Please answer the first question

Answer:

4x - 3(12x + 4)  = -6

Step-by-step explanation:

12x - y = -4 ------------(I)

12x      = -4 + y

12x + 4 = y --------------(III)

4x - 3y = -6 ------------(II)

Substitute y = 12x + 4 in equation (II)

4x - 3(12x + 4)  = -6

Answer:

The measure of angle A is 32

Step-by-step explanation:

A+B=180

2x-16+5x+28=180

7x+12=180

7x=168

x=24

A=2(24)-16

A=48-16

A=32

Answer:

The dude above is right it's 32, I put it in and it's right :-)

Step-by-step explanation:

The three consecutive multiples of 3 are 15, 18 and 21

First, let's determine three successive multiples of 3:

The subsequent two would be "x+3" and "x+6" if we call the initial number "x".

Since we are aware that the third number (x+6) is one more than the first two numbers (x + x+3), we can write the following equation:

2/3(x + x+3) = (x+6) + 1

Simplifying this equation, we get:

2/3(2x+3) = x+7

Multiplying both sides by 3, we get:

2(2x+3) = 3(x+7)

Expanding and simplifying, we get:

4x + 6 = 3x + 21

Subtracting 3x and 6 from both sides, we get:

x = 15

Therefore, the three consecutive multiples of 3 are 15, 18 and 21

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Option A, -9x - 2 = 14x is the required equivalent equation for the equation 5x - 2(7x + 1) = 14x.

What are equivalent equations?

Equations with the same answer or solution are said to be equivalent. Comparisons between linear equations are common. When graphed, linear equations result in straight lines with a slope and a y-intercept. The characteristics that make a linear equation linear are crucial in establishing if two linear equations are equivalent. Although it may not seem like it at first, there are mathematical procedures to determine whether the equivalent equations will have the same solution.

To get equivalent equation of the given equation, we need to simplify it.

So, given equation

5x - 2(7x + 1) = 14x

Lets multiply -2 with 7x+1, we get

5x-14x-2=14x

it can be written as:

-9x - 2 = 14x

This is required equivalent equation.

Therefore, option A is correct answer

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The ratio of the students who own a pet to the total number of students in the pet school is 5:6 ; Therefore, using this ratio, the number of students who own a pet out of the total students of 900 will be 750

Therefore,a total of 750 students own a pet.

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Generally:

- Vertical angles are congruent.   An example of vertical angles on the diagram are angles 1 and 4; they are opposite each other on the two intersecting lines.

When two parallel lines are intersected by a transversal:

- Corresponding angles are congruent.   Corresponding angles are angles on the same side of the transversal with corresponding positions, such as angles 2 and 5 in the diagram.

- Alternate interior angles are congruent.   Angles 3 and 5 are an example of alternate interior angles on the diagram.  They are contained within the interior of the two parallel lines, and are on opposite sides of the transversal.

- Alternate exterior angles are congruent.   These angles lie on the outside of the parallel lines and on opposite sides of the transversal.  Angles 1 and 7 are an example of alternate exterior angles.

Looking at the diagram, we can recognize that our given angle of 56° creates a vertical angle pair with angle 7; these angles are congruent.  Additionally, since corresponding angles are congruent, angles 4 and 7 are congruent.  Notice that angle 4 creates a vertical angle pair with angle 1, and that angle 1 also corresponds to the given angle.

The angles which are congruent to the given angle measure are:

∠1, ∠4 and ∠7

(a) The probability that the top card is an ace or a king is \($\frac{2}{13}\)

(b) The probability that the top card is spades and the second card is clubs is \($\frac{1}{2652}\)

(c) The probability that the top card is spades and the second card is an ace is \($ \frac{1}{663}\)

(d) The probability that the top 3 cards are all spades is \($\frac{1}{132600}\)

(e) The probability that the top 4 cards include 3 different ranks, with one rank appears twice is \($\frac{2}{925}\)

As per the data given:

