oscillating spring mass systems can be used to experimentally determine an unknown mass without using a mass balance. a student observes that a particular spring-mass system has a frequency of oscillation of 10 Hz. the spring constant of the spring is 250 N/m. what is the mass?​

Answer:

Explanation:

E = σ/ε = (F/A) / (ΔL/L)

E = (mg/(πd²/4) / (ΔL/L)

E = (4mg/(πd²) / (ΔL/L)

E = 4Lmg/(πd²ΔL)

E = 4(30.0)(90)(9.8)/(π(0.01²)0.25)

E = 1.35 x 10⁹ Pa  or 1.35 GPa

The stress acting on the rope is 112356 pa and the strain is 0.99. Then the Yung's modulus is 1.4 GPa.

Young's modulus is the ratio of stress to the strain. Stress is the force acting per cross sectional area of the material and strain is the ratio of change in length to the original length.

Given  mass = 90 Kg

change in length = 0.25 m

then strain = 0.25 m/30 m = 0.008

Force = mg = 90 × 9.8 =882 N

Area of the rope = πd²/4 =0.00007 m²

then stress = 882 N/area = 1.12 × 10⁹ N.

Then Young's modulus = stress/ strain

Y = 1.12 × 10⁹ N / 0.008 = 1.4 GPa.

Therefore, the Young's modulus of the rope is 1.4 Gpa.

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The magnitude of the power dissipated in resistor R4 is approximately 10,028 watts.

To find the power dissipated in resistor R4, use the formula:

P = I² × R

where P = power, I = current flowing through the resistor, and R = resistance of the resistor.

The total resistance, Rt, can be calculated using the formula:

1/Rt = 1/R1 + 1/R2 + 1/R3

Substituting the given values:

1/Rt = 1/3 + 1/0.8 + 1/2

Simplifying the equation:

1/Rt ≈ 1.6667

Rt ≈ 0.6 Ω

Next, calculate the total voltage, Vt, by summing the individual voltage sources:

Vt = ε1 + ε2 + ε3

Substituting the given values:

Vt = 9 + 6 + 4

Vt = 19 V

Now calculate the current flowing through resistor R4 using Ohm's Law:

I = Vt / Rt

Substituting the calculated values:

I = 19 / 0.6

I ≈ 31.6667 A

Finally, calculate the power dissipated in resistor R4:

P = I² × R4

Substituting the calculated values:

P = (31.6667)² × 10

P ≈ 10,028 W

Therefore, the magnitude of the power dissipated in resistor R4 is approximately 10,028 watts.

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Answer:

provide new testble ideas

A heavy truck would have larger momentum.

Because a body's mass and velocity affect its momentum. Additionally, a large truck would have higher momentum because its mass is greater than that of a light truck.

As momentum depends on both velocity and the direction of the body's motion, it is quantified by "mass velocity". Since velocity is a vector and mass is a scalar, momentum is a vector quantity.

The highest velocity change occurs in instance B, and momentum change relies on velocity change (as stated above). Keep in mind that each of the aforementioned collisions involved a ball rebounding off a wall. Observe that the acceleration, momentum change, and impulse increase with increasing rebound effect.

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Let the circumference of the circle be 10L.

A moves at 10L/2 = 5L per hour

B moves at 10L/5 = 2L per hour

Therefore it takes 10L/(5L+2L) = 10/7 hours

Answer:

Explanation:

Here's what we know and in which dimension:

y dimension:

\(v_0=30\) m/s

v = 0 (I'll get to that injust a second)

a = -9.8 m/s/s

The final velocity of 0 is important because that's the velocity of the ball right at the very top of its travels. If we knew how long it takes to get to that max height, we can also use that to find out how long it will take to hit the ground. Therefore, we will find the time it takes to reach its max height and pick up with the investigation of what this means after.

x dimension:

Δx = 70 m

v = ??

Velocity is our unknown.

Solving for the time in the y dimension:

\(v=v_0+at\) and filling in:

0 = 30 + (-9.8)t and

-30 = -9.8t so

t = 3.1 seconds

We know it takes 3.1 seconds to get to its max height. In order to determine how long it will take to hit the ground, just double the time. Therefore, it will take 6.2 seconds for the ball to come back to the ground, which is where the persom trying to catch the ball comes in. We will use that time in our x dimension now.

In the x dimension, the equation we need is just a glorified d = rt equation since the acceleration in this dimension is 0.

Δx = vt and

70 = v(6.2) so

v = 11.3 m/s

In mathematics, an algebraic expression is an expression built up from integer constants, variables, and the algebraic operations. For example, 3x² − 2xy + c is an algebraic expression.

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Answer:

Polarization.

