Study the animal and plant cell above. Select the features that you find in BOTH types of cells

Question 1 options:

chloroplasts, plasma membrane, ribosome


plasma membrane, nucleus, ribosomes


cell wall, plasma membrane, nucleus


plasma membrane, cell wall, chloroplast

Human activities are responsible for almost all of the increase in greenhouse gases in the atmosphere over the last 150 years. The largest source of greenhouse gas emissions from human activities in the United States is from burning fossil fuels for electricity, heat, and transportation.

As you can see the picture, in the three given compounds i.e. ethane, ethene and ethyne, ethyne have shortest bond. Bond length of ethyne is very short when compared to the ethane and ethene. Shorter the bond, bond strength will be more. Hence, our answer is ethyne.

Answer:

ethyne has shortest bond

The subshell with quantum numbers n=2 and l=2 is the 2D subshell.

The set of numbers used to describe the position and energy of the electron in an atom are called quantum numbers.

There are four known quantum numbers, and they include:

The  principal quantum number (n) indicates the energy level or shell of an electron, while the azimuthal quantum number (l) indicates the shape of the electron cloud or subshell.

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The result of the computation when you follow the steps is 1.699.

A logarithm is a mathematical function that represents the exponent or power to which a specific base must be raised to obtain a given number. In simpler terms, it answers the question: "To what power must we raise a base number to obtain a certain value?"

What you should do is that on your calculator, you could press the logarithm key and then put in the value that has been shown and then the result would be displayed on your calculator.

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The mass of water produced when 6.26g of butane reacts with excess of oxygen will be 9.78g.

According to given question, the reaction would be:

C₄H₁₀ + 13/2O₂ --- 4CO₂ + 5H₂O

6.26g 0 0

As we know,

(mole of C₄H₁₀)÷coefficient = (mole of H₂O)÷coefficient

6.26/molecular weight ÷ 1 = mass of H₂O/molecular weight ÷ 5

6.26÷58 = Mass of H₂O/18×5

Mass of H₂O = 9.78g

Therefore, the mass of water produced when 6.26gram of butane reacts in the presence of excess of oxygen will be 9.78gram.

The combustion of butane is a reaction between butane and oxygen gas that leads to the production of carbon dioxide gas and water. This hydrocarbon combustion reaction releases heat energy and is an example of an exothermic reaction.

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Answer:

3.25x10²³ ions

Explanation:

To solve this problem we'll first convert those 14.02 grams of cyanide (CN⁻) to moles, using its molar mass:

Then we'll convert those 0.5392 moles into number of ions, using Avogadro's number:

we would need 2625.13 grams (or 2.62513 kilograms) of NaCl.

To calculate the mass of NaCl required to produce a 26.4 mol/L solution with a 1.7 L volume, we need to use the formula that relates the mass of solute, moles of solute, and molarity:Molarity (M) = moles of solute / liters of solution Rearranging this formula, we get:moles of solute = Molarity (M) x liters of solutionWe can use this formula to find the moles of NaCl needed:moles of NaCl = 26.4 mol/L x 1.7 L = 44.88 molNow, we can use the molar mass of NaCl to convert from moles to grams. The molar mass of NaCl is 58.44 g/mol:mass of NaCl = moles of NaCl x molar mass of NaClmass of NaCl = 44.88 mol x 58.44 g/mol = 2625.13 gTo produce a 26.4 mol/L solution with a 1.7 L volume.

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Explanation:

aluminium

proton= 13

electron=13

neutron=27

nitrogen

proton= 7

electron=7

neutron= 14

Answer:

The answer is 2.4moles of Ag

Explanation:

450.98g Cu(NO3)2/1 x 1mole/187.554g Cu(NO3)2 = 2.4moles Ag

Answer:

a top predator, fighting

Respuesta:

0.13 mol

Explicación:

Paso 1: Escribir la ecuación química balanceada

3 Ba(NO₃)₂ + 2 H₃PO₄ ⇒ Ba₃(PO₄)₂ + 3 H₂O

Paso 2: Establecer la relación molar apropiada

La relación molar de Ba(NO₃)₂ a Ba₃(PO₄)₂ es 3:1.

Paso 3: Calcular cuantos moles de fosfato de bario se producen a partir de 0.38 moles de nitrato de bario

0.38 mol Ba(NO₃)₂ × 1 mol Ba₃(PO₄)₂/3 mol Ba(NO₃)₂ = 0.13 mol Ba₃(PO₄)₂

Answer:

180 g Ca

General Formulas and Concepts:

Chemistry - Atomic Structure

Explanation:

Step 1: Define

4.4 mol Ca

Step 2: Identify Conversions

Molar Mass of Ca - 40.08 g/mol

Step 3: Convert

\(4.4 \ mol \ Ca(\frac{40.08 \ g \ Ca}{1 \ mol \ Ca} )\) = 176.352 g Ca

Step 4: Check

We are given 2 sig figs. Follow sig fig rules and round.

176.352 g Ca ≈ 180 g Ca

Answer:

Answers:

Explanation:

1. Sulfur oxide

2. Calcium cyanamide

3. aluminum sulfide (I think on that one)

Good luck

Answer:

C

Explanation:

the electrons in an atom's outermost energy level

Valence electrons are the electrons located in the outermost energy level (also called valence shell) of an atom. These electrons are crucial in determining the chemical behavior and properties of an element.

The correct option is C.

Atoms consist of a nucleus containing protons and neutrons, surrounded by electron shells or energy levels. The electron shells are organized into different energy levels, with the innermost shell closest to the nucleus and higher energy levels further out. The outermost energy level is particularly important because it determines how the atom interacts with other atoms and forms chemical bonds.

