Number 99. A bullet is fired from the ground making an angle of 20 degwith the horizontal with a speed of 1500 m/s.How far (horizontally) will it fall? (1 point)A. O 80062.025 mB. O 147578.788 mC. O25126.105 mD. O 112231.316 mE. O 190655.097 m10. A bullet is fired from a 40 m tall building with a speed of1400 m/s making an angle of 80 deg with the horizontal.Calculate the vertical component of its velocity by the time it hitsA. O-421.75 m/sB 0-2552 599 m/s

Answer:

- 0.33 m/s

Explanation:

An illustration is shown above,

In this case, since the two objects move in opposite directions before collision, then move together, the formula to be used is,

m1u1 - m2u2 = (m1 + m2)v

Where,

m1 = mass of the first object

u1 = initial velocity of the first object

v1 = final velocity of the first object

m2 = mass of the second object

u2 = initial velocity of the second object

v2 = final velocity of the second object

Therefore,

(4.0 • 3.0) - (8.0 • 2.0) = (4.0 + 8.0)v

12 - 16 = 12v

-4 = 12v

Divide both sides by 12,

-4 / 12 = 12v / 12

-1 / 3 = v

v = -0.33 m/s

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Sound will travel fastest in air at 15°C.

The speed of sound in air, given in the range of 100 degrees Celsius and 0 degree Celsius include;

Air at 100°C 387 m/s

Air at 0°C 331 m/s

From the date above, the speed of sound in air increases with increases in temperature. Thus, Sound will travel fastest in air at 15°C.

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Answer:

Explanation:

student did an experiment using the following instructions. • Take a polythene rod (AB), hold it at its centre and rub both ends with a cloth.

Both forces are at work along the imaginary line that connects the objects. Both forces also possess proportionality constants. d) How do the strength of gravity and electric forces compare with one another

How is electric force similar to gravitational force?

Both forces are at work along the imaginary line that connects the objects. According to the inverse-square law, both forces are inversely dependent on the square root of the separation between the objects. Also, both forces have proportionality constants. The distance between the items and the relationship between electricity and gravity are inverse.

What parallels and differences exist between electrical and gravitational forces?

Each does their tasks between two others without making eye contact. However, the gravitational pull affects mass while the electric force just affects charge. Unlike electromagnetic currents, which can be both attractive and repellent, gravitational forces are only.

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Both forces are at work along the imaginary line that connects the objects. Both forces also possess proportionality constants. d) How do the strength of gravity and electric forces compare with one another

Both forces are at work along the imaginary line that connects the objects. According to the inverse-square law, both forces are inversely dependent on the square root of the separation between the objects. Also, both forces have proportionality constants. The distance between the items and the relationship between electricity and gravity are inverse.

Each does their tasks between two others without making eye contact. However, the gravitational pull affects mass while the electric force just affects charge. Unlike electromagnetic currents, which can be both attractive and repellent, gravitational forces are only.

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a.i) The work done when the body is displaced from s=0 to s = 0.4 m is 0.8 J.

(a.ii) The work done when the body is displaced from s=0 to s = 0.8 m is 1.2 J.

(b.i) The final velocity of the body when the displacement is 0.4 m is 3.46 m/s.

(b.ii) The final velocity of the body when the displacement is 0.8 m is 4 m/s.

The work done on an object is the product of force and displacement of the object.

The work done between 0 to 0.4 m is determined from the area of the triangle formed.

W = ¹/₂(0.4 m - 0 m) x ( 4 N )

W = ¹/₂(0.4 m) x ( 4 N )

W = 0.8 J

The work done from s=0 to s =0.8 m,

W = ( Area of 0 to 0.4 m) + ( Area of 0.4 m to 0.8 m)

W =  0.8 J  +   ¹/₂(0.8 m - 0.4 m) x ( 2 N )

W = 0.8J  +  ¹/₂(0.4 m) x ( 2 N )

W = 0.8J + 0.4 J

W = 1.2 J

The final velocity of the body is calculated by applying work energy principle.

change in kinetic energy of the body = work done by the body

¹/₂m(v₂² - v₁²) = W

Where;

when, s = 0.4 m, the final velocity is calculated as;

¹/₂m(v₂² - v₁²) = 0.8 J

¹/₂(0.2)(v₂² - 2²) = 0.8

0.1(v₂² - 2²) = 0.8

v₂² - 2² =  0.8 / 0.1

v₂² - 2² = 8

v₂² = 8 + 4

v₂² = 12

v₂ = √12

v₂ = 3.46 m/s

when s = 0.8 m, the final velocity is calculated as;

¹/₂(0.2)(v₂² - 2²) = 1.2 J

0.1(v₂² - 2²) = 1.2

v₂² - 2² =  1.2 / 0.1

v₂² - 2² = 12

v₂² = 12 + 4

v₂² = 16

v₂ = √16

v₂ = 4 m/s

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Answer:

The speed of the train before and after slowing down is 22.12 m/s and 11.06 m/s, respectively.