Reason being that phenomena verifies the transverse nature of light

Answer:

Cats most commonly contract worms after coming into contact with parasite eggs or infected feces. A cat may walk through an area with eggs or infected feces, and since cats are often such fastidious groomers, they will then ingest the eggs or fecal particles as they clean their fur and feet.

Explanation:

this is the only thing in my book hope it helps

The event that happens to sound waves from an object as it moves toward you is The pitch gets higher because of an increase in wavelength.

Sound waves refer to a form of transverse wave that compress and vibrate while travelling from one medium to another thereby transferring energy.

Therefore, The event that happens to sound waves from an object as it moves toward you is The pitch gets higher because of an increase in wavelength.

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Work is referred to as the displacement of an object when a force (push or pull) is applied to it while energy is referred to as the capacity to do the work. It exists in various forms like potential, kinetic, chemical, thermal, nuclear, electrical energy and so on. Power is the work done per unit of time.

power and energy are the same.
Work is usualy doing a task that gets rid of said energy.

Answer:

Explanation:

We shall apply Wien's displacement law which is as follows .

λ T = b where λ is wavelength of light that is coming out of hot body to maximum extent .

Putting the value of temperature given and b

λ x 500 = 2898 μmK

λ = 5.796 μm = 5796 nm

For temp 1050 K

λ = 2760 nm

For temp 1800 K

λ = 1610  nm

For temp 2500 K

λ = 1159.2  nm

The visible range starts from 740 nm .

Hence we can expect that some amount of visible light may emerge at the temperature of 2500K because the wavelength that we have calculated above gives the value of peak wavelength of a spectrum of light coming out of hot body .  

The expression \(X^{N} + Y^{N}\)is not divisible by X - Y (where Y is not equal to 0).

To determine whether the expression \(X^{N} + Y^{N}\) is divisible by X - Y (where Y is not equal to 0), we can use the factor theorem and the property of binomial expansion.

The factor theorem states that if a polynomial P(x) is divisible by (x - a), then P(a) equals zero. In our case, if \(X^{N} + Y^{N}\) is divisible by (X - Y), then when we substitute X = Y into the expression, the result should be zero.

Let's substitute X = Y into the expression:

\(Y^{N} + Y^{N}\)

Since \(Y^{N}\) is equivalent to \(Y^{N}\) , the expression becomes:

2(\(Y^{N}\))

We can see that the expression 2(\(Y^{N}\)) is not equal to zero unless Y is equal to zero. Therefore, if Y is not equal to zero, \(X^{N} + Y^{N}\) is not divisible by X - Y.

In summary, unless Y is equal to zero, the expression \(X^{N} + Y^{N}\) is not divisible by X - Y according to the factor theorem and the given condition.

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The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:

τ = r * F * sin(θ)

where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.

Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:

τ_M = r_M * F_M * sin(θ)

where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.

Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:

τ_M = τ_stick

r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)

Substituting the given values:

30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)

Solving for F_M:

F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)

F_M = 0.0264 kg * 9.8 m/s^2

F_M = 0.25872 N

Finally, we can convert the force into mass using the formula:

F = m * g

0.25872 N = M * 9.8 m/s^2

M = 0.0264 kg

Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

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your answer is second hope it's helpful to you

If you pull with a constant force of 400 N for 0.2 meters, then the work done will be equal to 80 J.

In physics, the word "work" involves the measurement of energy transfer that takes place when an item is moved over a range by an externally applied, at least a portion of which is applied within the direction of the displacement.

The length of the path is multiplied by the element of a force acting all along the path to calculate work if the force is constant. The work W is theoretically equivalent towards the force f times the length d, or W = fd, to portray this concept.

As per the given information in the question,

Force, f = 400 N

Displacement, d = 0.2 meters

\(Work done(W)=Force(f)*Displacement(d)\)

W = 400 × 0.2

W = 80 J.

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The mass flow rate of water is 5.146×10³ kg/s

The enthalpy change that occurs during a reaction is the heat that enters or exits the system. A critical factor that determines whether a reaction may occur is whether the enthalpy of the system increases (i.e., because energy is added) or lowers (i.e., because energy is given off).

Elevational difference (Z1-Z2) =15m

V1 = the inlet velocity, V2 = the outlet velocity

Using the equation for steady-state energy Q+m(h1+V2/12+g/z1) =W+m(h2+V22/2+gz2),

m(h1+V21/2+g/z1) m(h2+V22/2+g/z2) =WQ, and m(h1h2+V2/12V22/2+g/z1g/z2) =WQ.

