Answer:
Arranging from longest (at top) to shortest (at bottom)
DF
EF
DE
Step-by-step explanation:
We need to place the sides of triangle DE, DF and EF from longest to shortest.
The triangle has longest side that is opposite to the largest angle
We know two angles < E= 61° , <F= 59° we need to find <D
Sum of angles of triangle = 180°
So, 61°+59°+<D=180°
120°+<D=180°
<D=180°-120°
<D=60°
So, the largest angle is <E= 61°
The longest side must be opposite to <E so, the side is DF
The second largest angle is <D=60° so, second side will be EF
The smallest angle is <F=59° so, third (shortest) side will be DE
Arranging from longest (at top) to shortest (at bottom)
DF
EF
DE
Select the correct answer. in what year did feminists first propose the era? a. 1891 b. 1923 c. 1954 d. 1965 e. 1982
Answer: b. 1923
Step-by-step explanation:
Rewrite the equation so it does not have fractions. 5-3/4x=3/8
Answer: 6x=37
Step-by-step explanation: Because it is.
3.
A pitcher has 17. 6 fluid ounces of iced tea in it. Erin pours
12. 06 fluid ounces of tea into a glass to drink. How many fluid ounces
of tea remain in the pitcher? Show how to solve the problem
by adding on
5.56 fluid ounce of tea remain in the pitcher
In mathematics, a variable is an alphabet that represent an unknown number. We let required amount as variable and then try to calculate its value
According to the question,
Total ounces of iced tea a pitcher contains = 17.6 fluid ounces
Amount of tea Erin pours to drink = 12.06 fluid ounces
Let "x" fluid ounce of tea remain in the pitcher
So , total was 17.6
=> x + 12.06 = 17.6
Solving for x
Subtracting by 12.06 both the sides
=> x + 12.06 - 12.06 = 17.6 -12.06
=> x = 5.56 fluid ounce
Hence , 5.56 fluid ounce of tea remain in the pitcher
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You withdraw $375 from your bank account. You receive a stack of 24 bills consisting of $5, $10, and $20 bills. The number of $5 bills is one-half the number of $10 bills. How many of each type of bill do you receive?
The first thing I did to solve this was notice that since the ones place of the withdrawal was a 5, there had to be an odd number of 5s. Also, the amount of 10s has to be even, so there has to be an odd number of 20s. Then I started trying combinations.
3,6,15 = 15+60+300=375
Hey, I got lucky! I got it first try!
You get three 5-dollar bills, six 10-dollar bills, and 15 20-dollar bills.If the circumference of a circle is 5π what is the radius?
PLEASEEEEEEEE HELP
Factor the expression.
5x^2+32x+35
the Answer:
\((5x+7)(x+5)\)
Step-by-step explanation:
The picture below shows you step-by-step process.
Brainliest please!
Please make sure you answer both parts of the question. Remember to properly format your function.The hat that George bought turned out to previously belong to a magician! Initially, 3 rabbits hopped out of the hat. Each day after that, double thenumber of rabbits from the previous day appeared.1: Write an exponential function that can be used to model this function.2: How many rabbits appeared on the 13th day?
Solution
Question 1:
\(\begin{gathered} \text{ On day 1, 3 rabbits hopped out} \\ \text{ On day 2, }3\times2=6\text{ rabbits hopped out} \\ \text{ On day 3, }3\times2\times2=3\times2^2\text{ rabbits hopped out} \\ \text{ On day 4, }3\times2\times2\times2=3\times2^3\text{ rabbits hopped out} \\ \\ \text{Following this pattern, we can find the number of rabbits that will hop out on a day n.} \\ \\ \text{ On day }n,3\times2\times2\times2\ldots\times2=3\times2^{n-1}\text{ rabbits hopped out} \\ \\ \text{Thus, the exponential function to model this scenario is given below as } \\ \\ f(n)=3\times2^{n-1} \end{gathered}\)Question 2:
\(\begin{gathered} \text{The question is asking for the number of rabbits that will hop out on day 13} \\ \text{ We can simply apply our formula and this implies that }n=13 \\ \\ \therefore f(13)=3\times2^{13-1} \\ \\ f(13)=3\times2^{12}=12,288 \\ \\ \text{Thus, the number of rabbits that will hop out of the hat on the 13th Day is 12,288} \end{gathered}\)Final Answer
Question 1:
The exponential function to model the scenario is
\(f(n)=3\times2^{n-1}\)
Question 2:
The number of rabbits that will hop out of the hat on the 13th Day is 12,288 rabbits
as we go to high numbers of segments, if we double the number if segments in composite rectangle rule integration, we expect the error to be multiplied by approximately what? group of answer choices 1/2 1/4 2 4
As we go to high numbers of segments, if we double the number of segments, the error is to be multiplied by 1/4
The inaccuracy should often reduce as we increase the number of segments in the composite rectangle rule integration. In particular, with the composite rectangle rule, we estimate the error to be roughly increased by 1/4 if the number of segments is ideally doubled.
