The net force on q2 is -112.5 N, directed towards q3.
To find the net force on q2, we need to first find the forces exerted on it by q1 and q3 using Coulomb's Law:
The force exerted by q1 on q2 is given by:
\(F1 = (k * q1 * q2) / d1^2\)
where k is Coulomb's constant (\(9 * 10^9 N m^2 / C^2\)), d1 is the distance between q1 and q2 (0.5 m).
Plugging in the values:
F1 = \((9 * 10^9 N m^2 / C^2)\) * \((-5.00 * 10^{-6 }C)\) * (\(2.50 * 10^{-6} C\)) / \((0.5 m)^2\)
F1 = -22.5 N (repulsive, as q1 and q2 have opposite signs)
The force exerted by q3 on q2 is given by:
\(F3 = (k * q3 * q2) / d3^2\)
where d3 is the distance between q2 and q3 (0.25 m).
Plugging in the values:
F3 = \((9 *10^9 N m^2 / C^2)\) *\((-2.50 * 10^{-6} C)\) * \((2.50 * 10^{-6} C)\) / \((0.25 m)^2\)
F3 = -90 N (attractive, as q2 and q3 have the same sign)
To find the net force, we need to add these forces vectorially, since they act in opposite directions:
Fnet = F1 + F3
Fnet = -22.5 N - 90 N
Fnet = -112.5 N
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Can the sun explain global warming? ( 2 points) Suppose that the Earth has warmed up by 1 K in the last hundred years. i) How much would the solar constant have to increase to explain this? ii) Compare this to the observed fluctuation of the solar constant over the past 400 years (shown in class) For part (i), begin with the standard 'blackbody' calculation from class, that is: set α=0.30, and assume that the Earth acts as a blackbody in the infrared.
No, the sun cannot explain global warming. Global warming is a phenomenon in which the temperature of the Earth's surface and atmosphere is rising continuously due to human activities such as deforestation, burning of fossil fuels, and industrialization.
This increase in temperature cannot be explained only by an increase in solar radiation.There are several factors which contribute to global warming, including greenhouse gases such as carbon dioxide, methane, and water vapor. These gases trap heat in the Earth's atmosphere, which causes the planet's temperature to rise. The sun's radiation does contribute to global warming, but it is not the main cause.
i) To calculate the increase in solar radiation that would cause the Earth to warm up by 1 K, we can use the following formula:ΔS = ΔT / αWhere ΔS is the increase in solar constant, ΔT is the increase in temperature, and α is the Earth's albedo (reflectivity).α = 0.30 is the standard value used for the Earth's albedo.ΔS = ΔT / αΔS = 1 K / 0.30ΔS = 3.33 W/m2So, to explain the increase in temperature of 1 K over the last hundred years, the solar constant would need to increase by 3.33 W/m2.
ii) The observed fluctuation of the solar constant over the past 400 years has been around 0.1% to 0.2%. This is much smaller than the 3.33 W/m2 required to explain the increase in temperature of 1 K over the last hundred years. Therefore, it is unlikely that the sun is the main cause of global warming.
The sun cannot explain global warming. While the sun's radiation does contribute to global warming, it is not the main cause. The main cause of global warming is human activities, particularly the burning of fossil fuels, which release large amounts of greenhouse gases into the atmosphere.
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PLEASE ANSWER THESE FAST
AND CORRECT PLEASE
A body weights 50 N in air and 45 N when wholly immersed in water calculate (i) the loss in weight of the body in water (ii) the upthrust on the body. (iii) volume of the body.
Answer:
\(difference \: in \: weight = 150n - 100n = 50n\)
Now,buyantant force
\(difference \: in \: weight \: = volume(body) \times density \: of \: water \: \times g\)
so;
\(50 = {v}^{b} \times 1 \times {10}^{3} \times 9.8m {s}^{2}\)
\( {v}^{b} = \frac{50}{1000 } \times 9.8\)
\( = \frac{50}{9800} \)
\( = 0.0051\)
Now,
\(mass \: in \: air \: = 150n = \frac{150}{9.8kg} \)
\(density = \frac{weght}{volume} \)
\( = \frac{150}{0.0051} \times 9.8 \\ x = 3000\)
And now,
\(specific \: density \: = \frac{density of \: the \: body}{density \: of \: water} \)
\( = \frac{3000}{1000} \)
\( = 3\)
Hence that,specific density of a given body is 3
please mark me as brainliest, please
(10) A car is stopped for a traffic signal. When the light turns green, the car accelerates, increasing its speed from 0 to 6. 00 m/s in 0. 774 s. (a) What is the magnitude of the linear impulse experienced by a 70. 2 kg passenger in the car during this time? Submit Answer Tries 0/10 (b) What is the average force experienced by the passenger? 5. 44x102 N You are correct. Previous Tries Your receipt no, is 155-4422
The magnitude of the linear impulse experienced by the passenger during this time is 421.2 kg·m/s and the average force experienced by the passenger is approximately 5.44 × 10^2 N.
