Question: Which of the following pairs of compounds would you expect to form homogeneous solutions when combined? a)CH3CH2CH2CH2CH3 AND CH3CH2CH2CH2CH2CH3 b) ...

Option B is correct. benzene (C6H6). Pentane is an aliphatic hydrocarbon with only nonpolar C-C and C-H bonds, making it a nonpolar solvent. Its chemical formula is C₅H₁₂.

Benzene (C₆H₆) is also a nonpolar compound, consisting of a hexagonal ring of carbon atoms with hydrogen atoms attached. The carbon-carbon (C-C) bonds and carbon-hydrogen (C-H) bonds in benzene are nonpolar, resulting in a nonpolar molecule.

On the other hand, pentanol (C₅H₁₁OH), acetic acid (C₂H₄O₂), and ethyl methyl ketone (C₄H₈O) contain polar functional groups such as hydroxyl (-OH), carboxyl (-COOH), and carbonyl (-CO-) groups, respectively. These polar functional groups create polarity within the molecules.

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Yes, the provisions of Section 300.21 from the National Electrical Code (NEC) are designed to prevent the spread of fire and products of combustion within a building. These provisions apply to the installation of electrical conductors, raceways, and cables, including Chapter 8 articles.

Chapter 8 articles mainly cover communications systems, such as telephone, radio, television, and broadband communications. It is essential to follow Section 300.21 provisions for firestopping and fire-resistant construction when installing these systems to ensure the safety and integrity of the building and its occupants.

In summary, the provisions of 300.21 do apply to Chapter 8 articles, emphasizing the importance of maintaining fire safety standards when installing communication systems and other electrical components.

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Answer:

Option D, Plate Tectonics

In the rock cycle, surface events takes place at the surface of earth. Thus,

weathering and erosion are surface events, while the subsurface events he take place in the deeper section of the earth . Examples of sub surface events are plate tectonics and mountain building or anything that takes place in the inner core of earth.

Explanation:

Answer:

Option D, Plate Tectonics

In the rock cycle, surface events takes place at the surface of earth. Thus,

weathering and erosion are surface events, while the subsurface events he take place in the deeper section of the earth . Examples of sub surface events are plate tectonics and mountain building or anything that takes place in the inner core of earth.

Explanation:

Option D, Plate Tectonics

In the rock cycle, surface events takes place at the surface of earth. Thus,

weathering and erosion are surface events, while the subsurface events he take place in the deeper section of the earth . Examples of sub surface events are plate tectonics and mountain building or anything that takes place in the inner core of earth.

Answer:

36°C

Explanation:

Given parameters:

Mass of aluminum = 725g

Quantity of heat  = 2.35 x 10⁴J

Unknown:

Temperature change  = ?

Solution:

To solve this problem, we simply use the expression below:

  The quantity of energy is given as:

          Q  = m C Δt

Q is the quantity of energy

m is the mass

C is the specific heat capacity of aluminum  = 0.9J/g°C

Δt is the change in temperature

  The unknown is Δt;

             Δt  = \(\frac{Q}{mc}\)    = \(\frac{2.35 x 10^{4} }{725 x 0.9}\)    = 36°C

The correct statement is: For equal concentrations and equal path lengths, solutions of (+) and (-) enantiomers rotate plane-polarized light equally, but in opposite directions.

This is known as optical rotation, which is the phenomenon of rotating the plane of polarized light by chiral compounds. Enantiomers are mirror images of each other and have equal and opposite specific rotations. The (+) enantiomer rotates plane-polarized light clockwise and the (-) enantiomer rotates it counterclockwise by the same amount. Therefore, their optical rotations cancel out in equal concentrations and equal path lengths, resulting in no net rotation of the plane of polarized light.

Compounds with R stereocenters do not necessarily rotate plane-polarized light clockwise. The direction of optical rotation depends on the absolute configuration of the molecule and not just the R or S designation.

