Solve 2(1 - x) > 2x.

a.) O x < 0.5
b.) Ox> 2
c.) Ox<2
d.) O x > 0.5​

Answer: 81,000

Step-by-step explanation:

We can solve this by using the formula given.

If f(1)=1000x3^1, then 1,000x3=3,000

If f(2)=1000x3^2, then 3^2=9 and 1000x9=9000,

and so on,

Now, f(4) will equal 1000x3^4, and 3^4 is 3x3x3x3, which is 9x9 or 9^2, which would be equal to 81, and 81x1000=81,000

To complete the table of values for the exponential function f(x) = 1000*3^x, we can evaluate the function for x = 0, 1, 2, 3, and 4, since we are interested in the number of bacteria on the phone after 4 hours.

x f(x)

0 1000

1 3000

2 9000

3 27,000

4 81,000

Therefore, after 4 hours, there will be 81,000 bacteria on the surface of the phone, assuming the number of bacteria triples every hour and can be described by the exponential function f(x) = 1000*3^x.

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The Stokes approximation and Oseen approximation are methods used to determine the motion of fluid particles in a fluid dynamics problem.

The Stokes approximation applies to slow-moving fluid particles, where viscous forces are dominant, while the Oseen approximation applies to higher velocities, where convective forces are dominant..Oseen approximation: In this approximation, the equations governing the motion of fluid particles account for the convective forces in addition to the viscous forces.

This approximation is valid at moderate Reynolds numbers and is used when the viscous forces are still strong but not as dominant as in the Stokes approximation. The velocity of the fluid decreases less rapidly than in the Stokes approximation, and the approximation is valid for Reynolds numbers greater than one .The difference between the results of the two approximations lies in their range of applicability and the accuracy of their results.

The significance of the difference between the two approximations lies in their application to real-world problems. In fluid dynamics, it is essential to have accurate approximations to predict the behavior of fluid particles accurately. Therefore, choosing the appropriate approximation for the specific problem is critical. knowing the range of applicability of each approximation can help in determining the parameters for the problem.

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The final dilution required to produce 292 cfu on a petri dish is 1/8125.

Here is the explanation on how to arrive at that answer:

Given: Initial concentration of culture = 743,894 CFU/mL,

Exponential growth phase lasted for 978 minutes,

Growth constant = 0.03467 min-1,

Final dilution required to produce 292 CFU on a petri dish,

Solution:

We can use the equation N=N0e^(kt) to determine the concentration of the culture after the given time t,

where N0 is the initial concentration of the culture,

N is the final concentration of the culture, k is the growth constant, and t is the time.

In this case, we can use the given values to determine the final concentration of the culture.

So, we have:

N0 = 743,894 CFU/mL, k

   = 0.03467 min-1,t

   = 978 minutes.

N = N0e^(kt)N

  = 743,894 e^(0.03467 x 978)N

  = 22,136,343,978 CFU/mL

Now, we can use the formula C1V1 = C2V2

To determine the final dilution required to produce 292 CFU on a petri dish,

where C1 is the initial concentration of the culture,

V1 is the initial volume of the culture,

C2 is the final concentration of the culture, and V2 is the final volume of the culture (which is the volume transferred on the petri dish).

So, we have:

C1V1 = C2V2V2 = 0.1 mL (since it is given that 0.1 mL is transferred on the petri dish)

C2 = 292 CFU / V2

We need to find the value of V1.

So, we can rewrite the formula as:

V1 = C2V2 / C1V1

= (292 / 0.1) / 22,136,343,978 V1

= 1.3216 x 10^-7 mL

This is the volume of the culture that needs to be transferred on the petri dish.

The final dilution required will be the inverse of this volume, which is: 1 / 1.3216 x 10^-7 = 7,575,500.7

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Answer: Dome Fuji, in Antarctica, is the coldest place in the world with a record low of –92 degrees.

