One reaction that produces acid rain is:3 NO2 + H2O -> NO + 2HNO3When 60 grams of water reacts with NO2, 300 grams of HNO3 is produced, what is the percent yield?

Gallium is the element that belongs to the group 3 and the fourth period. Ga is symbol of Gallium.

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1) Diesel has a higher viscosity than petrol.

2) Petrol is more flammable than diesel.

3) The formula will be C₁₀H₂₂.

4) The equation is; 2C8H18+25O2→16CO2+18H2O.

Depending on the precise composition and temperature, the viscosity of gasoline and diesel can change. In general, diesel is more viscous than gasoline. Higher viscosity fluids are thicker and flow more slowly than lower viscosity fluids because viscosity relates to the resistance of a fluid to flow.

Diesel is less flammable than gasoline. The lowest temperature at which gasoline can evaporate and turn into an ignitable combination in air is known as its flash point, and it is lower for gasoline. Compared to diesel fuel, petrol vapors are much more flammable and can ignite at lower temperatures.

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The two statements that are true about the reaction are:

A catalyst is described as  a substance that speeds up a chemical reaction, or lowers the temperature or pressure needed to start one, without itself being consumed during the reaction.

If we happen to increase the temperature, it provides more kinetic energy to the reactant molecules and this makes it  more likely to overcome the activation energy barrier and engage in the reaction.

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Answer:

Are produced by division of another cell.

Contain cytoplasm.

Are the smallest unit of living matter.

Contain DNA.

Explanation:

Living cells are classed as either prokaryotic or eukaryotic. Which of the following characteristic(s) identify both cell types, eukaryotic cells and prokaryotic cells?

Answer:

1. evaporation

2.distilation

Answer:

changes like leaves turning color in the fall are chemical changes. They involve chemical reactions. Bonds break in chemicals and new bonds form. Substances change into new chemical compounds.

Explanation:

The properties of a natural resource that make it useful for humans as a material or energy source is the ability to convert mass into energy and vice versa.

The expression natural resources make reference to all types of matter and energy extracted from nature that can be used to produce goods and services.

Some examples of natural resources include for example irreversible resources such as fossil fuels (i.e., oil, or coal, gas, minerals such as metals, rocks, etc) as well as those based on the use of reversible energy such as eolic air energy, solar radiation or sunlight, soil and hydric resources or water.

Therefore, with this data, we can see that natural resources can be defined as any material and or energy obtained from nature that may be irreversible or reversibly used to produce goods and services.

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Answer:

Vanadium in given compound is metal and oxygen is non-metal so, the given compound is a binary ionic compound.

Answer:

Explanation:

Se denomina espectro electromagnético a la distribución energética del conjunto de las ondas electromagnéticas. Referido a un objeto se denomina espectro electromagnético o simplemente espectro a la radiación electromagnética que emite (espectro de emisión) o absorbe (espectro de absorción) una sustancia. Dicha radiación sirve para identificar la sustancia de manera análoga a una huella dactilar. Los espectros se pueden observar mediante espectroscopios que, además de permitir ver el espectro, permiten realizar medidas sobre el mismo, como son la longitud de onda, la frecuencia y la intensidad de la radiación.

Diagrama del espectro electromagnético, mostrando el tipo, longitud de onda con ejemplos, frecuencia y temperatura de emisión de cuerpo negro.

El espectro electromagnético se extiende desde la radiación de menor longitud de onda, como los rayos gamma y los rayos X, pasando por la radiación ultravioleta, la luz visible y la radiación infrarroja, hasta las ondas electromagnéticas de mayor longitud de onda, como son las ondas de radio. Si bien el límite para la longitud de onda más pequeña posible no sería la longitud de Planck (porque el tiempo característico de cada modalidad de interacción es unas 1020 veces mayor al instante de Planck y, en la presente etapa cosmológica, ninguna de ellas podría oscilar con la frecuencia necesaria para alcanzar aquella longitud de onda), se cree que el límite máximo sería el tamaño del Universo (véase Cosmología física) aunque formalmente el espectro electromagnético es infinito y continuo.