A standard deck of 52 cards has 13 ranks (ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen, king) and 4 suits (spades, hearts, diamonds, and clubs), such that there is exactly one card for any given rank and suit.

a) The probability that the top card is an ace or a king:

The probability that the top card is an ace \($\frac{4}{52} = \frac{1}{13}\)

The probability that the top card is an king \($\frac{4}{52}=\frac{1}{13}\)

The probability that the top card is an ace or a king is \($\frac{1}{13} +\frac{1}{13} =\frac{2}{13}\).

b) The probability that the top card is spades is \($\frac{1}{52}\)

Already a card is drawn then the probability that the second card is clubs is \($\frac{1}{51}\)

The probability that the top card is spades and the second card is clubs is \($\frac{1}{52}\times\frac{1}{51} = \frac{1}{2652}\)

c) The probability that the top card is spades is \($\frac{1}{52}\)

Already a card s drawn then the probability that the second card is an ace is \($\frac{4}{51}\)

The probability that the top card is spades and the second card is an ace  is \($\frac{1}{52}\times\frac{4}{51} = \frac{4}{2652} = \frac{1}{663}\)

d) The probability that the top 3 cards are all spades is \($\frac{1}{52}\times\frac{1}{51}\times\frac{1}{50} = \frac{1}{132600}\)

e) There are C(52, 4) ways to choose 4 cards from the deck, and the 4 ways to choose the rank that appears twice.

So, the total number of ways to choose 4 cards with 3 different ranks and one rank appearing twice is 4 C(52, 4) = 4 × 270725.

The number of ways to choose the 4 cards such that they include 3 different ranks, with one rank appearing twice is 4  C(13, 2)  C(4, 2) = 672.

Hence, the probability is \($\frac{672}{270725} =\frac{2}{925}\)

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A standard deck of 52 cards has 13 ranks (ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen, king) and 4 suits (spades, hearts, diamonds, and clubs), such that there is exactly one card for any given rank and suit. The deck is randomly arranged. What is the probability that

(a) the top card is an ace or a king.

(b) the top card is spades and the second card is clubs.

(c) the top card is spades and the second card is an ace.

(d) the top 3 cards are all spades.

(e) the top 4 cards include 3 different ranks, with one rank appears twice (for example, an ace of hearts, a 3 of clubs, a 3 of hearts, and a 7 of spades).

Answer:

B: the cost per pint of 3 pints of blueberries if the total cost is $6

Step-by-step explanation:

A is using multiplication

C is using addition and multiplication

D is using multiplication and addition.

Therefore, B would be your answer.

Hope this helps! :)

Answer:

Its B

Step-by-step explanation:

I got 100 on quiz

Answer:

your third answer

Step-by-step explanation:

its easy just plug in each domain into your function and the result will be the range

9514 1404 393

Answer:

  (-16, -12), (16, -12)

Step-by-step explanation:

The given values (side length and hypotenuse) have the ratio ...

  12 : 20 = 3 : 5

This suggests that the triangle formed by the axes and the point 20 units from the origin is a 3-4-5 triangle, and the remaining side is 16 units from the y-axis. That means the points of interest are ...

  (-16, -12) and (16, -12)

Answer:

B

Step-by-step explanation:

i got a 95% so i thinks its right

The total cost of the pita bread and hummus dips will be $305.00.

To determine the cost of the pita bread and hummus dips, Toula can use the following expressions:

Cost of pita bread:

Number of crates needed = (150 bags) / (50 bags/crate) = 3 crates

Cost of each crate = $15.00

Total cost of pita bread = (Number of crates needed) × (Cost of each crate) = 3 crates × $15.00/crate = $45.00

Cost of hummus dips:

Number of boxes needed = (65 containers) / (5 containers/box) = 13 boxes

Cost of each box = $20.00

Total cost of hummus dips = (Number of boxes needed) × (Cost of each box) = 13 boxes × $20.00/box = $260.00

Therefore, the expressions Toula can use to determine the costs are:

Cost of pita bread = 3 crates × $15.00/crate

Cost of hummus dips = 13 boxes × $20.00/box

The total cost will be the sum of the costs of pita bread and hummus dips:

Total cost = Cost of pita bread + Cost of hummus dips

Total cost = $45.00 + $260.00

Total cost = $305.00

Therefore, the total cost of the pita bread and hummus dips will be $305.00.

