state of the polygons are similar

The expression that is a

parameterization of the line that passes through the point (2,-3) with a slope of 4 is option D. x= t and y = 4t - 6, for any t

It is a parameterization of the line that passes through the point (2,-3) with a slope of 4, because the point (2,-3) satisfies the equation x = t and y = 4t - 6 and the slope of the line is

A parameterization of a line is a set of equations that describe the location of points on the line in terms of a parameter. One common parameterization of a line is the point-slope form, which expresses the line as y = mx + b, where m is the slope of the line and b is the y-intercept.

Another common parameterization is the two-point form, which expresses the line as (x - x1)/(x2 - x1) = (y - y1)/(y2 - y1), where (x1, y1) and (x2, y2) are two distinct points on the line.

Therefore, the correct answer is as given above

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Answer:

$146.1

Step-by-step explanation:

Answer:

12

Step-by-step explanation:

Answer: 12

Step-by-step explanation: Subtract 6 - 4 = 2. 2 * 2 = 4. 4 + 5 = 9. 9 - 3  = 6. 6 +6 = 12

Answer:

3

15

Step-by-step explanation:

15 is the number that forms the ratio 3/7 of 35

follow the column up until the row 3

Answer:

3 and 15

Step-by-step explanation:

I hope this helps (✿◡‿◡)

Step-by-step explanation:

(4x+7)/(2x-1)=(f/g)(x)

it means f(x)=4x+7

while g(x) =2x-1

f(g(x))=f(2x-1)

=4(2x-1)+7

=8x-4+7

ans =8x+3

Answer:

slope=3/4

Step-by-step explanation:

4-1

/      = 3/4

9-5

To determine the rate at which the car dealership sold cars, we need to divide the total number of cars sold by the number of months. In this case, the dealership sold 216 cars in four months.

To calculate the rate, we divide the total number of cars sold (216) by the number of months (4). The formula for calculating rate is:
Rate = Total quantity / Time
Substituting the given values, we have: Rate = 216 cars / 4 months
Simplifying this expression, we find: Rate = 54 cars per month
Therefore, the car dealership sold cars at a rate of 54 cars per month.

To find the rate at which the dealership sold cars, we divide the total quantity (216 cars) by the time period (4 months). This calculation gives us the average number of cars sold per month. By performing the division, we find that the dealership sold cars at a rate of 54 cars per month. This means that, on average, the dealership sold 54 cars each month over the four-month period.

The rate provides information about the speed or frequency at which the cars were being sold, giving us an understanding of the dealership's sales performance over time.

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Answer: 11

Step-by-step explanation:

i did 3.5 x 3.14 = 10.99 and rounded to the nearest whole number, 11.

The circumference of the circular window to the nearest whole number is 11 feet.

A circle is a two-dimensional figure with a radius and circumference of 2pir.

The area of a circle is pir^2.

We have,

To find the circumference of the circular window, we need to use the formula:

C = πd

where C is the circumference, π is the constant pi, and d is the diameter of the circle.

Since the window is 3.5 feet across at its widest point, the diameter of the circle is also 3.5 feet.

Plugging in the value of the diameter in the formula, we get:

C = πd

C = 3.14 x 3.5

C = 10.99

Rounding the result to the nearest whole number, we get:

C ≈ 11 feet

Therefore,

The circumference of the circular window to the nearest whole number is 11 feet.

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The joint probability density function (joint pdf) is a function used to characterize the probability distribution of multiple continuous random variables that together form a continuous random vector. The results of asking values are

a) E(X³) = 5.86

b)E(X/Y = 2) = 2

c) E(Y²) = 1.2

d) σᵧ= 0.7483

e) E(3Y) = 2.4

We are given that X, Y denotes the number of students and number of questions respectively.

P(X,Y) denote the joint probability mass function for X and Y. Also provide,

P(0,0)=0.04, P(1,0)=0.16, P(1,1)=0.1, P(2,0)=0.2, P(2,1)=0.3, P(2,2)=0.2.

