OBSERVATION: A shiny red rock is sitting at the bottom of a swimming pool. You grab a long stick and poke it into the pool aiming for the rock, but the stick overshot the rock by a lot. ANSWER GUIDE: Use concepts from L3 and L4 to explain two aspects of this observation: (1) Why was the rock in a different position than you thought it was? (2) Why does the rock appear red? What happened to the other colors in the white sunlight?
Answers
(1) The rock came to be in a various position than you thought it was by way of the wonder of refraction. The rock's position seemed different due to light refraction as it travels at varying speeds through different mediums.
2. Rock looks red as it absorbs all colors of sunlight except red.
2b. When white light enters water, it refracts and splits into various colors.
What is the concepts about?This causes the object to perform at a different position than it literally is. In this case, the light indications coming from the rock were bent when they entered the water, making the rock to appear at a more ignorant wisdom than it actually was.
Therefore, in response to question 2, rock appears red by way of the selective assimilation and reflection of light. The rock absorbs all of the banner of silvery light except for flaming, which is mirrored back to our eyes. This is because the microscopic structure of the rock absorbs all the banner except that red, that is reflected back.
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Related Questions
Imagine that you wanted to test the effects of driving at different speeds on the gas mileage of your car. To find out, you drove a distance of 100 miles at many different rates of speed. During your first trip, you drove at exactly 55 miles per hour and calculated that your gas mileage was 20 miles per gallon. During your next trips, you either decreased or increased your rate of speed. Also, what can you conclude from this experiment? How might your car get better gas?
Answers
The conclusion that you might arrive at is that the speed of the car affects the gas mileage.
What could you conclude from the experiment?We know that an experiment is the only way that we can be able to establish cause and effect relationship. We know that the speed would affect the consumption of the gas. By varying the speed of the car, we can be able to obtain the effect that it has on the mileage.
Thus, the conclusion that you might arrive at is that the speed of the car affects the gas mileage.
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High tide from Moon's pull on
oceans
High tide from Moon's pull on
solid ground
Low tide ahead of Moon's
orbit
Low tide behind Moon's orbit
3
TE
Label the diagram with descriptions of the tides at each location.
Sign out
ES
Feb 2
8:
PLEASE HURRY
Answers
I'm sorry but I don't know
High tide from Moon's pull on oceans
Low tide ahead of Moon's orbit
High tide from Moon's pull on solid ground
Low tide behind Moon's orbit
The index of refraction of crown glass is 1.515 for red light and 1.523 for blue light. Find the angle separating rays of the two colors in a piece of crown glass if their angle of incidence is 42o .
Answers
Given:
The angle of incidence is,
\(i=42\degree\)The refractive index of the crown glass for red light is,
\(n_r=1.515\)The refractive index of the crown glass for blue light is,
\(n_b=1.523\)To find:
The angle separating rays of the two colours in a piece of crown glass
Explanation:
We know, Snell's law,
\(n_1sini=n_2sinr\)For, the red light,
\(\begin{gathered} 1\times sin42\degree=1.515sinr_r \\ sinr_r=\frac{sin42\degree}{1.515} \\ r_r=sin^{-1}(0.4417) \\ r_r=26.2\degree \end{gathered}\)For, the blue light,
\(\begin{gathered} 1\times sin42\degree=1.523sinr_b \\ r_b=sin^{-1}\frac{sin42\degree}{1.523} \\ r_b=26.1\degree \end{gathered}\)The separation between the refracted rays is,
\(\begin{gathered} r_r-r_b=26.2\degree-26.1\degree \\ =0.1\degree \end{gathered}\)Hence, the required separation is 0.1 degrees.
function Of The glottis
Answers
Answer:
Their function is to produce sound by allowing the free edges of the folds to vibrate against one another and also to act as the laryngeal sphincter when they are closed.
The glottis is found within the larynx, and the epiglottis is a flap-like structure on top of the trachea. When swallowing, it will press downward to partially close off the trachea. Function of the glottis and epiglottis do to help prevent food and liquid from entering the air passage (trachea)
Can I please get brainliest
a. What is the smallest value of A
for which there are two stable nuclei? What are they?
b. For which values of A
less than this are there no stable nuclei?
(a) The smallest value of A
for which there are two stable nuclei is =
.
