PLSSSS NEED HELP ASAP I BEG U

Find m (gradient) and c (y-intercept) for each of the following.

Answer:

43.33%

Step-by-step explanation:

x : 100 = 520 : 1200

x = (520 * 100)/1200

x = 520/12

x = 43.333333%

Yes, whole numbers are closed while adding. As a result, the assertion that is made is true.

In addition, the idea of a set, is being explored. Adding any two members of the set will result in a value that is also a member of the set if the set is closed.

In other words, addition is closed for the set of all numbers.

The addition of the set of positive integers is closed because the sum of any two integers is also an integer.

example,

let W be the set of whole numbers

let ,

a = 7 and b =78

=a+ b

= 7 + 78

=85  which is a whole number

Therefore a , b are closed under addition.

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The correct Answer is D

s1 = s2 and r1 = r2

The two data sets have the same range. The first data set has a range of 88 − 56 = 32, and the second data set has a range of 112 − 80 = 32.

This relationship is sometimes referred to as the range rule for standard deviation. The range rule tells us that the standard deviation of a sample is approximately equal to one-fourth of the range of the data. In other words s = (Maximum – Minimum)/4.

The standard deviation is a more effective measure of variation than the range. Range of the data is a measure of variation which gives the difference in the maximum and the minimum observation of the dataset. It is only based on two observations, the maximum and the minimum.

Alternatively, it can be seen visually that the ranges are the same because the two dot plots are aligned, the scales of the graphs are the same, and the graphs have the same width. The two data sets have different standard deviations. Both dot plots show distributions that have a mean near the center value of the dot plot. The first dot plot shows most values clustered near the mean, while the second dot plot shows most values farther from the mean. Therefore, the standard deviations of the two data sets are not equal—the data represented by the second dot plot has a greater standard deviation.

Choices A, B, and C are incorrect because they incorrectly assert either that the standard deviations are the same or that the ranges are different.

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Answers in bold:

S9 = 2

i = 20

R = -2

=====================================================

Explanation:

\(S_0 = 20\) is the initial term because your teacher mentioned \(A_0 = I\) as the initial term.

Then R = -2 is the common difference because we subtract 2 from each term to get the next term. In other words, we add -2 to each term to get the next term.

Here is the scratch work for computing terms S1 through S4.

\(\begin{array}{|l|l|}\cline{1-2}S_{n} = S_{n-1} - 2 & S_{n} = S_{n-1} - 2\\S_{1} = S_{1-1} - 2 & S_{2} = S_{2-1} - 2\\S_{1} = S_{0} - 2 & S_{2} = S_{1} - 2\\S_{1} = 20 - 2 & S_{2} = 18 - 2\\S_{1} = 18 & S_{2} = 16\\\cline{1-2}S_{n} = S_{n-1} - 2 & S_{n} = S_{n-1} - 2\\S_{3} = S_{3-1} - 2 & S_{4} = S_{4-1} - 2\\S_{3} = S_{2} - 2 & S_{4} = S_{3} - 2\\S_{3} = 16 - 2 & S_{4} = 14 - 2\\S_{3} = 14 & S_{4} = 12\\\cline{1-2}\end{array}\)

Then here is S5 though S8

\(\begin{array}{|l|l|}\cline{1-2}S_{n} = S_{n-1} - 2 & S_{n} = S_{n-1} - 2\\S_{5} = S_{5-1} - 2 & S_{6} = S_{6-1} - 2\\S_{5} = S_{4} - 2 & S_{6} = S_{5} - 2\\S_{5} = 12 - 2 & S_{6} = 10 - 2\\S_{5} = 10 & S_{6} = 8\\\cline{1-2}S_{n} = S_{n-1} - 2 & S_{n} = S_{n-1} - 2\\S_{7} = S_{7-1} - 2 & S_{8} = S_{8-1} - 2\\S_{7} = S_{6} - 2 & S_{8} = S_{7} - 2\\S_{7} = 8 - 2 & S_{8} = 6 - 2\\S_{7} = 6 & S_{8} = 4\\\cline{1-2}\end{array}\)

And finally we arrive at S9.

\(S_{n} = S_{n-1} - 2\\\\S_{9} = S_{9-1} - 2\\\\S_{9} = S_{8} - 2\\\\S_{9} = 4 - 2\\\\S_{9} = 2\\\\\)

--------------------

Because we have an arithmetic sequence, there is a shortcut.

\(a_n\) represents the nth term

S9 refers to the 10th term because we started at index 0. So we plug n = 10 into the arithmetic sequence formula below.