Explanation:

We can calculate the speed of the train using the Doppler equation:

\( f = f_{0}\frac{v + v_{o}}{v - v_{s}} \)        

Where:

f₀: is the emitted frequency

f: is the frequency heard by the observer  

v: is the speed of the sound = 343 m/s

\( v_{o}\): is the speed of the observer = 0 (it is heard in the town)

\( v_{s}\): is the speed of the source =?

The frequency of the train before slowing down is given by:

\( f_{b} = f_{0}\frac{v}{v - v_{s_{b}}} \)  (1)                  

Now, the frequency of the train after slowing down is:

\( f_{a} = f_{0}\frac{v}{v - v_{s_{a}}} \)   (2)  

Dividing equation (1) by (2) we have:

\( \frac{f_{b}}{f_{a}} = \frac{f_{0}\frac{v}{v - v_{s_{b}}}}{f_{0}\frac{v}{v - v_{s_{a}}}} \)

\( \frac{f_{b}}{f_{a}} = \frac{v - v_{s_{a}}}{v - v_{s_{b}}} \)   (3)  

Also, we know that the speed of the train when it is slowing down is half the initial speed so:

\( v_{s_{b}} = 2v_{s_{a}} \)     (4)

Now, by entering equation (4) into (3) we have:

\( \frac{f_{b}}{f_{a}} = \frac{v - v_{s_{a}}}{v - 2v_{s_{a}}} \)  

\( \frac{300 Hz}{290 Hz} = \frac{343 m/s - v_{s_{a}}}{343 m/s - 2v_{s_{a}}} \)

By solving the above equation for \(v_{s_{a}}\) we can find the speed of the train after slowing down:

\( v_{s_{a}} = 11.06 m/s \)

Finally, the speed of the train before slowing down is:

\( v_{s_{b}} = 11.06 m/s*2 = 22.12 m/s \)

Therefore, the speed of the train before and after slowing down is 22.12 m/s and 11.06 m/s, respectively.                        

I hope it helps you!                                                        

The stone moves at a linear speed of 9.42 m/s.

Where v stands for speed, d for distance, and t for time, the equation for linear velocity is v = d/t. The SI unit for linear velocity is the metre per second, abbreviated as m/s (ms-1).

The circumference of the circle the stone traces and the distance the stone travels in one revolution are equal.

C = 2πr

where r is the rope's length. If we substitute r = 30 cm, we obtain:

C = 2π(30 cm) ≈ 188.5 cm

As a result, one revolution of the stone moves it approximately 188.5 cm.

The stone moves a total of five times, covering the following distance:

d = 5(188.5 cm) = 942.5 cm

v = d/t

Let's say the stone makes 5 revolutions in t seconds. The linear speed is then:

v = d/t = 942.5 cm/t

To obtain the answer in milliseconds, we can convert the quantities to metres and seconds:

v = 9.425 m/t

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The focal length of the concave mirror is approximately option B. 8.20 cm,

To solve this problem, we can use the mirror equation, which relates the object distance (d_o), image distance (d_i), and the focal length (f) of a concave mirror. The equation is:

1/f = 1/d_o + 1/d_i

Given the object distance (d_o) is 12.2 cm and the image distance (d_i) is 25.0 cm, we can plug in these values to find the focal length (f):

1/f = 1/12.2 + 1/25.0

To solve for f, first find the common denominator and combine the fractions:

1/f = (25 + 12.2) / (12.2 * 25) = 37.2 / 305

Now, take the reciprocal of both sides to isolate f:

f = 305 / 37.2

After calculating, we get:

f ≈ 8.20 cm

Thus, the focal length of the concave mirror is approximately 8.20 cm, Therefore the correct option to option b.

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Answer:

This problem involves the concept of a random walk, which is a mathematical model of a path consisting of a succession of random steps.