The radioactive element plutonium  undergo radioactive bombardment producing stable isotope curium. The balanced nuclear reaction is written below:

\(_{94}^{239}\textrm{Pu} + _{2}^{4}\textrm{He}\rightarrow _{96}^{241}\textrm{Cm} + 2_{0}^{1}\textrm{n}\)

Atomic nucleus undergoes reaction with charged particles producing either its isotope or a new atom. Heavy unstable atoms such as actinides undergo radioactive decay by emitting or bombarding charged species such as alpha particles to form stable species.

Plutonium is 94th element in periodic table. It is used as nuclear fuel because it releases energy during nuclear reactions. Bombardment of an alpha particle produces a curium (Z = 96, A =241) with two neutrons as side products.

Therefore the balanced nuclear reaction of Pu-239 to produce Cm-241 is written as below:

\(_{94}^{239}\textrm{Pu} + _{2}^{4}\textrm{He}\rightarrow _{96}^{241}\textrm{Cm} + 2_{0}^{1}\textrm{n}\)

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1) The pressure is 26.4 torr

2) The time is 24.4 s

A decomposition reaction is a type of chemical reaction in which a single compound breaks down into two or more simpler substances. In other words, it is the opposite of a synthesis reaction, where two or more substances combine to form a more complex substance.

We know that;

\(lnPt =lnPo - kt\\lnPt = ln(450) - ( 4.5 x 10^-2 * 63)\\Pt = eln(450) - ( 4.5 x 10^-2 * 63)\\Pt = 26.4 torrln[1/3(450)] = ln 450 - (4.5 x 10^-2t)\\5 = 6.1 - 0.045t\\5 - 6.1 = - 0.045t\\t = 24.4 s\)

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A chemical reaction that requires an input of energy in order to proceed is termed Endothermic, whereas one that releases energy is called Exothermic.

The endothermic process is a word used to describe a reaction in which the system takes up heat from its environment. Photosynthesis, evaporating liquids, melting ice, dry ice, alkane cracking, thermal decomposition, ammonium chloride in water, and many more processes are examples of endothermic processes. A reaction that is exothermic is the opposite of one that is endothermic. It emits energy onto its surroundings as heat or light. Examples include neutralization, burning a chemical, fuel reactions, dry ice deposition, respiration, sulphuric acid solution in water, and many more.

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Answer:

35.36 g

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

8Fe + S₈ —> 8FeS

Next, we shall determine the mass of Fe that reacted and the mass of FeS produced from the balanced equation. This can be obtained as follow:

Molar mass of Fe = 56 g/mol

Mass of Fe from the balanced equation = 8 × 56 = 448 g

Molar mass of FeS = 56 + 32 = 88 g/mol

Mass of FeS from the balanced equation = 8 × 88 = 704 g

SUMMARY:

From the balanced equation above,

448 g of Fe reacted to produce 704 g of FeS.

Finally, we shall determine the theoretical yield of FeS as follow:

From the balanced equation above,

448 g of Fe reacted to produce 704 g of FeS.

Therefore, 22.5 g of Fe will react to produce = (22.5 × 704)/448 = 35.36 g of FeS.

Thus, the theoretical yield of FeS is 35.36 g

2.5  A° is  wave length associated with an electron travelling a 40% velocity of light​.

40% velocity of light​=40/100×3×10^8

40% velocity of light=1.2×10^8 m/s

\(\lambda=c/v\)

\(\lambda\)=3×10^8/1.2×10^8 m/s=2.5 A°

Since the relationship between wave frequency and wavelength is inverse, gamma rays have extremely tiny wavelengths that are only a small portion of the size of atoms, whereas other wavelengths can extend as far as the universe. No of the medium they are passing through, electromagnetic radiation's wavelengths are typically expressed in terms of the vacuum wavelength, but this isn't always stated explicitly.