(a) To calculate the magnitude of the linear impulse experienced by the passenger, we can use the equation:
Impulse = mass × change in velocity
Given:
Mass of the passenger (m) = 70.2 kg
Change in velocity (Δv) = 6.00 m/s - 0 m/s = 6.00 m/s
Substituting the values into the equation, we get:
Impulse = 70.2 kg × 6.00 m/s = 421.2 kg·m/s
Therefore, the magnitude of the linear impulse experienced by the passenger during this time is 421.2 kg·m/s.
(b) To find the average force experienced by the passenger, we can use the equation:
Average force = Impulse ÷ time
Given:
Impulse (I) = 421.2 kg·m/s
Time (t) = 0.774 s
Substituting the values into the equation, we get:
Average force = 421.2 kg·m/s ÷ 0.774 s = 544.0 N (rounded to three significant figures)
Therefore, the average force experienced by the passenger is approximately 5.44 × 10^2 N.
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he difference between mass and weight. *
how does an a.c generator work?
which of the following are features of the nucleus of an atom
finding evidence to support or dispove is how science advanes
A coin is dropped off of a building from rest at a height of 155 meters. What is the velocity of the coin as it hits the ground?
Answer:
period let the coin do what it do
Explanation:
do you know this???
ill give you 20 points
Answer:
it looks like B on the first one and D on the second hope this helps!!
Explanation:
an object is found to be moving in a circle with a constant speed. is there a force acting on the particle? if so, in what direction is this force. if not, why not? explain your reasoning.
Because the object's motion is moving in the same direction as the velocity vector, the velocity vector is also pointed in a tangent direction to the circle.
While it moves in a circle, an object constantly changes its direction. The path of the object is always perpendicular to the circle. Given that its direction matches the motion of the item, the velocity vector is also oriented tangent to the circle. While it moves in a circle, an object constantly changes its direction. The path of the object is always perpendicular to the circle. Given that its direction matches the motion of the item, the velocity vector is also oriented tangent to the circle. Within, there is force.
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determine which part of the electromagnetic spectrum each of the following waves lies in. waves with a frequency f = 10.0 khz.
a. UV
b. Microwave
c. IR
d. X-ray
e. Visible
f. Radio
The waves with a frequency f = 10.0 kHz lie in the radio part of the electromagnetic spectrum.
The electromagnetic spectrum is the range of all types of electromagnetic radiation. It includes radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays. The position of a wave on the spectrum is determined by its frequency and wavelength. The waves with a frequency f = 10.0 kHz have a wavelength of approximately 30,000 meters, which falls within the radio part of the spectrum.
Radio waves have the longest wavelengths and the lowest frequencies in the electromagnetic spectrum. They are used for broadcasting and communications, such as radio and TV signals. Therefore, the waves with a frequency f = 10.0 kHz belong to the radio part of the electromagnetic spectrum.
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The temperature of an object is 15 degrees Celsius. What will be its temperature on the Fahrenheit scale? F= (C x 1.8) + 32.
Answer:
59F
Explanation:
Given parameters:
Temperature in °C = 15°C
Unknown:
Temperature in Fahrenheit scale = ?
Solution:
To solve this, we use the conversion equation below;
F = (C x 1.8) + 32
C is the temperature in celcius;
F = (15 x 1.8) + 32 = 59F
Kara started a new exercise program. Kara’s sister works out with her on a regular basis and even talks to Kara about her progress. In this scenario, what is another name for Kara’s sister?
A.
goal-setter
B.
self-monitor
C.
support system
D.
nutritionist
What is the net force in this image?
a
8000 N right
b
5000 N right
c
4000 N right
d
4000 N left
e
5000 N left
f
8000 N left
Answer:
4000N left
Explanation:
6000N-1000N-1000N
6000N-2000N
8000N
PLEASE HELP!!
