Metallic behavior correlates with large atomic size and low ionization energy. thus, metallic behavior increases down a group and decreases from left to right across a period.
a. True
b. False
Answers
Metallic behavior does not increase down a group and decreases from left to right across a period.
The chemical characteristics of elements that are metals are used to characterize the behavior of metals. These characteristics can all be traced back to a single fact. This fact refers to the relative ease with which metals may either lose electrons or get oxidized.
The chemical characteristics of elements that are metals are used to characterize the behavior of metals. These characteristics are all derived from a single observation.
This fact refers to the relative ease with which metals may either lose electrons or get oxidized.
This statement is false.
The correct statement is that metallic behavior increases from left to right across a period and decreases down a group. As the atomic radius decreases from left to right, the ionization energy and electronegativity increase, making the element less metallic.
As the atomic radius increases down a group, the ionization energy and electronegativity decrease, making the element more metallic.
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Related Questions
In another experiment the student turreted 50.0
Answers
Answer:
is this a full question ????
Explanation:
Why are there airlock on Mars and how do you think they work
Answers
Answer:
to protect astronauts from dieing from no air or presurre
Explanation:
To prepare 100 mL of a 0.40 mol/L solution of copper (II) sulfate from a 1.80 mol/L solution. What volume of the concentrated solution was required?
Answers
The volume of the concentrated solution required to prepare 100 mL of a 0.40 mol/L solution of copper (II) sulfate from a 1.80 mol/L solution is 22.22mL.
How to calculate volume?Volume is a three-dimensional measure of space that comprises a length, a width and a height.
It can be measured in units of cubic centimeters (cm³), cubic inches (in³), however, that of a solution is measured in litres or milliliters (mL).
The volume of a solution can be calculated using the following formula:
C1V1 = C2V2
Where;
C1 = initial concentrationC2 = final concentrationV1 = initial volumeV2 = final volume100 × 0.4 = 1.8 × V2
40 = 1.8V2
V2 = 40 ÷ 1.8
V2 = 22.22mL
Therefore, the volume of the concentrated solution required to prepare 100 mL of a 0.40 mol/L solution of copper (II) sulfate from a 1.80 mol/L solution is 22.22mL.
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What is the goal or the question trying to be answered while completing the Viscosity lab?
Question 1 options:
a. Why is honey sticky?
b. How does temperature influence viscosity?
c. How fast does honey flow down a pan?
Answers
The goal of the Viscosity lab is to investigate how temperature influences viscosity.
Viscosity is a measure of a fluid's resistance to flow. In this lab, the main question being addressed is how temperature affects viscosity. By conducting experiments and analyzing the results, the goal is to understand the relationship between temperature and the flow properties of a fluid.
The lab may involve measuring the viscosity of different liquids at various temperatures and observing how the viscosity changes as the temperature is manipulated. The focus is on examining how the internal structure and intermolecular forces within the fluid are affected by temperature, leading to changes in viscosity.
By answering this question, the lab aims to provide insights into the fundamental properties of fluids and their behavior under different temperature conditions, contributing to a better understanding of the concept of viscosity.
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24. what is the most likely method of decay of the radioactive isotope technicium-99 (99tc)? a. alpha decay b. beta decay c. electron capture d. positron emission e. both electron capture and positron emission
Answers
The radioactive isotope Technium-99 decays most likely through alpha decay (99tc). An atomic nucleus emits an alpha particle during the radioactive decay process known as "alpha decay".
and then changes or "decays" into a separate atomic nucleus with a mass number that is decreased by four and an atomic number that is decreased by two. The nucleus of an atom of helium-4 is the same as an alpha particle. Radioisotopes are an element's radioactive isotopes. They are the atoms with unstable neutron-proton combinations or excess energy in their nuclei. During those processes, the radionuclide is said to experience radioactive decay, albeit the surplus energy may be put to use in any number of ways.
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The term that refers to harmful chemicals emitted directly into the air from natural processes and human activities is _____. Group of answer choices secondary pollutant direct smog primary pollutant tertiary pollutant photochemical smog
Answers
The term refers to harmful chemicals emitted directly into the air from natural processes and human activities as primary pollutants.
Primary pollutants are those that are emitted directly into the atmosphere from sources such as factories, vehicles, and natural sources like volcanoes and wildfires. Common examples of primary pollutants include carbon monoxide (CO), nitrogen oxides (NOx), sulfur dioxide particulate matter (PM), and volatile organic compounds (VOCs).
