Satellites can focus on specific latitudes using:
North-South orbits
East-West orbits
O oblique orbits
none of the above

One filter box will be required for the plant expansion, but an alternative design needs to be proposed if the design loading rate is exceeded with one filter box out of service.

To determine the number of filter boxes required, we need to calculate the total surface area required and divide it by the maximum surface area per filter box.

Calculate the total surface area required:

Total surface area = Design flow rate / Design loading rate

Total surface area = 1.2 m³/s × 24 × 3600 s / (575 m³/d × 1 d/24h)

Total surface area = 18.67 m²

Determine the number of filter boxes required:

Number of filter boxes = Total surface area / Maximum surface area per filter box

Number of filter boxes = 18.67 m² / 50 m²

Number of filter boxes = 0.37 (round up to the nearest whole number)

Number of filter boxes = 1 (since we cannot have a fraction of a filter box)

Therefore, one filter box will be required to meet the design loading rate.

To check the design loading with one filter box out of service, we need to recalculate the loading rate:

Calculate the new design loading rate:

New design loading rate = Design flow rate / (Number of filter boxes - 1)

New design loading rate = 1.2 m³/s / (1 - 1)

New design loading rate = Undefined

Since the new design loading rate is undefined when one filter box is out of service, an alternative design should be proposed to ensure that the design loading rate is not exceeded. This could involve increasing the number of filter boxes or redesigning the filtration system to accommodate the required flow rate.

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Answer:

The frequency of the wave is 5 Hz (Hertz), which means it oscillates or cycles 5 times in one second.

Explanation:

The frequency of a wave is the number of times the wave oscillates or cycles in a given period of time. The period of a wave is the time it takes for the wave to complete one cycle.

The period of the wave is given as 0.2 seconds. To calculate the frequency, we can use the formula:

Frequency (f) = 1 / period (T)

So in this case:

f = 1 / 0.2 seconds

The frequency of the wave is 5 Hz (Hertz), which means it oscillates or cycles 5 times in one second.

Formula for frequency:

\(f=\dfrac{1}{T}\)

frequency(measured in Hertz) = 1 / period(measured in seconds)

__________________________________________________________

Given:

\(T=0.2s\)

\(f=?\)

__________________________________________________________

Finding frequency:

\(f=\dfrac{1}{T}\)

\(f=\dfrac{1}{0.2}\)

__________________________________________________________

Answer:

\(\fbox{f = 5 Hertz}\)

Answer:

C . 3.75 Ohms

Explanation:

V = IR

R = V / I

From the graph, you pick a value for potential difference and find its corresponding current.

The resistance of the wire in Ohms is 3.75 Ω, therefore the correct answer is option C

Resistance is the obstruction of electrons in an electrically conducting material.

The mathematical relation for resistance can be understood with the help of the empirical relation provided by Ohm's law.

V=IR

where V is the voltage

I is the current

From the voltage-current  graph, one can know the resistance by calculating the slope of the graph

As shown in the graph the variation of the voltage with the current

Y axis represents the voltage and the X axis represents the current

slope = variation in the Y coordinate /variation in the X coordinate

resistance = variation in the voltage /variation in the current

                 = (30 - 0 )/ (8-0 )

                 = 3.75 Ω

Thus, by observation and calculation from the graph, the resistance of the wire comes out to be 3.75 Ω

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Considering the table the acceleration is 2.72 Km/hr

Acceleration is defined as the rate of change of velocity with respect to time.

This means that if an object's velocity changes by a certain amount over a certain period of time, then the object is said to have experienced acceleration during that time.

The formula is

= Final velocity - initial velocity / time taken

plugging in the values

= (65 - 60) / (11:55 - 10:05)

= 5 / 1:50

converting 50 minutes to hour = 50 / 60

= 5 / 1 50/60

= 2 6/11

= 2.72 Km/hr

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Answer:

A=Gas

B= Solid

C=Liquid

Explanation:

A gas has the particles dispersed everywhere

so A is the gas

Liquid and Solid have them more close together

but the solid has them in some order

so as you can see

B is solid

and

C is liquid

Answ

— How can a small boy balance a big boy on a sea-saw? Show with a diagram. fast please...... Get the answers you need, now!

