Please help!! I already missed two!

The name which is given to the setting in the option profile which  automatically closes any open vulnerabilities on ports that are no longer targeted in your scan job is:

Based on the given question, we can see that in network security, there are certain protocols which has to be followed to ensure that there is security and that unauthorised access does not occur.

As a result of this, the Vulnerability Detection is used to set in the option profile to help to close the open vulnerability on the ports which are not targeted in the scan job.

Therefore, the correct answer is Vulnerability Detection

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Answer:

36

Step-by-step explanation:

square with 4 sides all equal call it a

so (a+5) * (a-3) =84

a²+2a-15=84

solve: a²+2a-99=0

Use the quadratic formula

a = 9 or -11

so a = 9

perimeter of the original square = 4*9 =36

Step-by-step explanation:

come on !

how do you create a line ?

you mark 2 points, take a ruler and draw a line through both points (and extend the line beyond the points as far as the chart goes).

how do you find points ?

you think about a nice value for x (really, any value on the x-axis of the chart is OK) and then calculate y.

you mark the point at this x, y coordinates.

you know, the x-axis is the horizontal coordinate line, and the y-axis is the vertical coordinate line.

so, I would pick x =0. that gives us y = 0 + 0.5 = 0.5.

and maybe x = 2. that gives us y = 2 + 0.5 = 2.5

so, you have (0, 0.5) and (2, 2.5) as points.

and then simply do as described above.

Yes, an edge exists between the vertices representing cities if there is an interstate highway between them.

In a graph representation of cities and interstate highways, the cities are represented by vertices, and the interstate highways are represented by edges. An edge connecting two vertices signifies that there is a direct connection between the cities through an interstate highway.

To determine whether an edge exists between two vertices representing cities, you need to check if there is an interstate highway connecting them. This can be done by consulting a map or transportation database that provides information about the interstate highways connecting different cities.

If you find that there is an interstate highway connecting two cities, you can add an edge between the corresponding vertices in the graph representation. This edge represents the direct connection between the cities through the interstate highway. Conversely, if there is no interstate highway connecting two cities, there will be no edge between the corresponding vertices in the graph representation.

Remember that the presence of an edge between two vertices represents the existence of an interstate highway between the cities they represent in the graph.

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The graph will cross the x-axis if the multiplicity of the real root is odd.

What is polynomial?

In arithmetic, a polynomial is an expression consisting of indeterminates and coefficients, that involves solely the operations of addition, subtraction, multiplication, and positive-integer powers of variables.

Main body:

For polynomials, the graph will cross the x-axis if the multiplicity of the real root is odd, and just touch the x-axis if the multiplicity of the real root is even. (The multiplicity of the root is the number of times it occurs as a root)

(a) y=(x+1)^2(x-2) The graph crosses at x=2 (multiplicity 1) but touches at x=-1 (mulitplicity 2)

(b) y=(x-4)^3(x-1)^2 The graph crosses at x=4 (multiplicity 3) but touches at x=1 (m=2)

(c) y=(x-3)^2(x+4)^4 The graph touches at x=3 and x=-4 as the multiplicities are both even.

The graphs: (a) black, (b) red, (c) green

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The two unit vectors that are orthogonal to both (3, 2, 1) and (-1, 1, 0) are (2/√14, -3/√14, 1/√14) and (1/√2, 1/√2, 0).

To calculate the first unit vector, take the cross product of the two vectors to find the vector that is perpendicular to both.

The vector (2, -3, 1) is the result of the cross product. To normalize the vector to a unit vector, divide each component of the vector by the magnitude, which is the square root of 14.

Therefore, the normalized vector is (2/√14, -3/√14, 1/√14).

To calculate the second unit vector, add the two original vectors together and then normalize the result by dividing each component by the magnitude, which is the square root of 2.

Therefore, the normalized vector is (1/√2, 1/√2, 0).

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The speed of the object is 12121 m per week.

What does it mean to do speed?

The object is moving at a speed of 2 centimeters every 7 seconds.

We need to find the speed in m per week.

2 cm = 0.02 m

1 week = 604800 s

7 s =  \(1.65 * 10^{-6} week\)

Speed = distance/time

So,

\(v = \frac{0.02 m}{1.65 * 10^{-6 } week}\)

\(v = 12121.21 m/ week\)

or v = 12121 m/ week

So, the speed of the object is 12121 m per week.