These pollutants can have harmful effects on human health and the environment and are an important focus of air quality regulations and initiatives to reduce air pollution.
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Full Question: The term that refers to harmful chemicals emitted directly into the air from natural processes and human activities is what? Please choose one of the following options:
secondary pollutant, direct smog, primary pollutant, tertiary pollutant, photochemical smog.Please write an explanation if you find the answer, I don't get it.
A flask contains 21.8 g of chlorine gas and 47.8 g of sulfur dioxide gas. What is the mole fraction of the sulfur dioxide?
Round your answer to 3 decimal spaces, even if sig figs are not conserved.
Answers
The mole fraction of the sulfur dioxide gas present in a falsk which contains 21.8 g of chlorine gas and 47.8 g of sulfur dioxide gas is 0.708.
How do we calculate mole fraction?Mole fraction of any substance will be calculated by dividing the moles of desired substance by the total moles of the species present in that sample.
Moles can be calculated as:
n = W/M, where
W = given mass
M = molar mass
Moles of 21.8g of chlorine gas = 21.8g / 71g/mol = 0.307mol
Moles of 47.8g of sulphur dioxide gas = 47.8g / 64g/mol = 0.746mol
Mole fraction of sulphur dioxide gas = 0.746 / 0.746+0.307 = 0.708
Hence required mole fraction of sulphur dioxide gas is 0.708.
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What is one difference between an electron and a neutron?
Answers
Answer: Neutron has no charge, electron has a charge and mass. Neutron occurs inside the nucleus where electron is seen outside the nucleus.
Explanation:
help<3
If a solid object is taken from Earth far into space, which of the following measurements of the object
will change the most?
A. density
B. mass
C. volume
D. weight
Answers
Answer:
D. weight
\( \: \)
If a solid object is taken from Earth far into space, which of the following measurements of the object will change the most?
A. density
B. mass
C. volume
D. weight
Answer:-option D. weight
Explanation:-Because the gravity of the planet/object changes, the weight of the object changes when you move it away from the earth or place it on another planet.
However, the mass of the object remains the same regardless of whether it is on Earth or outer space.
__M+__Q2----->___MQ3
Answers
Answer: 2M + 3Q2 -----> 2MQ3
Explanation:
2 Ms either side, and 6 Qs either side
5
Select the correct answer.
A chemistry student heated Iron (a graylsh solid) with sulfur (a yellow solid) and observed a black, lumpy solid forming. What is the student's
conclusion?
A. A physical change has occurred, and a new substance has formed.
B. A chemical change has occurred, and a new substance has formed.
OC A physical change has occurred, and the reactants and products have the same properties.
D. A chemical change has occurred, and the reactants and products have the same properties.
Reset
Next
O 2020 Edmentum. All rights reserve
Answers
Answer:
B.
Explanation:
The change in color and the indistinguishable states of the substances must indicate a chemical change.
When servers or sellers break state, county, or municipal alcohol laws when serving or selling alcohol, the server or seller
o is not llable; the establishment's owner will de held criminally liable.
o may be fined, but cannot face criminal charges.
will not be fined, but the establishment could lose its liquor license
Answers
When servers break state, county, or municipal alcohol laws when serving alcohol, the server could be fined and the establishment could lose its liquor license.
What is Liquor license?This is defined as governmentally issued permit for the service of alcohol in an area over a period of time.
When alcohol law is broken, there may be a fine or the revoking of the liquor license.
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is butanoic acid a hydrocarbon?
Answers
Yes butanoic acid is a hydrocarbon.
if the pco2 of a volume of water is increased, what effect will this have on the ph of the water?
Answers
An increase in pCO2 leads to an increase in the concentration of H3O+ ions and a decrease in pH, making the water more acidic.
If the pCO2 of a volume of water is increased, it will cause the pH of the water to decrease. This is because an increase in pCO2 leads to an increase in the concentration of dissolved carbon dioxide, which reacts with water to form carbonic acid (H2CO3) according to the following equation:
CO2 (g) + H2O (l) ⇌ H2CO3 (aq)
Carbonic acid is a weak acid that can donate protons to water, leading to an increase in the concentration of hydronium ions (H3O+) and a decrease in the pH of the water. The equation for the dissociation of carbonic acid is:
H2CO3 (aq) ⇌ H+ (aq) + HCO3- (aq)
Overall, an increase in pCO2 leads to an increase in the concentration of H3O+ ions and a decrease in pH, making the water more acidic.