The change in enthalpy and the rate of heat transfer are both zero because the pressure and temperature have barely changed.

m (0−0+0/22−10/22+9.81× (15))

=500×1000m\s

=5.146×10³ kg/s

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Mass of book will be m = 4.495 kg  

The force of attraction between all masses in the universe; especially the attraction of the earth's mass for bodies near its surface is called gravitational force

Force = 2.68 x 10-8 N

mass of student(M)  = 55

mass of book=?

distance = 0.435m

gravitational constant (G)=6.67×10^-11

gravitational force (F)=2.68×10^-8

gravitational force (F) = (G*M*m) /\(d^{2}\)

2.68 x 10-8  = ((6.67×10^-11) * ( 55 ) * m) / 0.435

m = 4.495 kg

Mass of book will be m = 4.495 kg  

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Answer:

acellus students

Explanation

1.382

Answer:

Gradient of the hill is 53.33m/km which is lesser than the 500 m/km. So, he will be able to climb the hill conveniently.

Explanation: Given that

Maximum gradient = 500 m/km

Total distance = 1.5 km

Starting elevation = 20 m

Final elevation = 100 m

Gradient = change in elevation/ total distance.

Now, substitute the values into the formula.

Gradient = (100m - 20m)/1.5km

= 80m/1.5km

= 53.33m/km

Gradient of the hill is 53.33m/km which is lesser than the 500 m/km. So, he will be able to climb the hill conveniently.

A wave with a wavelength of 4.0 m moves with a speed of 2.0 m/s will have frequency of 0.5 Hz.

Given,

The wavelength of the wave, λ = 4.0 m

Speed of the wave, v = 2.0 m/s

Frequency of the wave can be calculated as;

ν =v/λ

= 2/4

=1/2 Hz

Or, 0.5 Hz

Hence, the frequency of the wave will be 0.5 Hz.

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Answer:

t = 1.875 hours

Explanation:

Speed

The speed is the rate at which an object moves. If the speed is constant, then the formula to calculate it is:

\(\displaystyle v=\frac{d}{t}\)

Where d is the distance traveled in time t.

The jogger runs 6 Km plus 5 Km plus 4 Km north for a total of 15 Km.

It's given her average speed is 8 Km/h. We can calculate the time take to complete the run by solving the above formula for t:

\(\displaystyle t=\frac{d}{v}\)

\(\displaystyle t=\frac{15\ Km}{8\ Km/h}\)

t = 1.875 hours

We have that The  moles of air are in the cylinder and the volume would this air occupy at 1.0 atm and room Temperature is

From the question we are told

Generally the equation for the Volume of Cylinder  is mathematically given as

\(V=\pi r^2l\\\\V=\pi *{\frac{20}{2*100}}*1\\\\V=31.4L\)

Therefore

The equation for the ideal gas  is mathematically given as

\(PV=nRT\\\\n=\frac{PV}{RT}\\\\n=\frac{180*31.4}{0.082*300}\\\\n=229.756\)

Generally the equation for the ideal gas  is mathematically given as

\(PV=nRTWhere\\\\V=\frac{nRT}{P}\\\\V=229.756*0.082*300\\\\V=5651.997L\)

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Answer:

I believe the answer is 5718.75. Respond if it is wrong please.

Explanation:

I used a calculator.

A force is a push or pull upon an object resulting from the object's interaction with another object.

We have 3 laws of motion or Newton's laws

1. The law of inertia or first law postulates that a body will remain at rest or in straight motion with a constant speed unless an external force is applied.

2. Newton's second law or fundamental law, postulates that the net force that is applied on a body is proportional to the acceleration it acquires on its path.

The formula is F=ma

where F is the force, m is the mass and a is the acceleration

3. Newton's third law postulate says that every action generates an equal reaction but in the opposite direction.

Answer:the potential difference Vb − Va = -3 V

Explanation:

The potential difference Vb − Va s given by

Vb − Va=  Capacitance / Charge + current x resistance - Electromotive force

Vb − Va=Q/C + I X R - E

V=Q / C=(12 x 10^-3) / (3 x 10^-3)

=0.012/0.003ss

=4V

alsoV=  1R = 2.0 x 10^-3 x 4 x 10^3

=0.002 X 4000

=8

Vb − Va= 4V + 8V- 15V

= -3V

Therefore, the potential difference Vb − Va = -3 V

Answer:

The value of g is  \(g =76.2 m/s^2\)

Explanation:

From the question we are told that

     The mass of the weight is \(m = 1.30 kg\)

      The spring  constant  \(k = 1.73 g/m = 1.73 *10^{-3} \ kg/m\)

       The second harmonic frequency is \(f = 100 \ Hz\)

       The number of oscillation is \(N = 200\)

        The time taken is  \(t = 315 \ s\)