Therefore the required quantities here are computed as:

P(X = 0) = 0.04

P(X = 1) = 0.26

P(X = 2) = 0.7

a) E(X³) = 0 + 1×0.26 + 23×0.7

= 5.86 is the required value here.

b) Now given Y = 2, the conditional Probability density function for X here is obtained as:

P(X = 2 | Y = 2) = 1

Therefore, E(X | Y = 2) = 2 here.

c) For Y, we have here:

P(Y = 0) = 0.4

P(Y = 1) = 0.4

P(Y = 2) = 0.2

Therefore,

E(Y²) = 0.4×1 + 22×0.2

= 1.2 is the required value here.

d) The standard deviation of Y here is computed as:

E(Y) = 1×0.4 + 2×0.2 = 0.8

S.D(Y) = sqrt( E(Y²) - [E(Y)]²) = sqrt( 1.2 - 0.82 )

= 0.7483 is the required value here.

e) E(3Y) = 3E(Y) = 3×0.8

= 2.4 is the required value here.

The probability that X > 1 and Y > 0 here is computed as:

= p( 2, 1). + p(2, 2) = 0.3 + 0.2 = 0.5 is the required probability.

Hence, we calculate all the required Probability values .

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Complete question:

A professor of Statistics records the number of students who attend office hours one day and the number of questions asked on any one day. Let X denote the number of students and Y the number of questions asked, and let P(X,Y) denote the joint probability mass function for X and Y.

Records indicate that P(0,0)=0.04, P(1,0)=0.16, P(1,1)=0.1, P(2,0)=0.2, P(2,1)=0.3, P(2,2)=0.2.

Thus, for any given day, the probability of, say, two students and 1 question is 0.3.

matches the concept value.

All options are same

a) E(X³)

b)E(X/Y = 2)

c) E(Y²)

d) σᵧ

e) E(3Y)

The probability of getting 5 black chips and 6 white chips is \(\frac{7}{22}\).

What do you mean by probability?

Mathematical explanations of the likelihood that an event will occur or that a statement is true are referred to as probabilities. A number between 0 and 1 represents the likelihood of an event, with 0 generally denoting impossibility and 1 denoting certainty.

According to data in the given question,

We have the given information:

Total number of different colored chips = 35

Number of black chips = 20

Number of white chips = 15

And you draw 11 chips at random.

Now, we will calculate the probability of getting 5 black chips and 6 white chips,

\(P(B) = \frac{5}{20} =\frac{1}{4} \\P(W) = \frac{6}{15} =\frac{2}{5} \\P( black and white ) = \frac{\frac{1}{4}*\frac{2}{5}}{\frac{11}{35} } \\=\frac{\frac{1}{2}*\frac{1}{5}}{\frac{11}{35} }\\=\frac{1}{10}*\frac{35}{11}=\frac{7}{22}\)

Therefore, the probability of getting 5 black chips and 6 white chips is 7/22.

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Answer: P(rolling a sum of 4 or rolling a sum of 5)

Step-by-step explanation: edge2023

The scenario that uses the addition rule for mutually exclusive events is:

p(rolling a sum of 4 or rolling a sum of 5) = p(rolling a sum of 4) + p(rolling a sum of 5)

This is because the events "rolling a sum of 4" and "rolling a sum of 5" are mutually exclusive, meaning that they cannot occur at the same time. Therefore, the probability of either event occurring is the sum of their individual probabilities.

The probability of rolling a sum of 4 is 3/36, and the probability of rolling a sum of 5 is 4/36. The addition rule states that the probability of rolling a sum of 4 or 5 is the sum of their individual probabilities: 3/36 + 4/36 = 7/36

The other scenarios do not use the addition rule for mutually exclusive events:

p(rolling a sum of 4) is a single event and does not involve a second event.

p(rolling a sum of 12 or rolling a double 6) although the two events are mutually exclusive, it's not the sum of their individual probabilities.

p(rolling a sum of 11 and rolling a sum of 12) these events are not mutually exclusive, they can happen at the same time, so it's not the sum of their individual probabilities.

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The intrinsic value of the PUT option is $0. It means the option has no inherent value based on the given information.

To determine the intrinsic value of a PUT option, we compare the strike price (X) with the current market price (S) of the underlying asset. If the strike price is higher than the market price, the intrinsic value is the difference between the strike price and the market price. However, if the market price is higher than the strike price, the intrinsic value is $0.

