The change in energy of the hot water due to the heat transfer from the cold water is 8.4 J.
The amount of heat required to raise the temperature of one gram of a substance by one degree Celcius is known as the substance's specific heat.
This number may be used to indicate a substance's capacity to absorb heat because it is constant for all substances.
Mass of the first water, m₁ = 1 kg
Mass of the second water, m₂ = 1 kg
Initial temperature, T₁ = 39.5°C
Final temperature, T₂ = 19.5°C
Specific heat capacity of water, C = 4.2 J/kgK
According to the principle of calorimetry,
E = E₁ - E₂
E = mCΔT
E = 1 x 4.2 x (39.5 - 19.5)
E = 4.2 x 20
E = 8.4 J
To learn more about specific heat, click:
https://brainly.com/question/31608647
#SPJ12
A car approaches a stop sign going 5 m/s before it comes to a stop. If it does this in 4 seconds, what was its acceleration?
Answer:
\(a = - \frac{5}{4} \: m{s}^{ - 2}\)
Explanation:
a = acceleration (m/s²)
v = final velocity (m/s) = 0
u = initial velocity (m/s) = 5
t = time (s) = 4
\(a = \frac{v - u}{t} \\ a = \frac{(0 - 5)}{4} \\ a = - \frac{5}{4} \)
Match the following list of key words with their definitions
__ an objects
the rate at which an object changes position when traveling in a certain direction
_____
the rate at which an object changes position
_____
the unit of force in the metric system
_____
an object´s resistance to its motion changing, expressed as the object´s mass times the object´s velocity
____
the amount of matter or "stuff" an object is made up of
1.
mass
2.
momentum
3.
Newton
4.
speed
5.
velocity
Question 2
Match the following list of key words with their definitions:
_____
a push or pull; any quantity that produces, or is capable of producing, motion
_____
force of resistance acting between objects in contact and tending to dampen their motion
____
force of attraction between all masses in the universe
_____
attractive or repulsive force acting between charged particles
_____
rate of change in velocity, which is the change in velocity divided by the change in time
1.
acceleration
2.
electromagnetic force
3.
force
4.
friction
5.
gravity
Question 1 :
1. VELOCITY
2. SPEED
3. NEWTON
4. MOMENTUM
5. MASS
Question 2
1. FORCE
2. FRICTION
3. GRAVITY
4. ELECTROAGNETIC FORCE
5. ACCELERATION
An astronaut 1500n on the moon. What will be his weight on Earth?
I'm pretty sure this poor guy could never have been accepted for astronaut training, much less a mission to the Moon.
He weighs something like 335 pounds when he's ON THE MOON !
If he has enough fuel, and survives a trip back to Earth, he'll weigh around 9,080 Newtons here. That's like 2,040 pounds ... durn close to a ton ! !
Answer:
Gravitational field strength:
Moon is 1.6N/kg
Earth is 9.8N/kg or 10N/kg
Moon:
Weight = mass x gravitational field
1500N = m x 1.6N/kg
÷1.6 both sides
937.5 = m
Mass of astronaut is 937.5kg
(Your mass doesn't change, no matter where you go, in space)
Earth:
Weight = mass x gravitational field
= 937.5kg x 9.8 N/kg
= 9187.5N
Or
Weight = mass x gravitational field
= 937.5kg x 10 N/kg
= 9375N
Thus, the astronaut's weight will be 9187.5N or 9375N on Earth.
Hope this helps!
1. What are the two main gases responsible for lowering down the pH.
2. Can we control an acid rain? Why or Why not?
3. When pH changes from 6 to 3, how many times does acidity increase?
Answer:
1. The three main acidic gases responsible for lowering the pH of rainwater are non-metal oxides produced by the burning of fossil fuels like coal, oil and natural gas. Sulfur dioxide is produced when fossil fuels containing sulfur impurities are burned.
2. A great way to reduce acid rain is to produce energy without using fossil fuels. Instead, people can use renewable energy sources, such as solar and wind power. Renewable energy sources help reduce acid rain because they produce much less pollution.
3. The pH scale is logarithmic, meaning that an increase or decrease of an integer value changes the concentration by a tenfold. For example, a pH of 3 is ten times more acidic than a pH of 4.
