Question 3 options:
Triangle ABC is similar to triangle FGH. Given the following angle measures, find the missing angle measures.

m∠A = 48 degrees

m∠B = 35 degrees

Enter your answers as numbers only.

m∠F = _____ degrees
m∠G = _____ degrees
m∠H = _____ degrees
m∠C = _____ degrees

Answer:

8+p

Step-by-step explanation:

add 3 plues 5 and you got ur answer

Answer:

Rectangle

Step-by-step explanation:

It is because the length and breadth are not equal

The value of S, which represents the length of each side of the square, is 4 miles.

To find the value of S, we need to determine the length of each side of the square. Given that the perimeter of the square is 16 miles, we can use the formula for the perimeter of a square, which is 4 times the length of a side.

Perimeter = 4 × S

Given that the perimeter is 16 miles, we can substitute this value into the equation:

16 = 4 × S

To solve for S, we divide both sides of the equation by 4:

16 ÷ 4 = S

4 = S

Therefore, S, which stands for the square's side lengths, has a value of 4 miles.

So, S = 4 miles.

This means that each side of the square measures 4 miles, and the square has equal sides and right angles at each corner.

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The number of dimes are 2 and number of nickels are 8 according to the sum and number of coins.

Let the number of dimes be x. The number of nickels will be 4x. Also, as per the known fact, the value of dimes is 0.1 and value of nickels is 0.05. Keeping the values in formula -

0.05x + 0.1×4x = 0.90

0.05x + 0.4x = 0.90

Performing addition on Left Hand Side of the equation

0.45x = 0.9

Rewriting the equation

x = 0.9/0.45

Performing division on Right Hand Side of the equation

x = 2

Number of dimes = 2

Number of nickels = 4×2

Performing multiplication

Number of nickels = 8

Thus, there 2 dimes and 8 nickles.

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Answer: 0.335

Step-by-step explanation:

all 10 to the 2nd power is its multiplying its self twice so if theirs a 3 its gonna be 10x10x10 i did 33.5 ÷ 100

Answer:

  A: Opposite sides of a parallelogram are congruent

Step-by-step explanation:

The only diagonal involved is BD, so none of the statements regrading diagonals has been proven. The only thing proven is ...

  AB ≅ CD . . . . opposite sides are congruent

  AD ≅ CB . . . . opposite sides are congruent

Answer: 16,000

100,000 x 0.04 x 4

    p         x    I     x T.  

A racecar driver goes around in circles on a racetrack.

The driver that goes around in circles is a racecar driver on a circular racetrack.

In motorsport events like stock car racing or Formula 1, drivers often compete on oval or circular tracks where they make continuous laps around the circuit.

These tracks are specifically designed to allow drivers to navigate the curves and maintain a circular path throughout the race.

The nature of circular tracks requires drivers to master the art of maintaining speed and control while making consistent and precise turns.

They need to find the optimal racing line, which is the most efficient path around the track, to maximize their speed and minimize the time taken to complete each lap.

The driver's skill and strategy play a crucial role in their success on circular tracks.

In addition to professional racing, drivers in amusement park rides such as go-karts or bumper cars also go around in circles as they maneuver the vehicles on circular tracks.

These attractions provide a fun and thrilling experience for participants as they navigate the circular path, often competing with others to reach the finish line or engage in friendly collisions.

Overall, drivers who go around in circles are typically found in racing events or amusement park attractions that involve circular tracks. Their ability to handle the curves and maintain control is essential for their performance and enjoyment of the activity.

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Answer:

True

Step-by-step explanation:

Answer:

A. y = 3/7x

Step-by-step explanation:

Direct variation: y = kx

3 = 7k

k = 3/7

y = 3/7x

a. The solution for x - 3 ≥ 0  is x ≥ 3

b. The solution for 2x + 11 < 3  is x < -4

c. The solution for the quadratic equation is  -1  ≥ x ≥ 2

d. The solution is x < -4/3 or x > 1

a. x - 3 ≥ 0

isolating the variable x

x - 3 ≥ 0

x ≥ 3

b. 2x + 11 < 3

isolating variable x

2x + 11 < 3

2x < 3 - 11

2x < -8

x < -4

c. x² ≥ x + 2

rearranging the quadratic equation

x² - x - 2 ≥ 0

factorizing

(x - 2)(x + 1) ≥ 0

d. x + 4 > 3x²

rearranging the quadratic equation

3x² - x - 4 < 0

factorizing

(x - 1)(3x + 4) < 0

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The 3 solutions to system of equation is graphing , substitution and elimination .

What is equation ?

An equation is a mathematical statement that proves two mathematical expressions are equal in algebra, and this is how it is most commonly used. In the equation 3x + 5 = 14, for instance, the two expressions 3x + 5 and 14 are separated by the symbol "equal."

Equations are mathematical expressions that have two algebraic expressions on either side of an equals (=) sign. The expressions on the left and right are shown to be equal to one another, demonstrating this relationship.