Racemic mixtures have equal amounts of both enantiomers, which cancel out each other's optical rotations and result in no net rotation of the plane of polarized light.

Meso compounds do not rotate plane-polarized light because they have an internal plane of symmetry that cancels out the optical rotation of each half of the molecule.

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Answer:

The answer is C

Explanation:

Your answer is C because car pollutants going into the air isn't good at all

The mathematical expression for h is v²/(2g) which is based on conservation of energy and the correct option is option B.

The law of conservation of energy states that energy can neither be created nor be destroyed. Although, it may be transformed from one form to another.

Example, when a fruit is falling to the bottom, potential energy is getting converted into kinetic energy.

Conservation of energy implies

KEinitial = PEfinal

mv²/2 = mgh

therefore, h = v²/2g.

Thus, the ideal selection is option B.

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Answer:

Wavelength of electromagnetic wave = 4.0 × 10³

Explanation:

Given:

Wavelength of electromagnetic wave = 4000 meter

Find:

Write, Wavelength of electromagnetic wave into scientific notation

Computation:

Wavelength of electromagnetic wave = 4000 meter

Wavelength of electromagnetic wave = 4.0 × 1,000 meter

Wavelength of electromagnetic wave = 4.0 × 10³

So,

Option "B" is the correct answer to the following question.

For standard 1, the volume of stock solution required is 2.00 mL, while for standard 2, it is 4.00 mL.

In order to calculate the volume of 0.0315 m Bromocresol green (HBCG) standard stock solution required to make 10.00 ml of the three standards, we need to use the formula:

M1V1 = M2V2

Where M1 is the concentration of the stock solution,

V1 is the volume of the stock solution required,

M2 is the concentration of the final solution, and

V2 is the final volume of the solution.

To calculate the volume of 0.0315 m Bromocresol green (HBCG) stock solution required to make 10.00 ml of 0.00630 m Bromocresol green (HBCG) standard 1, we can plug in the values into the formula as:

M1V1 = M2V2V1 = (M2V2)/M1= (0.00630 mol/L x 0.01000 L)/0.0315 mol/L= 0.00200 L = 2.00 mL

Therefore, the volume of 0.0315 m Bromocresol green (HBCG) stock solution required to make 10.00 ml of 0.00630 m Bromocresol green (HBCG) standard 1 is 2.00 mL.

To calculate the volume of 0.0315 m Bromocresol green (HBCG) stock solution required to make 10.00 ml of 0.0126 m Bromocresol green (HBCG) standard 2, we can use the same formula as above:

M1V1 = M2V2V1 = (M2V2)/M1= (0.0126 mol/L x 0.01000 L)/0.0315 mol/L= 0.00400 L = 4.00 mL

Therefore, the volume of 0.0315 m Bromocresol green (HBCG) stock solution required to make 10.00 ml of 0.0126 m Bromocresol green (HBCG) standard 2 is 4.00 mL.

In conclusion, we can use the formula M1V1 = M2V2 to calculate the volume of 0.0315 m Bromocresol green (HBCG) stock solution required to make different standards.

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A buffer solution is made by mixing 375 ml of 0.25 m hf and 225 ml of 0.50 m naf. The ph of:

the original buffer solution is: 3.24,

the solution after adding 0.018 mol of KOH to the original buffer solution is: 9.85,

the solution after adding 12.5 ml of 1.25 m HI to the original buffer solution is 0.88.

A buffer solution is created by combining a weak acid and its conjugate base, which together maintain a relatively constant pH despite the addition of small amounts of acid or base. In this question, 375 mL of 0.25 M HF and 225 mL of 0.50 M NaF are mixed together to form the buffer solution.

The pH of the original buffer solution can be calculated using the Henderson-Hasselbalch equation, which states that \(pH = pKa + log([A-]/[HA]).\)

In this case, [A-] is the concentration of the conjugate base (NaF) and [HA] is the concentration of the weak acid (HF). Plugging in the values given, the pH of the original buffer solution is 3.24.

