\(\tt h=\dfrac{vo^2~sin^2\theta}{2g}\rightarrow \theta=90\\\\h=\dfrac{vo^2}{2g}=\dfrac{2.78^2}{2\times 9.8}=0.394~m\)
Which of the following statements is/are true for ultrasonic test?a. Equipment used for ultrasonic testing is portableb. Complicated shapes can be easily scannedc. Waves generated are health hazardousd. All the above statements are true
Answer:
Equipment used for ultrasonic testing is portable
Explanation:
An ultrasonic tester is used to detect flaws such as cracks and leaks. Hence, an ultrasonic tester is an integral tool used in material testing and engineering, manufacturing quality control, equipment condition monitoring, building and bridge inspection and much more.
Ultrasonic testing can be performed on steel and other metals and alloys, though it can also be used on concrete, wood and composites, although with less resolution.
A sports car moving at constant speed travels 164 m in 13.77 s. If it then brakes and comes to a stop in 3.6 s. What is its acceleration in terms of "g's", where 1.00 g = 9.80 m/s2?
Answer:
a = - 0.3376 g's
Explanation:
The sports car has a constant speed when travelling. Covered 164 m in 13.77 s. Thus, speed = 164/13.77 m/s
It brakes and now comes to a stop in 3.6 s.
Thus final velocity = 0 m/s
Formula for acceleration is;
a = (v - u)/t
a = (0 - (164/13.77))/3.6
a = -3.308 m/s²
In terms of g's", where 1.00 g = 9.80 m/s², we have;
a = -3.308/9.8 g's
a = - 0.3376 g's
At what horizontal velocity would a satellite have to be launched from the top of Mt. Everest to be placed in a circular orbit around the Earth.
Given formula:
GM/R = v^2
G= 6.67 x 10^-11 N.m^2/kg^2
M= 5.98 x 10^24kg
R= 6.38 x 10^3 km
An orbital projectile should be launched with such a horizontal speed exceeding 8000 m/s. Determine the speed of the a satellite inside an orbit 1000 km, M is 5.98x1024 kg, and R is 6.4x10m. [Ans x 10 = 7.34 m/s].
How far is the top of Mount Everest from outer space?At 328,084 feet, the barrier between earth and space is the highest point you have probably ever gone and is around 11 times greater than Mount Everest. Consider that for a second. If looking at this image doesn't inspire awe in you, perhaps contemplating it in a different way would.
What speed is necessary to send a satellite up at the very least?A: At low earth orbit, an object must travel at a speed of roughly 28,000 km/h (17,500 mph) in order to orbit the Earth. At this speed, the object would be able to leave Earth's atmosphere and keep a steady orbit around it at a height of about 325 km (200 km).
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A man pushing a crate of mass
m = 92.0 kg
at a speed of
v = 0.855 m/s
encounters a rough horizontal surface of length
ℓ = 0.65 m
as in the figure below. If the coefficient of kinetic friction between the crate and rough surface is 0.351 and he exerts a constant horizontal force of 296 N on the crate.
A man pushes a crate labeled m, which moves with a velocity vector v to the right, on a horizontal surface. The horizontal surface is textured from the right edge of the crate to a horizontal distance ℓ from the right edge of the crate.
(a) Find the magnitude and direction of the net force on the crate while it is on the rough surface.
magnitude
N
direction
(opposite as the motion of the crate) or (same as the motion of the crate)
(b) Find the net work done on the crate while it is on the rough surface.
J
(c) Find the speed of the crate when it reaches the end of the rough surface.
m/s
The frictional force is the force that opposes the motion of an object in the opposite direction. Frictional force equals the coefficient of static friction and normal force.
From the given,
mass of crate (m) = 92 kg
the initial speed of create(u) = 0.855 m/s
length (l) = 0.65 m
co-efficient of kinetic friction (μ) = 0.351
Force (F) = 296 N
F(net) =?
Work.done(net) =?
speed =?
F(net) = F - Ff (Ff is the frictional force and is equal to μ.N)
= 296 - (0.351×m×g)
= 296 - (0.351×92×9.8)
= 296 - 318.264
= - 22.264
Thus, the net force, F(net) = -22.264, and the direction of force is in the negative x-axis.
W.D(net) = F×l
= 22.264×0.65
= 14.47 J.
Hence, the net work done is 14.47 J.