Astronomers infer that the universe is expanding because distant galaxies all appear to?
Answer:
They appear to recede from our viewpoint.
That is, their emitted spectra are shifted toward the red (red-shift).
The wave-lengths that are received on earth are somewhat longer because of the "Doppler" shift of the receding atoms.
An object covers a distance of 8 meters in the first second of travel, another 8 meters
during the next second, and 8 meters again during tthe third second. What is the
acceleration of the object?
Answer:
I guess the acceleration would be 8 meters a second
Explanation:
I can't think of any other fitting way to put the answer sorry if it's not right
Explanation:
8+8+8=24
3/24×100
12.5
MARK ME BRAINLIEST
What aspects of human language do wild chimpanzees fail to use in their systems of calls about predators? When bonobos learn human sign-language or a pictogram language (symbols on buttons that can be pressed to initiate an artificial human voice speaking that word) what aspects of human language are they weak on?
Wild chimpanzees fail to use certain aspects of human language in their systems of calls about predators, such as syntax and grammar. They also do not have the ability to create new words or abstract concepts, which are key components of human language.
When bonobos learn human sign-language or a pictogram language, they may be weak on certain aspects of human language such as syntax and grammar, as well as the ability to understand figurative language, metaphors, and idioms. They may also struggle with understanding complex sentences and communicating complex ideas. However, with proper training and practice, bonobos can develop impressive communication skills using these artificial languages.
Hi! Wild chimpanzees fail to use certain aspects of human language in their systems of calls about predators, such as syntax, grammar, and complex vocabulary. Additionally, they lack the ability to produce and comprehend a wide range of sounds or symbols that represent specific concepts.
When bonobos learn human sign language or a pictogram language, they tend to be weak in areas such as grammar, syntax, and the ability to create complex sentences. They may also struggle with understanding idiomatic expressions, metaphors, and other abstract language features.
To know more about metaphors visit:-
https://brainly.com/question/27250460
#SPJ11
A ball is dropped from the top of a building. It initially
moves at 40 m/s. After 0.5 seconds, it moves at 3.8
m/s.
What force is responsible for the slowing of the ball?
air resistance
gravity
normal
tension
Answer:
Explanation:
I'm assuming you missed the decimal point in the initial velocity and that it should be 4.0 m/s. If after a half of a second it is moving a tiny bit slower, it would be because of air resistance. You can only neglect air resistance if the problems you are doing tell you neglect it.
Answer:
Air resistance
Explanation:
I got it correct on the quiz :)
(Pickleball) the biggest thing holding back most intermediate pickleball players is
The biggest thing holding back most intermediate pickleball players is their inconsistency in executing shots.
Pickleball is a fast-paced game that requires quick reactions and precise shots. To become an intermediate player, one needs to have a good understanding of the game, including the rules, court positioning, and strategies. Additionally, intermediate players should be able to execute various shots, including serve, return of serve, dinks, volleys, and smashes, with consistency and accuracy.
Inconsistency in executing shots is a significant issue for most intermediate players. It means that they are not able to hit the ball consistently to the desired location, height, or speed, leading to errors and missed opportunities. Inconsistency can be caused by various factors, including poor footwork, lack of proper technique, incorrect grip, and lack of focus.
For example, let's say an intermediate player hits 20 dinks during a game, but only 10 of them land in the desired location, while the other 10 go out of bounds or hit the net. This inconsistency can cost the player points and games, and prevent them from advancing to the next level.
To overcome this challenge, intermediate players need to work on their technique, footwork, and consistency in executing shots. They should practice their shots regularly, both on their own and in drills with partners.
Additionally, they should seek feedback from coaches and more experienced players to identify areas for improvement and practice. With consistent practice and focus on improving their shot execution, intermediate players can overcome this challenge and advance to higher levels of play.
To know more about pickleball, visit;
https://brainly.com/question/30633668
#SPJ11
The Space Shuttle travels at a speed of about 7.54 x 103 m/s. The blink of an astronaut's eye lasts about 96.2 ms. How many football fields (length
The space shuttle travels approximately 0.00794 football fields in one blink of an astronaut's eye.
