Project One Part Four Problem (9 points) All-American Sports uses operations costing one of its manufacturing divisions

Answers

Answer 1

To calculate the unit product cost for each type of soccer ball (professional and scholastic), we need to determine the direct materials cost and conversion costs associated with each batch. The provided data includes the direct materials costs for each batch and the budgeted conversion costs for the preparation, finishing, and packaging departments.

To calculate the unit product cost for the professional balls (Batch P76), we divide the total cost (direct materials cost + conversion costs) by the number of professional balls (1,000).

Unit product cost for professional balls = ($20,000 + $5,000 + $30,000 + $24,000 + $500) / 1,000

To calculate the unit product cost for the scholastic balls (Batch S43), we divide the total cost (direct materials cost + conversion costs) by the number of scholastic balls (3,000).

Unit product cost for scholastic balls = ($30,000 + $30,000 + $24,000) / 3,000

These calculations will provide the unit product cost for each type of soccer ball.

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# Complete Question:- Project One Part Four Problem (9 points) All-American Sports uses operations costing one of its manufacturing divisions. Conversion costs are accumulated by department, and process-costing methods are used to assign these costs to products. Direct materials costs are accumulated by batch and job order costing is used assign material costs to products. The company produces two different grades of soccer balls: professional balls with genuine leather exteriors and scholastic balls with the use of imitation leather. The cutting and stiching operations for the two different products are identifical. Scholastic balls are sold without special packaging. The professional balls are packaged in an attractive cardboard box. The following represents the data associated with two batches introduced and completed during the month of April. Direct materials costs: Conversion Costs (Budgeted) Batch P76 (1,000 professional balls) $20,000 (includes $5,000 for packaging) Preparation Department $30,000 Batch S43 (3,000 scholastic balls) $30,000 Finishing Department $24,000 Total direct materials costs $50,000 Packaging Department $500 Total Conversion Costs $54,500 Required: Calculate the unit product cost for each type of soccer ball by using Excel formulas with your designated answer in the highlighted cells below. Professional Scholastic Direct materials (Batch P76) Direct materials (Batch S43) Conversion: Preparation Department Conversion: Finishing Department Conversion: Packaging Department Total Product Cost


Related Questions

Which of the following is true of (1, 4) and (1, −7)?

More information is needed to determine the relationship between the two points.

The points lie on a diagonal line.

The points lie on a vertical line.

The points lie on a horizontal line.

Answers

Answer:

The points lie on a vertical line.

Step-by-step explanation:

The x-values in the given two points are the same. If they were graphed and then connected, it would form a vertical line.

[see graph]

So, the points would lie on a vertical line.

Which of the following is true of (1, 4) and (1, 7)?More information is needed to determine the relationship

If a breath
contains about

10^22 molecules

molecules and these molecules of last breath are thoroughly mixed among

10^44 molecules
molecules in the atmosphere, estimate the probability that you are inhaling at least
one of these breath molecules at this moment. You can assume that the
molecules in your breath are inhaled (sampled) sequentially with replacement.

Answers

The probability of inhaling at least one molecule from your last breath is virtually certain, reaching close to 1 or 100%.

The probability of inhaling at least one molecule from your last breath, given that there are approximately 10^22 molecules in your breath and they are thoroughly mixed among 10^44 molecules in the atmosphere, is extremely high. It is essentially certain that you are inhaling at least one of these molecules at any given moment.

The probability of inhaling at least one molecule from your last breath can be calculated by considering the ratio of the molecules in your breath to the molecules in the atmosphere. With approximately 10^22 molecules in your breath and 10^44 molecules in the atmosphere, the probability of inhaling at least one molecule from your last breath can be approximated as 1 - (probability of not inhaling any molecule).

The probability of not inhaling any molecule from your last breath can be calculated by the following formula: (1 - probability of inhaling one molecule)^N, where N is the number of breaths you have taken since your last breath.