The wavelength of electromagnetic radiation affects how it behaves. Speed of light = wavelength x frequency Energy = Planck's constant x frequency Wave number = 1/wavelength in cm. The wavelengths of different parts of the electromagnetic spectrum are displayed together with a rough approximation of the wavelength size.

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Answer:

61.9 g C3H8

Explanation:

First write and balance equation

C3H8 + 5O2 -> 3CO2 + 4H2O

Next find the limiting reactant

25.0g propane/ 44.097 g propane = 0.567 mol propane

(75.0gO2)(1mol C3H8)/ (32g)(5mol O2)= 0.468 mol propane

Since O2 is the limiting reactant now we can find the mass of CO2

(75.0g O2)(1 mol O2)( 3 mol CO2)(44.01 g CO2)/(32g O2)(5 mol O2)( 1 mol CO2) =61.9g CO2

Answer:

Nutrients arw compounds in foods essential to life and heath

Answer: In simple terms nutrients are the energy that you get from food certain foods give more nutrients and others give close to none. That is what nutrients in your food is

Explanation:

Answer:

Explanation:

The number of atoms that remains after 3 half-lives given that it was originally 300000 atoms is 37500 atoms

Data obtained from the question

Original amount (N₀) = 300000 atoms

Number of half-lives (n) = 3

Amount remaining (N) =?

How to determine the amount remaining

The amount remaining after 3 half-lives can be obtained as illustrated below:

N = N₀ / 2ⁿ

N = 300000 / 2³

N = 300000 / 8

N = 37500 atoms

The mass of carbon dioxide produced by the complete combustion of 48.0g of hexane is 147.35g.

The mass of a substance can be calculated by using the stoichiometry approach.

The balanced equation of the complete combustion of hexane is as follows:

2C6H14(g) + 19O2(g) → 12CO2(g) + 14H2O(g)

48g of hexane to moles is calculated as:

48g ÷ 86g/mol = 0.56 mol

2 moles of hexane produces 12 moles of CO2

0.56 mol of hexane will produce 0.56 × 12/2 = 3.35 mol

Next, we convert 3.35 moles of CO2 to mass as follows:

3.35 moles × 44g/mol = 147.35g

Therefore, the mass of carbon dioxide produced by the complete combustion of 48.0g of hexane is 147.35g.

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Types of luminous flames:

1. Yellow Luminous Flame

2. Smoky Luminous Flame

3. Orange Luminous Flame

4. Blue Luminous Flame

Luminous flames are characterized by their visible glow, which is caused by the incomplete combustion of fuel. The presence of soot particles in the flame causes the emission of light. There are different types of luminous flames, which can be classified based on their fuel composition and burning conditions. Here are some common types of luminous flames:

1. Yellow Luminous Flame: This is the most common type of luminous flame, often seen in open fires, candles, and gas stoves. It appears yellow due to the presence of soot particles in the flame. Yellow flames indicate incomplete combustion of hydrocarbon fuels, such as methane, propane, or natural gas. The high carbon content in these fuels leads to the formation of soot, which emits visible light.

2. Smoky Luminous Flame: This type of flame is characterized by a significant amount of black smoke and soot production. It is commonly observed in poorly adjusted or malfunctioning burners or engines. The excessive presence of unburned fuel in the flame results in incomplete combustion and the emission of dark smoke particles.

3. Orange Luminous Flame: An orange flame indicates a higher combustion temperature compared to a yellow flame. It is often seen in more efficient burners or when burning fuels with a higher carbon content, such as oil or diesel. The higher temperature helps in burning more of the carbon particles, reducing the amount of soot and making the flame appear less yellow.

4. Blue Luminous Flame: A blue flame is typically associated with complete combustion. It indicates efficient burning of fuel, resulting in minimal soot formation. Blue flames are commonly observed in gas burners or Bunsen burners. The blue color is a result of the combustion of gases, such as methane, in the presence of sufficient oxygen.

It's important to note that the luminosity of a flame can vary depending on factors such as fuel-air mixture, combustion temperature, and the presence of impurities. Achieving complete combustion and minimizing the production of soot is desirable for efficient and cleaner burning processes.