A person is traveling at 5m/s for around 20 minutes. how much distance did he cover? hint: change minutes to seconds.
a freely falling object is found to be moving downward at 18 m/s. if it continues to fall, two seconds later the object would be moving with a speed of
Assuming no air resistance, the acceleration due to gravity is approximately 9.81 m/s^2.
After two seconds, the object will have fallen a distance of:
d = 1/2 * g * t^2
d = 1/2 * 9.81 m/s^2 * (2 s)^2
d = 19.62 meters
During this time, the object's velocity will increase due to gravity by:
v = g * t
v = 9.81 m/s^2 * 2 s
v = 19.62 m/s
Therefore, the object's speed after two seconds will be the vector sum of its initial velocity and the velocity it gained due to gravity:
v_final = sqrt((18 m/s)^2 + (19.62 m/s)^2)
v_final = 25.14 m/s
So the object would be moving with a speed of approximately 25.14 m/s after two seconds of free fall.
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A substance that heats up relatively quickly has a low specific heat capacity. Select one: O True O False
As the given statement is False. As a substance that heats up relatively quickly must has a high specific heat capacity.
What is specific heat capacity?A physical property of matter is specific heat capacity. The quantity of heat energy required to raise a substance's temperature per unit of mass is known as the specific heat capacity. It serves as an illustration of a large property. Since the scale of the system under study directly affects it. Therefore, it is the amount of heat absorbed by the substance per unit mass when its temperature is elevated. Specific Heat Capacity is measured in J/(kg K) or J/(kg °C) units.
As heating is quick when the substance have high specific heat capacity and the heating will be slow when the substance have less specific heat capacity.
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Orbital Motion Interactive Purpose: The purpose of this activity is to investigate the nature of an elliptical orbit of a planet or other satellite about the Sun or some central body. Procedure and Questions: 1. Navigate to the Orbital Motion Interactive (Physics Classroom >> Physics Interactives >> Circular Motion and Gravitation >> Orbital Motion) and experiment with the on-screen buttons in order to gain familiarity with the Interactive. The eccentricity of the elliptical orbit can be varied. A trace of the object's motion is displayed. The vector nature of velocity and force can be shown on the screen. The animation can be started, paused, continued or reset.
Users of the Orbital Motion Interactive can view and investigate how a planet or satellite moves in an elliptical orbit around a central object, such as the Sun.
The route an object takes through space as it revolves around a main body, like a planet or star, is known as an elliptical orbit. The item has an elliptical shape rather than a circular one because the gravitational force acting on it is variable. The semi-major axis, which measures the average separation between the object and the central body, and eccentricity, which determines how the elliptical orbit looks, are the two characteristics that define an elliptical orbit. When an object is nearer to the central body, it moves more quickly, and when it is farther away, it moves more slowly. The periapsis is the location where the object is closest to the central body, and the apoapsis is the location where it is farthest.
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What is the purpose of the Orbital Motion Interactive and what can users view and investigate with it?
WILL PICK BRAINLYEST AND GETS 25 POINTS
Justin is planning his science fair project. He wants to measure how oxygen levels affect the rate of photosynthesis in plants. Is this an example of a scientific investigation or an experiment?
A. An experiment because it tests a cause and effect relationship
B. An experiment because it does not ask a testable question
C. An investigation because it uses only observations
D. An investigation because there is a control group
Answer:
is: B. why ? u ask.... well u forgot one important factor when ansering that factor being that...... H'ES CRACKED AT FORTNITE MY GUY
i desereve bwainweist... JK LOL give it to the other guy.
The given one is an experiment because it tests a cause and effect relationship. The rate of photosynthesis is determined by measuring the concentration of carbon dioxide on an enclosed transparent chamber.
What is photosynthesis ?Photosynthesis is a biochemical process by which green plants synthesis chemical energy with the aid of light energy. The photosynthetic reaction is the combination of carbon dioxide and water to form oxygen molecule and glucose.
The photosynthetic reaction is given here:
\(\rm 6CO_{2} + 6H_{2}O \rightarrow C_{6}H_{12}O_{6} + 6O_{2}\)
Here, the oxygen gas is the product in the reaction. Hence, increase in the oxygen level will reverse the reaction and thus, rate of photosynthesis decreases.
The rate of photosynthesis is determined by the measurement of concentration of carbon dioxide within the closed transparent chamber in which the plant is placed. Hence, we are testing a cause and effect and it is a scientific experiment. Hence, option A is correct.