In the given information, we have the following data:

- Strike price (X): $90

- Market price (S): $47.78

Since the market price is lower than the strike price (47.78 < 90), the intrinsic value of the PUT option is $0. This means that exercising the option would not result in any profit because it is currently out of the money.

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Answer:

Page # 1:

Diameter = 14 cm

Radius = 7 cm

Area of the circle = \(\pi r^2\)

=> (π)(7)²

=> 49π cm²

Page # 2:

Area of quarter circle = \(\frac{\pi r^2 }{4}\)

Where r = 8 cm

=> Area = \(\frac{(\pi)(8)^2 }{4}\)

=> Area = 16 π cm²

we know that 76% of the specialty soaps are made with fresh herbs, and we also know that there are a total of 350 specialty soap bars, so how many are made with fresh herbs?  well, just 76% of those 350

\(\begin{array}{|c|ll} \cline{1-1} \textit{\textit{\LARGE a}\% of \textit{\LARGE b}}\\ \cline{1-1} \\ \left( \cfrac{\textit{\LARGE a}}{100} \right)\cdot \textit{\LARGE b} \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{76\% of 350}}{\left( \cfrac{76}{100} \right)350}\implies 266\)

In this case, the monthly payment for the car loan would be approximately $1,299.13.

To calculate the monthly payment for a bank loan using Excel, you can use the PMT function.

Here's how to do it:

1. Open Excel and create a new spreadsheet.

2. In cell A1, enter the loan amount: -40000 (negative because it's an outgoing payment).

3. In cell A2, enter the annual interest rate: 9%.

4. In cell A3, enter the loan duration in years: 3.

5. In cell A4, enter the formula to calculate the monthly payment: =PMT(A2/12, A3*12, A1).

6. The result in cell A4 will be the monthly payment.

So, in this case, the monthly payment for the car loan would be approximately $1,299.13.

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To find the common ratio and the first four terms of the geometric sequence {(9^n+2)/(3)}, let's first rewrite the given expression to make it easier to understand i.e. Term a_n = (9^n+2)/3

Now, let's find the first four terms:
a_1 = (9^(1)+2)/3 = (9+2)/3 = 11/3
a_2 = (9^(2)+2)/3 = (81+2)/3 = 83/3
a_3 = (9^(3)+2)/3 = (729+2)/3 = 731/3
a_4 = (9^(4)+2)/3 = (6561+2)/3 = 6563/3

The first four terms are:
a_1 = 11/3
a_2 = 83/3
a_3 = 731/3
a_4 = 6563/3

To find the common ratio, divide the second term by the first term (or any consecutive terms):
Common ratio = a_2 / a_1 = (83/3) / (11/3) = 83/11 = 3

So, the common ratio is indeed 3, and the first four terms are 11/3, 83/3, 731/3, and 6563/3.

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Answer:

160 newspapers (400 × .4 = 160)

1   Y is distributed as N(aμ + b, a^2σ^2), as desired.

2  We have shown that under these conditions, E[XY] = E[X]E[Y].

To prove that Y is distributed as N(aμ + b, a^2σ^2), we need to show that the mean and variance of Y match those of a normal distribution with parameters aμ + b and a^2σ^2, respectively.

First, let's find the mean of Y:

E(Y) = E(aX + b) = aE(X) + b = aμ + b

Next, let's find the variance of Y:

Var(Y) = Var(aX + b) = a^2Var(X) = a^2σ^2

Therefore, Y is distributed as N(aμ + b, a^2σ^2), as desired.

We can use the definition of covariance to prove that E[XY] = E[X]E[Y]. By the properties of expected value, we know that:

E[XY] = ∫∫ xy f(x,y) dxdy

where f(x,y) is the joint probability density function of X and Y.

Then, we can use the fact that X and Y are independent to simplify the expression:

E[XY] = ∫∫ xy f(x) f(y) dxdy

= ∫ x f(x) dx ∫ y f(y) dy

= E[X]E[Y]

where f(x) and f(y) are the marginal probability density functions of X and Y, respectively.

