Problem 5 Data for a local hospital is displayed in the scatter plot. The graph shows the relationship between the length of a person's stay in the hospital in days, , and the amount owed for the hospital bill. The line of best fit for the data is . Find the residuals for the three patients who were in the hospital for 6 days, , , and . Compare the residuals for the three patients. How are they similar? How are they different? What does the information about the residuals for the three patients tell you about their hospital bills?

Answer:

Step-by-step explanation:

Help this person she really needs help! XD

The values of λ are the roots of this equation, denoted by λn. The source function f(r,θ,z) is given by:f(r,θ,z) = -(1/V)∑ n=0∞ [J₀(λn r) / (λn J₁(λn a))]Θn(θ)Zn(z)

Inhomogeneous equation is defined as a linear differential equation whose non-homogeneous part of the equation is equal to a function, that is not equal to 0.

The equation is of the form V(u) = -1, where V is the Laplacian operator. The problem states to solve the inhomogeneous equation V(u) = -1 in an infinite cylindrical region for zero boundary conditions (of first or second kind) and construct the source function.

The solution to this equation is obtained by using the method of separation of variables.In order to use separation of variables method, we will assume that the solution to the equation is of the form u(r,θ,z) = R(r)Θ(θ)Z(z). Substituting this into the equation, we get:

R''ΘZ + RΘ''Z + RΘZ'' = -1

Dividing both sides by RΘZ, we get:

(R''/R) + (Θ''/Θ) + (Z''/Z) = -1/(RΘZ)

Since the left-hand side is independent of r,θ,z, it must be equal to a constant, say -λ². Thus we have:

(R''/R) + (Θ''/Θ) + (Z''/Z) = -λ²

Now we consider the boundary conditions. Zero boundary conditions imply that u(0,θ,z) = u(a,θ,z) = 0. Applying this condition to the solution we obtained, we get:

R(0) = R(a)

= 0

This implies that we must have:

R(r) = J₀(λr)

where J₀ is the Bessel function of order zero. The constant λ is determined by the boundary condition. We get:

J₀(λa) = 0

The values of λ are the roots of this equation, denoted by λn. The source function f(r,θ,z) is given by:

f(r,θ,z) = -(1/V)∑ n=0∞ [J₀(λn r) / (λn J₁(λn a))]Θn(θ)Zn(z)

where J₁ is the Bessel function of order one and Θn(θ)Zn(z) are the corresponding eigenfunctions of the operator.

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Answer:

Yes, but make sure to check with another person to double check.

Good job ;)

Step-by-step explanation:

(None)

The probability of picking a cast member who sold more than 30 tickets is 2/5

Given that one cast member will be picked at random from the 20 cast members who sold tickets to receive a prize. We have to determine the probability of picking a cast member who sold more than 30 tickets.

To find the probability of picking a cast member who sold more than 30 tickets, we need to count the number of cast members who sold more than 30 tickets. Let A be the event of picking a cast member who sold more than 30 tickets. The number of cast members who sold more than 30 tickets is 8. Therefore, P(A) = 8/20 = 2/5.

The probability of picking a cast member who sold more than 30 tickets is 2/5.Answer: 2/5.

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Information is needed to evaluate the project's financial viability, considering factors such as the initial investment, expected cash flows, cost of capital, and project duration.

To calculate the year 1 operating cash flows (OCF), we need to subtract the year 1 costs from the year 1 revenues:

OCF = Year 1 Revenues - Year 1 Costs

OCF = $192,000 - $125,000

OCF = $67,000

To find the depreciation expense in year 3, we need to determine the depreciation method. The provided information is incomplete regarding the depreciation method, so we cannot calculate the depreciation expense in year 3 without knowing the specific method.

The change in Net Working Capital (NWC) in year 2 can be determined by multiplying the Net Working Capital percentage (given as a percentage of t+1 revenues) by the year 1 revenues and subtracting the result from the year 2 revenues:

Change in NWC = (Year 2 Revenues - Net Working Capital percentage * Year 1 Revenues) - Year 1 Revenues

Without the specific Net Working Capital percentage or Year 2 Revenues values, we cannot calculate the exact change in NWC in year 2.