Work done = ΔK.E
W = 1/2(mv²), m is mass and v is the final speed.
v² = 2W/m
= (2×14.4721)/92
= 0.31460
v = √0.31460
= 0.560 m/s.
Thus, the velocity is 0.560 m/s.
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what is a shargaff rule
According to Chargaff's rule, the amounts of adenine (A), thymine (T), and guanine (G) in the DNA molecule are equal to each other. The amounts of cytosine (C) and guanine (G) are also equal.
Who is Chargaff ?Erwin Chargaff was a biochemist, author, Bucovinian Jew who immigrated to America during the Nazi era, and professor of biochemistry at Columbia University's medical school.
Chargaff found patterns among the four bases, or chemical building blocks, of DNA, which are directly related to DNA's function as the genetic material of living things.
He was born in Austria-Hungary. Heraclitean Fire: Sketches from a Life Before Nature, an autobiography he penned, received positive reviews.
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The bond order for a single covalent bond is.
A. two
B. four
C. one
D. three
Answer:
I think it should be C, which is one
a load of 600 N is lifted using a first class lever applying an effort of 350 N. If the distance between the fulcrum and the effort is 60 cm and the distance between the load and the fulcrum is 30cm, calculate it's efficiency
Explanation:
(a) A machine is a device by which we can either overcome a large resistive force at some point by applying a small force at a convenient point and in a desired direction or by which we can obtain a gain in the speed.
(b) An ideal machine is a machine whose parts are weightless and frictionless so that which there is no dissipation of energy in any manner. Its efficiency is 100%, i.e. the work output is equal to work input.
ture or false
A land breeze is when the cooler air over the ocean moves in toward land.
Answer:
False
Explanation:
A land breeze is when air flows from land to water. The question above is describing a sea breeze, which is when cool ocean air blows toward land.
Melvina has a mass of 70 kg and is about to jump from the window ledge of a burning building.
The ledge is 80 m above the ground. What is Melvina's potential energy?
Melvina's potential energy is 54,880 Joules.
To calculate Melvina's potential energy, we need to use the formula for gravitational potential energy:
Potential energy = mass × gravitational acceleration × height
Potential energy is a measure of the energy an object possesses due to its position relative to other objects. In this case, Melvina's potential energy is a result of her height above the ground. As she stands on the ledge of the burning building, her potential energy is stored and can be converted into other forms of energy if she were to jump or fall. The potential energy will decrease as she descends, and it will be converted into kinetic energy (energy of motion).
Given that Melvina has a mass of 70 kg and the ledge is 80 m above the ground, we can substitute the values into the formula:
Potential energy = 70 kg × 9.8 m/s² × 80 m
Calculating this, we find:
Potential energy = 54,880 Joules
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What is the difference between the frictional force and shear stress in fluid mechanics?
Answer:
Friction is a force that opposes the relative motion of two objects (or the tendency to move) which are in contact with each other. In contrast, shear stress is a stress induced by a force.
Explanation:
Hope you have a Good day!
May God Bless You<3
A force called friction opposes the tendency of two things in touch with each other to move relative to one another. Shear stress, on the other hand, is a tension brought on by a force. The major distinction between friction and shear stress is this.
What is friction and shear stress in fluid mechanics?The resistance to motion of one object moving in relation to another is known as friction. Friction is dependent on the typical response. Things that are subjected to friction all the time tend to wear out.
Unaligned forces known as shear forces are those that press one part of a body in one direction while pushing a different component of the body in the opposite direction. Shear is dependent on cross-sectional area and shearing force. An object deforms from its initial shape as a result of shear stress.
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what happens to the weight and mass of an object transported from earth to the moon
When an object transported from earth to the moon, its mass remains same but weight becomes 1/6th that on earth..
What is mass?In physics, mass is a quantitative measurement of inertia, a basic characteristic of all matter.
It essentially refers to a body of matter's resistance to changing its speed or location in response to the application of a force. The change caused by an applied force is smaller the more mass a body has.
What is weight?The amount of a body's weight indicates how much gravity is pulling on it. Weight is calculated using the method w = mg. Since weight is a force, it has the same SI unit as a force, which is the Newton (N).
So, mass of an object is intrinsic property of the object - it remains same in earth and in moon. But weight is the amount of gravitational attraction force. Moon has nearly 1/6th gravitational attraction field. So, the weight of the object on moon will be 1/6th that on earth.