(b) The value of A
less than this no stable nuclei is = .
Answers
(a) The smallest value of A for which there are two stable nuclei is 2.
(b) For values of A less than 2, there are no stable nuclei.
(a) The smallest value of A for which there are two stable nuclei is 2. In nuclear physics, the stability of a nucleus is determined by the balance between the attractive strong nuclear force and the repulsive electromagnetic force between protons. For a stable nucleus, this balance is achieved when the number of protons (Z) and the number of neutrons (N) satisfy certain combinations.
The lightest stable nucleus is hydrogen-1, consisting of a single proton. When we consider the next stable nucleus, helium-2, it contains two protons and zero neutrons. This gives a total atomic mass number of A = Z + N = 2.
(b) For values of A less than 2, there are no stable nuclei. This is because stability requires a sufficient number of nucleons (protons and neutrons) to overcome the electrostatic repulsion between protons. In the case of hydrogen-1 (A = 1), it is stable with one proton. However, a nucleus with zero protons and zero neutrons does not exist.
It is important to note that stable nuclei exist across a range of atomic mass numbers (A) beyond helium-2. The specific combinations of protons and neutrons that form stable nuclei become more complex as A increases, with the stability determined by the interplay of nuclear forces and quantum mechanical effects.
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2. Write the equation that represents the relationship between the force, F, applied to the spring and its change in length, x.
3. Write a statement that describes the relationship between the force you applied to the spring and the extent to which it was compressed (stretched).
6. Now write the general equation describing the relationship between the applied force and the change in the length of the spring.
7. Conduct the above analysis for the second hoop.
Answers
The equation that represents the relationship between the force, F, applied to the spring and its change in length, x, is F = kx, where k is the spring constant.
The relationship between the force applied to the spring and the extent to which it was compressed (stretched) is directly proportional. This means that as the force applied to the spring increases, the extent to which it is compressed (stretched) also increases.
The general equation describing the relationship between the applied force and the change in the length of the spring is F = kx, where F is the force applied, k is the spring constant, and x is the change in length.
For the second hoop, the same analysis can be conducted. The equation that represents the relationship between the force, F, applied to the spring and its change in length, x, is F = kx, where k is the spring constant. The relationship between the force applied to the spring and the extent to which it was compressed (stretched) is directly proportional. The general equation describing the relationship between the applied force and the change in the length of the spring is F = kx.
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A space ship, initially traveling at a speed of 1,265 m/s, begins to accelerate at a rate of 16
m/s/s. Find the speed of the space ship after it accelerates for 41 s ?
Answers
Answer:
I Think the answer is 1380
Explanation:
Answer: press the link
Explanation:
The two types of biogenous sediments are calcareous ooze and _____ ooze.
Answers
Answer:
The two types of biogenous sediments are calcareous ooze and siliceous ooze
Explanation:
how long will it take you to travel 20 miles on a bus that drives 60 miles/h?
Answers
Answer:
20 Minutes
Explanation:
Well we know Mph (Miles per hour) is distance over time : \(\frac{distance}{time} \\\)
R (rate) = 60
d (distance) = 20
t (time) = Unknown
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
R = \(\frac{d}{t} \)
↓
60 = \(\frac{20}{t}\)
↓
t = \(\frac{20}{60} \)
↓
t = \(\frac{1}{3} \) or 0.3333
So basically it would take one third of an hour. Lets change these units to minutes.
60 * 0.333333 = 20
So it would take you 20 minutes to drive 20 miles on a bus that drives 60 mph
Hope that helps
~Siascon~
A wire of radius RR has a current density that increases linearly with distance from the center of the wire: J(r)=krJ(r)=kr, where kk is a constant. Find an expression for kk in terms of RR and the total current II carried by the wire.
Answers
The expression for kk in terms of RR and II is: k = I/πR^2. We can start by finding the total current II carried by the wire.