However, in this scenario, the number of molecules in the atmosphere is enormously greater than the number of molecules in your breath. This means that even if you take a vast number of breaths, the probability of not inhaling any molecule from your last breath becomes incredibly small, approaching zero. Therefore, the probability of inhaling at least one molecule from your last breath is virtually certain, reaching close to 1 or 100%.

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Find the volume of the solid generated when the region bounded by y=7x and y=21 x

is revolved about the x-axis. Set up the integral that gives the volume of the solid. ∫ 0

11dx (Type exact answers.) The volume of the solid is cubic units. (Type an exact answer.)

Answers

The volume of the solid generated by revolving the region between y = 7x and y = 21x about the x-axis is given by the integral ∫[0,11] 2πx(14x) dx, resulting in a volume of 133100π cubic units.

To find the volume of the solid generated by revolving the region bounded by the curves y = 7x and y = 21x about the x-axis, we can use the method of cylindrical shells. The integral that gives the volume of the solid is:

V = ∫[a,b] 2πx(f(x) - g(x)) dx,

where [a, b] is the interval of x-values over which the curves intersect, f(x) is the upper curve (y = 21x), and g(x) is the lower curve (y = 7x).

In this case, we can find the intersection points by setting the equations equal to each other:

7x = 21x.

Simplifying, we get:

14x = 0.

This equation implies that x = 0. Therefore, the interval of integration is [0, 11] (as stated in the question).

The integral for the volume becomes:

V = ∫[0,11] 2πx(21x - 7x) dx

  = ∫[0,11] 2πx(14x) dx

  = 2π ∫[0,11] 14x^2 dx.

Integrating, we get:

V = 2π [14 * (x^3 / 3)] |[0,11]

  = 2π * 14 * (11^3 / 3 - 0^3 / 3)

  = (308π/3) * 1331

  = 133100π.

Therefore, the volume of the solid generated is 133100π cubic units.

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Find the solution of the differential equation that satisfies the given initial condition. dL dt = kL2 ln(t), L(1) = â10

Answers

The solution of the differential equation satisfying the given initial condition  \(\dfrac{dL}{dt} = k\cdot L^{2} \cdot ln(t)\) is \(L = \dfrac{-1}{ {-k\cdot t\cdot ln(t) - k\cdot t + 10}}\).

A differential Equation is an equation involving derivations of a function or functions.

It is given that the differential equation is

\(\dfrac{dL}{dt} = k\cdot L^{2} \cdot ln(t)\)

The variables can be split apart, and both sides can be integrated. Let's go over each step:

\(\int L^-^2dL = \int k\ lntdt\)

\(\dfrac{-1}{L} = k\cdot t \cdot ln(t) - kt + C\)

\(L = \dfrac{-1}{ {-k\cdot t\cdot ln(t) - k\cdot t + C}}\)

Since L = -10,

therefore, \(C = 10\)

Thus,  \(L = \dfrac{-1}{ {-k\cdot t\cdot ln(t) - k\cdot t + 10}}\) .

Hence, the solution of the given differential equation is \(L = \dfrac{-1}{ {-k\cdot t\cdot ln(t) - k\cdot t + 10}}\).

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Is -3(x+2)=-6-3x no solution ,infinite soultion ,one solution?

Answers

Answer: There are infinite solutions.

Step-by-step explanation:

-3(x+2) = -6-3x

-3x-6 = -6-3x

-6=-6

INFINITE SOLUTIONS

A storage tank consist of a hemisphere and a cylinder which share a common base. The tank has a height of 16.5 m and the cylinder has a base diameter of 4.7m. Find the total capacity of the tank.

Answers

The total capacity of the tank is 272.675 cubic meters.

Given that,

A storage tank consist of a hemisphere and a cylinder which share a common base.

The base of both hemisphere and cylinder will be the same circle with the same radius.

Also, we have,

Height of the tank = 16.5 m

Base diameter of the cylinder = 4.7 m

Radius of the base of the cylinder = 4.7 / 2 = 2.35 m

Radius of the hemisphere = 2.35 m

Height of the cylinder = Total height of the tank - Height or radius of the hemisphere

Total capacity of the tank = Volume of hemisphere + Volume of cylinder

                                          = 2/3 π r³ + π r² h

                                          = 2/3 π (2.35)³ + π (2.35)² (16.5 - 2.35)

                                          = 8.652π + 78.143π

                                          = 272.675 cubic meters

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For the function {(0,1), (1,-3), (2,-4), (-4,1)}, what is the domain and range?