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A solution contains 1.27×10 −2
M sodium sulfide and 1.35×10 −2
M potassium hydroxide. Solid iron(III) nitrate is added slowly to this mixture. What is the concentration of sulfide ion when hydroxide ion begins to precipitate? [sulfide] =
Answers
To find the concentration of sulfide ion when hydroxide ion begins to precipitate, we need to determine the point at which the reaction between sodium sulfide and iron(III) nitrate produces a precipitate.
This reaction can be represented by the following balanced equation: Na2S(aq) + Fe(NO3)3(aq) → FeS(s) + 2NaNO3(aq) First, let's write the balanced equation for the reaction between potassium hydroxide and iron(III) nitrate:
3KOH(aq) + Fe(NO3)3(aq) → Fe(OH)3(s) + 3KNO3(aq)
From the balanced equation, we can see that for every 3 moles of potassium hydroxide (KOH), we get 1 mole of Fe(OH)3(s) precipitate.
Therefore, when hydroxide ion begins to precipitate, the concentration of sulfide ion will be equal to the concentration of potassium hydroxide. Given that the concentration of sodium sulfide is 1.27×10^(-2) M and the concentration of potassium hydroxide is 1.35×10^(-2) M, the concentration of sulfide ion [S^2-] at the point of precipitation is also 1.35×10^(-2) M. Therefore, the concentration of sulfide ion when hydroxide ion begins to precipitate is 1.35×10^(-2) M.
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KV Company has two service departments whose direct department costs are $15,000 and $25,000, respectively, and two producing departments whose direct department costs are $210,000 and $200,000, respectively. The combined total department costs for the producing departments after allocating the service departments are: Select one: A. $415,000 B. $450,000 C. $400,000 D. $460,000
Answers
According to the information, we can infer that the combined otal department cost is $450,000 (option B).
How to determine the combined total department costs?To determine the combined total department costs for the producing departments after allocating the service departments, we need to allocate the costs of the service departments to the producing departments.
First, we have to consider the information provided:
Service Department 1 cost: $15,000Service Department 2 cost: $25,000Producing Department 1 cost: $210,000Producing Department 2 cost: $200,000Second, we simply add them to the producing department costs:
Allocated total department costs for Producing Department 1: $210,000 + $15,000 = $225,000Allocated total department costs for Producing Department 2: $200,000 + $25,000 = $225,000And finally, the combined total department costs for the producing departments after allocating the service departments is:
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Air is cooling at night. The frost point (temperature at which RH with respect to ice reaches 100%) is reached at T = -10 degree Celsius. a) What is the RH (normal RH with respect to liquid water) at this point? b) Upon further cooling the air reaches a temperature of T =-11 degree Celsius Kaolinite particles of 200 nm diameter are present. Do you expect ice particles to form? If yes, do they form via deposition nucleation or condensation of droplets followed by freezing? Briefly explain your answer. c) Upon even further cooling the air reaches a temperature of T = -12 degree Celsius. Same question as before: Do you expect ice particles to form now? If yes, do they form via deposition nucleation or condensation of droplets followed by freezing? Briefly explain your answer. Equilibrium vapor pressures may be calculated or taken from the table below. t/°C 0 -1 -2 -3 -4 -5 -6 -7 -8 -9 - 10 -11 -12 -13 T/ Keow /Pa 273.15 611.2 272.15 568.2 271.15 527.9 270.15 490.2 269.15 454.8 268.15 421.8 267.15 390.9 266.15 362.1 265.15 335.1 264.15 310.0 263.15 286.5 262.15 264.7 261.15 244.3 260.15 225.4 259.15 207.8 258.15 191.4 e oi/Pa 611.2 562.7 517.7 476.1 437.5 401.8 368.7 338.2 310.0 283.9 259.9 237.7 217.3 198.5 181.2 165.3 - 14 - 15 Equilibrium vapor pressures with respect to water (eow) and with respect to ice (coi).
Answers
The equilibrium vapor pressure with respect to water (eow) is 259.9 Pa. assume that saturation vapor pressure is same as equilibrium vapor pressure.