The net cash flow from salvage (ATSV) is calculated by multiplying the Salvage Value percentage by the Initial Cost:

ATSV = Salvage Value percentage * Initial Cost

ATSV = 28% * $390,000

ATSV = $109,200

To calculate the project's NPV, we need the cash flows for each year, the cost of capital, and the project duration. Unfortunately, the information provided does not include the cash flows for each year, so we cannot calculate the project's NPV.

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The complete question is:

Below are your numerical inputs for the problem: 4 & Initial Cost (\$) & 390000 5 & Year 1 Revenues (\$) & 192000 6 & Year 1 Costs (\$) & 125000  7 & Inflation & 2.75% 8 & Project Duration (years) & 6 9 & Depreciation Method & 10 & Tax Rate & 11 & Net Working Capital (\% oft+1 Revenues) & MACRS 12 & Salvage Value (\$) & 28.00% 13 & Cost of Capital & 15.00% & 245000 How much are the year 1 operating cash flows (OCF)? How much is the depreciation expense in year 3 ? What is the change in Net Working Capital (NWC) in year 2? What is the net cash flow from salvage (aka, the after-tax salvage value, or ATSV)? What is the project's NPV? Would you recommend purchasing the ranch? Briefly explain.

Answer: 125/x^18

Step-by-step explanation: this should be the answer

Answer:

\((5 {x}^{ - 6} )^{3} \\ \\ (125 {x}^{ - 18}) \\ \\ = \frac{125}{ {x}^{18} } \)

I hope I helped you^_^

The amount of cashews needed is 15 and that of Brazil nuts is 10.

Here we have to find the number of cashews needed and brazil nuts.

Given data:

Cost of cashews = $7.60

Cost of brazil nuts = $5.10

Total mixture = 25 pound

Let the number of cashews needed to be x.

So by this, we have:

7.6x + 5.1(25 - x) = 6.60 × 25

7.6x + 127.5 - 5.1x = 165

2.5x + 127.5 = 165

2.5x = 37.5

x = 15

cashews = 15 pounds

brazil nuts = 25 - 15 = 10

Therefore the cashews are 15 pounds and brazil nuts are 10 pounds.

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In all cases, we can find a pumped string \(xy^kz\) that does not belong to L₂, which contradicts the assumption that L₂ is regular. Therefore, L₂ is not regular.

To prove that the given languages L₁ and L₂ are not regular using the pumping lemma, we need to show that for any hypothetical regular language L.

There exists a pumping length p such that for any string s in L of length at least p, we can pump s in a way that the pumped string is not in L.

1. L₁ = {\(0^n1^n2^n\) | n ≥ 0, Σ = {0, 1, 2}}

Assume L₁ is regular and let p be the pumping length. Consider the string s = \(0^p1^p2^p\). This string is in L₁ because it has the form \(0^n1^n2^n\), where n = p.

By the pumping lemma, we can decompose s into three parts: s = xyz, such that:

1. |y| > 0

2. |xy| ≤ p

3. For all k ≥ 0, \(xy^kz\) is in L₁.

Let's consider different cases for the possible placement of y in s.

y contains only 0s (\(y = 0^m\), where 1 ≤ m ≤ p).

In this case, when we pump y (k > 1), the number of 0s will exceed the number of 1s and 2s, and hence the pumped string \(xy^kz\) will not be in L₁.

y contains both 0s and 1s (\(y = 0^m1^k\), where 1 ≤ m + k ≤ p).

In this case, when we pump y (k > 1), the number of 0s and 1s will not be balanced with the number of 2s, and hence the pumped string \(xy^kz\) will not be in L₁.

y contains only 1s (\(y = 1^k\), where 1 ≤ k ≤ p).

In this case, when we pump y (k > 1), the number of 1s will exceed the number of 0s and 2s, and hence the pumped string \(xy^kz\) will not be in L₁.

y contains both 1s and 2s (\(y = 1^m2^k\), where 1 ≤ m + k ≤ p).

In this case, when we pump y (k > 1), the number of 1s and 2s will not be balanced with the number of 0s, and hence the pumped string \(xy^kz\) will not be in L₁.