D: {1, -3, -4,}, R: {0, 1, 2, -4}
D:{0, 1, 2, -4}, R:{1, -3, -4}
D:{0, 1, 2, 3, 4}, R:{1, -3, -4}

Answers

I think the second choice has the correct domain and ranges

write the equations of all the circles

write the equations of all the circles

Answers

The equation of a circle with center (a, b) and radius r is:

(x - a)^2 + (y - b)^2 = r^2

(x, y) represents any point on the circle

What is a circle?

A circle is described as a shape consisting of all points in a plane that are at a given distance from a given point, the center.

The properties of the circle are as follows:

The circles are said to be congruent if they have equal radii.The diameter of a circle is the longest chord of a circle.Equal chords of a circle subtend equal angles at the centre.The radius drawn perpendicular to the chord bisects the chord.

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(6x-8)°
(10x + 10)°
What is the value of x?

A. 5
B. 10
C. 13
D. 15

(6x-8)(10x + 10)What is the value of x?A. 5B. 10C. 13D. 15

Answers

The value of x is 13.

The correct option is C.

What is an Inscribed Angle?

An inscribed angle is an angle that an arc at any point on the circle subtends.

Given:
An inscribed angle is (6x-8)°.

And the angle measure of arc GE = (10x + 10)°

So,

m∠(EFG) = 1/2 m∠(GE)

(6x-8)° = 1/2(10x + 10)°

6x - 8 = 5x + 5

x = 13

Therefore, x = 13.

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the given scatterplot shows the average annual global surface temperature, in degrees celsius, for each year from 2000 to 2015. the line drawn is the least squares line for the data set.

Answers

The scatterplot with the least squares line provides insights into the relationship between average annual global surface temperature and the years from 2000 to 2015, allowing us to assess trends, strength of correlation, and make predictions within certain limitations.

The scatterplot represents the relationship between the average annual global surface temperature, in degrees Celsius, and the corresponding years from 2000 to 2015. The line drawn on the plot is the least squares line, which is the best fit line that minimizes the overall distance between the observed data points and the line.

The least squares line is determined using a statistical method called linear regression. It calculates the equation of a straight line that represents the trend in the data. This line serves as a mathematical model to estimate the average temperature based on the year.

By analyzing the scatterplot and the least squares line, we can make several observations. Firstly, we can see whether the temperature has been increasing, decreasing, or remaining relatively stable over the given years. If the slope of the line is positive, it indicates a positive correlation, implying that the temperature has been increasing. Conversely, a negative slope suggests a decreasing trend.

Additionally, we can evaluate the strength of the relationship between temperature and time by examining how closely the data points cluster around the line. If the points are closely grouped around the line, it suggests a strong correlation, indicating that the line is a good representation of the data. On the other hand, if the points are more scattered, the correlation may be weaker.

Furthermore, the line can be used to predict the average annual global surface temperature for future years beyond the data range of 2000 to 2015. However, it's important to note that such predictions should be made with caution and considering other factors that may affect global temperatures, such as climate change and natural variability.

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Question

The given scatterplot shows the average annual global surface temperature, in degrees celsius, for each year from 2000 to 2015. the line drawn is the least squares line for the data set.

All of the following are measures of central tendency except the ________.
Select one:
A. None of the answers are correct
B. mode
C. range
D. mean
E. median

Answers

All of the following are measures of central tendency except the range.

The range is a measure of dispersion, representing the difference between the largest and smallest values in a dataset. It provides information about the spread or variability of the data but does not provide information about the central tendency.

On the other hand, measures of central tendency are statistical measures that aim to summarize the center or typical value of a dataset. They include the mode, median, and mean.

The mode represents the most frequently occurring value(s) in the dataset.