Step-by-step explanation:

Given statement solution is :- To construct a grouped frequency distribution for the given test scores data, we will use the provided classes: 30-40, 40-50, and so on. Here's the grouped frequency distribution:

Classes Frequency

30-40 2

40-50 3

50-60 4

60-70 8

70-80 9

80-90 7

90-100 7

To construct a grouped frequency distribution for the given test scores data, we will use the provided classes: 30-40, 40-50, and so on. Here's the grouped frequency distribution:

Classes Frequency

30-40 2

40-50 3

50-60 4

60-70 8

70-80 9

80-90 7

90-100 7

To create this distribution, we count the number of scores that fall within each class range. For example, the class 30-40 has 2 scores falling within that range (35 and 39), and the class 40-50 has 3 scores (45, 48, and 48).

Note: It seems there is an inconsistency in the data provided. The class range 70-80 has 9 scores, but the frequencies given for the other classes do not match the actual number of scores falling within those ranges. Therefore, I have used the actual counts from the data to construct the grouped frequency distribution.

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Answer: 0,2

Step-by-step explanation:

Answer:

Chip worked 7 weeks

Step-by-step explanation:

Set up as proportion and cross multiply to solve:

6 hours/1 week = 42 hours/x

x = 7

Answer:

4 is the answer when you evaluate the function

Step-by-step explanation:

The equation of the new graph would be \(g(x) = 4(x + 7)\).

The correct answer is B.

When a graph is shifted 7 units to the left, we write \((x + 7)\) inside the parentheses.

Therefore, the equation of the new graph would be

\(f(x + 7) = 4(x + 7)\)

which can be simplified to \(f(x + 7) = 4x + 28\)

But, the question is asking for the equation of the new graph.

So, we replace f(x) with g(x), since we are creating a new function and not modifying the existing one.

Therefore, the equation of the new graph would be \(g(x) = 4(x + 7)\).

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Answer:

I'm not good at this I'm good at math

In the given question, we have to find the cardinality of the following sets:U = ( x | x E N and x < 10) b = (x |x E N and x is even and x <10) c = (x | x E N and x <5)

Cardinality is a mathematical term for the number of elements in a set. It is indicated as |A|. Therefore, the cardinality of set U is 10. The cardinality of set b is 5. The cardinality of set c is 5. The set with more than 250 elements is none of the given sets since all sets have less than 10 elements and thus less than 250 elements. Therefore, the correct answer is that none of the given sets have more than 250 elements.

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Step-by-step explanation:

Simple

Total no of marbles = 6 + 4 + 8 = 18

Probability of red marble = 6 / 18 = 1/ 3

The number of pounds of grapes is 24 sold and the number of pounds of apples sold is 30.

Given that,

Apples and grapes are sold at Arianys' farm stand. The price per pound for apples is $4 while the price per pound for grapes is $3.75. 64 pounds of apples and grapes were sold for a total profit of $251.75 for Arianys.

We have to find the number of the sold apples and pounds of grapes should be calculated.

a declaration that two mathematical expressions' values are equal (represented by the symbol =).

We get the equations as,

3.75x+4y=251.75

y=-0.93x+62.93---->equation(1)

x+y=64

y=-x+64------>equation (2)

We get the points as

For equation (1),

(0,62.93) and (67.66,0)

For equation (2),

(0, 64) and (64,0)

If we draw a graph we get 2 lines intersect at a point (24, 30).

Therefore, The number of pounds of grapes is 24 sold and the number of pounds of apples sold is 30.

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Answer: A. There are 3 squirrels for every 25 pigeons in the park

Step-by-step explanation:

The options include:

A) There are 3 squirrels for every 25 pigeons in the park.

B) There are 3 squirrels for every 5 pigeons in the park.

C) There are 5 squirrels for every 3 pigeons in the park.

D) There are 25 squirrels for every 3 pigeons in the park.