2 answers

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Explanation:

The required force is calculated to be 0.5 N, work is 10 J and power is 0.074 Watt.

The mass of the book is given as 1 kg.

The acceleration of the book is given as 0.5 m/s².

The distance moved by the book is given as 20 m.

The time taken to move the book is given as 2 1/4 minutes = 9/4 minutes.

The force applied on the book is given as,

F = m a = 1 × 0.5 = 0.5 N

where,

F is force

m is mass

a is acceleration

The expression for work is known to be,

W = F . s = 0.5 × 20 = 10 J

where,

W is work

s is distance

The relation for power is known to be,

P = W/t = 10/(9/4 × 60) = 0.074 Watt

where,

P is power

t is time

Thus, the force is 0.5 N, work is 10 J and power is 0.074 Watt.

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Complete question is;

A 50.-ohm resistor, an unknown resistor R, a 120-volt source, and an ammeter are connected in a complete circuit. The ammeter reads 0.50 ampere.

A) Calculate the equivalent resistance of the circuit shown.

B) Determine the resistance of resistor R shown in the diagram.

Answer:

A) R_eq = 240 Ω

B) R = 190 Ω

Explanation:

A) To get the equivalent resistance, we will use the formula;

R = V/I

Where;

V is Voltage

I is current

R is equivalent resistance

From the question, V = 120 V and I = 0.5A

Thus;

R_eq = 120/0.5

R_eq = 240 Ω

B) From the image, we see that the resistors are connected in series.

Formula for resistors in series is;

R = R1 + R2 +..... Rn

Thus;

240 = 50 + R

R = 240 - 50

R = 190 Ω

A) The equivalent resistance of the circuit shown will be  240 Ω.

B) The resistance of resistor R will be 190 Ω

Resistance is a type of opposition force due to which the flow of current is reduced in the material or wire. Resistance is the enemy of the flow of current.

The given data in the problem is;

R is the resistance = 50.-ohm

v is the voltage = 120-volt source

I is the value of the current =0.50 ampere.

A) The equivalent resistance of the circuit shown will be  240 Ω.

According to ohm's law

\(\rm R= \frac{V}{I} \\\\ \rm R= \frac{120}{0.5} \\\\ \rm R=240 \ ohm\)

Hence the equivalent resistance of the circuit shown will be 240 Ω.

B) The resistance of resistor R will be 190 Ω

The given resistors are connected in the series;

R = R1 + R2 +..... Rn

240 = 50 + R

R = 240 - 50

R = 190 Ω

Hence the resistance of resistor R will be 190 Ω

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Stellar masses can be determined by observing binary systems. Option A is the correct answer.

Astronomers refer to a star's mass as stellar mass when describing it. It is often represented as a percentage of the Sun's mass as a solar mass. By examining the orbits of binary stars—two stars orbiting a single mass center—it is possible to estimate the masses of stars. Option A is the correct answer.

A spectroscopic binary can only be viewed by looking at the spectrum, as opposed to visual binaries where the two stars may be seen independently through a telescope.  Planets are objects in which nuclear reactions cannot occur. The mass-luminosity connection states that most of the time, the most massive stars are also the most brilliant.

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The complete question is, "Stellar masses can be determined by observing __________ systems.

A. binary

B. spectroscopic"

Stellar masses can be determined by observing binary star systems.

When it comes to determining the masses of stars, one method is to observe binary star systems. Binary star systems consist of two stars that orbit around a common center of mass. By studying the motion of these stars, scientists can calculate their masses.

This is possible because the gravitational force between the two stars depends on their masses and the distance between them. By measuring the orbital period and the separation of the stars, astronomers can use Kepler's laws of motion and Newton's law of universal gravitation to determine their masses.

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Answer:

Matter

Explanation:

As one moves away from a positive point charge, the electric potential: decreases due to (r) is getting bigger

As the radius between the charges becomes larger the electric potential decreases because the relationship between the two is inversely proportional.

The electric potential formula  is:

Ep = (k * q1 * q2)/r

Where:

In physics the electric potential energy is the energy possessed by an electric charge in reference to another existing electric charge separated by a distance called (r). Its unit of measurement in the international system is the Joule.