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Three cars are driving at 29.0 m/s along the road shown in the figure (Figure 1). Car B is at the bottom of the hill and car C is at the top. Suppose each car suddenly brakes hard and starts to skid. Assume μk=1.00. What is the x-component of the tangential acceleration (i.e., the acceleration parallel to the road) of car A?
Since the car masses are unknown, we are unable to calculate the numerical value of the x-component of Car A's tangential acceleration.
How do kinetic and potential energy compare?The energy that is held in any object or system as a function of its position or component arrangement is known as potential energy. The object or system is unaffected by external factors like air pressure or altitude. Kinetic energy, on the other hand, describes the power of moving particles within a system or an object.
They are being affected by the kinetic frictional force, which is caused by:
f = μk * N
Therefore,
fB = μk * N = μk * mB * g
Car C is at its highest point at the top of the hill, where the normal force acting on it is equal to the force of gravity. Therefore,
fC = μk * N = μk * mC * g
where mC is the mass of Car C.
For Car A, the x-component of the tangential acceleration is given by:
aA = (fB - fC) / mA
where mA is the mass of Car A.
We can substitute the following values and simplify by assuming that the mass of each of the three automobiles is the same:
aA = (μk * mB * g - μk * mC * g) / mA
aA = μk * g * (mB - mC) / mA
Since μk = 1.00 and g = 9.81 m/s², we can plug in the values and get:
aA = (mB - mC) * 9.81 / mA
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The diameter of the asteroid Vesta is of the diameter of the planet Mercury. Mercury has a diameter of 5000 km. Calculate the diameter of Vesta. Show your working.
Answer:
5000 km
Explanation:
Sure, to calculate the diameter of Vesta, we can use the fact that Vesta's diameter is equal to the diameter of Mercury, which is 5000 km.
Therefore, the diameter of Vesta is also 5000 km.
We can show the working by using the following formula:
Diameter of Vesta = Diameter of Mercury
Diameter of Vesta = 5000 km
3. A beach ball is inflated to a volume of 25L of air at 15°C. During the afternoon,
the volume increases by 1L. What is the new temperature outside?
Answer:
Below
Explanation:
P1V1/T1 = P2V2/T2 T MUST be in Kelvin
P1 = P2 so this becomes
V1/T1 = V2/T2
25/ (273.15 + 15) = 26 / (273.15 + X) where 'X' is the °C afternoon temp
X = 26.5 °C
What is responsible for keeping an object at rest or maintaining an object's
constant velocity?
Answer:
Inertia
Explanation:
Inertia is a force which keeps stationary objects at rest and moving objects in motion at constant velocity.
When working with a razor blade or exacto knife --
O hold it as you would a pencil when writing.
O grip it with your fist with the blade facing upward.
O twirl it between your fingers.
O grip it with your fist with the blade facing downward.
Answer:
last answer
Explanation:
gripping it with the blade facing downward is the most efficient and safe way to use an exacto knife
Which interaction has the highest electrostatic potential energy?
O A +2 and -2 particle separated by a distance of 5 nm.
O A +1 and -2 particle separated by a distance of 5 nm.
O A +2 and +2 particle separated by a distance of 10 nm.
O A +2 and -2 particle separated by a distance of 10 nm.
O A +2 and +2 particle separated by a distance of 100 nm.
O A +1 and -2 particle separated by a distance of 10 nm.
O A +2 and +2 particle separated by a distance of 5 nm.
Answer:
The interaction with the highest electrostatic potential energy is:
A +1 and -2 particle separated by a distance of 5 nm.
Explanation:
The electrostatic potential energy between two charged particles depends on the magnitude of their charges and the distance between them. The formula for calculating electrostatic potential energy is:
U = k * (q1 * q2) / d
where U is the electrostatic potential energy, k is Coulomb's constant, q1 and q2 are the magnitudes of the charges, and d is the distance between them.
In the given options, the interaction between +1 and -2 particles separated by a distance of 5 nm has the highest electrostatic potential energy because the charges have a higher magnitude (compared to other options) and they are close to each other, resulting in a stronger electrostatic force of attraction. The other options either have smaller charges, larger distances, or both, leading to lower electrostatic potential energy.