The median is the middle value when the data is arranged in ascending or descending order. It divides the dataset into two equal halves.

The mean is the arithmetic average of all the values in the dataset. It is calculated by summing all the values and dividing by the total number of values.

Therefore, option C, range, is not a measure of central tendency as it focuses on the spread or dispersion of the data rather than summarizing the central or typical value.

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Erin bought 4 jars of jelly and 6 jars of peanut butter for $19.32. Adam bought 3 jars of jelly and 5 jars of peanut butter for $15.67. Find the cost of a jar of peanut butter?

Answers

Answer:

the jar of peanut butter is $2.36

Step-by-step explanation:

Answer: $2.36

Step-by-step explanation:

Consider the equation y = x 2 + 5x – 6. Determine whether the function has a maximum or minimum value. State the maximum of minimum value. What are the domain and range of the function? A min.; 0 C min.; –12.25 D: {all real numbers} D: {all real numbers} R: {all real numbers} R: {y | y ≥ –12.25}

Answers

To determine whether the function y = x^2 + 5x - 6 has a maximum or minimum value, we can use calculus by taking the derivative of the function and setting it equal to zero to find the critical points.

y = x^2 + 5x - 6

y' = 2x + 5

2x + 5 = 0

x = -2.5

Since the derivative is positive to the left of x = -2.5 and negative to the right of x = -2.5, the function has a minimum value at x = -2.5.

To find the minimum value, we can substitute x = -2.5 back into the original equation:

y = (-2.5)^2 + 5(-2.5) - 6 = -12.25

Therefore, the function has a minimum value of -12.25.

The domain of the function is all real numbers, since any real number can be plugged in for x. The range of the function is y | y ≥ -12.25, since the minimum value of the function is -12.25 and the function increases without bound as x approaches infinity.

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an aquarium is 12 decimeters long, 7.5 decimeters wide, and 10 decimeters high. it needs to be filled with 2/3 water. how many cubic decimeters of water is needed to be able to fill the aquarium
ppls help asap

Answers

600 cubic decimeters of water is needed to be able to fill the aquarium.

To calculate the volume of water needed to fill the aquarium, we need to first calculate the total volume of the aquarium. We can use the formula for the volume of a rectangular prism, which is:

Volume = length x width x height

In this case, the length of the aquarium is 12 decimeters, the width is 7.5 decimeters, and the height is 10 decimeters. Therefore, the volume of the aquarium is:

Volume = 12 x 7.5 x 10

Volume = 900 cubic decimeters

Now, we need to find 2/3 of the total volume to determine the amount of water needed to fill the aquarium. We can do this by multiplying the total volume by 2/3:

Water volume = 900 x 2/3

Water volume = 600 cubic decimeters

Therefore, 600 cubic decimeters of water are needed to fill the aquarium with 2/3 water.

In summary, to calculate the amount of water needed to fill the aquarium, we first calculated the total volume of the aquarium using the formula for the volume of a rectangular prism. Then, we multiplied the total volume by 2/3 to find the amount of water needed to fill the aquarium with 2/3 water. The answer is 600 cubic decimeters of water.

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Help please it’s for math I will give you Brainlyist!

Help please its for math I will give you Brainlyist!

Answers

B is correct, mostly because b has the correct answer for the equation as a whole,

En una tienda de antigüedades una lámpara cuesta $1956 que precios representa el 25% y el 50% del precio total

Answers

Answer:

Resultados están más abajo.

Step-by-step explanation:

Dada la siguiente información:

Costo total= $1,956

Para calculate el valor parcial, debemos usar la siguiente información:

Precio proporcional= costo total* ( 1 - porcentaje de descuento)

50%:

Precio proporcional= 1,956*(1 - 0.5)

Precio proporcional= $978

25%:

Precio proporcional= 1,956*(1 - 0.75)

Precio proporcional= $489

What is sextillion divided by nonmillion times 10,000 minus 200 million plus 5000.

Answers

The answer to this arithmetic expression is approximately 9.9998 x 10¹⁸

Define the term expression?

A combination of numbers, variables, and operators that represents a quantity or mathematical relationship is called an expression.