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Calculate the inverse tangent of the ratio of the displacement components in the y and x directions to determine the direction of the displacement vector. The magnitude of displacement is equal to the distance covered in a given interval of time if the particle moves at a constant or variable velocity in the same direction, because if it changes direction, the magnitude of displacement changes and does not remain equal to the distance covered.

A quantity with magnitude and direction must also follow certain combination rules in order to qualify as a vector. Vector addition, denoted symbolically as A + B = C, is one of these (vectors are conventionally written as boldface letters). Geometrically, the vector sum can be visualized by placing the tail of vector B at the head of vector A and drawing vector C so that it completes the triangle (starting from the tail of A and ending at the head of B). If A, B, and C are vectors, then it must be possible to reverse the operation and achieve the same result (C), B + A = C. This property (commutative law) is shared by quantities such as displacement and velocity, but there are some that do not (for example, finite rotations in a circle).

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Answer:

To calculate the resonant frequency and the wavelength in the ear canal, the formulas for closed cavity resonances can be used:

a. First resonant frequency:

The resonant frequency f n can be calculated from the length l of the ear canal and the speed of sound v as follows:

fn = nv / 4l

where n is an integer representing the number of resonances. For the first resonance (n = 1), the resonant frequency can be calculated as:

f 1 = v / 4l = (340 m/s) / (4 * 2.5 cm) = 272,000 Hz

b. Wavelength at second resonance:

The wavelength λ of the resonant frequency can be calculated from the frequency and speed of sound:

λ = v/f

For the second resonance (n = 2), the resonant frequency is:

f 2 = 2v / 4l = 2 * 272,000 Hz = 544,000 Hz

and the wavelength can be calculated as:

λ 2 = v / f 2 = (340 m/s) / 544,000 Hz = 0.00063 m = 6.3 mm

These calculations are approximate and may vary depending on the shape and acoustic properties of the ear canal.

Given

On Saturday, she found 4 times as many shells as she found on Sunday.

Saturday = 4*Sunday

Saturday = 21 + Sunday

Two system equations, now we can solve:

4*Sunday = 21 + Sunday

3*Sunday = 21

Sunday = 7 Shells

Saturday = 28 Shells

Total = 35 Shells

Answer:35 in total

Explanation:

The bandwidth of the periodic composite signal is drawn as a range between 100 Hz and 2100 Hz , The data rates for sending a digital signal using one harmonic, three harmonics, and five harmonics on a TV channel with a 6 MHz bandwidth would be 6 MHz, 18 MHz, and 30 MHz .

For the first question

Draw the bandwidth of a periodic composite signal, we need to consider the highest frequency component present in the signal.

We have two sine waves one with a frequency of 100 Hz and the other unspecified. Since the bandwidth is given as 2000 Hz, we can assume that the second sine wave has a frequency of 2100 Hz (2000 Hz above the first sine wave frequency).

Draw the bandwidth, we can create a graph with frequency on the x-axis and amplitude on the y-axis.

We plot the amplitude values for the two sine waves at their respective frequencies (100 Hz and 2100 Hz). The bandwidth will be the range between these two frequencies on the x-axis.

For the second question

The data rate for a digital signal transmitted using one harmonic, three harmonics, and five harmonics can be calculated by multiplying the channel bandwidth by the number of harmonics used. Since the bandwidth is given as 6 MHz, the data rates would be as follows:

One harmonic: 6 MHz

Three harmonics: 18 MHz

Five harmonics: 30 MHz

The data rate increases with the number of harmonics used because each harmonic contributes additional information to the signal, allowing for a higher data transmission rate.

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The hippo's center of gravity is located 3.2 meters from its tail.

To determine the distance of the hippo's center of gravity from its tail, we need to consider the weight distribution between its front and rear feet. Given that the hippo carries 80% of its weight on its front foot, we can assume that 80% of the hippo's total weight acts at the front. Let's denote the distance from the tail to the center of gravity as "x."

Since the rear foot is located at the tail, the remaining 20% of the weight acts at the rear foot. Using the principle of moments, we can set up the equation: (80% of the weight) * (distance from front foot to center of gravity) = (20% of the weight) * (distance from rear foot to center of gravity). Plugging in the given values, we have (0.8) * (4.0 - x) = (0.2) * x. Solving this equation, we find x = 3.2 meters. Therefore, the hippo's center of gravity is located 3.2 meters from its tail.