\(a_n = a_1 + d(n-1)\\\\a_n = 20 + (-2)(n-1)\\\\a_n = 20 - 2(n-1)\\\\a_{10} = 20 - 2(10-1)\\\\a_{10} = 20 - 2(9)\\\\a_{10} = 20 - 18\\\\a_{10} = 2\\\\\)

In other words, we start with 20 and subtract off 9 copies of 2 to arrive at 20-2*9 = 20-18 = 2, which helps see a faster way why \(S_9 = 2\)

The scale factor of the segment AB = 2

The segment AB is between (0,2) and (2,3).

It is dilated to get a segment A'B' between (0,4) and (4,6).

A scale factor is a number quantity by which the dimensions of a figure is multiplied to get a dilated or contracted figure.

So here the length of the line segment is multiplied with a scale factor to get new segment A'B'.

Length of AB = √[(2-0)²+(3-2)²] = √5

Length of A'B' = √[(4-0)²+(6-4)²] = √20

So the scale factor = Length of A'B' / Length of AB

                               = √20/√5

                               = 2√5/√5

                               = 2

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If "coffee-shop" is 5 blocks East of Amber's house and park is 3 blocks West of Amber's house, then the distance in blocks between "coffee-shop" to park is 8 blocks.

The distance between the "coffee-shop" and "Amber's house" is 5 blocks to the East, and the distance between the "park" and "Amber's house" is 3 blocks to the West.

To find the distance between the "coffee-shop" and the park, we can add the distances from the coffee shop to Amber's house and from Amber's house to the park:

On adding both the distance ,

We get,

⇒ 5 + 3 = 8,

Therefore, the distance between the coffee shop and the park is 8 blocks.

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Answer:

A

Step-by-step explanation:

The question is actually: 2 \sqrt[3]{x^3} ·\sqrt{16x}

The expression is equivalent to option A, \(\rm 8x \sqrt[6]{x}\).

An expression is a mathematical statement that consists of variables, constants, and mathematical operators.

The expression is \(\rm 2\sqrt[3]{x^2} . \sqrt{16x}\)

The expression can be simplified as

\(\rm = 2 . 4 x^{2/3} x^{1/2}\\\\\=8 x ^{ 7/6}\\\\\\ = 8x x^{1/6}\\\\= 8x \sqrt[6]{x}\)

Therefore, the expression is equivalent to option A, \(\rm 8x \sqrt[6]{x}\).

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A subclass refers to a class that can inherit properties of another class called a superclass. The subclass will have all the characteristics and behavior of the superclass, and it can be modified to meet the unique needs of a specific class. Therefore, if a program uses two classes, airplane, and jumbojet, then the most likely subclass is the jumbojet.

Suppose that the airplane is the superclass that will have all the characteristics and behavior of an airplane. On the other hand, the jumbojet will be the subclass that inherits the features of an airplane. As the subclass, the jumbojet can be modified to have additional features unique to it.

The inheritance concept in programming ensures that there is efficient use of code. It makes it easy to reuse code for creating new classes. When using inheritance, developers avoid copying and pasting code, which can lead to errors and repetition.

Suppose that the airplane and jumbojet are classes representing vehicles in a flight system.

Airplane is the superclass representing all the aircraft, while jumbojet is the subclass representing a specific type of airplane, which is a large passenger aircraft. Therefore, the jumbojet, being a specific type of airplane, is the most likely subclass.

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The magnitude of the centripetal force acting on the ball just prior to the moment of release in the hammer throw event is Fc = (0.730116kg *\(v^{2}\))/m.

To find the magnitude of the centripetal force acting on the ball just prior to the moment of release in the hammer throw event, we can use the principles of circular motion.

The centripetal force required to keep an object moving in a circle is given by the equation Fc = m\(v^2\)/r, where Fc is the centripetal force, m is the mass of the ball, v is the velocity of the ball, and r is the radius of the circle.

In this case, the mass of the ball is given as 7.30 kg, and the radius of the circle is 2.88 m. We need to find the velocity of the ball just prior to the release.

We are given that the ball moves upward on a curved path, which means it has both vertical and horizontal components of velocity. The velocity at the instant of release is directed 36.1 degrees above the horizontal.

To find the horizontal component of velocity, we can use the trigonometric relationship between the angle and the velocity components.

The horizontal component of velocity is given by vh = v * cosθ, where vh is the horizontal velocity and θ is the angle.