When two expressions are joined by an equal sign, a mathematical statement is called an equation. An equation is something like 3x - 5 = 16. By solving for x, we discover that x equals 7, which is the value for the variable.

There are three methods used to solve systems of equations: graphing, substitution, and elimination.

To solve a system by graphing, you simply graph the given equations and find the point(s) where they all intersect. The coordinate of this point will give you the values of the variables that you are solving for. This is most efficient when the equations are already written in slope-intercept form.

The next method is substitution. Substitution is best used when one of the equations is in terms of one of the variables such as y=2x+4, but the equations can always be manipulated. The first step in this method is to solve one of the equations for one variable. Once an expression for the variable is found, substitute or plug in the expression into the other equation where the original variable was to solve for the number value of the next variable. The final step is to substitute the number value that was found in for its corresponding variable in the original equation.

The third method is elimination. Elimination is adding the equations together in order to create an equation with only one variable. This can only be done when the coefficients of one variable in both equations are opposites and will cancel each other out once added together. Elimination is best used when this is already occurring in the equations, but the equations can also be manipulated into creating common coefficients by either multiplying or dividing equations by a certain number. The next step would be to use the equation that we created to find the value of the variable and then plug that value back into an original equation to find the remaining variable.

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Answer: Linear equations in two variables. If a, b, and r are real numbers (and if a and b are not both equal to 0) then ax+by = r is called a linear equation in two variables. (The “two variables” are the x and the y.) The numbers a and b are called the coefficients of the equation ax+by = r.

Step-by-step explanation:

Answer:

see below

Step-by-step explanation:

It's an equation that has two variables

that's to say it has x and y (generally)

it is linear when you graph it, it forms a line and that only happens when the mayor exponent is one

so

\((something_1)x^{1}+(something_2)y^{1} =(something_3)\)

notice all the something are completely different

or you could find it as

\(y=mx+b\)

where m is the slope

and b some number

so that's it

Answer:

D 10/18

Step-by-step explanation:

when you divide the top and bottom by 2, you get 5/9 which is 5:9 not 5:8

Answer:

10 out of 18 as it is giving 5:9

Answer:

36

Step-by-step explanation:

(1/3)x - (1/4)x = 3

multiply by 12 to clear the fraction

4x - 3x = 36

x = 36

The given initial value problem represents a second-order linear homogeneous differential equation, where coefficient of derivative is 1 and the coefficient of first derivative is 0. current I(t) in LC series as a function of time t circuit is = \((-8/19)cos(19t) + (27/19)sin(19t) for 0 ≤ t ≤ 2π.\)

Thus, the characteristic equation of the differential equation is given by \(λ^2 + 361 = 0\). Solving the characteristic equation, we get two complex roots \(λ = ±19i.\)

Therefore, the general solution of the differential equation is given by I(t) = \(c1cos(19t) + c2sin(19t)\), where c1 and c2 are constants determined by the initial conditions. Differentiating the general solution with respect to t, we get \(I'(t) = -19c1sin(19t) + 19c2cos(19t).\)

Using the initial condition I'(0) = 27, we get 27 = 19c2. Therefore, c2 = 27/19. Now, to determine c1, we need to use the initial condition I(0) = 1 and the given function g(t).

When \(0 ≤ t ≤ 2π, g(t) = 135sin(3t)\). Therefore, we have\(I(0) = c1cos(0) + c2sin(0)\) = c1 = 1 - c2 = 1 - 27/19 = -8/19. Thus, the current I(t) in LC series circuit is given by \(I(t) = (-8/19)cos(19t) + (27/19)sin(19t) for 0 ≤ t ≤ 2π.\)

When t > 2π, g(t) = 0 and the current will continue to oscillate with the same frequency and amplitude, but with different initial conditions determined by the values of I(2π) and I'(2π).

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100% of the F2 generation plants are expected to be tall and produce round fruit.

The given information suggests that F1 and F1 represent heterozygous tall and round plants, respectively. When these two genotypes are crossed, we can predict the possible genotype and phenotype combinations of the offspring by using a Punnett square.

The Punnett square for this cross would be:

F1     F1

F2 F1F1 F1F1

F1F1 F1F1

From this square, we can see that all of the F2 generation plants will be homozygous for both tallness and roundness. This is because the F1 generation is heterozygous for both traits, so when they are crossed, the recessive alleles are masked by the dominant alleles.

Therefore, the genotype of all F2 plants will be F1F1, and they will all be tall and round.

In summary, 100% of the F2 generation plants are expected to be tall and produce round fruit.

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Answer:

c

Step-by-step explanation:

Answer:

v=lxbxh

v=5x5x5

v=125cm

volume b

v=lxbxh

v=5x5x5

v=125cm

volume A+volume B

125+125=150

Step-by-step explanation:

you find the first one first then you find the second one then you add

Answer:

First cube

\( = {125}^{3} \)

second cube

\( = {125}^{3} \)

125 +125=250

Step-by-step explanation:

The formulas to find the volume of a cube are:

V = s3, where s is the edge length of the cube.