Since the ratio of squirrels to pigeons in the park is 15 to 125. The common factor we have here is 5. We can then divide the figures given by 5. This will be:

= 15/125 = (15/5)/(125/5) = 3/25

This mean that for every 3 squirrels, there are 25 pigeons in the park.

Therefore, the correct answer is A.

Answer:

D

Step-by-step explanation:

Answer:

This is FALSE.  Choose Option 2

Step-by-step explanation:

Substituting 7 for x, we get

7 + 9(7) > 73, or 70  73.  This is FALSE.  Choose Option 2

I think I know but I dont think it's going to be the right answer. But good luck anyway!

To calculate the mean of a frequency distribution, we multiply each value by its corresponding frequency, sum up these products, and divide by the total frequency. In this case, we have a frequency distribution with various measurement intervals and corresponding frequencies. The mean of the given frequency distribution is ___12.43_____.

To calculate the mean of the given frequency distribution, we need to find the sum of the products of each measurement value and its corresponding frequency, and then divide by the total frequency. Let's calculate the mean:

For the measurement interval 110-114: Mean = (113 * 13) / 80

For the measurement interval 115-119: Mean = (118 * 6) / 80

For the measurement interval 120-124: Mean = (122 * 27) / 80

For the measurement interval 125-129: Mean = (127 * 14) / 80

For the measurement interval 130-134: Mean = (132 * 15) / 80

For the measurement interval 135-139: Mean = (138 * 3) / 80

For the measurement interval 140-144: Mean = (142 * 2) / 80

Summing up these values and dividing by the total frequency (80), we obtain the mean of the given frequency distribution which is 12.43.

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Answer:

C is the correct answer

The range of the quadratic function is {y |0 ≤ y < 9}

The range of a function is the set of output values of the graph. This in other words mean the range of a function is the set of y values of the graph.

From the question, we have the following parameters:

Write out the vertex

So, we have

Vertex = (0, 0)

Remove the x value

y = 0

From the question, we have

The parabola opens upward

This means that the vertex is a minimum

So, the range is

y ≥ 0

Rewrite as

0 ≤ y

Recall that:

Closed circle point = (-2, 4)

Open circle point = (3, 9)

Remove the x values

Closed circle point = 4

Open circle point = 9

Remove the smaller y value

Open circle point = 9

This means that the highest value of y is at open circle point = 9

This is represented as

y < 9

So, we have

0 ≤ y and y < 9

Combine both

0 ≤ y < 9

Rewrite properly as

{y |0 ≤ y < 9}

Hence, the range of the quadratic function is {y |0 ≤ y < 9}

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Answer:

the range of the quadratic function is {y |0 ≤ y < 9}

Step-by-step explanation:

i got it right on the test

The population scenario of Dhaka City is characterized by rapid urbanization, high population density, and significant population growth.

1. The population scenario of Dhaka City is characterized by rapid urbanization, high population density, and significant population growth. These factors have led to numerous challenges, including increased traffic congestion, inadequate infrastructure, and strain on public services. The city's population is growing at a rapid pace, resulting in overcrowding, housing shortages, and environmental concerns.

2. To mitigate the present traffic jam situation in Dhaka City, a restructuring of the population can be pursued through various strategies. One approach is to promote decentralization by developing satellite towns or encouraging businesses and industries to establish themselves in other regions. This would help reduce the concentration of population and economic activities in the city center. Additionally, improving public transportation systems, including expanding the metro rail network, introducing dedicated bus lanes, and enhancing cycling and pedestrian infrastructure, can provide viable alternatives to private vehicles. Encouraging telecommuting and flexible work arrangements can also help reduce the number of daily commuters. Moreover, urban planning should focus on creating mixed-use neighborhoods with residential, commercial, and recreational spaces to minimize the need for long-distance travel.

By implementing these measures, the population of Dhaka City can be restructured in a way that reduces the strain on transportation systems, alleviates traffic congestion, and creates a more sustainable and livable urban environment.