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Answer:

The table in the top right

Step-by-step explanation:

That table represents the equation y=-2x-1. It is the only table that represents a linear equation.

To be a linear equation it has to consistently add the same amount up and right OR down and right (depending on if it's a positive or negative equation)

I have included a picture of the graph with the equation and all points on it (click/tap on it to see the full picture.)

If this helped please rate, thanks, and mark brainliest :)

The table which represents a linear function is one on the top-right corner.

A linear function is a mathematical relation which is characterized by a constant slope otherwise known as the rate of change of the function.

Upon evaluation of the slope of each table; only the top-right corner table has a constant slope.

Ultimately, a linear function is characterized by a constant slope as observed in the top-right corner table in discuss.

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The implicit solution to the differential equation yy' + x = 3 √(x^2 + y^2) is given by x^2 + y^2 = (x^2 + y^2)^(3/2) + C, where C is a constant of integration.

To solve the given differential equation, we'll rewrite it in a standard form. Dividing both sides of the equation by √(x^2 + y^2), we have yy'/(√(x^2 + y^2)) + x/(√(x^2 + y^2)) = 3. Notice that the left side of the equation represents the derivative of √(x^2 + y^2) with respect to x. Applying the chain rule, we obtain d(√(x^2 + y^2))/dx = 3. Integrating both sides with respect to x, we get √(x^2 + y^2) = 3x + C, where C is a constant of integration.

Squaring both sides of the equation yields x^2 + y^2 = (3x + C)^2. Simplifying further, we have x^2 + y^2 = 9x^2 + 6Cx + C^2. Rearranging the terms, we obtain x^2 + y^2 - 9x^2 - 6Cx - C^2 = 0, which can be rewritten as x^2 + y^2 = (x^2 + y^2)^(3/2) + C. Thus, this equation represents the implicit solution to the given differential equation.

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Answer:

Y + 1 = -2x

Y = -2x - 1

4(-2x-1) + 8x = -4

-8x-4+8x=-4

All I get left with is:
-4 = -4

Not totally sure if this is correct or the answer that you are looking for.

a. Interest of the first year = $26.93

b. Balance after the first year = $1256.93

c. Interest for the second year = $27.52

d. Balance after the second year = $1284.45

Although a part of your question is missing, you might refer to this full question: Gerry deposited $1230 in an account that pays 2.19% simple interest for one year.

a. How much interest will he earn in one year?

b. What will be his balance after one year?

c. Gerry withdraws all of the principal and interest after the first year and deposits into another one-year account at the same rate. What will be his interest for the second year?

d. What will his balance be after two years?

Principal = $1230

Rate = 2.19%

Formula to be used:

Simple interest = (P*R*T)/100

where P = principal

R = rate

T = time in years

Calculating interest for the first year:

S.I = (1230*2.19*1)/100

S.I = 26.93

So, he will earn $26.93 as interest in the first year

And balance after the first year will be $1256.93

Solving for the second year:

P = 1256.93

S.I = (1256.93*2.19*1)/100

= 27.52

So, interest for the second year will be $27.52

And balance after the second year will be $1284.45

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The expected value of this game is 0.5k - 0.5k, which simplifies to 0. This means that on average, you neither win nor lose money in the long run if you keep playing this game. However, it's important to note that in any individual round of the game, you could either win k dollars or lose k dollars. The expected value of this game is (1/2)k dollars.

To calculate the expected value of this game, we need to consider the probabilities and outcomes for each possible result of the coin flip:

1. If the coin comes up heads (probability = 1/2), you win k dollars in addition to getting your k dollars back. The total outcome for heads is 2k dollars.

2. If the coin comes up tails (probability = 1/2), you lose your k dollars. The total outcome for tails is -k dollars.

Now, we can calculate the expected value using the formula:

Expected Value = (Probability of heads * Outcome for heads) + (Probability of tails * Outcome for tails)

Expected Value = (1/2 * 2k) + (1/2 * -k)

Expected Value = k - (1/2)k

Expected Value = (1/2)k

The expected value of this game is (1/2)k dollars.