Valence electrons play a significant role in chemical bonding because they are involved in interactions between atoms. Elements in the same column or group of the periodic table have the same number of valence electrons, leading to similar chemical behaviors.

Hence, C is the correct option

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Answer:

Ionic bond.

Explanation:

Group 7 elements like Bromine (Br) and group 2 elements like Magnesium,(Mg) involved loss and gain of electrons which is typical with Ionic bonding.

Answer:  An electrochemical cell that produces electricity from a spontaneous oxidation-reduction reaction

Explanation:

Galvanic cell is a device which is used for the conversion of the chemical energy produced in a redox reaction into the electrical energy.

Galvanic cell consists of two half cells known as anode and cathode. Oxidation takes place at anode and reduction takes place at cathode. The two half cells are connected by a salt bridge which contains an electrolyte which maintains the electrical neutrality.

When sodium metal and hydrochloric acid combine, salt and hydrogen gas are produced. As a result, sodium metal and hydrochloric acid will be your reactants since these are the things that undergo transformation to produce salt and hydrogen gas.

In a chemical reaction, one or more substances—also known as reactants—are changed into one or more additional substances—also known as products. Chemical components or chemical compounds make up substances.

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Answer:

2HCl is the product of this reaction 2 is added in order to balance the reaction

The strength of this intermolecular force will be Strong, because it is a result of interaction between ions and polarized molecules.

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Answer:

it 3

Explanation:

Answer:

\(m=59.3gCO_2\)

Explanation:

Hello,

In this case, the first step is to compute the molar mass of carbon dioxide as shown below, considering it has one carbon atom and two oxygen atoms:

\(M=12.011g/mol+2*15.999g/mol\\\\M=44.009g/mol\)

It is important to notice it is the mass in one mole of such compound. Afterwards, we need to use the Avogadro's number to compute the how many moles are in the given molecules of carbon dioxide as shown below:

\(mol=8.12x10^{23}molec*\frac{1mol}{6.022x10^{23}molec} =1.35mol\)

Finally, the mass by using the molar mass:

\(m=1.35mol*\frac{44.009g}{1mol} \\\\m=59.3gCO_2\)

Best regards.

Answer:

59.3g

Explanation:

Got it right in Gizmo

Answer:

1,2,3

Explanation:

all if these answers are true except for the last one

Answer:1. Energy and matter are both conserved in stars.

2. Energy in stars causes the fusion of light elements

3.Some matter is converted into matter in stars

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2. Question

What makes up all stars?

A: Plasma

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3. Question

The International Astronomical Union(IAU) defines a constellation by its:

A: Boundary

Explanation:

Answer:

............................................................................................................................

Explanation:

because ........................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................

The concept molarity is used here to determine the pH after adding 12.6 mL of the base. The term molarity is an important method which is used to calculate the concentration of a solution. Here the pH is 0.501.

The term molarity is defined as the number of moles of the solute dissolved per litre of the solution. It is also called the molar concentration. It is represented as 'M' and its unit is mol / L.

Molarity is given as:

M = Number of moles / Volume of solution in liters

'n' of HCN = 36.9 × 1 L / 1000 mL × 0.423 = 0.0156 mol

'n' of Ba(OH)₂ = 12.6 × 1L / 1000 mL × 0.382 = 0.0048 mol

Excess H⁺ = 0.0108

Total volume = 36.9 + 12.6 = 49.5 mL = 0.0495 L

Concentration of H⁺ = 0.0156 / 0.0495 = 0.315

So pH is:

pH = - log[H⁺]

pH = - log[ 0.315] = 0.501

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The amount of Amoxicillin dose given to the 85.4 lb child daily is determined as 1,743.3 mg.

The amount of  Amoxicillin  dose given to the child is calculated as follows;

amount of Amoxicillin dose = weight of the child x dosage prescribed

The weight of the child in pounds (lb) is calculated as follows;

1 lb = 0.453592 kg

85.4 lb = ?

= 85.4 x 0.453592 kg

= 38.74 kg

amount of Amoxicillin dose = 38.74 kg x 45 mg/kg

amount of Amoxicillin dose = 1,743.3 mg

Thus, the amount of Amoxicillin dose given to the 85.4 lb child daily is determined as 1,743.3 mg.

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The complete question is below:

A 85.4 lb child has a Streptococcus infection. Amoxicillin is prescribed at a dosage of 45 mg per kg of body weight per day given b.i.d. Calculate the daily dose of the child.

When 2.0 moles of KCIO3 decompose, 2.0 moles of O2 will form.

The balanced chemical equation shows that 2 moles of KCIO3 decompose to produce 3 moles of O2. Therefore, we can use the stoichiometric ratio from the balanced equation to determine the number of moles of O2 formed when 2.0 moles of KCIO3 decompose.

According to the stoichiometry, 2 moles of KCIO3 produce 3 moles of O2. Therefore, we can set up a proportion:

(2 moles KCIO3 / 2 moles O2) = (2.0 moles KCIO3 / x moles O2),

where x represents the unknown number of moles of O2 formed.

Simplifying the equation:

(2 moles KCIO3 / 2 moles O2) = (2.0 moles KCIO3 / x moles O2),

1 = (2.0 moles KCIO3 / x moles O2),

Cross-multiplying:

x moles O2 = (2.0 moles KCIO3 / 1),

x moles O2 = 2.0 moles KCIO3.

Therefore, when 2.0 moles of KCIO3 decompose, 2.0 moles of O2 will form.

It is important to note that this calculation assumes complete and ideal conditions, where the reaction proceeds with 100% efficiency. In reality, the actual yield of O2 may be lower due to various factors such as side reactions or incomplete decomposition. To determine the actual yield, additional information or experimental data would be required.

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