Therefore, we have shown that under these conditions, E[XY] = E[X]E[Y].

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The correct answer is  the formula for probability is equal to the number of times an event occurs divided by the number of attempts or chances for each outcome.

The formula for probability is equal to the number of times an event occurs divided by the number of attempts or chances for each outcome.

This means that the probability of a specific outcome is calculated by dividing the number of successful attempts by the total number of attempts. This is different from the number of possible outcomes, which represents the total number of different outcomes that could potentially occur.

So, to answer the multiple choice question, the formula for probability is equal to the number of times an event occurs divided by the number of attempts or chances for each outcome.

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It is false that Parametric models are reliable when the models are flexible in terms of the project's size

Parametric models are mathematical models that make assumptions about the distribution of the data being modeled. These models rely on the estimation of one or more parameters that define the distribution, such as the mean and variance of a normal distribution.

While parametric models can be very useful when the underlying assumptions are met and the data follows the assumed distribution, they can be unreliable when the assumptions are not met. For example, if the data does not follow a normal distribution, using a parametric model based on a normal distribution may lead to incorrect conclusions.

In terms of project size, the reliability of parametric models depends on the specific model and the nature of the data being modeled. Some parametric models may be more or less flexible in terms of accommodating different sample sizes or project sizes. However, in general, the reliability of a parametric model depends on the appropriateness of the underlying assumptions and the fit of the model to the data, rather than the size of the project.

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Answer:

i think its C

Step-by-step explanation:

Answer:

it's 20

.......: )...…...

Answer:

$44

Step-by-step explanation:

Answer:

the answer is twenty one

y + 1 = -3 (x - 2) an equation of the line in point-slope form with the given slope and the point it passes through, slope=(2,-1)

An indication as to how sharp a line is its slope. Slope is computed mathematically as "rise over run" (change in y divided by change in x). The ratio of the increase in elevation between two places to the run in elevation between those same two points is referred to as the slope.

Slope-related equations The "change in y" over the "change in x" of a line is referred to as the slope. By dividing (y₂ - y₁) over (x₂ - x₁) and choosing two locations on the line (x₁, y₁) and (x₂, y₂), you can get the slope.

The point-slope formula states: (y₂- y₁) = m (x₂ - x₁)

where, m = slope and (x₁, y₁) is a point the line passes through.

Substituting the slope and values from the point in the problem gives:

[y₂- (-1)] = -3 (x₂ - 2)

y + 1 = -3 (x - 2)

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The complete question is as follows:

How do you write the equation in point slope form given (2,-1), m= -3?

The term "arc" is used to describe units of measure for angular distance because it refers to the length of an arc on a circle.

Angular distance is the measure of the separation between two points on a circle or an arc. The term "arc" is used to describe this measure because it refers to the length of the arc connecting the two points on the circle.

This length is a fraction of the circumference of the circle and is proportional to the angle between the two points. The use of the term "arc" in this context is a nod to the geometric origins of angular measurement, which is based on the properties of circles and their angles.

The most common units of angular measurement are degrees, minutes, and seconds, which are all based on the division of a circle into 360 equal parts (degrees) and further subdivisions (minutes and seconds).

Other units of angular measurement, such as radians and gradians, are also based on the properties of circles and their angles.

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To prove the opposite, we need to show that if G is not a pseudorandom generator (PRG), then Construction 3.17 cannot be EAV-secure.

Assume that G is not a PRG, which means it fails to expand the seed sufficiently. Let's suppose that G is computationally indistinguishable from a truly random function on its domain, but it does not meet the requirements of a PRG.

Now, consider the private-key encryption scheme Π described in Construction 3.17 using G as the pseudorandom generator. If G is not a PRG, it means that its output is not sufficiently pseudorandom and can potentially be distinguished from a random string.

Given this scenario, an adversary A could exploit the distinguishability of G's output and devise an attack to break the security of the encryption scheme Π. The adversary could potentially gain information about the plaintext by analyzing the ciphertext and the output of G.

Therefore, if G is not a PRG, it implies that Construction 3.17 cannot provide EAV-security, as it would be vulnerable to attacks by distinguishing the output of G from random strings. This contradicts Theorem 3.18, which states that if G is a PRG, then Construction 3.17 achieves indistinguishable encryptions.