The given problem is related to the conversion of units of speed and time to the distance of football fields. Given,The speed of the space shuttle is about 7.54 × 10³ m/s. The blink of an astronaut's eye lasts about 96.2 ms.To find the number of football fields the space shuttle travels in one blink of an astronaut's eye. The length of a football field is approximately 100 yards or 91.44 meters.The distance covered by the space shuttle in one blink of an astronaut's eye can be calculated as:Distance = Speed × TimeConvert the blink duration from milliseconds (ms) to seconds (s)96.2 ms = 96.2 × 10⁻³ sDistance = 7.54 × 10³ m/s × 96.2 × 10⁻³ s = 0.7251 mThe distance travelled in one blink of an eye by the space shuttle is 0.7251 m.To convert the distance to the number of football fields, divide the distance by the length of a football field:Number of football fields = distance ÷ length of a football fieldNumber of football fields = 0.7251 m ÷ 91.44 m/football fieldNumber of football fields = 0.00794 football fieldsTherefore, the space shuttle travels approximately 0.00794 football fields in one blink of an astronaut's eye.For more questions on space shuttle
https://brainly.com/question/31808987
#SPJ8
The international space station makes 15. 65 revolutions per day in its orbit around the earth.
Answer:
WHAT THE QUESTION
Explanation:
which statement is correct for a protein with an isoelectric point (pi) of 7.0?
A protein with an isoelectric point (pI) of 7.0 will have no net charge when the pH of the surrounding environment is also 7.0.
The isoelectric point (pI) of a protein is the pH at which the protein carries no net charge. At a pH below its pI, the protein will carry a net positive charge, while at a pH above its pI, the protein will carry a net negative charge.
In the case of a protein with a pI of 7.0, this means that at a pH below 7.0, the protein will carry a net positive charge, while at a pH above 7.0, the protein will carry a net negative charge. However, when the pH of the surrounding environment is 7.0, the protein will have no net charge and will be electrically neutral.
The charge of a protein can have important implications for its function and behavior, as it can affect its solubility, stability, and interactions with other molecules.
Learn more about "isoelectric point" : https://brainly.com/question/14895346
#SPJ11
Rank from greatest to least the amount of lift on the following airplane wings: (a) area 1000 m2 with atmospheric pressure difference of 2. 1N/m2 , (b) area 800 m2 with atmospheric pressure difference of 2. 3N/m2 , and (c) area 600 m2 with atmospheric pressure difference of 3. 3N/m2
The rank from greatest to least the amount of lift on the following airplane wings is:
Area 600 m2 with atmospheric pressure difference of 3.3N/m²Area 1000 m2 with atmospheric pressure difference of 2.1N/m²Area 800 m2 with atmospheric pressure difference of 2.3N/m², option C, A, B.The force per unit area that an atmospheric column exerts is known as atmospheric pressure, often referred to as barometric pressure. A mercury barometer, which shows the height of a mercury column that precisely balances the weight of the column of atmosphere over the barometer, may be used to determine atmospheric pressure.
Aneroid barometers can also be used to measure atmospheric pressure. The sensing element in an aneroid barometer is one or more hollow, partially evacuated, corrugated metal discs that are held against collapsing by an inside or outside spring. The change in the disk's shape with changing atmospheric pressure can be recorded using a pen arm and a clock-driven revolving drum.
Learn more about Atmospheric pressure;
https://brainly.com/question/30215097
#SPJ4
which is a harmful role of bacteria of bacteria?
Answer:
Harmful bacteria are called pathogenic
Explanation:
Harmful bacteria are called pathogenic bacteria because they cause disease and illnesses like strep throat, staph infections, cholera, tuberculosis, and food poisoning.
Graphical drafting programs, like autocad, will graph and add vectors, showing the resultant and providing its coordinates. Is autocad adding the vectors graphically and measuring the resultant, or is it adding the vectors algebraically and graphing the resultant? why?.
please help me, please i will mark brainliest
Answer:
conductor,neither,insulator
Explanation:
conductors allow electricity to flow through while insulators do not
HOPE IT HELPS
A current of 2 A passes through an 8 V load. What is the potential difference across the load? Show work.