A tennis ball and a bag filled with sand have the same mass. They are dropped from the same height and they hit the ground. The bag of sand stays on the ground, while the tennis ball rebounds. Which experiences the larger impulse from the ground?
Answer:
The bag of sand
Explanation:
I think it is the bag of sand because according to the definition of impulse, impulse is the average force acting on a particule when an external force is being acted on it.
For these questions, answer all parts of the question completely. Use complete
sentences.
4. Imagine that you have decided to try out a new kind of food that your friend
has made for you. You pick it up and take a bite, and it tastes awful. You are
wondering if you should tell your friend what you really think. Give an example of
how each of these parts of the brain would be involved in your experience:
a. Hindbrain (5 points)
b. Midbrain (5 points)
c. Forebrain (5 points)
Examples of how the parts of the brain would be involved in the experience of tasting the food and seeing it was awful include:
Hindbrain - initiating the digestive responseMidbrain - processing the sensory information Forebrain - deciding how to respondHow would the parts of the brain react ?The hindbrain, which includes the cerebellum and brainstem, is responsible for basic bodily functions such as breathing, heart rate, and digestion. In the scenario of trying a new food and finding it unpleasant, the hindbrain would play a role in initiating the digestive response to the food.
The midbrain is involved in the processing of sensory information, including auditory and visual stimuli. In the scenario of trying a new food and finding it unpleasant, the midbrain would be responsible for processing the sensory information related to taste and smell.
The forebrain is responsible for more complex cognitive processes, including decision-making and problem-solving. In the scenario of trying a new food and finding it unpleasant, the forebrain would be involved in deciding how to respond to the situation.
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PLEASE SAVE ME FROM THIS PHYSICS QUESTION (WILL MARK BRAINLIEST)
A 21 kg child is riding a 5.9 kg bike with a velocity of 4.5 m/s to the northwest.
- What is the total momentum of the child and the bike together?
- What is the momentum of the child?
- What is the momentum of the bike?
Answer:
See Below
Explanation:
Mass of child = 21 kg
Mass of bicycle = 5.9 kg
Total mass = 22 + 5.9 = 27.9 kg
Velocity = 4.5 m/s
1) Total momentum of the child and the bike together
= Total mass * Velocity
= 27.9*4.5
= 125.55 kg m per second
2) Momentum of the child
= Mass of child*Velocity
= 21*5.9
= 123.9 kg m per second
3) Momentum of the bike
= Mass of bike*Velocity
= 5.9*4.5
= 26.55 kg m per second
You deposit $2000 in an account earning 8% interest compounded monthly. How much will you have in the account in 5 years?
The amount in my account after 5 years, if a deposit $2000 will be $2985.62.
What is compound interest?Compound interest is the interest calculated on the principal and the interest accumulated over the previous period.
Tocalculate the amount, that will be in my account in 5 years, we use the formula below.
Fromula:
A = P(1+R/100n)ⁿˣ............... Equation 1Where:
A = AmountP = PrincipalR = Ratex = Timen = Total number of months in a yearFrom the question,
Given:
P = $2000R = 8%n = 12 monthsx = 5 yearsSubstitute these values into equation 1
A = 2000[1+8/(12×100)]⁵*¹²A = 2000(1+0.0067)⁶⁰A = 2000(1.0067)⁶⁰A = $2985.62Hence, the amount in my account will be $2985.62.
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The components of a 15 meters per second velocity at an angle of 60 above the horizontal are
The components of a 15 meters per second velocity at an angle of 60 above the horizontal are 13.05 m / s and 0.435 m / s
Resolving the velocity into its horizontal and vertical components, it makes a right angled triangle.