Because of this, the composite rectangle rule's error, which is determined by the formula (b-a)/n. In the given equation, b denotes upper bound of integration, a denotes lower bound of integration, and n denotes total number of segments, which is inversely proportional to the width of the segments. The width of the segments changes to (b-a)/(2n), which is half of their initial width, when the number of segments is doubled. Thus, the mistake should be multiplied by 1/4 or split by 4.
Complete Question:
As we go to high numbers of segments, if we double the number if segments in composite rectangle rule integration, we expect the error to be multiplied by approximately what?
a. 1/2
b. 1/4
c. 2
d. 4
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Lance bought 15 sets of 3 tennis balls. Some of the tennis balls, t, were lost during each of the 4 matches he played. Now, the are 37 tennis balls left. Which equation represents this situation?
the area of the u.s. is about 3.859 million square miles. approximately 590000 square miles are worked for food production. what percent of the u.s. is worked for food production? round your answer to the nearest tenth of a percent.
Consider the problem min X1 X2 subject to x1 + x2 ≥ 4 X2 ≥ X1 Which one is the local extremizer point? O [1,3]
O [2,3] O [3,3] O [1,2] O [1,1] O [2,1] O [2,2] O [0,4]
To find the local extremizer point that minimizes the expression X1X2, subject to the constraints x1 + x2 ≥ 4 and x2 ≥ x1, we need to evaluate the objective function for different points that satisfy the constraints. The local extremizer point is [2,2].
To determine the local extremizer point, we consider the objective function X1X2 and the constraints x1 + x2 ≥ 4 and x2 ≥ x1.
Let's evaluate the objective function for different points that satisfy the constraints: For [1,3]: X1X2 = 1 * 3 = 3
For [2,3]: X1X2 = 2 * 3 = 6
For [3,3]: X1X2 = 3 * 3 = 9
For [1,2]: X1X2 = 1 * 2 = 2
For [1,1]: X1X2 = 1 * 1 = 1
For [2,1]: X1X2 = 2 * 1 = 2
For [2,2]: X1X2 = 2 * 2 = 4
For [0,4]: X1X2 = 0 * 4 = 0
Among these points, [2,2] yields the minimum value of 4 for the objective function while satisfying both constraints. Therefore, the local extremizer point that minimizes the expression X1X2 is [2,2]. Hence, the correct answer is O [2,2].
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Louie Corporation has two departments to manufacutre its product --Assembly and Finishing. The company used the following data at the beginning of the year to calculate predetermined overhead rates: Assembly Finishing Total Estimated total machine-hours (MHs) 4,000 1,000 5,000 Estimated total fixed manufacturing overhead cost $ 25,000 $ 3,700 $ 28,700 Estimated variable manufacturing overhead cost per MH $ 1.00 $ 2.00 During the most recent month, the company started and completed two jobs--Job A and Job M. There were no beginning inventories. Data concerning those two jobs follow: Job A Job M Direct materials $ 15,100 $ 8,800 Direct labor cost $ 22,000 $ 9,000 Assembling machine-hours 2,700 1,300 Finishing machine-hours 400 600
Assume that the company uses a plantwide predetermined manufacturing overhead rate based on machine-hours. The total manufacturing cost assigned to Job M is closest to: (Round your intermediate calculations to 2 decimal places.)
The total manufacturing cost assigned to Job M is closest to $17,801.20.