After adding 0.018 moles of KOH to the original buffer solution, the pH can be calculated using the same Henderson-Hasselbalch equation. Since KOH is a strong base, the concentration of the conjugate base (NaF) increases and the concentration of the weak acid (HF) decreases. Plugging in the values, the pH of the solution after the addition of KOH is 9.85.

After adding 12.5 mL of 1.25 M HI to the original buffer solution, the pH can be calculated using the Henderson-Hasselbalch equation. Since HI is a strong acid, the concentration of the conjugate base (NaF) decreases and the concentration of the weak acid (HF) increases. Plugging in the values, the pH of the solution after the addition of HI is 0.88.

In conclusion, the original buffer solution had a pH of 3.24, the solution after the addition of 0.018 moles of KOH had a pH of 9.85, and the solution after the addition of 12.5 mL of 1.25 M HI had a pH of 0.88.

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Answer:

2KNO3 + H2SO4 → K2SO4 + 2HNO3

Explanation:

Hope this helps

The IUPAC nomenclature system is a set of logical rules devised and used by organic chemists to circumvent problems caused by arbitrary nomenclature.

The 1-ethyl-3-propylcyclopentane molecule contains a total of 30 bond(s) There are 10 non-H bond(s), 3 rotatable bond(s) and 1 five-membered ring(s).

The 1,2-dimethylcyclopentene molecule contains two methyl groups and one double bond in the ring.

The 1,3,5-Triethylbenzene molecule contains three ethyl groups and a benzene ring.

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Answer:

radiation because heat is being transferred

Answer:

It is ultraviolet radiation, which is going to be radiation.

Explanation:

When ultraviolet radiation from the sun reaches the skin, it damages the skin cells and causes mutations in their DNA.

Explanation:

When ethyne undergoes a hydrogenation reaction with Ni catalyst and excess hydrogen,

C2H2 + 2H2 => C2H6.

Ethyne reacts with hydrogen gas to form ethane.

The percent by mass of the solution made from 17 g sodium chloride, NaCl (the solute) and 59 g water is 22.4%

First, we shall obtain the mass of the solution. Details below:

Mass of solution = Mass of NaCl + mass of water

Mass of solution = 17 + 59

Mass of solution = 76 grams

Finally, we shall determine the percent by mass of the solution. Details below:

Percent by mass = (mass of NaCl / mass of solution) × 100

= (17 / 76) × 100

= 22.4%

Thus, the percent by mass of the solution is 22.4%

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Explanation:

Answer:

image 3 and 4show chemical reactions

Explanation:

The type of glassware that students need to use to prepare 250 ml of a 0.800 m aqueous solution of sucrose is a volumetric flask and the correct amount of solute to use is 68.46g.

It is always recommended to use volumetric flask when you make sucrose solution, as accuracy is very important. Other glassware can be used to make water measurements more accurate, but it is always better to use a volumetric flask to  this stock solution. and the correct amount of solute to use can be calculate as follow:

In this case, sucrose is a solid compound, so the best way to measure it is to use a balance and weigh the required mass based on the concentration of the solution. Therefore, it is best to measure grams of solute on a scale.

The amounts required are:

M = n/V

n = M*V

n = 0.800 * 0.250 = 0.2 moles

To get the mass:

m = n*MM

The molar mass of sucrose is 342.3 g/mol.

m = 0.2 * 342.3

m = 68.46g

Finally, after we have weighed the mass of sucrose we need, so all that remains is to add the solute to the volumetric flask and add water. In this way, sucrose mixes with water into a solution. Then, to make the solution 0.800M, the volume should be 250mL.

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Answer:

0.25 moles of COCl₂ are been produced

The element that is oxidized is C, it changed the oxidation state from +2 in CO to +4 in phosgene.