Hypotenuse = V = 15 m / s
θ = 60°
Opposite side = components = \(V_{y}\)
Adjacent side = Horizontal component = \(V_{x}\)
In a right angled triangle,
sin θ = Opposite side / Hypotenuse
cos θ = Adjacent side / Hypotenuse
sin 60° = \(V_{y}\) / V
\(V_{y}\) = 15 * 0.87
\(V_{y}\) = 13.05 m / s
cos 60° = \(V_{x}\) / V
\(V_{x}\) = 0.5 * 0.87
\(V_{x}\) = 0.435 m / s
Therefore,
The horizontal component, \(V_{x}\) = 0.435 m / sThe vertical component, \(V_{y}\) = 13.05 m / s.To know more about components of velocity
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When baseball players throw the ball from the out eld, they usually allow it to takeone bounce before it reaches the in eld because they think that the ball will arrive sooner that way.Suppose that the angle at which a bounced ball leaves the ground is the same as the angle at whichit is thrown but the ball's speed after the bounce is one-half of what it was just before the bounce.(a) Assume that the ball is always thrown with the same initial speed. At what angleshould the elder throw the ball to make it go the same distanceDwith one bounce as a ball thrown upwardsat 45with no bounce
Complete Question
The diagram illustrating this question is shown on the first uploaded image
Answer:
The value is \(\theta = 27^o\)
Explanation:
Generally the distance covered by the ball thrown at angle 45° that did not bounce is mathematically represented as
\(D = v cos (45) * t\)
Here t is the total time duration which is mathematically represented as
\(t = \frac{v sin (45)}{g}\)
This distance distance is also mathematically represented as
\(D = vcos(\theta)* t_1 + \frac{v}{2} cos(\theta )*t_2\)
Here \(\theta\) the angles made as shown in the diagram
Here \(t_1\) is the time before the first bounce which is mathematically represented as
\(t_1 = \frac{v sin (\theta )}{g}\)
\(t_1\) is the time duration before the final point which is mathematically represented as
\(t_2 = \frac{\frac{v}{2} * sin (\theta )}{g}\)
So
\(v cos (45) * \frac{v sin (45)}{g} = vcos(\theta)* \frac{v sin (\theta )}{g} + \frac{v}{2} cos(\theta ) * \frac{\frac{v}{2} * sin (\theta )}{g}\)
=> \(cos (45) sin(45) = cos(\theta)sin(\theta ) + cos(\theta )sin(\frac{\theta}{4})\)
=> \(0.5 = \frac{5}{8} * sin(2\theta )\)
=> \(\theta = 27^o\)
Jane (m=50kg) wants to save Tarzan (m= 80kg) who is standing in the middle of a ring of fire of 5.0 m diameter. Jane has a vine (conveniently attached to a branch right above Tarzan, at a height of 33 m above the ground. Jane holds onto the vine and climbs a tree, growing 16 m away from Tarzan, until she reaches a height of 5.3 m above the ground. She swings down and grabs Tarzan around his waist (1.0m above ground). If they let go of the vine when they reach their highest point, where will they land, relative to Tarzan's original position?
The height that will illustrate the distance will be d = 6.36m
How to calculate the height?Based on the information given, the length of the vine will be:
L = ✓(16² + 27.7)²
L = 32m
The velocity of Jane when she reaches position B will be:
V = ✓2gh
V = ✓(2 × 9.8 × 4.3)
V = 9.18m/s
We will apply the conversation of momentum. This will be:
50 × 9.18 = (50 + 80)V1
V1 = 3.53m/s
Therefore, the height that will illustrate the distance will be:
31.36² + d² = 32²
d² = 32² - 31.36²
d = 6.36m
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How does solar weather affect Earth’s magnetosphere? Select the two correct answers.
It causes geomagnetic storms.
It generates auroras.
It develops solar wind.
It forms radiation belts.
A concave cosmetic mirror has a focal length of 40 cm . A 4.0-cm-long mascara brush is held upright 20 cm from the mirror.
a) Use ray tracing to determine the location of its image
b) What is the height of the image? Use ray tracing to determine.
The location of image and the height of the image is mathematically given as
di = -40 cm
h=8 cm
The location of image and the height of the image
upright and enlarged
Question Parameters:
Generally the equation for the is mathematically given as
using mirror equation
1/f = (1/do) + (1/di)
Therefore
1/40 = (1/20) + (1/di)
di = -40 cm
Therefore, Magnification
m = -di/do = hi/h\
m = 40/20 = hi/4
m = 2 = hi/4
image height is
hi = 4*2
h=8 cm
upright and enlarged
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An object of mass 2 kg moving with velocity of 12 m/s, collides head-on with a stationary object whose mass is 6 kg. Given that the collision is elastic, what are the final velocities of the two objects? Neglect friction.
Answer:
5. An object of mass m = 2 kg, moving with velocity Vi1 = 12 m/s, collides head-on with a stationary object whose mass is m2 = 6 kg. The velocities of the objects after the collision are vj1 -6 m/s and Vr2 = 6 m/s.
Explanation:
We can use the conservation of momentum and kinetic energy to solve for the final velocities of the two objects.