The question asks for the distance, R(n), from the center of a star after n steps of a photon, assuming a 2D random walk.

The random walk in two dimensions has a step length of A_i and the direction of the steps is uniformly distributed in [0, 2π). The change in position after each step can be written in Cartesian coordinates (Δx, Δy), where Δx = A_i cos(θ_i) and Δy = A_i sin(θ_i).

The displacement from the center after n steps is given by the vector sum of all the individual steps. This vector sum can be written in terms of its Cartesian coordinates, (X, Y), where X = Σ Δx and Y = Σ Δy. This sum over n random vectors is itself a random variable. The net displacement R(n) from the center of the star after n steps is given by the magnitude of the net displacement vector:

R(n) = √(X² + Y²)

Because each step is independent and has a random direction, the expected value of the cosine and sine for any step is zero. This means that the expected values of X and Y are both zero.

However, the mean square displacement is not zero. Because the steps are independent, the mean square displacement in each direction is additive. For a 2D random walk:

<X²> = Σ <(Δx)²> = n <(A cos θ)²> = n A²/2

<Y²> = Σ <(Δy)²> = n <(A sin θ)²> = n A²/2

Because <X²> = <Y²>, we can write:

<R²> = <X²> + <Y²> = n A²

So, the root mean square distance (the square root of the mean square displacement) after n steps is:

R(n) = √(<R²>) = √(n) * A

Therefore, the distance R(n) that the photon is expected to be from the center of the star after n steps grows as the square root of the number of steps, with each step having a length A. Please note that this result holds for a 2D random walk. A real photon in a star would be performing a 3D random walk, which would have slightly different characteristics.

Answer:

thermal energy comes from a substance whose molecules and atoms are vibrating faster due to a rise in temperature. Kinetic energy is the energy of a moving object. As thermal energy comes from moving particles, it is a form of kinetic energy. Heat energy is another name for thermal energy.

Explanation:

i hope this helps :)

The physics behind the movement of electric charges between parallel plates is based on the principles of electrostatics. Electric charges are either positive or negative, and they are affected by electric fields.

Electric fields are created by a difference in electric potential, which is measured in volts. When a voltage is applied to a set of parallel plates, the charges within the plates will be affected by the electric field, and will move in response to it.

When a voltage is applied to a set of parallel plates, the positive charges in the plate connected to the positive voltage will be attracted to the negative voltage, while the negative charges in the plate connected to the negative voltage will be attracted to the positive voltage.

The movement of charges between the plates is also affected by the presence of any obstacles or resistances in the electric field, such as resistance in the wire. This can slow down the movement of charges and result in a decrease in the current flowing through the circuit.

In all, the movement of charges between electric parallel plates is the result of the electric field created by a difference in electric potential, and the movement of charges is called drift velocity. The movement is also affected by the presence of resistance.

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Answer:

90J

Explanation:

The only time work is being done is when he lifts the box off the ground. Therefore, using the work formula, 2 x 45, you get 90J. Hope this helps someone.

The frequency of f3 is approximately 716 Hz.

The frequency of a repeated event is its number of instances per unit of time. Hertz (Hz), which stands for the number of cycles per second, is a popular unit of measurement.

a. Given two frequencies, f1 and f2, the frequency ratio is as follows:

frequency ratio= \(\frac{f2}{f1}\)

Inputting the values provided yields:

frequency ratio = \(\frac{576}{320Hz}\) =1.8.

As a result, the difference in frequency between f1 = 320 Hz and f2 = 576 Hz is 1.8.

b. Since there are 12 half-steps in an octave and a fourth is a distance of 5 half-steps, going down a fourth requires dividing the frequency by \(2^{(4/12)}\). Hence, once a fourth is subtracted, the frequency ratio between f and f1 is:

frequency ratio= \(\frac{f}{ (f1 /f2 ) }\)=  \(\frac{f}{ (f1 / 1.3348) }\)

By dividing the numerator and denominator by 1.3348, we may make this more straightforward:

frequency ratio= (f × 1.33348)/f1

As a result, (f × 1.3348) / f1 is the frequency ratio between f and f1 after descending a fourth.

c. (c) To find the frequency of f3, we need to know the interval between f1 and f3. Let's assume that f3 is a fifth above f2. The frequency ratio for a fifth is given by: \(2^{(7/12)}\) = 1.49831

Therefore, the frequency of f3 is:

f3 = f1 × (\(2^{(7/12)}\)) × (\(2^{(7/12)}\)) = 320 Hz × 1.49831 ×1.49831 = 716 Hz

Therefore, the frequency of f3 is approximately 716 Hz.