Thus, in all cases, we can find a pumped string \(xy^kz\) that does not belong to L₁, which contradicts the assumption that L₁ is regular. Therefore, L₁ is not regular.

2. L₂ = {ωωω | ω ∈ {a, b}*}

Assume L₂ is regular and let p be the pumping length. Consider the string \(s = a^pb^pa^pb^pa^pb\). This string is in L₂ because it has the form ωωω, where ω = \(a^pb^p\).

By the pumping lemma, we can decompose s into three parts: s = xyz, such that:

1. |y| > 0

2. |xy| ≤ p

3. For all k ≥ 0, \(xy^kz\) is in L₂.

Let's consider different cases for the possible placement of y in s.

y contains only a's (\(y = a^m\), where 1 ≤ m ≤ p).

In this case, when we pump

y (k > 1), the number of a's will exceed the number of b's in the first or second occurrence of ω, and hence the pumped string \(xy^kz\) will not be in L₂.

y contains only b's (\(y = b^m\), where 1 ≤ m ≤ p).

In this case, when we pump y (k > 1), the number of b's will exceed the number of a's in the second or third occurrence of ω, and hence the pumped string \(xy^kz\) will not be in L₂.

y contains both a's and b's (\(y = a^mb^n\), where 1 ≤ m + n ≤ p).

In this case, when we pump y (k > 1), the number of a's or b's will exceed the number of the corresponding symbol in the corresponding occurrence of ω, and hence the pumped string \(xy^kz\) will not be in L₂.

Thus, in all cases, we can find a pumped string \(xy^kz\) that does not belong to L₂, which contradicts the assumption that L₂ is regular. Therefore, L₂ is not regular.

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Complete Question

Use the pumping lemma to prove that the following languages are not regular:

L1 = {0^n 1^n 2^n | n ≥ 0, Σ = {0, 1, 2}}

L2 = {ωωω | ω ∈ {a, b}*}

For each language, apply the pumping lemma to show that there exists a pumping length (p) such that no matter how the string is divided into segments, it is not possible to pump the segments to generate all the strings in the language. This demonstrates that the languages are not regular.

Answer:

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Assuming the time changes at a constant rate, the equation for this is linear (so has the equation y=mx +c)

8am = -2

9am = -0.5

10am = 1.0

11am = 2.5

12pm = 4

m = change in each value or the slope , for this it is m=1.5

c = the y intercept, we find this by: when x=8 y must = 1.5 , which it isn't , y has to = -2 . So c = -3.5

The equation then is: y= 1.5*x - 3.5

The gradient/slope/m value is 1.5. The answer is 1.5

Answer:

Step-by-step explanation:

4x is in a multiplication form

4x=36

meaning a number when multiplied with 4 gives the answer 36

hence in order to find the answer

36 divided by 4 which is equivalent to 9

answer is 9

Answer:  \(x = 9\)

Step-by-step explanation:

We must isolate \(x\) on one side of the equation in order to solve the equation \(4x = 36\) for \(x\).

Step 1: Divide both sides of equation by 4:

\(\frac{4x}{4} = \frac{36}{4}\)

Step 2: Simplify

\(x = 9\)

Therefore, the solution to the equation is \(x = 9\).

----------------------------------------------------------------------------------------------------------

Rearranging an algebraic equation so that \(x\) is on one side and all other terms are on the other side of the equal sign is known as isolating \(x\).

Answer:

8 ''A''-students out of 40 is bigger

Step-by-step explanation:

8 "A"-students out of 40:

\(\frac{8}{40}\) = \(\frac{1}{5}\) = 20%

9 "A"-students out of 50:

\(\frac{9}{50}\) = 18%

20% > 15%

8 ''A''-students out of 40 is bigger

The percentage of 8 ''A'' students out of 40 is more than 9 ''A''-students out of 50.

Given that, to determine which percent is bigger: 8 ''A''-students out of 40 or 9 ''A''-students out of 50.

The percentage is the ratio of the composition of matter to the overall composition of matter multiplied by 100.

Here,
According to the question,
8 ''A''-students out of 40 = 8 / 40 × 100%
                                         = 20%

9 ''A''-students out of 50 = 9 / 50 × 100%
                                         = 18%

Thus, the percentage of 8 ''A'' students out of 40 is more than 9 ''A''-students out of 50.