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The density, in g/L, of an ideal gas when it is at 1.48 atm and 94.06 °C is 6.67g/L.

The density of an ideal gas can be calculated by dividing the mass of the substance by its volume in litres.

According to this question, the pressure and temperature of the ideal gas is given. The number of moles occupied by the gas can be calculated as follows;

PV = nRT

1.48 × 22.4 = n × 0.0821 × 367.06

33.152 = 30.14n

n = 1.1 moles

mass of gas = 1.1 mol × 145.63g/mol = 160.18g

Density = 160.18g ÷ 22.4L = 6.67g/L

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Answer: The largest one, and answer is Sand

Explanation:

Answer:

humus

Explanation:

Answer:

To find the empirical formula of the compound, we need to determine the simplest whole-number ratio of atoms in the molecule.

First, we can assume that we have 100 grams of the compound, and calculate the number of moles of each element present in it:

Carbon: 40.8 g / 12.011 g/mol = 3.398 mol

Hydrogen: 5.8 g / 1.008 g/mol = 5.753 mol

Oxygen: 53.4 g / 15.999 g/mol = 3.337 mol

Next, we divide each of these values by the smallest one, which is 3.337, to get the mole ratio:

Carbon: 3.398 mol / 3.337 mol = 1.019

Hydrogen: 5.753 mol / 3.337 mol = 1.723

Oxygen: 3.337 mol / 3.337 mol = 1.000

Rounding these values to the nearest whole number, we get the empirical formula: C1.0H1.7O1.0, which can be simplified to CH1.7O.

To find the molecular formula, we need to know the actual molecular mass of the compound. We can estimate it by adding the atomic masses of the elements in the empirical formula:

Carbon: 1 x 12.011 = 12.011

Hydrogen: 1.7 x 1.008 = 1.714

Oxygen: 1 x 15.999 = 15.999

Total = 29.724 g/mol (approx.)

The molecular mass is close to 180 g/mol, which suggests that the actual molecular formula is a multiple of the empirical formula. Dividing 180 by 29.724, we get a value of about 6.05. Multiplying the subscripts in the empirical formula by this value, we get the molecular formula: C6H10.2O6, which can be further simplified to C3H5.1O3.

The compound with the empirical formula CH1.7O and the molecular formula C3H5.1O3 is commonly known as glyoxylic acid.

Answer:

About 3.5 kJ.

Explanation:

Recall the heat transfer equation:

\(\displaystyle q = mC\Delta T\)

Where q is the heat; m is the mass of the substance; C is its specific heat; and ΔT is the change in temperature.

The given specific heat of iron is 462 J/kg -°C.

Substitute and evaluate. Ensure correct units:
\(\displaystyle \begin{aligned} q & = (1\text{ kg})\left(\frac{462\text{ J}}{\text{kg -$^\circ$C}}\right)(27.5\text{ $^\circ$C} - 20.0\text{ $^\circ$C}) \\ \\ & = (1\text{ kg})\left(\frac{462\text{ J}}{\text{kg -$^\circ$C}}\right)(7.5\text{ $^\circ$C}) \\ \\ & = 3.5\times 10^3 \text{ J} = 3.5\text{ kJ}\end{aligned}\)

Therefore, the block of iron absorbed about 3.5 kJ of heat.

So

The block absorbed 3500J of heat

Answer:

119.9 pounds

Or 1.199e2 in E notation

Explanation:

First, find the total amount of liters.

3.7854 x 19.2 = 72.67968

There are 72.67968 liters of gasoline

Then, convert the liters to milliliters

72.67968 x 1000 = 72,679.68

There are 72,679.68 milliliters of gasoline

Now, convert it to grams

72,679.68 x 0.749 = 54,437.08032

There are 54,437.08032 grams of gasoline

Convert the grams to pounds

54,437.08032 ÷ 454 = 119.9054632599119

Round it with sig figs and you will find out the weight of the gasoline is 119.9 pounds.