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Answer:

Below

Explanation:

To find the acceleration of the car, we can use this formula :

     acceleration = net force / mass

     acceleration = 2070 N / 1350 kg

     acceleration = 1.53333 m/s^2

     acceleration = 1.53 m/s^2

Hope this helps!

Answer:

B. the Big Bang

Explanation:

Answer:

When the early universe cooled enough for atoms to form, Nucleosynthesis began.

hope it helps!

Answer:

6v

Explanation:

V=IR

V= 2* 3

V= 6 volts

Answer:

The period of the swing depends on only the length of the string and not on the mass of the bob and the period of the pendulum depends on only the horizontal component of g.

Explanation:

The period of the swing depends on only the length of the string and not on the mass of the bob. Since the length of the string and the mass of the bob define the pendulum.

Also, the properties that define the motion are the component of the weight of the bob in the horizontal direction which determines the to and fro movement of the bob. So, the period of the pendulum depends on only the horizontal component of g.

So, T = 2π√(l/g) where l = length of pendulum and g = acceleration due to gravity.

Answer:I need the answer pls

Explanation:

I don't have one

Answer:

The answer is D, what the cell parts are.

Explanation:

Answer: Ф = 17.2657 ≈ 17°

Explanation:

we simply apply ET =0 about the ending of the rod

so In.g.L/2sinФ - In.a.L/2cosФ = 0

g.sinФ - a.cosФ = 0

g.sinФ = a.cosФ

∴ tanФ = a/g

Ф =  tan⁻¹ a / g

Ф = tan⁻¹ ( 10 / 32.17405)

Ф = tan⁻¹ 0.31080948777

Ф = 17.2657 ≈ 17°

Therefore the angle of rotation of the rod during this acceleration is 17.2657 ≈ 17°

Nitrogen-14 is created through the beta decay of carbon-14. Beta particle emission occurs along with this kind of disintegration.

The unstable nucleus emits alpha particles during this disintegration. A helium nucleus with two protons and two neutrons makes up an alpha particle. Additionally, it bears a +2 charge.

This kind of radioactive decay results in the emission of gamma rays. The process produces a lot of energy, yet the number of protons doesn't change.

Carbon has an atomic number of 6, while nitrogen has a number of 7. Since the only way that carbon-14 and nitrogen-14 differ from one another is in their atomic number. Nitrogen-14 is created through the beta decay of carbon-14. Only beta decay allows for the conversion of carbon-14 into nitrogen-14, and the number of protons remains constant.

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Answer: Solubility; decreasing

Explanation:

In the divergence theorem, F refers to a vector field. The theorem relates a surface integral of the vector field to a volume integral of its divergence over a solid region.

The divergence theorem, also known as Gauss's theorem, relates a surface integral of a vector field to a volume integral of its divergence over a solid region. It is expressed mathematically as:

∫∫(F · dA) = ∫∫∫ (div F dV)

where F is a vector field, div F is its divergence, ∫∫ represents the surface integral over a closed surface, and ∫∫∫ represents the volume integral over the solid region enclosed by the surface. So F refers to a vector field.

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Answer:

s=0.204m

Explanation:

Assuming that the arrow is thrown horizontally and there is no air resistance, we can use the following formula to calculate the launch angle 0:

tan(0) = opposite/adjacent = height/distance

where opposite is the height that the arrow reaches and adjacent is the distance to the balloon.

Rearranging the formula, we get:

0 = arctan(height/distance)

0 = arctan(height/3)

Taking the tangent of both sides, we get:

tan(0) = tan(arctan(height/3))

tan(0) = height/3

Now, we need to find the height of the arrow. Using the kinematic equation:

v^2 = u^2 + 2as

where v is the final velocity (0m/s, at maximum height), u is the initial velocity (2m/s), a is acceleration (-9.8m/s^2, due to gravity) and s is the distance travelled vertically until the arrow reaches maximum height.

At maximum height, the final velocity is 0m/s. Therefore, we have:

0 = (2m/s)^2 + 2(-9.8m/s^2)s

Solving for s, we get:

s = 0.204m

Therefore, the height of the arrow is approximately 0.204m.