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The finance charge for the month is $37.31. The daily periodic rate by dividing the monthly periodic rate by the number of days in the billing cycle

To calculate the finance charge for the month, we need to first find the daily periodic rate by dividing the monthly periodic rate by the number of days in the billing cycle. Assuming a standard 30-day billing cycle, the daily periodic rate would be 1.325%/30 = 0.04417%.

Next, we multiply the daily periodic rate by the average daily balance and the number of days in the billing cycle to get the finance charge for the month.

Finance charge = Daily periodic rate x Average daily balance x Number of days
Finance charge = 0.04417% x $2,817.48 x 30
Finance charge = $37.31

Therefore, the finance charge for the month is $37.31.

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The ratio of basketballs to baseballs is 5 : 4 means out of 9 balls there are 5 basketballs and 4 baseballs.

A ratio is a comparison between two similar quantities in simplest form.

Proportions are of two types one is the direct proportion in which if one quantity is increased by a constant k the other quantity will also be increased by the same constant k and vice versa.

Written as quantity₁ ∝ quantity₂ or quantity₁ = kquantity₂

In the case of inverse proportion if one quantity is increased by a constant k the quantity will decrease by the same constant k and vice versa.

quantity₁ ∝ 1/quantity₂.

quantity₁ = K.1/quantity₂.

Given, The ratio of basketballs to baseballs is 5 : 4.

this means out of 9 balls there is 5 basketballs and 4 baseballs.

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The rate of change of an object's velocity with respect to time is defined as acceleration. The speed of a after it has moved 2m starting from rest is 1.98 m/s².

The rate of change of an object's velocity with respect to time is defined as acceleration. Vector quantities are accelerations. The orientation of an object's acceleration is determined by the orientation of its net force.

We can see that the acceleration of 3kg mass is double that of the 8kg mass. Therefore, Writing the force conservation equations altogether,

(T - 3g)/3 = 2(8g - 2T)/8

T= 3.6*g

Now, the Acceleration of 8kg mass can be written as

a = (8g - 2T)/8

  = 0.8g/8

  =0.1g

Therefore, acceleration of mass 3kg = 2×a = 0.2g

Further, as per the law of motion we can write,

v² - u² = 2as

Substituting the values, u =0; a=0.1g; s=2m; we will get,

v=1.98m/s

Hence, the speed of a after it has moved 2m starting from rest is 1.98 m/s².

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The correct option that will make the inequality expression 2x - 3 > 11 - 5x true is when x is equal to 2.

We shall evaluate for the values of x to know that make the inequality expression true as follows;

2x - 3 > 11 - 5x

2x + 5x - 3 > 11 {add the 5x to both sides}

7x > 11 + 3 {add 3 to both sides}

7x > 14

x > 14/7 {divide through by 7}

x > 2

Therefore, the value for x that makes the inequality expression 2x - 3 > 11 - 5x true is 2.

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Answer:

option (1) is a better 18th Birthday gift of child by Grandfather.

Step-by-step explanation:

Amount deposited in bank at time of birth by Grandfather is $100.

And there is no other deposits and withdrawals for 18 years.

So,

                          Principal amount =$100

                                             Time = 18 years

              Rate of interest of bank = 10.5%

Option 1:- An account That grows by 10.5% each year

we know that Bank give compound interest on the deposit amount

then                   Compound interest = C.I=P(1+r) with an exponent of t

                                  C.I= 100(1 + 10.5 over 100)with an exponent of 18

                                  C.I= 100*6.0328

                                  C.I= $603.28

Option 2:- An account that grows by $20 each year

Here,

                   Amount credited in account for 18 years = $20

So,                Total amount after completion of 18 years = 10+18*20

                                                                                         =460

Hope this helped <3

The child turns 18 years old, and the money in the account will be a birthday gift is a better 18th Birthday gift for a child by a Grandfather.

The amount deposited in the bank at the time of birth by Grandfather is $100.

And there is no other deposits and withdrawals for 18 years.