Generally the frequency is  mathematically represented as

           \(f = \frac{v}{\lambda}\)

At second harmonic frequency the length of the string vibrating is equal to  the wavelength of the wave generated

         \(l = \lambda\)

Noe from the question the vibrating string is just half of the length of the main string so

Let assume the length of the main string is  \(L\)

So      \(l = \frac{L}{2}\)

The velocity of the vibrating string is mathematically represented as

             \(v = \sqrt{\frac{T}{\mu} }\)

Where T is the tension on the string which can be mathematically represented as

             \(T = mg\)

So  

           \(v = \sqrt{\frac{mg}{k} }\)

Then

          \(f = \frac{v}{\frac{L}{2} }\)

=>       \(v = \frac{fL }{2}\)

=>      \(\sqrt{\frac{mg}{k} } = \frac{fL}{2}\)

=>        \(g = \frac{f^2 L^2 \mu}{4m}\)

substituting values

             \(g = \frac{(100) * (1.73 *10^{-3} )}{(4 * 1.30)} L^2\)

              \(g = 3.326 m^{-1} s^{-2} L^2\)

Generally the period of oscillation is mathematically represented as

       \(T_p = 2 \pi \sqrt{\frac{L}{g} }\)

=>   \(L = \frac{T^2 g}{4 \pi ^2}\)

   The period can be mathematically evaluated as

                \(T_p = \frac{t}{N}\)

 substituting values

             \(T_p = \frac{315}{200}\)

             \(T_p = 1.575 \ s\)

Therefore

          \(L = \frac{1.575^2 * g }{4 \pi ^2}\)

           \(L = 0.0628 ^2 g\)

so

      \(g = 3.326 m^{-1} s^{-2} L^2\)

substituting for L

        \(g = 3.326 ((0.0628) g)^2\)

=>    \(g = \frac{1}{(3.326)* (0.0628)^2}\)

       \(g =76.2 m/s^2\)

The work done is  2321 J.

We have to note that the acceleration has to do with the change in the velocity of the object with time. We are told that there is a movement of the crate as we can see. Let us note that the work that is done by the object subtracted from the work done by the friction. Thus we have that;

Work = (46 * 9.8 * 10.3) - (0.5 * 46 *9.8 *  10.3)

Work = 4643 - 2321

= 2321 J

The work that has been done is  2321 J. This is done in  moving the object

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Answer:

Explanation:

D. Black holes play a role in the formation of galaxies that contain stars, which help planets form and (at least for Earth) support life; but they also can subsume celestial bodies and destroy life that passes the event horizon.

The black holes are considered the "destroyers and creators" of life because Black holes play a role in the formation of galaxies that contain stars, which help planets form and (at least for Earth) support life; but they also can subsume celestial bodies and destroy life that passes the event horizon. Option (A) is correct.

In space, a black hole is a region where gravity is so strong that even light cannot escape. Because the substance is compressed into such a small area, the gravity is extremely intense. When a star is dying, this may take place.

People cannot perceive black holes because no light can escape from them. They are undetectable. Specialized space telescopes can aid in the discovery of black holes. The unique instruments can observe how stars that are very near black holes behave differently from other stars.

Black holes can vary in size. The smallest black holes, according to scientists, are as small as a single atom. These tiny black holes have the bulk of a massive mountain despite their size.

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F = Kv, where K is a constant, describes the magnitude of the force F felt by an object moving at a particular speed v.

What exactly is Newton's second rule of motion?

The formal formulation of Newton's second rule of motion is as follows: The acceleration of an object caused by a net force is inversely proportionate to the mass of the object and directly proportional to the magnitude of the net force in the same direction.

You accelerate when the forward forces are greater than the reversing forces (accelerate). The power of air resistance pushing back against you grows as you move faster. The forces eventually achieve equilibrium (the forward forces are the same size as the opposing forces).

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Answer:

3 m/s

Explanation:

A= F/m

12,000/ 4000 = 3

Answer:

3 m/s^2

Explanation:

The equation you have to use is F=ma because the problem is a Newton's 2nd law problem.

Our known values are:

F ( Force ) = 12,000 N

m ( mass ) = 4,000 kg

a ( acceleration ) = ?

Now we plug in the known values into the equation and solve

F=ma

12,000=4,000a

We have to divide 4,000 by both sides to isolate the a value

12,000/4,000=4,000/4,000a

The 4,000s on the right of the equation cancel.

And 12,000 divided by 4,000 equals 3

The acceleration (a) is 3 meters per second squared (m/s^2)

Next, check to make sure 3 does work by plugging it back into the equation.

12,000=4,000*3

12,000=12,000 ✔

As you can see, the acceleration will be 3 m/s^2