The potential difference across the load is 16 V.
The current flowing through the load, I = 2 A
Resistance of the load, R = 8 Ω
According to Ohm's law, the current flowing through a circuit is directly proportional to the voltage applied across the circuit.
The voltage in the circuit can be defined as the potential difference between any two points on the circuit.
So,
V ∝ I
The potential difference across the circuit is the product of the current and resistance.
Therefore, the potential difference across the load,
V = IR
V = 2 x 8
V = 16 V
To learn more about potential difference, click:
https://brainly.com/question/30828851
#SPJ1
Whispering Gallery: A hall 100 feet in length is to be designed as a whispering gallery. If the foci are located 25 feet from the center, how high will the ceiling be at the center?
The height of the ceiling at the center of the whispering gallery is approximately 43.3 feet.
In an ellipse, the sum of the distances from any point on the ellipse to its two foci is constant. In this case, the two foci are located 25 feet from the center of the hall.
Given that the hall is 100 feet in length, the distance from one end to the center is 50 feet. We can consider this as the semi-major axis (a) of the ellipse.
The sum of the distances from any point on the ellipse to its two foci is equal to 2a. Thus, the sum of the distances from the ceiling at the center of the hall to the two foci is also 2a.
Since the foci are located 25 feet from the center, the sum of the distances is 2a = 50 feet.
To find the height of the ceiling at the center, we need to determine the semi-minor axis (b) of the ellipse. The semi-minor axis can be calculated using the formula:
b = √(a² - c²)
where c represents the distance from the center to each focus. In this case, c = 25 feet.
Substituting the values into the formula:
b = √(50² - 25²)
b = √(2500 - 625)
b = √(1875)
b = 43.3 feet
Therefore, the height of the ceiling at the center of the whispering gallery is approximately 43.3 feet.
To know more about the Height:
https://brainly.com/question/33901355
#SPJ12
The brakes applied to a car
produce an acceleration of 6 m s-²
the opposite direction to the motion. If
the car takes 2 seconds to stop after the
application of brakes, calculate the
distance it travels during this time.
Explanation:
\(from \: newton \: first \: equation \\ V = U + at \\ 0 = U + ( - 6 \times 2) \\ U = 12 \: m {s}^{ - 1} \\ from \: newtons \: third \: equation \\ {V}^{2} = {U}^{2} + 2aS \\ 0 = {12}^{2} + (2 \times - 12 \times \: S ) \\ 144 = 24S \\S = 6 \: m \)
know the different types of communication and describe each
Answer:1. verbal communication, which you listen to a person to understand what they are saying 2. written communication, you read what a person is trying to say 3. nonverbal communication, which you observe what someone is trying to say, like sign language.
Explanation:
How does the vapor pressure of water at 10c compare with it vapor pressure at 50c
Answer:
The vapour pressure of water is great tah 50 than it is 10.
what happens to the sprinter's displacement between images?, What happens to the sprinter's velocity?
Answer: Explanation is below!
Explanation:
The sprinter's velocity and displacement both increased, since the runner is moving forward in a direction. Displacement and Velocity are both vector quantities.
Assuming that the direction in where the runner is running to is positive, we can assume that the displacement is positive ( vise versa for a negative direction)
The more displacement the runner has, the more velocity the runner will have.
Hope this helped! Have a good day ;D
The half-life of 238U is 4.5 * 109 yr. A sample of rock of mass 1.6 g produces 29 dis>s. Assuming all the radioactivity is due to 238U, find the percent by mass of 238U in the rock.
The percent by mass of 238U in the rock is approximately 0.14%.
To determine the percent by mass of 238U in the rock, we need to use the radioactive decay equation and the concept of half-life. The given information states that the half-life of 238U is 4.5 * 10⁹ years.