Explanation:

Equilibrium reaction:

Cl₂(g)  +  CO(g)  ⇄  COCl₂(g)

Let's convert the mass of CO to moles:

7g . 1mol /28g = 0.25 moles

As ratio is 1:1, we can say that 0.25 moles of COCl₂ are been produced.

1 mol of chlorine reacts to 1 mol of carbon monoxide in order to produce 1 mol of phosgene.

Chlorine is been reduced:

Cl₂  +  2e⁻  ⇄  2Cl⁻

Change the oxidation state, from 0 (ground state) to -1. Oxidation state decreased.

Carbon is been oxidized.

In CO, carbon has +2 as oxidation state. In phosgene the oxidation state is +4. This oxidation state was increased, that's why it has oxidized.

The element that is oxidized is carbon whose oxidation number was increased from +2 to +4.

The equation of the reaction is;

Cl2(g) + CO(g) ⇄ COCl2(g)

We have been told that the chlorine gas is the reactant in excess hence the carbon monoxide is the limiting reactant.

Number of moles of  CO = 7.0 g/28 g/mol = 0.25 moles

Since the reaction is 1:1, 0.25 moles of COCl2 is produced.

The element that is oxidized is carbon whose oxidation number was increased from +2 to +4.

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The following substances can behave as Bronsted-Lowry acids in aqueous solution: HNO₃ and  NH₄+

The correct answer is a and b.

The Bronsted-Lowry acid theory is a chemical theory that explains acids and bases and their reactions. It defines acids as proton donors and bases as proton acceptors.

According to the definition provided by Bronsted–Lowry, an acid is a proton (H+) donor, while a base is a proton acceptor. At the point when a Brønsted-Lowry corrosive loses a proton, a form base is shaped. Similarly, a conjugate acid is produced when a Bronsted–Lowry base acquires a proton.

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The temperature of the nitrogen gas is  33.92 Kelvin

How to solve:

To get the temperature of the nitrogen gas, we will use the ideal gas equation:

PV = nRT

where:

P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature. First, let's change the equation to account for temperature:

T = PV/(nR)

Presently, we can connect the given qualities:

The ideal gas constant, R, is 0.0821 L-atm/(mol-K), with P = 0.975 atm and V = 1.68 L and n = 0.589 mol.

Adding the following values to the equation:

T = (0.975 atm * 1.68 L) / (0.589 mol * 0.0821 L atm/(mol K)) T = 1.6332 atm L / (0.04813 L atm/(Kmol))

The nitrogen gas's temperature is 33.92 Kelvin because;

T = 1.6332 / 0.04813 K

T = 33.92 K.

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Answer:

Cell membrane

Explanation:

The molarity of the solution is determined as 5.12 M.

The molarity of a solution is calculated as follows;

Molarity is defined as the ratio of the number of moles of solute to the volume of the solution in liters.

The molarity (M) is calculated as follows;

Molarity = moles of solute / volume of solution (in liters)

Molarity = 4.28 moles / 0.836 liters

Molarity 5.12 M

Thus, the molarity of the solution is determined as 5.12 M.

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the answer is melting

Answer: melting :)

Explanation:

Answer:

20

Explanation:

In 0.75 moles of caffeine, there are a total of 6 carbon atoms, 7.5 hydrogen atoms, 3 nitrogen atoms, and 1.5 oxygen atoms.

To determine the total number of atoms in 0.75 moles of caffeine, we need to consider the molecular formula of caffeine, which is C8H10N4O2. The molecular formula provides the ratios of each element present in the compound. By multiplying the number of atoms in each element by the corresponding coefficient in the molecular formula, we can calculate the total number of atoms. In this case, there are 8 carbon (C) atoms, 10 hydrogen (H) atoms, 4 nitrogen (N) atoms, and 2 oxygen (O) atoms in each molecule of caffeine. Multiplying these values by 0.75 moles will give us the total number of atoms in 0.75 moles of caffeine.