Hence, by proving the opposite, we conclude that if G is not a PRG, then Construction 3.17 cannot be EAV-secure.

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Answer:

First question(unnumbered):
 \(\mathrm{Choice \; (B) : \;\;\dfrac{1}{2}}\)

Question 48

\(\mathrm{Choice \;(C)\;\; (x, y) = \left(-1, \dfrac{3}{2}\right)}\)

Question 49
\(\mathrm{Choice \; (D)\;\;-1}\)

Step-by-step explanation:

The imaginary variable i is \(\sqrt{-1}\) and \(i^2 = -1\)

For the unnumbered first question we have

the equation
\(\dfrac{1}{1-i}\)

Multiply numerator and denominator by \(i + 1\)

\(\rightarrow \dfrac{1\cdot \left(1+i\right)}{\left(1-i\right)\left(1+i\right)}\\\\\\= \dfrac{1 + i}{1 - i^2} \;\;\;\;\;\;\;since \;(a +b)(a-b) = a^2 - b^2\\\\\textrm{Since $i^2 = -1$, the denominator becomes:}\\\\1-i^2 = 1 -(-1) = 2\\\\\\\)

Therefore ,

\(\dfrac{1}{1-i} = \dfrac{1 + i}{2}\\\\= \dfrac{1}{2} + \dfrac{i}{2}\\\\\)

The real part is \(\dfrac{1}{2}\)   and the imaginary part is \(\dfrac{i}{2}\)

Answer to first question is: ) \(\dfrac{1}{2}\)
-------------------------------------------------------------------------

#48

Solve \((x, y)\)  for \(2y\:+\:xi\:=\:4+x-i\) for  \($x,y\in\mathbb{R}$\)

For the equation

\(2y\:+\:xi\:=\:4+x-i\)

Move the the x and i terms from the right to left side:

\(2y + xi - x + i = 4\\\\2y - x +xi + i =4\\\\\)

Since this works out to a real number, the imaginary part is 0

So

\(xi + i = 0\\\\xi = -i\\\\x = \dfrac{-i}{i}\\\\x = -1\)

and the real part

\(2y - x = 4\)

Substitute for x = -1 in the above to get
\(2y -(-1) = 4\\\\2y + 1 = 4\\\\2y = 4-1\\\\2y = 3\\\\y = \dfrac{3}{2}\\\\\)

\((x, y) = \left(-1, \dfrac{3}{2}\right)\)
which is choice (C)

------------------------------------------------------------------------

#49

For \($a,b\in\mathb{R}$\)

\(a+ib\:=\:\left(2-i\right)^2 \\\\\)

Expand \(x(2-i)^2\)

\(= 2^2 - 2.2.i +i^2\\\\\)

Since i² = -1 this works out to:
\(4 - 4i -1\)

\(3 - 4i\)

Therefore
\(a + ib = 3 - 4i\\\\\)

Equation real part on left to the real part on the right :
\(a = 3\)

Equation imaginary part on left to the imaginary part on the right :
\(ib = 4i\)

\(b = -4\)

\((a + b) = (3 +(-4))\\\\= 3 - 4 \\\\= -1\\\\\)

This would be option (D)

To convert 5.87 x 10^5 centigrams (cg) to kilograms (kg), we need to use the conversion factor of 1 kg = 100,000 cg. Therefore, 5.87 x 10^5 centigrams is equal to 5.87 kilograms.

First, we'll divide 5.87 x 10^5 cg by 100,000 cg/kg to convert centigrams to kilograms:

5.87 x 10^5 cg ÷ 100,000 cg/kg

Next, we'll simplify the expression:

5.87 ÷ 1 x 10^5 ÷ 10^5

Dividing 5.87 by 1 gives us:

5.87 x 10^5 ÷ 10^5

To divide numbers in scientific notation, we subtract the exponents:

5.87 x (10^5 ÷ 10^5)

10^5 ÷ 10^5 equals 1, so the expression simplifies to: 5.87 x 1

Finally, we multiply 5.87 by 1 to get the result: 5.87 kg

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