First, divide sextillion (10²¹) by nonmillion (10⁶) to get 10¹⁵.

Next, multiply 10¹⁵ by 10,000 to get 10¹⁹.

Subtract 200 million (2 x 10⁸) from 10¹⁹ to get 9.9998 x 10¹⁸.

Finally, add 5,000 to get the result of approximately 9.9998 x 10¹⁸ + 5,000 = 9.9998 x 10¹⁸ + 0.0005 x 10¹⁸ = 9.9998 x 10¹⁸.

Therefore, the answer to this arithmetic expression is approximately 9.9998 x 10¹⁸

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hi can someone help me with this proof?

hi can someone help me with this proof?

Answers

1월 5일은 꽁꽁꽁꽁꽁꽁꽁꽁꽁꽁꽁꽁꽁꽁꽁꽁꽁꽁\44865

according to a survey of adults, 64% have money in a regular savings account. if we plan on surveying 50 randomly selected adults, find the mean number of adults who would have regular savings accounts.

Answers

By using Binomial probability distribution, the mean number of adults who would have bank savings accounts is 32.

For every survey, there are only two possible outcomes.

First- they have bank savings accounts,

second- they do not.

So, by using the binomial probability distribution we can solve this problem.

Probability of exactly Y successes in ‘n’ repeated trials, with ‘p’ probability.

Probability = p

Successes repeated = n  times

The  value of the binomial distribution is:

E(Y) = n x p

In this problem, we have that:

p = 0.64

If we were to survey among 50 randomly selected adults, the mean number of adults who would have bank savings accounts is,

E(Y) when, n = 50

So,

E(Y)= n x p

= 50 x 0.64

= 32

Hence ,our required answer is 32 adults who would have bank savings accounts

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solve for x -6x+14 <-28 or 9x+15 equal to -12

solve for x -6x+14 &lt;-28 or 9x+15 equal to -12

Answers

Answer:

i think the answer is D. there are no solutions

Answer:

A. x ≤ -3 or x > 7

Step-by-step explanation:

Solve the first equation.

-6x + 14 < -28

Subtract 14 from both sides.

-6x < -42

Divide both sides by -6. REMEMBER: when dividing an inequality by a negative number, flip the sign.

x > 7.

Solve the second equation.

9x + 15 ≤ -12

Subtract 15 from both sides.

9x ≤ -27

Divide both sides by 9.

x ≤ -3.

Your answer is A.

50x3 – 20x + 8x ─ 21x3 – 3x + 15x ─29 x3

Answers

Answer:

0

General Formulas and Concepts:

Algebra I

Combining Like Terms

Step-by-step explanation:

Step 1: Define

50x³ -20x + 8x - 21x³ - 3x + 15x - 29x³

Step 2: Simplify

Combine like terms (x³):                    -20x + 8x - 3x + 15xCombine like terms (x):                     0

Answer:

\(\boxed {\boxed {\sf 0}}\)

Step-by-step explanation:

We are given the expression:

\(50x^3-20x+8x-21x^3-3x+15x-29x^3\)

We want to simplify it, so we must combine the like terms. For this equation, the like terms are terms with x³ or x.

First, combine all the x³ terms.

\((50x^3-21x^3-29x^3)-20x+8x-3x+15x\)

\((0x^3)-20x+8x-3x+15x\)

\(-20x+8x-3x+15x\)

Next, combine all the remaining terms, because they are all terms with an x.

\(-12x-3x+15x\)

\(-15x+15x=0\)

The expression is equal to 0

Find the area of the triangle below:

Find the area of the triangle below:

Answers

Answer:

9 cm^2

Step-by-step explanation:

The area of a triangle is calculated with the following formula:

1/2*b*h (b: base, h: height)

The base is given as 3 and height is 6 so

1/2*3*6 = 9 cm^2 is the answer we are looking for.