Using the given angle of 36.1 degrees, we can calculate the horizontal component of velocity: vh = v * cos(36.1) = v * 0.7986.

Since we don't have the value of v, we need to find it using the world record distance of 86.75 m. The horizontal distance traveled by the ball is equal to the circumference of the circle it moves in. Thus, 2πr = 86.75 m, which gives us r = 13.799 m.

Now, we can find the value of v by dividing the horizontal distance by the time it takes to travel that distance. Let's assume that the ball takes t seconds to complete one revolution.

Therefore, the time it takes to travel the world record distance is t = 86.75 m / (2πr) = 86.75 m / (2π * 13.799 m).

Now, we can calculate the horizontal component of velocity: vh = (86.75 m / t) * 0.7986.

With the horizontal component of velocity known, we can calculate the magnitude of the centripetal force using the formula Fc = m\(v^2\)/r. The magnitude of the centripetal force is Fc = m * (v\(h^2\) + v\(v^2\)) / r, where vv is the vertical component of velocity.

Since the ball is released at ground level, the vertical component of velocity just prior to release is zero. Thus, vv = 0.

Substituting the known values into the formula, we have Fc = 7.30 kg * (v\(h^2\) + 0) / 2.88 m.
Fc = (0.730116kg * \(v^2\)) / m.

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Answer:

sorry but i need the coins on here for school

Step-by-step explanation:

The derivative of the given function is dy/dx = f(x) [4(3x + 1)³ / (3x + 1) . (x - 4) + 4ln(3x + 1) . (x - 4) - 3(2x / (x² + 1)) + (1 / sin(x)) . cos(x)]

To find the derivative of the given function

f(x) = (3x + 1)⁴.(x - 4) / (x² + 1)³. sin(x),

logarithmic differentiation technique will be used.

In logarithmic differentiation, we take the natural logarithm of both sides of a given function, apply the rules of logarithms, and then differentiate both sides with respect to x, and then solve for the derivative.

To apply logarithmic differentiation, we have:

Let y = f(x) = (3x + 1)⁴.(x - 4) / (x² + 1)³. sin(x)

ln(y) = ln(3x + 1)⁴.(x - 4) - 3ln(x² + 1) + ln(sin(x))

Differentiate both sides with respect to x using the chain rule:

1 / y dy/dx = 4(3x + 1)³ / (3x + 1) . (x - 4) + 4ln(3x + 1) . (x - 4) - 3(2x / (x² + 1)) + (1 / sin(x)) . cos(x)

Simplifying the above equation by multiplying throughout by y:

dy/dx = y [4(3x + 1)³ / (3x + 1) . (x - 4) + 4ln(3x + 1) . (x - 4) - 3(2x / (x² + 1)) + (1 / sin(x)) . cos(x)]

f(x) = (3x + 1)⁴.(x - 4) / (x² + 1)³. sin(x)

dy/dy= f(x) [4(3x + 1)³ / (3x + 1) . (x - 4) + 4ln(3x + 1) . (x - 4) - 3(2x / (x² + 1)) + (1 / sin(x)) . cos(x)]

Therefore, the derivative of f(x) is given by:

dy/dx = f(x) [4(3x + 1)³ / (3x + 1) . (x - 4) + 4ln(3x + 1) . (x - 4) - 3(2x / (x² + 1)) + (1 / sin(x)) . cos(x)]

The solution involves logarithmic differentiation technique.

The required derivative is obtained using the chain rule and product rule of differentiation.

The value of y is first taken to be f(x) and then the logarithmic differentiation is applied to find the derivative of f(x).

thus,

dy/dx = f(x) [4(3x + 1)³ / (3x + 1) . (x - 4) + 4ln(3x + 1) . (x - 4) - 3(2x / (x² + 1)) + (1 / sin(x)) . cos(x)]

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To test the series for convergence or divergence using the alternating series test, we must first check if the terms satisfy the conditions of the test. The conditions are:

1. The terms should alternate in sign.
2. The absolute value of the terms should be decreasing.
3. The limit of the absolute value of the terms should be zero as n approaches infinity.

The given series is ∑(sin(n)/2^6^n) from n=0 to infinity. Let's analyze each condition:

1. The terms do not alternate in sign since sin(n) oscillates between -1 and 1, but doesn't consistently alternate between positive and negative values.

Since the first condition is not met, we cannot use the alternating series test to determine the convergence or divergence of this series.