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Answer:

T = 486.6 K

Explanation:

The final temperature of the block can be found using the following formula:

\(Q = mC\Delta T\\\)

where,

Q = Thermal Energy Transferred = 3.35 x 10⁵ J

m = mass of aluminum block = 2 kg

C = Specific Heat = 897 J/kg.K

ΔT = Change in Temperature = T - 300 K

T = Final Temperature of the Block = ?

Therefore,

\(3.35\ x\ 10^5\ J = (2\ kg)(897\ J/kg.K)(T-300\ K)\\\\5.38\ x\ 10^5\ J + 3.35\ x\ 10^5\ J = (1794 J/K)(T)\\\\T = \frac{8.73\ x\ 10^5\ J}{1794\ J/K}\)

T = 486.6 K

Answer:

b) boy kicking a football

Explanation:

it 's because the ball was at rest but when it was kicked, it starts to more

The charge would be in equilibrium so there would be no charge in the body of the conductor.

Answer:

(b) there cannot be any charge in the body of the conductor

Answer:

B

Explanation:

Note the line that there is no charges anywhere else outside means the charge is placed in equilibrium position.

Hence there cannot be any charge in the body of conductor

The distance from the proton where the speed of the electron is instantaneously equal to 8 times its initial value is approximately 2.05 × 10^-11 meters.

To find the distance from the proton where the speed of the electron is instantaneously equal to 8 times its initial value, we can apply the principles of conservation of energy and electrostatics.

The initial kinetic energy of the electron is given by:

KE_initial = (1/2) * m * v_initial^2

where

m is the mass of the electron and

v_initial is the initial velocity of the electron.

The potential energy between the electron and proton is given by:

PE = -k * (e^2) / r

where

k is the electrostatic constant,

e is the charge of the electron,

and r is the distance between the electron and proton.

At any distance r, the total mechanical energy of the system is conserved and equal to the sum of the initial kinetic energy and potential energy:

KE_initial + PE = KE_final

Since the speed of the electron is instantaneously equal to 8 times its initial value, the final kinetic energy (KE_final) can be expressed as:

KE_final = (1/2) * m * (8 * v_initial)^2 = 32 * KE_initial

Setting up the equation with conservation of energy:

(1/2) * m * v_initial^2 - k * (e^2) / r = 32 * KE_initial

Substituting the given values:

m = mass of electron = 9.11 × 10^-31 kg

v_initial = initial velocity = 2.6 × 10^5 m/s

k = electrostatic constant = 8.99 × 10^9 N·m²/C²

e = charge of electron = -1.6 × 10^-19 C

Simplifying the equation and solving for r:

(1/2) * (9.11 × 10^-31 kg) * (2.6 × 10^5 m/s)^2 - (8.99 × 10^9 N·m²/C²) * (1.6 × 10^-19 C)^2 / r = 32 * [(1/2) * (9.11 × 10^-31 kg) * (2.6 × 10^5 m/s)^2]

r = (8.99 × 10^9 N·m²/C²) * (1.6 × 10^-19 C)^2 / [(32 * [(1/2) * (9.11 × 10^-31 kg) * (2.6 × 10^5 m/s)^2]) - (1/2) * (9.11 × 10^-31 kg) * (2.6 × 10^5 m/s)^2]

Simplifying the expression and calculating:

r ≈ 2.05 × 10^-11 meters

Therefore, the distance from the proton where the speed of the electron is instantaneously equal to 8 times its initial value is approximately 2.05 × 10^-11 meters.

At a distance of approximately 2.05 × 10^-11 meters from the proton, the speed of the electron will be instantaneously equal to 8 times its initial value. This calculation is based on the principles of conservation of energy and electrostatics, taking into account the initial velocity and the interaction between the charges of the electron and proton.