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(figure 1) is a snapshot graph at t = 0 s of two waves on a string approaching each other at 1 m/s.
Six values of the displacement of the string exist at x = 5.0 m at 1 s from t = 0 s to t = 6 s.
All the numbers existing between two specific integers are called as an interval. Out of these whichever umbers fall between these actual values are termed as range.
Intervals contain real numbers falling between two set numbers.
A snapshot graph at t = 0 s of two waves on a string coming towards one other at time interval of 1 m/s is provided. Then, the values of the string displacement at x = 5.0 m at 1 s from t = 0 s to t = 6 s are,
At t = 0
s,= Y₀= 0 cm
At t =1
s,= Y₁= 0 cm
At t = 2
s,= Y₂= 0 cm
At t =3
s,= Y₃= 0 cm
At t =4
= Y₄= 0 cm
At t = 5 s,
= Y₅=0 cm
At t = 6
s,= Y₆= 0 cm
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The complete question:
(Figure 1) is a snapshot graph at t = 0 s of two waves on a string approaching each other at 1 m/s.
1. List the values of the displacement of the string at x = 5.0 m at 1 s intervals from t = 0 s to t = 6 s.
two points, a and b, are on a disk that rotates about an axis. point a is three times as far from the axis as point b. if the speed of point b is v, then what is the speed of point a?
There is a disk rotating around an axis, and on this disk, there are two points labeled as "a" and "b." Point "a" is located three times farther from the axis compared to point "b."
Let's assume that the distance of point b from the axis is "r" units. Since point a is three times as far from the axis as point b, the distance of point a from the axis is 3r units.
The speed of a point on a rotating disk is determined by its distance from the axis and the angular velocity of the disk. In this case, the angular velocity is the same for both points a and b, as they are on the same rotating disk.
The formula that relates the speed (v) of a point on a rotating disk to its distance from the axis (r) and the angular velocity (ω) is:
v = ω * r
For point b:
\(v_b = \omega \cdot r\)
For point a:
\(v_a = \omega \cdot (3r)\)
Since the angular velocity (ω) is the same for both points, we can express it as a common factor:
\(v_a = 3 * v_b\)
Therefore, the speed of point a is three times the speed of point b.
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In covalent bonds, the atoms that form bonds
A: May be metals or non- metals
B:transfer electrons
C: May both be the same element
D: all of the above
Answer:
the answer is C
Explanation:
Why is it not easy to witness
inertia on Earth?
A. Magnetism is much stronger.
B. Gravity and friction are always acting on
objects.
C. Our mass is too small.
D. Our mass is too large.
The world’s largest chandelier was created by a company in South Korea
and hangs in one of the department stores in Seoul, South Korea. The
chandelier’s mass is about 9700 kg. Consider a situation in which this
chandelier is placed in a wooden crate whose mass is negligible. The
chandelier is then pulled along a smooth horizontal surface by two forces
that are parallel to the smooth surface, are at right angles to each other,
and are applied 45º to either side of the direction in which the chandelier is
moving. If each of these forces is 1200 N, how much work must be done on
the chandelier to pull it 12 m?
The work done by the two forces in moving the chandelier to the given distance is 5,091.2 J.
Work done by a single force on the chandelier
The work done by a single force on the chandelier is determined by taking the net horizontal force applied on the chandelier over the given distance.
\(W = (F - F_f) d\\\\W = (F sin\theta \ - \ F_f)d\)
where;
\(F_f\) is frictional force = 0 (smooth surface).
\(W = Fsin(\theta) d\\\\W = 1200 \times sin(45) \times 12\\\\W = 10,182.34 \ J\)
Work done by the two forcesWhen the two forces combine to pull the chandelier, the total work done will be shared by the two forces.
\(W_1 = W_2 = \frac{10,182.34}{2} = 5,091.2 \ J\)
Thus, the work done by the two forces in moving the chandelier to the given distance is 5,091.2 J.
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what is the heat change in kj associated with 37.19 g of liquid water at 5.00 ° c changing to solid water at -5.00 °c?
The heat change associated with 37.19 g of liquid water at 5.00 °C changing to solid water at -5.00 °C is approximately 12.4007 kJ.
The heat change associated with a phase change can be calculated using the heat of fusion, which is the amount of heat required to change a given mass of a substance from a solid to a liquid, or vice versa. The heat of fusion for water is approximately 333 J/g.