The series can be tested for convergence or divergence using the alternating series test, and the given series isinfinity sin n / 2^(n+1) n=0We can apply the alternating series test to determine the convergence or divergence of the given series. The alternating series test asserts that if a series has alternating signs and if the magnitude of the terms decreases to zero, then the series is convergent.We must first verify that the conditions for the alternating series test are met in order to apply it.1) The sign of the terms alternates between positive and negative:We see that the sign of the terms alternates between positive and negative. The denominator 2^(n+1) increases as n increases, but the numerator sin n is also sinusoidal and oscillates between -1 and 1.2) The absolute value of the terms decreases as n increases:|sin n / 2^(n+1)| = sin n / 2^(n+1) is positive and decreasing as n increases.3) The limit of the absolute value of the terms goes to zero as n goes to infinity:lim(n → ∞) sin n / 2^(n+1) = 0Since the conditions for the alternating series test are met, the series is convergent.

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The p-value is 0.01, which means that it is very rare to observe a test statistic that is equal to or more extreme than the one that was actually observed. SO the option a is correct.

In the given question, in a hypothesis test for population proportion, we calculated the p-value is 0.01 for the test statistic, we have to find which statement of the p-value is correct.

The p-value is the probability of obtaining results as extreme as, or more extreme than, the observed results of a statistical hypothesis test, assuming that the null hypothesis is true. A small p-value (typically ≤ 0.05) indicates strong evidence against the null hypothesis, so you reject the null hypothesis.

A large p-value (> 0.05) indicates weak evidence against the null hypothesis, so you fail to reject the null hypothesis.

If the null hypothesis is correct, the p-value is the likelihood that a test statistic will be equal to or more extreme than the one that was actually observed. Given that the null hypothesis is correct in this situation, the p-value of 0.01 indicates that it is extremely unusual to see a test statistic as dramatic as the one that was actually seen. This shows that the alternative hypothesis is more likely to be correct and that the null hypothesis is probably not true.

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Answer:

4x+y=-4

Step-by-step explanation:

gradient(m)=y2-y1/x2-x1

the line also passes through points (x,y) and (-2,4)

-4=4-y/-2-x

cross multiplying

8+4x=4-y

option(A):4x+y=-4

is your answer.

The storm rainfall flux is 0.00127 m2/hr, 1.27 kg liquid water/m2hr, 2.8 lb liquid water/m2hr, 1.27 liters liquid water/m2hr, and 0.335 gallons liquid water/m2hr. The amount of liquid water fell on the garden is 80.6 L, 21.3 gallons.

Dimensions of outdoor vegetable garden = 2 m × 2 m

Storm rainfall = 0.8 inches of rain

Time of storm = 1 hr(

a) The rainfall flux is the amount of rainfall per unit area and unit time. It is given as:

Rainfall flux = (Amount of rainfall) / (Area × Time)

Given the area of the garden is 2 m × 2 m, and the time is 1 hr, the rainfall flux is:

Rainfall flux = (0.8 inches of rain) / (2 m × 2 m × 1 hr)

Converting inches to meters, we get:

1 inch = 0.0254 m

Therefore,

Rainfall flux = (0.8 × 0.0254 m) / (2 m × 2 m × 1 hr) = 0.00127 m/hr

Converting the rainfall flux to other units:

In kg/hr:

1 kg of water = 1000 g of water

Density of water = 1000 kg/m3

So, 1 m3 of water = 1000 kg of water

So, 1 m2 of water of depth 1 m = 1000 kg of water

Therefore, 1 m2 of water of depth 1 mm = 1 kg of water

Therefore, the rainfall flux in kg/hr = (0.00127 m/hr) × (1000 kg/m3) = 1.27 kg/m2hr

In lbs/hr:

1 lb of water = 453.592 g of water

So, the rainfall flux in lbs/hr = (0.00127 m/hr) × (1000 kg/m3) × (2.20462 lb/kg) = 2.8 lbs/m2hr

In liters/hr:

1 m3 of water = 1000 L of water

So, 1 m2 of water of depth 1 mm = 1 L of water

Therefore, the rainfall flux in L/hr = (0.00127 m/hr) × (1000 L/m3) = 1.27 L/m2hr

In gallons/hr:

1 gallon = 3.78541 L

So, the rainfall flux in gallons/hr = (0.00127 m/hr) × (1000 L/m3) × (1 gallon/3.78541 L) = 0.335 gallons/m2hr

(b) To calculate the amount of water that fell on the garden, we need to calculate the volume of water.

Volume = Area × Depth.