To calculate the total manufacturing cost assigned to Job M, we need to consider the predetermined overhead rate based on machine-hours for the Finishing department.
Given:
Estimated variable manufacturing overhead cost per MH for Finishing department = $2.00
Finishing machine-hours for Job M = 600
We can calculate the predetermined overhead cost for Job M using the formula: Predetermined overhead rate * Finishing machine-hours.
Predetermined overhead rate for the Finishing department:
Estimated variable manufacturing overhead cost per MH for Finishing department / Estimated total machine-hours for the Finishing department
= $2.00 / 1,000
= $0.002 per machine-hour
Predetermined overhead cost for Job M:
Predetermined overhead rate * Finishing machine-hours
= $0.002 * 600
= $1.20
Therefore, the total manufacturing cost assigned to Job M, considering direct materials cost, direct labor cost, and overhead cost, is:
Total manufacturing cost = Direct materials cost + Direct labor cost + Predetermined overhead cost
= $8,800 + $9,000 + $1.20
= $17,801.20
The total manufacturing cost assigned to Job M is closest to $17,801.20.
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Lola likes to knit slippers and donate them to a nursing home. She has a bag of 60 pom-
poms in different colors that she puts on the top of the slippers. She randomly selects some
pom-poms from the bag to use. The table below shows the colors she selects.
Color Number
purple 4
orange
N
9
pink
yellow
5
Based on the data, estimate how many orange pom-poms were in the bag of 60 pom-poms.
If necessary, round your answer to the nearest whole number.
orange pom-poms
Submit
There were approximately 9 orange pom-poms in the bag.
How to estimate orange pom-poms?To estimate the number of orange pom-poms, we can use the proportion of orange pom-poms in the sample to the total sample size, and set it equal to the proportion of orange pom-poms in the bag to the total number of pom-poms in the bag.
Let x be the number of orange pom-poms in the bag. Then we have:
orange proportion in sample = 9/60 = 0.15
orange proportion in bag = x/60
Setting these two proportions equal, we get:
0.15 = x/60
Solving for x, we get:
x = 0.15 x 60
x = 9
Therefore, there were approximately 9 orange pom-poms in the bag.
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To estimate the number of orange pom-poms in the bag of 60, we use the ratio of selected orange pom-poms to the total number of pom-poms selected.
Explanation:To estimate the number of orange pom-poms in the bag of 60, we need to find the ratio of orange pom-poms to the total number of pom-poms selected. The table shows that Lola selected 9 orange pom-poms out of a total of 18 pom-poms. We can use this ratio to estimate the number of orange pom-poms in the bag by setting up a proportion:
Orange pom-poms in bag / Total pom-poms in bag = Orange pom-poms selected / Total pom-poms selected
By substituting the known values into the equation and solving for the unknown, we can estimate the number of orange pom-poms in the bag.
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What’s the term for 5 _ 13
The nth term for the given series is given by 4n-3.
What is meant by series?
The fundamental concepts in mathematics are series and sequence. A series is the total of all elements, but a sequence is an ordered collection of elements for which repetitions of any kind are permitted. One of the typical examples of a series or a sequence is a mathematical progression. A series can be finite or infinite in length and has a length that corresponds to the number of terms.The number series is 1, 5, 9, 13, 17,...
Common deviation (d)=5-1=4
A=1 is the first phrase.
A+(n1)d=1+(n1) is the formula for the nth term.
4=4n−3
∴tn =4n−3
The nth term for the given series is given by 4n-3.
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It costs $3 for children and $7 for adults to attend a school basketball game. If 5000 people attended the game and the total takings at the door was $25000, determine the number of children and the number of adults that attended the game, using simultaneous elimination.
Answer:
2500 children and 2500 adults
The number of children is 2500 and the number of adults that attended the game is also 2500.
System of equations:Let us consider that, number of children be x and number of adults be y that attend game.
Since, total 5000 people attend the game.
\(x+y=5000\\\\x=5000-y..........(1)\)
It costs $3 for children and $7 for adults and the total takings at the door was $25000
\(3x+7y=25000 .............(2)\)
Substitute value of x from equation 1 into equation 2.