The decay constant (λ) is determined by the equation:
λ = ln(2) / t(1/2)
where ln denotes the natural logarithm and t(1/2) is the half-life. Plugging in the values:
λ = ln(2) / (4.5 * 10⁹)
λ ≈ 0.154 x 10⁻⁹ year⁻¹
The number of decays per second (dis/s) can be determined by the equation:
dis/s = λ * N
where N is the number of radioactive nuclei present. Since the mass of the rock is given as 1.6 g, we can use Avogadro's number to convert it to the number of atoms:
N = (1.6 g / molar mass of 238U) * Avogadro's number
Substituting the values and using the molar mass of 238U:
N ≈ (1.6 / 238) * 6.022 x 10²³
N ≈ 4.06 x 10²¹ atoms
Now, substituting the values into the equation for dis/s:
dis/s = 0.154 x 10⁻⁹ * 4.06 x 10²¹
dis/s ≈ 6.25
To find the percent by mass, we divide the mass of 238U by the mass of the rock and multiply by 100:
Percent by mass = (mass of 238U / mass of rock) * 100
Since the number of decays per second is 29, and each decay corresponds to one 238U atom, the mass of 238U can be calculated as:
mass of 238U = (dis/s / λ)
mass of 238U ≈ 6.25 / 0.154 x 10⁻⁹
mass of 238U ≈ 4.06 x 10⁹ g
Now, substituting the values into the equation for percent by mass:
Percent by mass = (4.06 x 10⁹ / 1.6) * 100
Percent by mass ≈ 0.14%
Learn more about Mass
brainly.com/question/11954533
#SPJ11
h John has been taking exam (for, since, from) last Sunday. This is the place... ...........(which, where, that) I found this bag Reeta ............... (as well as, besides, and) Sita is here, No rain fell that month the crops all failed. (although, so, however) She speaks she knows all about it. (as it, however, unless) Sumit studied hard he could get success. (as, because, so that) This is the village I was born. (where, which, when) his higher qualification, he was a failure as a teacher, (Because, In spite of, Even though) This is the book I wanted. (when, whom, that) She went to school............... her illness. (though, because of, in spite of) I don't know the spot he met with the accident. (who, where, which)
Answer:
YOP
Explanation:
Caught that boy lacking aint no capping had to stand on business
I NEED HELP PLEASE !!!!
Find the impulse that acts on the object during the time interval 10s to 20s
Answer:
I guess it's force hope this answer helps
according to product categorization, vehicles can be placed under the _____.
According to product categorization, vehicles can be placed under various categories based on their type, size, purpose, and other features.
Some of the most common categories include:
Passenger cars: This category includes all types of cars, SUVs, and hatchbacks designed for carrying passengers.
Light commercial vehicles: This category includes small trucks, vans, and pickup trucks that are used for carrying goods and equipment.
Heavy commercial vehicles: This category includes large trucks, buses, and other vehicles that are used for transporting goods over long distances.
Two-wheelers: This category includes motorcycles, scooters, and other small, lightweight vehicles designed for individual transportation.
Off-road vehicles: This category includes vehicles designed for off-road driving, such as SUVs, ATVs, and dirt bikes.
Electric vehicles: This category includes vehicles powered by electric motors, such as electric cars, buses, and motorcycles.
Hybrid vehicles: This category includes vehicles that use both electric and internal combustion engines, such as hybrid cars and SUVs.
Learn more about product Visit: brainly.com/question/30394406
#SPJ4
If the block compresses the spring 4. 8 cm before coming to rest, what is the force constant of the spring?.
The force constant of the spring is 40.91 N/m, which can be written as 2133.33 N/m if the value is rounded to the nearest hundredth.
The work done by the block is given by the formula:W = (1/2)kx²
where W is the work done, k is the force constant of the spring, and x is the maximum compression of the spring.
Substituting the given values into the equation,
W = (1/2)kx²= (1/2) x k x (0.048 m)²= (1/2) x k x (0.002304 m²)= (1/2) x 0.11 kJ= 0.055 kJ
The work done by the block is equal to the initial kinetic energy of the block, which is given by the formula:
W = (1/2)mv²
where m is the mass of the block and v is the initial velocity of the block.