Therefore, the RH at the frost point is
RH = (eow / saturation vapor pressure) × 100
= (259.9 Pa / 259.9 Pa) × 100
= 100%
b) At T = -11 °C, we need to compare the equilibrium vapor pressure with respect to water (eow) and the equilibrium vapor pressure with respect to ice (coi) to determine if ice particles will form. From the given table, at T = -11 °C, the equilibrium vapor pressure with respect to water (eow) is 237.7 Pa, and the equilibrium vapor pressure with respect to ice (coi) is 165.3 Pa.
The air is supersaturated with respect to ice, and the presence of Kaolinite particles can provide surfaces for water droplets to condense onto, leading to the formation of ice particles.
c) At T = -12 °C, we compare the equilibrium vapor pressure with respect to water (eow) and the equilibrium vapor pressure with respect to ice (coi). From the given table, at T = -12 °C, the equilibrium vapor pressure with respect to water (eow) is 217.3 Pa, and the equilibrium vapor pressure with respect to ice (coi) is 181.2 Pa.
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Which of the following is a chemical property of matter? *
Answers
Which characteristic of a substance is considered a chemical property?
its boiling point
its reactivity
its density
its conductivity
Answers
calulate the elctron energy at which radiative stopping power collisional stopping power are equal for lead oxygen and carbon
Answers
The electron energy at which the radiative stopping power and the collisional stopping power are equal for lead, oxygen, and carbon are 4.6 MeV, 0.9 MeV, and 1.7 MeV respectively.
In order to calculate the electron energy at which the radiative stopping power and the collisional stopping power are equal for lead, oxygen, and carbon, we need to use the Bethe-Bloch formula.
The Bethe-Bloch formula relates the energy loss of charged particles as they traverse matter to the properties of the material, such as its density and atomic number. It includes both the collisional stopping power and the radiative stopping power.
To calculate the energy at which the two stopping powers are equal, we can set the collisional stopping power equal to the radiative stopping power and solve for the electron energy.
Using the Bethe-Bloch formula and assuming a density of 11.3 \(g/cm^3\)for lead, 1.33 \(g/cm^3\) for oxygen, and 1.80 \(g/cm^3\) for carbon, we can calculate the energy for each element.
For lead, the electron energy at which the two stopping powers are equal is approximately 4.6 MeV. For oxygen, it is approximately 0.9 MeV. For carbon, it is approximately 1.7 MeV.
It is important to note that these values are approximate and can vary depending on the exact conditions and assumptions used in the calculations.
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What is the boiling point of water?
Answers
Answer:
212°F , 100°C , 373.15°K
They are all the same, in different units.
Answer:
The boiling point of water is 212 degrees fahrenheit, and/or 100 degrees celsius.
what does it mean to be coplanar in relationship to molecules
Answers
Answer: Coplanar in relationship to molecules means that groups of atoms or just atoms lie on the same plane.
Coplanar - Atoms in the molecule are on the same flat surface when visualized.
Using the periodic table, choose the more reactive nonmetal.
Te or O
Answers
the answer is Te because O is oxygen.
Answer:
O
Explanation:
this is because it is oxygen
Determine which statements apply to hemoglobin, myoglobin, or neither.
a. The oxygen dissociation curve is sigmoidal in shape (s-shaped).
b. As oxygen binds to this molecules, the shape of the molecule changes, enhancing further oxygen binding.
c. The binding pattern for this molecules is considered cooperative.
d. This molecule delivers oxygen more efficiently to tissues.
e. The oxygen dissociation curve is hyperbolic in shape.
f. This molecules has greater affinity for oxygen.
g. oxygen binds irreversibly to this molecule.
h. carbon monoxide binds at an allosteric site, lowering oxygen binding affinity.
Answers
Hemoglobin and myoglobin are both molecules that are involved in the transportation of oxygen in the body. The oxygen dissociation curve for both of these molecules is sigmoidal in shape (s-shaped).
As oxygen binds to these molecules, the shape of the molecule changes, enhancing further oxygen binding. The binding pattern for these molecules is considered cooperative, meaning that as more oxygen molecules bind, it becomes easier for additional oxygen molecules to bind. Hemoglobin delivers oxygen more efficiently to tissues compared to myoglobin. Myoglobin has a hyperbolic-shaped oxygen dissociation curve, while hemoglobin's is sigmoidal.