\(3(5000-y)+7y=25000\\\\15000-3y+7y=25000\\\\4y=10000\\\\y=10000/4=2500\)
So that, \(x=5000-2500=2500\)
Thus, the number of children is 2500 and the number of adults that attended the game is also 2500.
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Help help help help help
Answer:
i dont now
Step-by-step explanation:
inde man kona ka balo sorry
Answer:
quadrant 1 and quadrant IV
Step-by-step explanation:
(a)
secθ > 0 in quadrants 1 and IV
sinθ > 0 in quadrants 1 and II
Thus θ is in quadrant I
(b)
cosθ > 0 in quadrants I and IV
cotθ < 0 in quadrants II and IV
Thus θ is in quadrant IV
Please Help Quick ASAP Hurry
Find the constant of variation for the relationship shown in the following table:
x 1 2 3 4
y 4 8 12 16
A. 1
B. 2
C. 3
D. 4
Answer:
vfca
Step-by-step explanation:
vaddavavthui sn fa
Determine if the expression 10b^2 + b^3/6+ b^5 is a polynomial or not. If it is a polynomial, state the type and degree of the polynomial.
Answer:poly of 5
Step-by-step explanation:
mono
Drag the tiles to the boxes to form correct pairs. Not all tiles will be used. Match the resulting values to the corresponding limits.
The correct solution to the limits of x in the tiles can be seen below.
\(\mathbf{ \lim_{x \to 9^+} (\dfrac{|x-9|}{-x^2-34+387}) }\)\(\mathbf{ = -\dfrac{1}{52} }\)\(\mathbf{ \lim_{x \to 8^-} (\dfrac{8-x}{|-x^2-63x+568|}) }\)\(\mathbf{=\dfrac{1}{79} }\)\(\mathbf{ \lim_{x \to 7^+} (\dfrac{|-x^2-17x+168| }{x-7}) }\)= -31 \(\mathbf{ \lim_{x \to 6^-} (\dfrac{|x-6| }{-x^2-86x+552}) }\)\(\mathbf{ =\dfrac{1}{98}}\)What are the corresponding limits of x?The limits of x approaching a given number of a quadratic equation can be determined by knowing the value of x at that given number and substituting the value of x into the quadratic equation.
From the given diagram, we have:
1.
\(\mathbf{ \lim_{x \to 9^+} (\dfrac{|x-9|}{-x^2-34+387}) }\)
So, x - 9 is positive when x → 9⁺. Therefore, |x -9) = x - 9
\(\mathbf{ \lim_{x \to 9^+} (\dfrac{x-9}{-x^2-34+387}) }\)
Simplifying the quadratic equation, we have:
\(\mathbf{ \lim_{x \to 9^+} (-\dfrac{1}{x+43}) }\)
Replacing the value of x = 9
\(\mathbf{ = (-\dfrac{1}{9+43}) }\)
\(\mathbf{ = -\dfrac{1}{52} }\)
2.
\(\mathbf{ \lim_{x \to 8^-} (\dfrac{8-x}{|-x^2-63x+568|}) }\)
-x²-63x+568 is positive when x → 8⁻.Thus |-x²-63x+568| = -x²-63x+568
\(\mathbf{ \lim_{x \to 8^-} (\dfrac{1}{x+71}) }\)
\(\mathbf{=\dfrac{1}{8+71} }\)
\(\mathbf{=\dfrac{1}{79} }\)
3.
\(\mathbf{ \lim_{x \to 7^+} (\dfrac{|-x^2-17x+168| }{x-7}) }\)
x -7 is positive, therefore |x-7| = x - 7\(\mathbf{ \lim_{x \to 7^+} (\dfrac{-x^2-17x+168 }{x-7}) }\)
\(\mathbf{ \lim_{x \to 7^+} (-x-24)}\)
\(\mathbf{ \lim_{x \to 7^+} (-7-24)}\)
= -31
4.