Conservation of momentum:
m1v1i + m2v2i = m1v1f + m2v2f
where m1 and v1 are the mass and velocity of object 1 before the collision, and m2 and v2 are the mass and velocity of object 2 before the collision.
Plugging in the values:
(2 kg)(12 m/s) + (6 kg)(0 m/s) = (2 kg)(v1f) + (6 kg)(v2f)
Simplifying:
24 kg m/s = 2 kg v1f + 6 kg v2f
Conservation of kinetic energy:
(1/2)m1v1i^2 + (1/2)m2v2i^2 = (1/2)m1v1f^2 + (1/2)m2v2f^2
Plugging in the values:
(1/2)(2 kg)(12 m/s)^2 + (1/2)(6 kg)(0 m/s)^2 = (1/2)(2 kg)(v1f)^2 + (1/2)(6 kg)(v2f)^2
Simplifying:
144 J = 1 kg v1f^2 + 3 kg v2f^2
Now we have two equations with two unknowns (v1f and v2f). Solving for v1f in terms of v2f in the first equation:
v1f = (24 kg m/s - 6 kg v2f)/2 kg = 12 m/s - 3v2f
Plugging this into the second equation:
144 J = 1 kg (12 m/s - 3v2f)^2 + 3 kg v2f^2
Simplifying and solving for v2f:
144 J = 1 kg (144 m^2/s^2 - 72 v2f + 9 v2f^2) + 3 kg v2f^2
144 J = 144 J - 72 kg m/s v2f + 9 kg m^2/s^2 v2f^2 + 3 kg v2f^2
6 kg v2f^2 - 72 kg m/s v2f + 144 J = 0
Dividing by 6 kg:
v2f^2 - 12 kg m/s v2f + 24 J/kg = 0
Using the quadratic formula:
v2f = [12 kg m/s ± sqrt((12 kg m/s)^2 - 4(1)(24 J/kg))]/(2)
v2f = [12 kg m/s ± sqrt(96) m/s]/2
v2f = 6 kg m/s ± 2sqrt(6) m/s
v2f ≈ 9.90 m/s or v2f ≈ 2.10 m/s
Plugging these values into the equation we found for v1f:
v1f = 12 m/s - 3v2f
v1f ≈ -16.70 m/s or v1f ≈ 38.70 m/s
Since the negative velocity doesn't make physical sense, the final velocities of the two objects are:
v1f ≈ 38.70 m/s and v2f ≈ 2.10 m/s
What force is required to stop a 1800-kg car in a distance of 0.20 m if it is initially moving at 2.2 m/s? What if the car is moving at 4.5 m/s
The formula for the force required to stop the automobile is F = m x a, where m = 1200 kg and F = 1200 x (-12.5) N = - 15000 N.
What force does an automobile need to stop?As a car brakes, the rotating wheels create friction inside the wheel assemblies, bringing the vehicle to a stop. The kinetic energy of the automobile is lost as heat in the braking components due to this friction force, which slows the spinning of the wheels.
The automobile can come to a stop with any force higher than zero. The only difference is that it will take longer and cover a bigger distance before stopping.
Unless a force acts on a body, it stays at rest or moves in a straight path at a constant speed.
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Find the required angular speed, ω, of an ultracentrifuge for the radial acceleration of a point 1.60 cm from the axis to equal 300000 g (where g is the acceleration due to gravity).
Express your answer numerically in revolutions per minute.
Answer:
Explanation:
300000(9.8) = ω²(0.0160)
ω = 13555 rad/s
13555 rad/s (60 s/min/ 2π rad/rev) = 129,445 rev/min
two resistors with resistance values 4.5 ohms and 2.3 ohms are connected in series or parallel across a potential difference of 30V to a light bulb find the current flowing through the light bulb in both cases
Answer:
Look at work
Explanation:
Series:
I is the same for all resistors so just find the value of Req. In series Req= R1+R2+...+Rn. So here it will be 4.5+2.3=6.8ohms. Ieq=Veq/Req=4.41A. And since current is the same across all resistors the current to the lightbulb is 4.41A.
Parallel:
V is the same for all resistors so start of by finding Req. In parallel, Ieq=I1+I2+...+In. So I1= 30/4.5= 6.67A and I2= 13.04A. Ieq= 6.67+13.04= 19.71A.