Principal amount =$100

Time = 18 years

Rate of interest of bank = 10.5%

Option 1:- An account That grows by 10.5% each year

We know that Bank give compound interest on the deposit amount

Compound interest = C.I=P(1+r) with an exponent of t

C.I= 100(1 + 10.5 over 100)with an exponent of 18

C.I= 100*6.0328

C.I= $603.28

An account that grows by $20 each year

The amount credited in the account for 18 years = $20

The total amount after completion of 18 years = 10+18*20

 The total amount after completion of 18 years=460                                                                    

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Answer:

1749.6

Step-by-step explanation:

Answer:

jbvfksbvfkfjbfbk

Step-by-step explanation:

ghjkeflj

The response y(t) graphically, we can first plot the individual functions h(t) and x(t) on a graph, and then determine their convolution to obtain y(t). Let's go step by step:

Plotting h(t):

The function h(t) is defined as h(t) = [u(t-1) - u(t-4)].

The unit step function u(t-a) is 0 for t < a and 1 for t ≥ a. Based on this, we can plot h(t) as follows:

For t < 1, h(t) = [0 - 0] = 0

For 1 ≤ t < 4, h(t) = [1 - 0] = 1

For t ≥ 4, h(t) = [1 - 1] = 0

So, h(t) is 0 for t < 1 and t ≥ 4, and it jumps up to 1 between t = 1 and t = 4. Plotting h(t) on a graph will show a step function with a jump from 0 to 1 at t = 1.

Plotting x(t):

The function x(t) is defined as x(t) = t[u(t) - u(t-2)].

For t < 0, both u(t) and u(t-2) are 0, so x(t) = t(0 - 0) = 0.

For 0 ≤ t < 2, u(t) = 1 and u(t-2) = 0, so x(t) = t(1 - 0) = t.

For t ≥ 2, both u(t) and u(t-2) are 1, so x(t) = t(1 - 1) = 0.

So, x(t) is 0 for t < 0 and t ≥ 2, and it increases linearly from 0 to t for 0 ≤ t < 2. Plotting x(t) on a graph will show a line segment starting from the origin and increasing linearly with a slope of 1 until t = 2, after which it remains at 0.

Obtaining y(t):

To obtain y(t), we need to convolve h(t) and x(t). Convolution is an operation that involves integrating the product of two functions over their overlapping ranges.

In this case, the convolution integral can be simplified because h(t) is only non-zero between t = 1 and t = 4, and x(t) is only non-zero between t = 0 and t = 2.

The convolution y(t) = h(t) * x(t) can be written as:

y(t) = ∫[1,4] h(τ) x(t - τ) dτ

For t < 1 or t > 4, y(t) will be 0 because there is no overlap between h(t) and x(t).

For 1 ≤ t < 2, the convolution integral simplifies to:

y(t) = ∫[1,t+1] 1(0) dτ = 0

For 2 ≤ t < 4, the convolution integral simplifies to:

y(t) = ∫[t-2,2] 1(t - τ) dτ = ∫[t-2,2] (t - τ) dτ

Evaluating this integral, we get:

\(y(t) = 2t - t^2 - (t - 2)^2 / 2,\) for 2 ≤ t < 4

For t ≥ 4, y(t) will be 0 again.

Maximum value of y(t):

To find the value of t at which y(t) reaches its maximum value, we need to examine the expression for y(t) within the valid range 2 ≤ t < 4. We can graphically determine the maximum by plotting y(t) within this range and identifying the peak.

Plotting y(t) within the range 2 ≤ t < 4 will give you a curve that reaches a maximum at a certain value of t. By visually inspecting the graph, you can determine the specific value of t at which y(t) reaches its maximum.

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Answer:

b

Step-by-step explanation:

Answer:

1/2

Step-by-step explanation:

in point slope form (y-h) = slope(x-k)

The equation in the slope-intercept form will be y = x/2 + 7/2. Then the slope of the equation is 1/2.

A connection between a number of variables results in a linear model when a graph is displayed. The variable will have a degree of one.

The linear equation is given as,

y = mx + c

Where m is the slope of the line and c is the y-intercept of the line.

The linear equation is given below.

y - 4 = 1/2 (x - 1)

Convert the equation into a slope-intercept form. Then we have

y - 4 = 1/2 (x - 1)

y - 4 = x/2 - 1/2

y = x/2 - 1/2 + 4

y = x/2 + 7/2

The equation in the slope-intercept form will be y = x/2 + 7/2. Then the slope of the equation is 1/2.