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The unit rate for the problems are;

a. 50pages/hour

b. 4points / game

c. 8 car washed /hour

d. 8 ounces of peanut/ dollar

A unit rate means a rate for one of something. We write this as a ratio with a denominator of one. For example, if you ran 100 yards in 10 seconds, you ran on average 10 yards in 1 second.

a. The unit rate = number of pages/ time

= 100/2 = 50pages/hour

b. The unit rate = number of points /number of games

= 20/5 = 4 points per game

c. The unit rate = number of car washed/ time

= 40/5 = 8car washed per hour

d. unit rate = number of ounces of peanut/ number of dollars

= 20/2.5 = 8 ounces of peanut per dollar

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The values of f(x) for the given x - values rounded to 4 decimal places are 0.0078, 0.0078, 0.0020, 0.0020, 0.0019 and 0.0013 respectively

Given the function :

Substitute the given value of x to obtain the corresponding f(x) values :

x = -0.6

f(x) = (tanπ(-0.6))/7(-0.6) = 0.0078358

x = -0.51

f(x) = (tanπ(-0.51))/7(-0.51) = 0.0078350

x = -0.501

f(x) = (tanπ(-0.501))/7(-0.501) = 0.001967

x = -0.5

f(x) = (tanπ(-0.5))/7(-0.5) = 0.001959

x = -0.4999

f(x) = (tanπ(-0.4999))/7(-0.4999) = 0.001958

x = 0.499

f(x) = (tanπ(-0.499))/7(-0.499) = 0.001951

x = -0.49

f(x) = (tanπ(-0.49))/7(-0.49) = 0.00188

x = -0.4

f(x) = (tanπ(-0.4))/7(-0.4) = 0.00125

Therefore, values which complete the table are 0.0078, 0.0078, 0.0020, 0.0020, 0.0019 and 0.0013

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No, the rank of the product of two n by n square matrices A and B, denoted as AB, cannot be less than n-1 if both A and B have ranks of n-1.

According to the Rank-Nullity theorem, for any matrix M, the sum of its rank and nullity is equal to the number of columns in M. In this case, the number of columns in AB is n, so the sum of the rank and nullity of AB must be n.

If rank(A) = rank(B) = n-1, it means that both A and B have nullity 1. The nullity of a matrix is the dimension of its null space, which consists of all vectors that get mapped to the zero vector when multiplied by the matrix. Since both A and B have rank n-1, their null spaces consist only of the zero vector.

Now, considering AB, if the rank of AB were less than n-1, it would mean that the nullity of AB is greater than 1.

However, this would violate the Rank-Nullity theorem since the sum of the rank and nullity of AB must be n, which is the number of columns.

Therefore,  if rank(A) = rank(B) = n-1, the rank of AB cannot be less than n-1.

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Due to length restrictions, we kindly invite to read the explanation below to know how the graph of the quartic function is made. Here is a summary:

Zeros: x = - 0.732, x = 0, x = 1, x = 2.732

Critical values: x = - 0.432 (minimum), x = 0.541 (maximum), x = 2.141 (minimum)

Increasing: - 0.432 < x < 0.541 and x > 2.141

Decreasing: x < - 0.432 and 0.541 < x < 2.141

Herein we find the definition of a quartic function, that is, a polynomial with grade 4, of which we must sketch its graph. This can be done from the understanding of the following information:

Zeros

Let be equal the polynomial to zero. All roots can be found by means of numerical methods:

x⁴ - 3 · x³ + 2 · x = 0

x = - 0.732 or x = 0 or x = 1 or x = 2.732

Critical values

Determine the first derivative, equal it to zero and find the roots of the expression:

4 · x³ - 9 · x² + 2 = 0

x = - 0.432 or x = 0.541 or x = 2.141

Determine the second derivative and evaluate it at each root found in previous step:

f''(x) = 12 · x² - 18 · x + 2

x = - 0.432

f''(- 0.432) = 12.015 (MINIMUM)

x = 0.541

f''(0.541) = - 4.226 (MAXIMUM)

x = 2.141

f''(2.141) = 18.469 (MINIMUM)

Finally, find the coordinates of the quartic function:

f(- 0.432) = - 0.587

f(0.541) = 0.693

f(2.141) = - 4.148

Interval behavior

Use the first derivative find the roots of the following inequalities:

Increasing

4 · x³ - 9 · x² + 2 > 0

- 0.432 < x < 0.541 and x > 2.141

Decreasing

4 · x³ - 9 · x² + 2 < 0

x < - 0.432 and 0.541 < x < 2.141

Finally, we build the sketch with the help of a graphing tool.

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Answer:

one number = 3 ; other number = 6

(x = 3 ; y = 6)

Step-by-step explanation:

here is the written problem in an algebraic form:

(x is one number, y is the other number)

x = y - 3          {"if one number is 3 subtracted from the other..."}

x + y = 9         {"The sum of two numbers is 9"}

substitute [x = y-3] into [x + y =9]

x + y = 9 ;   {x = y - 3}

(y - 3) + y = 9  [substitute known x-value into equation]

y - 3 + y = 9

  + 3        + 3  [add 3 to isolate y]

2y = 12

÷2   ÷2           [divide by 2 to find y]

y = 6

Now, by plugging our y-value (6) into one of the equations:

x + y = 9

x + 6 = 9  [substitute the y-value, which we know is 6]

   -6    -6

x = 3    

so, one number is 3, and the other number is 6

Answer:

9

Step-by-step explanation:

first integer = x

second integer = x+2

third integer = x+4

8x=3(x+2+x+4)-4

8x=3(2x+6)-4

8x=6x+18-4

8x=6x+14

2x=14

x=7

second integer=7+2=9

Answer:

So the width of the rectangle is 20 units.

Step-by-step explanation:

Since the area of the rectangle is 80 square units and the length of one side is 4 units, we can use the formula for the area of a rectangle (A = lw) to find the width of the rectangle. We can set up the equation like this:

A = lw

80 = 4w

w = 20

So the width of the rectangle is 20 units. This means that the vertices of one of the sides of the rectangle that represents the width could be (0,0), (0,20), (20,0), and (20,20). These coordinates assume that the lower left corner of the rectangle is at the origin (0,0). If the rectangle is not at the origin, the coordinates of the vertices would be different. For example, if the lower left corner of the rectangle was at (-5,5), the coordinates of the vertices would be (-5,5), (-5,25), (15,5), and (15,25).

Answer:

A=6 should be the answer.

Answer:A

Step-by-step explanation: Count the edges, which is 6

Answer:

x=30,y=165,z=5

Step-by-step explanation:

check it bro

Answer:

go get a 19 dollor fortnite card

Step-by-step explanation:

The number 842 is the number whose digit 4 is ten times larger than in the number 384

To solve the problem, we need to find a number in which the digit 4 is ten times larger than in the number 384.

In the number 384, the digit 4 is in the ones place, which means that its value is 4.

To find a number in which the digit 4 is ten times larger, we need to find a number in which the digit 4 is in the tens place and its value is 10 times larger than 4, which is 40.

The only answer option that fits this description is 842. In this number, the digit 4 is in the tens place and its value is 40, which is ten times larger than its value in the number 384.

Therefore, the correct answer is 842.