Hemoglobin has a greater affinity for oxygen than myoglobin. Carbon monoxide binds at an allosteric site on hemoglobin, lowering its oxygen binding affinity. Oxygen binds reversibly to both hemoglobin and myoglobin, not irreversibly. In conclusion, statements a, b, c, d, f, and h apply to hemoglobin and myoglobin, while statement e applies only to myoglobin.
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Elements that LOSE electrons to form POSITIVE cations due to strong electronegativity are generally classified as... (check all that apply)
1. metals
2. transition metals
3. non-metals
Answers
Answer:
Metals
Explanation:
For example, Alkali metals always loose electrons to form cations because they have one electron and it's easier to loose one electron to gain a full set of valence electrons and form a cation rather than gaining seven and forming an anion.
Which of the following is NOT a common property of water?
o Water has high surface tension.
o Water expands when it freezes.
o Ice is less dense than water.
o Water has low heat of vaporization.
Answers
Answer:
A = water has high surface tension
the answer is a hope this helps and plz give me brainlist :)
Drag each tile to the correct image.
Match each alkane name with its structure.
octane
decane
propane
butane
heptane
CHE
IGH
CHE
Reset
Next
Answers
Answer:
The first one is Propane
The second one is HEPTANE
The third one is octane
The 4th is butane
the 5th is decane
The structures have been named according to IUPAC as \(\rm C_3H_8\) Propane, \(\rm C_7H_{16}\) Heptane, \(\rm C_8H_{18}\) Octane, \(\rm C_4H_{10}\) Butane, and \(\rm C_{10}H_{22}\) Decane.
The images has been the representation of the ball and stick structure of the compounds. The central balls have been the representation of the carbon atom , with small balls attached to the sticks have been the representation of the hydrogen attached.
The following structures has been given as:
The structure has 3 carbon atoms with the presence of 8 hydrogen. The molecular formula has been \(\rm C_3H_8\). It has been the structure of propane.The structure has 7 carbon and 16 hydrogen. The structure has been the representation of heptane with molecular formula \(\rm C_7H_{16}\).The structure has molecular formula \(\rm C_8H_{18}\) with 8 carbon and 18 hydrogen. It has been named Octane, according to IUPAC.The structure with 4 carbon and 10 hydrogen with molecular formula \(\rm C_4H_{10}\) has been named according to IUPAC as butane.The structure with molecular formula \(\rm C_{10}H_{22}\) has presence of 10 carbon and 22 hydrogen. It has been named as Decane.The structures have been named according to IUPAC as \(\rm C_3H_8\) Propane, \(\rm C_7H_{16}\) Heptane, \(\rm C_8H_{18}\) Octane, \(\rm C_4H_{10}\) Butane, and \(\rm C_{10}H_{22}\) Decane.
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1. Does warm air rise or sink? Does cold air rise or sink? 2. Air pressure can be high or low. Does air flow from low to high pressure or from high to low pressure? 3. Which is heavier—warm air or cold air? 4. Which has higher air pressure—warm air or cold air? How do you know? 5. Global circulation cells occur because of uneven heat distribution and the earth's rotation. What do we call the effect of the earth's rotation on air circulation?
Answers
Answer:
1. Warm air rises and cold air sinks.
2. Air moves from high to low pressure.
3. Cold air is denser than warm air.
4. Warm air is lighter than cold air and consequently exerts less pressure.
5. Because the Earth rotates on its axis, circulating air is deflected toward the right in the Northern Hemisphere and toward the left in the Southern Hemisphere. This deflection is called the Coriolis effect.
solid liquid gas or plasma
Answers
Answer:
I believe its gas
Explanation:
because it has no symbolic bonds
I am not sure with the answer but I think the answer is solid.
the rate of this reaction is markedly increased if a small amount of sodium iodide is added to the reaction mixture
Answers
If a tiny quantity of sodium iodide is given to the reaction mixture, then rate of this reaction between NaCN, DMSO, and CN is noticeably boosted.
What is sodium iodide used for?Iodine shortage is prevented or treated using sodium iodide. Iodine is necessary for the body's optimal growth and wellness. Sodium iodide may well be required for people who cannot acquire enough iodine from their typical diet or who require extra iodine. Your thyroid gland need iodine to operate correctly.
Where is sodium iodide found?Seafood, tiny quantities diet iodine, and vegetables cultivated in iodine-rich soils are just a few of the foods that contain iodine. Another significant source of iodine is ocean mist that contains iodine.
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