\(\mathbf{ \lim_{x \to 6^-} (\dfrac{|x-6| }{-x^2-86x+552}) }\)
x-6 is negative when x → 6⁻. Therefore, |x-6| = -x + 6\(\mathbf{ \lim_{x \to 6^-} (\dfrac{-x+6 }{-x^2-86x+552}) }\)
\(\mathbf{ \lim_{x \to 6^-} (\dfrac{1}{x+92}) }\)
\(\mathbf{ \lim_{x \to 6^-} (\dfrac{1}{6+92}) }\)
\(\mathbf{ =\dfrac{1}{98}}\)
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You and your friends decide to play video games online together for 5 hours on Saturday. This particular game charges a one-time $10 fee to download and $2.50 per hour to play.
Write the function that can be modeled by this situation.
Answer:
f(x) = 10 + 2.50x
Step-by-step explanation:
Let the total hours played be 'x' hours.
To find the charge for playing 'x' hours, multiply x by 2.50.
Charge for an hour = $2.50
Charge for 'x' hours = 2.50*x
= $ 2.50x
To find the total cost, add one time charge with the cost charged for playing ''x'' hours.
Total cost = one-time charge + charge for 'x' hours
f(x) = 10 + 2.50x
x = 5 hours,
f(5) = 10 + 2.50 * 5
= 10 + 12.50
= $ 22.50
They have to pay $ 22.50 for playing 5 hours.
Solve each equation or inequality.
|2 x|+4<7
3/2 < x <3/2 is the inequality for the equation |2 x|+4<7
For positive case
⇒ |2 x|+4 < 7
⇒ 2 |x| < 3
⇒ x < 3/2
And for negative case
⇒ x > -3/2
Thus, -3/2 < x <3/2
How to solve an equation?To solve linear equations, utilize the steps that are provided below.
Remove parentheses from each side of the equation and combine similar terms to make it simpler.To separate the variable term on one side of the equation, use addition or subtraction.To find the variable, use division or multiplication.The common denominator can be multiplied by each side of the equation to eliminate fractions.Lets take an example of solve z for 7z – (3z – 4) = 12
Here is no multiplication or division, so this will be easy to solve
⇒ 7z – (3z – 4) = 12
⇒ 7z – 3z + 4 = 12
⇒ 4z = 12 – 4
⇒ 4z = 8
⇒ z = 8/4
⇒ z = 2
See, that was so simple, using the mentioned methods, every linear equation can be solved easily.
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May I please receive help?
Answer:
∠x = 40°
Step-by-step explanation:
In Δ ABC
AB = AC
∠BAC = ∠ACB (angles opposite to equal sides are equal)
∠ACB = 35°
so in Δ ABC
∠ACB + ∠CBA + ∠BAC = 180°
35 + ∠CBA + 35 = 180
∠CBA = 180 - 70
∠CBA = 110
In ΔBCD
BC = CD
∠CBD = ∠CDB (opposite sides are equal)
∠CBD + ∠CBA = 180
∠CBD = 180 - 110
∠CBD = 70
∠CBD = ∠CDB = 70°
In Δ BCD
∠CBD + ∠BDC + ∠x = 180
70 + 70 + ∠x = 180
∠x = 40°
I think this is the answer....hope it helps
How many more times more intense is an earthquake that measures 8 on the Richter scale than an earthquake that measures 5? Explain your answer.
Answer:
1000 times more powerful
Step-by-step explanation:
Each level n the scale is 10 times more intense than the previous, (10 * 10 * 10 = 1000) hence, 8 on the richter scale is 1000 times more intense than a 5 on the scale.
Hope this helped :)
PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER!!
Answer:
Option C, 93.6 mi³
Step-by-step explanation:
Volume of the triangular prism,
base area × height
= (8×3.9/2)×6
= 93.6 mi³
3) Tell whether the matrices are inverses of
each other.
2 3
7 11
and
11 -3
-7 2
Can someone help me with this question?
Use the graph of the sine function y = 2 sin θ shown below.
a. How many cycles occur in the graph?
b. Find the period of the graph.
c. Find the amplitude of the graph.
a. There are 2 cycles in the graph.
b. The period of the graph is 360 degrees.
c. The amplitude of the graph is 2.
a. To determine the number of cycles in the graph, we need to count the number of complete repetitions of the pattern. In this case, there are 2 complete repetitions, so there are 2 cycles.
b. The period of a sine graph is the distance it takes to complete one full cycle. In this graph, one full cycle is completed in 360 degrees, so the period is 360 degrees.
c. The amplitude of a sine graph is the distance from the midline to the maximum or minimum point of the graph. In this case, the amplitude is 2 units. y = 2 sin θ.