\(v = 5 \times 5 \times 5 = {125}^{3} \)

Answer:

9 IS THE ANSWER

Step-by-step explanation:

3*3=9

R = 9, F = 4, S = 2, R = 9, F = 3, S = 3, R = 8, F = 5, S = 2, R = 8, F = 4, S = 3, R = 7, F = 5, S = 3, R = 6, F = 5, S = 4
These are the only six possible combinations that meet the criteria of Rover being the oldest, Spot being the youngest, and their ages adding up to 15.

What is combinations?

Combinations, in mathematics and combinatorial theory, refer to the selection of items from a larger set without considering their order.

Let's use the following variables to represent the ages of the dogs:

F = age of Fido
S = age of Spot
R = age of Rover
We know that Rover is the oldest, so R must be greater than or equal to both F and S. Also, Spot is the youngest, so S must be less than or equal to both F and R. Finally, we know that the sum of their ages is 15, so:

F + S + R = 15

To list all the different combinations of ages, we can use trial and error and logic to narrow down the possibilities. Here are all the possible combinations:

R = 9, F = 4, S = 2
R = 9, F = 3, S = 3
R = 8, F = 5, S = 2
R = 8, F = 4, S = 3
R = 7, F = 5, S = 3
R = 6, F = 5, S = 4
These are the only six possible combinations that meet the criteria of Rover being the oldest, Spot being the youngest, and their ages adding up to 15.

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Answer:

Step-by-step explanation:

To get the length of segment HJ if H lies at (-1,7) and J lies at (8,-5)​, we will use the formula for calculating the distance between two points as shown;

D = √(x₂-x₁)²+(y₂-y₁)²

From the coordinates x₁ = -1, y₁ = 7, x₂ = 8, y₂ = -5

HJ = √(8-(-1))²+(-5-7)²

HJ = √(8+1)²+(-12)²

HJ = √81+144

HJ = √225

HJ = 15

Hence the length of segment HJ is 15 units

The root of the graph of function f(x) = (x-5)³(x+2)² touch the x-axis at -2 and 5.

Given that,

The function is f(x)= (x-5)³(x+2)²

We have to find at which root does the graph function touch the x-axis.

We know that,

Mathematical calculus' core component is functions. The unique forms of relationships are the functions. When it comes to arithmetic, a function is represented as a rule that produces a different result for each input x.

Take the function

f(x) = (x-5)³(x+2)²

f(x) = 0 if a curve touches the x-axis.

⇒ (x - 5)³(x + 2)² = 0.

But if ab = 0

So, a=0 and b=0

⇒ (x - 5)³ = 0 and (x + 2)² = 0

⇒ (x - 5) = 0 and x + 2 = 0

⇒ x=5 and x=-2.

Therefore, The root of the graph of function f(x) = (x-5)³(x+2)² touch the x-axis at -2 and 5.

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The given differential equation is, \($$\frac{d^5y}{dx^5}-\frac{d^4y}{dx^4}-\frac{d^3y}{dx^3}+\frac{d^2y}{dx^2}=3$$[/tex based on given details.

The characteristic equation is given as:

A differential equation is a type of mathematical equation that connects the derivatives of an unknown function. The function itself, as well as the variables and their rates of change, may be involved. These equations are employed to model a variety of phenomena in the domains of engineering, physics, and other sciences.

Depending on whether the function and its derivatives are with regard to one variable or several variables, respectively, differential equations can be categorised as ordinary or partial.

Finding a function that solves the equation is the first step in solving a differential equation, which is sometimes done with initial or boundary conditions. There are numerous approaches for resolving these equations, including numerical methods, integrating factors, and variable separation.

\($$m^5-m^4-m^3+m^2=0$$ $$\implies m^2(m^3-m^2-m+1)=0$$\)

Solving the cubic factor, $m^3-m^2-m+1=0$ by synthetic division, we get,\($$(m-1)(m^2-m-1)=0$$\)

Therefore the characteristic equation is given as,\($$m^2(m-1)(m^2-m-1)=0$$\)

Hence the general solution is given by\($$y=C_1+C_2x+C_3e^x+C_4e^{-\frac{1}{2}x}(cos\frac{\sqrt{3}}{2}x+sin\frac{\sqrt{3}}{2}x)+C_5e^{-\frac{1}{2}x}(cos\frac{\sqrt{3}}{2}x-sin\frac{\sqrt{3}}{2}x)$$\)

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Answer: 3x=-3

Step-by-step explanation:

Answer:

pi=22/7

2pi=44/7

5pi+1=110/7+1=117/7

pi to the second power=22/7 times 22/7=484/49

Hope this helps, but I don't know.

Answer:

hi

Step-by-step explanation:

Answer:

\(5\sqrt{2}+\sqrt{10}\)

Step-by-step explanation:

\(\sqrt{5}(\sqrt{10}+\sqrt{2}) \\ \\ =\sqrt{50}+\sqrt{10} \\ \\ =5\sqrt{2}+\sqrt{10}\)