Since the current density J(r) increases linearly with distance, we can express it as the gradient of a linear function: J(r) = k r => dJ/dr = k
Integrating both sides with respect to r, we get: J(r) = kr + C
where C is an integration constant. Since J(0) = 0 (the current density at the center of the wire is zero), we have: 0 = k(0) + C => C = 0
Thus, the current density at any point is given by: J(r) = kr
The current II carried by the wire can be found by integrating the current density over the cross-sectional area of the wire: I = ∫ J(r) dA
Since the current density is radial, we can express the differential area element dA as 2πr dr, where r is the radial distance from the center of the wire. Thus, we have:
I = ∫ J(r) dA = ∫_0^R J(r) 2πr dr
Substituting J(r) = kr, we get:
I = ∫_0^R kr 2πr dr = πkR^2
Solving for k, we get:
k = I/πR^2
Therefore, the expression for kk in terms of RR and II is:
k = I/πR^2
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If a tsunami is travelling at 970 km/h with a wavelength of 450 km, what is the frequency of the wave
Answers
Answer:
Frequency of wave = 2.16 Hz (Approx)
Explanation:
Given:
Speed of tsunami = 970 km/h
Wavelength = 450 km
Find:
Frequency of wave
Computation:
Frequency = Speed / Wavelength
Frequency of wave = Speed of tsunami / Wavelength
Frequency of wave = 970 / 450
Frequency of wave = 2.16 Hz (Approx)
Last Thursday, I went for a walk through my neighborhood. I started at my house. My smart watch told me that I walked a total of 3.5 miles. I started my walk at 5 pm and ended at 8 pm. At the end of my walk, I was 50 meters north of my house visiting a neighbor. I wanted to find my average velocity on the trip. My distance walked was 3.5 miles. My time was 3 hours. To find velocity, I used my calculator to find 3.5 miles divided by 3 hours which equaled 1.16 miles per hour. Did I accurately calculate my velocity? If not, what did I do wrong and what was my correct velocity?
Answers
Answer:
Yes, that is correct, although most velocity is calculated via m/s and therfore you would multiply your 3 hours by 60 twice. Much of the information given is irrelevant and just trying to confuse.
Explanation:
A car accelerates by 4 m/s^2 and travels for 2.5 mins with an initial velocity of 20m/s. Find the final velocity.
Answers
Answer:
540m/s
Explanation:
v= u + at
u change t to seconds
A wave along a guitar string has a frequency of 540 Hz and a wavelength of 2.5 meters. Calculate the speed of the wave. Show your
work.
Answers
Answer: 1350 m/s
Explanation:
The equation for the speed of a wave: Speed = Wavelength x Frequency
Which of the following statements does NOT describe force?
A.Force causes objects to change direction.
B.Force causes objects to start moving.
C.Force causes objects to stop moving.
D.Force causes objects at rest to remain stationary.
Answers
Answer: D
Explanation: Force can do everything else.
Answer:
D. Force causes objects at rest to remain stationary.
Explanation:
how much energy is required to heat 600g of iron (c+0.41J/g Celsius) from a starting temperature of 25 Celsius to 60 Celsius
Answers
The amount of energy required to heat 600 g of iron from 25°C to 60°C is 8.61 kJ.
The amount of energy required to heat 600 g of iron from 25°C to 60°C can be calculated using the formula:
Q = mcΔT
where Q is the amount of energy (in joules), m is the mass of the iron (in grams), c is the specific heat of iron (in J/g°C), and ΔT is the change in temperature (in °C).
Substituting the given values, we get:
Q = (600 g)(0.41 J/g°C)(60°C - 25°C)
Q = (600 g)(0.41 J/g°C)(35°C)
Q = 8610 J or 8.61 kJ (to three significant figures)
As a result, the amount of energy necessary to heat 600 g of iron from 25°C to 60°C is 8.61 kJ.
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b. Two vectors with dimensions A = 5i + 3j + k and B = 4i + j + 2k are used for the following calculation. Determine: i. ii. iv. The dot product A.B. [2 marks] [3 Marks] The angle between vectors A and B. The cross product A XB. [2 marks] The area of the parallelogram spanned by the vectors A and B. [3 Marks]
Answers
The dot product is 25, the angle is \(\theta = cos^{-1} \frac{25}{\sqrt{35} \times \sqrt{21}}\), the cross product is 1i + (-6)j + (-7)k, and the area of the parallelogram spanned by vectors A and B is \(\sqrt{86}\).
Given,
A = 5i + 3j + k
B = 4i + j + 2k
i. Dot Product (A · B):
The dot product of two vectors A and B is given by the sum of the products of their corresponding components.