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Answer:

Explanation:

Momentum

Answer:

The earth is hotter

Explanation:

the average temperature on earth is 57 degrees Fahrenheit the average on the moon is -298 degrees Fahrenheit

Answer:

The mass of the lorry 7800 kg

Explanation:

Momentum conservation law for inelastic collision:

\(m1*V1 + m2*V2 =( m1 + m2)*V^{'} \\ \\1200*10^{3} g * 30 m/s + m2*0 m/s =(1200*10^{3} g + m2)*4 m/s\\ \\\frac{1200*10^{3} g * 30 m/s}{4 m/s} -1200*10^{3} g=m2\\ \\m2=9000*10^{3} g-1200*10^{3} g=7800*10^{3} g=7800 kg\)

The total number of bright fringes on a very large distant screen can be determined without calculating all the angles by using the concept of the interference pattern produced by a double slit.

In the double-slit interference pattern, bright fringes occur when the path difference between the waves from the two slits is an integer multiple of the wavelength. The central bright fringe is formed when the path difference is zero.

If we consider the central fringe as the zeroth order, the first-order fringe will be formed when the path difference is one wavelength, the second-order fringe when the path difference is two wavelengths, and so on.

Assuming that the distance between the two slits is d, the angle θ for the nth-order fringe can be approximated as θ = nλ/d, where λ is the wavelength of light.

The largest angle, θ_max, is determined by the screen size. Let's say the screen has a width L. To find θ_max, we need to consider the fringe that is at the edge of the screen. The angle for this fringe can be given by θ_max = λ/L.

To find the total number of bright fringes, including the central fringe and those on both sides of it, we can divide θ_max by the angle between adjacent fringes, Δθ. Δθ can be approximated as Δθ = λ/d.

The total number of fringes, N, can be calculated using the formula N = 2θ_max/Δθ.

Therefore, the total number of bright fringes can be determined without calculating all the angles by using the formula N = 2(λ/L)/(λ/d), which simplifies to N = 2d/L.

In conclusion, the total number of bright fringes, including the central fringe and those on both sides of it, is given by the formula N = 2d/L, where d is the distance between the double slits and L is the width of the screen.

More than 100 words.

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Evaluate

a) L{e+(2t - 1)² + sin(-3t) + cos(5t)}

To evaluate this Laplace transform, we'll use the basic Laplace transform properties and formulas.

Step 1: Apply the Laplace transform to each term separately.

L{e} = 1/s [Using the Laplace transform of the exponential function]

L{(2t - 1)²} = (2/s)² [Using the Laplace transform of (at + b)^n, where a, b are constants]

L{sin(-3t)} = -3/(s² + 9) [Using the Laplace transform of sin(at)]

L{cos(5t)} = s/(s² + 25) [Using the Laplace transform of cos(at)]

Step 2: Apply the linearity property of the Laplace transform to combine the individual transforms.

L{e+(2t - 1)² + sin(-3t) + cos(5t)} = L{e} + L{(2t - 1)²} + L{sin(-3t)} + L{cos(5t)}

= 1/s + (2/s)² - 3/(s² + 9) + s/(s² + 25)

= 1/s + 4/s² - 3/(s² + 9) + s/(s² + 25)

Therefore, the Laplace transform of the given expression is 1/s + 4/s² - 3/(s² + 9) + s/(s² + 25).

b) L^(-1) {1 / [(s + 1)(s² + 5 - 12)]}

To evaluate the inverse Laplace transform, we'll use partial fraction decomposition and the inverse Laplace transform formulas.

Step 1: Factorize the denominator.

(s + 1)(s² + 5 - 12) = (s + 1)(s² + 5 - 12)

= (s + 1)(s² + 4s - 7)

= (s + 1)(s + 7)(s - 1)

1 / [(s + 1)(s + 7)(s - 1)] = A / (s + 1) + B / (s + 7) + C / (s - 1)

For s^2 term: 0 = A + B + C

For s term: 0 = 6A - 6B + 8C

For constant term: 1 = -7A

From the third equation, A = -1/7. Substituting this into the second equation, we get -6/7 - 6B + 8C = 0, which simplifies to -6B + 8C = 6/7.

From the first equation, we get C = -A - B, which simplifies to C = 1/7 - B.

Substituting C into the equation -6B + 8C = 6/7, we have -6B

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Answer:

All of the above

Explanation:

I saw this on an EdPuzzle.