Substituting the given values into the equation, W = (1/2)mv²= (1/2) x 0.5 kg x (3 m/s)²= 2.25 J
Comparing the two equations, we have:
0.055 kJ = 2.25 J0.055 x 10³ J = 2.25 J
k = (2.25 J) / (0.055 x 10³ J/m)
k = 40.91 N/m
Learn more about the force at:
https://brainly.com/question/32816725
#SPJ11
Quiz 6) For a conceptual presentation of a gold atom, find D using Gauss' 1 aw for a spherical dieiectine whell geometry shown below, where \( Q \) is a positive point charge at nucleus. Negative volu
To determine D for a conceptual presentation of a gold atom using Gauss' 1 law for a spherical dielectric wheel geometry, we need to calculate the enclosed charge within the dielectric wheel.SolutionFirstly, the charge enclosed by the dielectric wheel (sphere) is the charge at the center minus the charge on the inner surface.\[Q_{enclosed} = Q - Q_{inside} \]The charge at the nucleus is positive,
thus,\[Q = +\frac{Ze}{4\pi\epsilon_o}\]where Z is the atomic number of gold, and e is the charge of an electron.For the inner surface,\[Q_{inside} = -\frac{Ze}{4\pi\epsilon_o}4\pi r^2 \sigma \]where r is the radius of the sphere and σ is the surface charge density.Using Gauss' law,\[\int{E.ds} = \frac{Q_{enclosed}}{\epsilon_o}\]Since there is spherical symmetry, E is constant, and the integral reduces to\(\[E(4\pi r^2) = \frac{Q - Q_{inside}}{\epsilon_o}\]\[E(4\pi r^2) = \frac{Ze}{4\pi\epsilon_o}+\frac{Ze}{\epsilon_o}r^2 \sigma \]Rearranging,\)
\(we get\[\frac{Ze}{4\pi\epsilon_o}=\frac{E(4\pi r^2)-Ze r^2 \sigma }{\epsilon_o}\]Hence, the dielectric constant,\[D = \frac{1}{\epsilon_o(1 - r^2 \sigma)} \]\)Therefore, for a conceptual presentation of a gold atom, we can determine D by calculating the enclosed charge within the dielectric wheel using Gauss' 1 law for a spherical dielectric wheel geometry.
To know more about presentation visit:
https://brainly.com/question/1493563
#SPJ11
The velocity-time equation for a golf cart isVA= (1 m/s) + (-0.5 m/s?)t (a) What is the cart's initial velocity? (b) What is the cart's acceleration?
If the velocity-time equation for a golf cart is v = (1 m/s) + (-0.5 m/s)t , then the initial velocity of the cart would be 1 m / s and the acceleration of the cart would be - 0.5 m / s² .
What is acceleration?The rate of change of the velocity with respect to time is known as the acceleration of the object. Generally, the unit of acceleration is considered as meter/seconds².
As given in the problem the velocity-time equation for a golf cart is
v = (1 m/s) + (-0.5 m/s)t ,
The initial velocity of the cart at t = 0 would be 1 m / s.
By differentiating the given equation of the velocity,
The acceleration of the cart would be -0.5 m / s.
Thus, the initial velocity would be 1 m / s and the acceleration would be -0.5 m / s.
To learn more about acceleration from here, refer to the link ;
brainly.com/question/2303856
#SPJ1
If p(a)=0.07692, p(b)=0.25, and probability of a and b. =0.01923, what is probability of a or b. to four decimal places? select one.
Answer:
p(a) * p(b) = .01923
p(b) = .01923 / .07692 = .2500
The probability of a or b will be equal to 0.30769.
What is probability?Probability is defined as the ratio of the number of favorable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.
The probability of the total sample points in A U B is P(A U B). The probabilities of sample points in A and B are now added together as P(A) + P(B). To get the total of probabilities in (A U B), which is P, we need to subtract once because we added the sample points in (A B) twice (A U B).
Given that p(a)=0.07692, p(b)=0.25, and probability of a and b. =0.01923. The probability will be calculated by using the formula below:-
P(A) = 0.07692
P(B)=0.25
P(A\(\cap\)B) = 0.01923
P(AUB) = P(A) + P(B) - P(A\(\cap\)B)
P(AUB) = 0.07692 + 0.25 - 0.01923
P(AUB) = 0.30769
Therefore, the probability of a or b will be equal to 0.30769.
To know more about probability follow
https://brainly.com/question/28025253
#SPJ2