\(A.B = (A_x \times B_x) + (A_y \times B_y) + (A_z \times B_z)\\A.B = (5 \times 4) + (3 \times 1) + (1 \times 2) \\= 20 + 3 + 2 \\= 25\)
ii. Angle between vectors A and B:
The angle between two vectors A and B can be calculated using the dot product and the magnitudes of the vectors.
\(cos\theta = (A.B) / (|A| \times |B|)\\\theta = \frac{1}{cos} ((A.B) / (|A| \times |B|))\\A = \sqrt{(5^2 + 3^2 + 1^2)} =\\ \sqrt{35}\\B = \sqrt{(4^2 + 1^2 + 2^2)} \\= \sqrt{21}cos\theta = \frac{(A.B) / (|A| \times |B|)\\\theta = \frac{1}{cos} \frac{25}{\sqrt{35} \times \sqrt{21}}}\)
iv. Cross Product (A × B):
The cross product of two vectors A and B is a vector that is perpendicular to both A and B and its magnitude is equal to the area of the parallelogram spanned by A and B.
\(A\times B = (A_y \timesB_z - A_z \timesB_y)i + (A_z \timesB_x - A_x \timesB_z)j + (A_x \times B_y - A_y \times B_x)k\\A\times B = ((3 \times 2) - (1 \times 1))i + ((1 \times 4) - (5 \times 2))j + ((5 \times 1) - (3 \times 4))k\\= 1i + (-6)j + (-7)k\)
Area of the parallelogram spanned by vectors A and B:
The magnitude of the cross product A × B gives us the area of the parallelogram spanned by A and B.
Area = |A × B|
Area of the parallelogram spanned by vectors A and B:
Area = |A × B| =
\(\sqrt{(1^2 + (-6)^2 + (-7)^2}\\\sqrt{1+36+49\\\\\sqrt{86}\)
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Physical Science
Draw the net force arrow on the picture to the left.
Calculate the net force and state the direction.
Net force = _
Net force direction = _
Answers
Answer:
Net force is 0 (zero)
Net force direction is 0 (zero)
Explanation:
water is a successful analogy in describing the nature of the trinity. true,or faks
Answers
The water analogy can be considered a useful but imperfect tool for describing the nature of the Trinity. It is true that water can exist in three different states - solid (ice), liquid (water), and gas (steam) - which can help us grasp the concept of three distinct yet interconnected entities within the Trinity (Father, Son, and Holy Spirit). However, this analogy has limitations, as it does not fully convey the complexity and uniqueness of the Trinity.
The water analogy might imply modalism, the belief that God takes on different "modes" or forms at different times, which is not an accurate representation of the Trinity. In Christianity, the Father, Son, and Holy Spirit are believed to be distinct persons that exist simultaneously, not merely different states or forms of a single being.
Additionally, the analogy could be misunderstood as suggesting that the three persons of the Trinity are divisible, just like the three states of water. However, the persons of the Trinity are indivisible, sharing the same divine essence.
In conclusion, while the water analogy may be helpful in understanding the concept of the Trinity to some extent, it is important to recognize its limitations and not to rely on it as a complete explanation for this complex theological concept.
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The decomposition of H2O2 is a first-order reaction given by the formula: Rate = k [H2O2]1. How would the reaction rate be affected if the H2O2 concentration were double its original value?
Answers
Answer: The decomposition of H₂O₂ is a first-order reaction. Then, the reaction rate will be 2 times the original rate, if we double its concentration value.
Explanation: To find the answer, we need to know about the decomposition of H₂O₂.
What is the rate of reaction, if we double the concentration of H₂O₂?We have the equation of decomposition of H₂O₂ as,2H₂O₂→ 2 H₂O+ O₂
We have given that, the equation of reaction rate of the first order reaction as,Rate = k [H₂O₂]1
As we know that the equation of reaction rate is,Rate = rate constant × concentration of [H₂O₂]
Thus, by comparing both the equations, we get,rate constant=k and the concentration of [H₂O₂] = 1[H₂O₂].
Given that the concentration is doubled. Then the expression for rate will be,Rate = 2k [H₂O₂].
Thus, we can conclude that the rate of reaction will be 2 times the initial rate if we double the concentration.
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If we double the concentration value, the reaction rate will be twice as fast as before.
