coefficient

              Fe =μ_s m g

Explanation:

For this exercise we must apply Newton's second law to the system

X axis

         Fe -fr = m a

         Fe = m a + fr

Y axis  

        N-W = 0

        N = W = mg

the roe force is given by

        fr = μ N

        fr = μ mg

we substitute

      Fe = m a + μ m g

      Ee = m (a + μ g)

Let's analyze the solution. We have several possibilities

* if the spring force is greater than the maximum of the static friction force, the system acquires an acceleration and the result is with the kinetic friction coefficient

               Fe = m (a + μ_k g)

* If the elastic force is less than or equal to the static friction force, the result is with static friction coefficient

              Fe =μ_s m g

The diffusion time for oxygen across the 2.0-μm-thick membrane separating air from blood is approximately 3.64 × 10^-5 s.

The diffusion time for oxygen across the 2.0-μm-thick membrane can be calculated using Fick's law of diffusion:

J = -D * (ΔC/Δx)

Where:

J = rate of diffusion

D = diffusion coefficient

ΔC/Δx = concentration gradient

Assuming that the concentration gradient across the membrane is constant, we can simplify the equation to:

t = x^2 / (2D)

Where:

t = diffusion time

x = thickness of the membrane

Substituting the given values:

t = (2.0 × 10^-6 m)^2 / (2 × 1.1 × 10^-11 m^2/s)

t = 3.64 × 10^-5 s

Therefore, the diffusion time for oxygen across the 2.0-μm-thick membrane separating air from blood is approximately 3.64 × 10^-5 s.

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Answer:

Liquid water is essential for life to exist. Water can occur in a liquid state only within a specific temperature range, so knowing the temperature range on a planet will help astronomers predict whether life exists on that planet.

the speed of the fast train is: u = 1.4 x 10^2 m/s

The beat frequency is the difference between the frequencies of the two sound waves coming from the trains. We can use this information to calculate the speed of the fast train.

First, we need to know the frequency of the sound wave emitted by each train. Let's call the frequency of the sound wave from the fast train f1 and the frequency of the sound wave from the slow train f2.

We can use the formula for beat frequency:

beat frequency = |f1 - f2|

Plugging in the given beat frequency of 4.2 Hz, we get:

4.2 Hz = |f1 - f2|

Next, we can use the Doppler effect formula for sound:

f = (v +/- u) / (v +/- vs) * f0

where:
f = observed frequency
v = speed of sound (343 m/s)
u = speed of the observer (unknown)
vs = speed of the source (unknown)
f0 = frequency of the sound wave emitted by the source

For the observer standing near the tracks, we can assume that vs = 0.

So for the sound wave from the fast train, we have:

f1 = (v + u) / v * f0

And for the sound wave from the slow train, we have:

f2 = (v - u) / v * f0

Substituting these into the beat frequency equation and simplifying, we get:

4.2 Hz = u / v * f0

Solving for u, we get:

u = 4.2 Hz * v / f0

Plugging in the given frequency of the sound wave from the fast train (which is the same as f0), we get:

u = 4.2 Hz * 343 m/s / f1

Rounding to two significant figures, the speed of the fast train is:

u = 1.4 x 10^2 m/s

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Answer:

where is the box? how can we answer if your question is lack given? how do we know what box is it your talking about

Answer:

\(\mu= 0.25\)

Explanation:

Given data

Force= 10N

mass= 4kg

r= 4*9.81

r= 39.24N

The expression for the force acting is expressed as

\(F=\mu*r\)

substitute

\(\mu=F/r\)

\(\mu= 10/39.24\)

\(\mu= 0.25\)

The minimum value of the coefficient of static friction in order for the block to remain motionless is 0.26.

Given the following data:

Scientific data:

To determine the minimum value of the coefficient of static friction in order for the block to remain motionless:

Note: The force that is required to make the block motionless must be lesser than or equal to the force of static friction.

Mathematically, the force of static friction is given by the formula;

\(Fs = uFn = umg\)

Where;

Making u the subject of formula, we have:

\(u=\frac{F_s}{mg}\)

Substituting the given parameters into the formula, we have;

\(u=\frac{10}{4.0 \times 9.8} \\\\u=\frac{10}{39.2}\)

u = 0.26

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My answer is addiction... It's addiction when it's the first thing you turn on in the morning and in the night when you sleep late when watching the TV.

Answer:

The vertical distance that the ski jumper fell is 417.45 m.

Explanation:

Given;

initial horizontal velocity of the jumper, \(V_x\) = 26 m/s

horizontal distance of the jumper, dx = 240 m

The time of the motion is given by;

dx = Vₓt

t = dx / Vₓ

t = 240 / 26

t = 9.23 s

The vertical distance traveled by the diver is given by;

\(d_y = V_yt + \frac{1}{2}gt^2\)

initial vertical velocity, \(V_y\), = 0

\(d_y = \frac{1}{2}gt^2\\\\d_y = \frac{1}{2}(9.8)(9.23)^2\\\\d_y = 417.45 \ m\)

Therefore, the vertical distance that the ski jumper fell is 417.45 m.

The cars move with a velocity of 0.713 m/s just after the collision.

By dividing the amount of time it took the object to move a certain distance by the overall distance, one can calculate the object's initial velocity. V is the velocity, d is the distance, and t is the duration in the equation V = d/t.

According to the rule of conservation of momentum, the total amount of momentum before a collision equals the total amount of momentum after the contact.