The heat change associated with 37.19 g of liquid water at 5.00 °C changing to solid water at -5.00 °C can be calculated as:
q = m * ΔHfusion
where m is the mass of the water and ΔHfusion is the heat of fusion. In this case, m = 37.19 g and ΔHfusion = 333 J/g, so:
q = 37.19 g * 333 J/g = 12400.07 J
To convert the heat change from joules to kilojoules, divide by 1000:
q = 12400.07 J / 1000 = 12.4007 kJ
So the heat change associated with 37.19 g of liquid water at 5.00 °C changing to solid water at -5.00 °C is approximately 12.4007 kJ.
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Joan needs to eliminate some employees for a short while. She and her managers identify those employees who are not meeting performance expectations and explain that this termination is temporary but they are encouraged to seek other positions elsewhere. How is Jane trying to reduce the size of the workforce here?
Answer: layoff
Explanation:
From the information in the question, we can see that Jane is trying to reduce the size of the workforce here through layoff.
Since Joan explains that the termination is temporary, then it's a layoff. If it were to be firing, the termination won't be temporary but permanent as they can't be recalled by the company. But since the employees are discharged temporarily, it's a layoff.
A solid conducting sphere is given a positive charge Q. How is the charge Q distributed in or on the sphere?
(A) It is concentrated at the center of the sphere.
(B) It is uniformly distributed throughout the sphere.
(C) Its density decreases radially outward from the center.
(D) Its density increases radially outward from the center.
(E) It is uniformly distributed on the surface of the sphere only.
The charge Q is uniformly distributed throughout the sphere. The correct answer is (B)
When a solid conducting sphere is given a positive charge Q, the charge will distribute itself evenly throughout the surface of the sphere due to the repulsion of like charges. This is known as the "Faraday's ice pail experiment".
According to the principle of electrostatics, the charge on a conductor always resides on its surface and distributes itself in a way that the electric field inside the conductor is zero. Since the charge on a conductor always resides on its surface, it follows that the charge Q in this case must be uniformly distributed throughout the surface of the sphere.
Option (A) is not true because the charge is not concentrated at the center of the sphere. If the charge was concentrated at the center of the sphere, the electric field would not be zero inside the conductor, which contradicts the principle of electrostatics.
Option (C) and (D) are not true because the density of the charge does not change radially outward from the center. If the density decreased or increased radially outward, the electric field inside the conductor would not be zero, which again contradicts the principle of electrostatics.
Option (E) is not true because the charge is distributed throughout the entire volume of the sphere, not just on its surface. A solid conductor has free charges that can move throughout its entire volume, so the charge will distribute itself throughout the entire volume of the sphere until the electric field inside the conductor is zero.
Therefore, the correct answer is (B) it is uniformly distributed throughout the sphere.
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please help me to find out my mistake
From the calculation, the speed of sound at 10 K is 63.5 m/s.
What is the speed of sound?We know that the speed of sound is directly proportional to the temperature of the body thus we can write;
V1/V2 = √T1/T2
Then;
T1 = 0 degrees or 273 K
T2 = 10 K
V1 = 330 m/s
V2 = ?
330/T2 = √273/10
330/T2 = 5.2
330 = 5.2T2
V2 = 330/5.2
V2 = 63.5 m/s
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a wind wave with a 100-m wavelength in water that is 25 m deep is an example of what? select one: a. a deep water wave b. a tidal wave c. a shallow water wave d. a transitional wave e. a rogue wave
The wind wave with a 100-m wavelength in water that is 25 m deep is an example of a shallow water wave.
In general, shallow water waves have a wavelength that is much larger than the depth of the water, which is the case in this scenario.
The velocity of shallow water waves is primarily determined by the depth of the water, which is much smaller than the velocity of deep water waves.
As a result, the speed of the wind wave in this case would depend on the depth of the water, and would be slower than a wind wave with the same wavelength in deeper water.
This distinction between shallow and deep water waves is important for understanding ocean wave dynamics and predicting wave behavior in different environments.
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Which of these causes summer in the northern hemisphere?
The Sun is closer to Earth during the summer.
The northern hemisphere receives more direct sunlight during the summer.
Earth's northern axis is tilted away from the Sun during the summer.
The North Pole is tilted away from the Sun during the summer.
Answer:
The northern hemisphere receives more direct sunlight during the summer.