In order to determine the solution, we must understand how H2O2 breaks down.
If we double the concentration of H2O2, what will happen to the reaction rate?The formula for the breakdown of H2O2 is,2H₂O₂→ 2 H₂O+ O₂
We have provided the first order reaction's reaction rate equation as,Rate = [H2O2] k
As we are aware, the reaction rate equation isRate = rate constant × [H2O2] concentration
As a result, by comparing the two equations, we obtain, rate constant is k, and the [H2O2] concentration is 1 [H2O2].The concentration has doubled as a result. Afterward, the rate expression will be,Rate = [H2O2] 2k.
As a result, we can infer that doubling the concentration will cause the reaction rate to double.
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Compare the momentum of a 7160 kg truck moving at 5.00 m/s to the
momentum of a 2240 kg car moving at 15.0 m/s.
Answers
Answer:
2,200
Explanation:
truck=35800,car=33600
A 0.20-kg yo-yo is attached to a string and swung in a circle of radius 0.90 m on a horizontal and frictionless surface. If the yo-yo makes 90 revolutions per minute, the tension force of the string on the yo-yo is a. 16 N b. 3.7 N c. 51 N d. 0.40 N e. 0.020 N
Answers
The tension force of the string on the yo-yo is (b) 3.7 N.
The body of the yo-yo has a string that is connected to it, allowing it to be lowered and raised while rolling on its surface. To determine the tension force on the yo-yo, we can use the formula for tension force (T) :
T = mv² / r
Where
m = mass of the yo-yo
v = velocity of the yo-yo
r = radius of the circle on which the yo-yo is moving.
The number of revolutions per minute of the yo-yo is given to be 90 revolutions per minute, which means it will make 1.5 revolutions per second.
In the given problem, we have:
m = 0.20 kg
v = 2πr/T = (2 x 3.14 x 0.90) / (90 / 60) = 3.77 mr = 0.90 m
Now substituting the values of m, v, and r into the formula, we get:
T = mv² / r = 0.20 x (3.77)² / 0.90= 3.71 N
Therefore, the string of the yo-yo has a tension force of 3.7 N. Thus, the correct option is (b).
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what is the dvd's moment of inertia for rotation about a perpendicular axis through the edge of the disk?
Answers
The DVD's moment of inertia for rotation about a perpendicular axis through the edge of the disk is
\(I = \frac{3}{2}MR^{2}\)
Where, M = the mass of the disk and
R = the radius of the disk.
The parallel axis theorem connects a shape's moment of inertia about a parallel centroidal axis to its moment of inertia about any other axis.
This theorem is particularly helpful since it allows us to compute a shape's moment of inertia around any parallel axis by adding the appropriate correction factor to our knowledge of the shape's centroidal moment of inertia. Alternatively, by deducting the same factor from the moment of inertia about an axis, we can determine the related centroidal moment of inertia.
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A periodic composite signal with a bandwidth of 2000 Hz is composed of two sine waves. The first one has a frequency of 100 Hz with maximum amplitude of 20 V; the second one has maximum amplitude of 5 V. Draw the frequency domain graph.
Answers
The frequency domain graph of the periodic composite signal consists of two peaks, one at 100 Hz with an amplitude of 20 V and another at an unknown frequency with an amplitude of 5 V.
In the frequency domain, the composite signal can be represented by a graph showing the amplitude of each frequency component present in the signal. In this case, the signal is composed of two sine waves. The first sine wave has a frequency of 100 Hz and a maximum amplitude of 20 V. This means that in the frequency domain graph, there will be a peak at 100 Hz with an amplitude of 20 V.
The second sine wave's frequency is not given, but we know that it has a maximum amplitude of 5 V. Therefore, there will be another peak in the frequency domain graph at an unknown frequency with an amplitude of 5 V.
Since the bandwidth of the composite signal is 2000 Hz, the frequency domain graph will span a range of frequencies from 0 Hz to 2000 Hz. Apart from the two peaks mentioned above, there will be no other significant frequency components in the graph.
To summarize, the frequency domain graph of the periodic composite signal will have two peaks—one at 100 Hz with an amplitude of 20 V, and another at an unknown frequency with an amplitude of 5 V.