The area of the garden is 2 m × 2 m.

We need to convert the rainfall amount to meters.

1 inch = 0.0254 m

Therefore, 0.8 inches of rain = 0.8 × 0.0254 m = 0.02032 m

Volume of water = Area × Depth = (2 m × 2 m) × 0.02032 m = 0.0806 m3

Converting the volume to other units:

In liters:

1 m3 of water = 1000 L of water

Therefore, the volume of water in liters = 0.0806 m3 × 1000 L/m3 = 80.6 L

In gallons:

1 gallon = 3.78541 L

Therefore, the volume of water in gallons = 80.6 L / 3.78541 L/gallon = 21.3 gallons.

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Answer:

See below ~

Step-by-step explanation:

The given polynomial : -2x + 1 + 2x² needs to be written in the form :

On rewriting in this asked format,

Answer:

Step-by-step explanation:

Exact Form: 6/5

Decimal Form : 1.2
Mixed Number Form : 1 (whole number) 1/5

The correct equation is n + 2.2 = 5 and the value of n is 2.8.

An equation is the statement of two expressions located on two sides connected with an equal to sign. The two sides of an equation is usually called as left hand side and right hand side.

The sum of two and two tenths and a number is five.

Let the number be n.

Sum means the result of adding two numbers.

Two tenths means 2/10.

The sum of two and two tenths and a number means 2 + (2/10) + n.

So we have,

2 + (2/10) + n = 5

(2 + 2/10) + n = 5

[(2 × 10 + 2) / 10] + n = 5

22/10 + n = 5

2.2 + n = 5

n + 2.2 = 5, which is the required equation.

Solving,

n = 5 - 2.2

n = 2.8

Check the value of n = 2.8 in the equation.

n + 2.2 = 2.8 + 2.2 = 5

Hence the equation is n + 2.2 = 5 and the value of n is 2.8.

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Answer:

----------------------------------

Given:

Perimeter is:

or

The perimeter is at most 96 cm (not greater than):

The matching choice is A.

Diverges; the limit of the terms, a_n, is not 0 as n goes to infinity.

To determine whether the geometric series converges or diverges, we need to first identify the general term a_n and the common ratio r. The series is given as:

(5 + 16(-1)n), where n starts from 1.

The general term for this series is

a_n = 5 + 16(-1)^n

Now, we need to find the common ratio r. Since this series is alternating, the common ratio r can be found by dividing the term a_(n+1) by the term a_n:

r = a_(n+1) / a_n

However, the terms of this series do not have a fixed common ratio, as the (-1)n term causes the series to alternate. This means that the series is not a geometric series, and we cannot determine whether it converges or diverges based on a common ratio.

Instead, let's examine the limit of the terms, a_n, as n goes to infinity:

lim (n→∞) a_n = lim (n) [5 + 16(-1)^n]

As n goes to infinity, the term (-1)n will alternate between -1 and 1, and thus the limit does not exist. Therefore, the series diverges.

Answer: Diverges; the limit of the terms, a_n, is not 0 as n goes to infinity.

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A. Johnny's biweekly gross pay is $2,595.23.

B. Johnny's Social Security deduction is 6.2% of his gross pay is $160.90.

C. Johnny's Medicare deduction is 1.45% of his gross pay, which is $37.63.

D. Johnny's new annual salary with a 14.5% raise is $71,179.93.

A. Johnny's biweekly gross pay is $62,285.50 / 24

= $2,595.23.

B. Johnny's Social Security deduction is 6.2% of his gross pay, which is $2,595.23 * 6.2% = $160.90.

C. Johnny's Medicare deduction is 1.45% of his gross pay, which is $2,595.23 * 1.45% = $37.63.

D. Johnny's new annual salary with a 14.5% raise is $62,285.50 * 1.145 = $71,179.93.

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To differentiate F(y) = 1/ y^2 − 9 /y^4 (y + 5y^3), we need to use the quotient rule of differentiation. Your answer: F'(y) = -2y^(-3) - (12y^(-5) + 60y^(-2))(y + 5y^3)

The quotient rule states that the derivative of a quotient of functions is equal to the numerator's derivative multiplied by the denominator minus the denominator's derivative multiplied by the numerator, all divided by the denominator squared.