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the derivative dy/dx is equal to 1/3 based on the given information. It's important to note that this calculation assumes that the partial derivatives (∂F/∂x) and (∂F/∂y) are not zero at the given point (z.y.a).

n the given problem, we have an implicit equation ln(x+y+z) = x+2y+3z that defines z as a function of x and y. We are given the values dy = (-1, 5, -3).

To find the derivative dy/dx, we can use the total derivative formula and apply it to the implicit equation. The total derivative is given by dy/dx = - (∂F/∂x)/(∂F/∂y), where F = ln(x+y+z) - x - 2y - 3z.

Differentiating F partially with respect to x and y, we have (∂F/∂x) = 1/(x+y+z) - 1 and (∂F/∂y) = 1/(x+y+z) - 2.

Plugging in the given values of dy = (-1, 5, -3), we can calculate dy/dx = - (∂F/∂x)/(∂F/∂y) = -(-1)/(5-2) = 1/3.

Therefore, the derivative dy/dx is equal to 1/3 based on the given information. It's important to note that this calculation assumes that the partial derivatives (∂F/∂x) and (∂F/∂y) are not zero at the given point (z.y.a).

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Answer:

Total student= 600

Step-by-step explanation:

Let x be the number of students

\(x \times \frac{80}{100} = 480 \\ = 480 \times \frac{10}{8} \\ x = 600\)

Brainliest please~

Answer:600

Step-by-step explanation:

by taking total number of pupils x

80/100×x=480

48000/80=600

x=600

Answer:

B. y = 30x

Step-by-step explanation:

Answer:

The answer to this problem is B)y = 30x

Step-by-step explanation:

The domain and the range of the function are (-∝, ∝) and (0, ∝), respectively

From the question, we have the following parameters that can be used in our computation:

The graph

The above graph is an exponential function

The rule of an function is that

The domain is the set of all real values

In this case, the domain is (-∝, ∝)

For the range, we have

Range = (0, ∝)

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4. We start with the base case of \(5^0 = 1\) and recursively generate the next element in the set by multiplying the previous element by \(5\).

5. if a divides \(b\) and \(b\) divides \(a\), either a equals \(b\) or \(a\) equals negative \(b\).

4. The recursive definition of the set of positive integer powers of 5 can be expressed as follows:

Base case: \(5^0 = 1\) is in the set.

Recursive step: If n is in the set, then \(5^(n+1)\) is also in the set.

Using this definition, we start with the base case of \(5^0 = 1\)and recursively generate the next element in the set by multiplying the previous element by \(5\).

5. To prove that if a divides \(b\) and \(b\)divides \(a\), then a equals \(b\) or \(a\) equals negative \(b\), we can use the definition of divisibility.

Assume that \(a\) divides \(b\), denoted as \(a | b\) , and \(b\) divides \(a\), denoted as \(b | a.\)

By definition, if a divides b, there exists an integer k such that b = ak.

Similarly, if \(b\) divides \(a\), there exists an integer m such that \(a = bm.\)

Substituting the expression for\(b\) in terms of \(a\), we have \(bm = ak.\)

Dividing both sides by b (since b is nonzero), we get m = a/b.

Since \(m\) is an integer, \(a/b\) must be an integer, which means \(a\) is divisible by \(b\).

If \(a/b\)  is an integer, it implies that \(b/a\)is also an integer, which means \(b\) is divisible by \(a\).

Therefore, if \(a\) divides \(b\) and \(b\) divides \(a\), it follows that \(a/b\) and \(b/a\) are both integers.

If \(a/b = m\) and \(b/a = k\), then we have \(a = bm\) and\(b = ak.\)

\(If m = k = 1, then $a = b.\)

\(If m = k = -1, then a = -b.\)

Therefore, if \(a\) divides \(b\) and \(b\) divides \(a\), either \(a\) equals \(b\) or \(a\) equals negative \(b\).

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The probability of choosing green, yellow, and blue in that order is 1/6, or roughly 0.1667, or 16.67%.

We need to take into account the sample space and tally the number of favourable occurrences in order to calculate the likelihood that William will choose the blocks in the prescribed order (green, yellow, blue).

When William chooses three blocks without replacing them, the sample space depicts every scenario that could occur. Three blocks make up the sample space, which can be listed as follows:

GYB

GBY

YGB YBG BGY

BYG

Only one of the six potential outcomes, GYB, fits the intended sequence.