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A weight lifter benches a bar a vertical distance of 1.5m. What is the work done on the weights if the lifter exerts a constant force of 1000N?
Answers
Answer: 1500 Joules
Explanation: To calculate the work done by the weight lifter, we can use the formula:
Work = Force x Distance x cos(theta)
where "Force" is the force applied by the weight lifter, "Distance" is the vertical distance that the weight is lifted, and "theta" is the angle between the direction of the force and the direction of the displacement.
In this case, the force applied by the weight lifter is 1000N and the vertical distance lifted is 1.5m. Since the force is applied vertically upwards and the displacement is also vertical, the angle between the direction of the force and the direction of the displacement is 0 degrees (cos(0) = 1).
Therefore, the work done by the weight lifter is:
Work = 1000N x 1.5m x cos(0) = 1500 Joules
So the work done by the weight lifter on the weights is 1500 Joules.
Mercury’s natural state is where the atoms are close to each other but are still free to pass by each other. In which state(s) could mercury naturally exist?
Answers
Answer:
Mercury's natural state is where the atoms are close to each other but are still free to pass by each other. In which state(s) could mercury naturally exist?
Liquid is the answer
Explanation:
two tiny metal spheres are fixed to the ends of a non-conducting string of length . equal charges, q, are placed on the metal spheres. randall says that the force on the string has magnitude . tilden says that the tension in the string has magnitude . which one, if either, is correct?
Answers
Randall is correct in stating that the force on the string has a magnitude equal to the product of the charges, q, divided by the square of the length of the string, L.
This is described by Coulomb's Law, which relates the force between two charged objects to the product of their charges and the inverse square of the distance between them. On the other hand, Tilden's statement about the tension in the string being equal to the product of the charges is incorrect.
Tension in the string is not directly related to the charges but is instead a result of the forces exerted by the charged spheres on the string itself.
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A graph titled Position versus Time shows time in seconds on the x axis, numbered 0 to 5, and position in meters on the y axis, numbered 0 to 15. The graph is a straight line from the (0, 3) to (4, 15).
Based on the information presented in the graph, what is the velocity of the object?
Answers
Answer:
3 m/s
Explanation:
distance (rise) over time (run) gives speed, that is velocity
it can be found using the gradient (m) formula
m=(y2-y1)/(x2-x1)
m=(15-3)/(4-0) =12/4=3 m/s
Answer:
3 m/s
Explanation:
.....as the answer for your question is 3m/s ..
THANK YOU..
Paul wants to jump his car over 45 barrels. Each barrel is 1m wide. If he takes off horizonally from a ramp that is 5.5 m higher than where he will land, how
fast does he need to drive to clear the barrels?
Paul needs to go
mis to clear the barrels ( Give answe to the hundreths place)
Answers
Answer:
h = -5.5 = 1/2 g t^2 distance he will fall in time t
t = (11 / 9.8)^1/2 using 9.80 m/s^2 for g
t = 1.06 sec
So Vx = 45 m / 1.06 s = 42.47 m/s
Claire starts driving with an initial velocity of 5.0 m/s towards north. She drives along a straight, level path with a uniform acceleration and travels 500. M in 20. Seconds. A. What is the average velocity for the entire 20. Seconds? B. What is the velocity at the end of 20. Seconds?
Answers
Answer:
A. 25 m/s
B. 100 m/s (i'm not sure about this one)
Explanation:
A. To find average velocity: velocity = distance / time
So it would be V = 500 m / 20 sec = 25 m/s
*This equation can only be used if you are finding velocity for a constant speed or direction or specific distance (in this case it was specific distance).
B. final velocity = initial velocity + acceleration * time
Initial velocity (5.0 m/s) and time (20 sec) is given but not acceleration.
To find acceleration: a = (final velocity - initial velocity) / time
To find final velocity = 5.0 + a * 20
Since there's a missing variable for both equation we will plug the final velocity equation into the acceleration equation so it looks like this :
a = ((5.0 + a * 2.0) - 5.0) / 20
Now solve to get a (acceleration)
Acceleration ends up being 0. So now that we know acceleration we can solve for the final velocity.
final velocity = 5.0 + 0 * 20
= 100 m/s
I know it's a lot but I hope that makes sense! Also for B. I'm not sure if it's right at all but if later I figure out it's wrong I'll edit my answer.