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The value x = 42 is a solution to the equation 7 = x/6
Answer:
Yes
Step-by-step explanation:
The value x = 42 is a solution to the equation 7 = x/6.
Answer:
whats your question i dont get it
Step-by-step explanation:
so then 7=42/6 which is 7=7 so True or Yes
If f(1)=6,f ′is continuous, and ∫ 18 f ′ (t)dt=14, what is the value of f(8)?
The value of \( f(8) \) is 6.To find the value of \( f(8) \) given that \( f(1) = 6 \), \( f' \) is continuous, and \( \int 18 f'(t) \, dt = 14 \), we can apply the Fundamental Theorem of Calculus.
The Fundamental Theorem of Calculus states that if \( F \) is an antiderivative of \( f \), then \( \int_a^b f(x) \, dx = F(b) - F(a) \). By integrating both sides of the equation \( \int 18 f'(t) \, dt = 14 \) and applying the Fundamental Theorem of Calculus, we can determine the value of \( f(8) \).
Let \( F(t) \) be the antiderivative of \( f'(t) \). By the Fundamental Theorem of Calculus, we have \( \int 18 f'(t) \, dt = 18F(t) + C \), where \( C \) is the constant of integration. Given that \( \int 18 f'(t) \, dt = 14 \), we can write the equation as \( 18F(t) + C = 14 \).
Since \( f'(t) \) is continuous, we can apply the Mean Value Theorem for Integrals, which states that if \( f(x) \) is continuous on \([a, b]\), then there exists a \( c \) in \([a, b]\) such that \( \int_a^b f(x) \, dx = (b - a) \cdot f(c) \). In our case, \( \int_a^b f(x) \, dx = 14 \), and since the interval is not specified, we can consider \( a = 1 \) and \( b = 8 \). Therefore, \( \int_1^8 f(x) \, dx = 7 \cdot f(c) \), where \( c \) is in \([1, 8]\).
Using the connection between \( f \) and \( F \) from the Fundamental Theorem of Calculus, we can rewrite the equation as \( 18F(c) + C = 14 \). Since \( F(c) \) is the antiderivative of \( f \), we can say that \( F(c) = f(c) \).
Substituting this into the equation, we get \( 18f(c) + C = 14 \). Since \( f(1) = 6 \), we know that \( f(c) = f(1) = 6 \). Substituting this value into the equation, we have \( 18 \cdot 6 + C = 14 \), which simplifies to \( C = 14 - 108 = -94 \).
Now, we can evaluate \( f(8) \) using the Fundamental Theorem of Calculus. We have \( 18f(8) + C = 14 \), and substituting the value of \( C \), we get \( 18f(8) - 94 = 14 \). Solving for \( f(8) \), we find \( f(8) = \frac{14 + 94}{18} = \frac{108}{18} = 6 \). Therefore, the value of \( f(8) \) is 6.
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A company has two large computers. The slower computer can send all the company's email in minutes. The faster computer can complete the same job in minutes. If both computers are working together, how long will it take them to do the job
Both the computers will take 18 minutes to do the job together.
The slower computer sends all the company's email in 45 minutes.
The faster computer completes the same job in 30 minutes.
Let's take minutes t to complete the task together.
As they complete one job, we get the following equation:
\(\frac{t}{45}\)+\(\frac{t}{30}\)=1
LCM of 45 and 30 is:
45 = 3 x 3 x 5
30 = 2 x 3 x 5
LCM = 2 x 3 x 3 x 5 = 90
Now, solving for t;
⇒\(\frac{2t+3t}{90} = 1\\\frac{5t}{90} =1\\5t=90\\\)
Dividing both sides by 5;
\(\frac{5t}{5}=\frac{90}{5}\)
We get t = 18
Hence, it will take both the computers 18 minutes to do the job together.
A company has two large computers. The slower computer can send all the company's emails in 45 minutes. The faster computer can complete the same job in 30 minutes. If both computers are working together, how long will it take them to do the job?
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