Q) Sandhya purchased a bag for ₹2500 inclusive of 8% VAT.Find the price of bag before the VAT.​

Answers

Answer:

sp with vat = Rs. 2500

vat% = 8%

so,

let sp without vat be x

vat amount = vat% of sp

= 8% of x

8x/100

again

sp with vat = sp without vat + vat amount

2500= x + 8x/100

2500=108x/100

250000=108x

x = 2314.81

so, the price if the bag before vat was rs. 2314.81

Suppose U, V and W are finite-dimensional vector spaces and S E L(V, W) and T E L(U, V). Prove that dim(range(ST)) ≤ min{dim(range(S)), dim(range(T))} .

Answers

We have shown that dim(range(ST)) ≤ min{dim(range(S)), dim(range(T))}, as required.

To prove that dim(range(ST)) ≤ min{dim(range(S)), dim(range(T))}, we can use the rank-nullity theorem, which states that:

For a linear transformation T : V → W between finite-dimensional vector spaces V and W, we have:

dim(V) = rank(T) + nullity(T)

where rank(T) is the dimension of the range of T (also known as the rank of T), and nullity(T) is the dimension of the null space of T (also known as the kernel of T).

Using this theorem, we can write:

dim(range(ST)) = rank(ST)

dim(range(S)) = rank(S)

dim(range(T)) = rank(T)

Now, consider the linear transformation ST: U → W. We want to show that dim(range(ST)) ≤ min{dim(range(S)), dim(range(T))}.

We know that the composition of linear transformations satisfies the following property:

range(ST) ⊆ range(S)

This follows from the fact that if v is in U and ST(v) = w, then S(T(v)) = w, so any element in the range of ST is also in the range of S.

Using this property, we have:

rank(ST) = dim(range(ST))

≤ dim(range(S))  (since range(ST) is a subset of range(S))

≤ min{dim(range(S)), dim(range(T))}  (by the definition of minimum)

Therefore, we have shown that dim(range(ST)) ≤ min{dim(range(S)), dim(range(T))}, as required.

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Jeans (x) cost $10, shirts (y) cost $5, and socks (z) cost $3. On Wednesday a store sold a total of 150 items for a total of $900. Of the 150 items solve ; 15 were socks . Which of the following would not be an equation in the system for this situation ?

Answers

Answer:

the answer is 900

Step-by-step explanation:

the 900 will not be necessary

which of the ordered pairs (18,8) , ( 8,18) , (9,4) or (4,9) is a solution to the system of equations

Answers

When we solve the provided question, the equations will be - > x = 1/2 y + 5

What exactly is an equation?

A mathematical equation is a formula that joins two statements and indicates equality with the equal symbol (=). In algebra, an equation is a mathematical statement that establishes the equality of two mathematical expressions. In the equation 3x + 5 = 14, for example, the equal sign separates the variables 3x + 5 and 14. A mathematical formula describes the relationship between the two sentences on either side of a letter. There is commonly only one parameter, which also provides as the symbol. For instance, 2x - 4 = 2.

Here, the equations will be -

x = 1/2 y + 5

2x + 3y = 14

2(1/2y + 5) +3y = -14

y = -6    

and x 2

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The manager of the service department of a local car dealership has noted that the service times of a sample of 15 new automobiles has a standard deviation of 4 minutes. A 95% confidence interval estimate for the variance of service times for all their new automobiles is : ___________

Answers

A 95% confidence interval estimate for the variance of service times for all their new automobiles is (9.29, 31.95).

The 95% confidence interval estimate for the variance of service times for all their new automobiles is calculated as follows:

Lower limit of the confidence interval = (n - 1)S² / χ²₀.₀₂₅

Upper limit of the confidence interval = (n - 1)S² / χ²₀.₉₇₅

Where, n is the sample size, S is the sample standard deviation, and χ² is the chi-square distribution value with degrees of freedom (df) = n - 1. Here, n = 15 and df = n - 1 = 15 - 1 = 14.

So, the chi-square distribution values with df = 14 and α/2 = 0.025 and 1 - α/2 = 0.975 are χ²₀.₀₂₅ and χ²₀.₉₇₅, respectively.

From the chi-square distribution table, we get:

χ²₀.₀₂₅ = 5.632 and χ²₀.₉₇₅ = 25.996.