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We can claim that after answering the above question, the So, logarithm \(log4 (0.5^(1/2)) =-0.0752\)

The logarithm is a power's reciprocal in mathematics. Accordingly, the exponent by which b must be raised to obtain a number x equals the logarithm of that number in base b. For instance, since 1000 = 103, its base-10 logarithm is 3, or log10 = 3. As an illustration, the base 10 logarithm of 10 is 2, while the square of 10 is 100. Log 100 = 2. To answer a question like, For example, how many times must a base of 10 be multiplied by itself to achieve 1,000, a logarithm (or log) is the mathematical term utilized. The solution is 3 (1,000 = 10 10 10).

Using the following property of logarithms:

\(log_a (b^c) = c * log_a (b)\\log4 (0.5^(1/2))\\(1/2) * log4 (0.5)\\log4 (0.5) = log (0.5) / log (4)\\log (0.5) ≈ -0.3010\\log (4) = 2\)

Therefore,

\(log4 (0.5) ≈ -0.3010 / 2 ≈ -0.1505\\(1/2) * log4 (0.5) ≈ (1/2) * (-0.1505) ≈ -0.0752\\\)

So, \(log4 (0.5^(1/2)) =-0.0752\)

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The appropriate test statistic is approximately 1.89.

To determine if there is evidence that 20 to 29-year-old drivers have a higher mean accident claim compared to 30 to 49-year-old drivers, we can perform a two-sample t-test.

The test statistic can be calculated using the following formula:

\(t = (mean1 - mean2) / \sqrt{(s1^2 / n1) + (s2^2 / n2)}\)

where:

mean1 and mean2 are the sample means of the two populations,

s1 and s2 are the sample standard deviations of the two populations,

n1 and n2 are the sample sizes of the two populations,

Given the following information:

For population 1 (20 to 29-year-old drivers):

Sample mean (mean1) = $4586

Sample standard deviation (s1) = $2302

Sample size (n1) = 40

For population 2 (30 to 49-year-old drivers):

Sample mean (mean2) = $3669

Sample standard deviation (s2) = $2029

Sample size (n2) = 40

Calculate the test statistic (t):

\(t = (4586 - 3669) /\sqrt{ (2302^2 / 40) + (2029^2 / 40))\)

Calculating this expression:

t ≈ 917 / √(132360.1 + 102996.025)

t ≈ 917 / √(235356.125)

t ≈ 917 / 485.086

t ≈ 1.89

Therefore, the appropriate test statistic is approximately 1.89.

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The number of groups, using the combination formula, for each case, is given as follows:

a) Same number of students from each grade: 1,245,816,000

b) At least two grade nine students: 31,650,886,995.

c) James and Lucy are in it: 2,481,256,778.

The number of groups is obtained for the three cases using the combination formula, as the order in which the students are chosen is not important.

\(C_{n,x}\) is the number of different combinations of x objects from a set of n elements, obtained by the following formula, involving factorials.

\(C_{n,x} = \frac{n!}{x!(n-x)!}\)

For item a, the same number of students is taken from each class, hence 3 students are taken from each class, as 12 students are taken from 4 classes, hence 12/4 = 3.

Hence the number of groups, considering the number of students in each class, is of:

\(C_{10,3}C_{11,3}C_{12,3}C_{13,3} = \frac{10!}{7!3!} \times \frac{11!}{8!3!} \times \frac{12!}{9!3!} \times \frac{13!}{10!3!} = 120 \times 165 \times 220 \times 286 = 1,245,816,000\)

For item b, we use complementary events, first obtaining the total number of students that can be taken, and then removing the combinations that do not have at least two grade nine students.

The total number of groups is obtained as follows:

\(C_{46,12} = \frac{46!}{12!34!} = 38,910,617,655\)

(as there are 10 + 11 + 12 + 13 = 46 students, and 12 are taken).

The number of groups with none students from grade 9 is:

\(C_{36,12} = \frac{36!}{12!24!} = 1,251,677,700\)

(removing the 10 students from grade 9).

The number of groups with one student from grade 9 is:

\(C_{10,1}C_{36,11} = 10 \times \frac{36!}{11!25!} = 6,008,052,960\)

(one from grade 10 and the remaining from the other classes).