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omg what is the......................

Answer:

I Think 2.

Step-by-step explanation:

If im correct pls give brainliest im tired thx! :D

\(\huge\fbox\orange{A} \huge\fbox\red{N}\huge\fbox\blue{S}\huge\fbox\green{W}\huge\fbox\gray{E}\huge\fbox\purple{R}\)

\(\huge\underline\mathsf\colorbox{white}{2}\)

\(\huge\underline\mathtt\colorbox{cyan}{I'm Sure}\)

\(\huge\mathsf\colorbox{white}{}\)

The cost to pay for the gas if this car made a trip of 866 miles cost is $53.31.

A car averages 32 mpg and gas costs $1.97 per gallon.

By unitary method for 866 miles, average would be,

= 866/32

= 27.0625 miles per gallon

and the cost to pay for the gas if this car made a trip of 866 miles would be,

= 27.0625 × $1.97

= $53.31

Therefore, the cost to pay for the gas if this car made a trip of 866 miles cost is $53.31.

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Answer:

2(4x-3)-8=4+8x distribute

8x-6-8=4+8x combine like terms

8x-14=4+8x subtract 8x on both sides

-14=4  semi-answer

answer is no solution

If brainiest is earned its Greatly Appreciated

The Fourier transform of f(t) = cos(24t) * sin(64t) is given by the expression.

To evaluate the function f(t) = cos(24t) * sin(64t) using the Fourier Transform, we can use the Fourier integral pairs and properties.

First, let's write the function in terms of exponential form using Euler's formula:

f(t) = (1/2) * [e^(24it) + e^(-24it)] * (1/2i) * [e^(64it) - e^(-64it)]

Next, we can use the Fourier integral pair for the cosine function:

cos(at) = (1/2) * [e^(iat) + e^(-iat)]

Applying this to our function, we have:

f(t) = (1/4i) * [(e^(24it + 64it) - e^(-24it + 64it)) - (e^(24it - 64it) - e^(-24it - 64it))]

Using the properties of the Fourier Transform, we know that the transform of the sum of functions is equal to the sum of the transforms of each function. Also, the transform of the product of functions is equal to the convolution of their transforms.

Now, let's find the Fourier transforms of the individual exponential terms:

Fourier transform of e^(at):

F{e^(at)} = δ(ω - a) / (2π)

Fourier transform of e^(-at):

F{e^(-at)} = δ(ω + a) / (2π)

Using these results, we can find the Fourier transform of f(t) by applying the properties mentioned above:

F{f(t)} = (1/4i) * [δ(ω - 88) - δ(ω + 40) - δ(ω - 40) + δ(ω + 88)] / (2π)

Simplifying the expression, we get:

F{f(t)} = (1/8iπ) * [δ(ω - 88) - δ(ω + 40) - δ(ω - 40) + δ(ω + 88)]

Therefore, the Fourier transform of f(t) = cos(24t) * sin(64t) is given by the expression above.

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Answer:

1/2

Step-by-step explanation:

The amount of oil required for 1 liter of fuel is 111.11 mL.

Fraction is the portion of a total amount where the above part of the fraction is the denominator and the bottom part of the fraction is called the numerator.

Given that the fuel is the mixture where 8 parts are petrol and 1 part is oil in the whole part of the fuel.

The total part of the fuel is 8+1=9

the portion of the petrol is = parts of petrol/total parts of the fuel= 8/9

the portion of the oil = parts of oil /total parts of the fuel= 1/9

Now we have to calculate the amount of oil required for 1 liter of fuel.

As discussed before, 1/9 parts of the fuel is oil.

So the amount of oil is= (1/9)*1 liter= (1/9)litre= 1/9* 1000 mL= 111.11 mL

Similarly, we can calculate the amount of petrol which will be

the amount of petrol= (8/9)*1 liter= (8/9) liter= 8/9*1000 mL= 888.88 mL

Therefore the amount of oil required for 1 liter of fuel is 111.11 mL.

Learn more about fraction

here: https://brainly.com/question/5091

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