Now, substituting the given values in the above formula, we have:

Lower limit of the confidence interval = (15 - 1)(4²) / 5.632 = 31.95

Upper limit of the confidence interval = (15 - 1)(4²) / 25.996 = 9.29

Hence, the 95% confidence interval estimate for the variance of service times for all their new automobiles is (9.29, 31.95). Therefore, the answer is  (9.29, 31.95).

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Select all the equations that are true when x = 6. 6x = 12 17 – x = 11 x ÷ 2 = 3 19 ÷ 3 = x 5 + x = 11

Answers

6x = 12

17 – x = 11

x ÷ 2 = 3

5 + x = 11

We are given

x = 6

In case of 1st equation –

\(\qquad\) \(\twoheadrightarrow\bf 6 \times x = 6 × 6 \)

\(\qquad\) \(\twoheadrightarrow\sf 6\times x = 12 \)

\(\qquad\) \(\purple{\twoheadrightarrow\bf L.H.S = R.H.S}\)

Hence, 6x = 12 is true! ☑

In case of 2nd equation –

\(\qquad\) \(\twoheadrightarrow\bf 17 – x = 11 \)

\(\qquad\) \(\twoheadrightarrow\sf 17-x = 17-6 \)

\(\qquad\) \(\twoheadrightarrow\sf 17-x = 11 \)

\(\qquad\) \(\purple{\twoheadrightarrow\bf L.H.S = R.H. S} \)

Hence, 17 – x = 11 is true! ☑

In case of 3rd equation –

\(\qquad\) \(\twoheadrightarrow\bf\dfrac{x }{2} = 3\)

\(\qquad\) \(\twoheadrightarrow\sf \dfrac{x}{2}=\cancel{ \dfrac{6}{2}}\)

\(\qquad\) \(\twoheadrightarrow\sf \dfrac{x} {2}=3\)

\(\qquad\) \(\purple{\twoheadrightarrow\bf L.H.S=R.H.S}\)

Hence, x/2 = 3 is true! ☑

In case of 4th equation –

\(\qquad\) \(\twoheadrightarrow\bf \dfrac{19}{ 3} = x\)

\(\qquad\) \(\twoheadrightarrow\sf \cancel{\dfrac{19}{ 3} }= x\)

\(\qquad\) \(\twoheadrightarrow\sf 6.33= x\)

\(\qquad\) \(\purple{\twoheadrightarrow\bf L.H.S≠R.H.S}\)

Hence, 19/3 = x is false ✖

In case of 5th equation –

\(\qquad\) \(\twoheadrightarrow\bf 5 + x = 11\)

\(\qquad\) \(\twoheadrightarrow\sf 5+ x = 6 +5 \)

\(\qquad\) \(\twoheadrightarrow\sf 5+x= 11\)

\(\qquad\) \(\purple{\twoheadrightarrow\bf L.H.S=R.H.S}\)

Hence, 5+x = 6 is true! ☑

Solve each equation. Check 19. x(x - 32)=0​

Answers

Answer:

x is equal to thirty-two.

Step-by-step explanation:

x(x - 32) = 0

x² - 32x = 0

x - 32 = 0

x = 32

What is the distance from the origin to point P graphed on the complex plane below?

What is the distance from the origin to point P graphed on the complex plane below?

Answers

The distance from the origin to point P graphed on the complex plane is d = \(\sqrt{29}\)

Given,

In the question;

From the figure,

To find the distance from the origin to point P graphed on the complex plane .

Now, According to the question:

To see the graph,

The point P lie on the x- axis and y - axis .

x = 2 and y = -5

We know the formula of distance,

Distance (d) = \(\sqrt{x^{2} +y^2}\)

d = \(\sqrt{2^2 + (-5)^2}\)

d = \(\sqrt{4 + 25}\)

d = \(\sqrt{29}\)

Hence, The distance from the origin to point P graphed on the complex plane is d = \(\sqrt{29}\)

Learn more about Distance of point at:

https://brainly.com/question/12040665

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