Answer:

13.6 N

Explanation:

Since one side of the wedge is vertical and the wedge makes and angle of 33 with the horizontal, the angle between the weight of the copper block on the incline and the incline is thus 90 - 33 = 57.

Let M be the mass of the block that hangs, m be the mass of the block on the incline and T be the tension in the weightless unstretchable cord.

We assume the motion is downwards in the direction of the hanging block, M.

We now write equations of motion for each block.

So

Mg - T = Ma    (1) and T - mgcos57 - F = ma where F is the frictional force on the block on the incline and a is their acceleration.

Now, since both blocks do not move, a = 0.

So, Mg - T = M(0) = 0     and T - mgcos57 - F = m(0) = 0

Mg - T = 0    (3) and T - mgcos57 - F = 0 (4)

From (3), T = Mg

Substituting T into (4), we have

T - mgcos57 - F = 0

Mg - mgcos57 - F = 0

So, Mg - mgcos57 = F  

F = Mg - mgcos57

F = (M - mcos57)g

Since g = acceleration due to gravity = 9.8 m/s², and M = 2.94 kg and m = 2.85 kg.

We find F, thus

F = (2.94 kg - 2.85 kgcos57)9.8 m/s²

F = (2.94 kg - 2.85 kg × 0.5446)9.8 m/s²

F = (2.94 kg - 1.552 kg)9.8 m/s²

F = (1.388 kg)9.8 m/s²

F = 13.6024 kgm/s²

F ≅ 13.6 N

The hill on which the ball roll down with increasing speed and decreasing acceleration is the middle hill in the diagram.

Your question is not complete, it seems to be missing the diagram I added.

Velocity is the change in displacement per change in time.

Acceleration is the change in velocity per change in time of motion.

In the given diagram;

Thus, the hill on which the ball roll down with increasing speed and decreasing acceleration is the middle hill in the diagram.

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3,000 x 1,000 x 3,000 =

FMultiply the whole numbers:

The boy throws the ball horizontally. The initial velocity of the ball as it left the boy's hand was approximately 3.72 m/s.

Initial velocity, often represented as v0, is the velocity of an object at the beginning of a time interval or at the start of a motion.

Use the following kinematic equations to arrive at the answer:

Horizontal velocity (Vx) = Distance / Time

Vertical displacement (y) = V0y*t + (1/2)gt²

Vertical velocity (Vy) = V0y + g*t

Tan(theta) = Vy / Vx

where V0y is the initial vertical velocity, g is acceleration due to gravity (9.8 m/s²), and theta is the angle of inclination.

First, let's find the time it takes for the ball to hit the ground. We can use the vertical displacement equation and set y = 0:

0 = V0y*t + (1/2)gt²

Simplifying and solving for t, we get:

t = sqrt((2y) / g)

= sqrt((21.10 m) / 9.8 m/s²)

= 0.472 s

Now, we can use the horizontal velocity equation to find Vx. Since the ball was thrown horizontally, Vx is the same as the initial velocity (V0):

Vx = Distance / Time

= (horizontal distance travelled by ball) / t

We don't know the horizontal distance travelled by the ball, but we can find it using the vertical displacement equation. At the instant the ball hits the ground, its vertical displacement (y) is:

y = V0y*t + (1/2)gt²

= 0 + (1/2)gt²

= (1/2)*9.8 m/s² * (0.472 s)²

= 1.10 m

This means the ball travelled a total distance of:

distance = horizontal distance + vertical distance

= x + 1.10 m

where x is the horizontal distance travelled by the ball. We can find x using the angle of inclination and the vertical displacement:

Tan(theta) = Vy / Vx

Vy = V0y + g*t

Solving for V0y, we get:

V0y = Vy - g*t

Plugging in the numbers, we get:

V0y = Tan(theta) * Vx - g*t

= Tan(30 deg) * Vx - 9.8 m/s² * 0.472 s

= 0.577 * Vx - 4.62 m/s

Now, we can use the vertical displacement equation again to find x:

y = V0yt + (1/2)gt²

= (0.577Vx - 4.62 m/s) * 0.472 s + (1/2)*9.8 m/s² * (0.472 s)²

= 1.10 m

Simplifying and solving for Vx, we get:

Vx = (2y - 0.577V0t) / t

= (21.10 m - 0.577*(0.577*Vx - 4.62 m/s)*0.472 s) / 0.472 s

= 3.72 m/s

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Answer:

The answer is flint glass.