The molecular formula of caffeine, C8H10N4O2, provides the number of atoms for each element present in one molecule of caffeine. In this case, there are 8 carbon (C) atoms, 10 hydrogen (H) atoms, 4 nitrogen (N) atoms, and 2 oxygen (O) atoms.

To calculate the total number of atoms in 0.75 moles of caffeine, we need to multiply the number of atoms for each element by the coefficient in the molecular formula, and then multiply that by the number of moles (0.75 moles).

For carbon (C): 8 atoms x 0.75 moles = 6 atoms (since there are 8 carbon atoms in one molecule of caffeine).

For hydrogen (H): 10 atoms x 0.75 moles = 7.5 atoms (since there are 10 hydrogen atoms in one molecule of caffeine).

For nitrogen (N): 4 atoms x 0.75 moles = 3 atoms (since there are 4 nitrogen atoms in one molecule of caffeine).

For oxygen (O): 2 atoms x 0.75 moles = 1.5 atoms (since there are 2 oxygen atoms in one molecule of caffeine).

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(a) The formula for first order kinetics is: ln[N]/[N]0 = -kt.  Where [N] is the concentration of the reactant at a given time, [N]0 is the initial concentration, k is the rate constant, and t is the time elapsed.

Since we know the half-life, we can use the formula: t1/2 = ln2/k to find k.
t1/2 = 445 seconds, therefore:
k = ln2/t1/2 = ln2/445 = 0.00156 s^-1.
(b) We can use the formula: ln[N]/[N]0 = -kt to find t when [N] = 0.0100 M:
ln(0.0100/0.0700) = -0.00156t
t = 1,300 seconds or 21.7 minutes.
(c) Using the same formula, we can find [N] after 1.40 hours (which is 5,040 seconds):
ln[N]/[N]0 = -kt
ln([N]/0.0650) = -0.00156 x 5,040
[N] = 0.040 M.

(a) The rate constant (k) for a first-order reaction can be calculated using the half-life formula: k = 0.693/t₁/₂. With a half-life of 445 seconds, k = 0.693/445 = 1.56 x 10⁻³ s⁻¹.

(b) To find the time required for [CH3NO2] to decrease from 0.0700 M to 0.0100 M, use the first-order integrated rate law: ln([A]₀/[A]) = kt. ln(0.0700/0.0100) = 1.56 x 10⁻³ * t. Solving for t, we get t ≈ 1873 seconds.

(c) To determine the [CH3NO2] after 1.40 h (5040 seconds) starting from 0.0650 M, use the same rate law: [CH3NO2] = 0.0650 * e^(-1.56 x 10⁻³ * 5040) ≈ 0.0013 M.

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3.3256 Liters

See the image I have shared to you above

Answer:

B. 7.2k

Explanation:

took the test ;)

Yes, a reaction occurs when aqueous solutions of calcium iodide and lead(II) acetate are combined. The net ionic equation is:

Ca²⁺(aq) + 2I⁻(aq) + Pb²⁺(aq) + 2C₂H₃O₂⁻(aq) → PbI₂(s) + 2CH₃COO⁻(aq) + Ca²⁺(aq)

The reaction between calcium iodide and lead(II) acetate is a double displacement reaction. The reactants of this reaction are calcium iodide (CaI₂) and lead(II) acetate (Pb(CH₃COO)₂), and the products of the reaction are lead(II) iodide (PbI₂) and calcium acetate (Ca(CH₃COO)₂).

Calcium iodide is soluble in water as it is composed of Ca²⁺ and I⁻ ions. On the other hand, lead(II) acetate is also soluble in water as it is composed of Pb²⁺ and C₂H₃O₂⁻ ions.

The reaction will occur when the two solutions are combined. The net ionic equation is obtained by omitting the spectator ions (ions that do not participate in the reaction) from the overall ionic equation.

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