This the number of groups with at least two grade 9 students is calculated as follows:

38,910,617,655 - (1,251,677,700 + 6,008,052,960) = 31,650,886,995.

For item c, considering Jamie and Lucy in it, the remaining 10 students are taken from a set containing the 44 remaining students, hence:

\(C_{44,10} = \frac{44!}{10!34!} = 2,481,256,778\)

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As a result, the experimental probability of landing on heads is 48%, probability which means that we should expect heads approximately 48 times out of 100 coin flips.

Probability is a measure of the likelihood of an event occurring. It is expressed as a number between 0 and 1, with 0 indicating an unlikely event and 1 indicating an unavoidable event. Because there are two equally likely outcomes, switching a fair coin and coin flips has a probability of 0.5 or 50%. (Either heads or tails). Probability theory, a branch of mathematics, is concerned with the investigation of random events rather than their properties. It is used in a variety of fields, including statistics, finance, science, and engineering.

The following formula can be used to calculate the relative frequency or experimental probability of landing on heads:

Number of Heads / Total Number of Flips = Experimental Probability of Heads

The number of heads in this case is 48, and the total number of flips is 100. Therefore,

Heads Experimental Probability = 48 / 100 = 0.48

We can multiply this by 100 to get a percentage:

Heads Experimental Probability = 0.48 * 100 = 48%

As a result, the experimental probability of landing on heads is 48%, which means that we should expect heads approximately 48 times out of 100 coin flips.

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Answer:

8575 joules

Step-by-step explanation:

We have that the volume is given as follows:

v = 7 * 1 * delta x

v = 7 * delta x

we know that the density: mass / volume

therefore the mass is:

mass = volume * density

replacing:

mass = 7 * delta x * 1000

mass = 7000 * delta x [kg]

now we know that force equals mass * acceleration:

F = 7000 * delta x * 9.8 m / s ^ 2

F = 68600 * delta x [N]

Now, we multiply by x meters, to calculate the work:

W = F * x

W = 68600 * delta x * x

W = 68600 * delta x [J]

We know that the portion of the chian x to x + delta x to be the following

limit when n tends to infinity of the sum of i = 1 up to n = infinity of 68600 * xi * delta x

therefore, the total work done to pump half of the water out of the aquarium is:

To the integral of 68600 * x * dx from 0 to 1/2, applying the integral we have:

68600 * x ^ 2/2 [x = 0 to x = 1/2]

68600 * ((1/2) ^ 2) / 2 - 68600 * (0 ^ 2) / 2 = 8575

That is to say that the work is 8575 joules

Answer:

about 18.85

Step-by-step explanation:

Answer:

Given that the vertices of quadrilateral PQRS are P(6,3), Q(4,2), R(2,4) and S(4,5) and the quadrilateral is dilated with a scale factor of 2, about the origin.

Now, let's find the new vertices of the dilated image:

Vertex P is dilated by a scale factor of 2, its new coordinates will be (2 × 6, 2 × 3) = (12, 6). Therefore, the new vertex P' is at (12, 6).

Vertex Q is dilated by a scale factor of 2, its new coordinates will be (2 × 4, 2 × 2) = (8, 4). Therefore, the new vertex Q' is at (8, 4).

Vertex R is dilated by a scale factor of 2, its new coordinates will be (2 × 2, 2 × 4) = (4, 8). Therefore, the new vertex R' is at (4, 8).

Vertex S is dilated by a scale factor of 2, its new coordinates will be (2 × 4, 2 × 5) = (8, 10). Therefore, the new vertex S' is at (8, 10).

Therefore, the coordinates of the vertices of the final image are P’(12, 6), Q’(8, 4), R’(4, 8), and S’(8, 10).So, the correct option is D. P’(12, 6), Q’(8, 4), R’(4, 8), and S’(8, 10).

Step-by-step explanation:

Hope this helps you!! Have a good day/night!!