The result is that there is only one favourable outcome.

Given that there are a total of six options, the likelihood that William would choose the green, yellow.

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When Omar does not have a common factor while factoring a polynomial, he should consider regrouping terms, factoring out a common factor, or adjusting signs to simplify the expression. The absence of a common factor does not necessarily mean the polynomial is prime.

If Omar noticed that he does not have a common factor when factoring a polynomial, there are a few possible next steps to consider. It is important to note that the absence of a common factor does not necessarily mean that the polynomial is prime.

One option for Omar is to go back and regroup the terms in step 1, as (3x³ – 15x²) – (4x + 20). By rearranging the terms, he may be able to identify a common factor or a different factorization approach.

Another possibility is for Omar to factor out a common factor from the first expression in step 2. He can examine the terms in the expression and determine if there is a factor that can be pulled out.

It is also worth considering whether Omar needs to factor out a negative from one of the groups so that the binomials become the same. This step can help simplify the expression and make the factoring process easier.

Overall, Omar should explore different factorization strategies, regroup terms if necessary, and look for common factors or patterns to continue factoring the polynomial. The absence of a common factor does not necessarily imply that the polynomial is prime.

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Answer:

a) 390

b)108

I hope this answer was helpfull for you

Answer:

y= 5 + 0.9x

Step-by-step explanation:

Giving the following information:

NYCab company charges an initial rate of $5.00 for a ride, plus $0.90 for each mile driven.

We need to structure the total cost formula:

y= total cost

x= miles driven

fixed cost= $5

Unitary variable cost= $0.9

y= 5 + 0.9x

The main answer is, tan A + cot A + csc A = -8.9394.

Given A= 86.0, B=15.0, and C= 24.0;To find, tanecot + csc

We know that, cos = -0.10cos A = -0.10

To find sin A; we use the identity;sin^2A + cos^2A = 1

Substituting the value of cos A; we get sin A as;sin^2A + (-0.10)^2 = 1sin^2A = 0.99sin A = ±√0.99

Given sin A is in Quadrant II; hence it is positive,sin A = √0.99sin A = √(9/10)^2sin A = 9/10

Similarly, we know that Tan A is negative in Quadrant II and III.

Tan A = -√(1-cos^2A)/cosA= -√(1-0.01)/(0.10)= -√(99/100)/(10/100)= -√99= -9.95

Given Tan A is negative and Sin A is positive; we know that Cos A is negative and located in Quadrant II; Thus we get Cos A = -√(1- sin^2A)Cos A = -√(1-0.99)Cos A = -√0.01= -0.10

From here, we can find sec A and cot A as;Sec A = -1/Cos A= -1/(-0.10)= 10Cot A = 1/Tan A= 1/(-9.95)= -0.1005Cosec A = 1/Sin A= 1/(9/10)= 1.1111tan A + cot A + csc A= -9.95 - 0.1005 + 1.1111= -8.9394

Therefore, the main answer is, tan A + cot A + csc A = -8.9394.

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Answer:

see attached

Step-by-step explanation:

Answer:

tori

Step-by-step explanation:

Answer:

Step-by-step explanation:

-1+4+4x=83

4x =83-3

4x=80

x=20

Answer:

The answer is A.

Step-by-step explanation:

To find the value you have to know how many hours the repairman took to repair. Then after you find how many hours he took multiply the hours by 35 than add 25.

So the equation would look like  35x hr+25 =

hr=hours

In 7 years, the population of the town will reach 24600.

Formula for population growth can be expressed as;

N = N₀ × e^(rt)

Where N is the future population, N₀ is the initial population, t is time and r is rate of growth.

Given the data in the question;

First, convert the rate from percent to decimal.

Growth rate r = 3%

Growth rate r = 3/100

Growth rate r = 0.03

Now, plug the given values into the above  population growth formula and solve for t.

N = N₀ × e^(rt)

t = ln( N/N₀ ) / r

t = ln( 24600 / 15000  ) / 0.03

t = 17 years.

Therefore, the time required is 7 years.

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Answer:

13

Step-by-step explanation:

Answer:

k

Step-by-step explanation:

yes u smart