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As per the sampling technique, Let us consider what you know about the sampling distribution of the sample proportion. this sampling distribution will have a center equal to the population proportion, or p.

Here we have to find  what you know about the sampling distribution of the sample proportion. This sampling distribution will become more variable as the sample size increases.

Here for the given question, let us check all the given statements in the options

Here we know that the shape is approximately normal. Then the given option will be false.

Next, it is collection of all samples taken from the population, So the given option will be false

Now, we have to check as the sample size increases, the value of n increases. here n is the value on the denominator of the equation of standard deviation.

Therefore, due to an increase in the value of n, then there will be decreases in the standard deviation.

Then the less standard deviation means a small variance.

Therefore, as a result, as the sample size grows, the variation will be minimal.

So, the center is the same as the sample proportion p.

Therefore, this is correct.

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Carrie will be paid $390 if she puts in 40 hours of work in a week.

The total amount of time of work = 40 hours.

As we are stated that the earnings for 1 hour is $9.75, so, we will perform multiplication to find the earnings for the time she worked. We are performing multiplication because the amount will increase as the number of hours increases.

Performing calculation now.

Amount earned in a week = 9.75 × 40

Performing multiplication on Right Hand Side of the equation to find the amount earned in a week

Amount earned in a week = $390

Thus, the amount paid to Carrie in a week is $390.

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We can conclude that it is extremely unlikely to obtain a sample mean greater than 904.8 minutes if the design engineer's claim about the population variance and mean is true.

We can use the Central Limit Theorem to approximate the distribution of the sample means.

Under the given assumptions, the mean of the sampling distribution of the sample means is equal to the population mean, which is 886886 minutes, and the standard deviation of the sampling distribution of the sample means is equal to the population standard deviation divided by the square root of the sample size, which is\(\sqrt{84648464/145145} = 41.77\) minutes.

Therefore, we can standardize the sample mean using the formula:

\(z = (\bar{x} - \mu) / (\sigma / \sqrt{n } )\)

where \(\bar{x}\)  is the sample mean, \(\mu\)  is the population mean, sigma is the population standard deviation, and n is the sample size.

Plugging in the values we get:

z = (904.8 - 886886) / (41.77) = -21115.47

The probability of getting a sample mean greater than 904.8 minutes can be calculated as the area under the standard normal curve to the right of z = -21115.47.

This probability is essentially zero, since the standard normal distribution is symmetric and nearly all of its area is to the left of -6.

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Answer:

70.9%

Step-by-step explanation:

"56 out of 79" can be written as (56/79).  This is equal to a decimal value of 0.708861, or a percentage of 70.8861%.  Round to 1 decimal point to give 70.9%.

Answer:

The maximum value is 5

Step-by-step explanation:

Since this is an upside-down parabola, the maximum value occurs at the vertex. Using -b/2a, we can find the x-value of the vertex and use that x value to plug back into the original function to find the maximum value.

x = -b/2a = -(-12)/(2(-6)) = 12/-12 = -1

f(-1) = -6(-1)^2-12(-1)-1 = 5

Answer:

\(k^{\prime}(9) = 1\).

Step-by-step explanation:

The expression \(k(x) = x\) is equivalent to \(k(x) = x^{1}\).

Apply the power rule of differentiation. For any constant \(a\):

\(\displaystyle \frac{d}{dx}[x^{a}] = a\, x^{a-1}\).

In \(k(x) = x^{1}\), \(a = 1\). Thus:

\(\begin{aligned}k^{\prime}(x) &= \frac{d}{dx}[x^{1}] \\ &= 1\, x^{1 - 1} \\ &= x^{0} \\ &= 1 && \text{given that $x \ne 0$}\end{aligned}\).

In other words, the instantaneous rate of change of \(k(x)\) (with respect to \(x\)) is constantly \(1\) at all \(x \ne 0\).

Therefore, for \(x = 9\), instantaneous rate of change of \(k(x)\) (with respect to \(x\)) would be \(1\).