We can thus write:

m1v1i = (m1 + m2)vf

We can solve for vf as follows:

vf = (m1v1i) / (m1 + m2)

Inputting the numbers provided yields:

vf = (18.0 kg x 100 kg·m/s) / (18.0 kg + 43.0 kg)

= 45.7 kg·m/s

Therefore, the velocity of the cars just after the collision is:

v = vf / (m1 + m2)

= 45.7 kg·m/s / (18.0 kg + 43.0 kg)

= 0.713 m/s

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Answer:

nothing

Explanation:

bocouse of darkness

Answer:

true

Explanation:

The values of a, B0, and the components of the Poynting vector for the given electric and magnetic fields of an electromagnetic wave can be determined. The values are as follows: A. a = -7.0, B. B0 = 10.0 T, C. Sx = -1750 W/m², D. Sy = -24500 W/m², E. Sz = 3500 W/m².

A. To find the value of a, we compare the z-component of the magnetic field B with the given expression B = B0(7.2i - 7.0j + ak). By comparing the z-component, we can determine that a = -7.0.

B. To find the value of B0, we can use the magnitude of the magnetic field B and equate it to the given expression B = B0(7.2i - 7.0j + ak). By comparing the magnitudes, we have |B| = |B0|. Therefore, B0 = 10.0 T.

C. The Poynting vector S represents the power flow per unit area in an electromagnetic wave and is given by the cross product of the electric field E and magnetic field B divided by the permeability of free space. In this case, the x-component of the Poynting vector Sx can be calculated as -EzBy, which yields Sx = -1750 W/m².

D. The y-component of the Poynting vector Sy can be calculated as EzBx, which gives Sy = -24500 W/m².

E. The z-component of the Poynting vector Sz can be calculated as EyBx, which gives Sz = 3500 W/m².

Therefore, the components of the Poynting vector at this time and position are Sx = -1750 W/m², Sy = -24500 W/m², and Sz = 3500 W/m².

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The correct option provided is option C) 5.7 m/s^2

When the rope is holding the rock, the tension force in the rope opposes the weight of the rock and the net force acting on the rock is zero. When the rope breaks, the tension force becomes zero and the weight of the rock is the only force acting on it.

The weight of the rock can be resolved into two components, one parallel to the inclined plane and one perpendicular to it. The component parallel to the inclined plane will cause the rock to accelerate down the plane.

The magnitude of the component of the weight parallel to the inclined plane is given by Wsinθ, where W is the weight of the rock and θ is the angle of the inclined plane with respect to the horizontal.

a = (Wsinθ)/m

where m is the mass of the rock.

Substituting the values, we get:

a = (10 kg) * sin(30°)/10 kg = 5 m/s^2

Therefore, the magnitude of the acceleration of the rock down the inclined plane if the rope breaks is 5 m/s^2.

The closest option provided is option C) 5.7 m/s^2.

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Acceleration pressure in cylinder with 2 in. bore and 0.75 in. rod pushing 1,062 lb load with 0.5 in. acceleration is 518.15 psi.

To find the acceleration pressure in the cap end when extending a cylinder with a 2 in. bore and a 0.75 in.

rod pushing a load of 1,062 lb across a horizontal surface with a coefficient of friction of 0.3, we need to use the formula:

Pressure = (Force x Area) + (Friction Force x Area) / Area.

The acceleration distance is 0.5 in. and the maximum speed is 20 ft/min. Using the given values, we get an acceleration pressure of 518.15 psi.

It's important to note that this is only the pressure during acceleration and deceleration, and not the steady-state pressure when the load is moving at a constant speed.

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Answer:

I believe the answer is roughly 49m/s

Explanation:

List all given variables:

Accel=20m/s^2

Dist=100m

Final velocity=80m/s

Initial velocity=?

Using the equation i=sqrt(f^2-2a*d) where i =initial velocity, f=final velocity, a=acceleration, and d=distance, we can plug in the known values and solve for initial velocity

i=sqrt(80^2-2*20*100)

i=sqrt(6400-4000)

i=sqrt(2400)

i=48.99, rounded up to 49m/s as the initial velocity

This is my speculation about this answer would appreciate if anyone can confirm this.

Answer and Explanation:

Using a = F/m, we get:

Acceleration for Road A = 480/62 = ~7.74 m/s^2

Acceleration for Road B = 240/62 = ~3.87 m/s^2

Acceleration for Road C = 600/62 = ~9.68 m/s^2

If the net force becomes higher than 600N and the mass stays constant, the acceleration will increase proportionally to how much the force increases and the acceleration will be greater than the acceleration when the force is 600N.

I hope this helps! :)

Answer:

B. If two objects collide, each object exerts a force equal to and in the opposite direction of the other.

Explanation:

Newton's law states that for every force there is an equal opposite force.

Answer:

.5 m

Explanation:

It is correct lol.

Adding more insulation to a home's attic is a simple approach to save heating bills. Consider that the attic and all outside surfaces of the home already have 15 cm of fiberglass insulation. The cost of heating would drop by 12%.

Don't make as many car excursions as you normally would. Cut back on, or stop using, wood stoves and fireplaces. Be careful not to burn rubbish, leaves, or other items. Use electric lawn and garden tools instead of gas-powered ones.

Touching fiberglass shouldn't have an adverse long-term health consequence. As a result of fiberglass exposure, eyes may become red and itchy. Inflammation of the throat and nose.

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Answer:

\({ \bf{power \: { \tt{(watts)}} = \frac{workdone \: { \tt{(joules)}}}{time \: { \tt{(seconds)}}} \: }}\)

Answer:

Hydrothermal vents

Explanation:

A hydrothermal vent is found along with areas of volcanic activity in the ocean floor which discharges geothermally heated water. Tectonic plates in such areas move apart at spreading centers and hotspots to form hydrothermal vent.

A hydrothermal vent ejects hot and often toxic, fluids and gases into the surrounding seawater when seawater meets magma.

Hence, the correct answer is "Hydrothermal vents".