Using this rule, we can find the derivative of F(y) as follows:

F'(y) = [(d/dy) (1/ y^2) * (y^4(y + 5y^3)) - (d/dy) (y^4(y + 5y^3)) * (1/ y^2)] / (y^4(y + 5y^3))^2

Simplifying this expression, we get:

F'(y) = [(-2y^3(y + 5y^3))/(y^4(y + 5y^3))^2 - (y^4(1 + 15y^2))/(y^2(y^4(y + 5y^3))^2)]

= [(-2y^3(y + 5y^3)) - (y^4(1 + 15y^2))] / (y^6(y + 5y^3))^2

= (-2y^4 - 10y^6 - y^4 - 15y^6) / (y^6(y + 5y^3))^2

= (-3y^4 - 25y^6) / (y^6(y + 5y^3))^2

Therefore, the derivative of F(y) is F'(y) = (-3y^4 - 25y^6) / (y^6(y + 5y^3))^2.
To differentiate the function F(y) = 1/y^2 - 9/y^4 (y + 5y^3), you can apply the power rule and the chain rule.

Your answer: F'(y) = -2y^(-3) - (12y^(-5) + 60y^(-2))(y + 5y^3)

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We need to know about Pythagoras's theorem to solve this problem. The Pythagorean equation for the diagram is given by \(base=\sqrt{(hypotenuse)^{2}-(height)^{2} }\) and the value of  x is 6.71 units.

Pythagoras' theorem is used to find the length of the hypotenuse of a right angled triangle. The Pythagoras' theorem states a relation between the base, height and hypotenuse of a right angled triangle. According to the theorem the sum of the squares of base and height is equal to the square of the hypotenuse. In the given question we have been provided with the height and hypotenuse of the triangle, we have to find x which is the base of the triangle,

\((hypotenuse)^{2} =(base)^{2} +(height)^{2}\)

hypotenuse =9, height =6

base=\(\sqrt{(hypo)^{2} -(height)^{2} } =\sqrt{9^{2}-6^{2} } =\sqrt{81-36} =\sqrt{45} =3\sqrt{5}\)=6.71

The Pythagorean equation for the diagram is \(base=\sqrt{(hypotenuse)^{2}-(height)^{2} }\) and the value of x is 6.71 units.

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The independent variable for Scenario A is given as follows:

a. The employee benefits package.

In the case of a relation, we have that the independent and dependent variables are defined by the standard presented as follows:

In the context of this problem, we have that the input and the output of the relation are given as follows:

Hence the independent variable for Scenario A is given as follows:

a. The employee benefits package.

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The domain of \(tanx\) is \(R - (n\pi -\frac{\pi }{2})\).

The range of the given function \(y = tanx\) is the set of all real numbers.

The domain of a function is the set of values that we are allowed to plug into our function.

The range of a function is the set of its possible output values.

According to the given question.

We have a function

\(y = tanx\)

The above function can be written as

\(y = \frac{sinx}{cosx}\)

⇒ \(tanx\) is defined for all values except the values that makes \(cosx = 0\), a fraction with denominator is not defined.

And we know that

\(cosx = 0 \ \forall \ x \in \frac{(2n+1)\pi }{2} \ where \ n \in Z\)

Hence, for all these values, \(tanx\) is not defined.

Therefore, the domain of \(tanx\) is \(R - (n\pi -\frac{\pi }{2})\).

Since, the domain of  \(tanx\) is \(R - (n\pi -\frac{\pi }{2})\), so when we input these values in the given function we get only real numbers.

Therefore, the range of the given function \(y = tanx\) is the set of all real numbers.

Thus, option D and B are correct.

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Answer:

60 minutes. (1 hour)

Step-by-step explanation:

An average recreational tank containing 200 bars or 12 L of air should last you for 60 minutes. However, several factors come into play while determining the lifespan of a scuba air cylinder. The amount of air that a diver needs depends on their air consumption rate, which in turn is based on their physical exertion level.

Answer: you have to say at what rate. we cant answer this question. there is  part of this question that is missing.

Each flower that Gavin bought will cost $0.875 and the approximate value of each flower will be $0.90

6.5 dozen of carnations = 6 × 12 + 6 (one dozen has 12 units)

(half dozen is half of 12 that is 6)

the total number of flowers Galvin bought = 72 + 6 = 78

total amount Gavin spent on carnations is $68.25

let the amount spent on one flower be x

then the ratio of flower to amount of flowers

ratio = \(\frac{net quantity}{amount}\) = \(\frac{78}{68.25}\) = \(\frac{1}{x}\)

therefore, x = 1 × \(\frac{68.25}{78}\)

x = 0. 875 or 0.88

x ≈ 0.90

∴ the approximate amount spent on one flower is $0.90

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